R E S E A R C H
Open Access
An implicit method for finding a common
fixed point of a representation of
nonexpansive mappings in Banach spaces
Nawab Hussain
1, Mahmood Lashkarizadeh Bami
2and Ebrahim Soori
3**Correspondence: [email protected];
[email protected] 3Department of Mathematics,
Lorestan University, P.O. Box 465, Khoramabad, Lorestan, Iran Full list of author information is available at the end of the article
Abstract
We introduce an implicit method for finding an element of the set of common fixed points of a representation of nonexpansive mappings. Then we prove the strong convergence of the proposed implicit scheme to the common fixed point of a representation of nonexpansive mappings.
MSC: 90C33; 47H10
Keywords: fixed point; nonexpansive mapping; representation; semigroup; sunny nonexpansive retraction
1 Introduction
LetCbe a nonempty closed and convex subset of a Banach spaceEandE∗ be the dual space ofE. Let·,·denote the pairing betweenEandE∗. The normalized duality mapping
J:E→E∗is defined by
J(x) =f∈E∗:x,f=x=f
for allx∈E. In the sequel, we usejto denote the single-valued normalized duality map-ping. LetU={x∈E:x= }.Eis said to be smooth or to have a Gâteaux differentiable norm if the limit
lim
t→
x+ty–x t
exists for eachx,y∈U.E is said to have a uniformly Gâteaux differentiable norm if for eachy∈U, the limit is attained uniformly for allx∈U.Eis said to be uniformly smooth or is said to have a uniformly Féchet differentiable norm if the limit is attained uniformly forx,y∈U. It is known that if the norm ofE is uniformly Gâteaux differentiable, then the duality mappingJis single-valued and uniformly norm to weak∗continuous on each bounded subset ofE. A Banach spaceEis smooth if the duality mappingJofEis single-valued. We know that ifEis smooth, thenJ is norm to weak-star continuous; for more details, see [].
LetCbe a nonempty closed and convex subset of a Banach spaceE. A mappingT ofC
into itself is called nonexpansive ifTx–Ty ≤ x–yfor allx,y∈C, and a mappingf is anα-contraction onEiff(x) –f(y) ≤αx–y,x,y∈Esuch that ≤α< .
In this paper, motivated by Lashkarizadeh Bami and Soori [] and Hussain and Taka-hashi [], we introduce the following general implicit algorithm for finding a common element of the set of fixed points of a representationS={Tt:t∈S}of a semigroupSas nonexpansive mappings fromCinto itself, with respect to a left regular sequence of means defined on an appropriate subspace of bounded real-valued functions of the semigroup. On the other hand, our goal is to prove that there exists a sunny nonexpansive retractionP
ofContoFix(S) andx∈Csuch that the following sequence{zn}converges strongly toPx:
zn=nf(zn) + ( –n)Tμnzn (n∈N).
2 Preliminaries
LetS be a semigroup. We denote byB(S) the Banach space of all bounded real-valued functions defined onSwith supremum norm. For eachs∈Sandf∈B(S), we definelsand
rsinB(S) by
(lsf)(t) =f(st), (rsf)(t) =f(ts) (t∈S).
LetXbe a subspace ofB(S) containing , and letX∗be its topological dual. An elementμ ofX∗is said to be a mean onXifμ=μ() = . We often writeμt(f(t)) instead ofμ(f) forμ∈X∗ andf ∈X. LetXbe left invariant (resp. right invariant),i.e.,ls(X)⊂X(resp.
rs(X)⊂X) for eachs∈S. A meanμonXis said to be left invariant (resp. right invariant) ifμ(lsf) =μ(f) (resp.μ(rsf) =μ(f)) for eachs∈Sandf ∈X.Xis said to be left (resp. right) amenable ifXhas a left (resp. right) invariant mean.Xis amenable ifXis both left and right amenable. As is well known,B(S) is amenable whenSis a commutative semigroup (see p. of []). A net{μα}of means onXis said to be left regular if
lim α l
∗
sμα–μα=
for eachs∈S, wherel∗s is the adjoint operator ofls.
