V.B. Kumar Vatti et al IJSRE Volume 05 Issue 02 February 2017 Page 6212
Volume||5||Issue||02||February-2017||Pages-6212-6216||ISSN(e):2321-7545 Website: http://ijsae.in
Index Copernicus Value- 56.65 DOI: http://dx.doi.org/10.18535/ijsre/v5i02.04
A Fourth Order Variant of Newton’s Method
AuthorsV.B. Kumar Vatti1 , Ramadevi Sri2 , M.S.Kumar Mylapalli3
1
Dept. of Engineering Mathematics, Andhra University, Visakhapatnam, India, 2
Dept. of Engineering Mathematics, Andhra University, Visakhapatnam, India, 3
Dept. of Engineering Mathematics, Gitam University, Visakhapatnam, India, Email- [email protected], [email protected], [email protected] ABSTRACT:
In this paper, we present a new two step iterative method to solve the nonlinear equation f x 0 and
discuss about its convergence. Few numerical examples are considered to show the efficiency of the new method in comparison with the other methods considered in this paper.
Keywords: Nonlinear equation, Iterative method, Newton’s method, Chebyshev’s method, Convergence.
1. INTRODUCTION
Many of the complex problems in Science and Engineering contains the function of nonlinear equation of the form
0
f x (1.1) Where f I: R for an open interval I is a scalar function.
Let 1 x
n be the root of the equation (1.1) i.e., f x
n1 0 while f
xn1 0.The classical quadratic convergent Newton‟s method [3] for finding the root of “(1.1),” is
, 01
f xn
x xn n
n f xn (1.2)
The third order two step Chebyshev‟s method [4] is
f xn yn xn
f xn
2
, 0
1 2
yn xn f xn
xn yn n
f xn
(1.3)
The third order Newton‟s variant method [7] is
2 , 01 1 1 2
f xn
x xn n
n f xn
n
(1.4)
where,
2 f xn f xn n
f xn
.
V.B. Kumar Vatti et al IJSRE Volume 05 Issue 02 February 2017 Page 6213
2. A FOURTH ORDER VARIANT OF NEWTON’S METHOD
Following the basic assumption of Abbasbandy and Maheshweri [1], [2] and also others [5], [6] and [8], we consider the second degree Taylor‟s expansion of
1
f x
n about xnis
2 1
1 1 2
xn xn
f xn f xn xn xn f xn f xn
(2.1)
Where
1
x xn h n
2
2
1 1 2 1 2
f xn xn f xn
f x x x f xn x fn xn f xn x fn xn
n n n
(2.2) Since, 1 x
n be the root of the equation (1.1) i.e., f x
n1 then the equation (2.2) becomes
2 2 2 2 2 2 0
1 1
x n f xn xn f xn x fn xn f xn x fn xn xn f xn (2.3)
Rewriting f
f
yn f
xn xnyn xn
and
2f yn
n
f xn
in “(1.4),” gives the two step Newton‟s variant
method as
f xn yn xn
f xn
2 , 0
1
1 1 4
f xn
xn xn n
f xn f yn f xn (2.4)
The simplified form of “(2.4),” can be rewritten as
1 1 1 4
121 2
f xn
x xn n
n f xn n
Expanding
1 4 n
12up to four terms i.e., up to third degree terms ofn, we get the required two step Newton‟s variant method as
f xn yn xn
f xn
21 2 , 0
1
f xn f yn f yn
xn xn n
f xn f xn f xn
(2.5)
3. CONVERGENCE CRITERIA
Theorem 3.1. Let Ibe a simple zero of a sufficiently differentiable function f I: Rfor an open interval I. Then, the new method that is defined by “(2.5),” has the fourth order convergence and satisfies the following error equation,
21 4 3
4
51 c c2 3 c2 n o n
n
Where,
1 1
x
n n and xn
n
V.B. Kumar Vatti et al IJSRE Volume 05 Issue 02 February 2017 Page 6214
2 3 4
52 3 4
f xn f nc n c n c n o n
(3.1)
And
1 2 3 2 4 3 5 4
5 52 3 4
f x n f c n c n c n c n o n (3.2)
Dividing “(3.2),” by“(3.1),” we have
2 2 2
22 3
3 3 4 4 23 7 2 3
4 5f xn c c c c c c c o
n
n n n n
f xn
(3.3)
2 2
2
3
3 4 3 7
4 53 2
2 4 2 2 3
f yn f c n c c n c c c c n on (3.4)
Dividing “(3.4),” by“(3.1),” we obtain
2
23 322
2
10 2 3 34 9 23
3 4 2 4 524 93 23 22 3 2
2
2 4
5 f ync n c c n c c c c n c c c c c c c n o n
f xn
(3.5)
Adding „1‟ on both sides to “(3.5),” we have
2 2 3 3 4 3
2 4
51 f yn 1 c2 n 2c3 3c2 n 10c c2 3 3c4 9c2 n 4c c2 4 5c2 9c c3 2 22 3 2c c 2 n o n
f xn
(3.6)
Multiplying “(3.3),” with “(3.6),” we have
1
2 22 3
13 2 3 6 23
4
5f xn f yn
c c c c o
n n n n
f xn f xn
(3.7)
Multiplying “(3.3),” with “(3.5),” we have
2
2 3 3 4 5
2 f xn f yn 2c2 n 8c c2 3 10c2 n o n f xn f xn
(3.8)
Thus,
2
1 2
1
f xn f yn f yn x xn
n f x f x f x
n n n
becomes
2 2 3 2 2 3
21 4 3
4
51 n n c2 n c2 n c c2 3 c2 n o n
n
3
4
521 4
1 c c2 3 c2 n o n
n
(3.9)
Equation (3.9) establishes the fourth order convergence of the method that is defined by “(2.5)”.
