Adv. Inequal. Appl. 2019, 2019:7 https://doi.org/10.28919/aia/3998 ISSN: 2050-7461
GENERALIZATION OF WEIGHTED OSTROWSKI INEQUALITY WITH APPLICATIONS IN NUMERICAL INTEGRATION
NAZIA IRSHAD, ASIF R. KHAN, MUHAMMAD AWAIS SHAIKH∗
Department of Mathematics, University of Karachi, Karachi-75270, Pakistan
Copyright c2019 the authors. This is an open access article distributed under the Creative Commons Attribution License, which permits
unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
Abstract. An integral inequality of Ostrowski type with weights is established for differentiable functions up to second order, whose second derivatives are bounded and first derivatives are absolutely continuous. The inequality of weighted integral is then functional to weighted composite quadrature rules.
Keywords:weighted Ostrowski’s inequality; numerical integration. 2010 AMS Subject Classification:65D30.
1. Introduction
It is a known that Ostrowski type inequalities can be used to estimate the absolute deviation
from its integral mean. These inequalities can be used to provide explicit error bounds for
nu-merical quadrature formulae. The weighted version of Ostrowski inequality was first presented
in 1983 by J. E. Peˇcari´c and B. Savi´c [10]. Keeping in view the importance of this inequality, for
last few decades, the researchers are in continuous effort to obtain sharp bounds of Ostrowski’s
∗Corresponding author
E-mail address: [email protected] Received January 15, 2019
inequality in terms of weight.
We have introduced a weighted inequality which has its applications in Numerical quadrature
rules and Probability theory. The probability density function, defined by us, has produced the
results of Ostrowski’s inequality in a more organized way.
In 1938, a Ukrainian Mathematician Alexandar Markowich Ostrowski discovered an inequality
called Ostrowski inequality, which states that.
Lemma 1.1. [15] Let ϕ: I⊆R→Rbe a differentiable function on I0(I0is the interior of I)
and leta0,b1∈I0witha0<b1. Ifϕ0:(a0,b1)→Ris bounded on(a0,b1), i.e.,
||ϕ0||∞= sup
t∈(a0,b1)
|ϕ0(t)|<∞,
Then the inequality is
ϕ(v)− 1
b1−a0
Z b1
a0
ϕ(t)dt
≤ "
1
4+
(v−a0+b1
2 ) 2
(b1−a0)2 #
(b1−a0)||ϕ0||∞
for allv∈[a0,b1].The number 14 is sharp which cannot be replaced by a smaller one.
G. V. Milovanovi´c and J. E. Pe˘cari´c proved a generalised Ostrowski’s inequality in 1976 forn
-times differentiable functions [9]. In which he pointed out the speciality of twice differentiable
functions [8, p. 470].
Lemma 1.2. [15] Letϕ: I ⊆R→Rbe a differentiable function on I0(I0 is the interior of I) and leta0,b1∈I0witha0<b1. Ifϕ0:(a0,b1)→Ris bounded on(a0,b1), i.e.,
||ϕ0||∞= sup
t∈(a0,b1)
|ϕ0(t)|<∞,
Then the inequality is
ϕ(v)− 1
b1−a0
Z b1
a0
ϕ(t)dt
≤ "
1
4+
(v−a0+b1
2 )2
(b1−a0)2 #
(b1−a0)||ϕ0||∞
for allv∈[a0,b1].The number 14 is sharp which cannot be replaced by a smaller one.
Ris bounded on(a0,b1). Then the following inequality holds for all v∈[a0,b1].
1 2
ϕ(v) +(v−a0)ϕ(a0) + (b1−v)ϕ(b1)
b1−a0
− 1 b1−a0
Z b1
a0
ϕ(t)dt
≤ kϕ 00k
∞
4 (b1−a0)
2 "
1
12+
(v−a0+b1
2 ) 2
(b1−a0)2 #
In 1999, the following inequality is proved by Cerone et.al. in [1].
