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Volume 2008, Article ID 417089,15pages doi:10.1155/2008/417089

Research Article

A New Hybrid Iterative Algorithm for

Fixed-Point Problems, Variational Inequality

Problems, and Mixed Equilibrium Problems

Yonghong Yao,1 Yeong-Cheng Liou,2 and Jen-Chih Yao3

1Department of Mathematics, Tianjin Polytechnic University, Tianjin 300160, China 2Department of Information Management, Cheng Shiu University, Kaohsiung 833, Taiwan 3Department of Applied Mathematics, National Sun Yat-Sen University, Kaohsiung 804, Taiwan

Correspondence should be addressed to Jen-Chih Yao,[email protected]

Received 29 August 2007; Accepted 6 February 2008

Recommended by Tomonari Suzuki

We introduce a new hybrid iterative algorithm for finding a common element of the set of fixed points of an infinite family of nonexpansive mappings, the set of solutions of the variational inequality of a monotone mapping, and the set of solutions of a mixed equilibrium problem. This study, proves a strong convergence theorem by the proposed hybrid iterative algorithm which solves fixed-point problems, variational inequality problems, and mixed equilibrium problems.

Copyrightq2008 Yonghong Yao et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

1. Introduction

Let Cbe a nonempty closed convex subset of a real Hilbert space H. Recall that a mapping

f : CCis called contractive if there exists a constantα ∈ 0,1such thatfxfy

αxyfor allx, yC. A mappingT :CCis said to be nonexpansive ifTxTyxy for allx, yC. Denote the set of fixed points ofT byFT.

Letϕ:CRbe a real-valued function andΘ:C×CRbe an equilibrium bifunction, that is,Θu, u 0 for eachuC. The mixed equilibrium problemfor short, MEPis to find

xCsuch that

MEP: Θx, yϕyϕx∗≥0 ∀yC. 1.1 In particular, ifϕ≡ 0, this problem reduces to the equilibrium problemfor short, EP, which is to findx∗∈Csuch that

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Denote the set of solutions of MEP by Ω. The mixed equilibrium problems include fixed-point problems, optimization problems, variational inequality problems, Nash equilibrium problems, and the equilibrium problems as special cases see, e.g., 1–5 . Some methods

have been proposed to solve the MEP and EP see, e.g., 5–14 . In 1997, Combettes and

Hirstoaga13 introduced an iterative method of finding the best approximation to the initial data and proved a strong convergence theorem. Subsequently, S. Takahashi and W. Takahashi 8 introduced another iterative scheme for finding a common element of the set of solutions of EP and the set of fixed-point points of a nonexpansive mapping. Yao et al.12 considered an iterative scheme for finding a common element of the set of solutions of EP and the set of common fixed points of an infinite nonexpansive mappings. Very recently, Zeng and Yao 14 considered a new iterative scheme for finding a common element of the set of solutions of MEP and the set of common fixed points of finitely many nonexpansive mappings. Their results extend and improve many results in the literature.

LetAofCintoHbe a nonlinear mapping. It is well known that the variational inequality problem is to finduCsuch that

Au, vu ≥0 ∀vC. 1.3

The set of solutions of the variational inequality problem is denoted byV IC, A. A mapping

A: CH is calledβ-inverse-strongly monotone if there exists a positive real numberβsuch that

AuAv, uvβAuAv2 u, vC. 1.4

Recently, some authors have proposed new iterative algorithms to approximate a common element of the set of fixed points of a nonxpansive mapping and the set of solutions of the variational inequality. For the details, see15,16 and the references therein.

Motivated by the recent works, in this paper we introduce a new hybrid iterative algorithm for finding a common element of the set of fixed points of an infinite family of nonexpansive mappings, the set of solutions of the variational inequality of a monotone mapping, and the set of solutions of a mixed equilibrium problem. We prove a strong convergence theorem by the proposed hybrid iterative algorithm which solves fixed-point problems, variational inequality problems, and mixed equilibrium problems.

2. Preliminaries

LetHbe a real Hilbert space with inner product·,·and norm·. LetCbe a nonempty closed convex subset ofH. Then for anyxH, there exists a unique nearest point inC, denoted by

PCxsuch that

xPCxxyyC. 2.1

Such aPCis called the metric projection ofHontoC. It is well known thatPCis a nonexpansive

mapping and satisfies

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Moreover,PCis characterized by the following properties:

xPCx, yPCx≤0,

xy2xP

Cx2yPCx2 ∀xH, yC.

