SOME CLASSES OF MEROMORPHIC MULTIVALENT
FUNCTIONS WITH POSITIVE COEFFICIENTS
INVOLVING CERTAIN LINEAR OPERATOR
Abdul Rahman S. Juma1, Hazha Zirar Hussain 2Department of Mathematics, Alanbar University, Ramadi-Iraq1,
Department of Mathematics, Salahaddin University,Erbil-Iraq2,
Abstract
Making use of a linear operator, which is defined here by means of the Hadamard product (or convolution), we introduce two novel subclasses Da,c,λ[p, α, A, B] and
P∗
p,a,c,λ[α, β] of meromorphically multivalent functions. In this paper, we obtain
co-efficient estimates, distortion theorems, radii of starlikeness and convexity and clo-sure theorems for the classDa,c,λ[p, α, A, B]. Several interesting results involving the
Hadamard product of functions belonging to the classDa,c,λ[p, α, A, B],P∗p,a,c,λ[α, β]
and P∗
p[α, β] are also derived. Also integral transforms of functions in the classes
P∗
p,a,c,λ[α, β] and
P∗
p[α, β] are studied.
Key Words : Linear operator, Meromorphic, Positive coefficients, Hadamard product.
AMS Subject Classification : Secondary 30C45.
1. Introduction
Let Pp denote the class of functions of the form:
f(z) = 1 zp +
∞ X
n=0
ap+nzp+n, (ap+n≥0;p∈N={1,2, ...}), (1)
which are analytic and p-valent in the punctured unit disk U∗ = {z ∈
C : 0 < |z| <
1} =U − {0}; where U = {z ∈ C: |z| < 1}. For functions f(z) ∈ P
p given by (1) and
g(z)∈P
p given by
g(z) = 1 zp +
∞ X
n=0
bp+nzp+n,(bp+n≥0),
1E-mail:
dr−[email protected] 2E-mail:
we define the Hadamard product (or convolution) of two functions, f(z) and g(z) given
by
(f ∗g)(z) = 1 zp +
∞ X
n=0
ap+nbp+nzp+n = (g∗f)(z).
In terms of the Pochhammer symbol (θ)n given by
(θ)n=
Γ(θ+n) Γ(θ) =
1 (n = 0),
θ(θ+ 1)(θ+ 2)...(θ+n−1) (n∈N),
we define the function ϕ(a, c,;z) by
ϕ(a, c,;z) = 1 zp +
∞ X
n=0
(a)n+1
(c)n+1
zn+p (2)
(z ∈ U∗;a∈
R;c∈R−Z−0;Z
−
0 ={0,−1,−2, ...}).
Corresponding to the function ϕ(a, c,;z), Liu [8] and Liu and Srivastava [9] have
intro-duced a linear operator `p(a, c) which is defined by means of the following Hadamard
product (or convolution):
`p(a, c) = ϕ(a, c,;z)∗f(z). (3)
Just as in [8] and [9], it is easily verified from the definitions (2) and (3) that
z(`p(a, c))f(z))0 =a`p(a+ 1, c)f(z)−(a+p)`p(a, c)f(z).
We also note, for any integer m >−p and for f(z)∈P
p, that
`p(n+p,1)f(z) =Dm+p−1f(z) =
1
zp(1−z)m+p ∗f(z),
where Dm+p−1f(z) is the differential operator studied by (among others) Uralegaddi and Somanatha [17] and Aouf [3].
Further M. K. Aouf et. al. [4] considered the generalized operators as follows:
Let
Fp,a,c,λ(z) = (1−λ)`p(a, c)f(z) +
λ
pz(`p(a, c)f(z))
(f ∈P
p;p∈N; 0≤λ <
1 2),
so that, obviously,
Fp,a,c,λ(z) =
1−2λ zp +
∞ X
n=0
[1 +λ(n p]
(a)n+1
(c)n+1
ap+nzp+n (4)
(p∈N; 0≤λ < 1 2),
since f(z)∈P
p is given by (1). From (4), it is easily verified that
zFp,a,c,λ0 (z) =aFp,a+1,c,λ(z)−(a+p)Fp,a,c,λ(z).
We say that a function f(z) ∈ P
p is in the class Da,c,λ[p, α, A, B] if it satisfies the
following inequality:
zFp,a,c,λ0 (z)
Fp,a,c,λ(z) +p
BzF 0
p,a,c,λ(z)
Fp,a,c,λ(z) + [pB+ (A−B)(p−α)]
<1 (z ∈ U∗), (5)
where the parameters A, B, α, p and λ are constrained as follows:
−1≤A < B ≤1, A+B ≥0,0≤α < p, p∈N and 0≤λ < 1 2.
The class Da,a,0[p, α, A, B] = Q∗[p, α, A, B] was studied by Aouf [2] and Srivastava et
al.[15].
We observe also that
1. Da,c,λ[p, α,−β, β] =
P∗
p,a,c,λ[α, β] = {f(z) ∈
P∗
p :
zFp,a,c,λ0 (z) Fp,a,c,λ(z)+p zFp,a,c,λ0 (z)
Fp,a,c,λ(z)+2α−p
< β, 0 ≤ α <
p, p ∈N,0< β ≤1,0≤α < p, z∈ U∗}
2. Da,a,0[p, α,−β, β] =
P∗
p[α, β], the class of meromorphic p-valent starlike functions
of order α and type β,
={f(z)∈
∗ X
p
:
zf0(z)
f(z) +p
f0(z)
f(z) + 2α−p
Meromorphically multivalent functions have been extensively studied by (for example)
Mogra [10, 11], Uralegaddi and Ganigi [16], Aouf [1, 2], Srivastava et al. [15], Owa et al.
