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Vol. 5, No. 1, 2012, 16-24

ISSN 1307-5543 – www.ejpam.com

SPECIALISSUE FOR THEINTERNATIONAL CONFERENCE ONAPPLIEDANALYSIS ANDALGEBRA 29 JUNE- 02 JULY2011, ISTANBULTURKEY

Majorization for Certain Analytic Functions

Osman ALTINTAS

Department of Mathematics, Faculty of Education, Ba¸skent University, Ankara, Turkey

Abstract. In this paper two subclasses p,q γ,A,B

and p,q γ,A,B

of valently starlike and p-valently convex functions of complex order γ 6= 0 in the open unit disk U are introduced and for these classes several majorization problems are discussed.

2000 Mathematics Subject Classifications: 30C45

Key Words and Phrases: Analytic function, p-valent function, Starlike function, Convex function, Majorization problems, Fractional derivative.

1. Introduction and Definitions

Definition 1([see 5]). Let the functions f(z)and g(z)be analytic in the open unit disk U ={z:z∈Cand |z|<1}.

We say that f(z)is majorized byg(z)and write

f(z)g(z) (1)

if there exists a functionφ(z)analytic in∪, such that

|φ(z)|≤1 and f(z) =φ(z)g(z). (2) Also, we say that f(z)is subordinate to g(z)and write

f(z)g(z)

if there exist a functionw(z)analytic inU, such that

w(0) =0,|w(z)| ≤ |z| and f (z) =g(w(z)).

Email address:oaltintasbaskent.edu.tr(O. Altınta¸s)

(2)

Definition 2([see 8]). The fractional derivative of orderδis defined by

Dzδf(z) = 1 Γ (1−δ)

d dz

z

Z

0

f(ζ)

(zζ)δdζ (0

δ <1) (3)

where f(z) is an analytic function in a simply connected region of the zplane containing the origin and the multiplicity of (zζ)−δ is removed by requiring log (zζ) to be real when zζ >0.

Definition 3 ([see 8]). Under the hypotheses of definition 2, the fractional derivative of order

(n+δ)is defined by

Dzn+δf(z) = d

dznD

δ

z f(z). (4)

Several majorization problems investigated by Altınta¸s and Owa [1], Altınta¸s et al. [2]

and[3].

LetApdenote the class of functions f normalized by

f(z) =zp+

X

n=p+1

anzn (P∈N={1, 2, 3, . . .})

which are analytic and pvalent in U. Also let a function fAp is said to be in the class p,q γ,A,B

if and only if

1+ 1

γ

z f(q+δ+1)(z)

f(q+δ)(z) −p+q+δ

!

11++AZ

BZ (5)

whereγ∈C\ {0},p∈N,q∈N0=N∪ {0}, 0δ <1,1B<A1 and

γ(AB) + (pqδ)B

pqδ . Furthermore a function fApis said to be in the classp,q γ,A,B

if and only if

1+1

γ 1+

z f(q+δ+2)(z)

f(q+δ+1)(z) −p

+q+δ

!

11++AZBZ (6)

whereγ∈C\ {0},p∈N,q∈N0, 0¶δ <1,−1¶B<A¶1 and

γ(AB) + (pqδ)B

pqδ . We have the following relationships (from[3, 11, 2], respectively)

(3)

S0p,0(γ, 1,1) =S(γ)andCp0,0(γ, 1,1) =C(γ). S(γ)andC(γ)were considered by Nasr and Aouf in[6].

S0p,0(1−α, 1,−1) =S∗(α)andCp0,0(1−α, 1,−1) =C(α)

denote respectively the class of starlike and convex functions of orderα,(0¶α <1) which were introduced by Robertson in[9].

2. Majorization Problems for the Class

S

δ

p,q

,

A

,

B

)

We begin by proving.

Theorem 1. Let the function f(z) be in the class Ap and suppose that gp,q(γ,A,B). If f(q+δ)(z)is majorized by g(q+δ)(z)in U for qNoandδ <1,then

f

(q+δ+1)(z)

g

(q+δ+1)(z)

|zr1

(7) where r1=r1(p,q,δ,γ,A,B)is the smallest positive root of the equation

γ(AB) + (pqδ)B

r3−(pqδ+2|B|)r2−[

γ(AB) + (pqδ)B

+2]r+pqδ=0 (8) where p∈N, q∈N0∈C\ {0},δ <1and

γ(AB) + (pqδ)B

pqδ . Proof. Sincegp,q(γ,A,B), we obtain from (5)

1+ 1

γ

z g(q+δ+1)(z)

g(q+δ)(z) −

p+q+δ

!

