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V.B. Kumar Vatti et al IJSRE Volume 05 Issue 02 February 2017 Page 6212

Volume||5||Issue||02||February-2017||Pages-6212-6216||ISSN(e):2321-7545 Website: http://ijsae.in

Index Copernicus Value- 56.65 DOI: http://dx.doi.org/10.18535/ijsre/v5i02.04

A Fourth Order Variant of Newton’s Method

Authors

V.B. Kumar Vatti1 , Ramadevi Sri2 , M.S.Kumar Mylapalli3

1

Dept. of Engineering Mathematics, Andhra University, Visakhapatnam, India, 2

Dept. of Engineering Mathematics, Andhra University, Visakhapatnam, India, 3

Dept. of Engineering Mathematics, Gitam University, Visakhapatnam, India, Email- [email protected], [email protected], [email protected] ABSTRACT:

In this paper, we present a new two step iterative method to solve the nonlinear equation f x 0 and

discuss about its convergence. Few numerical examples are considered to show the efficiency of the new method in comparison with the other methods considered in this paper.

Keywords: Nonlinear equation, Iterative method, Newton’s method, Chebyshev’s method, Convergence.

1. INTRODUCTION

Many of the complex problems in Science and Engineering contains the function of nonlinear equation of the form

  0

f x  (1.1) Where f I: R for an open interval I is a scalar function.

Let 1 x

n be the root of the equation (1.1) i.e., f x

 

n1 0 while f

 

xn1 0.

The classical quadratic convergent Newton‟s method [3] for finding the root of “(1.1),” is

 

 

, 0

1

f xn

x xn n

n   f xn  (1.2)

The third order two step Chebyshev‟s method [4] is

 

 

f xn yn xn

f xn

 

   

  2

, 0

1 2

yn xn f xn

xn yn n

f xn

 

   

(1.3)

The third order Newton‟s variant method [7] is

 

 

2 , 0

1 1 1 2

f xn

x xn n

n f xn

n

 

    

 

(1.4)

where,    

  2 f xn f xn n

f xn

  

   

.

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V.B. Kumar Vatti et al IJSRE Volume 05 Issue 02 February 2017 Page 6213

2. A FOURTH ORDER VARIANT OF NEWTON’S METHOD

Following the basic assumption of Abbasbandy and Maheshweri [1], [2] and also others [5], [6] and [8], we consider the second degree Taylor‟s expansion of

 

1

f x

n about xnis

 

 

 

 

2 1

1 1 2

xn xn

f xn f xn xn xn f xn f xn

 

 

   

  (2.1)

Where

1

x xn h n  

 

2

 

 

 

 

 

2

 

1 1 2 1 2

f xn xn f xn

f x x x f xn x fn xn f xn x fn xn

n n n

                     (2.2) Since, 1 x

n be the root of the equation (1.1) i.e., f x

 

n1 then the equation (2.2) becomes

 

 

 

 

 

 

2 2 2 2 2 2 0

1 1

x nf xn xn fxnx fn  xn   f xnx fnxnxn f xn  (2.3)

Rewriting f

 

f

 

yn f

 

xn xn

yn xn

  

 

 and

 

 

2f yn

n

f xn

  in “(1.4),” gives the two step Newton‟s variant

method as

 

 

f xn yn xn

f xn   

 

 

   

2 , 0

1

1 1 4

f xn

xn xn n

f xn f yn f xn                       (2.4)

The simplified form of “(2.4),” can be rewritten as

 

 

1 1 1 4

12

1 2

f xn

x xn n

n f xnn

             

Expanding

1 4 n

12up to four terms i.e., up to third degree terms ofn, we get the required two step Newton‟s variant method as

 

 

f xn yn xn

f xn   

 

 

 

 

 

 

2

1 2 , 0

1

f xn f yn f yn

xn xn n

f xn f xn f xn

                  (2.5)

3. CONVERGENCE CRITERIA

Theorem 3.1. Let Ibe a simple zero of a sufficiently differentiable function f I: Rfor an open interval I. Then, the new method that is defined by “(2.5),” has the fourth order convergence and satisfies the following error equation,

21 4 3

4

 

5

1 c c2 3 c2 n o n

n

     

Where,

1 1

x

n n  and xn

n

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V.B. Kumar Vatti et al IJSRE Volume 05 Issue 02 February 2017 Page 6214

 

 

2 3 4

 

5

2 3 4

f xnf  ncncncnon

  (3.1)

And

 

 

1 2 3 2 4 3 5 4

 

5 5

2 3 4

f xnf  cncncncnon (3.2)

Dividing “(3.2),” by“(3.1),” we have

 

 

 

2 2 2

22 3

 

3 3 4 4 23 7 2 3

4 5

f xn c c c c c c c o

n

n n n n

f xn     

 

 

 

 

      

 

 (3.3)

 

 

2 2

2

3

3 4 3 7

4 5

3 2

2 4 2 2 3

f ynf  cnccnccc cnon  (3.4)

Dividing “(3.4),” by“(3.1),” we obtain

 

 

2

23 322

2

10 2 3 34 9 23

3 4 2 4 524 93 23 22 3 2

2

2 4

 

5 f yn

c n c c n c c c c n c c c c c c c n o n

f xn     

 

 

 

            (3.5)

Adding „1‟ on both sides to “(3.5),” we have

 

 

 2 2  3 3 4 3

2 4

 

5

1 f yn 1 c2 n 2c3 3c2 n 10c c2 3 3c4 9c2 n 4c c2 4 5c2 9c c3 2 22 3 2c c 2 n o n

f xn     

 