2.3

It is clear that

uV IC, A⇐⇒uPCuλAuλ >0. 2.4

In this paper, for solving the mixed equilibrium problems for an equilibrium bifunction Θ:C×CR, we assume thatΘsatisfies the following conditions:

H1 Θis monotone, that is,Θx, y Θy, x≤0 for allx, yC;

H2for each fixedyC,x→Θx, yis concave and upper semicontinuous; H3for eachxC,y→Θx, yis convex.

A mappingη:C×CHis called Lipschitz continuous if there exists a constantλ >0 such that

ηx, yλxyx, y C. 2.5

A differentiable functionK:CRon a convex setCis called: iη-convex if

KyKxKx, ηy, x x, yC, 2.6

whereKis the Fr´echet derivative ofKatx;

iiη-strongly convex if there exists a constantσ >0 such that

KyKxKx, ηy, xσ 2

xy2 x, yC. 2.7

LetCbe a nonempty closed convex subset of a real Hilbert spaceH,ϕ:CRbe a real-valued function, andΘ: C×CRbe an equilibrium bifunction. Letrbe a positive number. For a given pointxC, the auxiliary problem for MEP consists of findingyCsuch that

Θy, z ϕzϕy 1rKyKx, ηz, y0 zC. 2.8

LetSr :CCbe the mapping such that for eachxC,Srxis the solution set of the auxiliary

problem MEP, that is,

Srx yCy, z ϕzϕy 1rKyKx, ηz, y≥0∀zC

xC.

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Lemma 2.1see14 . LetC be a nonempty closed convex subset of a real Hilbert space H and let

ϕ : CRbe a lower semicontinuous and convex functional. LetΘ : C×CRbe an equilibrium bifunction satisfying conditions (H1)–(H3). Assume that

iη:C×CHis Lipschitz continuous with constantλ >0such that aηx, y ηy, x 0for allx, yC,

bη·,·is affine in the first variable,

cfor each fixedyC,xηy, xis sequentially continuous from the weak topology to the weak topology;

iiK : CRisη-strongly convex with constantσ > 0and its derivative K is sequentially continuous from the weak topology to the strong topology;

iiifor eachxC, there exist a bounded subsetDxCandzxCsuch that for anyyC\Dx,

Θy, zxϕzxϕy 1rKyKx, ηzx, y<0. 2.10

Then there hold the following:

iSris single-valued;

iiSris nonexpansive ifKis Lipschitz continuous with constantν >0such thatσλνand

Kx

1

Kx

2

, ηu1, u2

Ku

1

Ku

2

, ηu1, u2

x1, x2

C×C, 2.11

whereuiSrxifori1,2;

iiiFSr Ω;

vi Ωis closed and convex.

We also need the following lemmas for proving our main results.

Lemma 2.2see17 . Let{xn}and{zn}be bounded sequences in a Banach spaceXand let{βn}be

a sequence in0,1 with0< lim infn→∞βn ≤lim supn→∞βn <1. Supposexn1 1−βnznβnxn

for all integersn≥0andlim supn→∞zn1−znxn1−xn≤0. Thenlimn→∞znxn0.

Lemma 2.3 see 18 . Assume {an} is a sequence of nonnegative real numbers such that an1 ≤

1−γnanδn, where{γn}is a sequence in0,1and{δn}is a sequence such that

1∞n1γn;

2lim supn→∞δn/γn≤0orn1|δn|<.

Thenlimn→∞an0.

3. Iterative algorithm and strong convergence theorems

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infinite mappings ofCinto itself and letξ1, ξ2, . . .be real numbers such that 0≤ξi≤1 for every iN. For anynN, define a mappingWnofCinto itself as follows:

Un,n1I,

Un,n ξnTnUn,n1

1−ξnI, Un,n−1ξn−1Tn−1Un,n

1−ξn−1

I,

.. .

Un,kξkTkUn,k1

1−ξkI, Un,k−1ξk−1Tk−1Un,k 1−ξk−1I,

.. .

Un,2ξ2T2Un,3 1−ξ2I,

WnUn,1 ξ1T1Un,2

1−ξ1

I.

3.1

SuchWnis called theW-mapping generated byTn, Tn−1, . . . , T2, T1andξn, ξn−1, . . . , ξ2, ξ1. For the

iterative algorithm for a finite family of nonexpansive mappings, we refer the reader to19 .

