http://www.scirp.org/journal/am ISSN Online: 2152-7393 ISSN Print: 2152-7385
DOI: 10.4236/am.2018.94028 Apr. 27, 2018 369 Applied Mathematics
Generated Sets of the Complete Semigroup
Binary Relations Defined by Semilattices of the
Class
Σ
8
(
X n
,
+ +
k
1
)
Yasha Diasamidze, Omari Givradze, Nino Tsinaridze, Giuli Tavdgiridze
Faculty of Mathematics, Physics and Computer Sciences, Shota Rustaveli State University, Batumi, Georgia Email:
Abstract
In this article, we study generated sets of the complete semigroups of binary relations defined by X-semilattices unions of the class Σ8
(
X n, + +k 1)
, andfind uniquely irreducible generating set for the given semigroups.
Keywords
Semigroup, Semilattice, Binary Relation
1. Introduction
Let X be an arbitrary nonempty set, D isan X-semilattice of unions which is closed with respect to the set-theoretic union of elements from D, f be an arbi-trary mapping of the set X in the set D. To each mapping f we put into corres-pondence a binary relation
α
f on the set X that satisfies the condition{ } ( )
(
)
f x X
x f x
α
∈
=
× . The set of all suchα
f ( f X: →D) is denoted by( )
X
B D . It is easy to prove that BX
( )
D is a semigroup with respect to theop-eration of multiplication of binary relations, which is called a complete semi-group of binary relations defined by an X-semilattice of unions D.
We denote by ∅ an empty binary relation or an empty subset of the set X. The
condition
( )
x y, ∈α
will be written in the formx y
α
. Further, let x y X, ∈ ,Y⊆X ,
α
∈BX( )
D ,Y D
D Y
∈
=
and T∈D. We denote by the symbols yα
,Yα
, V D(
,α
)
, X∗ and V X(
∗,α
)
the following sets:{
}
(
) {
}
{
}
(
)
{
}
| , , , | ,
| , , | ,
y Y
y x X y x Y y V D Y Y D
X Y Y X V X Y Y X
α α α α α α
α α
∈
∗ ∗
= ∈ = = ∈
= ∅ ≠ ⊆ = ∅ ≠ ⊆
How to cite this paper: Diasamidze, Y., Givradze, O., Tsinaridze, N. and Tavdgi-ridze, G. (2018) Generated Sets of the Complete Semigroup Binary Relations Defined by Semilattices of the Class
(
)
8 X n, k 1
Σ + + . Applied Mathematics, 9, 369-382.
https://doi.org/10.4236/am.2018.94028
Received: March 22, 2018 Accepted: April 24, 2018 Published: April 27, 2018
Copyright © 2018 by authors and Scientific Research Publishing Inc. This work is licensed under the Creative Commons Attribution International License (CC BY 4.0).
http://creativecommons.org/licenses/by/4.0/
DOI: 10.4236/am.2018.94028 370 Applied Mathematics
{
|}
,{
|}
.T T
D = Z∈D T ⊆Z Yα = y∈X yα =T
It is well known the following statements: Theorem 1.1. Let D=
{
D Z Z, 1, 2, ,Zm−1}
be some finite X-semilattice of unions and C D
( ) {
= P P P0, ,1 2,,Pm−1}
be the family of sets of pairwisenonin-tersecting subsets of the set X (the set ∅ can be repeated several times). If ϕ is a
mapping of the semilattice D on the family of sets C D
( )
which satisfies the conditions1 2 1
0 1 2 1
m
m
D Z Z Z
P P P P
ϕ
−−
=
and ˆ \
Z Z
D =D D , then the following equalities are valid:
( )
0 1 2 1 0
ˆ
, .
Zi
m i
T D
D P P P P− Z P ϕ T
∈
= ∪ ∪ ∪ ∪ = ∪
(1.1)In the sequel these equalities will be called formal.
It is proved that if the elements of the semilattice D are represented in the form (1.1), then among the parameters Pi
(
0< ≤ −i m 1)
there exist suchpa-rameters that cannot be empty sets for D. Such sets Pi are called bases sources,
where sets Pj
(
0≤ ≤ −j m 1)
, which can be empty sets too are calledcom-pleteness sources.
It is proved that under the mapping ϕ the number of covering elements of the
pre-image of a
bases source is always equal to one, while under the mapping ϕ the number of
covering elements of the pre-image of a completeness source either does not ex-ist or is always greater than one (see [1][2] chapter 11).
Definition 1.1. We say that an element α of the semigroup BX
( )
D is ex-ternal ifα δ β
≠ for allδ β
, ∈BX( ) { }
D \α
(see [1][2] Definition 1.15.1).It is well known, that if B is all external elements of the semigroup BX
( )
D andB′
is any generated set for the BX( )
D , then B⊆B′ (see [1][2] Lemma 1.15.1).Definition 1.2. The representation
(
T)
T DYα T
α
∈
=
× of binary relation α iscalled quasinormal, if T T D
Yα X
∈
=
and YT YTα α
′
∩ = ∅ for any T T, ′∈D,
T≠T′ (see [1][2] chapter 1.11).
Definition 1.3. Let
α β
, ⊆ ×X X . Their productδ α β
= is defined as follows: x yδ
(
x y, ∈X)
if there exists an element z∈X such that x z yα β
(see [1], chapter 1.3).
