R E S E A R C H
Open Access
Split hierarchical variational inequality
problems and related problems
Qamrul Hasan Ansari
1,2, Nimit Nimana
3and Narin Petrot
3,4**Correspondence: narinp@nu.ac.th 3Department of Mathematics,
Faculty of Science, Naresuan University, Phitsanulok, 65000, Thailand
4Centre of Excellence in
Mathematics, CHE, Si Ayutthaya Rd., Bangkok, 10400, Thailand Full list of author information is available at the end of the article
Abstract
The main objective of this paper is to introduce a split hierarchical variational inequality problem. Several related problems are also considered. We propose an iterative method for finding a solution of our problem. The weak convergence of the sequence generated by the proposed method is studied.
MSC: 47H09; 47H10; 47J25; 49J40; 65K10
Keywords: split hierarchical variational inequality problem; split common fixed point problem; split convex minimization problem; strongly nonexpansive operators; cutter operators
1 Introduction
In , Censor and Elfving [] introduced the following split feasibility problem (in short, SFP): find a point
x∗∈C such that Ax∗∈Q, (.)
whereCandQare nonempty closed convex subsets ofRnandRm, respectively, andAis
anm×nmatrix. They proposed an algorithm to find the solution of SFP. Their algorithm did not become popular, since it concerns the complicated matrix inverse computations and, subsequently, is considered in the case whenn=m. Based on these observations, Byrne [] applied the forward-backward method, a type of projected gradient method, presenting the so-called CQ-iterative procedure, which is defined by
xk+=PC
xk+γA(PQ–I)Axk
, ∀k≥,
where an initialx∈Rn, γ ∈(, /A), andP
C andPQdenote the metric projections
ontoCandQ, respectively. The convergence result of the sequence{xk}∞k=to a solution of the considered split feasibility problem was presented. Further, Byrne also proposed an application to dynamic emission tomographic image reconstruction. A few years later, Censoret al.[, ] proposed an incredible application of the split feasibility problem to the inverse problem of intensity-modulated radiation therapy treatment planning. Recently, Xu [] considered SFP in the setting of infinite-dimensional Hilbert spaces and established the following CQ-algorithm: LetHandHbe real Hilbert spaces andA:H→Hbe a
bounded linear operator. For a givenx∈H, generated a sequence{xk}∞k=by the following iterative scheme:
xk+=PC
xk+γA∗(PQ–I)Axk
, ∀k≥,
whereγ ∈(, /A), andA∗is the adjoint operator ofA. He also proved the weak con-vergence of the sequence produced by the above procedure to a solution of the SFP. The details of the CQ-algorithm for SFP problem are given in []. A comprehensive literature, survey, and references on SFP can be found in [].
In , Censor and Segal [] presented an important form of the split feasibility prob-lem called the split common fixed point probprob-lem, which is to find a point
x∗∈Fix(T) such that Ax∗∈Fix(S), (.)
whereTandSare some nonlinear operators onRnandRm, respectively, andAis a real
m×nmatrix. Based on the properties of operatorsT andS, called cutter or directed operators, they presented the following algorithm for solving the split common fixed point problem:
xk+=T
xk+γA(S–I)Axk
, ∀k≥, (.)
where an initial x∈Rn, γ ∈(, /A). They also presented a convergence result for this algorithm. Moudafi [] studied the split common fixed point problem in the context of the demicontractive operatorsT andS in the setting of infinite-dimensional Hilbert spaces. He established the weak convergence of the sequence generated by his scheme to a solution of the split common fixed point problem.
On the other hand, the theory of variational inequalities is well known and well devel-oped because of its applications in different areas of science, social science, engineering, and management. There are several monographs on variational inequalities, but we men-tion here a few [–]. LetCbe a nonempty closed convex subset of a real Hilbert space Handf :H→Hbe an operator. The variational inequality problem defined byCandf is to findx∗∈Csuch that
(VIP(C;f)) fx∗,x–x∗≥, for allx∈C.
Another problem closely related toVIP(C;f) is known as the Minty variational inequality problem: findx∗∈Csuch that
(MVIP(C;f)) f(x),x–x∗≥, for allx∈C.
