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R E S E A R C H

Open Access

Parallel hybrid viscosity method for fixed

point problems, variational inequality

problems and split generalized equilibrium

problems

Qingqing Cheng

1*

*Correspondence:

[email protected]

1Department of Science, Tianjin

University of Commerce, Tianjin, P.R. China

Abstract

In this paper, we first propose a new parallel hybrid viscosity iterative method for finding a common element of three solution sets: (i) finite split generalized equilibrium problems; (ii) finite variational inequality problems; and (iii) fixed point problem of a finite collection of demicontractive operators. And we prove that the sequence generated by the iterative scheme strongly converges to a common solution of the above-mentioned problems. Also, we present numerical examples to demonstrate the effectiveness of our algorithm. Our results presented in this paper improve and extend many recent results in the literature.

Keywords: Split generalized equilibrium problems; Variational inequality problems; Fixed point problems; Parallel hybrid viscosity method; Lipschitzian mappings

1 Introduction

LetH1andH2be two infinite dimensional real Hilbert space with inner product and norm

denoted by·,·and · , respectively. LetCandQbe a nonempty closed convex subset

ofH1 andH2, respectively. LetT:CCbe a mapping. The set of fixed points ofT is

denoted byF(T), that is,F(T) ={xC:Tx=x}.

In what follows, we recall some definitions of classes of operators often used in fixed point theory.

Definition 1.1 LetT:CCbe a mapping. Then

(i) T isρ-Lipschitzianwithρ> 0if

TxTyρxy, ∀x,yC;

Ifρ∈(0, 1), thenTisρ-contractiveand ifρ= 1, thenTisnonexpansive. (ii) T isfirmly nonexpansiveif

TxTy2≤ xy2–(IT)x– (IT)y2, ∀x,yC;

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(iii) Tisκ-strictly pseudo-contractivewithκ∈[0, 1)if

TxTy2≤ xy2+κ(IT)x– (IT)y2, ∀x,yC.

Definition 1.2 LetT:CCbe a mapping withF(T)=∅. Then

(i) Tisdirectedif

Txz2≤ xz2–xTx2, ∀zF(T),xC;

(ii) Tisquasi-nonexpansiveif

Txzxz, ∀zF(T),xC;

(iii) Tisβ-demicontractivewithβ< 1if

Txz2≤ xz2+βxTx2, ∀zF(T),xC.

Note that the class of demicontractive operators contains important classes of operators:

directed operator (firmly nonexpansive operator with nonempty fixed points set) forβ=

–1, quasi-nonexpansive operator (nonexpansive operator with nonempty fixed points set)

forβ = 0, and strictly pseudo-contractive operator with nonempty fixed points set for

β∈(0, 1); the class of quasi-nonexpansive operators also contains nonspreading mappings

with nonempty fixed point set andN-generalized hybrid mappings with nonempty fixed

point set.

It is well known that every nonexpansive operatorT:H1H1satisfies the following

inequality;

(IT)x– (IT)y,TyTx≤1

2(IT)y– (IT)x

2

,

for allx,yH1. Therefore, for allxH1,yF(T),

(IT)x,yTx≤1

2(TI)x

2

. (1.1)

We also know thatF(T) of nonexpansive mappingTis closed and convex.

The fixed point problem (FPP) for the mappingTis to findxCsuch that

Tx=x.

Many iterative algorithms has been introduced for finding fixed points of nonexpansive mappings, quasi-nonexpansive mappings, firmly nonexpansive mappings,

demicontrac-tive mappings (see [1–6]), including the since recently popular viscosity iterative

algo-rithms, which formally consist of the sequence{xn}given by the iteration

xn+1=αnf(xn) + (1 –αn)Txn, ∀n≥0, (1.2)

wheref is a contraction,{αn} ⊂(0, 1) is a slowly vanishing sequence, i.e.,limn→∞αn= 0

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whenf =μ(μbeing any given element), in 1967 by Halpern [7] (forμ= 0). There is an

extensive literature regarding the convergence analysis of (1.2), with several types of

oper-atorT, in the setting of Hilbert spaces and Banach spaces. This procedure can be regarded

as a regularization process for fixed point iterations which is supposed to induce the con-vergence in norm of the iterates. Another advantage of this method is that it allows one to

select a particular fixed point ofTwhich satisfies some variational inequality.

Given a nonlinear mappingB:CH1. Recall thatBis said to be monotone if

xy,BxBy ≥0, ∀x,yC;

Bis said to beα-strongly monotone if there existsα> 0 such that

xy,BxByαxy2, ∀x,yC;

Bis said to beα-inverse strongly monotone (for short,α-ism) if there existsα> 0 such

that

xy,BxByαBxBy2, ∀x,yC.

We can easily see that

(i) ifBis nonexpansive, thenIBis monotone;

(ii) ifBis anα-inverse-strongly monotone mapping, then it must be aα1-Lipschitz operator. Moreover,IrBis nonexpansive when0 <r≤2α.

The variational inequality problem (VIP) is to findxCsuch that

Bx,yx ≥0, ∀yC. (1.3)

The solution set of (1.3) is denoted byVI(C,B). In fact,

x∗∈VI(C,B)

Bx∗,yx∗≥0, ∀yC

–λBx∗,yx∗≤0, ∀λ> 0,∀yC

IλBxx∗–x∗,yx∗≤0, ∀λ> 0,∀yC

IλBxx∗–x∗,x∗–y≥0, ∀λ> 0,∀yC

x∗=PC(IλB)x∗, ∀λ> 0.

It is well known that ifBis strongly monotone and Lipschitz continuous mapping onC,

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this problem in finite dimensional and infinite dimensional spaces see [8–14] and the re-search in this direction is intensively continued.