2. Result
Let Σ8
(
X n, + +k 1)
(
3≤ ≤k n)
be a class of all X-semilattices of unionswhose every element is isomorphic to an X-semilattice of unions
{
1, 2, , n k,}
D= Z Z Z + D
, which satisfies the condition:
(
)
(
)
(
)
, 1, 2, , ; , 1, 2, , ;
\ and \ 1 .
n i i j p q q p
Z Z D i k Z D j n k
Z Z Z Z p q n k
+ ⊂ ⊂ = ⊂ = +
≠ ∅ ≠ ∅ ≤ ≠ ≤ +
DOI: 10.4236/am.2018.94028 371 Applied Mathematics
Figure 1. Diagram of the semilattice D.
It is easy to see that D=
{
Z Z1, 2,,Zn k+}
is irreducible generating set of thesemilattice D.
Let C D
( ) {
= P P P0, ,1 2,,Pn k+}
be a family of sets, where P P P0, ,1 2,,Pn k+are pairwise disjoint subsets of the set X and 1 2
0 1 2
n k
n k
D Z Z Z
P P P P
ϕ
++
=
is a map
ping of the semilattice D onto the family of sets C D
( )
. Then the formalequali-ties of the semilattice D have a form:
0 0, 0,
,
; , 1, 2, , ; , 1, 2, , .
n k n k n k
i j i n q i
i i i
i j i q n q
D P Z P j n Z P q k
+ + +
+
= = =
≠ ≠ +
= = = = =
(2.0)Here the elements P ii
(
=1, 2,,n+k)
are bases sources, the element P0are sources of completeness of the semilattice D. Therefore X ≥ +n k (by
symbol X we denoted the power of a set X), since Pi ≥1
(
i=1, 2,,n+k)
(see [1][2] chapter 11).
In this paper we are learning irreducible generating sets of the semigroup
( )
X
B D defined by semilattices of the class Σ8
(
X n, + +k 1)
.Note, that it is well known, when k=2, then generated sets of the complete
semigroup of binary relations defined by semilattices of the class
(
)
(
)
8 X, 2 2 1 8 X, 5
Σ + + = Σ .
In this paper we suppose, that 3≤ ≤k n.
Remark, that in this case (i.e. k≥3), from the formal equalities of a semilattice D follows, that the intersections of any two elements of a semilattice D is not empty.
Lemma 2.0 If D∈Σ8
(
X n, + +k 1)
, then the following statements are true:a) 0
1 ;
n k
i i
Z P
+
=
=
b) Zj+1\Zj=Pj, j=1, 2,,n−1;
c) Zq\Zn q+ =Pn q+ , 1,q= , .k
Proof. From the formal equalities of the semilattise D immediately follows the following statements:
0 1
1 0, 0,
1
0, 0,
,
, \ \ , 1, 2, , 1;
\ \ , 1, , .
n k n k n k
i j j i i j
i i i
i j i j
n k n k
q n q i i n q
i i
i q i q n q
Z P Z Z P P P j n
Z Z P P P q k
+ + +
+
= = =
≠ + ≠
+ +
+ +
= =
≠ ≠ +
= = = = −
= = =
DOI: 10.4236/am.2018.94028 372 Applied Mathematics
Lemma 2.0 is proved.
We denoted the following sets by symbols D1, D2 and D3:
{
}
{
}
{
}
1 1, 2, , k , 2 k1, k 2, , n , 3 n1, n2, , n k .
D = Z Z Z D = Z + Z + Z D = Z + Z + Z +
Lemma 2.1. Let D∈Σ8.0
(
X n, + +k 1)
andα
∈BX( )
D . Then the following statements are true:1) Let T T, ′∈D2∪D T3, ≠T′. If T T, ′∈V D
(
,α
)
, then α is external elementof the semigroup BX
( )
D ;2) Let T∈D1, T′∈D2∪D3. If T′ ⊄T and T T, ′∈V D
(
,α
)
, then α isex-ternal element of the semigroup BX
( )
D .3) Let T T, ′∈D1 and
T
≠
T′
. If T T, ′∈V D(
,α
)
and k≥3, then α isex-ternal element of the semigroup BX
( )
D ; Proof. Let Z0=D
and
α δ β
= for someδ β
, ∈BX( ) { }
D \α
. Ifquasi-normal representation of binary relation δ has a form
(
)
( , ) T T V D
Yδ T
δ
δ
∈
=
× , then(
)
( , ) T T V D
Yδ T
δ
α δ β
β
∈
= =
× . (2.1) From the formal equalities (2.0) of the semilattice D we obtain that:0
0 0,
0, ,
; , 1, 2, , ;
, 1, 2, , .
n k n k i j i
i i
i j n k
n q i i i q n q
Z P Z P j n
Z P q k
β β β β
β β
+ +
= =
≠ +
+ = ≠ +
= = =
= =
(2.2)where Piβ ≠ ∅ for any Pi≠ ∅
(
i=0,1, 2,,n+k)
andβ
∈BX( )
D bydefinition of a semilattice D from the class Σ8.0
(
X n, + +k 1)
.Now, let Zmβ =T and Zj
β
=T′ for someT
≠
T′
, T T, ′∈D2∪D3, thenfrom the equalities (2.3) follows that T =P0β =T′ since T and T′ are
minim-al elements of the semilattice D and P0≠ ∅ by preposition. The equality
T=T′ contradicts the inequality T≠T′.
The statement a) of the Lemma 2.1 is proved.
