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A Weaker Constraint Qualification of Globally Convergent

Homotopy Method for a Multiobjective

Programming Problem

Guangming Yao1, Wen Song2

1Department of Mathematics, Clarkson University, Potsdam, USA 2Department of Mathematics, Harbin Normal University, Harbin, China

Email: [email protected], [email protected]

Received September 29, 2012; revised January 9, 2013; accepted January 16, 2013

ABSTRACT

In this paper, we prove that the combined homotopy interior point method for a multiobjective programming problem introduced in Ref. [1] remains valid under a weaker constrained qualification—the Mangasarian-Fromovitz constrained qualification, instead of linear independence constraint qualification. The algorithm generated by this method associated to the Karush-Kuhn-Tucker points of the multiobjective programming problem is proved to be globally convergent.

Keywords: Multiobjective Programming Problem; Homotopy Method; KKT Condition; Efficient Solution; MFCQ

1. Introduction

Let be the -dimensional Euclidean space, and let and denote the nonnegative and positive , respectively. For any two vectors 1 2

n

n

n

n



n

, n

, ,

yy y

,n

y

and 1 2 in , we use the following conventions: i i . Similarly, we can define , and

, , ,z zn

iff

y

n

z i

z z

 

y z

,

y z

, y 1, 2,

  

z yz.

Consider the following multiobjective programming problem (MOP)

 

 

 

min

. . 0, 0,

f x

s t g xh x

where

T 1 2

T

1 2 1 2

, , , , ,

, , , , , , ,

n

p

m

x f f f f

g g g g h h h h

 

 

 

T

.

s

We assume that all f ii, 1, , , p gj,j

1, 2, , .

I and

are twice continuously differentiable functions, where

, k

h kJ

1, 2, ,

,

I   m J  s

Let

 

 

 

 

 

1

1

: 0,

: 0 ,

: 1 ,

: : 0 .

n

n

p p

i i

j

x g x h x

x g x

I x j I g x

 



 

    

   

 

    

 

  

0 ,

It is well known that if x is an efficient solution of

(MOP), under some constraint qualifications, such as the Kuhn and Tucker constraint qualification (see Ref. [2]) or the Abadie constraint qualification (see Ref. [3]), then the following Karush-Kuhn-Tucker (KKT) condition at

x for (MOP) holds (see Refs. [4,5]):

 

 

 

 

 

T T T

0 0

0

f x g x u h x v

Ug x

h x

     





(1)

where p\ 0 ,

 

m, ,

u v

  s and

1 2

diag , , , m .

Uu uu

We say that x is a KKT point of (MOP) if it satisfies

the KKT condition.

Since the remarkable papers of Kellogg et al. (Ref. [6])

and Chow et al.(Ref. [7]) have been published, more and

more attention has been paid to the homotopy method. As a globally convergent method, the homotopy method (or path-following method) now becomes an important tool for numerically solving nonlinear problems include- ing nonlinear mathematical programming and comple- mentarily problems (see Refs. [3,4]).

In 1988, Megiddo (see Ref. [8]) and Kojima et al. (see

(2)

methods, one of the main ideas is numerically tracing the center path generated by the optimal solution set of the so-called logarithmic barrier function. Usually, the strict convexity of the logarithmic barrier function or non- emptiness and boundedness of the feasible set (see Ref. [10]) are needed. In 1997, Lin, Yu and Feng (see Ref. [11]) presented a new interior point method—combined homotopy interior point method (CHIP method)—for convex nonlinear programming without such assump- tions. Subsequently, Lin, Li and Yu (see Ref. [12]) generalized CHIP method to general nonlinear program- ming where, instead of convexity condition, they used a

more general “normal cone condition”.

In 2003, Lin, Zhu and Sheng (see Ref. [13]) general- ized CHIP method to convex multiobjective program- ming(CMOP) with only inequality constraints. Instead of (CMOP), they considered an associated non-convex non- linear scalar optimization problem and constructed the homotopy mapping.

