Volume 2011, Article ID 717501,13pages doi:10.1155/2011/717501
Research Article
On Singular Integrals with Cauchy Kernel on
Weight Subspaces: The Basicity Property of Sines
and Cosines Systems in Weight Spaces
Tofig Isa Najafov
1and Saeed Farahani
21Nakhchivan State University, University Campus, AZ 7000 Nakhchivan, Azerbaijan
2Institute of Mathematics and Mechanics, Azerbaijan National Academy of Sciences,
AZ 1141 Baku, Azerbaijan
Correspondence should be addressed to Tofig Isa Najafov,s [email protected]
Received 3 February 2011; Accepted 28 March 2011
Academic Editor: Shyam Kalla
Copyrightq2011 T. I. Najafov and S. Farahani. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
A singular operator with Cauchy kernel on the subspaces of weight Lebesgue space is considered. A sufficient condition for a bounded action of this operator from a subspace to another subspace of weight Lebesgue space of functions is found. These conditions are not identical with Muckenhoupt conditions. Moreover, the completeness, minimality, and basicity of sines and cosines systems are considered.
1. Introduction
Consider the following singular operator with Cauchy kernel:
Sft 1
2πi
π
−π
fsds
1−e−is−t, 1.1
wheref ∈Lp,ρ−π, π, 1< p <∞, is an appropriate density,ρtis a weight function of the
form
ρt
r
k1
|t−tk|pβk, 1.2
UnderLp,ρwe understand a Lebesgue weight space with the norm
f
p,ρ≡
π
−π
ftp
ρtdt
1/p
. 1.3
Bounded action of the operator S in the spaces Lp,ρ plays an important role in
many problems of mathematics including the theory of bases. This direction has been well developed and treated in the known monographs. We will need the following.
Statement 1. The operatorSis bounded inLp,ρif and only if the inequalities
−1
p < βk< 1
q, k1, r, 1
p
1
q 1, 1.4
are fulfilled.
Concerning this fact a one can see the monograph1and papers2–4. Inequalities
1.4are Muckenhoupt condition with respect to the weight functionρtwith degreespβk.
It is known that the classic system of exponents{eint}
n∈ZZare integersforms a basis inLp,ρ
if and only if inequalities1.4holdsee, e.g.,3,4.
It turns that if you consider the singular operator acting on the subspace of the weighted Lebesgue space, then inequality 1.4 is not necessary for the bounded action. At different points of degeneration the change interval of the corresponding exponent is expanded. This paper is devoted to studying these issues.
2. Some Necessary Facts
LetL0
p,ω ≡Lp,ω0, π,ωt—a weight function of the form
ωt≡
r
k0
|t−τk|pαk, 2.1
where 0τ0< τ1<· · ·< τr π,{αk}r0⊂R.
Denote the space of evenoddfunctions inLp,ρbyLp,ρL−p,ρ, that is,
L±p,ρ ≡f ∈Lp,ρ:f−t ±ft, t∈−π, π
. 2.2
We’ll need the following identity:
1 1−eiθ−ϕ −
1 1−eiθϕ
i 2
sinϕ
Indeed, we have
1 1−eiθ−ϕ −
1 1−eiθϕ
1−e−iθ−ϕ
1−eiθ−ϕ1−e−iθ−ϕ−
1−e−iθϕ
1−eiθϕ1−e−iθϕ
1−cos
θ−ϕisinθ−ϕ
1−cosθ−ϕ2sin2θ−ϕ−
1−cosθϕisinθϕ
1−cosθϕ2sin2θϕ
i
sinθ−ϕ 2−2 cosθ−ϕ −
sinθϕ 2−2 cosθϕ
i
cosθ−ϕ/2 2 sinθ−ϕ/2−
cosθϕ/2 2 sinθϕ/2
i
2
cosθ−ϕ/2sinθϕ/2−cosθϕ/2sinθ−ϕ/2 sinθ−ϕ/2sinθϕ/2
i
2
sinϕ
sinθ−ϕ/2sinθϕ/2.