We have the following crucial Lemmas3.1and3.2concerningWnwhich can be found in

20 . Now we only need the following similar version in Hilbert spaces.

Lemma 3.1. Let C be a nonempty closed convex subset of a real Hilbert space H. Let T1, T2, . . . be

nonexpansive mappings of C into itself such thatn1FTn is nonempty, and let ξ1, ξ2, . . . be real

numbers such that 0 < ξib < 1 for any iN. Then for every xC and kN, the limit

limn→∞Un,kxexists.

Lemma 3.2. Let C be a nonempty closed convex subset of a real Hilbert space H. Let T1, T2, . . . be

nonexpansive mappings of C into itself such thatn1FTn is nonempty, and let ξ1, ξ2, . . . be real

numbers such that0< ξib <1for anyiN. ThenFWn1FTn.

The following remark12 is important to prove our main results.

Remark 3.3. Using Lemma 3.1, one can define a mapping W of C into itself as Wx limn→∞Wnx limn→∞Un,1x for every xC. If {xn} is a bounded sequence in C, then we

have

lim

n→∞WxnWnxn0. 3.2 Throughout this paper, we will assume that 0< ξib <1 for everyiN.

Now we introduce the following iteration algorithm.

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contraction ofCinto itself with coefficientα∈0,1and givenx0∈Carbitrarily. Suppose that

the sequences{xn}and{yn}are generated iteratively by

Θzn, xϕxϕzn1rKznKxn, ηx, zn≥0 ∀xC, ynPCznλnAzn,

xn1αnfWnxnβnxnγnWnPCynλnAynn≥0,

3.3

where{αn},{βn}, and{γn}are three sequences in0,1, and{λn}is a sequence in0,2β .

Now we study the strong convergence of the hybrid iterative algorithm3.3.

Theorem 3.5. LetCbe a nonempty closed convex subset of a real Hilbert spaceH and letϕ: CR be a lower semicontinuous and convex functional. LetΘ : C×CRbe an equilibrium bifunction satisfying conditions (H1)–(H3) and letT1, T2, . . .be an infinite family of nonexpansive mappings ofC

into itself. LetA:CHbe aβ-inverse-strongly monotone mapping such that∩∞n1FTnV IA, C

Ω /∅. Suppose{αn},{βn}, and{γn}are three sequences in0,1withαnβnγn1, n≥0. Assume

that

iη:C×CHis Lipschitz continuous with constantλ >0such that aηx, y ηy, x 0for allx, yC,

bη·,·is affine in the first variable,

cfor each fixedyC,xηy, xis sequentially continuous from the weak topology to the weak topology;

iiK : CR is η-strongly convex with constant σ > 0 and its derivative K is not only sequentially continuous from the weak topology to the strong topology but also Lipschitz continuous with constantν >0such thatσλν;

iiifor eachxC; there exist a bounded subsetDxCandzxCsuch that for anyyC\Dx,

Θy, zxϕzxϕy 1rKyKx, ηzx, y<0; 3.4

ivlimn→∞αn 0, ∞n0αn, 0 < lim infn→∞βn ≤ lim supn→∞βn < 1, λna, b ⊂ 0,2β, andlimn→∞λn1−λn 0.

Letf be a contraction ofCinto itself and givenx0 ∈Carbitrarily. Then the sequence{xn}generated

by3.3converges strongly toxPΓfx∗, whereΓ ∩n1FTnV IA, C∩Ωprovided thatSr is

firmly nonexpansive.

Proof. We first note thatfis a contraction with coefficientα∈0,1. ThenPΓfxPΓfy

fxfyαxyfor allx, yC. ThereforePΓf is a contraction ofCinto itself which

implies that there exists a unique elementx∗∈Csuch thatxPΓfx∗.

Next we divide the following proofs into several steps.

Step 1 {xn}, {yn}, and {zn}are bounded. Let x∗ ∈ Γ. From the definition ofSr, we know that znSrxn. It follows that

znxS

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For allx, yCandλn∈0,2β , we note that

IλnA

xIλnAy2xyλnAxAy2

xy22λ

nAxAy, x2nAxAy2

xy2λ

nλn−2βAxAy2,

3.6

which implies thatIλnAis nonexpansive.

Setun PCynλnAynfor all n ≥ 0. From 2.4, we have that xPCx∗−λnAx∗. It

follows from3.6that ynxP

CznλnAznPCx∗−λnAx

znλnAznx∗−λnAx∗≤znx∗≤xnx,

unxP

CynλnAynPCx∗−λnAx

ynλnAynx∗−λnAx∗≤ynx∗≤xnx.