[12], Joshi and Srivastava [7], Liu [8], Liu and Srivastava [9], Aouf et al. [5], Raina and
Srivastava [13] and Yang [18].
In this paper we investigate various important properties and characteristics of the
class Da,c,λ[p, α, A, B], we obtain coefficient estimates, distortion theorems, radii of
star-likeness and convexity and closure theorems. Several interesting results involving the
Hadamard product of functions belonging to the classesDa,c,λ[p, α, A, B],
P∗
p,a,c,λ[α, β] and
P∗
p[α, β] are also derived. Also integral transforms for functions in the classes
P∗
p,a,c,λ[α, β]
and P∗p[α, β] are studied.
2. Coefficient Estimates
Theorem 2.1 : A function f(z) defined by (1) is said to be in the class Da,c,λ[p, α, A, B]
if and only if
∞ X
n=0
[1+λ(n p)]
(a)n+1
(c)n+1
[(1+B)n+2p+2αB+(B+A)(p−α)]ap+n≤(1−2λ)(B−A)(p−α), (6)
where 1≤A < B ≤1, A+B ≥0,0≤α < p, p ∈N and 0≤λ < 12.
proof : We assume that the inequality (6) holds true. Then, if we let z ∈ ∂U, we find
from (1) and (6) that
zFp,a,c,λ0 (z)
Fp,a,c,λ(z) +p
BzF 0
p,a,c,λ(z)
Fp,a,c,λ(z) + [pB+ (A−B)(p−α)]
≤
P∞
n=0[1 +λ(
n p)]
(a)n+1
(c)n+1(2p+n)ap+n
(1−2λ)(B−A)(p−α)−P∞n=0[1 +λ(np)](a)n+1
(c)n+1[B(n+ 2α) + (B+A)(p−α)]ap+n
≤1(z ∈∂U ={z∈C:|z|= 1}
Conversely, let f(z)∈Da,c,λ[p, α, A, B] be given by (1). Then, from (1) and (6), we have
zFp,a,c,λ0 (z)
Fp,a,c,λ(z) +p
BzF 0
p,a,c,λ(z)
Fp,a,c,λ(z) + [pB+ (A−B)(p−α)]
=
P∞
n=0[1 +λ(
n p)]
(a)n+1
(c)n+1(2p+n)ap+nz 2p+n
(1−2λ)(B−A)(p−α)−P∞n=0[1 +λ(np](a)n+1
(c)n+1[B(n+ 2α) + (B+A)(p−α)]ap+nz 2p+n
<1 forz ∈ U∗
Since |<(z)≤ |z|(z ∈C), we have
<
( P∞
n=0[1 +λ(
n p)]
(a)n+1
(c)n+1(2p+n)ap+nz 2p+n
(1−2λ)(B−A)(p−α)−P∞n=0[1 +λ(np)](a)n+1
(c)n+1[B(n+ 2α) + (B +A)(p−α)]ap+nz 2p+n
)
<1.
(7)
Choose values ofzon the real axis so that zF 0
p,a,c,λ(z)
Fp,a,c,λ(z) is real. Upon clearing the denominator
in (7) and letting z →1− through real values, we obtain (7).
Hence the proof is complete.
Corollary 2.1Let the functionf(z) defined by (1) be in the classDa,c,λ[p, α, A, B]. Then
ap+n ≤
(1−2λ)(B −A)(p−α)
[1 +λ(np)][(1 +B)n+ 2p+ 2αB+ (B+A)(p−α)]. (c)n+1
(a)n+1
, (n≥0)
The result is sharp for the function:
f(z) = 1 zp +
(1−2λ)(B−A)(p−α)
[1 +λ(np)][(1 +B)n+ 2p+ 2αB+ (B+A)(p−α)]. (c)n+1
(a)n+1
zp+n (8)
Putting A=−β and B =β(0< β≤1) in Theorem 2.1, we obtain:
Corollary 2.2 A function f(z) defined by (1) is in the classP∗p,a,c,λ[α, β] if and only if
∞ X
n=0
[1 +λ(n p]
(a)n+1
(c)n+1
[(1 +B)n+ 2(p+αβ)]ap+n≤(1−2λ)2β(p−α).
Putting λ= 0 anda =c in Corollary 2.2, we obtain:
Corollary 2.3 A function f(z) defined by (1) is in the classP∗p[α, β] if and only if
∞ X
n=0
Putting A=−1, B = 1, a=cand λ= 0 in Theorem 2.1, we obtain:
Corollary 2.4 A function f(z) defined by (1) is in the classP∗p[α] if and only if
∞ X
n=0
(n+p+α)ap+n ≤(p−α).
3. Distortion Theorem
Theorem 3.1 : If the function f(z) defined by (1) is in the class Da,c,λ[p, α, A, B], then
for 0<|z|=r <1, we have
1 rp −
c(1−2λ)(B−A)(p−α) a[2p+ 2αB+ (B+A)(p−α)]r
p ≤ |f(z)| ≤ 1
rp +
c(1−2λ)(B−A)(p−α) a[2p+ 2αB+ (B+A)(p−α)]r
p.