The trivial unlikeness of two proposed problems is the linearity of variational inequalities. In fact, the Minty variational inequalityMVIP(C;f) is linear but the variational inequality
VIP(C;f) is not. However, under the (hemi)continuity and monotonicity off, the solution sets of these problems are the same (see [, Lemma ]).
LetT:H→H be a nonlinear operator with the set of fixed pointsFix(T)=∅andf : H→H be an operator. The hierarchical variational inequality problem is to findx∗ ∈
Fix(T) such that
fx∗,x–x∗≥, for allx∈Fix(T). (.)
A closely related problem to hierarchical variational inequality problem is the hierarchical Minty variational inequality problem: findx∗∈Fix(T) such that
f(x),x–x∗≥, for allx∈Fix(T). (.)
In the recent past, several methods for solving hierarchical variational inequalities have been investigated in the literature; see, for example, [–] and the references therein.
The goal of this paper is to introduce a split-type problem, by combining a split fixed point problem and a hierarchical variational inequality problem. The considered problem can be applied to solve many existing problems. We present an iterative procedure for find-ing a solution of the proposed problem and show that under some suitable assumptions, the sequence generated by our algorithm converges weakly to a solution of the considered problem.
The rest of this paper is divided into four sections. In Section , we recall and state preliminaries on numerous nonlinear operators and their useful properties. Section we divide in two subsections, that is, first, we present a split problem, called the split hierar-chical Minty variational inequality problem. We subsequently propose an algorithm for solving our problem and establish a convergence result under some assumptions. Second, we present the split hierarchical variational inequality problem. In the last section, we investigate some related problems, where we can apply the considered problem.
2 Preliminaries
LetH be a real Hilbert space whose inner product and norm are denoted by·,·and
· , respectively. The strong convergence and weak convergence of a sequence {xk}∞k= tox∈Hare denoted byxk→xandxkx, respectively. LetT :H→Hbe an operator.
We denote byR(T) the range of T, and byFix(T) the set of all fixed points ofT, that is,Fix(T) ={x∈H:x=Tx}. The operatorTis said to benonexpansiveif for allx,y∈H,
Tx–Ty ≤ x–y;strongly nonexpansive[, ] ifTis nonexpansive and for all bounded sequences{xk}∞k=,{yk}∞k=inH, the conditionlimk→∞(xk–yk–Txk–Tyk) = implies limk→∞(xk–yk) – (Txk–Tyk)= ;averaged nonexpansiveif for allx,y∈H,T = ( –
α)I+αSholds for a nonexpansive operatorS:H→Handα∈(, );firmly nonexpansive if T–Iis nonexpansive, or equivalently for allx,y∈H,Tx–Ty≤ x–y,Tx–Ty;cutter [] ifx–Tx,z–Tx ≤ for allx∈Hand allz∈Fix(T);monotoneifTx–Ty,x–y ≥, for allx,y∈H;α-inverse strongly monotone(orα-cocoercive) if there exists a positive real numberαsuch thatTx–Ty,x–y ≥αTx–Ty, for allx,y∈H.
LetB:H→H be a set-valued operator, we define a graph ofBby{(x,y)∈H×H:
y∈B(x)}and an inverse operator ofB, denotedB–, by{(y,x)∈H×H:x∈B(y)}. A set-valued operator B:H→His calledmonotoneif for allx,y∈H,u∈B(x) andv∈B(y)
ofB. For a maximal monotone operatorB, we know that for eachx∈Hand a positive real numberσ, there is a uniquez∈Hsuch thatx∈(I+σB)z. We define theresolventofB with parameterσbyJB
σ := (I+σB)–. It is well known that the resolvent is a single-valued and firmly nonexpansive operator.
Remark . It can be seen that the class of averaged nonexpansive operators is a proper subclass of the class of strongly nonexpansive operators. Since any firmly nonexpansive operator is an averaged nonexpansive operator, it is clear that a class of firmly nonex-pansive operators is contained in the class of strongly nonexnonex-pansive operators. Further, a firmly nonexpansive operator with fixed point is cutter. However, a nonexpansive cutter operator need not to be firmly nonexpansive; for further details, see [].
The following well-known lemma is due to Opial [].
Lemma .(Demiclosedness principle) [, Lemma ] Let C be a nonempty closed convex
subset of a real Hilbert space H and T:C→H be a nonexpansive operator.If the sequence
{xk}∞k=⊆C converges weakly to an element x∈C and the sequence{xk–Txk}∞k=converges strongly to,then x is a fixed point of the operator T.
