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Lecture 23 - Frequency Response of Amplifiers (I) Common-Source Amplifier. December 1, 2005

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Lecture 23 - Frequency Response of Amplifiers (I) Common-Source Amplifier December 1, 2005 Contents: 1. Introduction

2. Intrinsic frequency response of MOSFET

3. Frequency response of common-source amplifier 4. Miller effect

Reading assignment:

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Key questions

• How does one assess the intrinsic frequency response of a transistor?

• What limits the frequency response of an amplifier? • What is the ”Miller effect”?

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1. Introduction

Frequency domain is a major consideration in most ana-log circuits.

Data rates, bandwidths, carrier frequencies all pushing up.

Motivation:

• Processor speeds ↑

• Traffic volume ↑ ⇒ data rates ↑

• More bandwidth available at higher frequencies in the spectrum MMDS 3G Skybridge LMDS Spacewav WE Datacom Frequency 0 0 4 20 25 40 50 60 2 8 20 40 45 100 155 500 Video WirelessMAN Teledesic 'V Band' DOM Radio BW (MHz)

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cuit current-gain cut-off frequency

2. Intrinsic frequency response of MOSFET

2 How does one assess the intrinsic frequency response of a transistor?

ft ≡ short-cirshort-circuit current-gain cut-off frequency-g [GHz] Consider MOSFET biased in saturation regime with small-signal source applied to gate:

VDD

iD=ID+iout iG=iin

vs VGG

vs at input ⇒ iout: transistor effect

⇒ iin due to gate capacitance

|i ioutin | ↓ Frequency dependence: f ↑⇒ iin ↑⇒ iout ft ≡ frequency at which | | = 1 iin

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Complete small-signal model in saturation: G S D + -vgs Cgs Cgd Cdb Csb gmvgs gmbvbs ro + vbs -iout vs + -iin B vbs=0 + + -vgs gmvgs iout iin vs Cgs Cgd 1 2 node 1: iin − vgsjωCgs − vgsjωCgd = 0 ⇒ iin = vgsjω(Cgs + Cgd) node 2: iout − gmvgs + vgsjωCgd = 0 ⇒ iout = vgs(gm − jωCgd)

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� Current gain: iout gm − jωCgd h21 = = iin jω(Cgs + Cgd) 2 Magnitude of h21: g2 + ω2C2 |h21| = ω(Cm gd gs + Cgd)

• For low frequency, ω  gm ,

Cgd

gm |h21| 

ω(Cgs + Cgd) • For high frequency, ω  gm

,

Cgd

|h21|  C Cgd < 1

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log |h21| log ω ωT 1 Cgd Cgs+Cgd -1

|h21| becomes unity at:

gm ωT = 2πfT = Cgs + Cgd Then: gm fT = 2π(Cgs + Cgd)

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2 Physical interpretation of fT: Consider: 1 2πfT = Cgs + Cgd gm  Cgs gm

Plug in device physics expressions for Cgs and gm: 1 2πfT  Cgs gm = 2 3LW Cox W L µCox(VGS − VT) = L µ32VGS−VT L or 1 2πfT  L µ < Echan > = L < vchan > = τt

τt ≡ transit time from source to drain [s] Then:

fT  1 2πτt

fT gives an idea of the intrinsic delay of the transistor: good first-order figure of merit for frequency response.

transit time

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To reduce τt and increase fT : • L ↓: trade-off is cost

• (VGS − VT ) ↑⇒ ID ↑: trade-off is power

• µ ↑: hard to do

• note: fT independent of W

Impact of bias point on fT :

gm W L µCoxID fT = = L µCox(VGS − VT ) = 2 W 2π(Cgs + Cgd) 2π(Cgs + Cgd) 2π(Cgs + Cgd) fT fT 0 0 VT VGS 0 I D

In typical MOSFET at typical bias points: fT ∼ 5 − 50 GH z

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3. Frequency response of common-source amp VDD vs VGG vOUT iSUP RS RL signal source + -signal load VSS