In Refs. [1,14], we considered a combined homotopy interior point method for the multiobjective programm- ing (MOP) under the condition linearly independent constraint qualification (LICQ). To find a KKT point of (MOP), we construct a homotopy as follows

 

 

 

 

 

 

 

T T T 0

0

0 0

2 5 2 5 0

1

1

0 , ,

1 1 p i

i

f x g x u h x v x x

h x

H Ug x U g x

e

  

  

    

   

 

 

 

  

 

    

   

(2)

where 0

0, 0, ,0 0

m

 

0 ,

1,1, ,1

T p,

x u v R e R

  



       

, , ,

p m s,

 

0,1 ,

x u v R R

   



    

2 5 2 5

 

0 2 5

 

0 2 5

 

0 2 5

1 , p , and 1 , p .

2 5        

Let

  

0

1 0 , p m s 0,1 : , 0,

H H

     

 



    0 .

Let n

A be a nonempty closed set and xA.

We recall that the Fréchet normal cone of A at x is

defined as

 

lim sup , 0 .

A

n A

x x

x x x

N x x

x x

 

 

   

 

   

  

We used the following basic assumptions which are commonly used in that literature:

(A1)  is nonempty (Slater condition) and bounded;

(A2) (LICQ)   x , the matrix

 

 

 

T T

, j :

h x g x j I x

  

is a matrix of full column rank; (A3) Normal condition:

 

ˆ

 

, .

x x N x x

     

It is well known that if condition (A2) holds, then

 

 

 

 

 

ˆ : 0, , s . (3)

i i j j i

i I x j J

N x u g x v h x u i I x v

 

 

 

       

 

 

,

We have proved the following convergence result in Ref. [1].

Theorem 1.1 (Convergence of the method) Suppose

,

i j

f g and k are twice continuously differentiable

functions such that the conditions (A1), (A2), and (A3) hold. Then for almost all

h

0 m s,

R R

 



     

the zero-point set H01

 

0 of the homotopy map (2)

contains a smooth curve 0

0,1 ,

p m s

R

  

   

which starts from

0,1 . As

 

0

 

0 0

p m s

T  R   of is nonempty, and the

-x component of every point in T is a KKT point of

(MOP).

Recently, many researchers extended and improved the results in Ref. [1] to convex multiobjective pro- gramming problem, see Ref. [14-17]. The purpose of this paper is to show that Theorem 1.1 remains true under the condition MFCQ instead of LICQ. The paper is organi- zed as following. In Section 2, we prove the existence and convergence of a smooth homotopy path from almost any interior initial point 0 to a solution of the

(3)

KKT system of (MOP) under the condition MFCQ.

2. Main Results

We need the following elementary condition.

(A2′) (MFCQ) For every x , the following

conditions hold:

 hj

 

x , ,jJ are linear independent;

 there exists a n

pR such that

 

 

0,gi x piI x and hj

 

x p0,jJ.

Clearly, condition (A2) implies (A2′). It is also known

that if (A2′) holds, then (3) remains valid.

By using an analogue argument as in Ref. [1], we can prove the following two theorems.

Theorem 2.1 Suppose that and conditions

(A1), (A2′) hold. Then for almost all initial points

  

 

0 m 0 , 0

 



     is a regular value of H0

and 0

 

1 0

H consists of some smooth curves. Among

them, a smooth curve, say 0 starts from

 

0,1 .

Theorem 2.2 Suppose that and conditions

(A1), (A2′) hold. For a given if 0 is a regular value of

  

0

    m s,



  

0

H

 , then the projection of the

smooth curve 0 on the component is bounded.

We next prove that 0 is a bounded curve.

Theorem 2.3 (Boundedness) Suppose that the con- ditions (A1), (A2′), and (A3) hold. Then for a given

0 m ,

 



    s

if 0 is a regular value of H0,

then 0 is a bounded curve.

Proof: By Theorem 2.2, it is sufficient to show that the component of smooth curve is bounded. Suppose

 

u v,

-that there exists a sequence

,

0, k

k

   

such that

, ,

k k

k

xx    

and

k, k

,

u v   k 

where x , 0,1 , 0.

 

 

m s R

Since closed unit

circle of is compact, without loss of generality we can assume that

 

,

lim , .

,

k k

k k k

u v

u v u v

 

 

Clearly, u0, ,

u v 

1. By (2), we have

 

 

 

T T

T 0

1

0,

k k k k

k

k k k

k

f x g x

h x v x x

 

   

   

u

(4)

 

0

 

0 0.

k k k

U g x U g x (5)

Let

 

 

1

2

: lim ,

: lim .

k i k

k j k

I x i I u

I x j J v





   

   

By (5), we know I1

   

x I x .

