R E S E A R C H
Open Access
On the
k
-step Jordan-Fibonacci
sequence
Omur Deveci
1, Sait Ta¸s
2and A Kılıçman
3**Correspondence:
3Department of Mathematics,
University Putra Malaysia, Serdang, Selangor 43400 UPM, Malaysia Full list of author information is available at the end of the article
Abstract
In this paper, we define the 2k-step Jordan-Fibonacci sequence, and then we study the 2k-step Jordan-Fibonacci sequence modulom. Also, we obtain the cyclic groups from the multiplicative orders of the generating matrix of the 2k-step
Jordan-Fibonacci sequence when read modulom, and we give the relationships among the orders of the cyclic groups obtained and the periods of the 2k-step Jordan-Fibonacci sequence modulom. Furthermore, we extend the 2k-step Jordan-Fibonacci sequence to groups, and then we examine this sequence in the finite groups. Finally, we obtain the period of the 2k-step Jordan-Fibonacci sequence in the generalized quaternion groupQ2nas applications of the results produced.
MSC: Primary 11B50; 20F05; secondary 11C20; 20D60
Keywords: Jordan-Fibonacci sequence; group; matrix; period
1 Introduction
Suppose that the (n+k)th term of a sequence is defined consecutively by a linear combi-nation of the precedingkterms:
an+k=can+can++· · ·+ck–an+k–,
wherec,c, . . . ,ck–are real constants. In [], Kalman derived a number of closed-form
formulas for the generalized sequence by the companion matrix method as follows. Let the matrixAbe defined by
A= [aij]k×k=
⎡ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎣
. . .
. . .
. ..
..
. ... ... ... ...
. . .
c c c ck– ck–
⎤ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎦
,
then
Thek-step Fibonacci sequence{Fk
n}is defined by initial valuesFk=· · ·=Fkk–= ,Fkk=
It is clear that the characteristic polynomial of thek-step Fibonacci sequence is as fol-lows:
Pk(x) =xk–xk––· · ·–x– .
A square matrix of the form
⎡
is called a Jordan block. The Jordan block of orderkis denoted byJk(λ). A Jordan matrix
is a block diagonal matrix whose blocks are all Jordan blocks.
Work on Fibonacci sequences in groups began with the previous study of Wall [] where the ordinary Fibonacci sequences in cyclic groups were investigated. Later, Wilcox [] ex-tended the problem to Abelian groups. Recently, many authors have studied some special linear recurrence sequences in algebraic structures; see, for example, [–]. In [, , –]. The authors obtained the cyclic groups via some special matrices.
In this paper, we obtain the (k)×(k) Jordan-type matrixJwith the aid of the character-istic polynomial of thek-step Fibonacci sequence, and then we define the k-step Jordan-Fibonacci sequence by using the Jordan-Jordan-Fibonacci matrixFk
J of order kwhich is produced
from the matrixJ. Then we study the k-step Jordan-Fibonacci sequence modulom, and we obtain the cyclic groups from the multiplicative orders of the Jordan-Fibonacci matrix
obtain the period of the k-step Jordan-Fibonacci sequence in the generalized quaternion groupQnas applications of the results produced.
2 Main results and proofs
We consider the (k)×(k) Jordan-type matrixJwhich is defined by using the characteristic polynomial of thek-step Fibonacci sequence:
⎡
Next, we define the k-step Jordan-Fibonacci sequence with the aid of the matrixFk J as
follows:
akn+k=akn+k–+akn+k–akn+k––· · ·–akn ()
forn≥, with initial conditionsak=· · ·=akk–= andakk= . By mathematical induction onα, we may write
and
Now we consider the k-step Jordan-Fibonacci sequence{ak
n}modulom. If we reduce
the sequence{ak
n}by a modulusm, then we get the repeating sequence, denoted by
akn(m)=ak(m),ak(m), . . . ,aki(m), . . .,
where we denoteak
i (modm) byaki(m). It has the same recurrence relation as in ().
A sequence is said to beperiodicif, after a certain point, it consists only of repetitions of a fixed subsequence. The number of elements in the shortest repeating subsequence is called the period of the sequence. In particular, if the firstnelements in the sequence form a repeating subsequence, then this sequence issimply periodicand its period isn.
Theorem . {ak
n(m)}forms a simply periodic sequence.
Proof LetX={(x,x, . . . ,xk)|xi’s be integers such that ≤xi≤m– }. Since there are
mkdistinct k-tuples of elements ofZ
m, at least one of the k-tuples appears twice in the
sequence{ak
n(m)}. Therefore, the subsequence following this k-tuple repeats; hence, the
sequence is periodic. Assume thatu>vand
aku+(m) =akv+(m),aku+(m) =akv+(m), . . . ,aku+k(m) =akv+k(m),
thenu≡v(modk). By (), we may write
akn= –akn+k+akn+k–+akn+k–akn+k––· · ·–akn+.
