Volume 2011, Article ID 780764,15pages doi:10.1155/2011/780764
Research Article
An Iteration Method for Common Solution of
a System of Equilibrium Problems in Hilbert Spaces
Jong Kyu Kim
1and Nguyen Buong
21Department of Mathematics Education, Kyungnam University, Masan Kyunganm 631-701, Republic of Korea
2Department of Mathematics, Vietnamse Academy of Science and Technology,
Institute of Information Technology, 18, Hoang Quoc Viet, q. Cau Giay, Hanoi 122100, Vietnam
Correspondence should be addressed to Jong Kyu Kim,[email protected]
Received 11 December 2010; Revised 3 March 2011; Accepted 4 March 2011
Academic Editor: Qamrul Hasan Ansari
Copyrightq2011 J. K. Kim and N. Buong. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
The strong convergence theorem is proved for finding a common solution for a system of equilibrium problems: findu∗ ∈ S : ∩Ni1EPFi,EPFi : {z ∈ C : Fiz, v ≥ 0∀v ∈ C}, i 1, . . . , N,whereCis a closed convex subset of a Hilbert spaceHandFiareNbifunctions from C×CintoRgiven exactly or approximatively. As an application, finding a common solution for a system of variational inequality problems is given.
1. Introduction
LetHbe a real Hilbert space with the scalar product and the norm denoted by the symbols
·,· and · , respectively. Let C be a nonempty closed convex subset of H, and let
Fii1, . . . , NbeNbifunctions fromC×CintoR. In this paper, we consider the system of
equilibrium problems:
findu∗∈S:∩iN1EPFi,
EPFi:{z∈C:Fiz, v≥0∀v∈C}, i1, . . . , N.
1.1
We assume thatS /∅and the bifunctionsFisatisfy the following conditions.
Condition 1. The bifunctionFsatisfies the following conditions:
A1Fu, u 0 for allu∈C.
A3For everyu∈C,Fu,·:C →Ris lower semicontinuous and convex.
A4limt→0F1−tutz, v≤Fu, vfor allu, z, v∈C×C×C.
Definition 1.1. A mappingAofCintoHis called monotone if
Ax−Ay, x−y≥0, 1.2
for allx, y∈C.
Now, we consider the variational inequality problem: findu∗∈Csuch that
Au∗, x−u∗ ≥0, 1.3
for allx∈C. We denote VIC, Athe set of solutions of the variational inequality problem.
Definition 1.2. A mapping T of C into H is called k-strictly pseudocontractive in the terminology of Browder and Petryshyn1, if there exists a numberk∈0,1such that
Tx−Ty 2≤ x−y 2k I−Tx−I−Ty 2, 1.4
whereIis the identity operator inH.
The above inequality is equivalent to
Ax−Ay, x−y≥λ Ax−Ay 2, 1.5
where the operatorA:I−Tisλ 1−k/2-inverse strongly monotonehence monotone and Lipschitz continuous with the Lipschitz constant 2/1−k. Clearly, whenk 0, T is nonexpansive, that is,
Tx−Ty ≤ x−y 1.6
for allx, y ∈ DT, the domain ofT. It means that the class of k-strictly pseudocontractive mappings strictly includes the class of nonexpansive mappings. Denote byFTthe set of fixed points of the operatorTinC, that is,
FT {x∈C:xTx}. 1.7
If N 1, then 1.1 is a single equilibrium problem 2, 3 to cover monotone inclusion problems, saddle point problems, variational inequality problems, minimization problems, Nash equilibria in noncooperative games, vector equilibrium problems, as well as certain fixed point problems.
If N > 1, then 1.1 is a problem of finding a common solution for a system of equilibrium problems which is studied firstly in 5 cf. 16 under the condition that
Fi i 1, . . . , N are bounded, Fr´echet differentiable with respect tov and ∇vFiu, uare
Lipschitz continuous, that is,
∇vFix, x− ∇vFiy, y ≤L x−y ∀x, y∈C, i1,2, . . . , N, 1.8
whereLis a positive constant. With the case that
Fiu, v I−Tiu, v−u, 1.9
and Ti i 2, . . . , Nare N−1 strictly pseudocontractive mappings, 1.1 is a problem of
finding a solution of an equilibrium problem which is also a common fixed point for a system of a finite family of strictly pseudocontractive mappings17–19.