The equilibrium problem for a bifunctionf :C×CRis to find a pointxCsuch

that

f(x,y)≥0, ∀yC. (1.4)

We denoteEP(f) by the solution set of (1.4). It is easy to see thatEP(f) =VI(C,B) when

f(x,y) =Bx,yxfor allx,yC. Leth:C×CRbe a nonlinear bifunction, then the

generalized equilibrium problem (GEP) is to findx∗∈Csuch that

fx∗,x+hx∗,x≥0, ∀xC. (1.5)

We denote the solution set of generalized equilibrium problem (1.5) byGEP(f,h). Note

that this problem reduces to the equilibrium problem when the bifunction his a zero

mapping; this problem reduces to the mixed equilibrium problem when the bifunction

h(x∗,x) =ϕ(x) –ϕ(x∗), whereϕ:CR∪ {+∞}is for proper lower semicontinuous and

convex functions.

The split generalized equilibrium problem (SGEP) introduced by Kazmi and Rizvi [15]

in 2013 is the following problem: findx∗∈C

fx∗,x+hx∗,x≥0, ∀xC,

such that

y∗=Ax∗∈Q solves Fy∗,y+Hy∗,y≥0, ∀yQ,

wheref,h:C×CRandF,H:Q×QRare four nonlinear bifunctions andA:H1

H2is a bounded linear operator. The solution set of the split generalized equilibrium

prob-lem SGEP is denoted by

Ω=x∗∈GEP(f,h) :Ax∗∈GEP(F,H) .

IfH= 0 andF= 0, then the split generalized equilibrium problem reduces to the

gener-alized equilibrium problem considered by Cianciaruso et al. [16]; Ifh= 0 andH= 0, then

the split generalized equilibrium problem reduces to the split equilibrium problem

intro-duced in 2011 by Moudafi [17]; ifh=ϕ(·,·) andH=φ(·,·), whereϕ:CR∪ {+∞}and

φ:QR∪ {+∞}are proper lower semicontinuous and convex functions, then the split

generalized equilibrium problem reduces to the split mixed equilibrium problem (SEP). In this paper, we are interested in finding the common solution for a finite family of the

split generalized equilibrium problems, that is, find ax∗∈C,

fi

x∗,x+hi

x∗,x≥0, ∀xC,

such that

y∗=Aix∗∈Q solves Fi

y∗,y+Hi

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wherefi,hi:C×CRandFi,Hi:Q×QRare nonlinear bifunctions,Ai:H1H2

is a bounded linear operator, for 1≤iN1.

In 2017, Majee and Nahak [18] introduced a hybrid viscosity iterative method to

ap-proximate a common solution of a split equilibrium problem and a fixed point problem of

a finite collection of nonexpansive mappings; Onjai-uea and Phuengrattana [19] studied

iterative algorithms for solving split mixed equilibrium problems and fixed point

prob-lems of hybrid multivalued mappings in real Hilbert spaces; Sitthithakerngkiet et al. [20]

proposed an iterative method for finding a common solution of a single split generalized equilibrium problem, variational inequality problem and fixed point problem of nonex-pansive mapping in Hilbert spaces. For recent developments in the analysis technique and

algorithm design, see [21–25] and the references therein.

Motivated by the above related results in this field, in this paper, we first propose a new parallel hybrid viscosity method for finding a common element of the set of solutions of a finite family of split generalized equilibrium problems, variational inequality problems and the set of common fixed points of a finite family of demicontractive operators in Hilbert spaces.

The rest of the paper is organized as follows: Sect.2describes several definitions and

lemmas which will be used in proving our main results; Sect.3presents a new parallel

hy-brid viscosity method for finding a common element of the set of solutions of a finite family of split generalized equilibrium problems, variational inequality problems and the set of common fixed points of a finite family of demicontractive operators in Hilbert spaces, and establish the corresponding strong convergence theorem under suitable conditions.

Section4gives numerical examples to demonstrate the convergence of our algorithm.

2 Preliminaries

Throughout the paper, let the symbol→and denote strong convergence and weak

convergence, respectively. In addition,F(T) and ωw(xn) denote the fixed point set ofT

and the weakω-limit set of the sequence{xn}, respectively, that is,F(T) ={x:Tx=x}and

ωw(xn) ={u:∃xnju}. In order to prove our main results, we recall some basic definitions and lemmas, which will be needed in the sequel.

Definition 2.1([26]) Assume thatT:HHis a nonlinear operator, thenIT is said

to be demiclosed at zero if for any sequence{xn}inH, the following implication holds:

xnx and (IT)xn→0 ⇒ xF(T).

Lemma 2.2([27]) Let C be a nonempty closed convex subset of a real Hilbert spaceH,and let U:CC be aβ-strict pseudo-contractive.Then IU is demiclosed at0.

Lemma 2.3 ([28]) Suppose that U:HHis aβ-demicontractive mapping.Then the fixed point set F(U)of U is closed and convex.

Recall thatPC is the metric projection fromHintoC, then, for each pointxH, the

unique pointPCxCsatisfies the property:

xPCx=inf

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Lemma 2.4([29]) For a given xH:

(i) z=PCxif and only ifxz,zy ≥0,∀yC;

(ii) z=PCxif and only ifxz2≤ xy2–yz2,∀x,yC;

(iii) PCxPCy,xyPCxPCy2,∀x,yH.

It is obvious thatPCis nonexpansive and monotone.

Lemma 2.5([30]) Let f :C×CR be a bifunction satisfying the following assumptions:

(i) f(x,x)≥0,∀xC;

(ii) f is monotone,that is,f(x,y) +f(y,x)≤0,∀x,yC; (iii) f is upper hemicontinuous,that is,for eachx,y,zC,

lim sup

t→0

ftz+ (1 –t)x,y)≤f(x,y);

(iv) For eachxCfixed,the functionyf(x,y)is convex and lower semicontinuous.

Suppose that h:C×CR is a bifunction satisfying the following assumptions:

(i) h(x,x)≥0,∀xC;

(ii) for eachyCfixed,the functionxh(x,y)is upper semicontinuous;

(iii) for eachxCfixed,the functionyh(x,y)is convex and lower semicontinuous.

Then,for fixed r> 0and zC,there exist a nonempty compact convex subset K ofH1 and xCK such that

f(y,x) +h(y,x) +1

ryx,xz< 0, ∀yC\K.

Lemma 2.6 Assume that f,h:C×CR satisfying Lemma2.5.Let r> 0and xH1,

Then there exists zC such that

f(z,y) +h(z,y) +1

ryz,zx ≥0, ∀yC.

