Reservoir
Reservoir
Characterization (Part I)
Reservoir stratification (reservoir lithology) Reservoir geometry
Porosity, permeability, and water saturation Adjoining aquiferj g q
Reservoir stratification
Reservoir stratification
Most reservoirs are layered because of variations that existed Most reservoirs are layered because of variations that existed in the depositional environment.
Porosity
V
p b maV
V
V
V
V
Porosity
=
φ
=
=
−
b bV
V
Rock Matrix and Pore Space
Rock Matrix and Pore Space
P
S
Cl
ifi ti
Pore-Space Classification
z Total porosity, φt = Space Pore Total z Effective porosity, φe = Volume Bulk p y, φeSpace
Pore
cted
Interconne
Volume
Bulk
Space
Pore
cted
Interconne
Permeability
z Permeability is a property of the porous
medium and is a measure of the capacity medium and is a measure of the capacity of the medium to transmit fluids
Absolute Permeability
z When the medium is completely
saturated with one fluid then the saturated with one fluid, then the permeability measurement is often referred to as
specific
orabsolute
referred to asspecific
orabsolute
permeability
Effective Permeability
Effective Permeability
z When the rock pore spaces contain
more than one fluid, then the permeability to a particular fluid is called the
effective permeability
z Effective permeability is a measure of
the fluid conductance capacity of a the fluid conductance capacity of a porous medium to a particular fluid when the medium is saturated with when the medium is saturated with more than one fluid
Relative Permeability
z
Relative permeability
p
y
is defined as theratio of the effective permeability to a fluid at a given saturation to theg effective permeability to that fluid at 100% saturation
Calculating Relative Permeabilities
z Oilk
k
eo z Oilk
k
ro=
eo z Waterk
k
=
ewk
k
rw=
z Gask
k
=
egk
k
rg=
In-Situ Saturation
In-Situ Saturation
Fluid Saturation
Fluid Saturation
z The saturation of the fluid is the fraction of
the pore volume occupied by that fluid
fluid
of
Volume
volume
Pore
fluid
of
Volume
S
=
Fluid Saturations
Fluid Saturations
z Basic concepts of hydrocarbon
accumulation
– Initially, pore space filled 100% with water – Hydrocarbons migrate up dip into trapsy g p p p
– Hydrocarbons distributed by capillary forces and gravity
– Connate water saturation remains in hydrocarbon zone
Determining Fluid Saturations
Determining Fluid Saturations
z Core analysis
z Capillary pressure measurementsp y p z Electric openhole logs
Adjoining Aquifer
Adjoining Aquifer
The aquifer is the total volume of porous water-bearing rock in
Areal View Vertical view
g pressure communication with a hydrocarbon reservoir.
Areal View Vertical view
Gas
reservoir
Gas reservoir
B tt t
reservoir Bottom water
Aquifer water
h f h
encroaches from the side
Reservoir Fluid Properties
Reservoir Fluid Properties
The fluid properties of interest to the Reservoir Engineer are
th th t ff t th bilit f fl id ithi th i
those that affect the mobility of fluids within the reservoirs these are used in material balance calculations
Properties at surface conditions for transportation and sales (API, viscosity, oil quality)
Reservoir Fluid Properties
Reservoir Fluid Properties
Oil Properties
– Bubble Point Pressure – Bo – Rs – Bt – Co and μo Gas properties Gas properties – z – Bg and μg
Compositions oil & gas
Real Gas in Reservoir
Real Gas in Reservoir
nZRT
pV
=
Equation of State:
pV
=
nZRT
Quantity Description Unit/Value
p Pressure psia
V Volume ft^3
V Volume ft 3
n Mole number lb-moles
