R E S E A R C H
Open Access
An algorithm for treating asymptotically strict
pseudocontractions and monotone operators
Mingliang Zhang
**Correspondence: [email protected] School of Mathematics and Information Science, Henan University, Kaifeng, 475000, China
Abstract
In this paper, an algorithm for treating asymptotically
κ
-strict pseudocontractions and monotone operators is proposed. Convergence analysis of the algorithm isinvestigated in the framework of Hilbert spaces.
Keywords: asymptotically
κ
-strict pseudocontraction; inverse-strongly monotone mapping; maximal monotone operator; fixed point1 Introduction-preliminaries
In this paper, we are concerned with the problem of finding a common element in the intersectionF(T)∩(A+B)–(), whereF(T) denotes the fixed point set of the mappingT and (A+B)–() denotes the zero point set of the sum of the operatorAand the operatorB.
The motivation for the common element problem is mainly due to its possible appli-cations to mathematical modeling of concrete complex problems. The common element problems include mini-max problems, complementarity problems, equilibrium problems, common fixed point problems and variational inequalities as special cases; see, for exam-ple, [–] and the references therein.
Throughout the article, we always assume thatHis a real Hilbert space with the inner product·,·and the norm · , respectively. LetCbe a nonempty closed convex subset ofH, and letProjCbe the metric projection fromHontoC.
LetA:C→Hbe a mapping.A–() stands for the zero point set ofA; that is,A–() := {x∈C:Ax= }. Recall thatAis said to be monotone iff
Ax–Ay,x–y ≥, ∀x,y∈C.
Ais said to beα-strongly monotone iff there exists a constantα> such that
Ax–Ay,x–y ≥αx–y, ∀x,y∈C.
Ais said to beα-inverse-strongly monotone iff there exists a constantα> such that
Ax–Ay,x–y ≥αAx–Ay, ∀x,y∈C.
It is not hard to see thatα-inverse-strongly monotone mappings are Lipschitz continuous. Indeed, we have
αAx–Ay≤ Ax–Ay,x–y ≤ Ax–Ayx–y.
This shows thatAx–Ay ≤ αx–y.
Recall that the classical variational inequality, denoted byVI(C,A), is to findu∈Csuch that
Au,v–u ≥, ∀v∈C. (.)
One can see that the variational inequality (.) is equivalent to a fixed point problem of the mappingProjC(I–rA), whereIis the identity andris some positive real number. The elementu∈Cis a solution of the variational inequality (.) iffu∈Csatisfies the equation u=PC(u–rAu). This alternative equivalent formulation has played a significant role in the studies of variational inequalities and related optimization problems.
A multivalued operatorB:H→Hwith the domainD(B) ={x∈H:Bx=∅}and the rangeR(B) ={Bx:x∈D(B)}is said to be monotone if forx∈D(B),x∈D(B),y∈Bxand
y∈Bx, we havex–x,y–y ≥. A monotone operatorBis said to be maximal if its
graphG(B) ={(x,y) :y∈Bx}is not properly contained in the graph of any other monotone operator. LetIdenote the identity operator onHandB:H→Hbe a maximal monotone operator. Then we can define, for eachr> , a nonexpansive single-valued mappingJr: H→HbyJr= (I+rB)–. It is called the resolvent ofB. We know thatB– =F(Jr) for all r> andJris firmly nonexpansive.
LetT:C→Cbe a mapping. In this paper, we useF(T) to denote the fixed point set ofT; that is,F(T) :={x∈C:x=Tx}. Recall thatT is said to be nonexpansive iff
Tx–Ty ≤ x–y, ∀x,y∈C.
T is said to be asymptotically nonexpansive iff there exists a sequence{kn} ⊂[,∞) such that
Tnx–Tny≤knx–y, ∀x,y∈C,n≥.
Tis said to be aκ-strict pseudocontraction iff there exists a constantκ∈[, ) such that
Tx–Ty≤ x–y+κ(x–Tx) – (y–Ty), ∀x,y∈C.
Note that the class ofκ-strict pseudocontractions strictly includes the class of nonexpan-sive mappings as a special case. That is,T is nonexpansive iff the coefficientκ= .T is said to be an asymptoticallyκ-strict pseudocontraction iff there exist a constantκ∈[, ) and a sequence{kn}in [,∞) such that
Tnx–Tny≤k
nx–y+κx–Tnx
–y–Tny, ∀x,y∈C,n≥.