In addition, whenF1u, v A1u, v−u whereA1 is a monotone operator,1.1
is a problem of finding an element which is a solution of a variational inequality problem and a common fixed point for a finite family of strictly pseudocontractive mappings and investigated intensively in 20–32. If all Fi have the form 1.9, then 1.1is a problem of
finding a common fixed point for a finite family of strictly pseudocontractive mappingsTi
fromCintoH14,33–35.
In this paper, we present an iteration method for solving1.1, where the iteration sequence{xn}is defined by
x0x∈H,
ui
n∈C:Fi
ui n, v
ui
n−xn, v−uin ≥0, ∀v∈C, i1, . . . , N,
xn1xn−βn
n
i1
xn−uin
αnxn
,
1.10
where{αn},{βn}are two sequences of positive numbers satisfying some conditions.
As an application, we find a common solution for a system ofNvariational inequality problems with monotone mappings.
2. Main Results
The strong and weak convergence of any sequence are denoted by → and, respectively. We formulate the following facts which are necessary in the proof of our main results.
Lemma 2.1see5. LetCbe a nonempty closed convex subset of a Hilbert spaceH, and letFbe a bifunction ofC×CintoRsatisfying the Condition1. Letr >0andx∈H. Then, there existsz∈C such that
Fz, v 1
Lemma 2.2see5. Assume thatF :C×C →Rsatisfies the Condition1. Forr >0andx∈H, define a mappingTr :H → Cas follows:
Trx
z∈C:Fz, v 1
rz−x, v−z ≥0, ∀v∈C
. 2.2
Then, the following hold:
iTr is single-valued;
iiTr is firmly nonexpansive, that is, for anyx, y∈H,
Trx−Try 2 ≤Trx−Try, x−y; 2.3
iiiFTr EPF;
ivEPFis closed and convex.
Lemma 2.3. LetFhu, vbe a bifunction approximating the bifunctionFu, vin the sense
Fhu, v−Fu, v≤hg u u−v ∀u, v∈C, h >0, 2.4
wheregtis a real positive function. Then, for eachr >0andx∈H, we have
Th
rx−Trx ≤rhg Trx , 2.5
where
Th rx
z∈C:Fhz, v 1
rz−x, v−z ≥0∀v∈C
. 2.6
Proof. Letxbe an arbitrary element ofH. By replacingvbyzin2.2and byzin2.6, we obtain
Fz,z Fhz, z ≥ 1
rx−z,z−zz−x,z−z. 2.7
Therefore, by virtue ofA2in Condition1, we can write
Fz,z−Fhz,z≥ 1
r z−z 2. 2.8
Consequently,
z−z ≤rhg Trx . 2.9
Lemma 2.4 see36. Let {an},{bn}, and{cn} be sequences of positive numbers satisfying the conditions:
ian1≤1−bnancn, bn<1, ii∞n0bn ∞, limn→∞cn/bn 0. Then,limn→∞an0.
Lemma 2.5see37. Assume thatT is a nonexpansive mapping of a closed convex subsetCof a Hilbert spaceH. ThenI−T is demiclosed at zero; that is whenever{xn}is a sequence inCweakly converging to some x ∈ Cand the sequence {I −Txn} strongly converges to zero, it follows I−Tx 0.
Lemma 2.6see17. LetAbe aλ-inverse strongly monotone mapping fromCintoHsuch that
SA/∅, whereSA{x∈C:Ax 0}. Then,SA VIC, A.
Now, consider the firmly nonexpansive mappingsTidefined by
Tix {z∈C:Fiz, v z−x, v−z ≥0, ∀v∈C}, i1, . . . , N. 2.10
By virtue ofLemma 2.2, we can seeTi is nonexpansive. Consequently,Ai : I−Tiis1/2
-inverse strongly monotone and Lipschitz continuous with the Lipschitz constantLi 2,i
1, . . . , N.