2.4
For compactness of the notation, we assumeex≡1/1−eix. Thus,
eθ−ϕ−eθϕ i 2
sinϕ
sinθ−ϕ/2sinθϕ/2. 2.5
From this identity, we can easily get the following relations:
eθ−ϕ−eθϕ−i 2
cosϕ/2 cosθ/2
1
sinϕ−θ/2
1 sinϕθ/2
,
eθ−ϕ−eθϕ−i 2
sinϕ/2 sinθ/2
1
sinϕ−θ/2−
1 sinϕθ/2
.
2.6
The authors of the papers4–7used these relations earlier while establishing the basicity criterion of the system of sines and cosines with linear phases inLp. Thus, the following is
valid.
Lemma 2.1. The following identities are true:
1 1−eiθ−ϕ −
1
1−eiθϕ −
i 2
cosϕ/2 cosθ/2
1
sinϕ−θ/2
1 sinϕθ/2
,
1 1−eiθ−ϕ −
1
1−eiθϕ −
i 2
sinϕ/2 sinθ/2
1
sinϕ−θ/2−
1 sinϕθ/2
.
In the similar way, we obtain
1 1−eiθ−ϕ
1 1−eiθϕ
e−iθ−ϕ/2
e−iθ−ϕ/2−eiθ−ϕ/2
e−iθϕ/2
e−iθϕ/2−eiθϕ/2
−1
2i
e−iθ−ϕ/2
sinθ−ϕ/2− 1 2i
e−iθϕ/2
sinθϕ/2
−1
2i
cosθ−ϕ/2−isinθ−ϕ/2
sinθ−ϕ/2
cosθϕ/2−isinθϕ/2 sinθϕ/2
−1
2i
cosθ−ϕ/2 sinθ−ϕ/2
cosθϕ/2 sinθϕ/2
1
1− 1 2i
sinθ
sinθ−ϕ/2sinθϕ/2.
2.8
Further, we must take into account the following relation:
1
sinθ−ϕ/2sinθϕ/2
1
2 sinθ/2cosϕ/2
1
sinθ−ϕ/2
1 sinθϕ/2
,
1
sinθ−ϕ/2sinθϕ/2
1
2 cosθ/2sinϕ/2
1
sinθ−ϕ/2 −
1 sinθϕ/2
.
2.9
As a result, we have
eθ−ϕeθϕ1− 1 2i
sinθ/2 sinϕ/2
1
sinθ−ϕ/2 −
1 sinθϕ/2
, 2.10
eθ−ϕeθϕ1− 1 2i
cosθ/2 cosϕ/2
1
sinθ−ϕ/2
1 sinθϕ/2
. 2.11
Assume
Kϕθ e
θ−ϕeθϕ−1. 2.12
Thus,
Kϕ−θ −
1 2i
cosθ/2 cosϕ/2
1
−sinθϕ/2−
1 sinθ−ϕ/2
1
2i
cosθ/2 cosϕ/2
×
1
sinθϕ/2
1 sinθ−ϕ/2
−Kϕθ.
2.13
Lemma 2.2. The following identities are true:
1 1−eiθ−ϕ
1
1−eiθϕ 1−
1 2i
sinθ/2 sinϕ/2
1
sinθ−ϕ/2 −
1 sinθϕ/2
,
1 1−eiθ−ϕ
1
1−eiθϕ 1−
1 2i
cosθ/2 cosϕ/2
1
sinθ−ϕ/2−
1 sinθϕ/2
.