Letf be a function of the semigroupSinto a reflexive Banach spaceEsuch that the weak closure of{f(t) :t∈S}is weakly compact, and letXbe a subspace ofB(S) containing all the functionst→ f(t),x∗withx∗∈E∗. We know from [] that for anyμ∈X∗, there exists a unique elementfμinEsuch thatfμ,x∗=μtf(t),x∗for allx∗∈E∗. We denote suchfμ
byf(t) dμ(t). Moreover, ifμis a mean onX, then from [],f(t) dμ(t)∈co{f(t) :t∈S}. LetCbe a nonempty closed and convex subset ofE. Then a familyS={Ts:s∈S}of mappings fromCinto itself is said to be a representation ofSas a nonexpansive mapping onCinto itself ifSsatisfies the following:
() Tstx=TsTtxfor alls,t∈Sandx∈C;
() for everys∈S, the mappingTs:C→Cis nonexpansive.
We denote byFix(S) the set of common fixed points ofS, that is,Fix(S) =s∈S{x∈C:
Tsx=x}.
Theorem .[] Let S be a semigroup,let C be a closed,convex subset of a reflexive Banach space E,S={Ts:s∈S}be a representation of S as a nonexpansive mapping from C into
itself such that weak closure of{Ttx:t∈S}is weakly compact for each x∈C,and let X be
each x∈C and x∗∈E,andμbe a mean on X.If we write Tμx instead of
Ttxdμ(t),then
the following hold.
(i) Tμis a nonexpansive mapping fromCintoC. (ii) Tμx=xfor eachx∈Fix(S).
(iii) Tμx∈co{Ttx:t∈S}for eachx∈C.
(iv) IfXisrs-invariant for eachs∈Sandμis right invariant,thenTμTt=Tμfor each
t∈S.
Remark From Theorem .. in [], every uniformly convex Banach space is strictly
con-vex and reflexive.
LetDbe a subset ofB, whereBis a subset of a Banach spaceE, and letPbe a retraction ofBontoD, that is,Px=xfor eachx∈D. ThenPis said to be sunny if for eachx∈B
andt≥ withPx+t(x–Px)∈B,P(Px+t(x–Px)) =Px. A subsetDofBis said to be a sunny nonexpansive retract ofBif there exists a sunny nonexpansive retractionPofB
ontoD. We know that ifE is smooth andPis a retraction ofBontoD, thenPis sunny and nonexpansive if and only if for eachx∈Bandz∈D,x–Px,J(z–Px) ≤. For more details, see [].
Lemma .[] Let S be a semigroup,and let C be a compact convex subset of a real strictly convex and smooth Banach space E.Suppose thatS={Ts:s∈S}is a representation of S as
a nonexpansive mapping from C into itself.Let X be a left invariant subspace of B(S)such that∈X,and the function t→ Ttx,x∗is an element of X for each x∈C and x∗∈E∗.
Ifμis a left invariant mean on X,thenFix(Tμ) =TμC=Fix(S)and there exists a unique
sunny nonexpansive retraction from C ontoFix(S).
Throughout the rest of this paper, the open ball of radiusrcentered at is denoted byBr. LetCbe a nonempty closed convex subset of a Banach spaceE. For> and a mapping
T:C→C, we letF(T) be the set of-approximate fixed points ofT,i.e.,F(T) ={x∈C:
x–Tx ≤}.
3 Main result
In this section, we deal with a strong convergence approximation scheme for finding a common element of the set of common fixed points of a representation of nonexpansive mappings.