Now, let Zmβ =T and Zj
β
=T′, for some T∈D1, T′∈D2∪D3 andT′ ⊄T, then from the equalities 2.3 follows, that
0 0
n k
j i
i
T Z
β
Zβ
Pβ
+
=
′ = = =
, if j=0 , or0,
n k
j i
i i j
T Z β Pβ
+
= ≠
′ = =
, 1≤ ≤j n , or0, ,
n k
n q i
i i q n q
T Z β Pβ
+ +
= ≠ +
′ = =
where j= +n q. For the Zj
β
=T′ we consider the following cases:1) If 0 0
n k
i i
T Z
β
Pβ
+
=
′ = =
, then we have0 1 n k
Pβ=Pβ==P+ β=T′,
DOI: 10.4236/am.2018.94028 373 Applied Mathematics
0, 0,
0, 0,
, ,
, if 1 ;
, if .
n k n k i i i i m i m m n k n k
i i i i q n q i q n q
P T T m n
T Z
P T T m n q
β β β + + = = ≠ ≠ + + = = ≠ + ≠ + = ′= ′ ≤ ≤ = = = ′= ′ = +
But the equality
T
=
T
′
contradicts the inequalityT
≠
T
′
. Thus we have,that j≠0.
2) Let 1≤ ≤j n, i.e.
0,
n k
j i
i i j
T Z β Pβ
+
= ≠
′ = =
, then we have, that0 1 j1 j1 n k
P
β
=Pβ
==P−β
=P+β
==P+β
=T′,since
T′
is a minimal element of a semilattice D. On the other hand:0 0,
0, 0,
,
0, ,
, if 0;
, if 1 , ;
, if ;
n k n k
i i j j i i
i j n k n k
i i j j i i
i m i m j m
n k i i i j n j
i i
P P P T P m
P P P T P m n m j
T Z
P T m n j
P
β β β β
β β β β
β β β + + = = ≠ + + = = ≠ ≠ + = ≠ + = = ∪ = ′∪ = = ∪ = ′∪ ≤ ≤ ≠ = = = ′ = +
0, 0,
, , ,
, if , .
n k n k
i j j i
i q n q i q n q j
Pβ Pβ T Pβ m n q q j
+ + = ≠ + ≠ + = ∪ = ′∪ = + ≠
The equality
T
=
T
′
contradicts the inequalityT
≠
T′
. Also, the equalityj
T = ∪T′ P
β
(
Pjβ
∈D)
contradicts the inequalityT
≠ ∪
T
′
Z
for anyZ∈D and T′ ⊄T (T′ ⊄T, by preposition) by definition of a semilattice D. 3) If j= +n q
(
1≤ ≤q k)
, i.e.0, ,
n k
n q i
i i q n q
T Z β Pβ
+ +
= ≠ +
′ = =
, then we have, that0 1 q1 q1 n q1 n q1 n k
P
β
=Pβ
==P−β
=P+β
==P+ −β
=P+ +β
==P+β
=T′,since
T′
is a minimal element of a semilattice D. On the other hand:0, 0,
,
0, 0,
,
0,
, if 0;
, if 1 ;
n k n k
i i q n q q n q
i i
i q n q
n k n k
i i n q n q
i i
i q i q n q
m n k
i i
i i m
P P P P T P P m
P P P T P m q n
T Z
P P
β β β β β β
β β β β
β β β + + + + = = ≠ + + + + + = = ≠ ≠ + + = ≠ ′ = ∪ ∪ = ∪ ∪ = = ∪ = ′∪ ≤ = ≤ = = =
0, , ,0, 0, 0,
, , , , , ,
, if 1 ;
,
n k
q n q q n q
i i m q n q
n k n k n k
i i i q n q q n q
i i i
i m i q n q i q n q q n q
P P T P P m q n
P P P P P T P P
β β β β
β β β β β
+ + + = ≠ + + + + + + = = = ′ ′ ′ ′ ≠ ≠ + ≠ + + ∪ ∪ = ′∪ ∪ ≤ ≠ ≤ = = ∪ ∪ = ∪ ∪
if n 1 m n q n k q, q since j m.
DOI: 10.4236/am.2018.94028 374 Applied Mathematics
The equality
T
=
T
′
contradicts the inequalityT
≠
T′
. Also, the equalityq n q
T = ∪T′ P
β
∪P+β
, or T = ∪T′ Pn q+β
(
Pqβ
,Pn q+β
∈D)
contradicts thein-equality
T
≠ ∪
T
′
Z
for any Z∈D and T′ ⊄T by definition of a semilatticeD.
The statement 2) of the Lemma 2.1 is proved.
Let T T, ′∈D1 and
T
≠
T
′
. If k≥3 and Zjβ
=T′, Zmβ =T, then fromthe formal equalities (2.0) of a semilattice D there exists such an element, that
q j
P ⊆Z and Pq⊆Zm, where 0≤ ≤ +q m k. So, from the equalities (2.3)
fol-lows that Pq
β
⊆Zjβ
=T′ and Pqβ
⊆Zmβ
=T . Of from this and from theequalities (2.3) we obtain that there exists such an element Z∈D, for which the
equalities
T
′
= ∪
Z
Z
′
andT
= ∪
Z
Z′′
, where Z Z′ ′′∈, D. But such elementsby definition of a semilattice D do not exist. The statement c) of the Lemma 2.1 is proved. Lemma 2.1 is proved.