In [], Kamimura and Takahashi investigated the problem of finding zero points of a maximal monotone operator based on the following iterative algorithm:
x∈H, xn+=αnx+ ( –αn)Jrnxn, ∀n≥, (.)
where{αn}is a sequence in (, ),{rn}is a positive real number sequence,B:H→His maximal monotone andJrn= (I+rnB)–. It is proved that the sequence{xn}generated in
(.) converges strongly to somez∈B–() provided that the control sequence satisfies
some restrictions. Further, using this result, they also investigated the case that B=∂f, wheref :H→(–∞,∞] is a proper lower semicontinuous convex function. Convergence theorems are established in the framework of real Hilbert spaces; for more details, see []. Recently, Takahashiet al.studied zero point problems of the sum of two monotone map-pings and fixed point problems of a nonexpansive mapping based on the following iterative algorithm:
⎧ ⎪ ⎪ ⎨ ⎪ ⎪ ⎩
x∈C,
yn=αnx+ ( –αn)Jrn(xn–rnAxn),
xn+=βnxn+ ( –βn)Tyn, ∀n≥,
(.)
where {αn} and {βn} are real number sequences in (, ), {rn} is a positive sequence, T :C→Cis a nonexpansive mapping andA:C→H is an inverse-strongly monotone mapping. It is proved that the sequence{xn}generated in (.) converges strongly to some z∈(A+B)–()∩F(S) provided that the control sequence satisfies some restrictions; for
more details, see [].
Motivated by the above results, we investigate fixed point problems of asymptotically strict pseudocontractions and zero point problems of the sum of two monotone mappings.
In order to state our main results, we need the following tools.
Recall that a space is said to satisfy Opial’s condition [] if, for any sequence{xn} ⊂H withxnx, wheredenotes the weak convergence, the inequality
lim inf
n→∞ xn–x<lim infn→∞ xn–y
holds for everyy∈Hwithy=x. Indeed, the above inequality is equivalent to the following:
lim sup
n→∞ xn–x<lim supn→∞ xn–y.
Lemma .[] Let{xn}and{yn}be bounded sequences in a Banach space X,and letβn be a sequence in [, ]with <lim infn→∞βn≤lim supn→∞βn< .Suppose that xn+=
( –βn)yn+βnxnfor all integers n≥and
lim sup
n→∞
yn+–yn–xn+–xn
≤.
Thenlimn→∞yn–xn= .
Lemma .[] Assume that{αn}is a sequence of nonnegative real numbers such that
αn+≤( –γn)αn+δn,
where{γn}is a sequence in(, )and{δn}is a sequence such that (i) ∞n=γn=∞;
(ii) lim supn→∞δn/γn≤or ∞n=|δn|<∞. Thenlimn→∞αn= .
Lemma .[] Let C be a nonempty,closed and convex subset of H.Let T:C→C be an asymptotically strict pseudocontraction.Then T is Lipschitz continuous and I–T is demiclosed at zero.
2 Main results
Theorem . Let C be a nonempty closed convex subset of H.Let T:C→C be an asymp-totically κ-strict pseudocontraction. Let A:C→H be an α-inverse-strongly monotone mapping, and let B be a maximal monotone operator on H.Assume that F(T)∩(A+ B)–()=∅.Let{αn},{βn}and{γn}be real number sequences in(, ).Let Jrn= (I+rnB)–,
where{rn}is a positive real number sequence.Let{xn}be a sequence in C generated by: x∈C is chosen arbitrarily and
⎧ ⎨ ⎩
zn=ProjC(αnu+ ( –αn)Jrn(xn–rnAxn)),
xn+=βnxn+ ( –βn)(γnzn+ ( –γn)Tnzn), ∀n≥.
Assume that the sequences{αn},{βn},{γn}and{rn}satisfy the following restrictions: (a) <a≤rn≤b< α,limn→∞|rn+–rn|= ;
(b) limn→∞αn= , ∞n=αn=∞; (c) <c≤βn≤d< ;
(d) κ≤γn≤e< ,limn→∞|γn+–γn|= ,
where a,b,c,d and e are some real numbers.If T is asymptotically regular,then the se-quence{xn}converges strongly to some pointx,¯ wherex¯=PF(T)∩(A+B)–()u.
Proof First, we show that the mappingI–rnAis nonexpansive. Indeed, we have
(I–rnA)x– (I–rnA)y
=x–y– rnx–y,Ax–Ay+rnAx–Ay
≤ x–y–rn(α–rn)Ax–Ay.