Theorem . Let S be a semigroup.Let C be a nonempty compact convex subset of a real
strictly convex and reflexive and smooth Banach space E.Suppose thatS={Ts:s∈S}is a
representation of S as a nonexpansive mapping from C into itself such thatFix(S)=∅.Let X be a left invariant subspace of B(S)such that∈X,and the function t→ Ttx,x∗is an
element of X for each x∈C and x∗∈E∗.Let{μn}be a left regular sequence of means on X.
Suppose that f is anα-contraction on C.Letnbe a sequence in(, )such thatlimnn= .
Then there exists a unique sunny nonexpansive retraction P of C ontoFix(S)and x∈C such that the following sequence{zn}generated by
zn=nf(zn) + ( –n)Tμnzn (n∈N) ()
Proof By Proposition .. and Theorem .. in [], any compact subsetCof a reflexive Banach spaceEis weakly compact, and from Proposition .. in [], any closed convex subset of a weakly compact subsetCof a Banach spaceEis itself weakly compact, and by Proposition .. in [], any convex subsetCof a normed spaceEis weakly closed if and only ifCis closed. Therefore, weak closure of{Ttx:t∈S}is weakly compact for each
x∈C.
We divide the proof into five steps.
Step . The existence ofznwhich satisfies ().
This follows immediately from the fact that for everyn∈N, the mappingNngiven by
Nnx:=nf(x) + ( –n)Tμnx (x∈C)
is a contraction. To see this, putβn= ( +n(α– )), then ≤βn< (n∈N). Then we have Nnx–Nny ≤nf(x) –f(y)+ ( –n)Tμnx–Tμny
≤nαx–y+ ( –n)x–y = +n(α– )
x–y=βnx–y.
Therefore, by the Banach contraction principle [], there exists a unique pointzn∈Csuch thatNnzn=zn.
Step .limn→∞zn–Ttzn= for allt∈S.
Considert∈Sand let> . By Lemma in [], there existsδ> such thatcoFδ(Tt) +
Bδ⊆F(Tt). By Corollary . in [], there also exists a natural numberNsuch that
N+ N
i=
Ttisy–Tt
N+ N
i=
Ttisy
≤δ ()
for alls∈Sandy∈C. Letp∈Fix(S) andMbe a positive number such thatsupy∈Cy ≤
M. Lett∈S, since{μn}is strongly left regular, there existsN∈Nsuch thatμn–lt∗iμn ≤
δ
(M) forn≥Nandi= , , . . . ,N. Then we have
sup
y∈C Tμny–
N+ N
i=
Ttisydμn(s)
=sup
y∈C
sup x∗=
Tμny,x∗
–
N+ N
i=
Ttisydμn(s),x∗
=sup
y∈C
sup x∗=
N+ N
i=
(μn)sTsy,x∗
–
N+ N
i=
(μn)sTtisy,x∗
≤
N+ N
i= sup
y∈C
sup x∗=
(μn)sTsy,x∗
–l∗tiμn
s
Tsy,x∗
≤ max
i=,,...,N
μn–l∗tiμnM+ p
≤ max
i=,,...,N
μn–l∗tiμn(M)
By Theorem . we have
N+ N
i=
Ttisydμn(s)∈co
N+ N
i=
Tti(Tsy) :s∈S
. ()
It follows from ()-() that
Tμny∈co
N+ N
i=
Ttisy:s∈S
+Bδ
⊂coFδ(Tt) + Bδ⊂F(Tt)
for ally∈Candn≥N. Therefore,lim supn→∞supy∈CTt(Tμny) –Tμny ≤. Since> is arbitrary, we have
lim sup
n→∞
sup
y∈C
Tt(Tμny) –Tμny= . ()
Lett∈Sand> , then there existsδ> which satisfies (). TakeL= ( +α)M+
f(p) –p. Now, from the conditionlimnn= and from (), there exists a natural number
Nsuch thatTμny∈Fδ(Tt) for ally∈Candn<δL for alln≥N. Sincep∈Fix(S), we
have
nf(zn) –Tμnzn≤nf(zn) –f(p)+f(p) –p+Tμnp–Tμnzn
≤n
αzn–p+f(p) –p+Azn–p
≤n
αzn–p+f(p) –p+zn–p
≤n
( +α)zn–p+f(p) –p ≤n
( +α)M+f(p) –p
=nL≤
δ
for alln≥N. Observe that
zn=nf(zn) + ( –n)Tμnzn =Tμnzn+n
f(zn) –Tμnzn
∈Fδ(Tt) +Bδ
⊆Fδ(Tt) + Bδ
⊆F(Tt)
for alln≥N. This shows that
zn–Ttzn ≤ (n≥N).