Lemma 1.4. [15]Let the following assumption(1.2)be valid for all v∈[a0,b1]
ϕ(v)−
v−a0+b1
2
ϕ0(v)− 1
b1−a0
Z b
a0
1ϕ(t)dt
≤ "
(b1−a0)2
24 +
1 2
v−a0+b1
2
2#
kϕ00||∞≤
(b1−a0)2
6 kϕ
00||
∞
In the same year, the following result is stated by Dragomir and Barnett in [2].
Lemma 1.5. [15]Let the following assumption(1.2)be valid for all v∈[a0,b1]
ϕ(v)−ϕ(b1)−ϕ(a0)
b1−a0
v−a0+b1
2
− 1 b1−a0
Z b
a0
1ϕ(t)dt
≤ (b1−a0) 2
2
v−a0+b1
2 b1−a0
!2
+1
4
2
+ 1
12
kϕ00||∞≤
(b1−a0)2
6 kϕ
00||
∞.
An Ostrowski type integral inequality for functions whose second derivatives are bounded
is established by P. Cerone, S. S. Dragomir and J. Roumeliotis in [1]. S. S. Dragomir and N.
S. Barnett in [2] have also established a similar inequality. in [4], an Ostrowski type integral
inequality is similar in sense as that of [1] or [2] pointed out by S. S. Dragomir and A. Sofo.
The following integral inequality in [4] is proved by S. S. Dragomir and A. Sofo.
Lemma 1.6. [15]Let the functionϕ :[a0,b1]→ Ris considered having first derivative is ab-solutely continuous on [a0,b1] and the second derivative ϕ00 ∈ L∞ [a0,b1]. Then we get the
following inequality for all v∈[a0,b1]
Z b1
a0
ϕ(t)−(b1−a0) 2
ϕ(v) +ϕ(a0) +ϕ(b1) 2
+b1−a0
2
v−a0+b1
2
ϕ0(v)
≤ kϕ00k∞ 1 3
v−a0+b1
2
3
+(b1−a0)
3
48
!
In present paper, we give weighted version of Ostrowski-type inequality (1) using different
kernel and will also state its application in Numerical quadrature rules, probability theory and
special means. This paper is arranged in the following approach. The first part is based on
preliminaries whereas in second part we are using weights in inequality (1) from which we get
main result, which is in fact probability density functions. In the last part we would state about
the application in terms of composite quadrature rules.
3. Main results
We use here a weighted form of integral inequality which is proved by S. S. Dragomir and
A. Sofo in [4], and also we are using it in numerical integration.
Theorem 3.1.
Z b1
a0
ϕ(t)w(t)dt−1 2
ϕ(v) +b1−a0
2 [ϕ(a0)w(a0) +ϕ(b1)w(b1)]
−
Z b1
a0
ϕ(t)
t− a0+b1
2
w0(t)dt −
Z b1
a0
w(t)
v−a0+b1
2
ϕ0(v)dt
≤ ϕ00
∞
Z b1
a0
w(u)du v2
4 −
a0+b1
4 v
+
Z b1
a0
a 0+b1
4 t−
t2
4
w(t)dt
(2)
where w:[a0,b1]→[0,∞)is a PDF.
Proof.Let us begin with the following integral identity [8] (see also [6]).
ψ(v) =
Z b1
a0
w(t)ψ(t)dt+
Z b1
a0
Pw(v,t)ψ0(t)dt (3)
for all v∈[a0,b1], given that f is absolutely continuous on [a0,b1] and the weighted kernel
Pw:[a0,b1]×[a0,b1]→Ris given by:
Pw(v,t) =
Z t
a0
w(u)du, if t∈[a0,v],
Z t
a0+b1
2
w(u)du, if t∈(v,a0+b1−v],
Z t
b1
wheret∈[a0,b1]. Let us consider,ψ(v) =
v−a0+b1
2
ϕ0(v). Then(3)implies
v−a0+b1
2
ϕ0(v) =
Z b1
a0
w(t)
t−a0+b1
2
ϕ0(t)dt+
Z b1
a0
Pw(v,t)
ϕ0(t)
+
t−a0+b1
2
ϕ00(t)dt.