Lemma 2.2. Let D∈Σ8
(
X n, + +k 1)
andα
∈BX( )
D . Then the following statements are true:1) Let V D
(
,α
)
∩D1≠ ∅,V D(
,α
)
∩D2= ∅,V D(
,α
)
∩D3= ∅. If(
,)
1 2V D
α
∩D ≥ , then α is external element of the semigroup BX( )
D ;2) Let V D
(
,α
)
∩D1= ∅,V D(
,α
)
∩D2≠ ∅,V D(
,α
)
∩D3= ∅. If(
,)
2 2V D
α
∩D ≥ , then α is external element of the semigroup BX( )
D ;3) Let V D
(
,α
)
∩D1= ∅,V D(
,α
)
∩D2= ∅,V D(
,α
)
∩D3≠ ∅. If(
,)
3 2V D
α
∩D ≥ , then α is external element of the semigroup BX( )
D ;4) Let V D
(
,α
)
∩D1= ∅,V D(
,α
)
∩D2≠ ∅,V D(
,α
)
∩D3≠ ∅, then α isex-ternal element of the semigroup BX
( )
D ;5) Let V D
(
,α
)
∩D1≠ ∅,V D(
,α
)
∩D2= ∅,V D(
,α
)
∩D3≠ ∅. If(
,)
1 2V D
α
∩D ≥ , V D(
,α
)
∩D3 =1, or V D(
,α
)
∩D1 =1,(
,)
3 2V D
α
∩D ≥ then α is external element of the semigroup BX( )
D ;6) Let V D
(
,α
)
∩D1≠ ∅,V D(
,α
)
∩D2≠ ∅,V D(
,α
)
∩D3= ∅, then α isex-ternal element of the semigroup BX
( )
D ;7) Let V D
(
,α
)
∩D1≠ ∅,V D(
,α
)
∩D2≠ ∅,V D(
,α
)
∩D3≠ ∅, then α isex-ternal element of the semigroup BX
( )
D .Proof. Let α be any element of the semigroup BX
( )
D . It is easy that(
,)
V D
α
∈D. We consider the following cases:Let V D
(
,α
)
∩D1= ∅,V D(
,α
)
∩D2= ∅,V D(
,α
)
∩D3= ∅, then(
,)
{ }
V D
α
∈ D since V D(
,α
)
is subsemilattice of the semilattice D.1) Let V D
(
,α
)
∩D1≠ ∅,V D(
,α
)
∩D2= ∅,V D(
,α
)
∩D3= ∅.If V D
(
,α
)
∩D1 =1, then V D(
,α
)
∈{ }
Zj , or V D(
,α
)
∈{
Z Dj,}
, where
1, 2, ,
j= k, since V D
(
,α
)
is subsemilattice of the semilattice D.If V D
(
,α
)
∩D1 ≥2, then by statement c) of the Lemma 2.1 follows that αisexternal element of the semigroup BX
( )
D .2) Let V D
(
,α
)
∩D1= ∅,V D(
,α
)
∩D2≠ ∅,V D(
,α
)
∩D3= ∅.If V D
(
,α
)
∩D2 =1, then V D(
,α
)
∈{ }
Zj , or V D(
,α
)
∈{
Z Dj,}
, where
1, 2, ,
DOI: 10.4236/am.2018.94028 375 Applied Mathematics
If V D
(
,α
)
∩D2 ≥2, then by statement a) of the Lemma 2.1 follows that αisexternal element of the semigroup BX
( )
D .3) Let V D
(
,α
)
∩D1= ∅,V D(
,α
)
∩D2= ∅,V D(
,α
)
∩D3≠ ∅.If V D
(
,α
)
∩D3 =1 , then V D(
,α
)
∈{ }
Zj , or V D(
,α
)
∈{
Z Dj,}
,
1, 2, ,
j= +n n+ n+k, since V D
(
,α
)
is subsemilattice of the semilattice D.If V D
(
,α
)
∩D3 ≥2, then by statement a) of the Lemma 2.1 follows that α isexternal element of the semigroup BX
( )
D .4) Let V D
(
,α
)
∩D1= ∅,V D(
,α
)
∩D2≠ ∅,V D(
,α
)
∩D3≠ ∅, then by thestatement a) of the Lemma 2.1 follows that α is external element of the
semi-group BX
( )
D .5) Let V D
(
,α
)
∩D1≠ ∅,V D(
,α
)
∩D2= ∅,V D(
,α
)
∩D3≠ ∅.If V D
(
,α
)
∩D1 =1,V D(
,α
)
∩D3 =1 , then V D(
,α
)
={
Zn q+ ,Zq}
, or(
,)
{
n q, Z ,q}
V D
α
= Z + D , or V D(
,α
)
={
Zn q+ ,Z Dj,}
where Z1≤Zj≤Zk and
1, 2, ,
q= k.
If V D
(
,α
)
={
Zn q+ ,Z Dj,}
where j≠q q, =1, 2,,k, then by the statement
2) of the Lemma 2.1 follows that α is external element of the semigroup
( )
X
B D ;
If V D
(
,α
)
∩D1 =1,V D(
,α
)
∩D3 ≥2, or(
,)
1 2,(
,)
3 1V D
α
∩D ≥ V Dα
∩D = , then from the statement 1) and 3) of theLemma 2.1 follows that α is external element of the semigroup BX
( )
Drespec-tively.