Then we obtain
aku(m) =akv(m),aku–(m) =akv–(m), . . . ,aku–v+(m) =ak(m).
Thus it is verified that the sequence is simply periodic.
The period of the sequence{ak
Given an integer matrixA= [aij],A(modm) means that all entries ofAare modulom,
that is,
A(modm) = aij(modm)
.
Let us consider the set
Am=
Ai(modm)|i≥.
Ifgcd(m,detA) = , thenAm is a cyclic group; ifgcd(m,detA)= , thenAmis a
semi-group. Let the notation|Am|denote the order of the setAm. SincedetFJk= ,|FJkm|
is a cyclic group for every positive integer m. From () and (), it is easy to see that
Pk(m) =|Fk Jm|.
Now we give some properties of the periodPk(m) by the following theorems.
Theorem . Let t be a prime and suppose that u is the largest positive integer with Pk(t) =
Pk(tu).Then
Pk tv=tv–u·Pk(t)
for every v≥u.In particular if Pk(t)=Pk(t),then Pk(tv) =tv–·Pk(t).
Proof SincePk(m) =|Fk
Jm|, we have a positive integernsuch that
FJkPk(tn+)≡I modtn+,
whereIis the (k)×(k) identity matrix. Then it is clear that
FJkPk(tn+)≡I modtn,
which implies thatPk(tn+) is divisible byPk(tn). Furthermore, if we denote
FJkPk(tn)=I+ fij(t)·tn,
then by the binomial expansion, we may write
FJkPk(tn)·t= I+ fij(t)·tnt
=
t
i=
t i f
(t)
ij ·tn
i≡
I modtn+.
This yields thatPk(tn+) dividesPk(tn)·t. Then it is clear that
Pk tn+=Pk tn
or
It is easy to see that the latter holds if and only if there isfij(t)which is not divisible byt. Sinceuis the largest positive integer such that
Pk(t) =Pk tu,
Pk tu=Pk tu+,
then there isfij(u+)which is not divisible byt. Therefore, we obtain
Pk tu+=Pk tu+, and so
Pk tn+=Pk tn+·t=Pk tn·t.
To complete the proof we may use an inductive method.
Theorem . If m has the prime factorization m=ui=tri
i, where(u≥), then Pk(m)
equals the least common multiple of Pk(tri i)s.
Proof SincePk(tri
i) is a period of the sequence{akn(t ri
i)}, it is easy to see that the sequence
{ak n(t
ri
i )}repeats only after blocks of lengthn·Pk(t ri
i), (n∈N). Since alsoPk(m) is a period
of the sequence{ak
n(m)}, the sequence{akn(t ri
i )}repeats after termsPk(m) for all valuesi.
Then we get thatPk(m) is the formn·Pk(pri
i) for all values ofi, and since any such number
gives a period ofPk(m), we conclude that
Pk(m) =lcmPk tr
, . . . ,Pk tru u
.
Now we extend the k-step Jordan-Fibonacci sequence tok-generator groups such that
k≥. LetGbe a finitek-generator group and suppose that
X=(x,x, . . . ,xk)∈G ×G× · · · × G k
|{x,x, . . . ,xk}
=G.
We call (x,x, . . . ,xk) a generatingk-tuple forG.
Definition . For ak-tuple (x,x, . . . ,xk)∈X, we define the Jordan-Fibonacci orbit
JO(G;x,x, . . . ,xk) =
bki
by
bk=x, . . . ,bkk=xk,bkk+= (x)–(x)–· · ·(xk)–,
bkk+=· · ·=bkk= (x)–(x)–· · ·(xk)–(xk+)
and
bkn+k= bkn–· · · bkn+k–– bkn+k bkn+k–
Theorem . If the group G is finite,then the Jordan-Fibonacci orbitJO(G;x,x, . . . ,xk)
is simply periodic.
Proof Letβbe order of the groupG, then it is clear that there areβkdistinct k-tuples of elements ofG. Thus it is verified that at least one of the k-tuples appears twice in the Jordan-Fibonacci orbitJO(G;x,x, . . . ,xk). Because of the repeating, the sequence is
pe-riodic. Since the Jordan-Fibonacci orbitJO(G;x,x, . . . ,xk) is periodic, there exist natural
numbersmandlwithl≡m(modk) such that
bkm+=bkl+,bkm+=bkl+, . . . ,bkm+k=bkl+k.
From the definition of the Jordan-Fibonacci orbitJO(G;x,x, . . . ,xk), we may write
bkn= bkn+–· · · bkn+k–– bkn+k bkn+k– bkn+k–.
Thus it is verified that
bkm=bkl,bkm–=bkl–, . . . ,bk=bkl–m+.
So the proof is complete.
The period of the Jordan-Fibonacci orbit JO(G;x,x, . . . ,xk) is denoted byPJO(G;x, x, . . . ,xk).
