R E S E A R C H
Open Access
A general iterative method for two maximal
monotone operators and 2-generalized
hybrid mappings in Hilbert spaces
Rabian Wangkeeree
*and Uraiwan Boonkong
*Correspondence:
[email protected] Department of Mathematics, Faculty of Science, Naresuan University, Phitsanulok, 65000, Thailand
Abstract
LetCbe a closed and convex subset of a real Hilbert spaceH. LetTbe a 2-generalized hybrid mapping ofCinto itself, letAbe an
α
-inverse strongly-monotone mapping ofCintoH, and letBandFbe maximal monotone operators onD(B)⊂CandD(F)⊂C
respectively. The purpose of this paper is to introduce a general iterative scheme for finding a point ofF(T)∩(A+B)–10∩F–10 which is a unique solution of a hierarchical variational inequality, whereF(T) is the set of fixed points ofT, (A+B)–10 andF–10 are the sets of zero points ofA+BandF, respectively. A strong convergence theorem is established under appropriate conditions imposed on the parameters. Further, we consider the problem for finding a common element of the set of solutions of a mathematical model related to mixed equilibrium problems and the set of fixed points of a 2-generalized hybrid mapping in a real Hilbert space.
Keywords: 2-generalized hybrid mapping; inverse strongly monotone mapping; maximal monotone mapping; hierarchical variational inequality
1 Introduction
LetHbe a Hilbert space, and letCbe a nonempty closed convex subset ofH. LetNandR be the sets of all positive integers and real numbers, respectively. Letϕ:C→Rbe a real-valued function, and letf :C×C→Rbe an equilibrium bifunction, that is,f(u,u) = for eachu∈C. The mixed equilibrium problem is to findx∈Csuch that
f(x,y) +ϕ(y) –ϕ(x)≥ for ally∈C. (.)
Denote the set of solutions of (.) byMEP(f,ϕ). In particular, ifϕ= , this problem re-duces to the equilibrium problem, which is to findx∈Csuch that
f(x,y)≥ for ally∈C. (.)
The set of solutions of (.) is denoted byEP(f). The problem (.) is very general in the sense that it includes, as special cases, optimization problems, variational inequalities, min-max problems, the Nash equilibrium problems in noncooperative games and others; see, for example, Blum-Oettli [] and Moudafi []. Numerous problems in physics, opti-mization and economics reduce to finding a solution of the problem (.).
LetT be a mapping ofCintoC. We denote byF(T) :={x∈C:Tx=x}the set of fixed points ofT. A mappingT:C→Cis said to be nonexpansive ifTx–Ty ≤ x–yfor all x,y∈C. The mappingT:C→Cis said to be firmly nonexpansive if
Tx–Ty≤ x–y,Tx–Ty for allx,y∈C; (.)
see, for instance, Browder [] and Goebel and Kirk []. The mappingT:C→Cis said to be firmly nonspreading [] if
Tx–Ty≤ Tx–y+x–Ty (.)
for allx,y∈C. Iemoto and Takahashi [] proved thatT:C→Cis nonspreading if and only if
Tx–Ty≤ x–y+ x–Tx,y–Ty (.)
for allx,y∈C. It is not hard to know that a nonspreading mapping is deduced from a firmly nonexpansive mapping; see [, ] and a firmly nonexpansive mapping is a nonexpansive mapping.
In , Kocoureket al.[] introduced a class of nonlinear mappings, say generalized hybrid mappings. A mappingT:C→Cis said to be generalized hybrid if there areα,β∈
Rsuch that
αTx–Ty+ ( –α)x–Ty≤βTx–y+ ( –β)x–y (.) for allx,y∈C. We call such a mapping an (α,β)-generalized hybrid mapping. We ob-serve that the mappings above generalize several well-known mappings. For example, an (α,β)-generalized hybrid mapping is nonexpansive forα= andβ= , nonspreading for
α= andβ= , and hybrid forα=andβ=.
Recently, Maruyamaet al.[] defined a more general class of nonlinear mappings than the class of generalized hybrid mappings. Such a mapping is a -generalized hybrid map-ping. A mappingTis called -generalized hybrid if there existα,α,β,β∈Rsuch that
αTx–Ty
+αTx–Ty+ ( –α–α)x–Ty
≤βTx–y+βTx–y+ ( –β–β)x–y (.)
for all x,y∈C; see [] for more details. We call such a mapping an (α,α,β,β
)-generalized hybrid mapping. We can also show that ifTis a -generalized hybrid mapping andx=Tx, then for anyy∈C,
αx–Ty+αx–Ty+ ( –α–α)x–Ty
≤βx–y+βx–y+ ( –β–β)x–y,
generalize several well-known mappings. For example, a (,α, ,β)-generalized hybrid
mapping is an (α,β)-generalized hybrid mapping in the sense of Kocoureket al.[].
Recall that a linear bounded operatorBis strongly positive if there is a constantγ¯> with the property
Vx,x ≥ ¯γx for allx∈H. (.)
In general, a nonlinear operatorV :H→H is called strongly monotone if there exists
¯
γ > such that
x–y,Vx–Vy ≥ ¯γx–y for allx,y∈H. (.) SuchV is calledγ¯-strongly monotone. A nonlinear operatorV:H→His called Lips-chitzian continuous if there existsL> such that
Vx–Vy ≤Lx–y for allx,y∈H. (.)
SuchVis calledL-Lipschitzian continuous. A mappingA:C→His said to beα -inverse-strongly monotone if x–y,Ax–Ay ≥αAx–Ayfor allx,y∈C. It is known thatAx–
Ay ≤(α)x–yfor allx,y∈CifAisα-inverse-strongly monotone; see, for example, [–].
