R E S E A R C H
Open Access
Infinitely many solutions for
p
-harmonic
equation with singular term
Huazhao Xie
1*and Jianping Wang
2*Correspondence:
1Department of Mathematics,
Henan University of Economics and Law, Zhengzhou, 450002, China Full list of author information is available at the end of the article
Abstract
In this paper, we study the followingp-harmonic problem involving the Hardy term:
(|
u|p–2u
)
–λ
|u| p–2u|x|2p =f(x,u), in
, u=
∂
u∂
n= 0 on∂
,where
is an open bounded domain containing the origin inRN, 1 <p<N 2 and
0≤
λ
< [N(p– 1)(N– 2p)/p2]p. By using the variational method, we prove that theabove problem has infinitely many solutions with positive energy levels.
AMS Subject Classification: 35J60; 35J65
Keywords: infinitely many solutions;p-harmonic; Hardy term
1 Introduction
The main purpose of this paper is to show the existence of infinitely many solutions for the followingp-harmonic equation:
⎧ ⎨ ⎩
(|u|p–u) –λ|u||p–u
x|p =f(x,u), x∈, u=∂u
∂n= , x∈∂,
(.)
whereis an open bounded domain containing the origin inRN, the boundary∂is smooth. <p<N
, ≤λ<λ= [N(p– )(N– p)/p ]p. ∂
∂n is the outer normal derivative. Nonlinearityf(x,u) satisfies the following conditions:
(f)f(x,u) is continuous on×Rand limits subcritical growing at infinity; that is,
lim
u→∞ f(x,u)
|u|p*–= , uniformly forx∈, (.)
wherep*=Np/(N– p) is the critical exponent of Sobolev’s embeddingW,p
()→Ls().
(f) For anyx∈,f(x,u) satisfies
lim
u→
f(x,u)u
|u|p = and ulim→∞ f(x,u)u
|u|p = +∞. (.)
(f) DenoteG(x,t) =f(x,t)t–p
t
f(x,s)ds. For allx∈, there exists a constantM≥
such that
G(x,t)≤G(x,t) for anyM≤ |t| ≤ |t|. (.)
(f)f(x,u) is odd with respect tou.
By the Hardy-Rellich inequality (see [, ]), we know that
|u|p |x|pdx≤
λ
|u|pdx. (.)
Obviously, for anyλ∈[,λ),
–λ λ
|u|pdx≤
|u|p–λ|u| p
|x|p
dx≤
|u|pdx.
InW,p(), forλ∈[,λ), we define
u=uW,p
():=
|u|p–λ|u| p
|x|p
dx
p
,
this norm is equivalent to (|u|pdx)/p.
A weak solution of the problem (.) is a critical point of the energy functional
I(u) =
p
|u|p–λ|u| p
|x|p
dx–
F(x,u)dx, u∈W,p(), (.)
whereF(x,u) =uf(x,s)ds. It is easy to check thatI(u) is a continuous even functional. Biharmonic equations can describe the static form change of a beam or the sport of a rigid body. For example, this type of equation furnishes a model for studying traveling wave in suspension bridges (see []). By using variational arguments, many authors investigated nonlinear biharmonic equations under Dirichlet boundary conditions or Navier boundary conditions and got interesting results (see [–]).
Li and Squassina in [] considered the superlinearp-harmonic equation with Navier boundary conditions
|u|p–u=f(x,u), in, u=u= on∂, (.)
whereis an open bounded domain inRNwith a smooth boundary∂.p> ,N≥p+ andf:×R→Ris a Carathéodory function such that for some positive constantC,
f(x,u)≤C +|u|q– for allq∈,p*. (.)
By means of the Morse theory, they proved the existence of two nontrivial solutions to (.). After that, Li and Tang [] considered a more general problem than (.). They got three solutions by the three critical points theorem which was obtained in []. If
The authors in [] considered thep-harmonic equation with Dirichlet conditions and obtained the existence of a nontrivial solution. Under the condition of (.), [] proved the existence and multiplicity of weak solutions for the nonuniformly nonlinear problem
a(x,u)=f(x,u), in, u=∂u
∂n= on∂, (.)
where|a(x,t)| ≤c(h(x) +h(x)|t|p–) withh(x)≥,h(x)≥.a(x,t) andf(x,t) are odd
with respect to the second variable. Furthermore, f(x,t) is subcritical and satisfies the Ambrosetti-Rabinowitz condition, that is, there exists a constantθ>psuch that
<θ
t
f(x,s)ds≤f(x,t)t for anyx∈. (.)