The result is sharp.
proof : In view of Theorem 2.1, we have
a
c[2p+2αB+(B+A)(p−α)]
∞ X
n=0
ap+n≤
∞ X
n=0
[1+λ(n p)]
(a)n+1
(c)n+1
[(1+B)n+2p+2αB+(B+A)(p−α)]ap+n
≤(1−2λ)(B−A)(p−α),
that is, that
∞ X
n=0
ap+n≤
(1−2λ)(B−A)(p−α) [2p+ 2αB+ (B+A)(p−α)].
c a.
Then, for o <|z|= 1<1,
|f(z)|=| 1 zp +
∞ X
n=0
ap+nzp+n|,
|f(z)| ≤ 1 rp +
∞ X
n=0
ap+nrp+n,
≤ 1 rp +r
p
∞ X
n=0
ap+n
≤ 1 rp +
(1−2λ)(B−A)(p−α) [2p+ 2αB+ (B+A)(p−α)].
c ar
and
|f(z)|=| 1 zp +
∞ X
n=0
ap+nzp+n|,
|f(z)| ≥ 1 rp −
∞ X
n=0
ap+nrp+n,
≥ 1 rp −r
p
∞ X
n=0
ap+n
≥ 1 rp −
(1−2λ)(B−A)(p−α) [2p+ 2αB+ (B+A)(p−α)].
c ar
p
The bounds for |f(z)| are sharp and are attained for the function
f(z) = 1 zp +
(1−2λ)(B−A)(p−α) [2p+ 2αB+ (B+A)(p−α)].
c az
p
at z =r, z =re2piπ.
Hence the proof is complete.
Next we proof the following growth and distortion properties for the classDa,c,λ[p, α, A, B].
Theorem 3.2 : If the functionf(z) defined by (1) is in the classDa,c,λ[p, α, A, B]. Then
(p+m−1)! (p−1)! r
−(p+m)− c.p!(1−2λ)(B−A)(p−α)
a(p−m)![2p+ 2αB+ (B+A)(p−α)].r
p+n−m ≤ |
f(m)(z)|
≤ (p+m−1)! (p−1)! r
−(p+m)+ c.p!(1−2λ)(B −A)(p−α)
a(p−m)![2p+ 2αB+ (B +A)(p−α)].r
p+n−m.
(0<|z|=r <1;a > c >0;m ∈N0 =N∪ {0};p∈N;p > m).
The result is sharp for the function f(z) given by
f(z) = 1 zp +
c(1−2λ)(B −A)(p−α) a[2p+ 2αB+ (B+A)(p−α)]z
p
at z =r, z =re2piπ.
proof : In view of Theorem 2.1, we have
a
p!c[2p+ 2αB+ (B+A)(p−α)]
∞ X
n=0
≤
∞ X
n=0
[1 +λ(n p)]
(a)n+1
(c)n+1
[(1 +B)n+ 2p+ 2αB+ (B+A)(p−α)]ap+n
≤(1−2λ)(B−A)(p−α),
which yields
∞ X
n=0
(p+n)!ap+n ≤
c.p!(1−2λ)(B−A)(p−α)
a[2p+ 2αB+ (B+A)(p−α)](p∈N). (9)
Now, by differentiating both sides of (1) m times with respect toz, we have
f(m)(z) = (−1)m(p+m−1)!
(p−1)! z
−(p+m)+
∞ X
n=0
(p+n)!
(p+n−m)!ap+nz
p+n−m(p∈
N, m∈N0;p > m),
(10)
and Theorem 3.2 follows easily from (9) and (10).
Hence the proof is complete.
Next we determine the radii of meromorphically p-valent starlikeness of order δ(0 ≤
δ < p) and meromorphically p-valent convexity of order δ(0≤δ < p) for functions in the
class Da,c,λ[p, α, A, B].
4. Radii of Sarlikness and Convexity
Theorem 4.1 : Let the function f(z) defined by (1) be in the class Da,c,λ[p, α, A, B].
Then
1. f(z) is meromorphically p-valent starlike of order δ(0≤δ < p) in the disk |z|< r1,
that is,
<{−zff(0z(z))}> δ (|z|< r1; 0≤δ < p, n ∈N),
where
r1(p, α, A, B, a, c) =
h(p−δ)[1+λ(n
p)][(1+B)n+2p+2αB+(B+A)(p−α)] (n+p+δ)(1−2λ)(B−A)(p−α)
(a)n+1 (c)n+1
i2p+n1
(n≥0).
2. f(z) is meromorphically p-valent convex of order δ(0≤δ < p) in the disk |z|< r1,
that is,
where
r2(p, α, A, B, a, c) =
hp(p−δ)[1+λ(n
p)][(1+B)n+2p+2αB+(B+A)(p−α)] (p+n)(p+n+δ)(1−2λ)(B−A)(p−α) .
(a)n+1 (c)n+1
i2p+n1
(n≥0).
Each of these results is sharp for the function f(z) given by (8).
proof : 1. It is sufficient to show that
zf0(z)
f(z) +p
zf0(z)
f(z) −p+ 2δ
≤1.
Note that
zf0(z)
f(z) +p
zf0(z)
f(z) −p+ 2δ
≤ P∞
n=0(2p+n)ap+n|z|p+n
2(p−δ)−P∞n=0(n+ 2δ)ap+n|z|2p+n
.