Lemma 2.7([31]) Assume that f,h:C×CR satisfying Lemma2.5and h is monotone.

For r> 0and xH1,define the mapping Trf,h:H1C as follows:

Trf,h(x) :=

zC:f(z,y) +h(z,y) +1

ryz,zx ≥0,∀yC

.

Then the following statements hold:

(i) Trf,his single-valued;

(ii) Trf,his firmly nonexpansive,that is,

Trf,h(x) –Trf,h(y)2≤Trf,h(x) –Trf,h(y),xy, ∀x,yH1;

(iii) F(Trf,h) =GEP(f,h);

(iv) GEP(f,h)is compact and convex.

LetF,H:Q×QRsatisfying Lemma2.5. From the previous lemma, we can define a

mappingTsF,H:H2Qas follows:

TsF,H(w) :=

dQ:F(d,e) +H(d,e) +1

sed,dw ≥0,∀eQ

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where s> 0 and wH2, Then TF,H

s :H2Q also satisfies the same properties in

Lemma 2.7. Further, it is easy to prove thatΩ is a closed and convex set. We see that

Lemma 3.5 in [16] is a special case of Lemmas2.6and2.7; for more details see [32].

Lemma 2.8([33]) Let{Bi}Ni=1be a finite family of inverse strongly monotone mappings from C toHwith the constants{βi}Ni=1 and assume that

N

i=1VI(C,Bi)=∅.Let B=

N i=1αiBi, {αi}Ni=1⊂(0, 1)and

N

i=1αi= 1.Then B:CHis aβ-inverse strongly monotone mapping

withβ=min{β1, . . . ,βN}andVI(C,B) =

N

i=1VI(C,Bi).

A linear bounded operatorA:HHis calledstrongly positiveif and only if there exists

γ > 0 such thatAx,xγx2for allxH. and we call such anAa strongly positive

operator with coefficientγ.

Lemma 2.9([34]) LetHbe a Hilbert space and let A be a strongly positive bounded linear operator onHwith coefficientγ > 0.If0 <δA–1,thenIδA1 –δγ.

Lemma 2.10([18]) LetHbe a Hilbert space.Let f :CC be aρ-Lipschitzian mapping and A:HHbe a strongly positive bounded linear operator with coefficientδ> 0.If

μδ>ηρ,then

Aηf)x– (μAηf)y,xy≥(μδ–ηρ)xy2

for all x,yH.That is,μAηf is strongly monotone with coefficientμδηρ.

Lemma 2.11([35]) The following inequality holds in a Hilbert spaceH:

x+y2≤ x2+ 2y,x+y, ∀x,yH.

Lemma 2.12([36]) For each x1, . . . ,xmHandα1, . . . ,αm∈[0, 1]with

n

i=1αi= 1,we

have the equality

α1x1+· · ·+αmxm2= m

i=1

αixi2–

1≤i<jm

αiαjxixj2.

Lemma 2.13([37]) Let{an}be a sequence of non-negative real numbers,such that there

exists a subsequence{anj}of{an},such that anj<anj+1 for all jN.Then there exists a

nondecreasing sequence{mk}of N,such thatlimk→∞mk=∞,and the following properties

are satisfied by all(sufficiently large)numbers kN:

amkamk+1 and akamk+1.

In fact,mkis the largest number n in the set{1, 2, . . . ,k},such that anan+1.

Lemma 2.14([38]) Let{sn}be a sequence of non-negative real numbers satisfying

sn+1≤(1 –αn)sn+αnβn+γn, n≥0,

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(i) {αn} ⊂[0, 1],

n=1αn=∞,or equivalently,

n=1(1 –αn) = 0;

(ii) lim supn→∞βn≤0;

(iii) γn≥0(n≥0),

n=1γn<∞.

Thenlimn→∞sn= 0.

3 Main results

Theorem 3.1 LetH1andH2be two real Hilbert space.Let C and Q be nonempty,closed

and convex subsets ofH1 andH2, respectively. Let Ai:H1H2 be a bounded linear

operator and Ai :H2H1 be the adjoint of Ai. Assume that fi,hi:C×CR and

Fi,Hi:Q×QR are bifunctions satisfying Lemma2.5;hi,Hiare monotone and Fiis upper

semicontinuous for1≤iN1.Let Sj:CC be aκj-demicontractive mappings such that

SjI is demiclosed at0for all1≤jN2.Bl:CH1is aσl-inverse strongly monotone

operator for all1≤lN3.Suppose thatΓ =N1i=1Ωi∩(

N2

j=1F(Sj))∩(

N3

l=1VI(C,Bl))=∅.

Let f :H1H1 be a Lipschitzian mapping with coefficientρ≥0.Let L:H1H1 be a strongly positive bounded linear operator with coefficientδ> 0.Let{xn}be a sequence

generated from an arbitrary x1∈H1by the following algorithm:

⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩

ωn,i=Trfin,,hii(xn+ξn,iAi(T Fi,Hi

rn,iI)Aixn),

ωn=ωn,in, in=arg max1≤iN1{ωn,ixn},

zn,j=βn,jωn+ (1 –βn,j)Sjωn,

yn=PC(Iλn(

N3 l=1μlBl))(

N2 j=1νn,jzn,j),

xn+1=αnγf(xn) + (IαnηL)yn.

(3.1)

Also,the following conditions are satisfied:

(i) ηδ>γρ; (ii) μl∈(0, 1),

N3 l=1μl= 1;

(iii) {αn} ⊂(0, 1),limn→∞αn= 0,

n=1αn=∞;

(iv) rn,i⊂(0,∞),lim infn→∞rn,i> 0;

(v) {βn,j} ⊂(0, 1),{νn,j} ⊂(0, 1),

N2

j=1νn,j= 1,forn≥1.

lim infn→∞νn,j(1 –βn,j)(βn,jκj) > 0forj∈ {1, . . . ,N2};

(vi) 0 <lim infn→∞ξn,i≤lim supn→∞ξn,i<A22 for1≤iN1;

(vii) 0 <lim infn→∞λn≤lim supn→∞λn< 2σ,σ=max1≤lN3{σl}.

