Ground Water Hydrology
GW Resources - Quantity
• Aquifer system parameters
• Rate and direction of GW flow
• Darcy’s Law - governing flow relation • Dupuit Eqn for unconfined flow
• Recharge and discharge zones
GW Resources - Quality
• Contamination sources
Ground Water: A Valuable
Resource
• Ground water supplies 95% of the drinking
water needs in rural areas.
• 75% of public water systems rely on
groundwater.
• In the United States, ground water provides
drinking water to approximately 140
million people.
Aquifer Characteristics
1. Matrix type 2. Porosity (n)
3. Confined or unconfined
4. Vertical distribution (stratigraphy or layering) 5. Hydraulic conductivity (K)
6. Intrinsic permeability (k) 7. Transmissivity (T)
Vertical Zones of Subsurface
Water
• Soil water zone: extends from the ground surface down through the major root zone, varies with soil type and vegetation but is usually a few feet in
thickness
• Vadose zone (unsaturated zone): extends from the surface to the water table through the root zone, intermediate zone, and the capillary zone
Soil-Moisture Relationship
• The amount of moisture in the vadose zone
generally decreases with vertical distance
above the water table
Vertical Zones of Subsurface
Water Continued
• Water table: the level to which water will rise in a well drilled into the saturated zone
Porosity
– Porosity averages about 25% to 35% for most aquifer systems
– Expressed as the ratio of the volume of voids Vv to the total volume V:
n = Vv/V = 1- b/m
where:
b is the bulk density, and
Porosity
Arrangement of Particles in a
Subsurface Matrix
Porosity depends on:
• particle size
• particle packing
Soil Classification Based on
Particle Size
(after Morris and Johnson)
Material Particle Size, mm Clay <0.004
Soil Classification…cont.
Material Particle Size, mm Very coarse sand 1.0 - 2.0
Particle Size Distribution
and Uniformity
• The uniformity
coefficient U indicates the relative sorting of the material and is
defined as D60/D10
Unconfined Aquifer Systems
• Unconfined aquifer:
an aquifer where the
water table exists under atmospheric
pressure as defined by levels in shallow
wells
Confined Aquifer Systems
• Confined aquifer:
an aquifer that is overlain
by a relatively impermeable unit such that
the aquifer is under pressure and the water
level rises above the confined unit
• Potentiometric surface:
in a confined
Special Aquifer Systems
• Leaky confined aquifer: represents a stratum that allows water to flow from above through a leaky confining zone into the underlying aquifer
Ground Water Flow
Darcy’s Law
Darcy’s Law
• Darcy investigated the flow of water through beds of permeable sand and found that the flow rate through porous media is proportional to the head loss and
inversely proportional to the length of the flow path • Darcy derived equation of governing ground water
flow and defined hydraulic conductivity K:
V = Q/A where:
A is the cross-sectional area V -∆h, and
Example of Darcy
’
s Law
• A confined aquifer has a source of recharge.
• K for the aquifer is 50 m/day, and n is 0.2.
• The piezometric head in two wells 1000 m apart is 55 m and 50 m respectively, from a common
datum.
Calculate:
• the Darcy and seepage velocity in the aquifer
• the average time of travel from the head of the aquifer to a point 4 km downstream
The solution
• Cross-Sectional area 30(5)(1000) = 15 x 104 m2
• Hydraulic gradient (55-50)/1000 = 5 x 10 -3
• Rate of Flow through aquifer Q = (50 m/day) (75 x 101 m2) =
37,500 m3/day
• Darcy Velocity: V = Q/A = (37,500m3/day) / (15 x 104 m2) =
Therefore:
• Seepage Velocity:
Vs = V/n = 0.25 / 0.2 = 1.25 m/day (about 4.1 ft/day)
• Time to travel 4 km downstream:
T = 4(1000m) / (1.25m/day) = 3200 days or 8.77 years
Ground Water Hydraulics
• Hydraulic conductivity, K, is an indication
of an aquifer’s ability to transmit water
– Typical values:
10-2 to 10-3 cm/sec for Sands
10-4 to 10-5 cm/sec for Silts
Ground Water Hydraulics
Transmissivity (T) of Confined Aquifer
-
The product of K and the saturated
thickness of the aquifer T = Kb
- Expressed in m
2/day or ft
2/day
- Major parameter of concern
Ground Water Hydraulics
Intrinsic permeability (k)
Property of the medium only, independent of fluid
properties
Can be related to K by:
K = k(
g/µ)
where: µ = dynamic viscosity
= fluid density
Storage Coefficient
Relates to the water-yielding capacity of an aquifer
S = Vol/ (A
s
H)
– It is defined as the volume of water that an aquifer releases from or takes into storage per unit surface area per unit change in piezometric head - used
extensively in pump tests.