We construct a Tikhonov regularization solutionynfor1.1by solving the following
operator equation: findyn∈Hsuch that
N
i1
Aiynαnyn0, 2.11
where the positive regularization parameterαn → 0 asn → ∞. We have the following
result.
Theorem 2.7. iFor eachαn >0, problem2.11has a unique solutionyn. iilimn→∞ynu∗,u∗∈S, u∗ ≤ y , for ally∈S.
iii yn−ym ≤|αn−αm|/αn u∗ .
Proof. i Since the mapping ni1Ai is a monotone and Lipschitz continuous mapping
defined onH, it is maximal monotone. Therefore,2.11has a unique solution for eachαn>0 38.
iiFor eachy ∈S, on the base ofLemma 2.2, we have thatAiy 0,i 1, . . . , N.
Thus, from2.11it follows that
N
i1
Aiyn−Aiy, yn−yαnyn, yn−y0. 2.12
Since everyAiis monotone, from the last equality, we obtain
Hence,
yn ≤ y , ∀y∈S. 2.14
It means that the sequence{yn}is bounded. Let{ynk}be a subsequence of the sequence{yn}
such thatynk yask → ∞.
Again, letybe an arbitrary element ofS. From the1/2-inverse strongly monotone property ofAl, andAly 0,l1, . . . , N, it implies that
1
2 ynk−Tl
ynk 2≤Alynk, ynk−y
≤N
i1
Aiynk, ynk−y
≤ −αnkynk, ynk −y
−αnkynk−y, ynk −y−αnky, ynk−y
≤ −αnky, ynk−y
≤αnk2 y 2,
2.15
that is,
ynk −Tlynk ≤2 y αnk. 2.16
Therefore,
lim
k→ ∞ Al
ynk 0. 2.17
ByLemma 2.5,Aly 0, that is,y ∈ FTl,l 1, . . . , N. It means thaty ∈ S. BecauseSis
a closed convex subset in Hilbert space, it has a unique minimal elementu∗in norm. From
2.14and the weak convergence of{ynk}to y u∗, it also follows that ynk → u∗ , as
k → ∞. Moreover, the sequence{yn}converges strongly tou∗asn → ∞. iiiFrom2.11,2.14, and the monotone property ofAi, it follows
αnyn, yn−ym−αmym, yn−ym≤0 2.18
or
yn−ym ≤ |αnα−αm|
n ym ≤
|αn−αm|
αn u
∗ , 2.19
Theorem 2.8. Suppose thatαn, βnsatisfy the following conditions:
αn, βn>0 αn≤1, nlim
→ ∞αnn→ ∞lim
|αn−αn1|
α2
nβn
0,
∞
n0
αnβn∞, lim n→ ∞βn
2Nαn2
αn <1.
2.20
Then,
lim
n→ ∞xnu
∗∈S, 2.21
wherexnis defined by1.10.
Proof. Letynbe a solution of2.11. SetΔn xn−yn . Then,
Δn1 xn1−yn1 ≤ xn1−yn yn1−yn ,
xn1−yn xn−yn−βn
N
i0
Aixn−Aiynαnxn−yn.
2.22
From the monotone and Lipschitz continuous properties ofAi,i1, . . . , N,2.11, anduin
Tixn, we can write
xn−yn−βn
N
i1
Aixn−Aiynαnxn−yn
2
xn−yn 2β2n
N
i1
Aixn−Aiynαnxn−yn
2
−2βn
N
i1
Aixn−Aiynαnxn−yn, xn−yn
≤ xn−yn 2
1−2βnαnβ2n2Nαn2
.
2.23
Hence,
xn1−yn ≤Δn
1−2βnαnβ2n2Nαn2 1/2
. 2.24
Therefore,
Δn1≤Δn
1−2βnαnβ2n2Nαn2 1/2
|αn−ααn1|
n u
∗
≤Δn1−αnβn1/2|αn−ααn1|
n u
∗ .
Thus, applying the inequality
ab2≤1ε
a2b2 ε
ε >0, ε αnβn
2 , 2.26
we obtain
0≤Δ2n1≤Δ2n1−αnβn1 1
2αnβn
α
n−αn1 αn u
∗ 2 2
αnβn
11 2αnβn
≤a2
n
1−1 2αnβn−
1 2
αnβn2
αn−αn1 α2
nβn u
∗
2
2αnβn
1 1 2αnβn
.