Then{xn}converges strongly to a point x∗∈Γ,which is the unique solution of the following

variational inequality:

Lγf)x∗,x∗–x≤0, ∀xΓ. (3.2)

Equivalently,we have x∗=(IηL+γf)x∗.

Proof First, we show the uniqueness of the solution of the variational inequality(3.2). We

show it by contradiction. Supposexˆ∈Γ andx˜∈Γ be two solution of (3.2) withxˆ=x˜.

Then we have

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and

Lγf)x˜,x˜–xˆ≤0.

We can obtain

Lγf)xˆ– (ηLγf)x˜,xˆ–x˜≤0.

Fromηδ>γρand Lemma2.9, we can get

Lγf)xˆ– (ηLγf)x˜,xˆ–x˜≥(ηδ–γρ)ˆxx˜2≥0.

This leads to a contradiction. Hence, the variational inequality problem (3.2) has a unique

solution and we denote it byx∗∈Γ.

We have

Lγf)x∗,x∗–x≤0 ⇔ xˆ– (IηL+γf)x∗,x∗–x≤0, ∀xΓ.

It is easy to verifyΓ is closed and convex. From Lemma2.4, we obtainx∗=PC(IηL+

γf)x∗.

Next, we show that the sequence{xn}is bounded. LetpΓ, that is,pΩi, for∀i

{1, 2, . . . ,N1}, and we havep=Tfi,hi

rn,i pandAip=T Fi,Hi

rn,i Aip. Observe that

ωn,ip2 =Trfin,,hii

xn+ξn,iAi

TFi,Hi

rn,iI

Aixn

p2

xn+ξn,iAi

TFi,Hi

rn,iI

Aixnp

2

=xnp2+ 2ξn,i

AiTFi,Hi rn,iI

Aixn,xnp

+ξn2,iAiTFi,Hi rn,iI

Aixn

2

xnp2+ 2ξn,i

TFi,Hi

rn,iI

Aixn,AixnAip

+ξn2,iAi2TrFni,,iHiI

Aixn2.

DenotingΛ= 2ξn,i(TrFni,,iHiI)Aixn,AixnAipand using (1.1), we get

Λ= 2ξn,i

TFi,Hi

rn,iI

Aixn,AixnAip

= 2ξn,i

TFi,Hi

rn,iI

Aixn,AixnAip

+TFi,Hi rn,iI

Aixn

TFi,Hi

rn,iI

Aixn

= 2ξn,i

TFi,Hi

rn,iI

Aixn,TrFni,,iHiAixnAip

TFi,Hi rn,iI

Aixn

2

≤2ξn,i

1

2T

Fi,Hi rn,iI

Aixn

2

TFi,Hi rn,iI

Aixn

2

≤–ξn,iTrFni,,iHiI

Aixn

2

.

Therefore, for∀i∈ {1, 2, . . . ,N1}, we have

ωn,ip2≤ xnp2+

ξn2,iAi2–ξn,iTrFni,,iHiI

Aixn

2

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From the condition (v), we obtain

ωnp=ωn,inpxnp. (3.4)

From Lemma2.12and the definition ofSj, we have

zn,jp2=βn,jωn+ (1 –βn,j)Sjωnp

2

=βn,jωnp2+ (1 –βn,j)Sjωnp2

βn,j(1 –βn,j)ωnSjωn2

βn,jωnp2+ (1 –βn,j)

ωnp2+κjωnSjωn2

βn,j(1 –βn,j)ωnSjωn2

=ωnp2+ (1 –βn,j)(κjβn,j)ωnSjωn2.

It follows from the condition (iv) that

zn,jpωnpxnp, ∀j∈ {1, 2, . . . ,N2}. (3.5)

LetB=N3l=1μlBlandσ=min{σ1, . . . ,σN3}, by Lemma2.8, we know thatBisσ-ism, and

from the condition 0 <λn< 2σ, we see that IλnBis nonexpansive, andPC(IλnB)

is also nonexpansive. We havepΓ, that is,pN3l=1VI(C,Bl) =VI(C,B). Then from

Lemma2.12, we have

ynp2 =

PC(IλnB)

N2

j=1

νn,jzn,j

p

2

=

PC(IλnB)

N2

j=1

νn,jzn,j

PC(IλnB)p

2

N2

j=1

νn,jzn,jp

2

N2

j=1

νn,jzn,jp2

xnp2. (3.6)

From the conditionlimn→∞αn= 0, we may assume, with no loss of generality, thatαn<

1

ηL for alln. It follows from Lemma2.9that

xn+1–p =αnγf(xn) + (IαnηL)ynp

=αn

γf(xn) –ηLp

+ (IαnηL)(ynp)

αnγf(xn) –ηLp+IαnηLynp

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αnγρxnp+αnγf(p) –ηLp+ (1 –αnηδ)xnp

=1 –αn(ηδ–γρ)

xnp+αnγf(p) –ηLp

=1 –αn(ηδ–γρ)

xnp+αn(ηδ–γρ)

γf(p) –ηLp

ηδγρ

≤max

xnp,

γf(p) –ηLp

ηδγρ

≤ · · ·

≤max

x1–p,

γf(p) –ηLp

ηδγρ

.

That is,{xn}is bounded, and{yn},{zn,j},{ωn,i},{f(xn)}and{Sjωn}are also bounded.

