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R E S E A R C H

Open Access

Affine algorithms for the split variational

inequality and equilibrium problems

Yonghong Yao

1*

, Rudong Chen

1

and Yeong-Cheng Liou

2

*Correspondence:

[email protected] 1Department of Mathematics,

Tianjin Polytechnic University, Tianjin, 300387, China Full list of author information is available at the end of the article

Abstract

An affine algorithm for the split variational inequality and equilibrium problems is presented. Strong convergence result is given.

Keywords: affine algorithm; split method; variational inequality; equilibrium problem

1 Introduction

In the present manuscript, we focus on the following split variational inequality and equi-librium problem: Finding a pointx∗such that

x∗∈GVI(B,ψ,C) and ψx∗∈EP(F,A), (.)

whereGVI(B,ψ,C) is the solution set of the generalized variational inequality of finding uC,ψ(u)Csuch that

Bu,ψ(v) –ψ(u)≥, ∀ψ(v)C, (.)

andEP(F,A) is the solution set of the equilibrium problem, which is to findxCsuch

that

Fx†,y+Ax†,yx†≥, ∀yC. (.)

Our main motivations are inspired by the following reasons.

Reason  Recently, the split problems have been considered by some authors. Especially, the split feasibility problem which can mathematically be formulated as the problem of finding a pointx˜with the property

˜

xC and g(x)˜ ∈Q

has received much attention due to its applications in signal processing and image recon-struction with particular progress in intensity modulated radiation therapy [–]. Note that the involved operatorgis a bounded linear operator. However, in the present paper, the involved mappingψin (.) is a nonlinear mapping.

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Reason  The variational inequality problem [–] and equilibrium problem [–], which include the fixed point problems and optimization problems [–], have been studied by many authors. It is an interesting topic associated with the analytical and algo-rithmic approach to the variational inequality and equilibrium problems.

Motivated and inspired by the results in the literature, we present an affine algorithm for solving the split problem (.). Strong convergence theorem is given under some mild assumptions.

2 Preliminaries

LetHbe a real Hilbert space with the inner product·,·and the norm · , respectively. LetCbe a nonempty closed convex subset ofH.

2.1 Monotonicity and convexity

An operator A:CH is said to be monotone ifxy,AxAy ≥ for allx,yC. A:CHis said to be strongly monotone if there exists a constantγ >  such thatxy,AxAyγxyfor allx,yC.A:CHis called an inverse-strongly-monotone operator if there existsα>  such thatxy,AxAyαAxAyfor allx,yC. Let g:CCbe a nonlinear operator.A:CHis said to beα-inverse stronglyg-monotone iff g(x) –g(y),AxAyαAxAyfor allx,yC and for someα> . LetBbe a mapping ofHinto H. The effective domain ofBis denoted bydom(B), that is,dom(B) =

{xH:Bx=∅}. A multi-valued mappingBis said to be a monotone operator onHiff

xy,uv ≥ for allx,y∈dom(B),uBx, andvBy. A monotone operatorBonHis said to be maximal iff its graph is not strictly contained in the graph of any other monotone operator onH.

A functionF:HRis said to be convex if for anyx,yHand for anyλ∈[, ],F(λx+ ( –λ)y)λF(x) + ( –λ)F(y).

2.2 Nonexpansivity and continuity

A mappingT:CCis said to be nonexpansive [–] ifTxTyxyfor all x,yC. We useFix(T) to denote the set of fixed points ofT.T:CCis called a firmly nonexpansive mapping if, for allx,yC,TxTyxy,TxTy. It is known that T is firmly nonexpansive if and only if a mapping T–Iis nonexpansive, whereIis the identity mapping onH.T:CHis said to beL-Lipschitz continuous if there exists a constantL>  such thatTxTyLxyfor allx,yC. In such a case,T is said to beL-Lipschitz continuous. Given a nonempty, closed convex subsetCofH, the mapping that assigns every pointxHto its unique nearest point inCis called a metric projection ontoCand denoted byPC, that is,PCxCandxPCx=inf{x–y:yC}. The metric projectionPCis a typical firmly nonexpansive mapping. The characteristic inequality of the projection isxPCx,yPCx ≤ for allxH,yC.

2.3 Equilibrium problem

In this paper, we consider the split problem (.). In the sequel, we assume that the solution setSof (.) is nonempty.