Many studies have been done for structuring the fixed point of a nonexpansive map-pingT. In , Mann [] introduced the iteration as follows: a sequence{xn}defined
by
xn+=αnxn+ ( –αn)Txn, (.)
where the initial guessx∈Cis arbitrary and{αn}is a real sequence in [, ]. It is known
that under appropriate settings the sequence{xn}converges weakly to a fixed point ofT.
However, even in a Hilbert space, Mann iteration may fail to converge strongly; for ex-ample, see []. Some attempts to construct an iteration method guaranteeing the strong convergence have been made. For example, Halpern [] proposed the so-called Halpern iteration
xn+=αnu+ ( –αn)Txn, (.)
whereu,x∈Care arbitrary and{αn}is a real sequence in [, ] which satisfiesαn→,
∞
n=αn=∞and
∞
n=|αn–αn+|<∞. Then{xn}converges strongly to a fixed point ofT;
see [, ].
In , Baillon [] first introduced the nonlinear ergodic theorem in a Hilbert space as follows:
Snx=
n
n–
k=
Tkx (.)
Theorem . Let C be a nonempty,closed and convex subset of a Hilbert space H.Let T:
C→C be a-generalized hybrid mapping with F(T)=∅.Suppose that{xn}is a sequence
generated by x=x∈C,u∈C and
xn+=γnu+ ( –γn)
n
n–
k=
Tkxn, ∀n∈N, (.)
where≤γn≤,limn→∞γn= and
∞
n=γn=∞.Then{xn}converges strongly to PF(T)u.
LetBbe a mapping ofH into H. The effective domain ofBis denoted byD(B), that
is, D(B) ={x∈H:Bx=∅}. A multi-valued mappingBonH is said to be monotone if x–y,u–v ≥ for allx,y∈D(B),u∈Bx, andv∈By. A monotone operatorBonHis said to be maximal if its graph is not properly contained in the graph of any other monotone operator on H. For a maximal monotone operatorBonH andr> , we may define a single-valued operatorJr= (I+rB)–:H→D(B), which is called the resolvent ofBforr.
We denote byAr=r(I–Jr) the Yosida approximation ofBforr> . We know [] that
Arx∈BJrx, ∀x∈H,r> . (.)
LetBbe a maximal monotone operator onH, and letB– ={x∈H: ∈Bx}. It is known
that the resolventJris firmly nonexpansive andB– =F(Jr) for allr> ,i.e.,
Jrx–Jry ≤ x–y,Jrx–Jry, ∀x,y∈H. (.)
Recently, in the case whenT :C→C is a nonexpansive mapping,A:C→H is an
α-inverse strongly monotone mapping andB∈H ×H is a maximal monotone oper-ator, Takahashiet al. [] proved a strong convergence theorem for finding a point of F(T)∩(A+B)–, whereF(T) is the set of fixed points ofT and (A+B)– is the set
of zero points ofA+B. In , for finding a point of the set of fixed points ofT and the set of zero points ofA+Bin a Hilbert space, Manaka and Takahashi [] introduced an iterative scheme as follows:
xn+=βnxn+ ( –βn)T
Jλn(I–λnA)xn
, (.)
whereT is a nonspreading mapping,Ais anα-inverse strongly monotone mapping and Bis a maximal monotone operator such thatJλ= (I–λB)–;{βn}and{λn}are sequences
which satisfy <c≤βn≤d< and <a≤λn≤b< α. Then they proved that{xn}
converges weakly to a pointp=limn→∞PF(T)∩(A+B)–()xn.
scheme: ⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩
x=x∈H arbitrarily,
zn=Jλn(I–λnA)xn, yn=nnk=–Tkzn,
xn+=αnu+ ( –αn)yn for alln∈N,
(.)
where{αn}is an appropriate sequence in [, ]. They obtained strong convergence
theo-rems about a common element of the set of fixed points of a nonspreading mapping and the set of zero points of anα-inverse strongly monotone mapping and a maximal mono-tone operator in a Hilbert space.
On the other hand, iterative methods for nonexpansive mappings have recently been ap-plied to solve convex minimization problems; see,e.g., [–] and the references therein. Convex minimization problems have a great impact and influence on the development of almost all branches of pure and applied sciences. A typical problem is to minimize a quadratic function over the set of fixed points a nonexpansive mapping on a real Hilbert space:
θ(x) =min
x∈C
Vx,x– x,b, (.)
whereV is a linear bounded operator,C is the fixed point set of a nonexpansive map-pingT andbis a given point inH. LetHbe a real Hilbert space. In [], Marino and Xu introduced the following general iterative scheme based on the viscosity approximation method introduced by Moudafi []:
xn+= (I–αnV)Txn+αnγf(xn), n≥, (.)
where V is a strongly positive bounded linear operator on H. They proved that if the sequence{αn}of parameters satisfies appropriate conditions, then the sequence{xn}
gen-erated by (.) converges strongly to the unique solution of the variational inequality
(V–γf)x∗,x–x∗≥, x∈C,
which is the optimality condition for the minimization problem
min
x∈C
Vx,x–h(x), (.)
wherehis a potential function forγf (i.e.,h(x) =γf(x) forx∈H).
Recently, Tian [] introduced the following general iterative scheme based on the vis-cosity approximation method induced by a γ¯-strongly monotone and aL-Lipschitzian continuous operatorV onH
xn+=αnγg(xn) + (I–μαnV)Txn,
for alln∈N, whereμ,γ ∈Rsatisfying <μ<Lγ¯, <γ <μ(γ¯–
Lμ
)/k,gis ak-contraction
on the parameters, in [] that{xn}converges strongly to a pointp∈F(T) which is a
unique solution of the variational inequality
(V–γg)p,q–p
≥, ∀q∈F(T).