Next, we showωω(xn)⊆Γ. To see this, we takeqωω(xn) and assume thatxnlqas

l→ ∞for some subsequence{xnl}of{xn}. Observe that

xn+1–p2=αnγf(xn) + (IαnηL)ynp

2

=αn

γf(xn) –ηLp

+ (IαnηL)(ynp)

2

=αn2γf(xn) –ηLp

2

+(IαnηL)(ynp)

2

+ 2αn

γf(xn) –ηLp, (IαnηL)(ynp)

αn2γf(xn) –ηLp2+ (1 –αnηδ)2ynp2

+ 2αn(1 –αnηδ)γf(xn) –ηLpynp

αn2γf(xn) –ηLp2+ (1 –αnηδ)2ynp2

+ 2αn(1 –αnηδ)γf(xn) –ηLpxnp. (3.7)

From (3.4), (3.5) and (3.6), we obtain

xn+1–p2≤αn2γf(xn) –ηLp

2

+ (1 –αnηδ)2 N2

j=1

νn,jzn,jp2

+ 2αn(1 –αnηδ)γf(xn) –ηLpxnp

αn2γf(xn) –ηLp

2

+ (1 –αnηδ)2 N2

j=1

νn,j

ωnp2

+ (1 –βn,j)(κjβn,j)ωnSjωn2

+ 2αn(1 –αnηδ)γf(xn) –ηLpxnp

αn2γf(xn) –ηLp

2

+ (1 –αnηδ)2 N2

j=1

νn,j

xnp2

+ξn2,inAin2–ξn,inT Fin,Hin rn,inI

Ainxn

2

+ (1 –βn,j)(κjβn,j)ωnSjωn2

+ 2αn(1 –αnηδ)γf(xn) –ηLpxnp

=αn2γf(xn) –ηLp

2

(12)

+ (1 –αnηδ)2

ξn2,inAin2–ξn,inT Fin,Hin rn,inI

Ainxn

2

+ (1 –αnηδ)2 N2

j=1

νn,j(1 –βn,j)(κjβn,j)ωnSjωn2

+ 2αn(1 –αnηδ)γf(xn) –ηLpxnp. (3.8)

Then we have

(1 –αnηδ)2

ξn,inξ

2

n,inAin

2TFin,Hin rn,inI

Ainxn

2

αn2γf(xn) –ηLp2

xn+1–p2

+ (1 –αnηδ)2xnp2

+ 2αn(1 –αnηδ)

×γf(xn) –ηLp

× xnp (3.9)

and

(1 –αnηδ)2 N2

j=1

νn,j(1 –βn,j)(βn,jκj)ωnSjωn2≤αn2γf(xn) –ηLp2

xn+1–p2

+ (1 –αnηδ)2xnp2

+ 2αn(1 –αnηδ)

×γf(xn) –ηLp

× xnp. (3.10)

Next, we analyze the inequality (3.9) and (3.10) by considering the following two cases.

Case 1. Assume that there existsn0large enough such thatxn+1–p2≤ xnp2for

all nn0. Sincexnp2 is bounded, we see that limn→∞xnp2 exists. From the

conditions (iii) and (v), we obtain

TrFnin,in,HinI

Ainxn→0 (n→ ∞)

and

ωnSjωn →0 (n→ ∞),∀j∈ {1, 2, . . . ,N2}.

Then we have

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Sincep=Tfi,hi rn,i pandT

fi,hi

rn,i is firmly nonexpansive, we obtain

ωn,ip2 =Trfin,,hii

xn+ξn,iAi

TFi,Hi

rn,iI

Aixn

p2

=Tfi,hi rn,i

xn+ξn,iAi

TFi,Hi

rn,iI

Aixn

Tfi,hi rn,ip

2

ωn,ip,xn+ξn,iAi

TFi,Hi

rn,iI

Aixnp

= 1

2

ωn,ip2+xn+ξn,iAi

TFi,Hi

rn,iI

Aixnp

2

ωn,ixnξn,iAi

TFi,Hi

rn,iI

Aixn

2

= 1

2

ωn,ip2+xnp2+ξn2,iAi

TFi,Hi

rn,iI

Aixn

2

+ 2ξn,i

xnp,Ai

TFi,Hi

rn,iI

Aixn

ωn,ixn2+ξn2,iAi

TFi,Hi

rn,iI

Aixn

2

– 2ξn,i

ωn,ixn,Ai

TFi,Hi

rn,iI

Aixn

= 1

2

ωn,ip2+xnp2–ωn,ixn2

+ 2ξn,i

Aiωn,iAip,

TFi,Hi

rn,iI

Aixn

≤1 2

ωn,ip2+xnp2–ωn,ixn2

+ 2ξn,iAiωn,iAipTrFni,,iHiI

Aixn .

Then we get

ωn,ip2≤ xnp2–ωn,ixn2+ 2ξn,iAiωn,iAipTrFni,,iHiI

Aixn.

From (3.8), we have

xn+1–p2≤αn2γf(xn) –ηLp2+ (1 –αnηδ)2 N2

j=1

νn,j

ωnp2

+ (1 –βn,j)(κjβn,j)ωnSjωn2

+ 2αn(1 –αnηδ)γf(xn) –ηLpxnp

αn2γf(xn) –ηLp

2

+ (1 –αnηδ)2ωnp2

+ 2αn(1 –αnηδ)γf(xn) –ηLpxnp

αn2γf(xn) –ηLp2+ (1 –αnηδ)2

xnp2–ωnxn2

+ 2ξn,inAinωnAinpT Fin,Hin rn,inI

Ainxn

+ 2αn(1 –αnηδ)γf(xn) –ηLpxnp.

Then

(1 –αnηδ)2ωnxn2≤αn2γf(xn) –ηLp

2

+ (1 –αnηδ)2xnp2

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× AinωnAinpT Fin,Hin rn,inI

Ainxn

+ 2αn(1 –αnηδ)γf(xn) –ηLpxnp.

Sinceαn→0,(T

Fin,Hin

rn,inI)Ainxn →0, asn→ ∞, andlimn→∞xnpexists, we obtain

ωnxn →0 (n→ ∞). (3.12)

From (3.11), we have

zn,jxn →0 (n→ ∞).

Letzn=

N2

j=1νn,jzn,j, thenyn=PC(IλnB)zn, and we have

znxn

N2

j=1

νn,jzn,jxn

N2

j=1

νn,jzn,jxn

→0 (n→ ∞). (3.13)

SinceBisσ-ism, we obtain

ynp2 =PC(IλnB)znp2

=PC(IλnB)znPC(IλnB)p

2

≤(IλnB)zn– (IλnB)p

2

=znp2+λ2nBznBp2– 2λnznp,BznBp

znp2+

λ2n– 2λ

BznBp2.