Z G ibilit di i l Z Gas compressibility factor dimensionless T Temperature Rankine R Universal Gas 10.73 constant
Calculating Z (1)
Calculating Z (1)
0 1 2 3 4 5 6 7 8 0 1 2 3 4 5 6 7 8 3,0 2,8 2,6 2,4 2,2 2,0 1,9NHIEÄT ÑOÄ GIAÛ GIAÛM
1,5 1,3 1 1 1,0 1,1 1,0 1,1
Step 1: Calculate pseudo-critical pressure and temperature (Sutton) 1,8 1,7 1,6 1,5 1,45 1,4 1,4 1,1 1,05 1,1 1,2 1 6 1,7 0,9 0 7 0,8 0,9 2 6 . 3 0 . 131 8 . 756 g g pc p = − γ − γ 2 0 74 5 349 2 169 T = − γ − γ 1,35 1,3 1,25 1,2 1,3 1,4 1,5 1,6 1,7 1,8 1 4 1,5 1,6 0 5 0,6 0,7 HEÄ SOÁ LEÄ CH KH Í, Z 0 . 74 5 . 349 2 . 169 g g pc T γ γ
Step 2: Calculate pseudo-reduced pressure and temperature: 1,15 1,1 , 1,9 2,0 2,2 2,4 2,6 3,0 1,2 1,3 1,4 0,3 0,4 0,5 pc pr pc pr T T T p p p = ; = 1,05 1,2 1,1 1 71,8 1,9 2,0 2,2 2,4 2,6 3,0 2,8 1,0 1,1 1,0 1,1 pc pc p
Step 3: Use Standings-Katz plot to determine Z 7 8 9 10 11 12 13 14 15 , 1,05 1,4 1,3 1,6 1,7 0,9 0,9
Exercise 1
Exercise 1
Calculate z-factor according to the given data as followsQuantity Value Unit
Specific gravity 0.665 Dimensionless g y Reservoir temperature 213 °F temperature Reservoir pressure 3250 psia pressure
Solution to Exercise 1
Solution to Exercise 1
0 1 2 3 4 5 6 7 8 0 1 2 3 4 5 6 7 8 3,0 2,8 2,6 2,4 2,2 2,0 1,9NHIEÄT ÑOÄ GIAÛ GIAÛM
1,5 1,3 1 1 1,0 1,1 1,0 1,1
Step 1: Calculate pseudo-critical pressure and temperature (Sutton) 1,8 1,7 1,6 1,5 1,45 1,4 1,4 1,1 1,05 1,1 1,2 1 6 1,7 0,9 0 7 0,8 0,9 668 ) 665 (. 6 . 3 ) 665 (. 0 . 131 8 . 756 − − 2 = = pc p 369 ) 665 (. 0 . 74 ) 665 (. 5 . 349 2 . 169 − − 2 = = pc T 1,35 1,3 1,25 1,2 1,3 1,4 1,5 1,6 1,7 1,8 1 4 1,5 1,6 0 5 0,6 0,7 HEÄ SOÁ LEÄ CH KH Í, Z pc
Step 2: Calculate pseudo-reduced pressure and temperature: 1,15 1,1 , 1,9 2,0 2,2 2,4 2,6 3,0 1,2 1,3 1,4 0,3 0,4 0,5 82 . 1 ; 87 . 4 = = pr pr T p 1,05 1,2 1,1 1 71,8 1,9 2,0 2,2 2,4 2,6 3,0 2,8 1,0 1,1 1,0
1,1 Step 3: Use Standings-Katz plot to determine
Z 7 8 9 10 11 12 13 14 15 , 1,05 1,4 1,3 1,6 1,7 0,9 0,9
AÙP SUAÁT GIAÛ GIAÛM
Calculate Z using Dranchuk and
Abou-Kassem Correlation
Abou-Kassem Correlation
2 11 2 11 5 5 4 2 3 2 1 r r (1 r ) exp( r ) 1 0 r r Z R R R A A R R F = − + ρ − ρ + + ρ − ρ + = ρ ρ 5 5 4 4 3 3 2 1 1 / 27 0 / / / / ) /( 27 . 0 pr pr pr pr pr pr r T p R T A T A T A T A A R ZT p = + + + + = = ρ 2 8 7 9 4 2 8 7 6 3 2 ) / / ( / / / 27 . 0 pr pr pr pr pr pr T A T A A R T A T A A R T p R + = + + = = 5339 . 0 ; 0700 . 1 ; 3265 . 0 2 3 1 = A = − A = − A 3 10 5 A / T pr R = 1056 . 0 ; 1844 . 0 ; 7361 . 0 5475 . 0 ; 05165 . 0 ; 01569 . 0 9 8 7 6 5 4 = = − = = − = = A A A A A A 7210 . 0 ; 6134 . 0 11 10 = A = AExercise 2: PVT Analysis
Exercise 2: PVT Analysis
Using the data in the table below and assuming real gas behavior, calculate the density of the gas phase under initial reservoir conditions. Compare the results with that of ideal gas behavior.
Critical Critical Component Mole Percent Molecular Weight
Critical Critical Press. Temp. (psia) (R) (1) (2) (3) (4) C1 0.85 16.043 666.4 343.00 C2 0 04 30 070 706 5 549 59 C2 0.04 30.070 706.5 549.59 C3 0.03 44.097 616.0 665.73 iC4 0.03 58.123 527.9 734.13 nC4 0.02 58.123 550.6 765.29 iC5 0.00 72.150 490.4 828.77 nC5 0.00 72.150 488.6 845.47 C6 0.00 86.177 436.9 913.27 C7 0.00 100.204 396.8 972.37 C8 0.00 114.231 360.7 1023.89 C9 0 00 128 258 331 8 1070 35 C9 0.00 128.258 331.8 1070.35 C10 0.00 142.285 305.2 1111.67 H2S 0.00 34.080 1300.0 672.12 CO2 0.02 44.010 1071.0 547.58 N2 0.01 28.013 493.1 227.16 H 0 00 4 003 33 0 9 36 He 0.00 4.003 33.0 9.36 Air 0.00 28.960 546.9 238.36 O2 0.00 31.999 731.4 278.24