• For confined aquifers, S values range between 0.00005 to 0.005
• For unconfined aquifers, S values range
Regional Aquifer Flows are
Affected by Pump Centers
Dupuit Assumptions
For unconfined ground water flow Dupuit
developed a theory that allows for a simple solution based off the following assumptions:
1) The water table or free surface is only slightly inclined
2) Streamlines may be considered horizontal and equipotential lines, vertical
Derivation of the Dupuit
Equation
Darcy’s law gives one-dimensional flow per unit width as:
q = -Kh dh/dx
At steady state, the rate of change of q with distance is zero, or
d/dx(-Kh dh/dx) = 0
OR (-K/2) d2h2/dx2 = 0
Which implies that,
Dupuit Equation
Integration of d2h2/dx2 = 0 yields
h2 = ax + b
Where a and b are constants. Setting the boundary condition h = ho at x = 0, we can solve for b
b = ho2
Differentiation of h2 = ax + b allows us to solve for a,
a = 2h dh/dx
And from Darcy’s law,
Dupuit Equation
So, by substitution
h2 = h
02 – 2qx/K
Setting h = hL2 = h
02 – 2qL/K Rearrangement gives
q = K/2L (h02- h
L2) Dupuit Equation
Then the general equation for the shape of the parabola is
h2 = h
02 – x/L(h02- hL2) Dupuit Parabola
Cross Section of Flow
Adding Recharge W -
Causes a Mound to Form
Dupuit Example
Example:
2 rivers 1000 m apart K is 0.5 m/day
average rainfall is 15 cm/yr evaporation is 10 cm/yr
water elevation in river 1 is 20 m water elevation in river 2 is 18 m
Example
Dupuit equation with recharge becomes
h2 = h
02 + (hL2 - h02) + W(x - L/2)
If W = 0, this equation will reduce to the parabolic Equation found in the previous example, and
q = K/2L (h02- h
L2) + W(x-L/2) Given:
L = 1000 m K = 0.5 m/day h0 = 20 m
hL= 28 m
Example
For discharge into River 1, set x = 0 m
q = K/2L (h02- h
L2) + W(0-L/2)
= [(0.5 m/day)/(2)(1000 m)] (202 m2 – 18 m2 ) +
(1.369 x 10-4 m/day)(-1000 m / 2)
q = – 0.05 m2 /day
The negative sign indicates that flow is in the opposite direction From the x direction. Therefore,
Example
For discharge into River 2, set x = L = 1000 m: q = K/2L (h02- h
L2) + W(L-L/2)
= [(0.5 m/day)/(2)(1000 m)] (202 m2 – 18 m2 ) +
(1.369 x 10-4 m/day)(1000 m –(1000 m / 2))
q = 0.087 m2/day into River 2
Flow Nets - Graphical Flow Tool
Q = KmH / n
n = # head drops m= # streamtubes K = hyd cond
Flow Net in Isotropic Soil
Portion of a flow net is shown below
Stream tube
Flow Net Theory
1. Streamlines and Equip. lines are .
2. Streamlines are parallel to no flow
boundaries.
3. Grids are curvilinear squares, where diagonals cross at right angles.