Unit 8: Bonding
AP Chemistry, Kreipe8.1: compare the characteristics of ionic compounds and covalent molecules.
8.2: use models to explain the role of valence
electrons in bond formation including resonance forms using formal charges.
8.3: describe the relationship between
electronegativity, bond type, and polarity of a molecule or compound.
Electronegativi
ty
Electronegativity
• Electronegativity: Theability of atoms in a molecule to attract electrons to itself.
• On the periodic table,
electronegativity
increases as you go…
• …from left to right
across a row.
• …from the bottom to
the top of a column.
• Based on Unit 7, why
Electronegativity
• The “Pauling Scale”
graduates from 0.7 – 4.0 with 4.0 being the highest electronegativity (fluorine)
• The difference in
electronegativity is the
technical way to calculate bonding type.
EN Dif Bond Type 0-0.5 Covalent
You try…
• Calculate the electronegativity difference and thus the type of bonding occurring between…
• Chlorine and another Chlorine
• Hydrogen and Bromine
Ionic Bonding
Ionic Bonding Basics
• Donation of one or more electrons from
(typically) a metal to a non-metal forming a cation and anion.
• These ions are then held together ONLY by
an electrostatic (+ and -) attraction.
• There is a high electronegativity difference
between bonding elements.
• Also explained by high electron affinity
Ionic Bonding, why?
• The ionization energy is such that it takes 495 kJ/mol to remove electrons from sodium.
• We get 349 kJ/mol back by giving electrons to chlorine.
• But these numbers don’t explain why the reaction of sodium metal and
chlorine gas to form sodium chloride is so exothermic! • http://www.pbslearningmedia.org/asset/n vhe_vid_compounds/? utm_source=teachersdomain_redirect/as set/nvhe_vid_compounds/utm_medium= teachersdomain/asset/nvhe_vid_compou nds/utm_campaign=td_redirects
Lattice Energy
• This third piece of the
puzzle is the lattice energy:
The energy required to completely separate a mole of a solid ionic
compound into its gaseous ions.
• The energy associated
with electrostatic
interactions is governed by Coulomb’s law:
Eel = Q1Q2
Lattice Energy
• Lattice energy, then, increases with the charge
of the ions.
• It also increases with
decreasing size of ions.
Eel = Q1Q2
• Figure 8.4: Stare at it…
• By accounting for all three energies
(ionization energy, electron affinity, and
lattice energy), we can get a good idea of the energetics involved in such a process.
• Notice that without the
stability of the lattice energy provided by
electrostatic attraction of the ions, ionic
Energetics of Ionic Bonding
• These phenomena also
helps explain the “octet rule.”
• Metals, for instance, tend to stop
losing electrons once they attain a noble gas configuration
because energy would be expended that cannot be
Polar Covalent
Bonding
Polar Covalent Bonds
• Although atoms often form
compounds by sharing
electrons, the electrons are not always shared equally. This is a Polar Covalent
Bond
• Fluorine pulls harder on the electrons it shares with
hydrogen than hydrogen does.
• Therefore, the fluorine end of the molecule has
Polar Covalent Bonds
• When two atoms share
electrons unequally, a bond dipole results.
• The dipole moment, ,
produced by two equal but opposite charges
separated by a distance,
r, is calculated by:
= Qr
• It is measured in debyes
Polar Covalent Bonds
The greater the difference in
Covalent
Bonding
Little Electronegativity Difference
Covalent Bonding Basics
• Two non-metal elements share electrons to
complete their octet.
• Both elements have high electron affinities
and can pull electron clouds away from each other simultaneously.
• Both elements have high ionization energies
and will not release valence electrons.
• Both elements have high electronegativities. • Can share more than one pair of electrons in
Covalent Bonding
Forces must be balanced in a Covalent bond…
• There are several
electrostatic interactions in these bonds:
• Attractions between electrons
and nuclei
• Repulsions between electrons • Repulsions between nuclei
Lewis Structures
• Lewis structures are representations of
molecules showing all VALENCE electrons, bonding and nonbonding.
• Useful for quickly sketching covalent molecule
Writing Lewis Structures
1. Find the sum of valenceelectrons of all atoms in the polyatomic ion or
molecule.
• If it is an polyatomic
anion, add one electron for each negative
charge.
• If it is a polyatomic
cation, subtract one electron for each
positive charge.
You try…
• PCl3
• 5 + 3(7) = 26 • CO2
• 4 + 2(6) = 16 • NH4+
Writing Lewis Structures
2. The central atom is the least
electronegative
element that isn’t hydrogen. Connect the outer atoms to it by single bonds.