Very recently, Lin and Takahashi [] obtained the strong convergence theorem for find-ing a pointp∈(A+B)–∩F– which is a unique solution of a hierarchical variational
inequality, whereAis anα-inverse strongly-monotone mapping ofCintoH, andBand Fare maximal monotone operators onD(B)⊂CandD(F)⊂C, respectively. More pre-cisely, they introduced the following iterative scheme: Letx=x∈Hand let{xn} ⊂Hbe
a sequence generated
xn+=αnγg(xn) + (I–αnV)Jλn(I–λnA)Trnxn for alln∈N, (.) where{αn} ⊂(, ),{λn} ⊂(,∞) and{rn} ⊂(,∞) satisfy certain appropriate conditions,
Jλ= (I+λB)–andTr= (I+rF)–are the resolvents ofBforλ> andFforr> ,
respec-tively.
In this paper, motivated by the mentioned results, letCbe a closed and convex subset of a real Hilbert spaceH. LetTbe a -generalized hybrid mapping ofCinto itself, letA be anα-inverse strongly-monotone mapping ofCinto H, and letBandF be maximal monotone operators onD(B)⊂CandD(F)⊂Crespectively. We introduce a new gen-eral iterative scheme for finding a common element ofF(T)∩(A+B)–∩F– which
is a unique solution of a hierarchical variational inequality, whereF(T) is the set of fixed points ofT, (A+B)– andF– are the sets of zero points ofA+BandF, respectively.
Then, we prove a strong convergence theorem. Further, we consider the problem for find-ing a common element of the set of solutions of a mathematical model related to mixed equilibrium problems and the set of fixed points of a -generalized hybrid mapping in a real Hilbert space.
2 Preliminaries
LetHbe a real Hilbert space with the inner product ·,·and the norm · , respectively. LetCbe a nonempty closed convex subset ofH. The nearest point projection ofHonto Cis denoted byPC, that is,x–PCx ≤ x–yfor allx∈Handy∈C. SuchPCis called
the metric projection ofHontoC. We know that the metric projectionPCis firmly
non-expansive,i.e.,
PCx–PCy≤ PCx–PCy,x–y (.)
for allx,y∈H. Furthermore, PCx–PCy,x–y ≤ holds for allx∈Handy∈C; see [].
Letα> be a given constant.
We also know the following lemma from [].
Lemma . Let H be a real Hilbert space, and let B be a maximal monotone operator
on H.For r> and x∈H,define the resolvent Jrx.Then the following holds:
s–t
s Jsx–Jtx,Jsx–x ≥ Jsx–Jtx
for all s,t> and x∈H.
From Lemma ., we have that
Jλx–Jμx ≤
|λ–μ|/λx–Jλx (.)
for allλ,μ> andx∈H; see also [, ]. To prove our main result, we need the following lemmas.
Remark . It is not hard to know that ifAis anα-inverse strongly monotone mapping, then it isα -Lipschitzian and hence uniformly continuous. Clearly, the class of monotone mappings includes the class ofα-inverse strongly monotone mappings.
Remark . It is well known that ifT:C→Cis a nonexpansive mapping, thenI–Tis
-inverse strongly monotone, whereIis the identity mapping onH; see, for instance, [].
It is known that the resolventJris firmly nonexpansive andB– =F(Jr) for allr> .
Lemma .[] Let H be a real Hilbert space,and let C be a nonempty closed convex
subset of H.Letα> .Let A be anα-inverse strongly monotone mapping of C into H,and let B be a maximal monotone operator on H such that the domain of B is included in C. Let Jλ= (I+λB)–be the resolvent of B for anyλ> .Then the following hold:
(i) ifu,v∈(A+B)–(),thenAu=Av;
(ii) for anyλ> ,u∈(A+B)–()if and only ifu=J
λ(I–λA)u.
Lemma .[, ] Let{an} be a sequence of nonnegative real numbers satisfying the
property
an+≤( –tn)an+bn+tncn,
where{tn},{bn}and{cn}satisfy the restrictions: (i) ∞n=tn=∞;
(ii) ∞n=bn<∞; (iii) lim supn→∞cn≤.
Then{an}converges to zero as n→ ∞.
Lemma .[] Let H be a Hilbert space,and let g:H→H be a k-contraction with
<k< .Let V be aγ¯-strongly monotone and L-Lipschitzian continuous operator on H withγ¯> and L> .Let a real numberγ satisfy <γ <γk¯.Then V–γg:H→H is a (γ¯–γk)-strongly monotone and(L+γk)-Lipschitzian continuous mapping.Furthermore, let C be a nonempty closed convex subset of H.Then PC(I–V +γg)has a unique fixed
point zin C.This point z∈C is also a unique solution of the variational inequality
(V–γf)z,q–z
≥, ∀q∈C.
3 Main results
Theorem . Let H be a real Hilbert space,and let C be a nonempty,closed and convex subset of H.Letα> and A be anα-inverse-strongly monotone mapping of C into H.Let the set-valued maps B:D(B)⊂C→H and F:D(F)⊂C→H be maximal monotone.Let
Jλ= (I+λB)–and Tr= (I+rF)–be the resolvents of B forλ> and F for r> ,respectively.
Let <k< and let g be a k-contraction of H into itself.Let V be aγ¯-strongly monotone and L-Lipschitzian continuous operator withγ¯> and L> .Let T:C→C be a-generalized hybrid mapping such that:=F(T)∩(A+B)–∩F–=∅.Takeμ,γ∈Ras follows:
<μ<γ¯
L, <γ <
¯
γ–Lμ k .