Problem . Assume that

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(A) ψ:CCis a weakly continuous andγ-strongly monotone mapping such that

R(ψ) =C;

(A) F:C×CRis a bifunction;

(A) A:CHis aβ-inverse-strongly monotone mapping.

Our objective is to

findx∗∈GVI(B,ψ,C) such thatψx∗∈EP(F,A),

whereFsatisfies the following conditions:

(F) F(x,x) = for allxC;

(F) Fis monotone,i.e.,F(x,y) +F(y,x)≤for allx,yC; (F) for eachx,y,zC,limt↓F(tz+ ( –t)x,y)F(x,y);

(F) for eachxC,yF(x,y)is convex and lower semicontinuous.

In order to solve Problem ., we need the following useful lemmas.

2.4 Useful lemmas

The following three lemmas are important tools for our main results in the next section. Note that these lemmas are used extensively in the literature.

Lemma .(Combettes and Hirstoaga’s lemma []) Let C be a nonempty closed convex subset of a real Hilbert space H.Let F:C×CR be a bifunction which satisfies conditions (F)-(F).Letλ> and xC.Then there exists zC such that

F(z,y) +

λyz,zx ≥, ∀yC.

Further,if Tλ(x) ={zC:F(z,y) +λyz,zx ≥for all yC},then the following hold: (a) Tλis single-valued andTλis firmly nonexpansive;

(b) EP(F)is closed and convex andEP(F) =Fix(Tλ).

Lemma .(Suzuki’s lemma []) Let{xn}and{yn}be bounded sequences in a Banach space X and let{βn}be a sequence in[, ]with <lim infn→∞βn≤lim supn→∞βn< . Suppose xn+= ( –βn)ynnxnfor all n≥andlim supn→∞(yn+–ynxn+–xn)≤. Thenlimn→∞ynxn= .

Lemma .(Xu’s lemma []) Assume that{an}is a sequence of nonnegative real numbers such that an+≤( –γn)an+δnγn,where{γn}is a sequence in(, )and{δn}is a sequence such thatn=γn=∞andlim supn→∞δn≤ (or

n=|δnγn|<∞).Thenlimn→∞an= .

3 Algorithms and convergence analysis

In this section, we first present our algorithm for solving Problem .. Assume that the conditions in Problem . are all satisfied.

Algorithm . LetCbe a nonempty closed and convex subset of a real Hilbert spaceH. Step . (Initialization)

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Step . (Projection step) For{xn}, let the sequence{un}be generated iteratively by

un=PC

αnδϕ(xn) + ( –αn)

ψ(xn) –μnBxn

, n≥,

wherePCis the metric projection,{αn} ⊂[.] is a real number sequence,ϕ:CHis an L-Lipschitz continuous mapping andδ>  is a constant.

Step . (Proximal step) Find{zn}such that

F(zn,y) +Aun,yzn+  λn

yzn,znun ≥, ∀yC,

where{λn} ⊂(,∞) is a real number sequence.

Step . (Affine step) For the above sequences{xn}and{zn}, let the (n+ )th sequence

{xn+}be generated by

ψ(xn+) =βnψ(xn) + ( –βn)zn, n≥,

where{βn} ⊂[, ] is a real number sequence.

Theorem . Suppose S=∅.Assume that the following restrictions are satisfied:

(C) λn∈(a,b)⊂(, β),μn∈(c,d)⊂(, α)andγ ∈(Lδ, α);

(C) limn→∞(μn+–μn) = andlimn→∞(λn+–λn) = ;

(C) limn→∞αn= and

nαn=∞;

(C) βn∈[ξ,ξ]⊂(, ).

Then the sequence{xn}generated by Algorithm.converges strongly to x∗∈S,which solves the following variational inequality:

δϕx∗–ψx∗,ψ(x) –ψx∗≤, ∀x. (.)

Remark . The solution of variational inequality (.) is unique. As a matter of fact, if

˜

xSalso solves (.), we have

δϕx∗–ψx∗,ψ(x) –˜ ψx∗≤ and δϕ(x) –˜ ψ(x),˜ ψx∗–ψ(x)˜ ≤.

Adding up the above two inequalities, we deduce

δϕ(x) –˜ ψ(x) –˜ δϕx∗+ψx∗,ψx∗–ψ(x)˜ ≤.