2.14
3. Boundedness of Singular Operators on Subspace of Even Functions
Letf∈L−p,ρ. We have
Sft 1
2πi
π
−π
fsds 1−e−is−t
1 2πi
π
0
fsds 1−eit−s
0
−π
fsds 1−eit−s
1
2πi
π
0
1 1−eit−s −
1 1−eits
fsds− 1 4π
π
0
K1t, sfsds
− 1
4π
π
0
K2t, sfsds,
3.1
where the kernelsKit, s,i1,2, are determined by the expressions
K1t, s coss/2
cost/2
1
sins−t/2
1 sinst/2
,
K2t, s
sins/2 sint/2
1
sins−t/2−
1 sinst/2
.
3.2
Continue the weightωtto the interval−π,0by parity and denote byμ:
μt
⎧ ⎨ ⎩
ωt, 0≤t≤π,
ω−t, −π≤t <0.
3.3
It is obvious that{±τk}r0 ⊂ −π, πare the degeneration points ofμt. Thus,μt ω|t|,
t∈−π, π, that is,
μt
r
k0
||t| −τk|pαk. 3.4
Accept the denotation
f∼g ast−→a, if∃δ >0 :δ≤f g
It is easy to see that the following holds
||t| −τk| ∼ |t−τk||tτk|, t∈−π, π, fork >1. 3.6
As a result, forμ, we get the representation
μt∼ρ0t≡ |t|pα0
r
k1
|t−τk|pαk|tτk|pαk, t∈−π, π. 3.7
It is obvious that the singular integral S boundedly acts in Lp,μ−π, π if and only if it
boundedly acts inLp,ρ0−π, π. Statement1is valid also in the case if the Cauchy kernel is
replaced by the Hilbert kernel1/sinϕ−t/2. So, assume that the inequalities −1/p < αk<1/q,k0, r, are fulfilled. Then, from Statement1, we directly get thatSboundedly acts
fromL−p,ρ0toLp,ρ0and so fromL−p,μtoLp,μ. Assume
k±s, t sins/2 sint/2
1
sins±t/2, s, t∈−π, π×−π, π, 3.8
and consider the integral operatorI±:
I±f
π
−π
k±s, tfsds, 3.9
with the kernelk±s, t. We havef ∈L−p,μ−π, π:
Sfp,μ 1 4π
I−f−If
p,μ≤
1 4π
I−f
p,μ
If
p,μ , 3.10
where
ft
⎧ ⎨ ⎩
ft, t∈0, π,
0, t∈−π,0.
3.11
Consequently,
I−fp
p,μ
π
−π
I−ftpμtdt∼
π
−π
I−fpρ0tdt
π
−π
π
−π
fssins/2ds sins−t/2
p
ρ0t
sint
2
−pdt.
3.12
It is obvious that
ρ0t
sin t
2
whereθt |s|pα0−1r
k1|t−τk|pαk|tτk|pαk. So, if the inequalities
−1
p < α0−1< 1
q, −
1 p < αk<
1
q, k1, r, 3.14
hold, then from Statement1we obtain
I−fp
Lp,μ
≤c
π
−π
π
−π
fssins/2 sins−t/2ds
p
θtdt≤cfssinsθs 2
p
Lp,θ
≤c
π
0
fssp
θsdscfpL0
p,ω,
3.15
wherecis a constant independent fromf different in different places. As a result, we get that if the inequalities3.14hold, the operatorI−boundedly acts fromL0
p,ωtoLp,μ. The same
conclusion is true for the operator I as well. As a result, we get that while fulfilling the conditions
α0∈
−1
p, 1 q
1 q,1
1
q , αk∈
−1
p, 1
q , k1, r, 3.16
the operator S boundedly acts from L−p,μ to Lp,μ. On the other hand, it is easily seen that
Sf −t Sft. As a result, we get that the operatorSboundedly acts fromL−p,μtoLp,μ. Now, consider the case whenα0 1/qandαk,k 1, r, satisfy conditions3.16. Let
p±εp±εandq±εbe a number conjugated top±ε. It is obvious that the relations
α0∈
− 1
p±ε
, 1 q±ε
1 q±ε
,1 1 q±ε
, αk∈
− 1
p±ε
, 1 q±ε
, k1, r, 3.17
are fulfilled for sufficiently smallε >0. Then, from the previous reasonings we get that the operatorSboundedly acts from L−p±ε,μ toLp±ε,μ. As a result, it follows from the Riesz-Torin theoremsee, e.g.,7, page 144that the operatorSboundedly acts fromL−p,μtoLp,μ. We get the following.