It is well known that the generalized quaternion groupQnis defined by presentation
x,y|xn–=e,y=xn–,y–xy=x–,
forn≥. We will now address the Jordan-Fibonacci orbit of the generalized quaternion groupQnfor generating pair (x,y).
Theorem . The period of the Jordan-Fibonacci orbitJO(Qn;x,y)is P()·n–= ·n–.
Proof We prove this by direct calculation. We first note that|x|= n–,|y|= andxy= yx–. Since
an()={, , , , , , , , , . . .},
it is clear thatP() = . From Definition ., it is easy to see that the Jordan-Fibonacci
orbitJO(Qn;x,y) is as follows:
bn+= bn– bn+– bn+ bn+
forn≥, with initial conditions
Then we have the sequence
x,y,xn––y,xn–,e,xn–+,yx,
yx,x–,x–n––,x–,yx–,xn–+,xn–+, . . . .
So, the Jordan-Fibonacci orbitJO(Qn;x,y) can be said to form layers of length . Using the above, the sequence becomes
b=x,b=y,b=xn––,b=xn–, . . . ,
b=x–,b=x–y,b =xn–+y,b=xn–+, . . . ,
bi+=x–i+,bi+=x–iy,bi+=xi+n––,bi+=xi+n–, . . . .
Hence, we need the smallesti∈Nsuch that i= n–α
and i= n–α. If we choose i= n–, we obtain
b·n–+=x,b·n–+=y,b·n–+=x n––
,b·n–+=x n–
.
Since the elements succeeding b
·n–+, b·n–+, b·n–+ andb·n–+ depend onx, y,
xn––andxn–for their values, the cycle begins again with the (·n–)nd element. Then
we get that
PJO(Qn;x,y) =P()·n–= ·n–.
Thus it is verified thatPA(Q:x,y) = .
Competing interests
The authors declare that they have no competing interests.
Authors’ contributions
The authors contributed equally and significantly in writing this paper. All authors read and approved the final manuscript.
Author details
1Department of Mathematics, Faculty of Science and Letters, Kafkas University, Kars, 36100, Turkey.2Department of
Actuarial Sciences, Faculty of Science, Atatürk University, Erzurum, 25240, Turkey.3Department of Mathematics,
University Putra Malaysia, Serdang, Selangor 43400 UPM, Malaysia.
Acknowledgements
The authors express their sincere thanks to the referee for his/her careful reading and suggestions that helped to improve this paper.
Publisher’s Note
Springer Nature remains neutral with regard to jurisdictional claims in published maps and institutional affiliations.
Received: 9 February 2017 Accepted: 11 April 2017
References
1. Kalman, D: Generalized Fibonacci numbers by matrix methods. Fibonacci Q.20(1), 73-76 (1982) 2. Wall, DD: Fibonacci series modulom. Am. Math. Mon.67(6), 525-532 (1960)
3. Wilcox, HJ: Fibonacci sequences of periodnin groups. Fibonacci Q.24(4), 356-361 (1986)
4. Aydin, H, Smith, GC: Finitep-quotients of some cyclically presented groups. J. Lond. Math. Soc.49(1), 83-92 (1994) 5. Campbell, CM, Doostie, H, Robertson, EF: Fibonacci length of generating pairs in groups. In: Bergum, GE,
6. Campbell, CM, Campbell, PP: The Fibonacci length of certain centro-polyhedral groups. J. Appl. Math. Comput., Int. J.
19(1), 231-240 (2005)
7. Deveci, O, Karaduman, E: The Pell sequences in finite groups. Util. Math.96, 263-276 (2015)
8. Doostie, H, Hashemi, M: Fibonacci lengths involving the Wall numberk(n). J. Appl. Math. Comput.20(1-2), 171-180 (2006)
9. Karaduman, E, Aydın, H: On the relationship between the recurrences in nilpotent groups and the binomial formula. Indian J. Pure Appl. Math.35(9), 1093-1103 (2004)
10. Knox, SW: Fibonacci sequences in finite groups. Fibonacci Q.30(2), 116-120 (1992) 11. Lü, K, Wang, J:k-Step Fibonacci sequence modulom. Util. Math.71, 169-177 (2006)
12. Ozkan, E, Aydin, H, Dikici, R: 3-step Fibonacci series modulom. Appl. Math. Comput.143(1), 165-172 (2003) 13. Tas, S, Deveci, O, Karaduman, E: The Fibonacci-Padovan sequences in finite groups. Maejo Int. J. Sci. Technol.8(3),
279-287 (2014)
14. Tas, S, Karaduman, E: The Padovan sequences in finite groups. Chiang Mai J. Sci.41(2), 456-462 (2014) 15. Deveci, O, Karaduman, E: The cyclic groups via the Pascal matrices and the generalized Pascal matrices. Linear