The aim of this paper is to obtain infinitely many solutions for the problem (.) when p<N. The main difficulty lies in the fact that the embeddingsW,p()→Lp*() and
W,p()→Lp(,|x|–pdx) are not compact. Furthermore, the assumption (f) is not the
usual subcritical growth (.). The condition (f) is weaker than the A-R condition (.).
We use the concentration compactness principle (see [, ]) to overcome those difficul-ties. The following theorem is our main result.
Theorem . Assume f(x,u)satisfies(f)-(f),then the problem(.)possesses infinitely many weak solutions and the corresponding critical values are positive.
This paper proceeds as follows. In the next section, we prove the energy functionalI(u) satisfies the Palais-Smale condition. In Section , by using the symmetric mountain pass theorem (see []), we get the main result of this paper. Throughout the paper, denote
Sp,λ:= inf u∈W,p()\{}
up upp*
.
We useuq= (|u|qdx)/qto denote the norm ofLq(),C,C
istand for universal con-stants. We omitdxandin the integrals if there is no other indication.
2 Palais-Smale condition
To show the (PS) sequence{un}of the variational functionalI(u) is compact inW,p(), we first prove the boundedness of{un}by the analytic argument which has been used in []. Then, using the concentration compactness principle, we get the compactness of{un}.
Lemma . The condition(f)implies that for anyε> ,there exists a positive constant Cεsuch that
F(x,u)≤ε|u|p*+Cε|u|, (x,u)∈×R. (.)
(f)implies that F(x,u) =o(up)as u→.Furthermore,for any|u| ≥M> ,there exists a small positive constantθ
Lemma . Under the conditions(f), (f)and(f),if the sequence{un} ∈W,p()satisfies
I(un)→c, I(un)→ as n→+∞, (.)
then the sequence{un}is bounded in W,p().
Proof We prove this lemma by contradiction. Without loss of generality, we assume that
un →+∞ asn→+∞. (.)
Setwn=un/un, thenwn= for anyn∈N. Asn→+∞, there existsw∈W,p() such
that
wn w weakly inW,p(),
wn→w strongly inLs() for any ≤s<p*,
wn→w a.e.x∈.
Ifw ≡, we denote={x∈:w= }, set\is nonempty. (.) implies that
unp–
f(x,un)undx=o().
Therefore,
–o() =
f(x,un)un unp dx=
f(x,un)un unp dx+
\
f(x,un)un
unp dx. (.)
Asn→+∞,|un|pdx≤ un →. So,|un| →+∞forx∈\
. It follows from (f)
that
lim
un→∞
f(x,un)un unp =unlim→∞
f(x,un)un |un|p |wn|
p= +∞.
Since|\|> , then
\
f(x,un)un
unp dx→+∞ asn→+∞. (.)
Using (.) and (.), we derive that
f(x,un)un unp dx=
unp
(|un|>M)
· · ·+
(|un|≤M)
· · ·
≥–
unp
(|un|≤M)
f(x,un)undx
≥– C
unp M+M p*|
|
From (.) and (.), we get
f(x,un)un
unp dx→+∞ asn→+∞. (.)
This contradicts (.).
Ifw≡, thenwn→ strongly inL(). SinceI(un)→c, we know that
c← pun
p–
F(x,un)dx≥
pun
p–ε
|un|p*dx–Cε
|un|dx. (.)
In (.), chooseε= , then
pun
p≤ unp*
p*+Cun+c≤Cunp
*
p*+c.
From (.), it follows thatunp*→+∞asn→+∞. Denote
An=M
un
unp* ≥
MS/p,pλ, (.)
whereMis any fixed positive constant. It is clear that
An un=
M
unp* → (asn→+∞).
Therefore, fornlarge enough,An/un ∈(, ).
For everyn∈N, we define a sequence oftnas follows:
I(tnun) = max t∈[,]I(tun).
We claim that
I(tnun)→+∞ (asn→+∞). (.)
In fact, by (.)-(.) and the definition oftn, we have
I(tnun)≥I
An unun
≥
pA
p
n–ε
An unun
p
*
dx–CεAn
|wn|dx
=
pA
p n–εMp
*
–CεAn
|wn|dx.