To prove the main theorem of this paper, we need the following lemma.
Lemma .[, Section .., Lemma ] Assume that{ak}∞k=and{bk}∞k=are nonnegative real sequences such that ak+≤ak+bk.If
∞
k=bk<∞,thenlimk→∞akexists.
The following lemma can be immediately obtained by the properties of an inner product.
Lemma . Let H be a real Hilbert space H.Then,for all x,y∈H,
x–y≤ x+ y,y–x.
3 Split hierarchical variational inequality problems and convergent results
In this section we introduce split hierarchical variational inequality problems and discuss some related problems. Further, we propose an iterative method for finding a solution of the hierarchical variational inequality problem and prove the convergence result for the sequence generated by the proposed iterative method.
3.1 Split hierarchical Minty variational inequality problem
LetHandHbe two real Hilbert spaces,f,T:H→Hbe operators such thatFix(T)=∅, andh,S:H→Hbe operators such thatFix(S)=∅. LetA:H→Hbe an operator with R(A)∩Fix(S)=∅. Thesplit hierarchical Minty variational inequality problem(in short, SHMVIP) is to findx∗∈Fix(T) such that
f(x),x–x∗≥, for allx∈Fix(T), (.)
and such thatAx∗∈Fix(S) satisfies
The solution set of SHMVIP (.)-(.) is denoted by, that is,
:=xwhich solves (.) :Axsolves (.).
We note that the problems (.) and (.) are nothing but hierarchical Minty variational inequality problems. Iff andhare zero operators, that is,f ≡h≡, then SHMVIP (.) and (.) reduces to the split fixed point problem (.). Moreover, SHMVIP (.) and (.) can be applied to several existing split-type problems, which we will discuss in Section . Inspired by the iterative scheme (.) for solving split common fixed point problem (.) and the existing algorithms, a generalization of the projected gradient method, for solving the hierarchical variational inequality problem of Yamada [] and Iiduka [], we now present an iterative algorithm for solving HMVIP (.)-(.).
Algorithm .
Initialization: Choose{αk}∞k=,{βk}∞k=⊂(, +∞). Take arbitraryx∈H. Iterative Step: For a given current iteratexk∈H, compute
yk:=xk–γA∗
I–S(I–βkh)
Axk,
whereγ ∈(,A) and definexk+∈Hby
xk+:=T(I–αkf)yk.
Updatek:=k+ .
Rest of the section, unless otherwise specified, we assume thatT is a strongly nonex-pansive operator onHwithFix(T)=∅andSis a strongly nonexpansive cutter operator onHwithFix(S)=∅,f (respectively,h) is a monotone and continuous operator onH (respectively,H) andA:H→His a bounded linear operator withR(A)∩Fix(S)=∅.
Remark . (i) The Algorithm . can be applied to the iterative scheme (.) by setting the operatorsf ≡h≡.
(ii) The iterative Algorithm . extends and develops the algorithms in [, Algo-rithm .] and [, AlgoAlgo-rithm ()] in many aspects. Indeed, the metric projectionsPC
andPQin [, Algorithm .] and the resolvent operatorsJλB andJ
B
λ in [, Algorithm ()] are firmly nonexpansive operators which are special cases of the assumption on the operators T andS. Second, its involves control sequences{αk}∞k= and{βk}∞k=, while in [, Algorithm .] and [, Algorithm ()] they are constant. Furthermore, we assume
γ ∈(,A), while in [, Algorithm .] and [, Algorithm ()], it was assumed to be in
(,A), which clearly is a more restrictive assumption.
(iii) By setting an operatorAto be zero operator, the iterative Algorithm . relates to existing iterative schemes for solving the hierarchical variational inequality problem in, for example, [, Algorithm .] and [, Algorithm ].
Theorem . Let a sequence{xk}∞k=be generated by Algorithm.with x∈H,and let
{αk}∞k= and {βk}∞k=⊂(, ) be sequences such that∞k=αk<∞andlimk→∞βk= .If
=∅,then the following statements hold.
(i) If there exists a natural numberksuch that
⊂
∞
k=k
z∈H:
h(Axk),S(I–βkh)Axk–Az
≥,
then,for allk≥kandz∈,we have
yk–z≤ xk–z–γ
–γAI–S(I–βkh)
Axk
.