2.27
Set
bnαnβn
1 2
1 2αnβn
,
cn
αn−αn1 α2
nβn
u∗
2
2αnβn
11 2αnβn
.
2.28
It is not difficult to check thatbnandcn satisfy the conditions inLemma 2.4for sufficiently
largen. Hence, limn→∞Δ2n0. Since limn→ ∞ynu∗, we have
lim
n→ ∞xnu
∗∈S.
2.29
Now, letFniu, v:Fihnu, vbe bifunctions approximating the bifunctionsFiu, vin
the sense2.4wherehn → 0, asn → ∞, andgtis a real positive and boundedthe image
of any bounded set is boundedfunction. Then, the sequence of iterations{xn}is defined by
x0x∈H,
ui
n∈C:Fin
ui n, v
ui
n−xn, v−uni ≥0 ∀v∈C, i1, . . . , N,
xn1xn−βn
n
i1
xn−uin
αnxn
,
2.30
where{αn},{βn}are two sequences of positive numbers satisfying some conditions.
We have the following result.
Theorem 2.9. Suppose thatαn, βn, andhnsatisfy the conditions inTheorem 2.8and
lim
n→ ∞
hnhn1 α2
nβn
Then, we have
lim
n→ ∞xnu
∗∈S,
2.32
wherexnis defined by2.30.
Proof. Letynbe a solution of the following equation:
N
i1 An
i
ynαnyn0, Ani I−Tin, 2.33
where eachTinis defined by
Tn ix
z∈C:Finz, v z−x, v−z ≥0, ∀v∈C, i1, . . . , N. 2.34
Since
xn−u∗ ≤ xn−yn yn−yn yn−u∗ , 2.35
and limn→ ∞ynu∗, in order to prove that limn→ ∞xnu∗, it is necessary to prove that
lim
n→ ∞ xn−yn nlim→ ∞ yn−yn 0. 2.36
For this purpose, first we estimate the value yn−yn . On the basis ofLemma 2.3, we have
Aix−Anix Tix−Tinx ≤hng Tix . 2.37
Therefore, from2.11,2.33, and the monotone property ofAni it implies that
yn−yn 2 α1 n
N
i1
An i
yn−Aiyn, yn−yn
≤ 1 αn
N
i1
An i
yn−Aiyn, yn−yn.
2.38
Consequently, we have
yn−yn ≤ α1 n
N
i1 An
i
yn−Aiyn
≤Nhn αng
Tiyn .
On the other hand,
Tiyn Tiyn−Tiu∗ u∗
≤ yn−u∗ u∗
≤ yn 2 u∗
≤3 u∗ .
2.40
Therefore,
yn−yn ≤C0N hn
αn, 2.41
whereC0sup{gt: 0< t≤3 u∗ }. It means that limn→ ∞ynu∗because limn→ ∞hn/αn
0.
Secondly, to prove
lim
n→ ∞ xn−yn 0, 2.42
as in the proof ofTheorem 2.8, first we need to estimate the value yn1−yn . By the argument
as in the proof ofTheorem 2.7, we have
N
i1
An i
yn−Ani1
yn1
,yn−yn1 αnyn,yn−yn1
−αn1
yn1,yn−yn1
0. 2.43
Thus,
yn−yn1 2 αn−ααn1 n
−yn1,yn−yn1
α1
n N
i1
An1
i
yn1
−An i
yn,yn−yn1
≤ αn−αn1 αn
−yn,yn−yn1
1
αn N
i1
An1
i
yn1
−An i
yn,yn−yn1
≤ αn−αn1
αn yn yn−yn1
1
αn N
i1
An1
i
yn−Ani
yn,yn−yn1 .
2.44
Therefore,
yn−yn1 ≤ αn−ααn1
n yn
1
αn N
i1 An1
i
yn−Aiyn Aiyn−Ani
yn
≤ αn−αn1
αn yn N
hnhn1 αn g
yn .