It follows that

ψx∗–ψ(x)˜ ≤δϕx∗–ϕ(x),˜ ψx∗–ψ(x)˜

δ ϕx∗–ϕ(x)˜ ψx∗–ψ(x)˜ ,

which implies that

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Sinceψisγ-strongly monotone, we have

γ x∗–x˜ ≤ψx∗–ψ(x),˜ x∗–x˜≤ ψx∗–ψ(x)˜ x∗–x˜ .

Hence,

γ x∗–x˜ ≤ ψx∗–ψ(x)˜ ≤δ ϕx∗–ϕ(x)˜ ≤δL x∗–x˜ .

This deduces the contraction because ofδL<γ by the assumption. Therefore,x∗=x. So,˜ the solution of variational inequality (.) is unique.

Remark . Using the characteristic inequality of the projection, we have

˘

x∈GVI(B,ψ,C) ⇐⇒ ψ(x) =˘ PC

ψ(x) –˘ νBx˘, ∀ν> .

Remark .

ψ(x) –μBxψ(y) –μBy ≤ ψ(x) –ψ(y) +μ(μ– α)BxBy.

In fact,

ψ(x) –μBxψ(y) –μBy

= ψ(x) –ψ(y) – μBxBy,ψ(x) –ψ(y)+μBxBy

ψ(x) –ψ(y) – μαBxBy+μBxBy

ψ(x) –ψ(y) +μ(μ– α)BxBy.

Next, we prove Theorem ..

Proof Letx. HencexGVI(B,ψ,C) andψ(x)EP(F,A). Sinceμ

n> , from Re-mark . we haveψ(x‡) =PC[ψ(x‡) –μnBx‡] for alln≥. Thus,

unψ

x‡ = PC

αnδϕ(xn) + ( –αn)

ψ(xn) –μnBxn

PC

ψx‡–μnBx

αn

δϕ(xn) –ψ

x‡+μnBx

+ ( –αn)

ψ(xn) –μnBxn

ψxμ

nBx

αn δϕ(xn) –δϕ

x‡ +αn δϕ

x‡–ψx‡+μnBx

+ ( –αn) ψ(xn) –μnBxn

ψx‡–μnBx

αnδL xnx‡ +αn δϕ

x‡–ψx‡+μnBx

+ ( –αn) ψ(xn) –ψ

x

αnδL/γ ψ(xn) –ψ

x‡ +αn δϕ

x‡–ψx‡+μnBx

+ ( –αn) ψ(xn) –ψ

x

= – ( –δL/γn ψ(xn) –ψ

x‡ +αn δϕ

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≤ – ( –δL/γn ψ(xn) –ψ

x

+αn δϕ

x‡–ψx‡ + α Bx‡ . (.)

By Algorithm ., we havezn=Tλn(I–λnA)unfor alln≥. Noting thatψ(x‡)∈EP(F,A), we deduceψ(x‡) =T

λn(I–λnA)ψ(x‡) for alln≥. It follows that ψ(xn+) –ψ

x‡ ≤βn ψ(xn) –ψ

x

+ ( –βn) Tλn(I–λnA)unTλn(I–λnA)ψ

x

βn ψ(xn) –ψ

x‡ + ( –βn) unψ

x

βn ψ(xn) –ψ

x

+ ( –βn)

 – ( –δL/γn ψ(xn) –ψ

x

+ ( –βnn δϕ

x‡–ψx‡ + α Bx

= – ( –δL/γ)( –βnn ψ(xn) –ψ

x

+ ( –δL/γ)( –βnn

δϕ(x) –ψ(x)+ αBx

 –δL/γ .

By induction

ψ(xn) –ψ

x‡ ≤max ψ(x) –ψ

x‡ ,δϕ(x

) –ψ(x)+ αBx

 –δL/γ

.

Hence, {ψ(xn)} is bounded. Since ψ is γ-strongly monotone, we can get (by a simi-lar technique as that in Remark .) γxnx‡ ≤ ψ(xn) –ψ(x‡). So, xnx‡ ≤

γψ(xn) –ψ(x

)

γ max{ψ(x) –ψ(x

),δϕ(x‡)–ψ(x‡)+αBx

–δL/γ }. This implies that{xn}

is bounded. Next, we showxn+–xn →. From Step  in Algorithm ., we have

F(zn,y) +λn

yzn,zn– (unλnAun)

≥, ∀yC.