6) Let V D
(
,α
)
∩D1≠ ∅,V D(
,α
)
∩D2≠ ∅,V D(
,α
)
∩D3= ∅. Then fromthe statement b) of the Lemma 2.1 follows that α is external element of the
semi-group BX
( )
D .7) Let V D
(
,α
)
∩D1≠ ∅,V D(
,α
)
∩D2≠ ∅,V D(
,α
)
∩D3≠ ∅, then by thestatement a) of the Lemma 2.1 follows that α is external element of the
semi-group BX
( )
D .Lemma 2.2 is proved.
Now we learn the following subsemilattices of the semilattice D:
{
}
{
}
{
}
{
}
{
}
{
}
{ }
{ }
{
}
1
2
3
4
, , , where 1, 2, , ;
, , where 1, 2, , ;
, , where 1, 2, , ;
, , where 1, 2, , .
n j j j n j j
j
Z Z D j k
Z D j n k
Z Z j k
Z D j n k
+
+
= =
= = +
= =
= = +
A
A
A
A
We denoted the following sets by symbols A0 and B
( )
A0 :(
)
(
)
{
}
( )
{
( ) (
)
}
0 1 2 3 4
0 0
, | , ,
| , .
X
V D D V D
B B D V D
α α
α α
= ⊆ ∉ ∪ ∪ ∪
= ∈ ∈
A A A A A
A A
By definition of a set B
( )
A0 follows that any element of the set is externalelement of the semigroup BX
( )
D .Lemma 2.3. Let D∈Σ8
(
X n, + +k 1)
. If quasinormal representation of aDOI: 10.4236/am.2018.94028 376 Applied Mathematics
(
Yn j Zn j) (
Yj Zj) (
Y0 D)
,α α α
α
= + × + ∪ × ∪ ×
where Yn j,Yj ,Y0
{ }
α α α
+ ∉ ∅ and j=1, 2,,k, then α is generated by elements of
the elements of set B
( )
A0 .Proof. 1). Let quasinormal representation of binary relations δ and β have a
form
(
) (
) (
) (
)
(
) (
(
)
)
(
(
0)
)
(
(
)
)
,\ \ \ ,
n j n j j j q q
n j n j j n j j j q
Y Z Y Z Y Z Y D
Z Z Z Z Z D Z Z X D D
δ δ δ δ
δ β
+ +
+ + +
= × ∪ × ∪ × ∪ ×
= × ∪ × ∪ × ∪ ×
where Yn j,Yj ,Yq
{ }
,Z1 Zq Z qk, j j, 1, ,kα α α
+ ∉ ∅ ≤ ≤ ≠ = .
(
)
(
) (
)
(
)
(
)
0 1,
,
\ \ \
\ \
n j j n j j n k
i n j j i
i j n j
Z Z Z D Z X D
P P P P X D D X D X
+ +
+
+ =
≠ +
∪ ∪ ∪
= ∪ ∪ ∪ ∪ = ∪ =
,since the representation of a binary relation β is quasinormal and by
state-ment 3) of the Lemma 2.1 binary relations δ and β are external elements of the semigroup BX
( )
D . It is easy to see, that:,
n j n j
Z +
β
=Z +0 0
1, 1,
,
,
n k n k
j i i n j
i i
i j i j n j n j n j n j j j
Z P P P P P
Z P Z Z Z
β β β
β β
+ +
+
= =
≠ ≠ +
+ + +
= ∪ = ∪ ∪
= ∪ = ∪ =
0 1,
0
,
n k
q i n j j q i
i q n k
i n j j q i
Z P P Z Z Z D
D P Z Z Z D
β β
β β
+
+ =
≠ +
+ =
= ∪ = ∪ ∪ =
= = ∪ ∪ =
since Zq∩Zn j+ ≠ ∅,Zq∩
(
Zj\Zn j+)
=Pn j+ ≠ ∅,Zq∩(
D Z\ j)
=Pj ≠ ∅ (seeequality (2.0))
(
) (
) (
) (
)
(
) (
) (
) (
)
(
) (
) (
(
)
)
0
0
0 ,
n j n j j j q q
n j n j j j q
n j n j j j q
Y Z Y Z Y Z Y D
Y Z Y Z Y D Y D
Y Z Y Z Y Y D
δ δ δ δ
δ δ δ δ
δ δ δ δ
α δ β β β β β
α
+ +
+ +
+ +
= = × ∪ × ∪ × ∪ × = × ∪ × ∪ × ∪ ×
= × ∪ × ∪ ∪ × =
if Yn j Yn j
δ α
+ = + , Yj Yj
δ = α and
0 0
q
Yδ ∪Yδ =Yα. Last equalities are possible since
0 1
q
Yδ∪Yδ ≥ (Y0 0
δ ≥ , by preposition). Lemma 2.3 is proved.