Statement 2. Let the inequalities
−1
p < α0<2− 1
p, −
1 p < αk<
1
q, k1, r, 3.18
be fulfilled. Then, the operatorSboundedly acts fromL−p,μtoLp,μ.
Now, consider the representation of the operatorSby the kernelK1t, s. Having paid
attention to the expression
coss/2 cost/2
sinπ−s/2
similar to the previous case we establish that the boundedness of the operatorSholds also in the case when the change interval of the exponentαr extends by−1/p,2−1/p. In the
conclusion we get that the following main theorem is valid.
Theorem 3.1. Let the weight function ω be defined by the expression 2.1 and assume that the
inequalities
−1
p < α0<2− 1
p, −
1
p < αm<2− 1
p, −
1 p < αk<
1
q, k1, r−1, 3.20
are fulfilled. Then the singular operatorS:
Sf
π
−π
kt, sfsds, 3.21
with Cauchy kernelkt, s 1/1−e−is−t, boundedly acts fromL−
p,μtoLp,μ, whereμt ω|t|,
t∈−π, π.
4. Boundedness of Singular Operators on Subspace of Odd Functions
Let the weight function ωt be defined by expression2.1 and assumeμt ≡ ω|t|,t ∈
−π, π. Denote byKs;tthe following Cauchy-type kernel
Ks;t 1
1−eit−s −
1
2, s;t∈−π, π×−π, π. 4.1
Appropriate integral operator denote byK:
Kft 1
2π
π
−π
Ks;tfsds. 4.2
Let the following inequalities
−1
p < αk< 1
q, k0, r, 4.3
be fulfilled. We have
π
−π
ftdt
π
−π
ftμ1/pμ−1/pdt≤f p,μ
π
−π
μ−q/pdt
1/q
. 4.4
From4.3it follows that−qαk > −1,k 0, r, and as a resultμ−q/p ∈L1−π, π. As a
inequalities4.3hold. In particular, it follows that the operatorKboundedly acts fromLp,μ toLp,μ, if the inequalities4.3are fulfilled, that is,
Kf
Lp,μ ≤cfLp,μ, ∀f ∈L
p,μ, 4.5
wherecis a constant independent fromf. On the other hand forf∈Lp,μwe have
Kft 1
2π
π
0
fsKs;t K−s;t−1ds. 4.6
Pay an attention to the relation2.13, we obtain thatKf−t −Kft,t∈−π, π. Then from4.5yields
KfL0
p,ω ≤cfL0p,ω, ∀f∈L
0
p,ω. 4.7
Now, let
−1− 1
p < α0 <− 1
p, −
1 p < αk<
1
q, k1, r 4.8
be fulfilled. Assume
K±s;t −1 2i
sint/2
sins/2sint∓s/2, s;t∈0, π×0, π. 4.9
Denote the integral operator with kernelK±s;tbyS±, that is,
S±ft 1 2π
π
0
K±s;tfsds, t∈0, π. 4.10
Taking into account the relation2.10, forf∈Lp,μwe have
Kft 1
2π
π
0
fsKs;t K−s;t−1ds
1
2π
π
0
Ks;t−K−s;tfsdsS−S−f,
4.11
that is,
Kft S−S−ft, t∈−π, π. 4.12
Take into account the nonparityKfton−π, πwe obtain
2KfpL0
p,ω
Kfp Lp,μ ≤
SfL
p,μS
−f
Lp,μ
p
Let
ft
⎧ ⎨ ⎩
ft, t∈0, π,
0, t∈−π,0.