From (3.7), we have

xn+1–p2≤αn2γf(xn) –ηLp

2

+ (1 –αnηδ)2ynp2

+ 2αn(1 –αnηδ)γf(xn) –ηLpxnp

αn2γf(xn) –ηLp

2

+ (1 –αnηδ)2

znp2

+λ2n– 2λ

BznBp2

+ 2αn(1 –αnηδ)γf(xn) –ηLpxnp.

Then

(1 –αnηδ)2

λ2n

BznBp2≤αn2γf(xn) –ηLp

2

+ (1 –αnηδ)2znp2

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×γf(xn) –ηLpxnpα2nγf(xn) –ηLp

2

+ (1 –αnηδ)2xnp2

xn+1–p2+ 2αn(1 –αnηδ)

×γf(xn) –ηLpxnp.

Since 0 <lim infn→∞λn≤lim supn→∞λn< 2σ,αn→0, asn→ ∞, andlimn→∞xnp

exists, we obtain

BznBp →0 (n→ ∞).

SincePCis firmly nonexpansive, we obtain

ynp2 =PC(IλnB)znp

2

=PC(IλnB)znPC(IλnB)p

2

ynp, (IλnB)zn– (IλnB)p

= 1

2

ynp2+(IλnB)zn– (IλnB)p

2

ynzn+λn(BznBp)

2

= 1

2

ynp2+znp2+λ2nBznBp2

– 2λnznp,BznBp

ynzn2+λ2nBznBp2

+ 2λnynzn,BznBp

= 1

2

ynp2+znp2–ynzn2

– 2λnynp,BznBp

≤ 1 2

ynp2+znp2–ynzn2

+ 2λnynpBznBp .

Then

ynp2≤ znp2–ynzn2+ 2λnynpBznBp.

From (3.7), we have

xn+1–p2≤αn2γf(xn) –ηLp

2

+ (1 –αnηδ)2ynp2

+ 2αn(1 –αnηδ)γf(xn) –ηLpxnp

αn2γf(xn) –ηLp

2

+ (1 –αnηδ)2

znp2–ynzn2

+ 2λnynpBznBp

+ 2αn(1 –αnηδ)

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αn2γf(xn) –ηLp

2

+ (1 –αnηδ)2

xnp2–ynzn2

+ 2λnxnpBznBp

+ 2αn(1 –αnηδ)

×γf(xn) –ηLpxnp.

Then we have

(1 –αnηδ)2ynzn2≤αn2γf(xn) –ηLp

2

+ (1 –αnηδ)2xnp2

xn+1–p2+ 2λn(1 –αnηδ)2

× xnpBznBp+ 2αn(1 –αnηδ) ×γf(xn) –ηLpxnp.

Sinceαn→0,BznBp →0, asn→ ∞, andlimn→∞xnpexists, we obtain

ynzn →0 (n→ ∞).

Sincexnl qasl→ ∞for some subsequence{xnl}of{xn}. from (3.12), we haveωnlq

asl→ ∞for some subsequence{ωnl}of{ωn}. Again sincelimn→∞ωnlSjωnl= 0 and

SjI are demiclosed at 0, for eachj∈ {1, 2, . . . ,N2}, it follows from Definition2.1that

qN2i=1F(Sj).

Sinceyn=PC(I–λnB)znandλn> 0 is bounded, with no loss of generality, we may assume

that

λnlλ (l→ ∞).

Then we have

znlPC(IλB)znl = znlPC(IλnlB)znl

+PC(IλnlB)znlPC(IλB)znl

znlynl+(IλnlB)znl– (IλB)znl

= znlynl+|λnlλ|Bznl

→0 (n→ ∞).

From (3.13), we haveznl qasl→ ∞for some subsequence{znl}of{zn}. Again since

PC(IλB) is nonexpansive and we have Lemma2.2, we obtainq∈VI(C,B). It follows from

Lemma2.8thatqN3l=1VI(C,Bl).

From (3.1) and (3.12), we have

ωn,ixn →0 asn→ ∞, 1≤iN1,

and from (3.3), we obtain

TFi,Hi rn,iI

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Letωn,i=Trfin,,hiiυn,i, whereυn,i=xn+ξn,iAi(T Fi,Hi

rn,iI)Aixn, and we have

υn,ixn = ξn,iAi

TFi,Hi

rn,iI

Aixn

ξn,iAiTrFni,,iHiI

Aixn

→0 (n→ ∞).

Then we haveωn,iυn,i →0 asn→ ∞, 1≤iN1.

Sinceωn,i=Trfni,,hiiυn,i, we have

fin,i,ω) +hin,i,ω) +

1

rn,i

ωωn,i,ωn,iυn,i ≥0, ∀ωC,

then

hin,i,ω) +

1

rn,i

ωωn,i,ωn,iυn,i ≥–fin,i,ω)fi(ω,ωn,i), ∀ωC.

Sinceωn,iνn,i →0,ωn,iq,fiis lower semicontinuous in the second argument and

hiis upper semicontinuous in the first argument, we obtain

hi(q,ω)fi(ω,q), ∀ωC.

Then we have

fi(ω,q) +hi(ω,q)≤fi(ω,q) –hi(q,ω)≤0, ∀ωC.

Letωˆ=+ (1 –t)qC, we haveωˆ∈Candfi(ω,ˆ q) +hi(ω,ˆ q)≤0. Observe that

0 =fi(ω,ˆ ω) +ˆ hi(ω,ˆ ω)ˆ

=tfi(ω,ˆ ω) +hi(ω,ˆ ω)

+ (1 –t)fi(ω,ˆ q) +hi(ω,ˆ q)

tfi(ω,ˆ ω) +hi(ω,ˆ ω)

.

Hence

fi(ω,ˆ ω) +hi(ω,ˆ ω)≥0, ∀ωC.

Sincefiis upper hemicontinuous andhiis upper semicontinuous in the first argument, we

have

fi(q,ω) +hi(q,ω)≥0, ∀ωC.

That is,q∈GEP(fi,hi), for∀i∈ {1, . . . ,N1}.

