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Unit 8: Bonding

AP Chemistry, Kreipe

8.1: compare the characteristics of ionic compounds and covalent molecules.

8.2: use models to explain the role of valence

electrons in bond formation including resonance forms using formal charges.

8.3: describe the relationship between

electronegativity, bond type, and polarity of a molecule or compound.

(2)

Electronegativi

ty

(3)

Electronegativity

Electronegativity: The

ability of atoms in a molecule to attract electrons to itself.

On the periodic table,

electronegativity

increases as you go…

…from left to right

across a row.

…from the bottom to

the top of a column.

Based on Unit 7, why

(4)

Electronegativity

The “Pauling Scale”

graduates from 0.7 – 4.0 with 4.0 being the highest electronegativity (fluorine)

The difference in

electronegativity is the

technical way to calculate bonding type.

EN Dif Bond Type 0-0.5 Covalent

(5)

You try…

• Calculate the electronegativity difference and thus the type of bonding occurring between…

Chlorine and another Chlorine

Hydrogen and Bromine

(6)
(7)

Ionic Bonding

(8)

Ionic Bonding Basics

Donation of one or more electrons from

(typically) a metal to a non-metal forming a cation and anion.

These ions are then held together ONLY by

an electrostatic (+ and -) attraction.

There is a high electronegativity difference

between bonding elements.

Also explained by high electron affinity

(9)

Ionic Bonding, why?

• The ionization energy is such that it takes 495 kJ/mol to remove electrons from sodium.

• We get 349 kJ/mol back by giving electrons to chlorine.

• But these numbers don’t explain why the reaction of sodium metal and

chlorine gas to form sodium chloride is so exothermic! • http://www.pbslearningmedia.org/asset/n vhe_vid_compounds/? utm_source=teachersdomain_redirect/as set/nvhe_vid_compounds/utm_medium= teachersdomain/asset/nvhe_vid_compou nds/utm_campaign=td_redirects

(10)

Lattice Energy

This third piece of the

puzzle is the lattice energy:

The energy required to completely separate a mole of a solid ionic

compound into its gaseous ions.

The energy associated

with electrostatic

interactions is governed by Coulomb’s law:

Eel =  Q1Q2

(11)

Lattice Energy

Lattice energy, then, increases with the charge

of the ions.

It also increases with

decreasing size of ions.

Eel =  Q1Q2

(12)

• Figure 8.4: Stare at it…

• By accounting for all three energies

(ionization energy, electron affinity, and

lattice energy), we can get a good idea of the energetics involved in such a process.

Notice that without the

stability of the lattice energy provided by

electrostatic attraction of the ions, ionic

(13)

Energetics of Ionic Bonding

These phenomena also

helps explain the “octet rule.”

Metals, for instance, tend to stop

losing electrons once they attain a noble gas configuration

because energy would be expended that cannot be

(14)

Polar Covalent

Bonding

(15)

Polar Covalent Bonds

Although atoms often form

compounds by sharing

electrons, the electrons are not always shared equally. This is a Polar Covalent

Bond

Fluorine pulls harder on the electrons it shares with

hydrogen than hydrogen does.

Therefore, the fluorine end of the molecule has

(16)

Polar Covalent Bonds

When two atoms share

electrons unequally, a bond dipole results.

The dipole moment, ,

produced by two equal but opposite charges

separated by a distance,

r, is calculated by:

 = Qr

It is measured in debyes

(17)

Polar Covalent Bonds

The greater the difference in

(18)

Covalent

Bonding

Little Electronegativity Difference

(19)

Covalent Bonding Basics

Two non-metal elements share electrons to

complete their octet.

Both elements have high electron affinities

and can pull electron clouds away from each other simultaneously.

Both elements have high ionization energies

and will not release valence electrons.

Both elements have high electronegativities.Can share more than one pair of electrons in

(20)

Covalent Bonding

Forces must be balanced in a Covalent bond…

There are several

electrostatic interactions in these bonds:

Attractions between electrons

and nuclei

Repulsions between electronsRepulsions between nuclei

(21)

Lewis Structures

Lewis structures are representations of

molecules showing all VALENCE electrons, bonding and nonbonding.

Useful for quickly sketching covalent molecule

(22)

Writing Lewis Structures

1. Find the sum of valence

electrons of all atoms in the polyatomic ion or

molecule.

If it is an polyatomic

anion, add one electron for each negative

charge.

If it is a polyatomic

cation, subtract one electron for each

positive charge.

You try… 

PCl3

5 + 3(7) = 26CO2

4 + 2(6) = 16NH4+

(23)

Writing Lewis Structures

2. The central atom is the least

electronegative

element that isn’t hydrogen. Connect the outer atoms to it by single bonds.