Takingy=zn+, we get

F(zn,zn+) +  λn

zn+–zn,zn– (unλnAun)

≥.

Similarly, we also have

F(zn+,zn) +  λn+

znzn+,zn+– (un+–λn+Aun+)

≥.

Adding up the above two inequalities, we get

F(zn,zn+) +F(zn+,zn) +AunAun+,zn+–zn+

zn+–zn, znun

λn

zn+–un+ λn+

≥.

By the monotonicity ofF, we have

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So,

AunAun+,zn+–zn+

zn+–zn, znun

λn

zn+–un+ λn+

≥.

Thus,

λnAunAun+,zn+–zn+

zn+–zn,znzn++zn+–unλn λn+

(zn+–un+)

≥.

It follows that

zn+–zn≤λnAunAun+,zn+–zn

+

zn+–zn,un+–un+

 – λn λn+

(zn+–un+)

=(I–λnA)un+– (I–λnA)un,zn+–zn

+

zn+–zn,

 – λn λn+

(zn+–un+)

≤ (I–λnA)un+– (I–λnA)un zn+–zn

+ – λn λn+

zn+–znzn+–un+

zn+–zn

un+–un+  – λn

λn+

zn+–un+

and hence

zn+–znun+–un+  – λn

λn+

zn+–un+

un+–un+ 

a|λn+–λn|zn+–un+.

By Algorithm ., we have

un+–un= PC

αn+δϕ(xn+) + ( –αn+)

ψ(xn+) –μn+Bxn+

PC

αnδϕ(xn) + ( –αn)

ψ(xn) –μnBxn

αn+δϕ(xn+) + ( –αn+)

ψ(xn+) –μn+Bxn+

αnδϕ(xn) + ( –αn)

ψ(xn) –μnBxn

αn+δ ϕ(xn+) –ϕ(xn) +δ|αn+–αn| ϕ(xn)

+ ( –αn+) ψ(xn+) –μn+Bxn+–

ψ(xn) –μn+Bxn

+|αn+–αn| ψ(xn) +|μn+–μn| B(xn) +|αn+μn+–αnμn| B(xn)

αn+δLxn+–xn+ ( –αn+) ψ(xn+) –ψ(xn)

+|αn+–αn|

δ ϕ(xn) + ψ(xn) +|μn+–μn| B(xn)

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αn+(δL/γ) ψ(xn+) –ψ(xn) + ( –αn+) ψ(xn+) –ψ(xn)

+|αn+–αn|

δ ϕ(xn) + ψ(xn) +|μn+–μn| B(xn)

+|αn+μn+–αnμn| B(xn)

= – ( –δL/γn+ ψ(xn+) –ψ(xn)

+|αn+–αn|

δ ϕ(xn) + ψ(xn)

+|μn+–μn| B(xn) +|αn+μn+–αnμn| B(xn) .

Therefore,

zn+–zn

 – ( –δL/γn+ ψ(xn+) –ψ(xn)

+|αn+–αn|

δ ϕ(xn) + ψ(xn)

+|μn+–μn| B(xn) +|αn+μn+–αnμn| B(xn)

+

a|λn+–λn|zn+–un+.

It follows that

zn+–znψ(xn+) –ψ(xn) ≤ |αn+–αn|

δ ϕ(xn) + ψ(xn)

+|μn+–μn| B(xn) +|αn+μn+–αnμn| B(xn)

+

a|λn+–λn|zn+–un+.

Sincelimn→∞αn= ,limn→∞(μn+–μn) = ,limn→∞(λn+–λn) =  and the sequences

{ϕ(xn)},{ψ(xn)},{zn},{un}and{Bxn}are bounded, we have

lim sup

n→∞

zn+–znψ(xn+) –ψ(xn) ≤.

By Lemma ., we obtain

lim

n→∞ znψ(xn) = .

Hence,

lim

n→∞ ψ(xn+) –ψ(xn) =nlim→∞( –βn) znψ(xn) = .

This together with theγ-strong monotonicity ofψimplies that

lim

n→∞xn+–xn= .