Writing Lewis Structures
3. Fill the octets of the outer atoms.
Writing Lewis Structures
4. Fill the octet of the central atom.
Writing Lewis Structures
5. If you run out of
electrons before the central atom has an octet…
Now you try
• Draw the Lewis Dot Structure for:
• H2O • NF3 • CO2
Double/Triple Bonds
• Many covalent molecules form double or
triple bonds to complete octets of elements.
• This is why nitrogen and oxygen form
diatomic molecules spontaneously at STP.
• This also explains molecules
Double and Triple Bonds
Double and triple bonds:• Increase the enthalpy of a bond. (require more
energy to break)
• Increase stability of the bond.
• Decrease the bonding radius (atoms are pulled
Formal Charges
• Step 6?
Assign formal charges if molecule has double/triple bonds to determine the best possible resonance .
Writing Lewis Structures
• The best possible Lewis
structure…
• …is the one with the fewest
charges.
• …and puts a negative charge
Formal Charges the Easy
way!
•
# valence electrons for element –
More Than Eight Electrons ?!?!
• The only way PCl5 can exist is if
phosphorus has 10 electrons around it.
• It is allowed to expand the
octet of atoms on the 3rd row or below.
• Presumably d orbitals
in these atoms participate in bonding.
• Presumably orbitals
are “hybridized” (we will discuss this
More Than Eight Electrons
Even though we can draw a Lewis structure for the phosphate ion that has only 8
More Than Eight Electrons
• This eliminates the charge on the phosphorus
and the charge on one of the oxygens.
• The lesson is: When the central atom is on
the 3rd row or below and breaking its octet
Now you try
• Determine the best possible structure for the following based on formal charges:
• NO3
-• CO3
Resonance
Resonance Basics
• Doube/triple bond electrons have the ability to
move between bonds in a molecule, this is called resonance.
• If a molecule cannot achieve a stable octet for
its elements it can use resonance to spread one or more sets of electrons between
Resonance
This is the Lewis
structure we would draw for ozone, O3.
Resonance
• But this is at odds with the true, observed
structure of ozone, in which…
• …both O—O bonds
are the same length.
• …both outer
Resonance
• One Lewis structure
cannot accurately
depict a molecule such as ozone since the
resonating electron pair is delocalized.
• We use multiple
structures, resonance structures, to describe the molecule.
• Or we use a more
accurate hybrid
• In truth, the electrons that form the second C—O bond in the double bonds below do not always sit between that C and that O, but rather can move among the two oxygens and the carbon.
• They are not localized, but rather are delocalized.
• You can think of the resonating electron pair as spending half it’s time on each bond so each bond has approximately 1.5 bonds
instead of a single bond or a true double bond.
• This still stabilizes the bonds, pulls the atoms closer, and
Now you try
• Write all the possible resonance structures for:
• SO4
3-Covalent Bond Strength
• Most simply, the strength of a bond is measured
by determining how much energy is required to break the bond.
• This is the bond enthalpy.
• The bond enthalpy for a Cl—Cl bond,
Average Bond Enthalpies
• This table lists the average bond
enthalpies for many different types of
bonds.
• Average bond
enthalpies are
positive, because
Average Bond Enthalpies
NOTE: These are
average bond enthalpies, not absolute bond
enthalpies; the C—H bonds in methane, CH4, will be a bit
different than the C—H bond in
Enthalpies of Reaction
• Yet another way to
estimate H for a reaction is to compare the bond
enthalpies of bonds broken to the bond
enthalpies of the new bonds formed.
• In other words,
Hrxn = (bond enthalpies of bonds broken)
Enthalpies of Reaction
CH4(g) + Cl2(g)
CH3Cl(g) + HCl(g)
In this example, one C—H bond and one
Enthalpies of Reaction
So,
Hrxn = [D(C—H) + D(Cl—Cl) [D(C—Cl) +
D(H—Cl)
= [(413 kJ) + (242 kJ)] [(328 kJ) + (431 kJ)]
Now you try…
• Use the table of bond energies to estimate the
enthalpy of the following reactions:
• N2(g) + 3 H2(g) 2 NH3(g)
Metallic
Bonding
Metallic Bonding
• Two or more elements that have low electronegativies. • If both have low EN, then both elements don’t want
electrons!
• Results in e- “hot potato” game, where elements pass e- around constantly in a “sea of e-”
• Basically, ALL the valence electrons are delocalized amongst ALL atoms in the metal lattice.