(ii) If the sequence{f(yk)}∞k=is bounded,thenlimk→∞xk–zexists for allz∈.
(iii) If the sequence{h(Axk)}∞k=is bounded,thenlimk→∞xk+–xk= ,
limk→∞xk–Txk= ,andlimk→∞Axk–SAxk= .
(iv) Ifxk+–xk=o(αk),andαk=o(βk),then the sequence{xk}∞k=converges weakly to an element of.
Proof (i) Letz∈be given. Then
yk–z =xk–γA∗
I–S(I–βkh)
Axk–z
=xk–z+γA∗
I–S(I–βkh)
Axk
– γxk–z,A∗
I–S(I–βkh)
Axk
≤ xk–z+γAI–S(I–βkh)
Axk
– γxk–z,A∗
I–S(I–βkh)
Axk
, (.)
for allk≥. On the other hand, sinceSis a cutter operator, we have with
xk–z,A∗
S(I–βkh) –I
Axk
=Axk–Az,
S(I–βkh) –I
Axk
=S(I–βkh)(Axk) –Az,S(I–βkh)(Axk) –Axk
–S(I–βkh) –I
Axk
=S(I–βkh)(Axk) –Az,S(I–βkh)(Axk) – (I–βkh)Axk
–βk
S(I–βkh)(Axk) –Az,h(Axk)
–S(I–βkh) –I
Axk
≤–S(I–βkh) –I
Axk, (.)
for allk≥k. By using (.), the inequality (.) becomes
yk–z≤ xk–z+γAS(I–βkh) –I
Axk
– γS(I–βkh) –I
Axk
=xk–z–γ
–γAS(I–βkh) –I
Axk
for allk≥k, as required. Furthermore, sinceγ <A, we observe thatγ( –γA) > ,
and hence
yk–z ≤ xk–z, ∀k≥k. (.)
(ii) LetM:=sup{f(yk):k≥}. Fork≥k, we havexk+–z ≤ xk–z+αkM. Since
∞
k=αk<∞, by using Lemma ., we obtain the result thatlimk→∞xk–zexists.
(iii) We first show thatlimk→∞xk–xk+= .
Letwk:=yk–αkf(yk) for allk≥. Note that{wk}∞k=is a bounded sequence, since for all
k≥kwe know thatwk–z ≤ yk–z+αkf(yk)and{yk}∞k=is a bounded sequence. By using the nonexpansiveness ofT and (.), we have
≤ wk–z–Twk–Tz ≤ xk–z+αkf(yk)–xk+–z, ∀k≥k.
Subsequently, by the existence oflimk→∞xk–zand the fact thatαk→, it follows that lim
k→∞
wk–z–Twk–Tz
= .
By the strong nonexpansiveness ofT and the boundedness of{wk}∞k=, we have
lim
k→∞wk–Twk= .
On the other hand, by (i), we observe that
xk+–z≤yk–αkf(yk) –z
≤ yk–z+αkf(yk)
+ αkf(yk)yk–z ≤ xk–z–γ
–γAI–S(I–βkh)
Axk
+αkf(yk)
+ αkf(yk)yk–z,
which is equivalent to
γ –γAI–S(I–βkh)
Axk
≤ xk–z–xk+–z+αkf(yk)
+ αkf(yk)yk–z, (.)
for allk≥k. Taking the limit ask→ ∞, we get
lim
k→∞I–S(I–βkh)
Axk= , (.)
which implies, by the definition ofyk, that
lim
k→∞yk–xk= , (.)
and also
lim
These together imply that
lim
k→∞xk–xk+ ≤klim→∞
xk–wk+wk–Twk
= , (.)
as desired.
We now show thatlimk→∞xk–Txk= .
Observe thatxk+–Tyk ≤αkf(yk) → ask→ ∞. Using this one together with (.),
(.) and the nonexpansiveness ofT, we obtain
lim
k→∞xk–Txk= . (.)
Next, we show thatlimk→∞Axk–SAxk= .
Setzk:=Axk–βkh(Axk) for allk≥. For everyk≥k, we observe that
≤ zk–Az–Szk–SAz ≤βkh(Axk)+Axk–Szk.