IfAn→+∞asn→+∞, then (.) follows from the above estimate. IfAnis bounded for anyn, that is, there exists a constantK> such thatAn≤K, then
I(tnun) ≥
pA
p n–εMp
*
–CεAn
|wn|dx≥ pSp,λM
p–εMp*–C εK
|wn|dx
→
pSp,λM
where we use the fact thatwn→ asn→+∞. The positive constantεis arbitrary,
thus
lim
n→+∞I(tnun)≥
pSp,λM
p for any positive constantM.
(.) follows from the above inequality. From (.), we know that
pc+o() =pI(un) –
I(un),un
= f(x,un)un–pF(x,un)
dx. (.)
By the definition oftn, we obtain dtdI(tun)|t=tn= andtn∈[, ], then|tnun| ≤ |un|. The
condition (f) and (.) derive that
f(x,un)un–pF(x,un)
dx ≥ f(x,tnun)tnun–pF(x,tnun)
dx
= pI(tnun) –
I(tnun),tnun
= pI(tnun) –tn
d dtI(tun)
t=tn
→+∞.
Which is a contradiction to (.). Therefore, the sequence{un}is bounded inW,p().
Under the conditions of Lemma ., we knowun ≤C. Therefore, there exists a sub-sequence, still denoted by{un}, and someu∈W,p() such that
un u weakly inW,p(),
un u weakly inLp ,|x|–pdx
,
un→u strongly inLs() for any ≤s<p*,
un→u a.e.x∈.
Obviously,uis a weak solution of (.). Now we prove thatu ≡. According to the con-centration compactness principle (see [, ]), there exists a subsequence, still denoted by{un}, at most countable setJ, a set of different points{xj}j∈J⊂\ {}and two positive number sequences{μj}j∈J∪{},{νj}j∈J∪{}such that
|un|p dμ≥ |u|p+ j∈J
μjδxj+μδ weakly in the sense of measure,
|un|p* dν=|u|p*+ j∈J
νjδxj+νδ weakly in the sense of measure,
|un|p
|x|p dγ= |u|p
|x|p+γδ weakly in the sense of measure,
Sp,λν p p*
≤μ–λγ, and Sp,ν p p*
j ≤μj forj∈J,
Lemma . Assume f(x,u)satisfies(f),the sequence{un}is bounded in W,p()and sat-isfies(.).Then the set J={x,x, . . . ,xj} ⊂is finite,μ–λγ= .
Proof We first prove thatμj= for anyxj∈J.
Letε> be small enough such that /∈Bε(xj) andBε(xi)∩Bε(xj) =∅fori=j.φj(x)∈[, ] is a cutting-off function inC∞().φj(x)≡ for|x–xj|<ε/,φj(x)≡ for|x–xj| ≥ε, and |φj| ≤/ε. Since
I(un),unφj
=
|un|pφjdx+
|un|p–un∇un∇φjdx
+
un|un|p–unφjdx
–
λ|un| p
|x|pφjdx–
f(x,un)unφjdx, (.)
we deduce that
lim
ε→n→+∞lim
|un|pφ
jdx=lim ε→
φjdμ≥lim ε→
|u|pφ
jdx+μj=μj,
lim
ε→n→+∞lim
||uxn||ppφjdx
≤lim
ε→n→+∞lim
Bε(xj)
|un|p
(|xj|–ε)p|φj|dx= ,
lim
ε→n→+∞lim
|un|p*φ
jdx=lim ε→
|u|p*φ
jdx+νj=νj, (.)
lim
ε→n→+∞lim
|un|φjdx=lim ε→
|u|φjdx= . (.)
By Hölder’s inequality,
lim
ε→n→+∞lim
|un|p–un∇un∇φjdx
≤lim
ε→n→+∞lim un
p–
Lp(B
ε(xj))∇unLNp/(N–p)(Bε(xj))∇φjLN(Bε(xj))
≤Clim
ε→un
p Lp(B
ε(xj))= ,
lim
ε→n→+∞lim
|un|p–ununφjdx
≤lim
ε→n→+∞lim un p–
Lp(B
ε(xj))unLp*(Bε(x
j))φjLN/(Bε(xj))
≤Clim
ε→unLp*(B ε(xj))= .
Using (f), (.) and (.), we have
lim
ε→n→+∞lim f(x,un)unφjdx≤εlim→n→+∞lim
ε
|un|p*φjdx+Cε
|un|φjdx
= .
By the above estimates, (.) becomes
=lim
ε→n→+∞lim
I(un),unφj
≥μj. (.)
If the concentration is at the origin, letφ(x)∈[, ] be a cutting-off function inC∞().