3.7

Hence we obtain that xn1xα

nfWnxnxβnxnxγnWnunx

αnfWnxnxβnxnxγnWnunx

αnfWnxnfxαnfx∗−xβnxnxγnunx

αnβxnxαnfx∗−xβnxnxγnxnx

1−βαn

f

xx

1−β

1−1−βαnxnx

≤max xnx,

f

xx∗ 1−β

≤max x0−x,

f

xx∗ 1−β

.

3.8

Therefore{xn}is bounded, so are{yn}and{zn}.

Step 2xn1−xn →0. Settingxn1βnxn 1−βnVnfor alln≥0. It follows that

Vn1−Vn

xn2−βn1xn1

1−βn1 −

xn1−βnxn

1−βn

αn1f

Wn1xn1

γn1Wn1un1

1−βn1 −

αnfWnxnγnWnun

1−βn

αn1f

Wn1xn1

1−βn1 −

αnfWnxn

1−βn γn1

1−βn1

Wn1un1−Wn1un

γ

n1

1−βn1 −

γn

1−βn

Wn1un1γnβ n

Wn1unWnun,

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which implies that

Vn1Vn αn1

1−βn1

f

Wn1xn1Wn1un

αn 1−βn

f

WnxnWn1un

γn1 1−βn1

un1un γn

1−βn

Wn1unWnun.

3.10

Now we estimateun1−unandWn1unWnun.

From3.1, sinceTiandUn,iare nonexpansive, we have

Wn1unWnunξ1T1Un1,2unξ1T1Un,2un

ξ1Un1,2unUn,2un

ξ1ξ2T2Un1,3unξ2T2Un,3unξ1ξ2Un1,3unUn,3un

≤ · · ·

ξ1ξ2· · ·ξnUn1,n1unUn,n1un

Mn i1

ξi,

3.11

whereMis a constant such thatsup{Un1,n1unUn,n1un, n≥0} ≤M.

At the same time, we observe that yn1ynPC

zn1−λn1Azn1

PCznλnAzn

zn1−λn1Azn1

znλnAzn

zn1−λn1Azn1

znλn1Aznλnλn1

Azn

zn1−λn1Azn1

znλn1Aznλnλn1Azn

zn1−znλnλn1Azn,

un1unPC

yn1−λn1Ayn1

PCynλnAyn

yn1−λn1Ayn1

ynλnAyn

yn1−λn1Ayn1

ynλn1Ayn

λnλn1

Ayn

yn1−ynλnλn1Ayn

zn1−znλnλn1AynAzn.

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SinceznSrxnandzn1Srxn1, from the nonexpansivity ofSr, we get

zn1znxn1xn. 3.13 Substituting3.11–3.13into3.10, we have

Vn1Vnxn1xn αn1

1−βn1

f

Wn1xn1Wn1un

αn 1−βn

f

WnxnWn1unM n

i1

ξi

λnλn1AynAzn.

3.14

Sinceαn→0, λn1−λn→0, andξia, b , we have

lim sup

n→∞

Vn1Vnxn1xn0. 3.15

Hence byLemma 2.2, we have

lim

n→∞Vnxn0. 3.16 Consequently,

lim

n→∞xn1−xn0. 3.17 Step 3unWun →0. Note thatxn1−xnαnfWnxnxn γnWnunxn. Then we have

xnWnun 1

γn

xnxn1αnf

Wnxnxn−→0. 3.18

Forx∗∈Γ, noting thatSris firmly nonexpansive, we have

znx∗2S

rxnSrx∗2

SrxnSrx, xnx

znx, xnx

1

2znx

∗2x

nx∗2−xnzn2,

3.19

and hence

znx∗2x

nx∗2−xnzn2. 3.20

So, we have

xn1x∗2α

nfWnxnx∗2βnxnx∗2γnWnunx∗2

αnfWnxnx∗2βnxnx∗2γnunx∗2

αnfWnxnx∗2βnxnx∗2γnznx∗2

αnfWnxnx∗2βnxnx∗2γnxnx∗2−xnzn2

αnfWnxnx∗2xnx∗2−γnxnzn2,

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that is,

xnzn2 1

γn

αnfWnxnx∗2xnx∗2−xn1−x∗2

γ1

n

αnfWnxnx∗2xn1−xnxnxxn1−x

−→0.