Let the sequence{xn} ⊂H be generated by
⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩
x=x∈H arbitrarily,
zn=Jλn(I–λnA)Trnxn, yn=n
n– k=Tkzn,
xn+=αnγg(xn) + (I–αnV)yn, ∀n= , , . . . ,
(.)
where the sequences{αn},{λn}and{rn}satisfy the following restrictions: (i) {αn} ⊂[, ],limn→∞αn= and
∞
n=αn=∞;
(ii) there exist constantsaandbsuch that <a≤λn≤b< αfor alln∈N; (iii) lim infn→∞rn> .
Then{xn}converges strongly to a point pof,where pis a unique fixed point of P(I–V+
γg).This point p∈is also a unique solution of the hierarchical variational inequality
(V–γg)p,q–p
≥, ∀q∈. (.)
Proof First we prove that{xn}is bounded andlimn→∞xn–pexists for allp∈. Let
p∈, we have thatp=Jλn(I–λnA)pandp=Trnp. Puttingun=Trnxn, we have that
zn–p=Jλn(I–λnA)Trnxn–Jλn(I–λnA)p
≤(Trnxn–Trnp) –λn(ATrnxn–ATrnp)
=Trnxn–Trnp
– λ
n un–p,Aun–Ap+λnAun–Ap ≤ un–p– λnαAun–Ap+λnAun–Ap
≤ xn–p–λn(α–λn)Aun–Ap
≤ xn–p. (.)
This together with quasi-nonexpansiveness ofTimplies that
yn–p=
n
n–
k=
Tkzn–p
≤
n
n–
k=
≤
n
n–
k=
zn–p
=zn–p ≤ xn–p. (.)
Therefore, we have
xn+–p=αn
γg(xn) –Vp
+ (I–αnV)yn– (I–αnV)p ≤αnγg(xn) –Vp+(I–αnV)yn– (I–αnV)p
≤αnγkxn–p+αnγg(p) –Vp+(I–αnV)yn– (I–αnV)p. (.)
Puttingτ=γ¯–Lμ, we can calculate the following:
(I–αnV)yn– (I–αnV)p =(yn–p) –αn(Vyn–Vp)
=yn–p– αn yn–p,Vyn–Vp+αnVyn–Vp ≤ yn–p– αnγ¯yn–p+αnLyn–p
= – αnγ¯+αnL
yn–p
= – αnτ–αnLμ+αnL
yn–p ≤ – αnτ–αn
Lμ–αnL
+αnτyn–p ≤ – αnτ+αnτ
yn–p
= ( –αnτ)yn–p. (.)
Since –αnτ> , we obtain that
(I–αnV)yn– (I–αnV)p≤( –αnτ)yn–p.
Therefore, by (.), we have
xn+–p ≤αnγkxn–p+αnγg(p) –Vp+ ( –αnτ)yn–p ≤αnγkxn–p+αnγg(p) –Vp+ ( –αnτ)xn–p
= –αn(τ–γk)
xn–p+αnγg(p) –Vp
= –αn(τ–γk)
xn–p+αn(τ–γk)
γg(p) –Vp
τ–γk
≤max
xn–p,
γg(p) –Vp
τ–γk
for alln∈N,
which yields that the sequence{xn–p}is bounded, so are{xn},{yn},{Vyn},{g(xn)}and {Tnz
n}. Using Lemma ., we can take a uniquep∈ of the hierarchical variational
inequality
(V–γg)p,q–p
We show thatlim supn→∞ (V–γg)p,xn–p ≥. We may assume, without loss of
gen-erality, that there exists a subsequence{xnk}of{xn}converging tow∈C, ask→ ∞, such that
lim sup
n→∞
(V–γg)p,xn–p
= lim
k→∞
(V–γg)p,xnk–p
.
Since {xnk –p} is bounded, there exists a subsequence {xnki} of {xnk} such that limi→∞xnki–pexists. Now we shall prove thatw∈.
(a) We first provew∈F(T). We notice that
xn+–yn=αnγg(xn) + (I–αnV)yn–yn=αnγg(xn) –Vyn.
In particular, replacingnbynkiand takingi→ ∞in the last equality, we have
lim
i→∞xnki+–ynki= ,
so we haveynkiw. SinceTis -generalized hybrid, there existα,α,β,β∈Rsuch that
αTx–Ty+αTx–Ty+ ( –α–α)x–Ty
≤βTx–y+βTx–y+ ( –β–β)x–y
for allx,y∈C. For anyn∈Nandk= , , , . . . ,n– , we compute the following:
≤βTTkzn–y
+βTTkzn–y
+ ( –β–β)Tkzn–y
–αTTkzn–Ty–αTTkzn–Ty– ( –α–α)Tkzn–Ty
=βTk+zn–y+βTk+zn–y+ ( –β–β)Tkzn–y
–αTk+zn–Ty
–αTk+zn–Ty
– ( –α–α)Tkzn–Ty
≤βTk+zn–Ty
+Ty–y+βTk+zn–Ty
+Ty–y
+ ( –β–β)Tkzn–Ty
+Ty–y–αTk+zn–Ty
–αTk+zn–Ty
– ( –α–α)Tkzn–Ty
=βTk+zn–Ty
+Ty–y+ Tk+zn–Ty,Ty–y
+βTk+zn–Ty
+Ty–y+ Tk+zn–Ty,Ty–y
+ ( –β–β)Tkzn–Ty+Ty–y+
Tkzn–Ty,Ty–y
–αTk+zn–Ty–αTk+zn–Ty– ( –α–α)Tkzn–Ty
= (β–α)Tk+zn–Ty
+ (β–α)Tk+zn–Ty
+ (α+α–β–β)Tkzn–Ty
×(β+β+ –β–β)Ty–y+
βTk+zn–βTy+βTk+zn–βTy
+ ( –β–β)Tkzn– ( –β–β)Ty,Ty–y
= (β–α)Tk+zn–Ty
–(β–α) + (α–β)Tkzn–Ty
+Ty–y
+ βTk+zn+βTk+zn+ ( –β–β)Tkzn–Ty,Ty–y
= (β–α)Tk+zn–Ty–Tkzn–Ty
+ (β–α)Tk+zn–Ty
–Tkzn–Ty
+Ty–y+ βTk+zn+βTk+zn+ ( –β–β)Tkzn–Ty,Ty–y
=Ty–y+ Tkzn–Ty,Ty–y
+ β
Tk+zn–Tkxn
+β
Tk+zn–Tkzn
,Ty–y
+ (β–α)Tk+zn–Ty–Tkzn–Ty
+ (β–α)Tk+zn–Ty–Tkzn–Ty
.