= 1+(z)

1+(z) (9)

where

ω(0) =0 and |ω(z)|¶|z| (zU). (10) From (9) we readily obtain

z g(q+δ+1)(z)

g(q+δ)(z) =

pqδ+

γ(AB) + (pqδ)B

ω(z)

1+(z) . (11)

Using (10) in (11) we find

g

(q+δ)(z)

(1+|B| |z|)|z|

pqδγ(AB) + (pqδ)B |z|

g

(q+δ+1)(z)

(4)

Since f(q+δ)(z)is majorized byg(q+δ)(z)from (2) we have

f(q+δ+1)(z) =φ(z)g(q+δ+1)(z) +φ′(z)g(q+δ)(z), (13) φ(z)is satisfies the inequality[cf. Nehari 7, p. 168]:

φ′(z)

1−φ(z)

2

1− |z|2 (zU) (14)

and using (12) and (14) in (13), we get

f

(q+δ+1)(z)

φ(z)

+

1−φ(z)

2

1− |z|2

(1+|B| |z|)|z|

pqδγ(AB) + (pqδ)B |z|

g

(q+δ+1)(z)

(15) which, upon setting

|z|=r,φ(z)

=ρ (0¶ρ¶1) leads us to the inequality

f

(q+δ+1)(z)

θ(ρ)

(1−r2)”

pqδγ(AB) + (pqδ)B r

—g

(q+δ+1)(z) (16)

where

θ(ρ) =(r+|B|r2)ρ2+ (1r2)pqδγ(AB) + (pqδ)B

r]ρ+ (r+|B|r2) (17) takes on its maximum value atρ=1 withr=r1(p,q,δ,γ,A,B)gives by (8) if

σr1(p,q,δ,γ,A,B)

then the function∧(ρ)defined by

∧(ρ) =−(σ+σ2|B|)ρ2+ (1−σ2)”pqδγ(AB) + (pqδ)B σ

—

ρ+ (σ+σ2|B|)

(18) is an increasing function on the interval 0¶ρ¶1 so that

∧(ρ)¶∧(1) = (1−σ2)”pqδγ(AB) + (pqδ)B σ

—

(0¶ρ¶1; 0¶σr1(p,q,δ,γ,A,B)).

Hence, by settingρ=1 in (16), we conclude that Theorem 1 holds true for|zr1(p,q,δ,γ,A,B)

is given by (8). This completes the proof of Theorem 1.

Corollary 1([see 3]). Let the function f(z)be in the class Apand suppose that gS0p,q(γ, 1,−1). If f(q)(z)is majorized by g(q)(z)in U, then

f

(q+1)(z)

g

(q+1)(z)

(5)

where

R1=R1(p,q,δ) = k

Æ

k24(pq)

2γp+q

22γp+q

(19)

(k=pq+2+2γp+q

,p∈N,q∈N0,γ∈C\ {0}). Proof. If we setδ=0,A=1,B=−1 in Theorem 1, then

f

(q+1)(z)

g

(q+1)(z)

|zR1

whereR1=R1(p,q,δ)is the smallest positive root of the equation

2γp+q

r3−(pq+2)r2−[

2γp+q

+2]r+pq=0 r=1 is the root of the above equation and we obtain

2γp+q r2−(

2γp+q

+pq+2)r+pq=0. (20) and the positive root of the equation (20) isR1=R1(p,q,δ).

Corollary 2([see 2]). Let the function f(z)be in the class A1and suppose that gS1,00 (γ, 1,−1). If f(z)is majorized by g(z)in U, then

f

(z)

g

(z)

(|zR2)

where

R2=R2(γ) =3+

2γ−1

Æ

9+22γ−1 +

2γ−1

2

22γ−1

Corollary 3([see 5]). Let f(z)be in the class A1and suppose that g(z)∈S1,00 (1, 1,−1). If f(z) is majorized by g(z)in U, then

f

(z)

g′(z)

(|zR3)

where R3=2−

p

3.

3. Majorization Problems for the Class

C

pδ,q

(

γ

,

A

,

B

)

.

The proof Theorem 2 is based upon the following Lemmas.

Lemma 1([see 10, Theorem 1]). If fCpδ,q(γ,A,B) (γ∈C\ {0})then

Re –

1+1

γ

‚

z f(q+δ+2)(z)

f(q+δ+1)(z) −p+q+δ+1

Ϊ

> 1−A

(6)

Proof. If fCpδ,q(γ,A,B)then we have from (6)

1+ 1

γ(

z f(q+δ+2)(z)

f(q+δ+1)(z)p+q+δ+1) =

1+Aw(z)

1+Bw(z) (22)

wherew(0) =0 and|w(z)|¶|z|,(B<A¶1). We let

h(z) = 1+Aw(z)

1+Bw(z) (23)

and

h(z) =u+iv, |w(z)|2=

h(z)−1 ABh(z)

2 ¶1 and

(1−B2)u2−2(1−AB)u+1−A2¶0 (24) from (24) implies that

1−A

1−BReh(z) =u¶ 1+A

1+B. (25)

The following lemma is proved in[3]forδ=0.

