VARIABLES OF GAS LAWS
• Volume – three-dimensional space that matter
occupies
• Temperature - property of matter which
reflects the quantity of kinetic energy of the component particles
• Pressure – force exerted by particles on a
specific area
• Mole – the unit of counting molecules, atoms
Temperature
ºF
ºC
K
-459 32 212
-273 0 100
0 273 373
K = ºC + 273
Always use absolute temperature (Kelvin) when working with gases.
Courtesy Christy Johannesson www.nisd.net/communicationsarts/pages/chem
F
32
Boyle’s Law
Condition 1 Condition 2
P1V1 = C P2V2 = C
Problem Solving
If 35 mL of oxygen gas is compressed fromm
Step 1: Identify the variables (Given)
Given:
Initial Conditions Final Conditions P1 = 1,900 torr P2 = 1.8 atm
V1 = 35 mL V2 = ?
Convert to uniform units
Step 2: Identify what is Required and state
the appropriate equation
Required:
The volume at the final condition (V2)
Equation:
From Boyle’s Law, P1V1 = P2V2 V2 = P1V1
Step 3: Substitute and do the Math
Solution:
V2 = P1V1 P2
= 1900 torr (35 mL) = 48.6111111 ml 1368 torr
Answer:
Your Turn
At constant pressure, the volume of a given gas sample divided by its Kelvin temperature is a constant value.
Initial Condition Final Condition
V1 / T1= C V2 / T2 = C
Problem Solving
If the temperature of a 12L gas sample increases from 32C to 60C, what will happen to the
Step 1: Identify the variables (Given)
Given:
Initial Conditions Final Conditions T1 = 32C T2 = 60C
V1 = 12L V2 = ?
Convert to standard units
Step 2: Identify what is Required and
state the appropriate equation
Required:
The volume at the final condition (V2)
Equation:
From Charles’ Law, V1/T1 = V2/T2 V2 = T2V1
Step 3: Substitute and do the Math
Solution:
V2 = T2V1 T1
= 333 K (12L) = 13.1016393442 L 305 K
Answer: