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R E S E A R C H

Open Access

A modified Mann iteration for zero points of

accretive operators

Jianmin Song

*

and Minjiang Chen

*Correspondence:

[email protected]

Department of Mathematics and Sciences, Shijiazhuang University of Economics, Shijiazhuang, Hebei 050031, China

Abstract

A modified Mann iteration with computational errors is investigated. A strong convergence theorem for zero points of anm-accretive operator is established in a Banach space.

MSC: 47H06; 47H09; 47J25; 65J15

Keywords: accretive operator; fixed point; nonexpansive mapping; zero point

1 Introduction

In this paper, we are concerned with the problem of finding zero points of accretive oper-ators. Interest in accretive operators stems mainly from their firm connection with equa-tions of evolution, and this is an important class of nonlinear operators. It is known that many physically significant problems can be modelled by initial value problems of the form

x(t) +Ax(t) = , x() =x, (.)

whereAis an accretive operator in an appropriate Banach space. Typical examples where such evolution equations occur can be found in the heat, wave or Schrödinger equations. Ifx(t) is dependent oft, then (.) is reduced to

Au= , (.)

whose solutions correspond to the equilibrium points of (.). An early fundamental result in the theory of accretive operators, due to Browder [], states that the initial value prob-lem (.) is solvable ifAis locally Lipschitz and accretive onE. One of the most popular techniques for solving zero points of accretive operators goes back to the work of Browder []. One of the basic ideas in the case of a Hilbert spaceHis reducing the above equation (.) to a fixed point problem of the operatorRA:H→Hdefined byRA= (I+A)–, which

is called the classical resolvent ofA.

The paper is organized in the following way. In Section , we present the preliminaries that are needed in our work. In Section , a modified Mann iteration with computational errors is presented. A strong convergence theorem for zero points of anm-accretive op-erator is established in a Banach space. In Section , applications of the main results are discussed.

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2 Preliminaries

LetEbe a real Banach spaceEand letE∗be the dual space ofE. Let·,·denote the pairing betweenEandE∗. The normalized duality mappingJ:E→Eis defined by

J(x) =fE∗:x,f=x=f

for allxE. LetUE={xE:x= }.Eis said to be smooth or is said to have a Gâteaux differentiable norm if the limitlimt→x+tytx exists for eachx,yUE.Eis said to have

a uniformly Gâteaux differentiable norm if for eachyUE, the limit is attained uniformly for allxUE.E is said to be uniformly smooth or is said to have a uniformly Fréchet differentiable norm if the limit is attained uniformly forx,yUE. In the sequel, we use

jto denote the single-valued normalized duality mapping. It is known that if the norm ofEis uniformly Gâteaux differentiable, then the duality mappingJis single-valued and uniformly norm to weak∗continuous on each bounded subset ofE.

Recall that a closed convex subsetC of a Banach spaceE is said to have the normal structure if for each bounded closed convex subsetK ofCwhich contains at least two points, there exists an elementxofKwhich is not a diametral point ofK,i.e.,sup{xy:

yK}<d(K), whered(K) is the diameter ofK. It is well known that a closed convex subset of a uniformly convex Banach space has the normal structure and a compact convex subset of a Banach space has the normal structure; see [] for more details.

LetT:CCbe a mapping. Recall thatT is said to be contractive if there exits a con-stantα∈(, ) such that

TxTyαxy, ∀x,yC.

For such a case, we also callTanα-contraction.T is said to benonexpansiveif

TxTyxy, ∀x,yC.

LetDbe a nonempty subset ofC. LetQ:CD.Qis said to becontractionifQ=Q; sunny if for eachxCandt∈(, ), we haveQ(tx+ ( –t)Qx) =Qx; sunny nonexpansive retraction ifQis sunny, nonexpansive, and contraction.K is said to be a nonexpansive retract ofCif there exists a nonexpansive retraction fromContoD.

The following result, which was established in [], describes a characterization of sunny nonexpansive retractions on a smooth Banach space.

LetEbe a smooth Banach space andCbe a nonempty subset ofE. LetQ:ECbe a retraction andjbe the normalized duality mapping onE. Then the following are equiva-lent:

() Qis sunny and nonexpansive;

() QxQy≤ xy,j(QxQy),∀x,yE; () xQx,j(yQx) ≤,∀xE,yC.

Krasnoselski-Mann iteration generates a sequence{xn}in the following manner:

x∈C, xn+=αnTxn+ ( –αn)xn, ∀n≥. (.)

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and the references therein. In many disciplines, including economics, image recovery, quantum physics, and control theory, problems arise in infinite dimension spaces. In such problems, strong convergence (norm convergence) is often much more desirable than weak convergence, for it translates the physically tangible property that the energyxnx

of the error between the iteratexnand the solutionxeventually becomes arbitrarily small.

To improve the weak convergence of Krasnoselski-Mann iterative process, different mod-ified Mann iterations have been considered; see [–] and the references therein.

LetIdenote the identity operator onE. An operatorAE×Ewith domainD(A) ={zE:Az=∅}and rangeR(A) ={Az:zD(A)}is said to beaccretiveif for eachxiD(A) andyiAxi,i= , , there existsj(x–x)∈J(x–x) such thaty–y,j(x–x) ≥. An

accretive operatorAis said to bem-accretiveifR(I+rA) =Efor allr> . In a real Hilbert space, an operatorAism-accretive if and only ifAis maximal monotone. In this paper, we useA–() to denote the set of zeros ofA.

For an accretive operatorA, we can define a nonexpansive single-valued mappingJr:

R(I+rA)→D(A) byJr= (I+rA)–for eachr> , which is called theresolventofA.

One of classical methods of studying the problem ∈Ax, whereAE×Eis an accretive operator, is the following:

x∈E, xn+=Jrnxn, ∀n≥, (.)

whereJrn= (I+rnA)–and{rn}is a sequence of positive real numbers.

The following iteration also has been extensively investigated:

xn+=αnu+ ( –αn)Jrnxn, ∀n≥, (.)

where{αn}is a real number sequence in (, ),{rn}is a positive real number sequence,

andJrn= (I+rnA)–. It is known that the sequence{xn}generated in the above iteration

converges strongly to a zero point ofAin a Banach space under some restrictions imposed on{αn}and{rn}.

Chenet al.[] investigated the following iteration:

⎧ ⎨ ⎩

yn=βnxn+ ( –βn)Jrnxn,

xn+=αnf(xn) + ( –αn)yn, ∀n≥,

(.)

where {αn}and{βn}are real number sequences in (, ),{rn}is a positive real number

sequence, andJrn= (I+rnA)–. They proved that the sequence{xn}generated in the above

iteration converges strongly to a zero point ofAin a Banach space; for more details, see [] and the references therein.

We also remark that the viscosity approximation method was first introduced by Moudafi [] in the framework of Hilbert spaces. Moudafi proved that the desired so-lution is not only a fixed point of nonlinear mappings but a soso-lution to some variational inequality; for more details, see [] and the references therein.

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points of accretive operators. In this paper, a modified Mann iteration with computational errors is investigated. A strong convergence theorem for zero points of anm-accretive operator is established in a Banach space. The results mainly improve the corresponding results in Qin and Su [], Hao [], Qinet al.[] and Chenet al.[].

In order to state our main results, we also need the following lemmas.

Lemma .[] Let E be a real reflexive Banach space with the uniformly Gâteaux differ-entiable norm and the normal structure,and C be a nonempty closed convex subset of E.

Let S:CC be a nonexpansive mapping with a fixed point,and f :CC be a fixed contraction with the coefficientα∈(, ).Let{xt}be a sequence generated by the following xt=tf(xt) + ( –t)Sxt,where t∈(, ).Then{xt}converges strongly as t→to a fixed point xof T,which is the unique solution in F(T)to the following variational inequality

f x∗–x∗,j x∗–p≥, ∀pF(S).

Lemma .[] Let{xn}and{yn}be bounded sequences in a Banach space E,and{βn} be a sequence in (, )with <lim infn→∞βn≤lim supn→∞βn< .Suppose that xn+=

( –βn)yn+βnxn,∀n≥and lim sup

n→∞

yn+–ynxn+–xn

≤.

Thenlimn→∞ynxn= .

Lemma .[] Let{an},{bn},and{cn}be three nonnegative real sequences satisfying an+≤( –tn)an+bn+cn, ∀n≥,

where{tn}is a sequence in(, ).Assume that the following conditions are satisfied: (a) ∞n=tn=∞andbn=o(tn);

(b) ∞n=cn<∞.

Thenlimn→∞an= .

Lemma .[] Let E be a Banach space and let A be an m-accretive operator.Forλ> , μ> ,and xE,we have Jλx=(μλx+ ( –μλ)Jλx),where Jλ= (IA)–and Jμ= (IA)–.

3 Main results

Theorem . Let E be a real reflexive Banach space with the uniformly Gâteaux differen-tiable norm.Let A be an m-accretive operator in E such that C:=D(A)is convex and has the normal structure.Let f:CC be anα-contraction.Let{xn}be a sequence generated in the following manner:x∈C and

⎧ ⎨ ⎩

yn=βnxn+ ( –βn)Jrn(xn+en+),

xn+=αnf(xn) + ( –αn)yn, ∀n≥,

where{αn}and{βn}are real number sequences in(, ),{en}is a sequence in E,{rn}is a positive real number sequence,and Jrn= (I+rnA)–.Assume that A–()is not empty and

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(a) limn→∞αn= and

n=αn=∞;

(b)  <lim infn→∞βn≤lim supn→∞βn< ;

(c) ∞n=en<∞;

(d) rnrfor eachn≥andlimn→∞|rnrn+|= .

Then the sequence{xn}converges strongly tox¯,which is the unique solution to the following variational inequalityf(x¯) –x¯,j(px¯) ≤,∀pA–().

Proof First, we prove that{xn}is bounded. FixingpA–(), we see that

ynpβnxnp+ ( –βn)Jrn(xn+en+) –p

xnp+en+.

It follows that

xn+–pαnf(xn) –p+ ( –αn)ynp

≤  –αn( –α)

xnp+αnf(p) –p+en+

≤max

xnp,f(p) –p  –α

+en+

≤max

xn––p,

f(p) –p

 –α

+en+en+

.. .

≤max

x–p,

f(p) –p

 –α

+ ∞

i=

ei<∞.

This proves that the sequence{xn}is bounded. Ifrnrn+, we see from Lemma . that Jrn(xn+en+) –Jrn+(xn++en+)

rn

rn+

(xn+en+) +

 – rn

rn+

Jrn+(xn+en+) – (xn++en+)

= rn

rn+

(xn+en+) – (xn++en+)

+rn+–rn

rn+

Jrn+(xn+en+) – (xn++en+)

xnxn++en++en++ M

r (rnrn+), (.)

where M is an appropriate constant such that M ≥supn≥{Jrn+(xn+en+) – (xn++ en+)}. Putzn=xn+–ββnnxn; that is,

xn+= ( –βn)zn+βnxn, n≥. (.)

Note that

zn+–zn=

αn+f(xn+) + ( –αn+)yn+–βn+xn+

 –βn+

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= αn+  –βn+

f(xn+) –yn+

+Jrn+(xn++en+) –

αn

 –βn

f(xn) –yn

Jrn(xn+en+).

It follows that

zn+–zn

αn+

 –βn+

f(xn+) –yn++

αn

 –βn

f(xn) –yn

+Jrn+(xn++en+) –Jrn(xn+en+). (.)

Substituting (.) into (.), we arrive at

zn+–znxnxn+ ≤

αn+

 –βn+

f(xn+) –yn++

αn

 –βn

f(xn) –yn

+en++en++ M

r (rnrn+).

In view of restrictions (a), (b) and (c), we find that

lim sup

n→∞

zn+–znxnxn+

≤.

By virtue of Lemma ., one obtains that

lim

n→∞znxn= . (.)

It follows from (.) thatxn+–xn= ( –βn)(znxn). In view of restriction (c), we find from

(.) that

lim

n→∞xn+–xn= . (.)

Ifrnrn+, we can prove that (.) still holds. On the other hand, we have xnJrn(xn+en+)

xnxn++xn+–yn+ynJrn(xn+en+)

xnxn++αnf(xn) –yn+βnxnJrn(xn+en+).

It follows that

( –βn)xnJrn(xn+en+)≤ xnxn++αnf(xn) –yn.

In view of restriction (b), one finds that

lim

n→∞xnJrn(xn+en+)= . (.)

Notice that

xnJrnxnxnJrn(xn+en+)+Jrn(xn+en+) –Jrnxn

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Since∞n=en<∞, from (.) we obtain thatlimn→∞xnJrnxn= . Taking a fixed

numberksuch thatr>k> , we arrive at

JrnxnJkxn=

Jk

k rnxn+

 – k

rn

Jrnxn

Jkxn

≤ – k

rn

(Jrnxnxn)

Jrnxnxn. (.)

Since

xnJkxnxnJrnxn+JrnxnJkxn ≤xnJrnxn,

we therefore find that

lim

n→∞xnJkxn= . (.)

Now, we are in a position to prove thatlim supn→∞¯xf(x¯),j(xnx¯) ≤, wherex¯=

limtzt, andzt solves the fixed point equation

zt=tf(zt) + ( –t)Jkzt, ∀t∈(, ). Therefore, we see that

ztxn= ( –t)

Jkztxn,j(ztxn)

+tf(zt) –xn,j(ztxn)

= ( –t) JkztJkxn,j(ztxn)+Jkxnxn,j(ztxn)

+tf(zt) –zt,j(ztxn)+tztxn,j(ztxn)

≤( –t)ztxn+Jkxnxnztxn

+tf(zt) –zt,j(ztxn)+tztxn

ztxn+Jkxnxnztxn+tf(zt) –zt,j(ztxn), ∀t∈(, ).

This implies that

ztf(zt),j(ztxn)≤

tJkxnxnztxn, ∀t∈(, ).

It follows from (.) that

lim sup n→∞

ztf(zt),j(ztxn)≤. (.)

Sincezt→ ¯xast→ and from the fact thatjis strong to weak∗uniformly continuous on bounded subsets ofE, we find that

ztf(zt),j(ztxn)–f(x¯) –x¯,j(xnx¯)

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+f(x¯) –x¯,j(xnzt)–ztf(zt),j(ztxn)

f(x¯) –x¯,j(xnx¯) –j(xnzt)+f(x¯) –x¯+ztf(zt),J(xnzt)

f(x¯) –x¯j(xnx¯) –j(xnzt)+f(x¯) –x¯+ztf(zt)xnzt.

It follows that

lim t→

ztf(zt),j(ztxn)

f(x¯) –x¯,j(xnx¯)= .

For any> , there existsκ>  such that∀t∈(,κ) the following inequality holds

f(x¯) –x¯,j(xnx¯)

ztf(zt),j(ztxn)

+.

This implies that

lim sup n→∞

f(x¯) –x¯,j(xnx¯)≤lim sup n→∞

ztf(zt),j(ztxn)+.

Note that is arbitrary. In view of (.), we see thatlim supn→∞f(x¯) –x¯,j(xnx¯) ≤. This implies that

lim sup n→∞

f(x¯) –x¯,j(xn+–x¯)

≤. (.)

Finally, we show thatxn→ ¯xasn→ ∞. Notice that

xn+–x¯≤αn

f(xn) –x¯,j(xn+–x¯)

+ ( –αn)ynx¯xn+–x¯

αn

f(xn) –x¯,j(xn+–x¯)

+ –αn

ynx¯

+x n+–x¯

.

It follows that

xn+–x¯≤( –αn)xnx¯+ αn

f(xn) –x¯,j(xn+–x¯)

+dn,

where dn=en+(xnx¯+en+). In view of restrictions (a) and (c), we know that

n=dn<∞. Putan=xnx¯,tn=αn, andcn=dn. In view of Lemma ., we find the

desired conclusion.

Iff(x) =u, whereuis a fixed element inC, for anyxC, we find the following result. Corollary . Let E be a real reflexive Banach space with the uniformly Gâteaux differen-tiable norm.Let A be an m-accretive operator in E such that C:=D(A)is convex and has the normal structure.Let{xn}be a sequence generated in the following manner:x∈C and

⎧ ⎨ ⎩

yn=βnxn+ ( –βn)Jrnxn,

xn+=αnu+ ( –αn)yn, ∀n≥,

where{αn} and{βn} are real number sequences in(, ),{rn} is a positive real number sequence,and Jrn= (I+rnA)–. Assume that A–()is not empty and the above control

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(a) limn→∞αn= and

n=αn=∞;

(b)  <lim infn→∞βn≤lim supn→∞βn< ;

(c) rnrfor eachn≥andlimn→∞|rnrn+|= . Then the sequence{xn}converges strongly tox¯=QA–()u.

