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(1)

Cross hedging with stochastic correlation

Gregor Heyne

(joint work with Stefan Ankirchner)

Humboldt Universit ¨at Berlin, QPL

March 20th, 2009

Finance and Insurance, Jena

(2)

Motivation

Consider a call option on the DAX.

How to hedge?

(3)

Motivation

0 20 40 60 80 100 120 140 160 180 4000 4500 5000 5500 6000 6500 7000 7500 Days to maturity DAX − FDAX Dax FDax
(4)

Related literature

Henderson, 2002, Valuation of claims on nontraded assets using

utility maximization;

Musiela, Zariphopoulou, 2004, An example of indifference prices

under exponential preferences;

Davis, 2006 , Optimal hedging with basis risk;

(5)

Motivation

40 60 80 100 120 140 160 180 0.85 0.9 0.95 1 Days to maturity Correlation
(6)

Modelling correlation

Direct modelling with Jacobi process:

d

ρ

t

=

κ

(

ϑ

ρ

t

)

dt

+

α

p

(

1

(

ρ

t

)

2

W

ˆ

t

, with

α

,

κ

>

0,

ϑ

(

1

,

1

)

Indirect modelling with OU process:

Set

ρ

t

=

b

1

(

U

t

)

, with

dU

t

=

a

(

ϑ

U

t

)

dt

+

σ

U

d

W

ˆ

t

,

where a

>

0,

ϑ

R

,

σ

U

>

0 and b

: (

1

,

1

)

R

continuous

bijection.

(7)

The Model

We want to hedge the contingent claim H

=

h

(

I

T

)

by trading the asset

X .

dX

t

=

X

t

((

µ

X

r

)

dt

+

σ

X

dW

t

1

)

dI

t

=

I

t

((

µ

I

r

)

dt

+

σ

I

(

ρ

t

dW

t

1

+

q

1

ρ

2

t

dW

t

2

))

d

ρ

t

=

a

(

ρ

t

)

dt

+

g

(

ρ

t

)

d

W

ˆ

t

(8)

FS decomposition via BSDEs

El Karoui, Peng, Quenez, 1997:

The FS decomposition of H

=

h

(

I

T

)

is given by

h

(

I

T

) =

Y

0

+

Z

T

0

Z

s

1

σ

X

X

s

dX

s

+

Z

T

0

Z

2

s

dW

s

2

+

Z

T

0

Z

3

s

dW

s

3

,

where Y and Z are determined by

Y

t

=

h

(

I

T

)

Z

T

t

Z

s

dW

s

Z

T

t

Z

s

1

µ

X

r

σ

X

ds

,

for 0

t

T .

(9)

Explicit solution of linear BSDE

The solution of

Y

t

=

h

(

I

T

)

Z

T

t

Z

s

dW

s

Z

T

t

Z

1

s

µ

X

r

σ

X

ds

,

is given by

Y

t

= ˜

IE

[

h

(

I

T

)

|

F

t

]

and

Z

t

=

σ

(

t

,

I

t

,

ρ

t

)

x

ψ

(

t

,

I

t

,

ρ

t

)

v

ψ

(

t

,

I

t

,

ρ

t

)

,

where

ψ

(

t

,

x

,

v

) = ˜

IE

[

h

(

I

T

t,x,v

)]

.

(10)

Technical details

ψ

(

t

,

x

,

v

) = ˜

IE

[

h

(

I

T

t,x,v

)]

1

Under which conditions is

ψ

(

t

,

x

,

v

)

differentiable with respect to

x and v ?

2

Under which conditions are I

t,x,v

and

ρ

t,v

differentiable with

respect to x and v ?

(11)

Differentiability of I and

ρ

Denote

dv

d

ρ

s

t,v

and

dv

d

I

t,x,v

s

by

ρ

¯

t,v

s

and

¯

I

t,x,v

s

. Then

¯

ρ

t,v

s

=

1

+

Z

s

t

a

(

ρ

t,v

u

ρ

t,v

u

du

+

Z

s

t

g

(

ρ

t,v

u

ρ

t,v

u

d

W

ˆ

u

,

¯

I

t,x,v

s

=

Z

s

t

¯

I

t,x,v

u

((

µ

I

r

)

du

+

σ

I

(

ρ

u

t,v

dW

u

1

+

q

1

(

ρ

u

t,v

)

2

dW

u

2

))

+

Z

s

t

I

u

t,x,v

σ

I

ρ

u

t,v

dW

u

1

ρ

t,v

u

q

1

(

ρ

u

t,v

)

2

¯

ρ

t,v

u

dW

u

2

)

.

(12)

Differentiability of I and

ρ

Set

τ

=

inf

{

s

0

:

ρ

s

∈ {−

1

,

1

}}

.

(H1)

τ

>

T

,

IP

a

.

s

.

Moreover

Z

T

t

ρ

s

t,v

)

2

1

(

ρ

s

t

,v

)

2

du

<

,

IP

a

.

s

.

(13)

Differentiability of

ψ

(

t

,

x

,

v

) = ˜

IE

[

h

(

I

T

t

,

x

,

v

)]

(H2) There exists p

>

1 such that for every v0

(

1

,

1

)

there exists an

open intervall U

(

1

,

1

)

of v

0

such that

sup

v

U

IE

[

Z

T

t

ρ

s

t,v

)

2

1

(

ρ

s

t,v

)

2

p

ds

]

<

.

Lemma

Let h be Lipschitz such that the weak derivative h

is

Lebesgue-almost everywhere continuous. Under the Conditions (H1)

and (H2) the partial derivative

v

ψ

(

t

,

x

,

v

)

exists and is given by

(14)

Representation of Z

We want to justify

Z

s

t,x,v

=

σ

(

s

,

I

t

,x,v

s

,

ρ

t,v

s

)

x

ψ

(

s

,

I

s

t,x,v

,

ρ

t,v

s

)

v

ψ

(

s

,

I

s

t,x,v

,

ρ

t,v

s

)

!