4. NUMERICAL EXAMPLES
We consider few numerical examples considered by [6], [8] and the method “(2.5),” are compared with the methods “(1.2),” “(1.3),” and “(1.4)”. The computational results are tabulated below and the results are correct up to an error less thanas indicated for each of the problems.
Example 1. Consider the following equation f x
ex3x2 0.Table 4.1.The results obtained by four methods for solving f x
ex3x2 0withx00.5and 0.5E20.Formula No. of iterations (n) Root
xn No. of functional valuesNewton 7 0.91000757248870907904 14
Chebyshev --- DIVERGENT ---
V.B. Kumar Vatti et al IJSRE Volume 05 Issue 02 February 2017 Page 6215 Example 2. Consider the following equation f x
x3ex0.Table 4.2.The results obtained by four methods for solving f x
x3ex0withx00.5and 0.5E20.Example 3. Consider the following equation f x
sinx0.5x0.Table 4.3. The results obtained by four methods for solving f x
sinx0.5x0withx03and 0.5E20.Example 4. Consider the following equation f x
x32x 5 0.Table 4.4.The results obtained by four methods for solving f x
x32x 5 0withx03and 0.5E20.Example 5. Consider the following equation f x
sinx0.Table 4.5 The results obtained by four methods for solving f x
sinx0withx00.5and0.5E20.5. CONCLUSION
With the number of iterations and the number of functional evaluations tabulated for each of the methods for five non-linear equations, we conclude that the method “(2.5),” is efficient one compared to the methods considered in this paper.
REFERENCES
1. S.Abbasbandy, “Improving Newton-Raphson method for nonlinear equations by modified Adomian decomposition method”, Applied Mathematics and Computation, Vol. 145, 2003, pp. 887 – 893. 2. Amit kumar Maheshwari, “A fourth order iterative method for solving nonlinear equations”, Applied
Mathematics and computation, Vol.211, 2009, pp. 383-391.
3. Avram Sidi, “Unified treatment of regular falsi, Newton–Raphson, Secant, and Steffensen methods for nonlinear equations”, Journal of Online Mathematics and its Applications. 2006, pp. 1-13.
Formula No. of iterations (n) Root
xn No. of functional valuesNewton 6 0.77288295914921017344 12
Chebyshev 5 0.77288295914921017344 15 Newton‟s variant 5 0.77288295914921017344 15 New Method 3 0.77288295914921017344 9
Formula No. of iterations (n) Root
xn No. of functional valuesNewton 6 1.89549426703398109184 12
Chebyshev 5 1.89549426703398109184 15 Newton‟s variant 5 1.89549426703398109184 15 New Method 3 1.89549426703398109184 9
Formula No. of iterations (n) Root
xn No. of functional values Newton 7 2.09455148154232668160 14Chebyshev 5 2.09455148154232668160 15 Newton‟s variant 5 2.09455148154232668160 15 New Method 3 2.09455148154232668160 9
Formula No. of iterations (n) Root
xn No. of functional valuesNewton 5 0 10
Chebyshev 4 0 12
Newton‟s variant 4 0 12
V.B. Kumar Vatti et al IJSRE Volume 05 Issue 02 February 2017 Page 6216 4. J.M.Gutierrez, M.A.Hernandez, “A family of Chebyshev-Halley type methods in Banach spaces”,
Bull. Aust. Math. Soc. 55, 113-130 (1997).
5. Jinhai Chen, Weiguo Li, “On new exponential quadratically convergent iterative formulae”, Applied Mathematics and Computation, Vol. 180, 2006, pp. 242-246.
6. Nasr Al-Din Ide, “A new Hybrid iteration method for solving algebraic equations”, Applied Mathematics and Computation, Vol. 195, 2008, pp. 772-774.
7. Vatti V.B.Kumar., Ramadevi Sri., Mylapalli M. S. Kumar., “A Newton‟s Variant third order method”, Engineering Science and Technology: An International Journal, Vol. 6, No. 4, 2016. 8. Xing-Guo Luo, “A note on the new iterative method for solving algebraic equation”, Applied