4 Applications

In this section, we consider solutions of variational inequalities. LetC be a nonempty, closed, and convex subset of a Banach spaceE. LetA:CE∗be a single-valued mono-tone operator which is hemicontinuous; that is, continuous along each line segment inC

with respect to the weak∗ topology ofE∗. Consider the following variational inequality problem of finding a pointxCsuch that

yx,Ax ≥, ∀yC.

In this section, we use VI(C,A) to denote the solution set of the variational inequality involvingA. The symbolNC(x) stands for the normal cone forCat a pointxC; that is,

NC(x) =x∗∈E∗:yx,x∗≤,∀yC.

Theorem . Let E be a real reflexive Banach space with the uniformly Gâteaux differ-entiable norm.Let C be a nonempty,closed,and convex subset of E.Let A:CEbe a single-valued,monotone,and hemicontinuous operator.Assume that VI(C,A)is not empty and C has the normal structure.Let f :CC be anα-contraction.Let{xn}be a sequence generated in the following manner:x∈C and

⎧ ⎨ ⎩

yn=βnxn+ ( –βn)VI(C,A+rn(Ixn)), xn+=αnf(xn) + ( –αn)yn, ∀n≥,

where{αn}and{βn}are real number sequences in(, ),{en}is a sequence in E,{rn}is a positive real number sequence,and Jrn= (I+rnA)–.Assume that A–()is not empty and

the above control sequences satisfy the following restrictions: (a) limn→∞αn= and

n=αn=∞;

(b)  <lim infn→∞βn≤lim supn→∞βn< ;

(c) rnrfor eachn≥andlimn→∞|rnrn+|= .

Then the sequence{xn}converges strongly tox¯,which is the unique solution to the following variational inequalityf(x¯) –x¯,j(px¯) ≤,∀pA–().

Proof Define a mappingTE×E∗by

Tx=

⎧ ⎨ ⎩

Ax+NCx, xC,

∅, x∈/C.

By Rockafellar [], we know thatTis maximal monotone, andT–() =VI(C,A). For each

rn>  andxnE, we see that there exists a uniquexrnD(T) such thatxnxr+rnT(xrn),

wherexrn= (I+rnT)–xn. Notice that

yn=VI

C,A+ 

rn(Ixn)

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which is equivalent to

yyn,Ayn+ 

rn(ynxn)

≥, ∀yC,

that is, –Ayn+rn(xnyn)∈NC(yn). This implies thatyn= (I+rnT)–xn. Following the proof

of Theorem ., we can immediately conclude the desired conclusion.

Iff(x) =u, whereuis a fixed element inC, for anyxC, we find the following result. Corollary . Let E be a real reflexive Banach space with the uniformly Gâteaux differ-entiable norm.Let C be a nonempty,closed,and convex subset of E.Let A:CEbe a single-valued,monotone,and hemicontinuous operator.Assume that VI(C,A)is not empty and C has the normal structure.Let{xn}be a sequence generated in the following manner:

x∈C and ⎧ ⎨ ⎩

yn=βnxn+ ( –βn)VI(C,A+rn(Ixn)), xn+=αnu+ ( –αn)yn, ∀n≥,

where{αn}and{βn}are real number sequences in(, ),{en}is a sequence in E,{rn}is a positive real number sequence,and Jrn= (I+rnA)–.Assume that A–()is not empty and

the above control sequences satisfy the following restrictions: (a) limn→∞αn= andn=αn=∞;

(b)  <lim infn→∞βn≤lim supn→∞βn< ;

(c) rnrfor eachn≥andlimn→∞|rnrn+|= . Then the sequence{xn}converges strongly tox¯=QA–()u.

Competing interests

The authors declare that they have no competing interests.

Authors’ contributions

All authors contributed equally to this manuscript. All authors read and approved the final manuscript.

Acknowledgements

This work is supported by the Department of Hebei Education (Z2013110). The authors are grateful to Professor Jin Wang and the anonymous reviewers for useful suggestions which improved the contents of the article.

Received: 1 October 2013 Accepted: 2 December 2013 Published:19 Dec 2013

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