Thus, the boundedness of{h(Axk)}∞k=and (.) yield
lim k→∞
zk–Az–Szk–SAz
= ,
and hence, by the fact that the sequence{zk}∞k=is bounded andSis a strongly nonexpansive mapping, we have
lim
k→∞zk–Szk= . (.)
We note thatAxk–zk=βkh(Axk) → ask→ ∞. Also, we observe that zk–SAxk ≤ zk–Szk+S
Axk–βkh(Axk)
–SAxk≤ zk–Szk+βkh(Axk),
for allk≥k. By using (.) and taking the limit ask→ ∞, we get
lim
k→∞zk–SAxk= .
Hence, we get
lim
k→∞Axk–SAxk= , (.)
as required.
(iv) Since{xk}∞k=is a bounded sequence, there exist a subsequence{xkj}∞j=of{xk}∞k=and q∈Hsuch thatxkjq∈H. By (iii) and the demiclosed principle of the nonexpansive
operatorT, we obtainq∈Fix(T). We claim thatq∈Fix(T) solves (.). In fact, fork≥k, we have
xk+–z≤ yk–z+ αk
f(yk),z–wk
=xk–z+ αk
f(yk),z–yk
+ αkf(yk)
=xk–z+ αk
f(z),z–yk
– αk
f(yk) –f(z),yk–z
+ αkf(yk)
≤ xk–z+ αk
f(z),z–yk
+ αkf(yk)
, (.)
and then
f(z),yk–z
≤
αk
xk–z–xk+–z
+ αkf(yk)
≤
αk
xk–z+xk+–z
xk–z–xk+–z
+ αkf(yk)
≤ xk–xk+
αk
M+ αkf(yk),
whereM:=sup{xk–z+xk+–z:k≥}<∞. Sincexkjq,αk→, andxk+–xk= o(αk), by (.), we havef(z),q–z ≤ for allz∈Fix(T) which means thatq∈Fix(T)
solves (.).
Next, byAxkjAq∈Htogether with (iii) and the demiclosedness of the nonexpansive
operatorS, we know thatAq∈Fix(S). We show that suchAq∈Fix(S) solves (.). Sinceαk=o(βk), we may assume thatαk≤βkfor allk≥k. From (.), for allk≥k,
we have
γ –γAAxk–Szk≤ xk–xk+M+αkf(yk)
+ αkf(yk)yk–z,
whereM:=sup{xk–z+xk+–z:k≥k}. This implies that, fork≥k,
γ –γAAxk–Szk
βk ≤
xk–xk+
βk M+ αk
βkM≤
xk–xk+
αk
M+αk
βkM,
where M:=max{M,supk≥{f(yk)+ f(yk)yk–z}}. Subsequently, sincexk+– xk=o(αk),αk=o(βk), andγ( –γA) > , we have
lim k→∞
Axk–Szk
βk
= . (.)
Fork≥k, we compute
Szk–SAz≤Axk–βkh(Axk) –Az
≤ Axk–Az+ βk
h(Axk),Az–zk
=Axk–Az+ βk
h(Axk),Az–Axk
+ βkh(Axk)
=Axk–Az– βk
Axk–Az,h(Axk) –h(Az)
+ βk
h(Az),Az–Axk
+ βkh(Axk)
≤ Axk–Az+βkh(Axk) –h(Az)
+ βk
h(Az),Az–Axk
+ βkh(Axk)
This gives
h(Az),Axk–Az
≤
βk
Axk–Az–Szk–SAz
+βkh(Axk) –h(Az)
+ βkh(Axk)
≤Axk–Szk
βk
M+βkh(Axk) –h(Az)
+ βkh(Axk)
,
whereM:=sup{Axk–Az+Szk–SAz:k≥}<∞. Using this together withAxkj
Aq∈Fix(S) and (.), we obtainh(Az),Aq–Az ≤ for allAz∈Fix(S). Thus,Aq∈Fix(S) solves (.), and therefore,q∈.
Finally, it remains to show thatxkq∈. By the boundedness of{xk}∞k=, it suffices to show that there is no subsequence{xki}∞i=of{xk}∞k=such thatxkip∈Handp=q.