.

Problem:

ψ

(

s

,

x

,

v

) = ˜

IE

[

h

(

I

T

t,x,v

)]

is only locally Lipschitz.

We use

dI

t

n

=

I

t

n

(

µ

I

r

)

dt

+

σ

I

I

n

t

(

1

1

n

)

ρ

t

dW

1

t

+

r

1

(

1

1

n

)

2

ρ

2

t

dW

2

t

!

and

ψ

n

(

t

,

x

,

v

) = ˜

IE

[

h

n

(

I

T

n,t,x,v

)]

in approximation proof.

(15)

Representation of Z

Lemma

Assume that (H1) and (H2) hold, and that a and g are continuously

differentiable with bounded derivatives. Let h be Lipschitz such that

the weak derivative h

is Lebesgue-almost everywhere continuous.

Then

Z

s

t,x,v

=

σ

(

s

,

I

t

,x,v

s

,

ρ

t,v

s

)

x

ψ

(

s

,

I

s

t,x,v

,

ρ

t,v

s

)

v

ψ

(

s

,

I

s

t,x,v

,

ρ

t,v

s

)

!

.

(1)

(16)

Representation of Z

Lemma

Assume that (H1) and (H2) hold, and that a and g are continuously

differentiable with bounded derivatives. Let h be Lipschitz such that

the weak derivative h

is Lebesgue-almost everywhere continuous.

Then

Z

s

t,x,v

=

σ

(

s

,

I

t

,x,v

s

,

ρ

t,v

s

)

x

ψ

(

s

,

I

s

t,x,v

,

ρ

t,v

s

)

v

ψ

(

s

,

I

s

t,x,v

,

ρ

t,v

s

)

!

.

(1)

By an argument of Imkeller, Reveillac, Richter one can show (1)

without the use of Malliavin calculus! This allows us to drop the

bounded derivatives assumption.

(17)

Main results

Theorem

Suppose that the coefficients a and g in the dynamics of

ρ

are

continuously differentiable. Assume furthermore that Conditions (H1)

and (H2) are satisfied. Let h be Lipschitz such that the weak

derivative h

is Lebesgue-almost everywhere continuous. Then, there

exists a locally risk minimizing strategy

ϕ

= (

ξ

,

η

)

for the derivative

h

(

I

T

)

.

ξ

is given by

ξ

t

=

ξ

(

t

,

I

t

,

X

t

,

ρ

t

)

, where, with

P denoting the

˜

minimal martingale measure of X ,

ξ

(

t

,

x

,

y

,

v

) =

v

x

σ

I

y

σ

X

˜

IE

[

h

(

I

T

t,x,v

)

I

T

t,1,v

] +

g

(

v

)

γ

y

σ

X

˜

IE

[

h

(

I

t

T

,x,v

I

T

t,x,v

]

.

(18)

Main results

Problem:

(H2) There exists p

>

1 such that for every v

0

(

1

,

1

)

there exists an

open intervall U

(

1

,

1

)

of v

0

such that

sup

v

U

IE

[

Z

T

t

ρ

s

t,v

)

2

1

(

ρ

s

t,v

)

2

p

ds

]

<

.

Very technical, unintuitive assumption. BUT:

Theorem

Let a and g be bounded with bounded derivatives. We assume that

g

(

1

) =

g

(

1

) =

0, and that g does not have any roots in

(

1

,

1

)

. If

lim sup

x

1

2a

(

x

)(

1

x

)

g

2

(

x

)

<

0

and

lim inf

x

↓−

1

2a

(

x

)(

1

+

x

)

g

2

(

x

)

>

0

,

(19)

Examples

(20)

Examples

d

ρ

t

=

κ

(

ϑ

ρ

t

)

dt

+

α

(

1

(

ρ

t

)

2

) ˆ

W

t

, with

α

,

κ

>

0,

ϑ

(

1

,

1

)

Set

ρ

t

=

b

1

(

U

t

)

, with

dU

t

=

a

(

ϑ

U

t

)

dt

+

σ

U

d

W

ˆ

t

,

where a

>

0,

ϑ

R

,

σ

U

>

0 and b

(

x

) =

x

1

x

2

.

(21)

Examples

d

ρ

t

=

κ

(

ϑ

ρ

t

)

dt

+

α

(

1

(

ρ

t

)

2

) ˆ

W

t

, with

α

,

κ

>

0,

ϑ

(

1

,

1

)

Set

ρ

t

=

b

1

(

U

t

)

, with

dU

t

=

a

(

ϑ

U

t

)

dt

+

σ

U

d

W

ˆ

t

,

where a

>

0,

ϑ

R

,

σ

U

>

0 and b

(

x

) =

x

1

x

2

.

d

ρ

t

=

κ

(

ϑ

ρ

t

)

dt

+

α

p

(

1

(

ρ

t

)

2

W

ˆ

t

, with

κ

α

2

1

±

ϑ

and

1

<

ϑ

2

±

r

ϑ

2

4

+

α

2

2

κ

<

1

,

also fulfills Conditions (H1) and (H2)!

(22)

Conclusions

Correlation is random.

Explicit hedge formula under the assumption

(H2) There exists p

>

1 such that for every v0

(

1

,

1

)

there

exists an open intervall U

(

1

,

1

)

of v0

such that

sup

v

U

IE

[

Z

T

t

ρ

s

t,v

)

2

1

(

ρ

s

t,v

)

2

p

ds

]

<

.

(H2) is fulfilled by a large class of models for correlation

dynamics (including Jacobi and OU processes).

(23)

References

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