(4)
Using integration by parts, we get
Z b1
a0
t−a0+b1
2
w(t)ϕ0(t)dt = b1−a0
2 [ϕ(a0)w(a0) +ϕ(b1)w(b1)]
−
Z b1
a0
ϕ(t)w(t)dt−
Z b1
a0
ϕ(t)
t−a0+b1
2
w0(t)dt,
(5)
also
Z b1
a0
Pw(v,t)ϕ0(t)dt=ϕ(v)−
Z b1
a0
ϕ(t)w(t)dt. (6)
Now using equations(5)and(6)in(4), we get
v−a0+b1
2
ϕ0(v) =b1−a0
2 [ϕ(a0)w(a0) +ϕ(b1)w(b1)]
+ϕ(v)−2
Z b1
a0
ϕ(t)w(t)dt−
Z b1
a0
ϕ(t)
t−a0+b1
2
w0(t)dt
+
Z b1
a0
Pw(v,t)
t−a0+b1
2
ϕ00(t)dt.
or
Z b1
a0
ϕ(t)w(t)dt =b1−a0
4 [ϕ(a0)w(a0) +ϕ(b1)w(b1)] + 1 2ϕ(v)
−1
2
v−a0+b1
2
ϕ0(v)−1 2
Z b1
a0
ϕ(t)
t−a0+b1
2
w0(t)dt
+1
2
Z b1
a0
Pw(v,t)
t−a0+b1
2
for allv∈[a0,b1], which gives us
Z b1
a0
ϕ(t)w(t)dt−1 2
ϕ(v) +b1−a0
2 [ϕ(a0)w(a0) +ϕ(b1)w(b1)]
−
Z b1
a0
ϕ(t)
t−a0+b1
2
w0(t)dt−
v−a0+b1
2
ϕ0(v)
= 1 2
Z b1
a0
Pw(v,t)
t−a0+b1
2
ϕ00(t)dt
≤ 1 2
Z b1
a0
|Pw(v,t)|
t−a0+b1
2 ϕ00(t)
dt
Then we have
Z b1
a0
|Pw(v,t)|
t−a0+b1
2 ϕ00(t)
dt
≤ kϕ00k∞
Z b1
a0
|Pw(v,t)|
t−a0+b1
2 dt, (7) Also I =
Z b1
a0
|Pw(v,t)|
t−a0+b1
2 dt or I= Z v a0 Z t a0
w(u)du
t−a0+b1
2 dt+
Z a0+b1−v
v Z t
a0+b1
2
w(u)du ×
t−a0+b1
2 dt+
Z b1
a0+b1−v
Z t b1
w(u)du
t−a0+b1
2 dt. (8)
Now, we have a case:
forv∈ha0,a0+b1
2 i
, we find
I=
Z v
a0
Z t
a0
w(u)du a0+b1
2 −t
dt+
Z a0
+b1
2
v
Z b1
t
w(u)du
×
a0+b1
2 −t
dt+
Z b1
a0+b1
2
Z b1
t
w(u)du t−a0+b1
2
After solving the equations,we find
I=
Z v
a0
w(u)du
v2
2 −
a0+b1
2 v − Z v a0 t2 2 −
a0+b1
2 t
w(t)dt
+
Z a0+2b1
v
w(u)du
v2
2 −
a0+b1
2 v
+
Z a0+2b1
v
a0+b1
2 t−
t2
2
w(t)dt
−
Z a0+b1−v
a0+b1
2
w(u)du a
0+b1
2 v−
v2
2
+
Z a0+b1−v
a0+b1
2
a 0+b1
2 −
t2
2
w(t)dt
−
Z b1
a0+b1−v
w(u)du
a0+b1
2 v−
v2
2
+
Z b1
a0+b1−v
a0+b1
2 t−
t2
2
w(t)dt
=
Z v
a0
w(u)du
v2
2 −
a0+b1
2 v + Z v a0
a0+b1
2 t−
t2
2
w(t)dt
+
Z a0+b1
2
v
w(u)du
v2
2 −
a0+b1
2 v
+
Z a0+b1
2
v
a0+b1
2 t−
t2
2
w(t)dt
+
Z a0+b1−v
a0+b1
2
w(u)du
v2
2 −
a0+b1
2 v
+