It follows from Restriction (a) thatI–rnAis nonexpansive. Putyn=γnzn+ ( –γn)Tnzn and fixp∈F(T)∩(A+B)–(). It follows from Lemma . that
zn–p=ProjCαnu+ ( –αn)Jrn(xn–rnAxn)
–p
≤αnu–p+ ( –αn)Jrn(xn–rnAxn) –p
In view of Restriction (d), we find that
yn–p≤γn(zn–p) + ( –γn)
Tnzn–Tnp
=γnzn–p+ ( –γn)Tnzn–Tnp
–γn( –γn)(zn–p) –Tnzn–Tnp
≤γnzn–p+ ( –γn)
zn–p+κ(zn–p) –Tnzn–Tnp
–γn( –γn)(zn–p) –Tnzn–Tnp
=zn–p– ( –γn)(γn–κ)(zn–p) –
Tnzn–Tnp
≤ zn–p. (.)
Substituting (.) into (.), we obtain that
xn+–p ≤βnxn–p+ ( –βn)yn–p
≤βnxn–p+ ( –βn)
αnu–p+ ( –αn)xn–p
≤ –αn( –βn)
xn–p+αn( –βn)u–p.
PuttingM=max{x–p,u–p}, we find thatxn–p ≤Mfor alln≥. Indeed, it is
clear thatx–p ≤M. Suppose thatxm–p ≤Mfor some positive integerm. It follows
that
xm+–p ≤
–αm( –βm)xm–p+αm( –βm)u–p
≤ –αm( –βm)
M+αm( –βn)M
=M.
This finds that{xn}is bounded. Puttingρn=Jrn(xn–rnAxn), we find that
ρn+–ρn ≤Jrn+(xn+–rn+Axn+) –Jrn+(xn–rnAxn)
+Jrn+(xn–rnAxn) –Jrn(xn–rnAxn)
≤(xn+–rn+Axn+) – (xn–rnAxn)
+Jrn+(xn–rnAxn) –Jrn(xn–rnAxn)
≤ xn+–xn+|rn+–rn|Axn
+Jrn+(xn–rnAxn) –Jrn(xn–rnAxn). (.)
On the other hand, we have
zn+–zn ≤αn+u+ ( –αn+)ρn+
–αnu+ ( –αn)ρn
Substituting (.) into (.), we find that
zn+–zn ≤αn+u+ ( –αn+)ρn+
–αnu+ ( –αn)ρn
≤( –αn+)xn+–xn+|rn+–rn|Axn+|αn+–αn|ρn–u
+ ( –αn+)Jrn+(xn–rnAxn) –Jrn(xn–rnAxn). (.)
Putξn=xn–rnAxn. SinceBis monotone, we find that
Jrn+ξn–Jrnξn,
ξn–Jrn+ξn rn+
–ξn–Jrnξn rn
≥.
It follows thatJrn+ξn–Jrnξn, ( –
rn+
rn )(ξn–Jrnξn) ≥ Jrn+ξn–Jrnξn
. This yields that|rn +–
rn|ξn–Jrnξn ≥rnJrn+ξn–Jrnξn. This combines with (.) to yield that
zn+–zn ≤( –αn+)xn+–xn+|rn+–rn|Axn
+|αn+–αn|ρn–u+|
rn+–rn|
rn ξn–Jrnξn. (.)
On the other hand, we have
yn+–yn ≤γn+zn+–zn+|γn+–γn|zn–Tnzn
+ ( –γn+)Tn+zn+–Tnzn. (.)
Substituting (.) into (.), we find that
yn+–yn–xn+–xn
≤ |rn+–rn|Axn+|αn+–αn|ρn–u
+|rn+–rn| rn
ξn–Jrnξn+|γn+–γn|zn–T
nzn
+ ( –γn+)Tn+zn+–Tnzn.
It follows from Restrictions (a), (c) and (d) that
lim sup
n→∞
yn+–yn–xn+–xn
≤.
It follows from Lemma . thatlimn→∞yn–xn= . Sincexn+–xn= ( –βn)(yn–xn), we find thatlimn→∞xn+–xn= . Notice that
Jrn(I–rnA)xn–Jrn(I–rnA)p
=(xn–p) –rn(Axn–Ap)
=xn–p– rnxn–p,Axn–Ap+rnAxn–Ap
Since the norm is convex, we see from (.) and (.) that
xn+–p≤βnxn–p+ ( –βn)yn–p
≤βnxn–p+ ( –βn)zn–p
≤βnxn–p+ ( –βn)αn(u–p) + ( –αn)
Jrn(xn–rnAxn) –p
≤βnxn–p+αn( –βn)u–p
+ ( –αn)( –βn)Jrn(xn–rnAxn) –p
≤ xn–p+αnu–p–rn(α–rn)( –αn)( –βn)Axn–Ap. (.)