Rewrite (4) as

 

 

 

 

 

 

T

T 0

1

0.

k k k k

k i i

i I x

k k k k k

i i k

i I x

f x u g x

u g x h x v x x

 

 

   

 

 

     

 

(6)

Divide (6) by

k, k

u v and let k , since

k, k

u v  , (6) becomes

 

T

 

T

1 0

I I

g x  uh xv ,

     (7) where

 

 

 

 

: ,

: .

I i

I i

g x g x i I x

u u i I x

  

  

  

 

1) If uI 0,

then 0,and

 

0. By u h x Tv

(A2′), v0. This is a contradiction with

u v, 

1.

2) If uI 0,

we consider the following two cases:

1. If 

0,1

, we know

1

uI0 because of

0.

I

u  By (A2′), there exists a nonzero vector

such that

,

n pR

 

T

 

T

T 0 and T 0.

I

pg x  ph x 

,

(8) This, together with (7), implies that

which is a contradiction.

1  uI 0  

 

2. If 1, by (7) and (A2′), we know v0. So, 1

u  since

u v, 

1.

Because of (5), I1

   

x I x  . Thus

1, ,

k

i .

x  u   k   i I

Without loss of generality, we can assume that

0, 1 ,and lim .

k

k I

I k k k

I

u

u k N

u



    u

Hence u0, u 1.

a) If I2

 

x

 , then

k

is bounded. We may

v

assume lim k .

kvv Divide (6) by

1

k k uI

 and let ,

(4)

 

 

T

T 0

1

lim 0.

1

I

k k k

k k

k

k I

g x u

h x v x x

u

 



 

 

   

 

 

 (9)

This implies that

1

lim

1 k

k

k uI



exists. Indeed,

 

 

T 0

T 0

lim

.

k k k

k

k h x v x x

h x v x x

 

 

  

 

 

   

If

 

T 0

0,

h xv xx

  

that is

 

T 0

.

h xv xx

  

By condition (A3), 0.

xx This is impossible since

. So

x 

 

T 0 0.

h xv xx

   

By (9), we then have that

1 lim

1 k

k

k uI

 exists.

Assume

1

lim .

1 k

k

k uI

 



Then 0. 0

If  , (9) becomes

 

T

 

T 0

.

I u

g x h x v x

  

    x

This contradicts to condition (A3). If 0, (9) becomes

 

T 0. I

g xu

 

By (A2′), there exists a nonzero vector such

that

n pR

 

T

 

T

0, and 0.

I I

g xp p g xu

   

Thus u0, which contradicts u 1.

b) If 2 , without loss of generality, we can

assume that

 

I x  

 

1 ,

ˆ ˆ

lim , ,

1 ,

k k k I

k k k

k I

u v

u v u v

 



 

where

 

ˆ ˆ, = 1. Since

1 k, k

as

k u vI k

 ,

     (10)

we divide (4) by

1

k, k

k u vI

 , and let k , we have that

 

T

 

T

ˆ ˆ 0.

I

g xu h xv

    (11) If uˆ 0, then

 

T

ˆ 0.

h xv

 

By condition (A2′), ˆ 0.v This is a contradiction

since

 

u vˆ ˆ, 1.

If ˆ 0,u by (A2′), there is a nonzero vector

such that

n

pR

 

T

 

T

T 0,and T 0.

I

pg x  ph x 

This, together with (11), implies This is a contradiction.

ˆ 0.

u

Therefore, 0 is a bounded curve.

By an analogue argument as in Ref. [1], it is easy to show the following result.

Theorem 2.4 (Convergence of the method) Suppose that the conditions (A1),(A2′), and (A3) hold. Then for almost all 0    ms, the zero-point set

 

0

1 0

H of the homotopy map (2) contains a smooth curve

0 0,1 ,

p m

 

    which starts from

 

0,1 . As

0,

  the limit set

 

0 p m

 

0

T    of 0

is nonempty, and every point in T is a solution of (1).

Therefore, Theorem 2.4 shows that for almost all

 

0 p m s 0 ,

 



    the homotopy Equation (2) generates a smooth curve 0 starts from

 

0,1

which is called the homotopy path, the limit set

 

0

 

0 0

p m s

T  R   of  is nonempty, and

the x-component of every point in is a KKT point of

(MOP), the

T

-component

 of the homotopy path is the solution of (1) as  goes to 0.

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