(24)

Writing Lewis Structures

3. Fill the octets of the outer atoms.

(25)

Writing Lewis Structures

4. Fill the octet of the central atom.

(26)

Writing Lewis Structures

5. If you run out of

electrons before the central atom has an octet…

(27)

Now you try

• Draw the Lewis Dot Structure for:

H2ONF3CO2

(28)

Double/Triple Bonds

Many covalent molecules form double or

triple bonds to complete octets of elements.

This is why nitrogen and oxygen form

diatomic molecules spontaneously at STP.

This also explains molecules

(29)

Double and Triple Bonds

Double and triple bonds:

Increase the enthalpy of a bond. (require more

energy to break)

Increase stability of the bond.

Decrease the bonding radius (atoms are pulled

(30)

Formal Charges

Step 6?

Assign formal charges if molecule has double/triple bonds to determine the best possible resonance .

(31)

Writing Lewis Structures

The best possible Lewis

structure…

…is the one with the fewest

charges.

…and puts a negative charge

(32)

Formal Charges the Easy

way!

# valence electrons for element –

(33)

More Than Eight Electrons ?!?!

The only way PCl5 can exist is if

phosphorus has 10 electrons around it.

It is allowed to expand the

octet of atoms on the 3rd row or below.

Presumably d orbitals

in these atoms participate in bonding.

Presumably orbitals

are “hybridized” (we will discuss this

(34)

More Than Eight Electrons

Even though we can draw a Lewis structure for the phosphate ion that has only 8

(35)

More Than Eight Electrons

This eliminates the charge on the phosphorus

and the charge on one of the oxygens.

The lesson is: When the central atom is on

the 3rd row or below and breaking its octet

(36)

Now you try

• Determine the best possible structure for the following based on formal charges:

NO3

-• CO3

(37)

Resonance

(38)

Resonance Basics

Doube/triple bond electrons have the ability to

move between bonds in a molecule, this is called resonance.

If a molecule cannot achieve a stable octet for

its elements it can use resonance to spread one or more sets of electrons between

(39)

Resonance

This is the Lewis

structure we would draw for ozone, O3.

(40)

Resonance

• But this is at odds with the true, observed

structure of ozone, in which…

…both O—O bonds

are the same length.

…both outer

(41)

Resonance

One Lewis structure

cannot accurately

depict a molecule such as ozone since the

resonating electron pair is delocalized.

We use multiple

structures, resonance structures, to describe the molecule.

Or we use a more

accurate hybrid

(42)

• In truth, the electrons that form the second C—O bond in the double bonds below do not always sit between that C and that O, but rather can move among the two oxygens and the carbon.

• They are not localized, but rather are delocalized.

• You can think of the resonating electron pair as spending half it’s time on each bond so each bond has approximately 1.5 bonds

instead of a single bond or a true double bond.

• This still stabilizes the bonds, pulls the atoms closer, and

(43)

Now you try

• Write all the possible resonance structures for:

SO4

(44)

3-Covalent Bond Strength

Most simply, the strength of a bond is measured

by determining how much energy is required to break the bond.

• This is the bond enthalpy.

The bond enthalpy for a Cl—Cl bond,

(45)

Average Bond Enthalpies

This table lists the average bond

enthalpies for many different types of

bonds.

Average bond

enthalpies are

positive, because

(46)

Average Bond Enthalpies

NOTE: These are

average bond enthalpies, not absolute bond

enthalpies; the C—H bonds in methane, CH4, will be a bit

different than the C—H bond in

(47)

Enthalpies of Reaction

Yet another way to

estimate H for a reaction is to compare the bond

enthalpies of bonds broken to the bond

enthalpies of the new bonds formed.

In other words,

Hrxn = (bond enthalpies of bonds broken) 

(48)

Enthalpies of Reaction

CH4(g) + Cl2(g) 

CH3Cl(g) + HCl(g)

In this example, one C—H bond and one

(49)

Enthalpies of Reaction

So,

Hrxn = [D(C—H) + D(Cl—Cl)  [D(C—Cl) +

D(H—Cl)

= [(413 kJ) + (242 kJ)]  [(328 kJ) + (431 kJ)]

(50)

Now you try…

Use the table of bond energies to estimate the

enthalpy of the following reactions:

N2(g) + 3 H2(g) 2 NH3(g)

(51)
(52)

Metallic

Bonding

(53)

Metallic Bonding

Two or more elements that have low electronegativies.If both have low EN, then both elements don’t want

electrons!

Results in e- “hot potato” game, where elements pass e- around constantly in a “sea of e-”

• Basically, ALL the valence electrons are delocalized amongst ALL atoms in the metal lattice.

http://www.pbslearningmedia.org/asset/nvhe_vid_compounds/?

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