Z a0+b1−v
a0+b1
2
a0+b1
2 −
t2
2
w(t)dt
+
Z b1
a0+b1−v
w(u)du
v2
2 −
a0+b1
2 v
+
Z b1
a0+b1−v
a0+b1
2 t−
t2
2
w(t)dt
(9)
and finally
I=
Z b1
a0
w(u)du
v2
2 −
a0+b1
2 v
+
Z b1
a0
a0+b1
2 t−
t2
2
w(t)dt
(10)
Using equations (7), (8), and (9),we find
Z b1
a0
ϕ(t)w(t)dt−1
2
ϕ(v) +b1−a0
2 [ϕ(a0)w(a0) +ϕ(b1)w(b1)]
−
Z b1
a0
ϕ(t)
t−a0+b1
2
w0(t)dt−
v−a0+b1
2
ϕ0(v)
≤ kϕ 00k
∞ 2
Z b1
a0
w(u)du
v2
2 −
a0+b1
2 v
+
Z b1
a0
a0+b1
2 t−
t2
2
w(t)dt
= ϕ00
∞
Z b1
a0
w(u)du
v2
4 −
a0+b1
4 v
+
Z b1
a0
a0+b1
4 t−
t2
4
w(t)dt
which is our required result.
remarks 3.2.If we put w(t)≡ 1
b1−a0 in (2), then we will get
Z b1
a0
ϕ(t)−(b1−a0) 2
ϕ(v) +ϕ(a0) +ϕ(b1) 2
+b1−a0
2
v−a0+b1
2
ϕ0(v)
≤ kϕ00k∞
(b1−a0)
4
x−a0+b1
2
2
+(a0−b1)
3
48 (11)
.
remarks 3.3.If we put the midpoint v= a0+b1
2 in (2), then we will get
Z b1
a0
ϕ(t)w(t)dt−1 2
ϕ
a0+b1
2
+b1−a0
2 (ϕ(a0)w(a0) +ϕ(b1)w(b1))
−
Z b1
a0
ϕ(t)
t−a0+b1
2
w0(t)dt
≤ ϕ00
∞
Z b1
a0
a0+b1
4 t−
t2
4
w(t)dt −
Z b1
a0
w(u)du
a0+b1
4
2
(12)
.
remarks 3.4.If we put w(t)≡ b 1
1−a0 in (12), then we will get
Z b1
a0
ϕ(t)dt−(b1−a0) 2
ϕ
a0+b1
2
+b1−a0
2 (ϕ(a0)w(a0) +ϕ(b1)w(b1))
−(b1−a0)
Z b1
a0
ϕ(t)
t−a0+b1
2
w0(t)dt ≤ ϕ00 ∞
Z b1
a0
a0+b1
4 t−
t2
4
dt −
Z b1
a0
du
a0+b1
4
2
(13)
.
remarks 3.5.If we examine an approximation for the end point v=a0in (2), then we will get
Z b1
a0
ϕ(t)w(t)dt−1
2[ϕ(a0) +
b1−a0
2 (ϕ(a0)w(a0) +ϕ(b1)w(b1))
−
Z b1
a0
ϕ(t)
t−a0+b1
2
w0(t)dt + (b1−a0)
Z b1
a0
w(t)ϕ0(a0)dt]|
≤ ϕ00
∞
Z b1
a0
a 0+b1
4 t−
t2
4
w(t)dt −
Z b1
a0
w(u)du a
0b1
4
remarks 3.6.If we examine an approximation for the end point v=b1in (2), we will get
Z b1
a0
ϕ(t)w(t)dt−1 2
ϕ(b1) +
b1−a0
2 (ϕ(a0)w(a0) +ϕ(b1)w(b1))
−
Z b1
a0
ϕ(t)
t−a0+b1
2
w0(t)dt −
Z b1
a0
w(t)(b1−a0)ϕ0(b1)dt
≤ ϕ00
∞
Z b1
a0
a0+b1
4 t −
t2
4
w(t)dt−
Z b1
a0
w(u)du
a0b1
4
.