Lemma 2.4. Let D∈Σ8
(
X n, + +k 1)
. If quasinormal representation of abi-nary relation α has a form
α
=(
Yjα×Zj) (
∪ Y0α×D)
, where Yjα,Y0α∉ ∅{ }
,1, 2, ,
j= n+k, then binary relation α is generated by elements of the elements of set B
( )
A0 .DOI: 10.4236/am.2018.94028 377 Applied Mathematics
form:
(
) (
) (
)
(
)
(
(
)
)
(
(
)
)
0 ,
\ \ ,
j j q q j j j q
Y Z Y Z Y D
Z Z D Z Z X D D
δ δ δ
δ β
= × ∪ × ∪ ×
= × ∪ × ∪ ×
where Y Yjδ, qδ∉ ∅
{ }
and Z1≤Zj≠Zq ≤Zn k+ . Then from the statements a), b)and c) of the Lemma 2.1 follows, that δ and β are generated by elements of the
set B
( )
A0 and,
j j
Z
β
=Zq
Z
β
=D , since Zq∩(
D Z\ j)
=Pj≠ ∅, ;D
β
=D(
) (
) (
)
(
) (
) (
)
(
) (
(
)
)
0
0
0 ,
j j q q
j j q
j j q
Y Z Y Z Y D
Y Z Y D Y D
Y Z Y Y D
δ δ δ
δ δ δ
δ δ δ
δ β β β β
α = × ∪ × ∪ × = × ∪ × ∪ × = × ∪ ∪ × =
if Yj Yj
δ = α
, Yq Y0 Y0
δ ∪ δ = α
and q=1, 2,,n+k. Last equalities are possible
since Yq Y0 1
δ∪ δ ≥ (
0 0
Yδ ≥ by preposition).
Lemma 2.4 is proved.
Lemma 2.5. Let D∈Σ8
(
X n, + +k 1)
. If quasinormal representation of abi-nary relation α has a form
(
Yn j Zn j) (
Yj Zj)
α α
α
= + × + ∪ × , where Yn j,Yj{ }
α α + ∉ ∅ ,
1, 2, ,
j= k, then binary relation α is generated by elements of the elements of set B
( )
A0 .Proof. Let quasinormal representation of a binary relations δ, β have a form
(
) (
) (
)
(
)
(
(
)
)
(
(
)
)
0 ,
\ \ ,
n j n j q q n j n j n j j
Y Z Y Z Y D
Z Z D Z Z X D D
δ δ δ
δ β
+ +
+ + +
= × ∪ × ∪ ×
= × ∪ × ∪ ×
where Yn jδ+ ,Yqδ∉ ∅
{ }
, j≠q and j=1, 2,,k. Then from the Lemma 2.2follows that β is generated by elements of the set B
( )
A0 ,δ
∈B( )
A0 and ,n j n j
Z +
β
=Z +q n j j j
Z
β
=Z + ∪Z =Z , since Zq∩Zn j+ ≠ ∅ ,(
\)
,q n j n j
Z ∩ D Z+ =P+ ≠ ∅ ≠j q
(see equality (2.0))
j
D
β
=Z since D∩(
X D\ )
= ∅,(
) (
) (
)
(
) (
) (
)
(
) (
(
)
)
0
0
0 ,
n j n j q q
n j n j q j j
n j n j q j
Y Z Y Z Y D
Y Z Y Z Y Z
Y Z Y Y Z
δ δ δ
δ δ δ
δ δ δ
δ β β β
α
+ +
+ +
+ +
= × ∪ × ∪ × = × ∪ × ∪ × = × ∪ ∪ × =
if Yn j Yn j
δ α
+ = + and Yq Y0 Yj
δ ∪ δ = α
. Last equalities are possible since
0 1
q
Yδ∪Yδ ≥ (Y0 0
δ ≥ by preposition). Lemma 2.5 is proved.
Lemma 2.6. Let D∈Σ8
(
X n, + +k 1)
. Then the following statements are true:DOI: 10.4236/am.2018.94028 378 Applied Mathematics
(
j=1, 2,,k)
, then binary relation α is generated by elements of the set( )
0B A .
2) If quasinormal representation of a binary relation α has a form α = ×X D,
then binary relation αis generated by elements of the set B
( )
A0 .Proof. 1)Let T∈D\
(
D2∪D3)
. If quasinormal representation of a binaryre-lations δ, β have a form
(
) (
)
(
) (
(
)
)
(
(
)
)
0 ,
\ \ ,
j j
n j n j j n j j
Y Z Y D
Z Z Z Z Z X D D
δ δ
δ
β + + +
= × ∪ ×
= × ∪ × ∪ ×
where Y Yj, 0
{ }
δ δ∈ ∅ ,
1, 2, ,
j= k
(
)
(
)
(
)
(
)
(
)
0, ,
\ \
\ \
n j j n j
n k
i j n j
i i j n j
Z Z Z X D
P P P X D D X D X
+ +
+
+ =
≠ +
∪ ∪
= ∪ ∪ ∪ = ∪ =
(see equalities (2.0) and (2.1)), then from the Lemma 2.4 follows that δ is
gener-ated by elements of the set B
( )
A0 and from the Lemma 2.3 element β isgen-erated by elements of the set B
( )
A0 and,
j n j j j
Z
β
=Z + ∪Z =Zj
D
β
=Z , since D∩(
X D\ )
= ∅,(
Yj Zj) (
Y0 D) (
Yj Zj) (
Y0 Zj)
X Zj ,δ δ δ δ
δ β
= ×β
∪ × β
= × ∪ × = × =α
since representation of a binary relation δ is quasinormal.
The statement a) of the lemma 2.6 is proved.
2) Let quasinormal representation of a binary relation δhave a form
(
Zn j Zq) (
(
X Z\ n j)
D)
,δ = + × ∪ + ×
where j≠q, then from the Lemma 2.4 follows that δ is generated by elements
of the set B
( )
A0 and0, 0,
,
n k n k
q i i q
i i
i q i q
Z δ P δ Pδ Z D D Dδ D
+ +
= =
≠ ≠
= = = ∪ = =
, since1
, q n
j≠q Z
δ
∩Z + ≠ ∅ and Zqδ
∩(
X Z\ n+1)
≠ ∅;(
) (
(
)
)
(
)
(
(
)
)
\\
n j q n j n j n j
Z Z X Z D
Z D X Z D X D
δ δ δ δ
α
+ +
+ +
= × ∪ ×
= × ∪ × = × =
,
since representation of a binary relation δ is quasinormal.