Thus, we have the desired inequality
zf0(z)
f(z) +p
zf0(z)
f(z) −p+ 2δ
≤1 (0≤δ < p, n∈N), (11)
if
∞ X
n=0
((n+p+δ)
(p−δ) ap+n|z|
2p+n≤1.
But Theorem 2.1 ensures that
∞ X
n=0
[1 +λ(np)][(1 +B)n+ 2p+ 2αB+ (B+A)(p−α)] (1−2λ)(B−A)(p−α) .
(a)n+1
(c)n+1
ap+n≤1. (12)
In view of (12), it follows that (11) will be true if
(n+p+δ p−δ )|r|
2p+n ≤ [1 +λ( n p)]
(a)n+1
(c)n+1[(1 +B)n+ 2p+ 2αB+ (B+A)(p−α)]
(1−2λ)(B−A)(p−α) ,
or if
r ≤
"
(p−δ)[1 +λ(np)][(1 +B)n+ 2p+ 2αB+ (B +A)(p−α)] (n+p+δ)(1−2λ)(B −A)(p−α) .
(a)n+1
(c)n+1
#2p+n1
(n ≥0).
(13)
2. In order to prove the second assertion of Theorem 4.1, it sufficient to show that
1 + zff000((zz)) +p 1 + 1+ff0(00z()z)−p+ 2δ
≤1 (0≤δ < p, n∈N).
Note that
1 + zff000((zz)) +p 1 + ff000((zz)) −p+ 2δ
≤
P∞
n=0(n+p)(n+ 2p)ap+n|z|2p+n
2p(p−δ)−P∞n=0(p+n)(n+ 2δ)ap+n|z|2p+n
.
Thus we have the desired inequality
1 + zff000((zz)) +p 1 + ff000((zz)) −p+ 2δ
≤1 (0 ≤δ < p, n ∈N),
∞ X
n=0
(p+n)(p+n+δ) p(p−δ) ap+nr
2p+n≤1. (14)
By Theorem 2.1, (14) will be true if
(p+n)(p+n+δ) p(p−δ) r
2p+n ≤ [1 +λ( n
p)][(1 +B)n+ 2p+ 2αB+ (B+A)(p−α)]
(1−2λ)(B−A)(p−α) . (a)n+1
(c)n+1
.
or if
r≤
"
p(p−δ)[1 +λ(np)](a)n+1
(c)n+1[(1 +B)n+ 2p+ 2αB+ (B+A)(p−α)]
(p+n)(p+n+δ)(1−2λ)(B−A)(p−α)
# 1 2p+n
(n≥0).
(15)
Setting r=r2(p, α, A, B, λ, a, c) in (15), the result follows, and the proof of Theorem 4.1
completed by merely verifying that each assertion is sharp for the function f(z) given by
(8).
5. Closure Theorems
Theorem 5.1 : Letfp−1(z) =
1 zp,
and
fp+n(z) =
1 zp +
(1−2λ)(B−A)(p−α) [1 +λ(n
p)][(1 +B)n+ 2p+ 2αB+ (B+A)(p−α)]
(c)n+1
(a)n+1
Then f(z) is in the class Da,c,λ[p, α, A, B] if and only if it can be expressed in the form
f(z) =
∞ X
n=−1
µp+nfp+n(z),
where µp+n≥0 and
P∞
n=−1µp+n = 1.
proof : First suppose that f(z) can be expressed of the form
f(z) =
∞ X
n=−1
µp+nfp+n(z)
= 1 zp +
∞ X
n=0
µp+n
(1−2λ)(B−A)(p−α)
[1 +λ(np)][(1 +B)n+ 2p+ 2αB+ (B+A)(p−α)] (c)n+1
(a)n+1
zp+n
Then
∞ X
n=0
µp+n
(1−2λ)(B−A)(p−α)
[1 +λ(np)][(1 +B)n+ 2p+ 2αB+ (B+A)(p−α)] (c)n+1
(a)n+1
.[1 +λ(
n
p)][(1 +B)n+ 2p+ 2αB+ (B+A)(p−α)]
(1−2λ)(B−A)(p−α) . (a)n+1
(c)n+1
=
∞ X
n=0
µp+n = 1−µp−1 ≤1,
which shows that f(z)∈Da,c,λ[p, α, A, B].
Conversely, suppose that f ∈Da,c,λ[p, α, A, B]. Then
ap+n ≤
(1−2λ)(B−A)(p−α)
[1 +λ(np)][(1 +B)n+ 2p+ 2αB+ (B+A)(p−α)] (c)n+1
(a)n+1
(n≥0),
and setting
µp+n=
[1 +λ(np)][(1 +B)n+ 2p+ 2αB+ (B+A)(p−α)] (1−2λ)(B −A)(p−α) .
(a)n+1
(c)n+1
ap+n (n≥0),
and
µp−1 = 1−
∞ X
n=0
λp+n,
it follows that f(z) =P∞n=−1µp+nfp+n(z).