By the convexity of the norm, we have

ψ(xn+) –ψ

x‡ 

= βn

ψ(xn) –ψ

x‡+ ( –βn)

znψ

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βn ψ(xn) –ψ

x‡ + ( –βn) znψ

x‡ 

βn ψ(xn) –ψ

x‡ + ( –βn) αn

δϕ(xn) –ψ

x‡+μnBx

+ ( –αn)

ψ(xn) –μnBxn

ψx‡–μnBx‡ 

βn ψ(xn) –ψ

x‡ + ( –βn)

αn δϕ(xn) –ψ

x‡+μnBx‡ 

+ ( –αn) ψ(xn) –μnBxn

ψx‡–μnBx‡ 

+ αn( –αn) δϕ(xn) –ψ

x+μ

nBxψ(xn) –μnBxn

ψxμ

nBx

βn ψ(xn) –ψ

x‡ 

+ ( –βn)( –αn) ψ(xn) –μnBxn

ψx‡–μnBx‡ 

+αnM, (.)

whereM>  is some constant. From Remark ., we derive ψ(xn)–μnBxn

ψx‡–μnBx‡ ≤ ψ(xn)–ψ

x‡ +μnn–α) Bxn–Bx‡ .

Thus,

ψ(xn+) –ψ

x‡ ≤βn ψ(xn) –ψ

x‡ + ( –βn)( –αn) ψ(xn) –ψ

x‡ 

+μnn– α) BxnBx‡ 

+αnM

ψ(xn) –ψ

x‡ 

+ ( –βn)( –αnnn– α) BxnBx‡ 

+αnM.

So,

( –βn)( –αnn(α–μn) BxnBx‡ 

ψ(xn) –ψ

x‡ – ψ(xn+) –ψ

x‡ +αnM

ψ(xn) –ψ

x‡ + ψ(xn+) –ψ

xψ(xn+) –ψ(xn) +αnM.

Sinceαn→,ψ(xn+) –ψ(xn) → andlim infn→∞( –βn)( –αnn(α–μn) > , we obtain

lim

n→∞ BxnBx

= .

Setyn=ψ(xn) –μnBxn– (ψ(x‡) –μnBx‡) for alln. By using the property of projection, we get

unψ

x‡  = PC

αnδϕ(xn) + ( –αn)

ψ(xn) –μnBxn

PC

ψx‡–μnBx‡ 

αn

δϕ(xn) –ψ

x‡+μnBx

+ ( –αn)yn,unψ

x

=   αn

δϕ(xn) –ψ

x‡+μnBx

+ ( –αn)yn

+ unψ

x‡ 

αn

δϕ(xn) –ψ

x‡+μnBx

+ ( –αn)ynun+ψ

x‡ 

≤ 

αn δϕ(xn) –ψ

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+ ( –αn) ψ(xn) –ψ

x‡ + unψ

x‡ 

αn

δϕ(xn) –ψ

x‡+μnBx‡–yn

+ψ(xn) –unμn

BxnBx‡ 

=  

αn δϕ(xn) –ψ

x‡+μnBx‡ 

+ ( –αn) ψ(xn) –ψ

x‡ + unψ

x‡ 

ψ(xn) –un

μn BxnBx

αnδϕ(xn) –ψ

x‡+μnBx‡–yn

+ μnαn

BxnBx‡,δϕ(xn) –ψ

x‡+μnBx‡–yn

+ μn

ψ(xn) –un,BxnBx

– αn

ψ(xn) –un,δϕ(xn) –ψ

x‡+μnBx‡–yn

. (.)

It follows that

unψ

x‡ ≤αn δϕ(xn) –ψ

x‡+μnBx‡ 

+ ( –αn) ψ(xn) –ψ

x‡ – ψ(xn) –un

+ μnαn BxnBxδϕ(xn) –ψ

x+μ

nBx‡–yn

+ μn ψ(xn) –un BxnBx

+ αn ψ(xn) –un δϕ(xn) –ψ

x‡+μnBx‡–yn . (.)