The statement b) of the lemma 2.6 is proved. Lemma 2.6 is proved.
Lemma 2.7. Let D∈Σ8
(
X n, + +k 1)
. Then the following statements are true:a) If X D\ ≥1 and T∈D2∪D3, then binary relation
α = ×
X T
isDOI: 10.4236/am.2018.94028 379 Applied Mathematics
b) If X =D and T∈D2∪D3, then binary relation
α = ×
X T
is externalelement for the semigroup BX
( )
D .Proof. 1) If quasinormal representation of a binary relation δ has a form
(
0)
(
)
1
n k
j j j k
Yδ D Yδ Z
δ +
= +
= × ∪
× ,where Yj
δ ≠ ∅ for all
1, 2, ,
j= +k k+ n+k, then
δ
∈B( ) { }
A0 \α
. Letqua-sinormal representation of a binary relations β have a form
(
)
(
{ } ( )
)
\
t X D
D T t f t
β
′∈
′ ′ = × ∪ ×
, where f is any mapping of the set X D\ in theset
(
D2∪D3) { }
\ T . It is easy to see, thatβ α
≠ and two elements of the set2 3
D ∪D belong to the semilattice V D
(
,β
)
, i.e.δ
∈B( ) { }
A0 \α
. In this casewe have that Zj
β
=T for all j= +k 1,k+2,,n+k.(
)
(
)
(
)
(
)
0
1
0
1
0 1
,
n k
j j j k
n k j j k n k
j j k
Y D Y Z
Y T Y T
Y Y T X T
δ δ
δ δ
δ δ
δ β δ β β
α
+ = + + = + + = +
= = × ∪ ×
= × ∪ ×
= ∪ × = × =
since the representation of a binary relation δ is quasinormal. Thus, the element α is generated by elements of the set B
( )
A0 .The statement a) of the lemma 2.7 is proved.
2) Let X =D,
α = ×
X T
, for some T∈D2∪D3 andα δ β
= for some( ) { }
, BX D \
δ β
∈α
. Then we obtain that Zjβ
=T since T is a minimal elementof the semilattice D.
Now, let subquasinormal representations
β
of a binary relation β have a form{ }
( )
(
2)
0 \
n k
i
i t X D
P T t t
β
+β
′
= ∈
′ ′ = × ∪ ×
,where 0 1 2
1
n k
P P P P
T T T T
β
+ =
is normal mapping. But complement mapping
2
β
is empty, since X D\ = ∅, i.e. in the given case, subquasinormalrepresen-tation β of a binary relation β is defined uniquely. So, we have that
X T
β β
= = × =α
(see property 2) in the case 1.1), which contradict thecondi-tion, that
β
∉BX( ) { }
D \α
.Therefore, if X =D and
α = ×
X T
, for some T∈D2∪D3, then α isex-ternal element of the semigroup BX
( )
D .The statement 2) of the Lemma 2.7 is proved. Lemma 2.7 is proved.
Theorem 2.1. Let D∈Σ8
(
X n, + +k 1)
, k≥3, and{
}
{
}
{
}
1 1, 2, , k , 2 k1, k 2, , n , 3 n1, n2, , n k ;
D = Z Z Z D = Z + Z + Z D = Z + Z + Z+
{
}
{
}
1= Zn q+ ,Z Dq, , whereq=1, 2, , ;k
DOI: 10.4236/am.2018.94028 380 Applied Mathematics
{
}
{
}
2= Z Dj, , where j=1, 2, ,n+k;
A
{
}
{
}
3= Zn j+ ,Zj , where j=1, 2,, ;k
A
{ }
{ }
{
}
4 = Zj , D , where j=1, 2, ,n+k;
A
(
)
(
)
{
}
0= V D,
α
⊂D V D| ,α
∉ 1∪ 2∪ 3∪ 4 ,A A A A A
( )
0{
X( ) (
| ,)
0}
,B A =
α
∈B D V Dα
∈A{
}
0 | 2 3
B = X T T× ∉D ∪D
Then the following statements are true:
1) If X D\ ≥1, then the S0=B
( )
A0 is irreducible generating set for the semigroup BX( )
D ;2) If X =D, then the S1=B0∪B
( )
A0 is irreducible generating set for the semigroup BX( )
D .Proof. Let D∈Σ8
(
X n, + +k 1)
, k≥3 and X D\ ≥1
. First, we proved that every element of the semigroup BX
( )
D is generated by elements of the set S0.Indeed, let α be an arbitrary element of the semigroup BX
( )
D . Thenquasi-normal representation of a binary relation α has a form
(
0)
(
)
1
n k
i i
i
Yα D Yα Z
α
+=
= × ∪
× ,where
0
n k
i i
Yα X
+
=
=
and Yi Yjα∩ α = ∅
(
)
0≤ ≠ ≤ +i j n k . For the V X
(
∗,α
)
we consider the following cases: 1) If V X
(
,α
)
1 2 3 4∗ ∉A ∪A ∪A ∪A , then
( )
0
B S
α
∈ A0 ⊆ by definition ofa set S0.