Theorem 5.2: The classf ∈Da,c,λ[p, α, A, B] is closed under convex linear combinations.
proof : Let each of the functions
fj(z) =
1 zp +
∞ X
n=0
ap+n,jzp+n, (j = 1,2) (16)
be in the class Da,c,λ[p, α, A, B]. It is sufficient to show that the functionh(z) defined by
h(z) = (1−t)f1(z) +tf2(z), (0≤t≤1)
is also in the class Da,c,λ[p, α, A, B]. Since
h(z) = 1 zp +
∞ X
n=0
[(1−t)ap+n,1+tap+n,2]zp+n (0≤t ≤1),
with the aid of Theorem 2.1, we have
∞ X
n=0
[1 +λ(n p)]
(a)n+1
(c)n+1
[(1 +B)n+ 2p+ 2αB+ (B +A)(p−α)][(1−t)ap+n,1+tap+n,2]
= (1−t)
∞ X
n=0
[1 +λ(n p)]
(a)n+1
(c)n+1
[(1 +B)n+ 2p+ 2αB+ (B+A)(p−α)]ap+n,1
+t
∞ X
n=0
[1 +λ(n p)]
(a)n+1
(c)n+1
[(1 +B)n+ 2p+ 2αB+ (B+A)(p−α)]ap+n,2
≤(1−t)(1−2λ)(B −A)(p−α) +t(1−2λ)(B −A)(p−α)
= (1−2λ)(B −A)(p−α),
which shows that h(z)∈Da,c,λ[p, α, A, B].
This completes the proof of the theorem.
6. Convolution Properties
For functions fj(z)(j = 1,2) defined by (16) belonging to the class
P∗
p, we denote by
(f1∗f2)(z) the convolution (or Hadamard product) of the functionsf1(z) and f2(z); that
is
(f1 ∗f2)(z) =
1 zp +
∞ X
n=0
Theorem 6.1 : Let the functions f1(z) defined by (16) be in the class Da,c,λ[p, α, A, B],
and the function f2(z) defined by (16) be in the classDa,c,[p, γ, A, B]. Then (f1∗f2)(z)∈
Da,c,λ[p, τ, A, B], where
τ ≤pn1− a[2p+2αB+(B+A)(p−2αc(1)][2−p2+2λ)(1+γB+(B)(BB+−AA)()(p−p−γ)]+(1α)(p−−γ2)λ)(B−A)2(p−α)(p−γ) o
.
The result is sharp for the functions fj(z)(j = 1,2) given by
f1(z) =
1 zp +
c(1−2λ)(B −A)(p−α) a[2p+ 2αB+ (B +A)(p−α)]z
p
, (p∈N)
f2(z) =
1 zp +
c(1−2λ)(B−A)(p−γ) a[2p+ 2γB+ (B+A)(p−γ)]z
p, (p∈
N).
proof : Employing the technique used earlier by Schild and Silverman [13], we need to
find the largest τ such that
∞ X
n=0
[1 +λ(np)][(1 +B)n+ 2p+ 2τ B+ (B +A)(p−τ)] (1−2λ)(B−A)(p−τ) .
(a)n+1
(c)n+1
ap+n,1ap+n,2 ≤1,
for f1(z)∈Da,c,λ[p, α, A, B], and f2(z)∈Da,c,λ[p, γ, A, B].
Since f1(z)∈Da,c,λ[p, α, A, B], and f2(z)∈Da,c,λ[p, γ, A, B], we readily see that
∞ X
n=0
[1 +λ(np)][(1 +B)n+ 2p+ 2αB+ (B+A)(p−α)] (1−2λ)(B −A)(p−α) .
(a)n+1
(c)n+1
ap+n,1 ≤1,
∞ X
n=0
[1 +λ(np)][(1 +B)n+ 2p+ 2γB + (B+A)(p−γ)] (1−2λ)(B−A)(p−γ) .
(a)n+1
(c)n+1
ap+n,2 ≤1.
Therefore, by the Cauchy- Schwarz inequality, we obtain
P∞
n=0
[1+λ(np)] (1−2λ)(B−A)).
(a)n+1 (c)n+1
q
[(1+B)n+2p+2αB+(B+A)(p−α)][(1+B)n+2p+2γB+(B+A)(p−γ)] (p−α)(p−γ)
√
ap+n,1ap+n,2 ≤
1.(17)
This implies that we need only to show that
[(1 +B)n+ 2p+ 2τ B+ (B+A)(p−τ)]
(p−τ) ap+n,1ap+n,2 ≤
q
[(1+B)n+2p+2αB+(B+A)(p−α)][(1+B)n+2p+2γB+(B+A)(p−γ)]
(p−α)(p−γ) .
√
ap+n,1ap+n,2 (n≥0),
√
ap+n,1ap+n,2 ≤
(p−τ)√[(1+B)n+2p+2αB+(B+A)(p−α)][(1+B)n+2p+2γB+(B+A)(p−γ)]
√
(p−α)(p−γ)[(1+B)n+2p+τ B+(B+A)(p−τ)] (n≥0).
Hence, by the inequality (17), it is sufficient to prove that
(1−2λ)(B−A)√(p−α)(p−γ)
[1+λ(np)]√[(1+B)n+2p+2αB+(B+A)(p−α)][(1+B)n+2p+2γB+(B+A)(p−γ)]. (c)n+1 (a)n+1
≤ (p−τ)
p
[(1 +B)n+ 2p+αB+ (B +A)(p−α)][(1 +B)n+ 2p+ 2γB+ (B+A)(p−γ)]
p
(p−α)(p−γ)[(1 +B)n+ 2p+ 2τ B+ (B +A)(p−τ)] (n ≥0) (18)
It follows from (18) that
τ ≤p−[1+λ(n (n+2p)(1−2λ)(1+B)(B−A)(p−α)(p−γ)
p)][(1+B)n+2p+2αB+(B+A)(p−α)][(1+B)n+2p+2γB+(B+A)(p−γ)]+(1−2λ)(B−A)2(p−α)(p−γ) (c)n+1 (a)n+1 (n≥
0).