φ(x)≡ for|x|<ε/,φ(x)≡ for|x| ≥ε, and|φ| ≤/ε. Chooseε> small enough
such thatxj∈/Bε() for allj∈J. Then
lim
ε→n→+∞lim
|un|pφdx=lim
ε→
φdμ≥lim
ε→
|un|pφdx+μ=μ, (.)
lim
ε→n→+∞lim
||uxn||ppφdx
=lim
ε→
Bε(xj)
|u|p
|x|p|φ|dx+γ=γ. (.)
Similarly, we can get
lim
ε→n→+∞lim
|un|p–un∇un∇φ+|un|p–ununφj
dx= , (.)
lim
ε→n→+∞lim f(x,un)unφdx= . (.)
From equalities (.)-(.), we get
=lim
ε→n→+∞lim
I(un),unφ
≥μ–λγ. (.)
On the other hand,μ–λγ≥Sp,λν p p*
≥, thusμ–λγ= . The proof is complete.
Lemma . Assume f(x,u)satisfies(f),the sequence{un}satisfying(.)is bounded in W,p().Then there exist some u∈W,p()and a subsequence,still denoted by{un},such that
un→u strongly in Lp
*
(),
∇un→ ∇u strongly in L
Np N–p(),
where=\ji=B(xi),xi∈J={x,x, . . . ,xj} ∪ {}.
Proof Lemma . implies thatJis finite. Chooseϕ∈C∞ () withϕ(xi) = for anyxi∈
J∪ {}. Then
|ϕun|p*dx=
|ϕu|p*dx+ j
i=
νiϕp
*
(xi) +νϕp
*
()
=
|ϕu|p*dx. (.)
Sinceϕun→ϕua.e. in, we get that
un→u strongly inLp
*
().
Similarly,
∇un→ ∇u strongly inL
Np
By using the Lebesgue decomposition theorem, we have
dμ–λdγ =|u|p–λ|u| p
|x|p +dσ, (.)
where (|u|p–λ|u|p|x|–p)⊥dσ. Thendσ≥j∈Jμjδxj+ (μ–λγ)δ.
Lemma . Assume f(x,u)satisfies(f)-(f),the sequence{un} ∈W,p()satisfies(.). Then there exist u∈W,p()and a subsequence,still denoted by{un},such that un
con-verges to u strongly in W,p().
Proof We first prove that
σ– j∈J
μjδxj– (μ–λγ)δ
() = . (.)
Claim for any closed setF⊂\J,J=J∪ {},σ(F) = . In fact, denoter=dist(F,J) > . Then, by using a finite covering theorem, there exist finite open ballsBr/(zi), withzi∈F,
i= , . . . ,m, such thatF⊂mi=Br/(zi)⊂\J. Let(t) be a smooth cutting-off function. ≤(t)≤ for anyt∈[,∞).(x)≡ for ≤t≤/, and≡ fort≥. Denoteηε,y= (|x–y|/ε), then
RN|∇
ηε,y|Ndx=
/
(t)Ndt=C, (.)
RN|
ηε,y| N
dx:=
/
(t)N dt=C
. (.)
The sequence{ηε,yun}is still bounded inW,p(). Define
η(x) = m
i=
ηr/,zi(x), (.)
thenη(x)∈C∞(\J) and ≤η(x)≤m. Furthermore,
F⊂
m
i= Br
(zi)⊂sptη(x)⊂r, (.)
wheresptη(x) denotes the support ofη(x). Asn→+∞, (.) implies
←I(un) –I(u), (un–u)η
=
η |un|p–|un|p–unu–|u|p–uun+|u|p
dx
–λ
η |x|p |un|
p–|un|p–u
nu–|u|p–uun+|u|p
dx
+
∇η∇(un–u)|un|p–un–|u|p–u
dx
+
η(un–u) |un|p–un–|u|p–u
–
η(un–u)f(x,un) –f(x,u)
dx
= I+II+III+IV+V.
Asn→+∞,
I+II=
η |un|p–|un|p–unu–|u|p–uun+|u|p
dx –λ η |x|p |un|
p–|un|p–u
nu–|u|p–uun+|u|p
dx = η
|un|p–|u|p–λ|un| p–|u|p
|x|p
dx+o()
=
ηdσ+o(),
where we have used (.). Lemma . implies thatun ≤M. Hölder’s inequality, (.)-(.) and Lemma . deduce that
|III|=
∇η∇(un–u) |un|p–un–|u|p–u
dx
≤C
|un|p+|u|pdx∇ηN
spt(η)
∇(un–u)
Np N–pdx
N–p Np
≤C(m,M,p)C
r
∇(un–u)
Np N–pdx
N–p Np
→ asn→+∞,
|IV|=
(un–u)η |un|p–un–|u|p–u
dx
≤C(m,M,p)C
r
|un–u|p
*
dx
p*
→ asn→+∞.