Indeed, if this is not true, the well-known Opial theorem would imply
lim
k→∞xk–p=jlim→∞xkj–q
< lim
j→∞xkj–p
= lim
k→∞xk–p
= lim
i→∞xki–p < lim
i→∞xki–q
= lim
k→∞xk–p,
which leads to a contradiction. Therefore, the sequence{xk}∞k=converges weakly to a point
q∈.
3.2 Split hierarchical variational inequality problems
We consider another kind of split hierarchical variational inequality problem (in short, SHVIP) in which we consider a variational inequality formulation instead of the Minty variational inequality. More precisely, we consider the followingsplit hierarchical varia-tional inequality problem:find a pointx∗∈Fix(T) such that
fx∗,x–x∗≥, for allx∈Fix(T), (.)
such thatAx∗∈Fix(S) and it satisfies
hAx∗,y–Ax∗≥, for ally∈Fix(S). (.)
The solution set of the SHVIP is denoted by . SinceFix(T) andFix(S) are nonempty closed convex and f and h are monotone and continuous, by the Minty lemma [, Lemma ], SHVIP (.)-(.) and SHMVIP (.)-(.) are equivalent. Hence, Algo-rithm . and Theorem . are also applicable for SHVIP (.)-(.).
Remark . It is worth to note that, in the context of SHVIP (.)-(.), if we assume either the finite dimensional settings ofH andH or the compactness of spacesHand H, then the monotonicity assumptions of operatorsf andhcan be omitted.
In fact, as in the statement and the proof of Theorem ., since we know thatxkjq∈ Fix(T), we also havexkj→q∈Fix(T). Recalling the inequality (.), we have, fork≥k,
xk+–z≤ xk–z+ αk
f(yk),z–yk
+ αkf(yk)
,
which is equivalent to
f(yk),yk–z
≤xk–xk+
αk
M+ αkf(yk)
,
whereM:=sup{xk–z+xk+–z:k≥}<∞. Since we know thatykj→q∈Fix(T) and
f is continuous, by approachingjto infinity, we obtainf(q),q–z ≤, for allz∈Fix(T), which means thatq∈Fix(T) solves (.). Similarly, from the inequality (.), we note that, fork≥k,
Szk–SAz≤ Axk–Az+ βk
h(Axk),Az–Axk
+ βkh(Axk)
,
which is equivalent to
h(Axk),Axk–Az
≤Axk–Szk
βk
M+ βkh(Axk)
,
whereM:=sup{Axk–Az+Szk–SAz:k≥}<∞. SinceAxkj →Aq∈Fix(S) and
his continuous, we also geth(Aq),Aq–Az ≤, for allAz∈Fix(S), which means that Aq∈Fix(S) solves (.), and subsequently,q∈ .
Remark . The strong nonexpansiveness of operatorsT andSin Theorem . can be
applied to the cases when the operatorsT andSare not only firmly nonexpansive, but with relaxation of being firmly nonexpansive and averaged nonexpansive but also strictly nonexpansive, that is, Tx–Ty<x–yor x–y=Tx–Tyfor allx,y; regarding the compactness of the spacesHandH, for more details, see [, Remark ..].
4 Some related problems
In this section, we present some split-type problems which are special cases of SHVIP (.) and (.) and can be solved by using Algorithm ..
4.1 A split convex minimization problem
Letφ:H→Randϕ:H→Rbe convex continuously differentiable functions andA: H→Hbe a bounded linear operator such thatA(H)∩Fix(S)=∅. Consider the following split convex minimization problem(in short, SCMP): find
x∗∈Fix(T) such that x∗=argmin x∈Fix(T)
φ(x), (.)
and such that
Ax∗∈Fix(S) such that Ax∗=argmin y∈Fix(S)
We know that the SCMP (.)-(.) can be formulated as the following split hierarchical variational inequality problem: find a point
x∗∈Fix(T) such that ∇φx∗,x–x∗≥, for allx∈Fix(T), and such that the point
Ax∗∈Fix(S) such that ∇ϕAx∗,y–Ax∗≥, for ally∈Fix(S),
where ∇φ and∇ϕ denote the gradient ofφ andϕ, respectively. Since∇φ and∇ϕ are monotone [, Proposition .] and continuous, we can apply Algorithm . to obtain the solution of SCMP (.)-(.), and Theorem . will provide the convergence of the sequence{xk}∞k=to a solution of SCMP (.)-(.). Furthermore, in the context of finite-dimensional cases, we can remove the convexity ofφandϕ.