Small-signal equivalent circuit model (assuming current source has no parasitic capacitance):

+ + -vgs + -vout gmvgs vs Cgs Cgd RL roc ro RS Cdb ' Rout

Low-frequency voltage gain:

Av,LF = vout = −gm(ro//roc//RL) = −gmR out

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Cgd RS 1 2 + + -vgs + -vout gmvgs vs Cgs Cdb Rout ' node 1: vsR−vgs − vgsjωCgs − (vgs − vout)jωCgd = 0 S

node 2: (vgs−vout)jωCgd−gmvgs−voutjωCdb− vout = 0

R out Solve for vgs in 2: 1 jω(Cgd + Cdb) + R vgs = vout jωCgd − gm out

Plug in 1 and solve for vout/vs:

−(gm − jωCgd)R Av = out DEN with DEN = 1 + jω{RSCgs + RSCgd[1 + R 1 + gm)] + R out( outCdb} RS −ω2RSRout Cgs(Cgd + Cdb)

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Simplify:

gm

1. Operate at ω  ωT = C

gs+Cgd

gm  ω(Cgs + Cgd) > ωCgs, ωCgd 2. Assume gm high enough so that

1

+ gm  gm

RS

3. Eliminate ω2 term in denominator of Av

⇒ worst-case estimation of bandwidth Then:

R −gm

Av  out

1 + jω[RSCgs + RSCgd(1 + gmRout ) + Rout Cdb]

This has the form:

Av(ω) = A

1 + j ωω

H

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log |Av| gmRout' logω ωH -1 At ω = ωH: |Av(ωH)| = 1 2|Av,LF|

ωH gives idea of frequency beyond which |Av| starts rolling off quickly ⇒ bandwidth

For common-source amplifier:

ωH = 1

RSCgs + RSCgd(1 + gmRout ) + RoutCdb

Frequency response of common-source amplifier limited by Cgs and Cgd shorting out the input, and Cdb shorting out the output.

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Can rewrite as: 1 fH = 2π{RS [Cgs + Cgd(1 + |Av,LF |)] + R outCdb} Compare with: gm fT = 2π(Cgs + Cgd) 2 In general: fH  fT due to • typically: gm  R1 S

• Cdb enters fH but not fT

• presence of |Av,LF | in denominator

2 To improve bandwidth,

• Cgs, Cgd, Cdb ↓ ⇒ small transistor with low parasitics

• |Av,LF | ↓⇒ don’t want more gain than really needed

but...

why is it that effect of Cgd on fH appears to being

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4. Miller effect

In common-source amplifier, Cgd looks much bigger than

it really is.

Consider simple voltage-gain stage:

iin C + + -vin + -vout Avvin

What is the input impedance?

iin = (vin − vout)jωC But

vout = −Avvin

Then:

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ler ca acitance fundamen andwidth tradeoff or vin 1 Zin = = iin jω(1 + Av)C

From input, C, looks much bigger than it really is. This is called the Miller effect.

When a capacitor is located across nodes where there is voltage gain, its effect on bandwidth is amplified by the voltage gain ⇒ Mil Miller c pacitance: p :

CM iller = C(1 + Av)

Why?

vin ↑ ⇒ vout = −Avvin ↓↓ ⇒ (vin − vout) ↑↑ ⇒ iin ↑↑

In amplifier stages with voltage gain, it is critical to have small capacitance across voltage gain nodes.

As a result of the Miller effect, there is a tal gain-b in amplifiers.

fundamental

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Key conclusions

• fT (short-circuit current-gain cut-off frequency):

fig-ure of merit to assess intrinsic frequency response of transistors.

• In MOSFET, to first order, 1 ft =

2πτt

where τt is transit time of electrons through channel. • In common-source amplifier, voltage gain rolls off at high frequency because Cgs and Cgd short out input and Cdb shorts out output.

• In common-source amplifier, effect of Cgd on

band-width is magnified by amplifier voltage gain.

• Miller effect: effect of capacitance across voltage gain nodes is magnified by voltage gain

References

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