This yields that
rn(α–rn)( –αn)( –βn)Axn–Ap
≤ xn–p+αnu–p–xn+–p ≤xn–p+xn+–p
xn+–xn+αnu–p.
In view of Restrictions (a), (b) and (c), we obtain that
lim
n→∞Axn–Ap= . (.)
Notice that
ρn–p=Jrn(xn–rnAxn) –Jrn(p–rnAp)
≤(xn–rnAxn) – (p–rnAp),ρn–p
=
(xn–rnAxn) – (p–rnAp)
+ρn–p
–(xn–rnAxn) – (p–rnAp) – (ρn–p)
≤
xn–p+ρn–p–xn–ρn–rn(Axn–Ap)
≤
xn–p+ρn–p–xn–ρn–rnAxn–Ap
+ rnxn–ρnAxn–Ap
≤
xn–p+ρn–p–xn–ρn+ rnxn–ρnAxn–Ap
.
It follows that
ρn–p≤ xn–p–xn–ρn+ rnxn–ρnAxn–Ap. (.)
This yields that
zn–p≤αnu–p+ ( –αn)ρn–p
It follows from (.) that
xn+–p≤βnxn–p+ ( –βn)yn–p
≤βnxn–p+ ( –βn)zn–p
≤ xn–p+αnu–p– ( –αn)( –βn)xn–ρn
+ rn( –βn)xn–ρnAxn–Ap.
We therefore obtain that
( –αn)( –βn)xn–ρn
≤ xn–p+αnu–p–xn+–p
+ rn( –βn)xn–ρnAxn–Ap
≤xn–p+xn+–p
xn–xn++αnu–p
+ rn( –βn)xn–ρnAxn–Ap.
In view of Restrictions (a), (b) and (c), we find from (.) that
lim
n→∞xn–ρn= . (.)
Next, we show thatlim supn→∞u–x,¯ ρn–x¯ ≤, wherex¯=PF(T)∩(A+B)–()u. To show it, we can choose a subsequence{ρni}of{ρn}such that
lim sup
n→∞
u–x,¯ ρn–x¯=lim
i→∞u–x,¯ ρni–x¯.
Sinceρniis bounded, we can choose a subsequence{ρnij}of{ρni}which converges weakly
to some pointx. We may assume, without loss of generality, thatρniconverges weakly tox.
Sinceρn=Jrn(xn–rnAxn), we find that
xn–ρn
rn –Axn∈Bρn. SinceBis monotone, we get, for
any (μ,ν)∈B, thatρn–μ,xn–rnρn–Axn–ν ≥. Replacingnbyniand lettingi→ ∞, we obtain from (.) thatx–μ, –Ax–ν ≥. This means –Ax∈Bx, that is, ∈(A+B)(x). Hence we getx∈(A+B)–(). Next, we show thatx∈F(T). Notice that
zn–xn ≤ProjCαnu+ ( –αn)Jrn(xn–rnAxn)
–xn
≤αnu–xn+ ( –αn)Jrn(xn–rnAxn) –xn.
In view of Restriction (a), we find from (.) thatlimn→∞zn–xn= . Note that
γnxn+ ( –γn)Tnxn
–xn
≤γnxn+ ( –γn)Tnxn
–γnzn+ ( –γn)Tnzn
+γnzn+ ( –γn)Tnzn–xn
≤γnxn–zn+ ( –γn)Tnxn–Tnzn+γnzn+ ( –γn)Tnzn
–xn
It follows from (.) that
lim
n→∞γnxn+ ( –γn)T
nx n
–xn= . (.)
Note that
Tnxn–xn≤Tnxn–γnxn+ ( –γn)Tnxn
+γnxn+ ( –γn)Tnxn–xn
≤γnTnxn–xn+γnxn+ ( –γn)Tnxn
–xn.
It follows that ( –γn)Tnxn–xn ≤ (γnxn+ ( –γn)Tnxn) –xn. This implies from Restric-tion (d) and (.) thatlimn→∞Tnxn–xn= . SinceTis uniformlyL-Lipschitz continu-ous, we can obtain thatlimn→∞Txn–xn= . In view of Lemma ., we find thatx∈F(T). This implies that
lim sup
n→∞
u–x,¯ ρn–x¯=u–x,¯ x–x¯ ≤.