 

 

              (3.6)

Multiplying “(3.3),” with “(3.6),” we have

 

 

1

 

 

2 22 3

13 2 3 6 23

4

 

5

f xn f yn

c c c c o

n n n n

fxnf xn         

 

 

  (3.7)

Multiplying “(3.3),” with “(3.5),” we have

 

 

 

 

 

2

2 3 3 4 5

2 f xn f yn 2c2 n 8c c2 3 10c2 n o n fxn f xn       

 

 

 

(3.8)

Thus,

 

 

 

 

 

 

2

1 2

1

f xn f yn f yn x xn

n f x f x f x

n n n

 

     

   

 

 

becomes

2 2 3 2 2 3

21 4 3

4

 

5

1 n n c2 n c2 n c c2 3 c2 n o n

n

              

3

4

 

5

21 4

1 c c2 3 c2 n o n

n

     

(3.9)

Equation (3.9) establishes the fourth order convergence of the method that is defined by “(2.5)”.

4. NUMERICAL EXAMPLES

We consider few numerical examples considered by [6], [8] and the method “(2.5),” are compared with the methods “(1.2),” “(1.3),” and “(1.4)”. The computational results are tabulated below and the results are correct up to an error less thanas indicated for each of the problems.

Example 1. Consider the following equation f x

 

ex3x2 0.

Table 4.1.The results obtained by four methods for solving f x

 

ex3x2 0withx00.5and 0.5E20.

Formula No. of iterations (n) Root

 

xn No. of functional values

Newton 7 0.91000757248870907904 14

Chebyshev --- DIVERGENT ---

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V.B. Kumar Vatti et al IJSRE Volume 05 Issue 02 February 2017 Page 6215 Example 2. Consider the following equation f x

 

x3ex0.

Table 4.2.The results obtained by four methods for solving f x

 

x3ex0withx00.5and 0.5E20.

Example 3. Consider the following equation f x

 

sinx0.5x0.

Table 4.3. The results obtained by four methods for solving f x

 

sinx0.5x0withx03and 0.5E20.

Example 4. Consider the following equation f x

 

x32x 5 0.

Table 4.4.The results obtained by four methods for solving f x

 

x32x 5 0withx03and 0.5E20.

Example 5. Consider the following equation f x

 

sinx0.

Table 4.5 The results obtained by four methods for solving f x

 

sinx0withx00.5and0.5E20.

5. CONCLUSION

With the number of iterations and the number of functional evaluations tabulated for each of the methods for five non-linear equations, we conclude that the method “(2.5),” is efficient one compared to the methods considered in this paper.

REFERENCES

1. S.Abbasbandy, “Improving Newton-Raphson method for nonlinear equations by modified Adomian decomposition method”, Applied Mathematics and Computation, Vol. 145, 2003, pp. 887 – 893. 2. Amit kumar Maheshwari, “A fourth order iterative method for solving nonlinear equations”, Applied

Mathematics and computation, Vol.211, 2009, pp. 383-391.

3. Avram Sidi, “Unified treatment of regular falsi, Newton–Raphson, Secant, and Steffensen methods for nonlinear equations”, Journal of Online Mathematics and its Applications. 2006, pp. 1-13.

Formula No. of iterations (n) Root

 

xn No. of functional values

Newton 6 0.77288295914921017344 12

Chebyshev 5 0.77288295914921017344 15 Newton‟s variant 5 0.77288295914921017344 15 New Method 3 0.77288295914921017344 9

Formula No. of iterations (n) Root

 

xn No. of functional values

Newton 6 1.89549426703398109184 12

Chebyshev 5 1.89549426703398109184 15 Newton‟s variant 5 1.89549426703398109184 15 New Method 3 1.89549426703398109184 9

Formula No. of iterations (n) Root

 

xn No. of functional values Newton 7 2.09455148154232668160 14

Chebyshev 5 2.09455148154232668160 15 Newton‟s variant 5 2.09455148154232668160 15 New Method 3 2.09455148154232668160 9

Formula No. of iterations (n) Root

 

xn No. of functional values

Newton 5 0 10

Chebyshev 4 0 12

Newton‟s variant 4 0 12

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V.B. Kumar Vatti et al IJSRE Volume 05 Issue 02 February 2017 Page 6216 4. J.M.Gutierrez, M.A.Hernandez, “A family of Chebyshev-Halley type methods in Banach spaces”,

Bull. Aust. Math. Soc. 55, 113-130 (1997).

5. Jinhai Chen, Weiguo Li, “On new exponential quadratically convergent iterative formulae”, Applied Mathematics and Computation, Vol. 180, 2006, pp. 242-246.

6. Nasr Al-Din Ide, “A new Hybrid iteration method for solving algebraic equations”, Applied Mathematics and Computation, Vol. 195, 2008, pp. 772-774.

7. Vatti V.B.Kumar., Ramadevi Sri., Mylapalli M. S. Kumar., “A Newton‟s Variant third order method”, Engineering Science and Technology: An International Journal, Vol. 6, No. 4, 2016. 8. Xing-Guo Luo, “A note on the new iterative method for solving algebraic equation”, Applied

Figure

Table 4.1.The results obtained by four methods for solving  f x    e x  3 x 2   0 with x 0  0.5 and   0.5 E  20
Table 4.2.The results obtained by four methods for solving  f x    x 3  e  x  0 with x 0  0.5 and   0.5 E  20

References

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