4.14
Consider the operatorS. We have
Sft sint/2 2π
π
0
fssin−1s/2 sint−s/2 ds
sint/2 2π
π
−π
fssin−1s/2
sint−s/2 ds. 4.15
Thus
SfpL
p,μ c
π
−π
Sftpμtdtc
π
−π
π
−π
fssin−1s/2 sint−s/2 ds
p
sin t 2
pμtdt. 4.16
Further, we must take into account the expression sint/2∼t,t∈−π, π. As a result, from the previous relation we have
SfpL
p,μ ≤c
π
−π
π
−π
fssin−1s/2 sint−s/2 ds
p
μtdt, 4.17
where
μt |t|pα01
r
k1
||t| −tk|pαk. 4.18
It is clear that for weight function μt Muckenhoupt condition is fulfilled and applying Statement1to the expression4.17we obtain
SfpL
p,μ ≤c
fssin−1s
2
p
Lp,μ
c
π
−π
fsp
sin−1s 2
pμsds
≤c
π
0
fsp|s|−pμsdsc
π
0
fspωsdscfpL
p,μ.
4.19
In the similar way we establish the validity of the inequality
S−f
Lp,μ ≤cfLp,μ, ∀f ∈L
p,μ. 4.20
If the inequalities4.8hold, as a result, we have
KfL
p,μ ≤cfLp,μ, ∀f ∈L
Consider the case
α0−
1
p, −
1 p < αk<
1
q, k1, r. 4.22
Take sufficiently smallε >0 and determinep±ε p±ε. Acting similarly to the caseL−p,μpar.3 and accept the Riesz-Torin theorem we obtain boundedly acting of the operatorKfromLp,μ toL−p,μsinceKft∈L−p,μ. Thus, if the following inequalities
−1−1
p < α0 < 1
q, −
1 p < αk<
1
q, k1, r, 4.23
are fulfilled, then the operatorKboundedly acts fromLp,μtoL−p,μ.
Using the identity2.11in the similar way we establish that the same conclusion with respect to the operatorKis true in the case when the change interval of the exponentαr is
expanded on−1−1/p,1/q. As a result, we obtain the validity of the following theorem.
Theorem 4.1. Let the weight functionωbe defined by the expression2.1andμt ≡ ω|t|,t ∈
−π, π. Assume that the inequalities
−1− 1
p < α0< 1
q, −1−
1 p < αr <
1
q, −
1 p < αk<
1
q, k1, r−1, 4.24
are fulfilled. Then the singular operatorK:
Kf
π
−π
Ks;tfsds, 4.25
with Cauchy-type kernelKs;t 1/1−e−is−t−1/2, boundedly acts fromL
p,μtoL−p,μ.
5. Completeness, Minimality, and Basicity of the
System of Sines in Weight Space
Consider the system of sines{sinnt}n∈N. Let conditions3.20be fulfilled. It is easy to see that then the system{sinnt}n∈Nis minimal inL0
p,ω. The system{2/πω−1tsinnt}n∈N, 1/p
1/q1, is a biorthogonal system to it. Indeed, it is obvious thatL0
q,ωis a space conjugated to
L0p,ω, and an arbitrary continuous functionallgonL0p,ω, generated byg∈L0q,ω, realized by the
formula
lg
f
π
0
fgωdt, ∀f∈L0p,ω, 5.1
Takegt ω−1tsinnt,n∈N. We have
ω−1tsinntq
L0 q,ω
π
0
ω−1tsinntqωtdt
π
0
ω1−qt|sinnt|qdt. 5.2
Since sinnt∼tast → 0 and sinnt∼π−tast → πfor every fixedn∈N, then from relation5.2follows that{ω−1sinnt}
n∈N⊂L0q,ω, if the inequalities
α0<2−
1
p, αm<2− 1
p, αk< 1
q, k1, r−1, 5.3
are fulfilled.