Lemma 2. If fCpδ,q(γ,A,B) (γ∈C\ {0})then fp,q(12γ,A,B)that is Cpδ,q(γ,A,B)p,q(γ

2,A,B) (26)

Proof. We know that all convex function in U is starlike of order 12 in U,[see 4, p. 7]or, equivalently

Re[1+z f

′′(z)

f′(z) ]>0⇒Re[

z f′(z)

f(z) ]>

1

2. (27)

If we let

Re[1+z f

′′(z)

f′(z) ]> αfor f(z)−→f

(q+δ)(z),

and using Lemma 1, we have

Re[1+z f

(q+δ+2)(z)

f(q+δ+1)(z) −p+q+δ+1)]>

1−A

1−B (28)

or

Re[1+ 1

1−α(

z f(q+δ+2)(z)

f(q+δ+1)(z)p+q+δ+1]>0. (29)

This implies that

1+ 1

1−α(

z f(q+δ+2)(z)

f(q+δ+1)(z)p+q+δ+1=

1−w(z)

(7)

So, we have

1+1

γ(

z f(q+δ+2)(z)

f(q+δ+1)(z) −(p+q+δ+1) =

γ+ (γ2+2α)w(z)

γ(1+w(z)) . (31)

On the other hand we know that z fp(z)

f(z) > α⇒Re(1+

1 1α

z fp(z)

f(z) )>0. (32)

Similarly using (27) and (29) we obtain the following relations.

[1+ 1

1−α(

z f(q+δ+1)(z)

f(q+δ)(z)p+q+δ)]>

1

2, (33)

1+ 1

1−α(

z f(q+δ+1)(z)

f(q+δ)(z)p+q+δ) =

1

1+w(z), (34)

1+ 2

γ(

z f(q+δ+1)(z)

f(q+δ)(z)p+q+δ) =

γ+ (γ−2+2α)

γ(1+w(z)) . (35)

(36) The inclusion property (26) is easily seen that from (31) and (35).

Upon replacingγin Theorem 1 by 12γ, if we apply Lemma 2 we have,

Theorem 2. Let the function f(z) be in the class Ap and suppose that g(z) Cpδ,q(γ,A,B). If f(q+δ)(z)is majorized by g(q+δ)(z)U, for p∈Nq∈N0andδ <1then

f

(q+δ+1)(z)

g

(q+δ+1)(z)

(|z| ≤r2) (37)

where r2=r2(p,q,δ,γ,A,B)is the smallest positive root of the equation

1

2γ(AB) + (pqδ)B

r3−(pqδ+2|B|)r2−[1

2γ(AB) + (pqδ)|B|

+2]r+pqδ=0 where p∈N, q∈N0∈C\ {0},δ <1, and

1

2γ(AB) + (pqδ)B

pqδ .

Corollary 4([see 3]). Let the function f(z)be in the class Apand suppose that

g(z)∈Cp0,q(γ, 1,−1). If f(q)(z)is majorized by g(q)(z)in U, then

f

(q+1)(z)

g

(q+1)(z)

(8)

where

R1=R1(p,q,δ) = µ

Æ

µ24(pq)

γp+q

2γp+q

µ=2+pq+γp+q

,p∈N,q∈N0,γ∈C\ {0} Proof. We letδ=0,A=1,B=1 in Theorem 2.

Corollary 5([see 2]). Let the function f(z)be in the class A1and suppose that g(z)∈C1.00 (1, 1,−1). If f(z)is majorized by g(z)in U, then

f

(z)

g

(z)

(|zR2)

where

R2=R2(γ) = 3+

γ−1

Æ

92γ−1 +

γ−1

2

2γ−1

Proof. We letp=1,q=0,δ=0,A=1,B=−1 in Theorem 2.

Corollary 6([see 5]). Let the function f(z)be in the class A1and suppose that g(z)∈C1.00 (1, 1,−1). If f(z)is majorized by g(z)in U, then

f

(z)

g

(z)

(|z|¶ 1 3)

Proof. We let limit forγ−→1 in Corollary 5 orγ−→ 12γin Corollary 1.

References

[1] O Altinta¸s and S Owa. Majorization and quasi-subordinations for certain analytic func-tions.Japan Acad. Ser. A Math. Sci., 68:181–185, 1992.

[2] O Altinta¸s, Ö Özkan, and H Srivastava. Majorization by starlike functions of complex order. Complex Variables Theory Appl, 46:207–218, 2001.

[3] O. Altinta¸s and H Srivastava. Some majorization problems associated with p- valently starlike and convex functions of complex order. East Asian Math. Journal, 17(2):175– 183, 2001.

[4] T MacGregor. The radius of converity for starlike functions of order 12. Amer. Math. Soc, 14:71–76, 1963.

[5] T MacGregor. Majorization by univalent functions.Duke Math.J, 34:95–102, 1967.

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[7] Z Nehari. Conformal Mopping, McGraw-Hill Book Company. New York, Toronto and London, 1952.

[8] S Owa. On the distortion theorems I. Complex Variables Theory Appl, 18:53–59, 1978.

[9] M Robertson. On the theory of univalent functions. Ann. of Math., 37(2):1359–1363, 1936.

[10] H Srivastava, O Altınta¸s, and S Serenbay. Coffecient bounds for certain subclass of starlike functions of complex order. Applied Mathematics Letters, 24(8), August 2011.

References

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