Next, we show that Aiq∈GEP(Fi,Hi). Sincexnl q and continuity ofAi, we have

Aixnl Aiq. Letϑn,i=AixnT Fi,Hi

rn,i Aixn, from (3.14), we havelimn→∞ϑn,i= 0, for∀i∈ {1, . . . ,N1}. And sinceTFi,Hi

rn,i Aixn=Aixnτn,i, for∀εQ, we have

Fi(Aixnϑn,i,ε) +Hi(Aixnϑn,i,ε) +

1

rn,i

ε– (Aixnϑn,i), (Aixnϑn,i) –Aixn

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SinceFiandHiare upper semicontinuous in the first argument, we have

Fi(Aiq,ε) +Hi(Aiq,ε)≥0, ∀εQ.

Then we obtainAiq∈GEP(Fi,Hi), for∀i∈ {1, . . . ,N1}. Therefore we conclude thatqΓ.

Next, we show that

lim sup

n→∞

Lγf)x∗,x∗–xn

≤0. (3.15)

Indeed, take a subsequence{xnj}of{xn}such that

lim sup

n→∞

Lγf)x∗,x∗–xn

=lim

j→∞

Lγf)x∗,x∗–xnj

.

Since{xn}is bounded, without loss of generality, we may assume thatxnjx¯∈Γ. Then

we obtain

lim sup

n→∞

Lγf)x∗,x∗–xn

=(ηLγf)x∗,x∗–x¯≤0.

Finally, we show thatxnx∗(n→ ∞). From Lemma2.9, Lemma2.11and (3.6), we have

xn+1x∗2 =αnγf(xn) + (IαnηL)ynx

2

=αn

γf(xn) –ηLx

+ (IαnηL)

ynx∗2

≤(1 –αnηδ)2ynx

2

+ 2αn

γf(xn) –ηLx∗,xn+1–x

= (1 –αnηδ)2ynx∗2+ 2αn

γf(xn) –γf

x∗,xn+1–x

+ 2αn

γfx∗–ηLx∗,xn+1–x

≤(1 –αnηδ)2ynx

2

+ 2αnγρxnxxn+1–x

+ 2αn

γfx∗–ηLx∗,xn+1–x

≤(1 –αnηδ)2xnx

2

+αnγρxnx

2

+xn+1–x∗ 2

+ 2αn

γfx∗–ηLx∗,xn+1–x

.

Thus

(1 –αnγρ)xn+1–x∗ 2

≤(1 –αnηδ)2+αnγρxnx

2

+ 2αn

γfx∗–ηLx∗,xn+1–x

.

Sinceηδ>γρand 0 <αnη1L

1

ηδ, we have 1 –αnγρ> 1 –αnηδ≥0. Hence

xn+1–x∗ 2

≤(1 –αnηδ)2+αnγρ

1 –αnγρ

xnx

2

+ 2αn

1 –αnγρ ×γfx∗–ηLx∗,xn+1–x

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=

1 –2αn(ηδ–γρ) 1 –αnγρ

xnx∗2+

n

1 –αnγρ

×γfx∗–ηLx∗,xn+1–x

+ α

2

2δ2

1 –αnγρ

xnx

2

1 –2αn(ηδ–γρ) 1 –αnγρ

xnx

2

+2αn(ηδ–γρ)

1 –αnγρ

γf(x∗) –ηLx∗,xn+1–x

ηδγρ +αnM

,

whereMis the constant satisfying

M=sup

n≥0

η2δ2

2(ηδ–γρ)xnx

∗2

.

From the condition∞n=0αn=∞,limn→∞αn= 0 and (3.15), we have

n=0

n(ηδ–γρ)

1 –αnγρ

>

n=0

n(ηδ–γρ) =

and

lim sup

n→∞

γf(x∗) –ηLx∗,xn+1–x

ηδγρ +αnM

≤0.

By Lemma2.14, we obtainxnx∗ →0 asn→ ∞.

Case 2. Assume that there exists a subsequence{xnjp

2} of{x

np2} such that

xnjp

2<x

nj+1–p

2for alljN. Then it follows from Lemma2.13that there exists a

nondecreasing sequence{mk}ofN, such thatlimk→∞mk=∞, and the following

inequal-ities hold for allkN:

xmkp

2x

mk+1–p

2 and x

kp2≤ xmk+1–p

2. (3.16)

Similarly, we get

ωmk,ixn →0 (k→ ∞),∀i∈ {1, 2, . . . ,N1}, ωmkSjωmk →0 (k→ ∞),∀j∈ {1, 2, . . . ,N2}, zmk,jωmk →0 (k→ ∞),∀j∈ {1, 2, . . . ,N2}, zmkxmk →0 (k→ ∞),

ymkzmk →0 (k→ ∞),

ωmk,iυmk,i →0 (k→ ∞),∀i∈ {1, 2, . . . ,N1},

AixmkT Fi,Hi

rmk,iAixmk→0 (k→ ∞),∀i∈ {1, 2, . . . ,N1}.

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Also, we obtain

lim sup

k→∞

Lγf)x∗,x∗–xmk

≤0

and

xmk+1–x

∗2

1 –2αmk(ηδ–γρ) 1 –αmkγρ

xmkx

∗2

+2αmk(ηδ–γρ)

1 –αmkγρ

γf(x∗) –ηLx∗,xmk+1–x

ηδγρ +αmkM

,

whereMis the constant satisfying

M=sup

k≥0

η2δ2

2(ηδ–γρ)xmkx

∗2

.

By a similar argument to that in Case 1, we obtainxmkx∗ →0 ask→ ∞. By (3.16),

we getxkx∗ ≤ xmkx∗,∀kN. Therefore,xkx∗ask→ ∞.

Remark3.2 We present several corollaries of Theorem3.1and we can consider the fol-lowing cases:

(i) Ai=A, for1≤iN1;

(ii) hi=ϕi(·,·)andHi=φi(·,·), whereϕi:CR∪ {+∞}andφi:QR∪ {+∞}is

proper lower semicontinuous and convex functions, for1≤iN1;

(iii) hi= 0andHi= 0, for1≤iN1;

(iv) Hi= 0andFi= 0, for1≤iN1;

(v) N1=N2=N3= 1.