Summing up these inequalities fromk= ton– , we get
≤
n–
k=
Ty–y+ n–
k=
Tkzn–Ty
,Ty–y
+ β n– k=
Tk+zn–Tkzn
+β
n–
k=
Tk+zn–Tkzn
,Ty–y
+ (β–α) n–
k=
Tk+z n–Ty
–Tkzn–Ty
+ (β–α) n–
k=
Tk+zn–Ty
–Tkzn–Ty
=nTy–y+ n–
k=
Tkzn–nTy,Ty–y
+ β
Tn+zn–Tnzn–zn–Tzn
+β
Tnzn–zn
,Ty–y
+ (β–α)Tn+zn–Ty+Tnzn–Ty–zn–Ty–Tzn–Ty
+ (β–α)Tnzn–Ty–zn–Ty
.
Dividing this inequality byn, we get
≤ Ty–y+ yn–Ty,Ty–y
+
nβ
Tn+zn–Tnzn–zn–Tzn
+
nβ
Tnzn–zn
,Ty–y
+
n(β–α)T
n+z n–Ty
+Tnzn–Ty
–zn–Ty–Tzn–Ty
+
n(β–α)T
nz n–Ty
–zn–Ty
.
Replacingnbynkiand lettingi→ ∞in the last inequality, we have
In particular, replacingybywin (.), we obtain that
≤ Tw–w+ w–Tw,Tw–w= –Tw–w,
which ensures thatw∈F(T).
(b) We prove thatw∈(A+B)–. From (.), (.) and (.), we have
xn+–p≤(I–αnV)yn– (I–αnV)p
+ αn
γg(xn) –Vp,xn+–p
≤( –αnτ)yn–p+ αn
γg(xn) –Vp,xn+–p
≤( –αnτ)zn–p+ αn
γg(xn) –Vp,xn+–p
≤( –αnτ)
xn–p–λn(α–λn)Aun–Ap
+ αn
γg(xn) –Vp,xn+–p
= – αnτ+αnτ
xn–p– ( –αnτ)λn(α–λn)Aun–Ap
+ αn
γg(xn) –Vp,xn+–p
≤ xn–p+αnτxn–p– ( –αnτ)λn(α–λn)Aun–Ap
+ αn
γg(xn) –Vp,xn+–p
, (.)
and hence
( –αnτ)λn(α–λn)Aun–Ap≤ xn–p–xn+–p+αnτxn–p
+ αn
γg(xn) –Vp,xn+–p
. (.)
Replacingnbynkiin (.), we have
( –αnkiτ)λnki(α–λnki)Aunki–Ap
≤ xnki–p–xnki+–p+αnkiτxnki–p
+ αnki
γg(xn) –Vp,xnki+–p
.
Sincelimn→∞αn= , <a≤λn≤b< αand the existence oflimi→∞xnki–p, we have
lim
i→∞Aunki–Ap= . (.)
We also have from (.) that
un–p = Trnxn–Trnp
≤ xn–p,un–p
=xn–p+un–p–un–xn,
and hence
From (.), (.), (.) and (.), we obtain the following:
xn+–p≤(I–αnV)yn– (I–αnV)p
+ αn
γg(xn) –Vp,xn+–p
≤( –αnτ)yn–p+ αn
γg(xn) –Vp,xn+–p
≤( –αnτ)zn–p+ αn
γg(xn) –Vp,xn+–p
≤( –αnτ)
un–p–λn(α–λn)Aun–Ap
+ αn
γg(xn) –Vp,xn+–p
≤( –αnτ)
xn–p–un–xn
– ( –αnτ)λn(α–λn)Aun–Ap
+ αn
γg(xn) –Vp,xn+–p
≤ – αnτ+αnτ
xn–p– ( –αnτ)un–xn
– ( –αnτ)λn(α–λn)Aun–Ap
+ αn
γg(xn) –Vp,xn+–p
≤ xn–p+αnτxn–p– ( –αnτ)un–xn
– ( –αnτ)λn(α–λn)Aun–Ap
+ αn
γg(xn) –Vp,xn+–p
,
and hence
( –αnτ)un–xn≤ xn–p–xn+–p+αnτxn–p
– ( –αnτ)λn(α–λn)Aun–Ap
+ αn
γg(xn) –Vp,xn+–p
. (.)
Replacingnbynkiin (.), we have
( –αnkiτ)unki–xnki≤ xnki–p–xnki+–p+αnkiτxnki–p
– ( –αnkiτ)λnki(α–λnki)Aunki–Ap
+ αnki
γg(xnki) –Vp,xnki+–p
.