Now, defining the function ϕ(n) by
ϕ(n) =p−[1+λ(n (n+2p)(1−2λ)(1+B)(B−A)(p−α)(p−γ)
p)][(1+B)n+2p+2αB+(B+A)(p−α)][(1+B)n+2p+2γB+(B+A)(p−γ)]+(1−2λ)(B−A)
2(p−α)(p−γ). (c)n+1 (a)n+1.
We see that ϕ(n) is an increasing function ofn(n ≥0).
Therefore, we conclude that
τ ≤ϕ(0) =pn1− a[2p+2αB+(B+A)(p−2αc)][2(1−p2+2λ)(1+γB+(BB)(B+A−A)(p)(−pγ−)]+(1α)(p−−γ2)λ)(B−A)2(p−α)(p−γ)] o
.
Hence the proof is complete.
Putting A=−β and B =β(0< β≤0) in Theorem 6.1, we obtain:
Corollary 6.1 : Let the functions f1(z) defined by (16) be in the class
P∗
p,a,c,λ[α, β],
and the function f2(z) defined by (16) be in the class
P∗
p,a,c,λ[γ, β]. Then (f1∗f2)(z) ∈
P∗
p,a,c,λ[τ, β], where
τ ≤p
1− 2c(1−2λ)β+ (1 +B)(p−α)(p−γ) a(p+αβ)(p−γβ) + (1−2λ)β2(p−α)(p−γ)
.
The result is sharp for the functions fj(z)(j = 1,2) given by
f1(z) =
1 zp +
c(1−2λ)β(p−α) a(p+αβ) z
p, (p∈
N)
f2(z) =
1 zp +
c(1−2λ)β(p−γ) a(p+γβ) z
p, (p∈
N).
Corollary 6.2 : Let the functions f1(z) defined by (16) be in the class
P∗
p[α, β], and
the function f2(z) defined by (16) be in the class
P∗
p[γ, β]. Then (f1∗f2)(z)∈
P∗
p[τ, β],
where
τ ≤p
1− cβ(1−β)(p−α)(p−γ)
a(p+αβ)(p+γβ) +β2(p−α)(p−γ)
.
The result is sharp for the functions fj(z)(j = 1,2) given by
f1(z) =
1 zp +
cβ(p−α) a(p+αβ)z
p, (p∈
N)
f2(z) =
1 zp +
cβ(p−γ) a(p+γβ)z
p
, (p∈N).
Using an argument similar to those in the proof of Theorem 6.1, we obtain the following
result:
Theorem 6.2: Let the functionsfj(z)(j = 1,2) defined by (16) be in the classDa,c,λ[p, α, A, B].
Then (f1∗f2)(z)∈Da,c,λ[p, γ, A, B], where
γ ≤p
1− 2c
2(1−2λ)(1 +B)(B−A)(p−α)2
a2[2p+ 2αB+ (B+A)(p−α)]2+ (1−2λ)[(B −A)(p−α)]2
.
The result is sharp for the functions fj(z)(j = 1,2) given by
fj(z) =
1 zp +
c(1−2λ)(1 +B)(B−A)(p−α) a[2p+ 2αB+ (B +A)(p−α)] z
p, (j = 1,2;p∈
N) (19)
Putting A=−β and B =β(0< β≤1) in Theorem 6.2, we obtain:
Corollary 6.3 : Let the functions fj(z)(j = 1,2) defined by (16) be in the class
P∗
p,a,c,λ[α, β]. Then (f1∗f2)(z)∈
P∗
p,a,c,λ[γ, β], where
γ ≤p
1− c(1−2λ)β(1 +B)(p−α)
2
a(p+αβ)2+ (1−2λ)β2(p−α)2
.
The result is sharp for the functions fj(z)(j = 1,2) given by
fj(z) =
1 zp +
c(1−2λ)β(p−α) a(p+αβ) z
p, (j = 1,2;p∈
Putting λ= 0 in Corollary 6.3, we obtain:
Corollary 6.4: Let the functionsfj(z)(j = 1,2) defined by (16) be in the class
P∗
p[α, β].
Then (f1∗f2)(z)∈
P∗
p[γ, β], where
γ ≤p
1− cβ(1 +β)(p−α)
2
a(p+αβ)2+β2(p−α)2
.
The result is sharp for the functions fj(z)(j = 1,2) given by
fj(z) =
1 zp +
cβ(p−α) a(p+αβ)z
p, (j = 1,2;p∈
N)
Theorem 6.3 : If f1(z) = z1p + P∞
n=0ap+n,1z
p+n ∈ D
a,c,λ[p, α, A, B] and f2(z) = z1p + P∞
n=0ap+n,2z
p+n ∈ D
a,c,λ[p, α, A, B] with |ap+n,2| ≤ 1, n = 1,2, ...,, then (f1 ∗f2)(z) ∈
Da,c,λ[p, α, A, B].
proof : Since
∞ X
n=0
[1 +λ(np)][(1 +B)n+ 2p+ 2αB+ (B+A)(p−α)] (1−2λ)(B−A)(p−α) .