3.Application in Numerical Integration
Theorem 3.1. Let In:a0=v0<v1< . . . <vn−1<vn=b1 be a partition of interval [a0,b1], ∆ζ =vi+1−vi,, a0i≤ξi≤b1i, where a0i=vi, b1i=vi+1, i=0, . . . ,n−1then
Z vi+1
vi
ϕ(t)w(t)dt =S(ϕ,ϕ0,In,v,w) +R(ϕ,ϕ0,In,v,w)
where
|S(ϕ,ϕ0,In,v,w)|
= 1
2
n−1
∑
i=0
ϕ(ξi) +
∆ζ
2 [ϕ(vi)w(vi) +ϕ(vi+1)w(vi+1)]
−
Z vi+1
vi
ξ−
vi+vi+1
2
ϕ0(ξi)dt
−
Z vi+1
vi
ϕ(t)
t−vi+vi+1
2
w0(t)dt
∆ζ
and
R(ϕ,ϕ0,In,v,w) ≤
ϕ00
∞
n−1
∑
i=0
Z vi+1
vi
(vi+vi+1)t
4 −
t2
4
w(t)dt
+
Z vi+1
vi
ξ2
4 −
(vi+vi+1)ξ 4
.
(14)
.
Proof. Applying inequality (2) on ξi ∈[xi,xi+1] and summing over i from to n−1 and using
remarks 3.6.If we put w(t)≡ 1
b1−a0 in (2) then we will get
|S(ϕ,ϕ0,In,v,w)|=
(15)
(vi+1−vi)
2
n−1
∑
i=0
ϕ(v) +ϕ(vi) +ϕ(vi+1)
2 +
vi+1−vi
2
v−vi+vi+1
2
ϕ0(v)
and
R(ϕ,ϕ0,In,v,w) ≤
ϕ00
∞
(vi+1−vi)
4
n−1
∑
i=0
ξi−
vi+vi+1
2
2
+(vi−vi+1)
3
48 (16)
.
for allξi∈[vi,vi+1]
remarks 3.7.forξi= vi+2vi+1(i=0,· · ·n−1),in (2) then the following quadrature rule is:
S(ϕ,ϕ0,In,v,w) =
1 2
n−1
∑
i=0
ϕ(ξi) +
∆ζ
2 [ϕ(vi)w(vi) +ϕ(vi+1)w(vi+1)]
−
Z vi+1
vi
ϕ(t)
t−vi+vi+1
2
w0(t)dt
∆ζ (17)
and
R(ϕ,ϕ0,In,v,w) ≤
ϕ00
∞
Z vi+1
vi
w(t)dt
(vi+vi+1)t
2 −
t2
2
+
Z vi+1
vi
vi+vi+1
4
2
(18)
.
remarks 3.8.If we put w(t)≡ 1
vi+1−vi in (12) then we will get
|S(ϕ,ϕ0,In,v,w)|= (vi+1−vi)
2
n−1
∑
i=0
ϕ
vi+vi+1
2
+b1−vi
2 (ϕ(vi)w(vi) +ϕ(vi+1)w(vi+1))
−(vi+1−vi)
Z vi+1
vi
ϕ(t)
t−vi+vi+1
2
w0(t)dt
and
R(ϕ,ϕ0,In,v,w)
≤ϕ00
∞
n−1
∑
i=0Z vi+1
vi
vi+vi+1
4 t−
t2
4
dt −
Z vi+1
vi
du
vi+vi+1
4
2
(20)
.
remarks 3.9.If we examine an approximation for the end point v=viin (2), we will get
|S(ϕ,ϕ0,In,v,w)|=
1 2
n−1
∑
i=0
ϕ(vi) +
vi+1−vi
2 (ϕ(vi)w(vi) +ϕ(vi+1)w(vi+1))
−
Z vi+1
vi
ϕ(t)
t−vi+vi+1
2
w0(t)dt+ (vi+1−vi)
Z vi+1
vi
w(t)ϕ0(vi)dt
(21)
and
R(ϕ,ϕ0,In,v,w) ≤
n−1
∑
i=0ϕ00
∞
Z vi+1
vi
vi+vi+1
4 t−
t2
4
w(t)dt −
Z vi+1
vi
w(u)du viv
i+1
4
.