By (.), for anyε> , we have
|V| =
f(x,un) –f(x,u)
(un–u)ηdx
≤
f(x,un)+f(x,u)|un–u|ηdx ≤
Cε+ε |un|p
*–
+|u|p*–|un–u|ηdx
≤ Cε
|un–u|ηdx+ε unp
*–
p* +u
p*–
p*
spt(η)
|un–u|p
*
dx
p*
≤ Cε
|un–u|dx+εC(M)
Therefore, asn→+∞,
≤σ(F)≤σ spt(η)≤
ηdσ≤ |III|+|IV|+|V|= . (.)
Since the setFis arbitrary, (.) is obtained.
Lemma . means thatμj= for anyj∈Jandμ–λγ= , soσ() = , which implies
that asn→+∞,
|un|p–λ|un| p
|x|p
dx→
|u|p–λ|u| p
|x|p
dx. (.)
Together withun→ua.e. in, we complete the proof.
3 The proof of the main result
In this section, by using the following symmetric mountain pass theorem (see []), we give the proof of Theorem ..
Lemma .(Symmetric mountain pass theorem) Assume functional I satisfies the follow-ing conditions:
() I∈C(W,p
(),R)is even and satisfies the Palais-Smale condition.
() There exists a finite dimensional subspaceX∈W,p()such thatI|X∩∂Br≥a> . () There exists a sequence of the finite dimensional subspace{Xj},dim(Xj) =jandrj>
such that
I(u)≤ for anyu∈Xj\Brj,j= , , . . . .
Then I has infinitely many different critical points,and the corresponding energy values are positive.
Proof of Theorem . We know the energy functional I(u) is continuous and even. Lemma . implies thatI(u) satisfies the PS condition inW,p(). In any finite dimen-sional subspaceX⊂W,p(), all norms are equivalent. For anyu∈X, sinceF(x,u) =o(up) asu→, there exists a constantq>psuch that
I(u) =
p
|u|p–λ|u| p
|x|p
dx–
F(x,u)dx
≥
pu
p–Cuq> forusmall enough. (.)
Thus, there existsr> such thatI|X∩∂Br ≥a> . On the other hand, by using (.), we
have
I(u) =
p
|u|p–λ|u| p
|x|p
dx–
F(x,u)dx
≤
pu
p–C
{x∈:|u|>M}
|u|p+θdx–C
≤
pu
p–Cup+θ
There exists a sequence of the finite dimensional subspace{Xj},dim(Xj) =jandrj> such that
I(u)≤ for anyu∈Xj\Brj,j= , , . . . .
Finally, all the assumptions of Lemma . are satisfied. Hence, the problem (.) possesses infinitely many weak solutions, and the corresponding critical values are positive.
Remark . Under the same conditions of Theorem ., we can also prove that the fol-lowingp-harmonic type equation with Navier boundary conditions:
⎧ ⎨ ⎩
(|u|p–u) –λ|u|p–u
|x|p =f(x,u), x∈,
u=u= , x∈∂,
(.)
has infinitely many solutions{un} ∈W,p()∩W,p
(), wherecontaining the origin
is an open bounded domain inRN,∂is smooth. <p< N
, ≤λ<λ= [N(p– )(N–
p)/p]p.
Remark . All the results obtained above obviously hold if we choosef(x,u) =|u|q–u+
|u|r–uwithp<q<r<p*.
Competing interests
The authors declare that they have no competing interests.
Authors’ contributions
HX carried out the existence of infinitely many solutions for thep-harmonic equation studies and drafted the manuscript. JW participated in its coordination. All authors read and approved the final manuscript.
Author details
1Department of Mathematics, Henan University of Economics and Law, Zhengzhou, 450002, China.2College of
Information and Management Science, Henan Agricultural University, Zhengzhou, 450002, China.
Acknowledgements
The authors are thankful to the referees for their helpful suggestions and necessary corrections in the completion of this paper. This research is supported by the Education Department of Henan Province (12B110002) and NSF of China (61143002).
Received: 19 May 2012 Accepted: 13 November 2012 Published: 6 January 2013 References
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doi:10.1186/1029-242X-2013-9