(a)n+1
(c)n+1
|ap+n,1ap+n,2|
=
∞ X
n=0
[1 +λ(np)][(1 +B)n+ 2p+ 2αB+ (B+A)(p−α)] (1−2λ)(B−A)(p−α) .
(a)n+1
(c)n+1
ap+n,1|ap+n,2|,
≤
∞ X
n=0
[1 +λ(np)][(1 +B)n+ 2p+ 2αB+ (B+A)(p−α)] (1−2λ)(B−A)(p−α) .
(a)n+1
(c)n+1
ap+n,1,
≤1.
By Theorem 2.1, it follows that (f1∗f2)(z)∈Da,c,λ[p, α, A, B].
This completes the proof of the theorem.
Corollary 6.5 : If f1(z) = z1p + P∞
n=0ap+n,1z
p+n ∈ D
a,c,λ[p, α, A, B] and f2(z) = z1p + P∞
n=0ap+n,2z
p+n∈D
a,c,λ[p, α, A, B] with (0 ≤ap+n,2 ≤1, n= 1,2, ...,), then (f1∗f2)(z)∈
Da,c,λ[p, α, A, B].
Theorem 6.4: Let the functionsfj(z)(j = 1,2) defined by (16) be in the classDa,c,λ[p, α, A, B]
and
2(p+αβ)a
then the function h(z) defined by
h(z) = 1 zp +
∞ X
n=0
(a2p+n,1+ap2+n,2)zp+n, (20)
belongs to the class Da,c,λ[p, α, A, B].
proof : Since f1(z)∈Da,c,λ[p, α, A, B], we get:
∞ X
n=0
[1 +λ(np)][(1 +B)n+ 2p+ 2αB+ (B+A)(p−α)] (1−2λ)(B −A)(p−α) .
(a)n+1
(c)n+1
ap+n,1 ≤1.
and so
∞ X
n=0
"
[1 +λ(np)][(1 +B)n+ 2p+ 2αB+ (B+A)(p−α)] (1−2λ)(B−A)(p−α) .
(a)n+1
(c)n+1
#2
a2p+n,1 ≤1.
Similarly, since f2(z)∈Da,c,λ[p, α, A, B], we have
∞ X
n=0
"
[1 +λ(np)][(1 +B)n+ 2p+ 2αB+ (B+A)(p−α)] (1−2λ)(B−A)(p−α) .
(a)n+1
(c)n+1
#2
a2p+n,2 ≤1.
Hence
∞ X
n=0
1 2
"
[1 +λ(np)][(1 +B)n+ 2p+ 2αB+ (B +A)(p−α)] (1−2λ)(B −A)(p−α) .
(a)n+1
(c)n+1
#2
(a2p+n,2+a2p+n,2)≤1.
In view of Theorem 2.1, it is sufficient to show that
∞ X
n=0
"
[1 +λ(np)][(1 +B)n+ 2p+ 2αB+ (B+A)(p−α)] (1−2λ)(B−A)(p−α) .
(a)n+1
(c)n+1
#
(a2p+n,1+a2p+n,2)≤1.
(21)
Thus the inequality (21) will be satisfied if, for n= 0,1,2, ...
[1 +λ(np)][(1 +B)n+ 2p+ 2αB+ (B +A)(p−α)] (1−2λ)(B−A)(p−α) .
(a)n+1
(c)n+1
≤ 1 2
"
[1 +λ(np)][(1 +B)n+ 2p+ 2αB+ (B+A)(p−α)] (1−2λ)(B−A)(p−α) .
(a)n+1
(c)n+1
#2
,
or if
[1+λ(n p)]
(a)n+1
(c)n+1
for n = 0,1,2, .... Then left hand side of (22) is an increasing function of n, and hence
(22) is satisfied for all n if
2(p+αβ)a
c + (p−α)[3A−B+ 4λ(B−A)]≥0,
which is true by our assumption.
This completes the proof of the theorem.
Putting λ= 0 in Theorem 6.4, we obtain:
Corollary 6.6 : Let the functions fj(z)(j = 1,2) defined by (16) be in the class
Da,c[p, α, A, B] and
2(p+αβ)c
a + (p−α)(3A−B)≥0,
then the function h(z) defined by (20) belongs to the class Da,c[p, α, A, B].
Theorem 6.5: Let the functionsfj(z)(j = 1,2) defined by (16) be in the classDa,c,λ[p, α, A, B].
Then the function h(z) defined by (20) belongs to the classDa,c,λ[p, γ, A, B], where
γ ≤p
1− 4c
2(1−2λ)(1 +B)(B−A)(p−α)2
a2[2p+ 2αB+ (B +A)(p−α)]2) + 2(1−2λ)[(B −A)(p−α)]2
.
The result is sharp for the functions fj(z)(j = 1,2) defined by (19).
proof : Noting that
∞ X
n=0
[[1 +λ(np)][(1 +B)n+ 2p+ 2αB+ (B +A)(p−α)]]2 [(1−2λ)(B −A)(p−α)]2 .[
(a)n+1
(c)n+1
]2a2p+n,j
≤
∞ X
n=0
[1 +λ(np)][(1 +B)n+ 2p+ 2αB+ (B+A)(p−α)] (1−2λ)(B−A)(p−α) .