remarks 3.10.If we examine an approximation for the end point v=b1in (2), we will get:
|S(ϕ,ϕ0,In,v,w)|=
1 2
n−1
∑
i=0
ϕ(vi+1) +
vi+1−vi
2 (ϕ(vi)w(vi) +ϕ(vi+1)w(vi+1))
−
Z vi+1
vi
ϕ(t)
t−vi+vi+1
2
w0(t)dt−
Z vi+1
vi
w(t)(vi+1−vi)ϕ0(vi+1)dt
(22)
and
R(ϕ,ϕ0,In,v,w) ≤
ϕ00
∞
n−1
∑
i=0Z b1
vi
vi+vi+1
4 t −
t2
4
w(t)dt−
Z vi+1
vi
w(u)duvivi+1
4
.
4.Application for Probability Density Function
Let X be a continuous random variable having the probability density function
Ψ:[a0,b1]→R+ and the cumulative distribution function
Ψ:[a0,b1]→[0,1],i.e,
Ψ(ξ) =
Z ξ
a0
ψ(t)dt, ξ ∈[α,β]⊂[a0,b1],
is the expectation of the random variable X on the interval [a0;b1] and weighted expectation
would be
Ew(X) =
Z b1
a0
tψ(t)w(t)dt,
t−ξ+b1−a0
2 ≤ξ ≤t−ξ−
b1−a0
2
is the expected of the random variable X on the interval [a0,b1]. so, we get the following theorem.
Theorem 4.Let the suppositions of Theorem2.1be valid if probability density function belongs to L2[a0,b1]space, then we get the following inequality
b1w(b1)−Ew(X)−
Z b1
a0
tΨ(t)w0(t)dt
−1
2
Ψ(v) +b1−a0
2 [Ψ(a0)w(a0) ]Ψ(b1)w(b1)−
Z b1
a0
Ψ(t)
t− a0+b1
2
×w0(t)dt−
Z b1
a0
w(t)
v−a0+b1
2
Ψ0(v)dt
≤ Ψ00
∞
v2
4 −
a0+b1
4 v
+
Z b1
a0
a0+b1
4 t−
t2
4
w(t)dt
(24)
Proof. Putψ =Ψin(2)we get(24), by using this identities
Z b1
a0
Ψ(t)w(t)dt =b1w(b1)−Ew(X)−
Z b1
a0
tΨ(t)w0(t)dt
wherew:[a0,b1]→[0,∞)is a probability density function
Proof. Putψ =Ψin(2)we get(24), by using this identities
Z b1
a0
Ψ(t)w(t)dt =b1w(b1)−Ew(X)−
Z b1
a0
tΨ(t)w0(t)dt
wherew:[a0,b1]→[0,∞)is a probability density function.
Conclusion
Weighted Peano Kernels are used for Ostrowski type inequalities, depending on the second
derivatives, are stated in this paper. In the research paper [5] and [11], Weighted Ostrowski
type inequalities for the second derivative of the functions are addressed.A generalization and
extension of the inequalities is presented in [5] and[11]. we have presented a generalization
(2)of the inequality(1)found in[5]for twice differentiable function whose first derivatives are
absolutely continuous and 2nd derivative belong toL∞−(a0,b1)by presenting a parameterλ ∈ [0,1]. This generalization also results in finding a inequality for a specific value ofλ as stated
in remarks . The inequality thus found has a better bound than the inequalities presented in[5]
and [11]. Remarks also shows that the perturbed trapezoid inequality that can be found from
(2)is better than the perturbed inequalities presented in[5]and[11]of perturbed trapezoid type.
The inequality is then functional for a partition of the interval[a0,b1] to find some composite quadrature rules and also functional to special means.
Conflict of Interests
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