Now, let V X
(
,α
)
1 2 3 4∗ ∈A ∪A ∪A ∪A . 2) If V X
(
,α
)
1∗ ∈A , then quasinormal representation of a binary relation α has a form
(
Yn j Zn j) (
Yj Zj) (
Y0 D)
α α α
α
= + × + ∪ × ∪ ×
, where Yn j,Yj ,Y0
{ }
α α α
+ ∉ ∅
(
j=1, 2,,k)
and from the Lemma 2.3 follows that α is generated by elementsof the elements of set B
( )
A0 ⊆S0 by definition of a set S0.3) If V X
(
,α
)
2∗ ∈A , then quasinormal representation of a binary relation α has a form
(
Yj Zj) (
Y0 D)
α α
α
= × ∪ × , where Yjα,Y0α∉ ∅{ }
, j=1, 2,,n+kand from the Lemma 2.4 follows that α is generated by elements of the elements
of set B
( )
A0 ⊆S0 by definition of a set S0.4) If V X
(
,α
)
3∗ ∈A , then quasinormal representation of a binary relation α
has a form
(
Yn j Zn j) (
Yj Zj)
α α
α
= + × + ∪ × , where Yn j,Yj{ }
α α
+ ∉ ∅ , j=1, 2,,k and from the Lemma 2.5 follows that α is generated by elements of the elements
of set B
( )
A0 ⊆S0 by definition of a set S0.Now, let V X
(
,α
)
4∗ ∈
A , then quasinormal representation of a binary
rela-tion α has a form α = ×X D, or
α
= ×X Zj, where j=1, 2,,n+k.5) If α = ×X D, then from the statement b) of the Lemma 2.6 follows that
DOI: 10.4236/am.2018.94028 381 Applied Mathematics
6) If
α
= ×X Zj, where j=1, 2,,n+k, then from the statement a) of theLemma 2.6 and 2.7 follows that binary relation αis generated by elements of the
set B
( )
A0 .Thus, we have that S0 is a generating set for the semigroup BX
( )
D .If X D\ ≥1, then the set S0 is an irreducible generating set for the
semi-group BX
( )
D since, S0 is a set external elements of the semigroup BX( )
D .The statement a) of the Theorem 2.1 is proved.
Now, let X =D. First, we proved that every element of the semigroup
( )
X
B D is generated by elements of the set S1. The cases 1), 2), 3), 4) and 5)
are proved analogously of the cases 1), 2), 3), 4) and 5 given above and consider case, when V X
(
,α
)
1∗ ∈
A .
If V X
(
,α
)
Zj∗ = , where
1, 2, ,
j= k, then from the statement a) of the
Lemma 2.7 follows that binary relation α is generated by elements of the set
( )
0B A .
If V X
(
,α
)
Zj∗ = , where
2 3
j
Z ∈D ∪D , then from the statement b) of the
Lemma 2.6 follows that binary relation
α
= ×X T is external element for thesemigroup BX
( )
D .Thus, we have that S1 is a generating set for the semigroup BX
( )
D .If X =D, then the set S1 is an irreducible generating set for the semigroup
( )
X
B D since S1 is a set external elements of the semigroup BX
( )
D .The statement b) of the Theorem 2.1 is proved. Theorem 2.1 is proved.
Corollary 2.1. Let D∈Σ8
(
X n, + +k 1)
(
k≥3)
and{
}
{
}
{
}
1 1, 2, , k , 2 k1, k 2, , n , 3 n1, n2, , n k ;
D = Z Z Z D = Z + Z + Z D = Z + Z + Z +
{
}
{
}
1= Zn q+ ,Z Dq, , whereq=1, 2, , ;k
A
{
}
{
}
2= Z Dj, , where j=1, 2, ,n+k;
A
{
}
{
}
3= Zn j+ ,Zj , where j=1, 2,, ;k
A
{ }
{ }
{
}
4 = Zj , D , where j=1, 2, ,n+k;
A
(
)
(
)
{
}
0= V D,
α
⊂D V D| ,α
∉ 1∪ 2∪ 3∪ 4 ,A A A A A
( )
0{
X( ) (
| ,)
0}
,B A =
α
∈B D V Dα
∈A{
}
0 | 2 3
B = X T T× ∉D ∪D
Then the following statements are true:
1) If X D\ ≥1, then S0=B
( )
A0 is the uniquely defined generating set for the semigroup BX( )
D ;2) If X =D, then S1=B0∪B
( )
A0 is the uniquely defined generating set for the semigroup BX( )
D .Proof. It is well known, that if B is all external elements of the semigroup
( )
X
B D and
B′
is any generated set for the BX( )
D , then B⊆B′ (see [1][2]DOI: 10.4236/am.2018.94028 382 Applied Mathematics
( )
1 0
S =B ∪B A0 are defined uniquely, since they are sets external elements of
the semigroup BX
( )
D .Corollary 2.1 is proved.
It is well-known, that if B is all external elements of the semigroup BX
( )
Dand
B′
is any generated set for the BX( )
D , then B⊆B′ (Definition 1.1).In this article, we find irredusible generating set for the complete semigroups of binary relations defined by X-semilattices of unions of the class
(
)
8 X n, k 1
Σ + +
(
k≥3)
. This generating set is uniquely defined, since they aredefined by elements of the external elements of the semigroup BX
( )
D .References
[1] Diasamidze, Y. and Makharadze, S. (2013) Complete Semigroups of Binary Rela-tions. Kriter, Turkey, 1-519.