3.22

From3.6, we obtain that

xn1x∗2 α

nfWnxnx∗2βnxnx∗2γnynx∗2

αnfWnxnx∗2βnxnx∗2γnznλnAznx∗−λnAx∗2

αnfWnxnx∗2βnxnx∗2γnznx∗2λnλn−2βAznAx∗2

αnfWnxnx∗2xnx∗2γnab−2βAznAx∗2.

3.23 Then we have

γnab−2βAznAx∗2≤αnfWnxnx∗2xnx∗2−xn1−x∗2−→0, 3.24

which implies that

lim

n→∞AznAx

0. 3.25

We note that ynx∗2P

CznλnAznPCx∗−λnAx∗2

znλnAznx∗−λnAx, ynx

1 2

znλnAznx∗−λnAx∗2ynx∗2

znλnAznx∗−λnAx∗−ynx∗2

≤ 1

2

znx∗2ynx∗2−znynλnAznAx∗2

1 2

znx∗2ynx∗2−znyn22λnAznAx, znynλ2nAznAx∗2

.

3.26 Then we derive

ynx∗2z

nx∗2−znyn22λnAznAx, znynλ2nAznAx∗2

xnx∗2−znyn22λnAznAx, znyn.

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Hence

xn1x∗2

αnfWnxnx∗2βnxnx∗2γnxnx∗2−znyn22λnAznAx, znyn,

3.28 which implies that

znynγ1 n

αnfWnxnx∗2xnx∗2−xn1−x∗22γnλnAznAxznyn−→0.

3.29 SinceynunPCznλnAznPCynλnAynznyn, we have

WununWunWnunWnunun

WunWnunWnunxnxnznznynynun

WunWnunWnunxnxnzn2znyn.

3.30

Combining the above inequality,3.18–3.29, andRemark 3.3, we have lim

n→∞Wunun0. 3.31 Step 4limn→∞fx∗−x, xnx∗, wherexPΓfx∗. To show the above inequality, we can

choose a subsequence{uni}of{un}such that

lim

j→∞

fxx, u

njx

lim sup

n→∞

fxx, u

nx. 3.32

Since{unj}is bounded, there exists a subsequence{unji}of{unj}which converges weakly tow. Without

loss of generality, we can assume thatunj w. FromWunun →0, we obtainWunj w.

First, we show wFW ∩∞n1FTn. Assume that ω /FW. Since unj w and w /Ww, by Opial’s condition, we have

lim inf

j→∞ unjw<lim infj→∞ unjWw

≤lim inf

j→∞ unjWunjWunjWw

≤lim inf

j→∞ unjw,

3.33

which is a contradiction. Hence we getwFW. By the same argument as that in the proof of [21, Theorem 3.1], we can prove thatwV IA, C; and by the same argument as that in the proof of [14, Theorem 4.1], we also can prove thatw∈Ω. Hencew∈Γ.

SincexPΓfx∗∈Γandunxn →0, we have

lim sup

n→∞

fxx, x

nx∗lim j→∞

fxx, x

njx

lim

j→∞

fxx, u

njx

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Step 5xnx∗, wherexPΓfx∗. From3.3, we have

xn1x∗2β

nxnxγnWnunx∗22αnfWnxnx, xn1−x

βnxnxγnunx∗22αnfWnxnfx, xn1−x

2αnfx∗−x, xn1−x

≤1−αn2xnx∗22αnfWnxnfxxn1−x

2αnfx∗−x, xn1−x

≤1−αn2xnx∗22ααnxnxxn1−x∗2αnfx∗−x, xn1−x

≤1−αn2xnx∗2ααnxnx∗2xn1−x∗2

2αnfx∗−x, xn1−x,

3.35 that is,

xn1x∗2

1−21−α 1−ααnαn

xnx∗2211ααα nαn

αn

21−αxnx

2 1

1−α

fxx, x

n1−x.

3.36 It is easy to see thatn021−α/1−ααnαnand

lim sup

n→∞

αn

21−αxnx

2 1

1−α

fxx, x

n1−x

≤0. 3.37

ApplyingLemma 2.3and3.34to3.36, we conclude thatxnxasn → ∞. This completes the

proof.

ConcerningSr, we give the following remark.