From (.),limn→∞αn= and the existence oflimi→∞xnki–p, we have
lim
i→∞unki–xnki= . (.)
On the other hand, sinceJλnis firmly nonexpansive andun=Trnxn, we have that
zn–p=Jλn(I–λnA)un–Jλn(I–λnA)p
≤zn–p, (I–λnA)un– (I–λnA)p
=
–zn–p– (I–λnA)un+ (I–λnA)p
≤
zn–p+un–p–zn–p– (I–λnA)un+ (I–λnA)p
≤
zn–p+xn–p–zn–un– λn zn–un,Aun–Ap
–λnAun–Ap
,
and hence
zn–p
≤ xn–p–zn–un– λn zn–un,Aun–Ap–λnAun–Ap. (.)
From (.), (.), (.) and (.), we have
xn+–p≤(I–αnV)yn– (I–αnV)p
+ αn
γg(xn) –Vp,xn+–p
≤( –αnτ)yn–p+ αn
γg(xn) –Vp,xn+–p
≤( –αnτ)zn–p+ αn
γg(xn) –Vp,xn+–p
≤( –αnτ)
xn–z–zn–un– λn zn–un,Aun–Ap
–λnAun–Ap
+ αn
γg(xn) –Vp,xn+–p
≤ xn–p+αnτxn–p– ( –αnτ)zn–un
– ( –αnτ)λn(λn– α)zn–unAun–Ap
– ( –αnτ)λnAun–Ap+ αn
γg(xn) –Vp,xn+–p
,
and hence
( –αnτ)zn–un
≤ xn–p–xn+–p+αnτxn–p
– ( –αnτ)λn(λn– α)zn–unAun–Ap
– ( –αnτ)λnAun–Ap+ αn
γg(xn) –Vp,xn+–p
. (.)
Replacingnbynkiin (.), we have
( –αnkiτ)znki–unki
≤ xnki–p–xnki+–p+αnkiτxnki–p
– ( –αnkiτ)λnki(λnki– α)znki–unkiAunki–Ap
– ( –αnkiτ)λnkiAunki–Ap+ αnki
γg(xnki) –Vp,xnki+–p
.
From (.),limn→∞αn= and the existence oflimi→∞xnki–p, we obtain that
lim
Sinceznki–xnki ≤ znki–unki+unki–xnki, by (.) and (.), we obtain that
lim
i→∞znki–xnki= . (.)
SinceAis Lipschitz continuous, we also obtain
lim
i→∞Aznki–Axnki= . (.)
Sincezn=Jλ(I–λA)un, we have that
zn = (I+λnB)–(I–λnA)un
⇔ (I–λnA)un∈(I+λnB)zn=zn+λnBzn ⇔ un–zn–λnAun∈λnBzn
⇔
λn
(un–zn–λnAun)∈Bzn.
SinceBis monotone, we have that for (u,v)∈B,
zn–u,
λn
(un–zn–λnAun) –v
≥,
and hence
zn–u,un–zn–λn(Aun+v)
≥. (.)
Replacingnbynkiin (.), we have that
znki–u,unki–znki–λnki(Aunki+v)
≥. (.)
Sincexnkiwandxnki–unki→, sounkiw. From (.), we get thatznkiw, together
with (.), we have that
w–u, –Aw–v ≥.
SinceBis maximal monotone, (–Aw)∈Bw, that is,w∈(A+B)–.
(c) Next, we show that w∈F–. SinceF is a maximal monotone operator, we have
from (.) thatArnkixnki∈FTrnkixnki, whereAris the Yosida approximation ofFforr> .
Furthermore, we have that for any (u,v)∈F,
u–unki,v–
xnki–unki
rnki
≥.
Sincelim infn→∞rn> ,unkiwandxnki–unki→, we have
SinceFis a maximal monotone operator, we have ∈Fw, that is,w∈F–. By (a), (b) and
(c), we conclude that
w∈F(T)∩(A+B)–∩F–.
Using (.), we obtain
lim sup
n→∞
(V–γg)p,xn–p
= lim
k→∞
(V–γg)p,xnk–p)
=(V–γg)p,w–p)
≥.
Finally, we prove thatxn→p. Notice that
xn+–p=αn
γg(xn) –p
+ (I–αnV)yn– (I–αnV)p,
we have
xn+–p≤( –αnτ)yn–p+ αn
γg(xn) –Vp,xn+–p
≤( –αnτ)xn–p+ αn
γg(xn) –Vp,xn+–p
≤( –αnτ)xn–p+ αnγkxn–pxn+–p
+ αn
γg(p) –Vp,xn+–p
≤( –αnτ)xn–p+αnγk
xn–p+xn+–p
+ αn
γg(p) –Vp,xn+–p
≤( –αnτ)+αnγk
xn–p+αnγkxn+–p
+ αn
γg(p) –Vp,xn+–p
,
and hence
xn+–p≤
– αnτ+ (αnτ)+αnγk
–αnγk
xn–p
+ αn –αnγk
γg(p) –Vp,xn+–p
=
–(τ–γk)αn –αnγk
xn–p+
(αnτ)
–αnγk
xn–p
+ αn –αnγk
γg(p) –Vp,xn+–p
=
–(τ–γk)αn –αnγk
xn–p+
αn·αnτ
–αnγk
xn–p
+ αn –αnγk
γg(p) –Vp,xn+–p
= ( –βn)xn–p
+βn
αnτxn–p
(τ–γk) +
τ–γk
γg(p) –Vp,xn+–p
whereβn=(–τ–αγnkγ)kαn. Since ∞
n=βn=∞, we have from Lemma . and (.) thatxn→p.