4.2 A split variational inequality problem over the solution set of monotone variational inclusion problem
LetHandHbe two real Hilbert spaces,φ:H→H,ϕ:H→HbeL, (respectively, L)-inverse strongly monotone operators,B :H→H, B:H →H are set-valued
maximal monotone operators. Let us consider the followingmonotone variational inclu-sion problem(in short, MVIP): find
x∗∈H such that ∈φx∗+Bx∗. We denote the solution set of MVIP bySOL(φ,B).
Forσ> ,λ∈(, L), we know that the operatorJσB(I–λφ) is an averaged nonexpansive operator and
FixJB
σ (I–λφ)
=SOL(φ,B), whereJB
σ represents the resolvent ofBwith parameterσ.
We consider the following split variational inequality problem: findx∗∈SOL(φ,B) such that
f(x),x–x∗≥, for allx∈SOL(φ,B), (.)
and such thatAx∗∈SOL(ϕ,B) satisfies
h(y),y–Ax∗≥, for ally∈SOL(ϕ,B). (.) By using these facts and adding the assumption thatJB
σ (I–λϕ) is cutter, we can apply Algorithm . and Theorem . to obtain the solution of SVIP (.)-(.).
4.3 A split variational inequality problem over the solution set of equilibrium problem
LetHandHbe real Hilbert spaces,C⊆HandQ⊂Hbe nonempty closed convex sets,
andφis the problem of findingx∗∈Csuch that
φx∗,x≥, for allx∈C,
and we denote the solution set of equilibrium problem ofCandφbyEP(C,φ).
Recall that Blum and Oettli [] showed that the bifunctionφ satisfies the following conditions:
(A) φ(x,x) = for allx∈C;
(A) φis monotone, that is,φ(x,y) +φ(y,x)≤for allx,y∈C; (A) for allx,y,z∈C,
lim sup t↓ φ
tz+ ( –t)x,y≤φ(x,y);
(A) for allx∈C,φ(x,·)is a convex and lower semicontinuous function,
and letr> andz∈H, then the set
Tr(z) :=
x∗∈C:φx∗,x+ r
x–x∗,x∗–x≥ for allx∈C
=∅.
Moreover, from [], we know that
(i) Tris single-valued;
(ii) Tris firmly nonexpansive;
(iii) Fix(Tr) =EP(C;φ).
We now consider the following split variational inequality problem: findx∗∈EP(C,φ) such that
f(x),x–x∗≥, for allx∈EP(C,φ), (.)
and such thatAx∗∈EP(Q,ϕ) satisfies
h(y),y–Ax∗≥, for ally∈EP(Q,ϕ). (.) Similarly, by assuming that conditions (A)-(A) in the context of the equilibrium problem defined byQandϕhold, we see that, for allu∈Hands> , the set
Ts(u) :=
y∗∈Q:ϕy∗,y+ s
y–y∗,y∗–u≥ for ally∈Q
is a nonempty set. Moreover, we also see thatTsis single-valued and firmly nonexpansive;
andFix(Ts) =EP(Q;ϕ).
By using these facts, we obtain the result that the problem (.)-(.) forms a special case of the SHVIP (.)-(.).
Competing interests
The authors declare that they have no competing interests.
Authors’ contributions
Author details
1Department of Mathematics, Aligarh Muslim University, Aligarh, 202 002, India.2Department of Mathematics and
Statistics, King Fahd University of Petroleum & Minerals, Dhahran, Saudi Arabia.3Department of Mathematics, Faculty of
Science, Naresuan University, Phitsanulok, 65000, Thailand. 4Centre of Excellence in Mathematics, CHE, Si Ayutthaya Rd.,
Bangkok, 10400, Thailand.
Acknowledgements
The authors would like to thank the anonymous referees for their careful reading and suggestions, which allowed us to improve the first version of this paper. This research is partially support by the Center of Excellence in Mathematics the Commission on Higher Education, Thailand. QH Ansari was partially supported by a KFUPM Funded Research Project No. IN121037. N Nimana was supported by the Thailand Research Fund through the Royal Golden Jubilee PhD Program (Grant No. PHD/0079/2554).
Received: 14 May 2014 Accepted: 16 September 2014 Published: 13 October 2014 References
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