(vi) Sjisκj-strict pseudo-contractive for anyj. From Lemma2.2, we can remove the

condition thatSjIis demiclosed at 0 of Theorem3.1;

(vii) Sjis a nonspreading mapping or anN-generalized hybrid mapping. We note that

nonspreading mappings with nonempty fixed point set andN-generalized hybrid mappings with nonempty fixed point set are quasi-nonexpansive operators.

4 Numerical examples

In this section, we give two numerical examples to demonstrate the convergence of our algorithm. All codes were written in Matlab 2010b and run on Dell i-5 Dual-Core laptop.

Example4.1 We consider the case thatN1=N2=N3= 1.

LetH1=H2=R,C=Q= [–20, 10] and letf1,h1:C×CRandF1,H1:Q×QRbe

defined byf1(z,y) =y2+ 3zy– 4z2,h1(z,y) =y2z2andF1(z,y) = 3y2+ 2zy– 5z2,H1(z,y) = 0.

DefineS1,A1,B1,f,Las follows:

S1(x) =

⎧ ⎨ ⎩

x, x∈(–∞, 0),

–2x, x∈[0,∞).

A1x= –x,B1x=12xandf(x) =L(x) = 2x. Putαn=n+11 ,βn,1=12+n1+2,ξn,1= 1 –n1+1,λn=15

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all the conditions of Theorem3.1. Then, by Lemma2.7, we see thatTrf1,h1 andTrF1,H1 are

single-value mappings onH1 andH2, respectively. Hence, forrn=r> 0,xH1andx

H2, there existz1Candz2Qsuch that

f1(z1,y) +h1(z1,y) +1

ryz1,z1x ≥0, ∀yC,

and

F1(z2,y) +H1(z2,y) +

1

ryz2,z2–x ≥0, ∀yQ.

We can reform the above inequalities to standard quadratic form in the variableyas

fol-lows:

P1(y) = 2ry2+ (2rz1+z1–x)y+

xz1– 5rz12–z21

≥0, ∀yC,

and

P2(y) = 3ry2+ (2rz2+z2x)y+xz2– 5rz22–z22≥0, ∀yQ.

It is easy to check that the discriminants of the above two quadratic inequalities are

non-negative. And since P1(y)≥0 for all yCandP2(y)≥0 for all yQ, we see that the

discriminant must be zero. Then we obtainz1=Trf1,h1(x) =1+7xr andz2=TrF1,H1(x) =1+8xr.

It is clear thatΓ ={0}.

In what follows, we observe the convergence of the Algorithm3.1by considering the

following three cases:

Case 1. Taking the different initial pointx1= –5, 1, 5 withη= 1,r= 4, Fig.1presents the

[image:21.595.118.478.498.708.2]

convergence behaviors of{xn}for Algorithm3.1.

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[image:22.595.118.478.91.461.2] [image:22.595.116.477.251.546.2]

Figure 2Behaviors of{xn}with differentr= 4, 0.4, 0.04,x1= 1 andη= 1

Figure 3Behaviors of{xn}with differentη= 1, 10, 50, 100, 200,x1= 1 andr= 4

Case 2. Taking the differentr= 4, 0.4, 0.04 withx1= 1,η= 1, Fig.2presents the

conver-gence behaviors of{xn}for Algorithm3.1.

Case 3. Taking the differentη= 1, 10, 50, 100, 200 withx1= 1,r= 4, Fig.3presents the

convergence behaviors of{xn}for Algorithm3.1.

Example4.2 We consider the case thatN1=N2=N3= 2.

LetH1=H2=R,C=Q= [–20, 10] and letfi,hi:C×CRandFi,Hi:Q×QRbe

defined byf1(z,y) =y2+ 3zy– 4z2,h1(z,y) =y2–z2,F1(z,y) = 3y2+ 2zy– 5z2,H1(z,y) = 0 and f2(z,y) =y2z2,h2(z,y) = 0,F2(z,y) =y2+ 3zy– 4z2,H2(z,y) =1

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[image:23.595.119.478.80.308.2]

Figure 4Behaviors of{xn}withx1= 1

L,αn,βn,1,ξn,1,λn,γ be the same as that of Example4.1, and defineS2,A2,B2byS2x=45x,

A2x= 2xandB2x= 2x. Putβn,2=21–n1+2,ξn,2=12(1 – n1+1),νn,1=12n+21 ,νn,2=12+n+21 , rn,1=rn,2=r= 4,μ1=μ2=12andη= 1. It is easy to verify that they satisfy all the conditions

of Theorem3.1.

Following an argument similar to that of Example 4.1, we obtain Trf1,h1(x) = 1+7xr,

TrF1,H1(x) = 1+8xr,Trf2,h2(x) = 1+2xr andTrF2,H2(x) = 1+6xr andΓ ={0}. Figure4presents the

convergence behaviors of{xn}for Algorithm3.1.

5 Conclusion

In this paper, we first propose a new parallel hybrid viscosity method for finding a common element of the set of solutions of a finite family of split generalized equilibrium problems, variational inequality problems and the set of common fixed points of a finite family of demicontractive operators in Hilbert spaces. And then we establish the corresponding strong convergence theorem under suitable conditions. We study more general split

equi-librium problems and fixed point problems of operators than those in [18]. Our results

in this paper improve and extend many recent results in the literature. Finally, we present numerical examples to demonstrate the effectiveness of our algorithm.

Acknowledgements

The author is most grateful to the referees and the editor for their helpful comments and advice which helped to improve the contents of this paper.

Funding

Not applicable.

Availability of data and materials

All data generated or analysed during this study are included in this published article.

Competing interests

The author declares to have no competing interests.

Authors’ contributions

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Publisher’s Note

Springer Nature remains neutral with regard to jurisdictional claims in published maps and institutional affiliations. Received: 27 February 2019 Accepted: 30 May 2019

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Figure

Figure 1 Behaviors of {xn} with initial points x1 = –5,1,5, η = 1 and r = 4
Figure 2 Behaviors of {xn} with different r = 4,0.4,0.04, x1 = 1 and η = 1
Figure 4 Behaviors of {xn} with x1 = 1

References

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