From (.) and (.), we have

ψ(xn+) –ψ

x‡ 

βn ψ(xn) –ψ

x‡ + ( –βn) unψ

x‡ 

βn ψ(xn) –ψ

x‡ + ( –βnn δϕ(xn) –ψ

x‡+μnBx‡ 

+ ( –αn)( –βn) ψ(xn) –ψ

x‡ – ( –βn) ψ(xn) –un

+ μn( –βnn BxnBxδϕ(xn) –ψ

x‡+μnBx‡–yn

+ μn( –βn) ψ(xn) –un BxnBx

+ ( –βnn ψ(xn) –un δϕ(xn) –ψ

x‡+μnBx‡–yn

ψ(xn) –ψ

x‡ +αn δϕ(xn) –ψ

x‡+μnBx‡ 

– ( –βn) ψ(xn) –un

+ μnαn BxnBxδϕ(xn) –ψ

x‡+μnBx‡–yn

+ μn ψ(xn) –un BxnBx

+ αn ψ(xn) –un δϕ(xn) –ψ

(11)

Then we obtain

( –βn) ψ(xn) –un

ψ(xn) –ψ

x‡ + ψ(xn+) –ψ

xψ(xn+) –ψ(xn)

+αn δϕ(xn) –ψ

x‡+μnBx‡ 

+ μnαn BxnBxδϕ(xn) –ψ

x‡+μnBx‡–yn

+ μn ψ(xn) –un BxnBx

+ αn ψ(xn) –un δϕ(xn) –ψ

x‡+μnBx‡–yn .

Sincelimn→∞αn= ,limn→∞ψ(xn+) –ψ(xn)=  andlimn→∞BxnBx‡= , we have

lim

n→∞ ψ(xn) –un = . (.)

Next, we provelim supn→∞δϕ(x∗) –ψ(x∗),un–ψ(x∗) ≤, wherex∗is the unique solution of (.). We take a subsequence{uni}of{un}such that

lim sup

n→∞

δϕx∗–ψx∗,unψ

x

=lim

i→∞

δϕx∗–ψx∗,uniψ

x

=lim

i→∞

δϕx∗–ψx∗,ψ(xni) –ψ

x∗. (.)

Since{xni}is bounded, there exists a subsequence{xnij}of{xni}which converges weakly to some pointzC. Without loss of generality, we may assume thatxniz. This implies

thatψ(xni) ψ(z) due to the weak continuity ofψ. Now, we showzS. We firstly show

z∈EP(F,A). Sincezn=Tλn(unλnAun), for anyyC, we have

F(zn,y) +λn

yzn,zn– (unλnAun)

≥.

From the monotonicity ofF, we have

λn

yzn,zn– (unλnAun)

F(y,zn), ∀yC.

Hence,

yzni,

zniuni

λni

+Auni

F(y,zni), ∀yC. (.)

Putvt=ty+ ( –t)zfor allt∈(, ] andyC. Then we havevtC. So, from (.) we have

vtzni,Avtvtzni,Avt

vtzni,

zniuni

λni

+Auni

+F(vt,zni)

=vtzni,AvtAzni+vtzni,AzniAuni

vtzni,

zniuni

λni

(12)

Note thatAzniAuni ≤

βzniuni →. Further, from the monotonicity ofA, we

havevtzni,AvtAzni ≥. Lettingi→ ∞in (.), we havevtz,AvtF(vt,z). This

together with (F), (F) implies that

 = F(vt,vt)≤tF(vt,y) + ( –t)F(vt,z)

tF(vt,y) + ( –t)vtz,Avt

=tF(vt,y) + ( –t)tyz,Avt,

and hence ≤F(vt,y) + ( –t)Avt,yz. Lettingt→, we have ≤F(z,y) +yz,Az. This implies thatz∈EP(F,A). Next, we only need to provez∈GVI(B,ψ,C). Set

Rv= ⎧ ⎨ ⎩

Bv+NC(v), vC,

∅, v∈/C.

By [], we know thatRis maximalψ-monotone. Let (v,w)G(R). SincewBvNC(v) and xnC, we haveψ(v) –ψ(xn),wBv ≥. Noting thatun=PCnδϕ(xn) + ( – αn)(ψ(xn) –μnBxn)], we get

ψ(v) –un,un

αnδϕ(xn) + ( –αn)

ψ(xn) –μnBxn

≥.

It follows that

ψ(v) –un,

unψ(xn) μn

+Bxnαn μn

δϕ(xn) –ψ(xn) +μnBxn

≥.