On the other hand, we have
xn+–x¯≤βnxn–x¯+ ( –βn)yn–x¯
≤βnxn–x+ ( –βn)zn–x¯
≤βnxn–x+ ( –βn)αn(un–x) + ( –¯ αn)(ρn–x)¯
≤βnxn–x+ ( –αn)( –βn)ρn–x
+ αn( –βn)u–x,¯ ρn–x
≤ –αn( –βn)xn–x¯+ αn( –βn)u–x,¯ ρn–x¯.
From Lemma ., we find thatlimn→∞xn–x¯= . This completes the proof. IfT is asymptotically nonexpansive, then we find the following result.
Corollary . Let C be a nonempty closed convex subset of H.Let T:C→C be an asymp-totically nonexpansive mapping.Let A:C→H be anα-inverse-strongly monotone map-ping,and let B be a maximal monotone operator on H.Assume that F(T)∩(A+B)–()=∅. Let{αn}and{βn}be real number sequences in(, ).Let Jrn= (I+rnB)–,where{rn}is a
positive real number sequence.Let{xn}be a sequence in C generated by:x∈C is chosen
arbitrarily and
⎧ ⎨ ⎩
zn=PC(αnu+ ( –αn)Jrn(xn–rnAxn)),
xn+=βnxn+ ( –βn)Tnzn, ∀n≥.
Assume that the sequences{αn},{γn}and{rn}satisfy the following restrictions: (a) <a≤rn≤b< α,limn→∞|rn+–rn|= ;
where a,b,c and d are some real numbers.If T is asymptotically regular,then the sequence
{xn}converges strongly to some pointx,¯ wherex¯=PF(T)∩(A+B)–()u.
3 Applications
In this section, we shall consider equilibrium problems and variational inequalities. LetFbe a bifunction ofC×CintoR, whereRdenotes the set of real numbers. Recall the following equilibrium problem:
Findx∈Csuch thatF(x,y)≥, ∀y∈C.
In this work, we useEP(F) to denote the solution set of the equilibrium problem. To study the equilibrium problems, we may assume thatFsatisfies the following condi-tions:
(A) F(x,x) = for allx∈C;
(A) Fis monotone,i.e.,F(x,y) +F(y,x)≤for allx,y∈C; (A) for eachx,y,z∈C,
lim sup
t↓
Ftz+ ( –t)x,y≤F(x,y);
(A) for eachx∈C,y→F(x,y)is convex and weakly lower semi-continuous.
PuttingF(x,y) =Ax,y–xfor everyx,y∈C, we see that the equilibrium problem is reduced to the variational inequality (.).
The following lemma can be found in [].
Lemma . Let C be a nonempty closed convex subset of H,and let F:C×C→Rbe a bifunction satisfying(A)-(A).Then,for any r> and x∈H,there exists z∈C such that
F(z,y) +
ry–z,z–x ≥, ∀y∈C.
Further,define
Trx=
z∈C:F(z,y) +
ry–z,z–x ≥,∀y∈C
(.)
for all r> and x∈H.Then the following hold: (a) Tris single-valued;
(b) Tris firmly nonexpansive,i.e.,for anyx,y∈H,
Trx–Try≤ Trx–Try,x–y;
(c) F(Tr) =EP(F);
(d) EP(F)is closed and convex.
mapping of H into itself defined by
AFx=
⎧ ⎨ ⎩
{z∈H:F(x,y)≥ y–x,z,∀y∈C}, x∈C,
∅, x∈/C. (.)
Then AFis a maximal monotone operator with the domain D(AF)⊂C,EP(F) =A–
F ()and
Trx= (I+rAF)–x, ∀x∈H,r> ,
where Tris defined as in(.).
The following result is not derived based on Theorem . and Lemma ..
Theorem . Let C be a nonempty closed convex subset of H.Let T:C→C be an asymp-toticallyκ-strict pseudocontraction.Let F be a bifunction from C×C toRwhich satisfies (A)-(A).Assume that F(T)∩EP(F)=∅.Let{αn},{βn}and{γn}be real number sequences in(, ).Let{xn}be a sequence in C generated by:x∈C is chosen arbitrarily and
⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩
wn∈C such that FB(wn,u) +rnu–wn,wn–xn ≥, ∀u∈C,
zn=PC(αnu+ ( –αn)wn),
yn=γnzn+ ( –γn)Tnzn,
xn+=βnxn+ ( –βn)yn, ∀n≥.