Step .S{zn} ⊂Fix(S), whereS{zn}denotes the set of strongly limit points of{zn}. Letz∈S{zn}, and let{znj}be a subsequence of{zn}such thatznj→z,
Ttz–z ≤ Ttz–Ttznj+Ttznj–znj+znj–z ≤znj–z+Ttznj–znj,
then by Step ,
Ttz–z ≤lim
j znj–z+limj Ttznj–znj= , thereforez∈Fix(S).
Step . There exists a unique sunny nonexpansive retractionPofC ontoFix(S) and
x∈Csuch that :=lim sup
n
x–Px,J(zn–Px)
≤. ()
By Lemma . there exists a unique sunny nonexpansive retractionPofContoFix(S). The Banach contraction mapping principle guarantees thatfPhas a unique fixed point
x∈C. We show that
:=lim sup
n
x–Px,J(zn–Px)
≤.
Note that from the definition ofand the fact thatCis a compact subset ofE, we can select a subsequence{znj}of{zn}with the following properties:
(i) limjx–Px,J(znj–Px)=;
(ii) {znj}converges strongly to a pointz.
By Step , we havez∈Fix(S). SinceEis smooth, we have
=lim
j
x–Px,J(znj–Px)
=x–Px,J(z–Px)≤.
SincefPx=x, we have (f –I)Px=x–Px. From Theorem ..(v) in [], forx,y∈Eand
f ∈J(y),x–y≥(x–y,f). Therefore, for eachn∈N, we have n(α– )zn–Px
≥nαzn–Px+ ( –n)zn–Px
–zn–Px ≥nf(zn) –f(Px)+ ( –n)Tμnzn–Px
–zn–Px ≥n
f(zn) –f(Px)+ ( –n)(Tμnzn–Px) – (zn–Px),J(zn–Px)
= –n
(f –I)Px,J(zn–Px)
= –n
x–Px,J(zn–Px)
.
Hence
zn–Px≤ –α
x–Px,J(zn–Px)
Step .{zn}strongly converges toPx.
Indeed, from (), () andPx∈Fix(S), we conclude
lim sup
n
zn–Px≤
–αlim supn
x–Px,J(zn–Px)
≤.
That is,zn→Px.
Remark . It would be an interesting problem to prove Theorem . for continuous
representations instead of nonexpansive.
Competing interests
The authors declare that they have no competing interests.
Authors’ contributions
All authors contributed equally and significantly in writing this article. All authors read and approved the final manuscript.
Author details
1Department of Mathematics, King Abdulaziz University, P.O. Box 80203, Jeddah, 21589, Saudi Arabia.2Department of
Mathematics, University of Isfahan, Isfahan, Iran. 3Department of Mathematics, Lorestan University, P.O. Box 465, Khoramabad, Lorestan, Iran.
Acknowledgements
This article was funded by the Deanship of Scientific Research (DSR), King Abdulaziz University, Jeddah. The first author acknowledges with thanks DSR, KAU for financial support. The authors would like to thank the referee of the paper for his helpful comments and invaluable suggestions. This research was supported by the Center of Excellence for Mathematics and the Office of Graduate Studies of the Lorestan University and the University of Isfahan.
Received: 31 August 2014 Accepted: 12 November 2014 Published:04 Dec 2014 References
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