Remark 3.6. For eachx1, x2∈C, we denoteu1Srx1andu2 Srx2. Then for allyC, we

have

rΘu1, y

ϕyϕu1

Ku

1

Kx

1

, ηy, u1

≥0, 3.38

rΘu2, y

ϕyϕu2

Ku

2

Kx

2

, ηy, u2

≥0. 3.39 Takingyu2in3.38andyu1in3.39, and adding up these two inequalities, we obtain

rΘu1, u2

ϕu2

ϕu1

Ku

1

Kx

1

, ηu2, u1

rΘu2, u1

ϕu1

ϕu2

Ku2

Kx2

, ηu1, u2

≥0.

3.40

Note thatηu1, u2 ηu2, u1 0 andΘu1, u2 Θu2, u1≤0. Hence from3.40, we deduce

Kx

1

Ku

1

, ηu1, u2

Ku

2

Kx

2

, ηu1, u2

(13)

which implies that

Kx1

Kx2

, ηu1, u2

Ku1

Ku2

, ηu1, u2

. 3.42

SinceK : CHisη-strongly monotone with constantμ > 0, then from3.42, we conclude

that

Kx

1

Kx

2

, ηu1, u2

μu1−u22. 3.43

TakeKx x2/2,ηy, x yx, andμ1. Then from3.43, we have

x1−x2, u1−u2

u1−u22. 3.44

This indicates thatSris firmly nonexpansive.

Corollary 3.7. LetCbe a nonempty closed convex subset of a real Hilbert spaceHand letϕ:CR be a lower semicontinuous and convex functional. LetΘ : C×CRbe an equilibrium bifunction satisfying conditions (H1)–(H3). LetA:CHbe aβ-inverse-strongly monotone mapping such that

V IA, C∩Ω /∅. Suppose{αn}, {βn}, and{γn}are three sequences in0,1withαnβnγn

1, n≥0. Assume that

iη:C×CHis Lipschitz continuous with constantλ >0such that

aηx, y ηy, x 0for allx, yC, bη·,·is affine in the first variable,

cfor each fixedyC,xηy, xis sequentially continuous from the weak topology to the weak topology;

iiK : CR is η-strongly convex with constant σ > 0 and its derivative K is not only sequentially continuous from the weak topology to the strong topology but also Lipschitz continuous with constantν >0such thatσλν;

iiifor eachxC, there exist a bounded subsetDxCandzxCsuch that, for anyyC\Dx,

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ivlimn→∞αn 0,∞n0αn, 0 < lim infn→∞βn ≤ lim supn→∞βn < 1, λna, b ⊂ 0,2β, andlimn→∞λn1−λn 0.

Letf be a contraction ofCinto itself and givenx0 ∈Carbitrarily. Let the sequences{xn},{yn}, and

{zn}be generated iteratively by

Θzn, xϕxϕzn1rKznKxn, ηx, zn≥0 ∀xC, ynPCznλnAzn,

xn1αnfxnβnxnγnPCynλnAynn≥0.

3.46

Then the sequence{xn}generated by3.46converges strongly toxPΓfx∗, whereΓ V IA, C

Ωprovided thatSris firmly nonexpansive.

Proof. TakeTnx xfor alln 1,2, . . ., and for allxCin3.1. ThenWnx xfor all xC.

The conclusion follows immediately fromTheorem 3.5. This completes the proof.

Corollary 3.8. LetCbe a nonempty closed convex subset of a real Hilbert space H. LetT1, T2, . . .be

an infinite family of nonexpansive mappings ofCinto itself. LetA : CH be a β-inverse-strongly monotone mapping such that ∩∞n1FTnV IA, C/∅. Suppose {αn}, {βn}, and {γn} are three

sequences in0,1withαnβnγn1,n≥0. Assume that

ilimn→∞αn0andn0αn;

ii0<lim infn→∞βn≤lim supn→∞βn<1;

iiiλna, b ⊂0,2βandlimn→∞λn1−λn 0.

Let f be a contraction of Cinto itself and given x0 ∈ Carbitrarily. Then the sequence {xn}, generated iteratively by

ynPCxnλnAxn,

xn1αnfWnxnβnxnγnWnPCynλnAynn≥0,

3.47

converges strongly toxPΓfx∗, whereΓ ∩∞n1FTnV IA, C.

Proof. Setϕx 0 and Θx, y 0 for allx, yC and putr 1. TakeKx x2/2 and

ηy, x yxfor allx, yC. Then we havezn PCxn xn. Hence the conclusion follows.

This completes the proof.

Acknowledgments

(15)

References

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