This completes the proof.
4 Applications
LetHbe a Hilbert space, and letf be a proper lower semicontinuous convex function of Hinto (–∞,∞]. Then the subdifferential∂f off is defined as follows:
∂f(x) =z∈H:f(x) + z,y–x ≤f(y),y∈H
for allx∈H; see, for instance, []. From Rockafellar [], we know that∂f is maximal monotone. LetCbe a nonempty closed convex subset ofH, and letiC be the indicator
function ofC,i.e.,
iC(x) =
⎧ ⎨ ⎩
, x∈C,
∞, x∈/C.
TheniCis a proper lower semicontinuous convex function ofHinto (–∞,∞], and then the
subdifferential∂iCofiCis a maximal monotone operator. So, we can define the resolvent Jλof∂iC forλ> ,i.e.,
Jλx= (I+λ∂iC)
–x
for allx∈H. We have that for anyx∈Handu∈C,
u=Jλx ⇔ x∈u+λ∂iCu
⇔ x∈u+λNCu
⇔ x–u∈λNCu
⇔
λ x–u,v–u ≤, ∀v∈C
⇔ x–u,v–u ≤, ∀v∈C
⇔ u=PCx,
whereNCuis the normal cone toCatu,i.e.,
NCu=
x∈H: z,v–u ≤,∀v∈C.
LetCbe a nonempty, closed and convex subset ofH, and letf :C×C→Rbe a bifunc-tion. For solving the equilibrium problem, let us assume that the bifunctionf:C×C→R satisfies the following conditions.
For solving the mixed equilibrium problem, let us give the following assumptions for the bifunctionF,ϕand the setC:
(A) f(x,x) = for allx∈C;
(A) for allx,y,z∈C,
lim sup
t↓
ftz+ ( –t)x,y≤f(x,y);
(A) for allx∈C,f(x,·)is convex and lower semicontinuous;
(B) for eachx∈Handr> , there exist a bounded subsetDx⊆Candyx∈Csuch that for anyz∈C\Dx,
f(z,yx) +ϕ(yx) +
r yx–z,z–x<ϕ(z);
(B) Cis a bounded set.
We know the following lemma which appears implicitly in Blum and Oettli [].
Lemma .[] Let C be a nonempty closed convex subset of H,and let f be a bifunction of C×C intoRsatisfying(A)-(A).Let r> and x∈H.Then there exists a unique z∈C such that
f(z,y) +
r y–z,z–x ≥, ∀y∈C.
By a similar argument as that in [, Lemma .], we have the following result.
Lemma .[] Let C be a nonempty closed convex subset of a real Hilbert space H.Let f : C×C→Rbe a bifunction which satisfies conditions(A)-(A),and letϕ:C→R∪ {+∞} be a proper lower semicontinuous and convex function.Assume that either(B)or(B) holds.For r> and x∈H,define a mapping Tr:H→C as follows:
Tr(x) =
z∈C:f(z,y) +ϕ(y) +
r y–z,z–x ≥ϕ(z),∀y∈C
for all x∈H.Then following conclusions hold:
() For eachx∈H,Tr(x)=∅; () Tris single-valued;
() Tris firmly nonexpansive,i.e.,for anyx,y∈H,
Tr(x) –Tr(y)≤
Tr(x) –Tr(y),x–y
;
() Fix(Tr) =MEP(f,ϕ);
() MEP(f,ϕ)is closed and convex.
We call suchTrthe resolvent off forr> . Using Lemmas . and ., Takahashiet al.
[] obtained the following lemma. See [] for a more general result.
Lemma .[] Let H be a Hilbert space,and let C be a nonempty closed convex subset of H.Let f:C×C→Rsatisfy(A)-(A).Let Af be a set-valued mapping of H into itself
defined by
Afx=
⎧ ⎨ ⎩
{z∈H:f(x,y)≥ y–x,z,∀y∈C}, ∀x∈C,
Then MEP(f) =A–
f and Af is a maximal monotone operator withdomAf ⊂C.
Further-more,for any x∈H and r> ,the resolvent Trof f coincides with the resolvent of Af,i.e.,
Trx= (I+rAf)–x.
Applying the idea of the proof in Lemma ., we have the following results.
Lemma . Let H be a Hilbert space,and let C be a nonempty closed convex subset of H. Let f :C×C→Rsatisfy(A)-(A),and letϕ:C→R∪ {+∞}be a proper lower semicon-tinuous and convex function.Assume that either(B)or(B)hold.Let A(f,ϕ)be a set-valued
mapping of H into itself defined by
A(f,ϕ)x=
⎧ ⎨ ⎩
{z∈H:f(x,y) +ϕ(y) –ϕ(x)≥ y–x,z,∀y∈C}, ∀x∈C,
∅, ∀x∈/C. (.)
Then MEP(f,ϕ) =A–
(f,ϕ)and A(f,ϕ)is a maximal monotone operator withdomA(f,ϕ)⊂C.
Furthermore,for any x∈H and r> ,the resolvent Trof f coincides with the resolvent of
A(f,ϕ),i.e.,
Trx= (I+rA(f,ϕ))–x.
Proof It is obvious thatMEP(f,ϕ) =A–
(f,ϕ). In fact, we have that
z∈MEP(f,ϕ) ⇔ f(z,y) +ϕ(y) –ϕ(z)≥, ∀y∈C
⇔ f(z,y) +ϕ(y) –ϕ(z)≥ y–z, , ∀y∈C
⇔ ∈A(f,ϕ)z
⇔ z∈A–(f,ϕ).