Then

ψ(v) –ψ(xni),w

ψ(v) –ψ(xni),Bv

ψ(v) –ψ(xni),Bv

ψ(v) –uni,

uniψ(xni)

μni

ψ(v) –uni,Bxni

+αni

μni

ψ(v) –uni,δϕ(xni) –ψ(xni) +μniBxni

=ψ(v) –ψ(xni),BvBxni

+ψ(v) –ψ(xni),Bxni

ψ(v) –uni,

uniψ(xni)

μni

ψ(v) –uni,Bxni

+αni

μni

ψ(v) –uni,δϕ(xni) –ψ(xni) +μniBxni

≥–

ψ(v) –uni,

uniψ(xni)

μni

ψ(xni) –uni,Bxni

+αni

μni

ψ(v) –uni,δϕ(xni) –ψ(xni) +μniBxni

. (.)

Since ψ(xni) –uni → and ψ(xni) ψ(z), we deduce thatψ(v) –ψ(z),w ≥ by

(13)

z∈GVI(B,ψ,C). Therefore,zS. From (.), we obtain

lim sup

n→∞

δϕx∗–ψx∗,unψ

x

=lim

i→∞

δϕx∗–ψx∗,ψ(xni) –ψ

x

=δϕx∗–ψx∗,ψ(z) –ψx∗≤.

Note that

unψ

x∗ ≤αn

δϕ(xn) –ψ

x∗+ ( –αn)yn,unψ

x

αnδ

ϕ(xn) –ϕ

x∗,unψ

x∗+αn

δϕx∗–ψx∗,unψ

x

+ ( –αn) ψ(xn) –μnBxn

ψx∗–μnBxunψ

x

αnLδ xnxunψ

x∗ +αn

δϕx∗–ψx∗,unψ

x

+ ( –αn) ψ(xn) –ψ

xunψ

x

αn(δL/γ) ψ(xn) –ψ

xunψ

x

+αn

δϕx∗–ψx∗,unψ

x

+ ( –αn) ψ(xn) –ψ

xunψ

x

= – ( –Lδ/γn ψ(xn) –ψ

xunψ

x

+αn

δϕx∗–ψx∗,unψ

x

=  – ( –Lδ/γn

ψ(xn) –ψ

x∗ +  unψ

x∗ 

+αn

δϕx∗–ψx∗,unψ

x‡.

It follows that

unψ

x∗ ≤ – ( –Lδ/γn ψ(xn) –ψ

x∗ 

+ αn

δϕx∗–ψx∗,unψ

x∗.

Therefore,

ψ(xn+) –ψ

x∗ ≤βn ψ(xn) –ψ

x∗ + ( –βn) unψ

x∗ 

βn ψ(xn) –ψ

x∗ 

+ ( –βn)

 – ( –δL/γn ψ(xn) –ψ

x∗ 

+ ( –βnn

δϕx∗–ψx∗,unψ

x

= – ( –δL/γ)( –βnn ψ(xn) –ψ

x∗ 

+ ( –βnn

δϕx∗–ψx∗,unψ

x

= – ( –δL/γ)( –βnn ψ(xn) –ψ

x∗ 

(14)

×αn

  –δL/γ

δϕx∗–ψx∗,unψ

x

= ( –γn) ψ(xn) –ψ

x∗ +δnγn,

whereγn= ( –δL/γ)( –βnnandδn=–δL/γδϕ(x∗) –ψ(x∗),unψ(x∗). It is easily seen

thatnγn=∞andlim supn→∞δn≤. We can therefore apply Lemma . to conclude thatψ(xn)→ψ(x∗) andxnx∗. This completes the proof.

Competing interests

The authors declare that they have no competing interests.

Authors’ contributions

All authors read and approved the final manuscript.

Author details

1Department of Mathematics, Tianjin Polytechnic University, Tianjin, 300387, China.2Department of Information Management, Cheng Shiu University, Kaohsiung, 833, Taiwan.

Acknowledgements

Yonghong Yao was supported in part by NSFC 11071279 and NSFC 71161001-G0105. Rudong Chen was supported in part by NSFC 11071279. Yeong-Cheng Liou was supported in part by NSC 101-2628-E-230-001-MY3 and NSC 101-2622-E-230-005-CC3.

Received: 11 October 2012 Accepted: 14 May 2013 Published: 29 May 2013 References

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