Using2.14and2.41, we have
yn ≤ u∗ C0N hn
αn. 2.46
Consequently, there exists a positive constantCsuch that yn ≤Cforn≥0. Finally, we have
yn−yn1 ≤ αn−ααn1
n CNC1
hnhn1
αn , 2.47
whereC1sup{gt: 0< t < C}. Now, setΔn xn−yn . It is not difficult to verify that
xn1−yn ≤Δn
1−2βnαnβ2n2Nαn2 1/2
,
Δn1≤Δn1−αnβn1/2|αn−ααn1|
n CNC1
hnhn1 αn .
2.48
Therefore, limn→ ∞Δn0. The proof is completed.
Remark. The sequencesαn 1n−p, 0< p <1/2, andβnγ0αnwith
0< γ0<
1
2Nα02
, 2.49
satisfy all the necessary conditions inTheorem 2.8.
3. Applications
Consider the following problem: find an elementu∗∈Csuch that
Aiu∗, v−u∗ ≥0, ∀v∈C, i1, . . . , N, 3.1
whereAi areN monotone hemicontinuous mappings from a closed convex subsetC of a
Hilbert spaceHintoH.
Theorem 3.1. Letx0xbe an arbitrary element inH. If{αn},{βn}are chosen as inTheorem 2.8, and the iteration sequence{xn}is defined as follows:
ui n∈C,
Ai
ui n
, v−ui
n
ui
n−xn, v−uin ≥0, ∀v∈C, i1, . . . , N,
xn1xn−βn
N
i1
xn−uin
αnxn
,
3.2
IfC≡H, then we have a problem of finding a common zero for a system of monotone hemicontinous mappingsAi,i1, . . . , N. In this case, variational inequality in3.2has the
formAiuin uinxn. Therefore, we have the following result.
Theorem 3.2. LetAi, i1, . . . , NbeNhemicontinuous monotone mappings defined onH. Letx0 xbe an arbitrary element inH, let{αn}and{βn}be the sequences that are chosen as inTheorem 2.8, and, the iteration sequence{xn}be defined as follows:
ui n:Ai
ui n
ui
nxn,
xn1xn−βn
N
i1
xn−uin
αnxn
.
3.3
Then the sequence{xn}converges strongly to an elementu∗such that
Aiu∗ 0, i1, . . . , N. 3.4
Without the strongly or uniformly monotone property forAi, each problem of3.1,
in general, is ill-posed. Some methods for finding a solution of each variational inequality in
3.1are presented in39.
Here we show an iterative regularization method for finding a common solution of these problems. Suppose that instead ofAi, we have their monotone approximationsAni such
thatDAni Cand
An
ix−Aix ≤hng x , i1, . . . , N, 3.5
where the positive parameterhn → 0 as n → ∞, andgtis a real positive and bounded
function. Obviously, the bifunctions
Fnu, v:An
iu, v−u
, i1, . . . , N, 3.6
satisfy the Condition1and2.4. Therefore, we have the following theorem.
Theorem 3.3. Letx0xbe an arbitrary element inH. If{αn},{βn}are chosen as inTheorem 2.9, and the iteration sequence{xn}is defined as follows:
ui n∈C:
Ai
ui n
, v−ui
n
ui
n−xn, v−uni ≥0 ∀v∈C, i1, . . . , N,
xn1xn−βn
N
i1
xn−uin
αnxn
,
3.7
then the sequence{xn}converges strongly to a common solution for3.1.
IfC ≡ H, then a common zero for a system of monotone hemicontinuous mappings
Theorem 3.4. LetAi,i1, . . . , NbeNhemicontinuous monotone mappings defined onH. Letx0 xbe an arbitrary element inH, let{αn}and{βn}be the sequences that are chosen as inTheorem 2.9, and the iteration sequence{xn}be defined as follows:
ui n:Ai
ui n
ui
nxn,
xn1xn−βn
N
i1
xn−uin
αnxn
.
3.8
Then the sequence{xn}converges strongly to an elementu∗such that
Aiu∗ 0, i1, . . . , N. 3.9
Acknowledgment
This work was supported by the Kyungnam University Research Fund, 2010.
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