Assume that the sequences{αn},{βn},{γn}and{rn}satisfy the following restrictions: (a) <a≤rn≤b< α,limn→∞|rn+–rn|= ;
(b) limn→∞αn= , ∞n=αn=∞; (c) <c≤βn≤d< ;
(d) κ≤γn≤e< ,limn→∞|γn+–γn|= ,
where a,b,c,d and e are some real numbers.If T is asymptotically regular,then the se-quence{xn}converges strongly to some pointx,¯ wherex¯=PF(T)∩EP(F)u.
IfT is asymptotically nonexpansive, then Theorem . is reduced to the following.
Corollary . Let C be a nonempty closed convex subset of H.Let T:C→C be an asymp-totically nonexpansive mapping.Let F be a bifunction from C×C toRwhich satisfies (A)-(A).Assume that F(T)∩EP(F)=∅.Let{αn}and{βn}be real number sequences in(, ). Let{xn}be a sequence in C generated by:x∈C is chosen arbitrarily and
⎧ ⎪ ⎪ ⎨ ⎪ ⎪ ⎩
wn∈C such that FB(wn,u) +rnu–wn,wn–xn ≥, ∀u∈C,
zn=PC(αnu+ ( –αn)wn),
xn+=βnxn+ ( –βn)Tnzn, ∀n≥.
Assume that the sequences{αn},{βn},{γn}and{rn}satisfy the following restrictions: (a) <a≤rn≤b< α,limn→∞|rn+–rn|= ;
where a,b,c and d are some real numbers.If T is asymptotically regular,then the sequence
{xn}converges strongly to some pointx,¯ wherex¯=PF(T)∩EP(F)u.
LetHbe a Hilbert space andf :H→(–∞, +∞] be a proper convex lower semicontin-uous function. Then the subdifferential∂f off is defined as follows:
∂f(x) =y∈H:f(z)≥f(x) +z–x,y,z∈H, ∀x∈H.
From Rockafellar [], we find that∂f is maximal monotone. It is easy to verify that ∈
∂f(x) if and only iff(x) =miny∈Hf(y). LetICbe the indicator function ofC,i.e.,
IC(x) =
⎧ ⎨ ⎩
, x∈C,
+∞, x∈/C.
SinceICis a proper lower semicontinuous convex function onH, we see that the subdif-ferential∂ICofICis a maximal monotone operator.
Lemma .[] Let C be a nonempty closed convex subset of a real Hilbert space H,ProjC
the metric projection from H onto C,∂ICthe subdifferential of IC,where ICis defined above and Jλ= (I+λ∂IC)–.Then
y=Jλx ⇐⇒ y=ProjCx, x∈H,y∈C. Now, we consider a variation inequality problem.
Theorem . Let C be a nonempty closed convex subset of H.Let T:C→C be an asymp-totically κ-strict pseudocontraction. Let A:C→H be an α-inverse-strongly monotone mapping.Assume that F(T)∩VI(C,A)=∅.Let{αn},{βn} and{γn}be real number se-quences in(, ).Let{xn}be a sequence in C generated by:x∈C is chosen arbitrarily and
⎧ ⎪ ⎪ ⎨ ⎪ ⎪ ⎩
zn=PC(αnu+ ( –αn)PC(xn–rnAxn)),
yn=γnzn+ ( –γn)Tnzn,
xn+=βnxn+ ( –βn)yn, ∀n≥.
Assume that the sequences{αn},{βn},{γn}and{rn}satisfy the following restrictions: (a) <a≤rn≤b< α,limn→∞|rn+–rn|= ;
(b) limn→∞αn= , ∞n=αn=∞; (c) <c≤βn≤d< ;
(d) κ≤γn≤e< ,limn→∞|γn+–γn|= ,
where a,b,c,d and e are some real numbers.If T is asymptotically regular,then the se-quence{xn}converges strongly to some pointx,¯ wherex¯=PF(T)∩VI(C,A)u.
Proof PutBx=∂IC. Next, we show thatVI(C,A) = (A+∂IC)–(). Notice that
x∈(A+∂IC)–() ⇐⇒ ∈Ax+∂ICx
⇐⇒ Ax,y–x ≥
⇐⇒ x∈VI(C,A).
From Lemma ., we can conclude the desired conclusion immediately.
Competing interests
The author declares that they have no competing interests.
Acknowledgements
The author is grateful to the referees for useful suggestions which improved the contents of the article.
Received: 16 December 2013 Accepted: 13 February 2014 Published:27 Feb 2014
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