(a)n+1
(c)n+1
ap+n,j
!2
≤1 (j = 1,2),
for fj(z)∈Da,c,λ[p, γ, A, B](j = 1,2), we have
∞ X
n=0
1 2
"
[1 +λ(np)][(1 +B)n+ 2p+ 2αB+ (B +A)(p−α)] (1−2λ)(B −A)(p−α) .
(a)n+1
(c)n+1
#2
(a2p+n,1+a2p+n,2)≤1.
Therefore, we have to find the largest γ such that
≤ [1 +λ(
n
p)][(1 +B)n+ 2p+ 2αB+ (B+A)(p−α)]
2
2(1−2λ)(B−A)(p−α)2 .
(a)n+1
(c)n+1
, (n≥0)
that is, that
γ ≤p−
2(2p+n)(1−2λ)(1 +B)(B −A)(p−α)2
[1 +λ(np)](a)n+1 (c)n+1]
2[(1 +B)n+ 2p+ 2αB+ (B +A)(p−α)]2+ 2(1−2λ)[(B −A)(p−α)]2. (n ≥0)
Now, defining the function ϕ(n) by
ϕ(n) = p−
2(2p+n)(1−2λ)(1 +B)(B −A)(p−α)2
[1 +λ(np)](a)n+1 (c)n+1]
2[(1 +B)n+ 2p+ 2αB+ (B +A)(p−α)]2+ 2(1−2λ)[(B −A)(p−α)]2. (n ≥0)
We see that ϕ(n) is an increasing function ofn.Thus, we conclude that
γ ≤ϕ(0) =p
1− 4c(1−2λ)(1 +B)(B −A)(p−α)
2
a[2p+ 2αB+ (B+A)(p−α)]2+ 2(1−2λ)[(B−A)(p−α)]2
.
Hence the proof is complete.
Putting A=−β and B =β(0< β≤1) and λ= 0 in Theorem 6.5, we obtain:
Corollary 6.7: Let the functionsfj(z)(j = 1,2) defined by (16) be in the class
P∗
p[α, β].
Then the function h(z) defined by (20) belongs to the classP∗p[γ, β], where
γ ≤p
1− 2β(1 +β)(p−α)
2
(p+αβ)2+ 2β2(p−α)
.
The result is sharp for the functions fj(z)(j = 1,2) defined by (19).
7. Integral Transforms
In this section, we consider integral transforms of functions in the classesP∗p,a,c,λ[α, β] and P∗p[α, β].
Theorem 7.1 : If f(z) is in the class P∗p,a,c,λ[α, β], then the integral transforms
Fd+p−1(z) =d
Z 1
0
are in the class P∗p[δ],0≤δ < p, where
δ =δ(α, β, a, c, d, p, λ) = p
(d+ 2p)(p+αβ)a
c −β(p−α)d(1−2λ)
(d+ 2p)(p+αβ)ac +β(p−α)d(1−2λ)
.
The result is the best possible for the function f(z) given by
f(z) = 1 zp +
(1−2λ)β(p−α) p+αβ .
c az
p, (p∈
N)
proof : Suppose f(z) = z1p + P∞
n=0ap+nz
p+n∈P∗
p,a,c,λ[α, β]. Then we have
Fd+p−1(z) = d
Z 1
0
ud+p−1f(uz)du= 1 zp +
∞ X
n=0
dap+n
n+d+ 2pz
p+n.
In view of Corollary 2.2, it is sufficient to show that
∞ X
n=0
n+p+δ p−δ
dap+n
n+d+ 2p ≤1. (24)
Since f(z)∈P∗p,a,c,λ[α, β], we have
∞ X
n=0
[1 +λ(np)][(1 +B)n+ 2p+αβ)] (1−2λ)2β(p−α) .
(a)n+1
(c)n+1
ap+n ≤1.
Thus (24) will be satisfied if
(n+p+δ)d (p−δ)(n+d+ 2p) ≤
[1 +λ(np)][(1 +B)n+ 2(p+αββ)] (1−2λ)2β(p−α) .
(a)n+1
(c)n+1
(n≥0),
or
δ≤ p(n+d+ 2p)[1 +λ(
n p)]
(a)n+1
(c)n+1[(1 +B)n+ 2(p+αβ)]−(n+p)d(1−2λ)2β(p−α)]
(n+d+ 2p)[1 +λ(np)]((a)n+1
(c)n+1)[(1 +B)n+ 2(p+αβ) +d(1−2λ)2β(p−α)
.
(25)
Since the right hand side of (25) is an increasing function of n, putting n= 0 in (25), we
get
δ≤p
(
(d+ 2p)(p+αβ)(ac)−β(p−α)d(1−2λ) (d+ 2p)(p+αβ)(a)n+1
(c)n+1 +β(p−α)d(1−2λ) )
.
Putting λ= 0 in Theorem 7.1, we get:
Corollary 7.1 : If f(z) is in the class P∗p[α, β], then the integral transforms (23)are in the class P∗p[δ],0≤δ < p, where
δ =δ(α, β, a, c, d, p) =p
(d+ 2p)(p+αβ)a
c −β(p−α)d
(d+ 2p)(p+αβ)ac +β(p−α)d
.
The result is the best possible for the function f(z) given by
f(z) = 1 zp +
β(p−α) p+αβ .
c az
p,(p∈
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