Takegt 2/πω−1tsinntand denote byϑ
ngenerated by its functional, that is,
ϑn
f 2
π
π
0
ftsinnt dt, ∀f∈L0p,ω. 5.4
It is clear thatϑnsinkt δnk,∀n, k∈N, whereδnkis a Kronecker’s symbol. Consider
sinntpL0
p,ω
π
0
|sinnt|pωtdt. 5.5
Thus,{sinnt}n∈N ⊂Lp,ω, ifα0 >−1/p−1,αr >−1/p−1,αk >−1/p,k 0, r−1. As a result,
we obtain that if the inequalities
−1− 1
p < α0<2− 1
p, −1−
1
p < αr <2− 1
p, −
1 p < αk<
1
q, k0, r−1, 5.6
hold, then the system{sinnt}n∈Nis minimal inL0
p,ω.
Now consider the completeness of the system{sinnt}n∈N in L0
p,ω. Suppose that for
someg∈L0
q,ω,
π
0
sinnt gω dt0, ∀n∈N, 5.7
holds. We have
π
0
gωdt
π
0
gω1/qω1/pdt≤g L0
q,ω
π
0
ω dt
1/p
. 5.8
It is easy to see that if the inequalities
αk>−
1
are fulfilled, thenω∈L1. Then from the previous relation we getgω ∈L1. Since, the system {sinnt}n∈N is complete in space of continuous on 0, π functions with sup-norm, which vanishes at the ends of the segment0, π, then from5.7it follows thatgt 0 a.e. on
0, π. Consequently, the system{sinnt}n∈Nis complete inL0
p,ω. So, the following statement
is true.
Statement 3. Let the weight functionωtbe defined by expression2.1. The system of sines
{sinnt}n∈Nis minimal inL0
p,ω, if the inequalities5.6are fulfilled. It is complete inL0p,ω, if the
inequalities5.9are fulfilled. Moreover, it forms a basis inL0p,ω, if the inequalities
−1
p < αk< 1
q, k0, m 5.10
hold.
The basicity of system of sines inL0
p,ω, when the inequalities5.10hold, follows from
the basicity of system of exponent{eint}
n∈Z inLp,μ, whereμt ω|t|,t ∈ −π, π. The
basicity of these systems earlier considered in papers3,4,8,9. In the similar way we prove the following statement.
Statement 4. Let the weight functionωtdefined by expression2.1. The system of cosines
1∪ {cosnt}n∈N is minimalforms a basisinL0
p,ω, if the inequalities5.10are fulfilled. It is
complete inL0
p,ω, if the inequalities5.9holds.
References
1 I. I. Danilyuk, Irregular Boundary Value Problems on a Plane, Nauka, Moscow, Russia, 1975.
2 B. S. Pavlov, “Basicity of an exponential system and Muckenhoupt’s condition,” Doklady Akademii Nauk
SSSR, vol. 247, no. 1, pp. 37–40, 1979Russian.
3 K. S. Kazaryan and P. I. Lizorkin, “Multipliers, bases and unconditional bases of the weighted spaces B and SB,” Akademiya Nauk SSSR. Trudy Matematicheskogo Instituta imeni V. A. Steklova, vol. 187, pp. 111–130, 1989.
4 S. S. Pukhov and A. M. Sedletskiy, “Bases of exponents, sines and cosines in weight spaces on finite interval,” Proceedings of the Russian Academy of Sciences, vol. 425, no. 4, pp. 452–455, 2009.
5 E. I. Moiseev, “The basis property for systems of sines and cosines,” Doklady Akademii Nauk SSSR, vol. 275, no. 4, pp. 794–798, 1984.
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1, pp. 170–171, 1986.
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http://www.hindawi.com Volume 2014
Discrete Mathematics
Journal ofHindawi Publishing Corporation
http://www.hindawi.com Volume 2014
Hindawi Publishing Corporation
http://www.hindawi.com Volume 2014