We show thatA(f,ϕ)is monotone. Let (x,z), (x,z)∈A(f,ϕ)be given. Then we have, for all
y∈C,
f(x,y) +ϕ(y) –ϕ(x)≥ y–x,z and f(x,y) +ϕ(y) –ϕ(x)≥ y–x,z,
and hence
f(x,x) +ϕ(x) –ϕ(x)≥ x–x,z and f(x,x) +ϕ(x) –ϕ(x)≥ x–x,z.
It follows from (A) that
≥f(x,x) +f(x,x)≥ x–x,z+ x–x,z= –x–x,z–z.
This implies thatA(f,ϕ) is monotone. We next prove thatA(f,ϕ)is maximal monotone. To
H for allr> , whereR(I+rA(f,ϕ)) is the range ofI+rA(f,ϕ). Letx∈H andr> . Then,
from Lemma ., there existsz∈Csuch that
f(z,y) +ϕ(y) –ϕ(z) +
r y–z,z–x ≥, ∀y∈C.
So, we have that
f(z,y) +ϕ(y) –ϕ(z)≥
y–z, r(x–z)
, ∀y∈C.
By the definition ofA(f,ϕ), we get
A(f,ϕ)z
r(x–z),
and hencex∈z+rA(f,ϕ)z. Therefore,H⊂R(I+rA(f,ϕ)) andR(I+rA(f,ϕ)) =H. Also,x∈
z+rA(f,ϕ)zimplies thatTrx= (I+rA(f,ϕ))–xfor allx∈Handr> .
Using Theorem ., we obtain the following results for an inverse-strongly monotone mapping.
Theorem . Let H be a real Hilbert space,and let C be a nonempty,closed and convex subset of H.Letα> and let A be anα-inverse-strongly monotone mapping of C into H.Let <k< and let g be a k-contraction of H into itself.Let V be aγ¯-strongly monotone and L-Lipschitzian continuous operator withγ¯> and L> .Let T:C→C be a-generalized hybrid mapping such that:=F(T)∩VI(C,A)= ∅.Takeμ,γ∈Ras follows:
<μ<γ¯
L, <γ <
¯
γ–Lμ k .
Let{xn} ⊂H be a sequence generated by
⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩
x=x∈H arbitrarily,
zn=PC(I–λnA)PCxn,
yn=n
n–
k=Tkzn, ∀n= , , . . . ,
xn+=αnγg(xn) + (I–αnV)yn for all n∈N,
(.)
where{αn} ⊂(, )and{rn} ⊂(,∞)satisfy
lim
n→∞αn= ,
∞
n=
αn=∞ and lim inf n→∞ rn> .
Then{xn}converges strongly to a point pof,where pis a unique fixed point of P(I–V+
γg).This point p∈is also a unique solution of the hierarchical variational inequality
(V–γg)p,q–p
Proof PutB=F=∂iCin Theorem .. Then, forλn> andrn> , we have that
Jλn=Trn=PC.
Furthermore we have, from the proof of [, Theorem ], that
(∂iC)– =C and (A+∂iC)–=VI(C,A).
Thus we obtained the desired results by Theorem ..
Using Theorem ., we finally prove a strong convergence theorem for inverse-strongly monotone operators and equilibrium problems in a Hilbert space.
Theorem . Let H be a real Hilbert space,and let C be a nonempty,closed and convex subset of H.Letα> and let A be anα-inverse-strongly monotone mapping of C into H. Let B:D(B)⊂C→H be maximal monotone.Let J
λ= (I+λB)–be the resolvent of B forλ> .Let <k< and let g be a k-contraction of H into itself.Let V be aγ¯-strongly monotone and L-Lipschitzian continuous operator withγ¯> and L> .Let f :C×C→R be a bifunction satisfying conditions(A)-(A),and letϕ:C→R∪{+∞}be a proper lower semicontinuous and convex function.Assume that either(B)or(B)holds.Let T:C→ C be a-generalized hybrid mapping with:=F(T)∩(A+B)–∩MEP(f,ϕ)=∅.Take
μ,γ ∈Ras follows:
<μ<γ¯
L, <γ <
¯
γ–Lμ k .
Let{xn} ⊂H be a sequence generated by
⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩
x=x∈H arbitrarily,
f(un,y) +ϕ(y) –ϕ(un) +rn y–un,un–xn ≥, ∀y∈C,
zn=Jλn(I–λnA)un,
yn=nkn=–Tkzn, ∀n= , , . . . ,
xn+=αnγg(xn) + (I–αnV)yn, ∀n∈N,
(.)
where{αn} ⊂(, )and{rn} ⊂(,∞)satisfy
lim
n→∞αn= ,
∞
n=
αn=∞ and lim inf n→∞ rn> .
Then{xn}converges strongly to a point pof,where pis a unique fixed point of P(I–V+
γg).This point p∈is also a unique solution of the hierarchical variational inequality
(V–γg)p,q–p
≥, ∀q∈. (.)
Proof Sincef is a bifunction ofC×CintoRsatisfying conditions (A)-(A) andϕ:C→
Aϕf defined by (.) is a maximal monotone operator withdomAϕf ⊂C. PutF =Aϕf in Theorem .. Then we obtain thatun=Trnxn. Therefore, we arrive at the desired results.
Competing interests
The authors declare that they have no competing interests.
Authors’ contributions
Both authors read and approved the final manuscript.
Acknowledgements
The first author was partially supported by Naresuan University.
Received: 18 May 2013 Accepted: 20 August 2013 Published:07 Nov 2013 References
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Cite this article as:Wangkeeree and Boonkong:A general iterative method for two maximal monotone operators