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R E S E A R C H

Open Access

An inertial S-iteration process

Aniruth Phon-on

1*

, Nifatamah Makaje

1

, Areeyuth Sama-Ae

1

and Kittiya Khongraphan

1

*Correspondence: [email protected]

1Department of Mathematics and

Computer Science, Faculty of Science and Technology, Prince of Songkla University, Pattani, Thailand

Abstract

In this paper, we establish a new iteration method, called an InerSP (an inertial S-iteration process), by combining a modified S-iteration process with the inertial extrapolation. This strategy is for speeding up the convergence of the algorithm. We then prove the convergence theorems of a sequence generated by our new method for finding a common fixed point of nonexpansive mappings in a Banach space. We also present numerical examples to illustrate that the acceleration of our algorithm is effective.

MSC: 47H04; 54H25

Keywords: Common fixed point; MIS-iteration; Nonexpansive mapping; Inertial extrapolation

1 Introduction

In the last half century, mathematicians have been studied the approximation methods for fixed point problems and various iteration schemes for several classes of nonexpansive mappings to solve some mathematical problems such as convex optimization problems, convex feasibility problems, and variational inequalities problems. The details of those studies can be found in [1–12].

In 2008, Mainge [13] studied convergence of the inertial Mann algorithm by combining the Mann algorithm and the inertial extrapolation:

wn=xn+αn(xnxn–1),

xn+1=wn+βn

S(wn) –wn

,

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for eachn≥1. The study is for speeding up the convergence of the given algorithm. The author showed that the sequence{xn}converges weakly to a fixed point of the mapping Sunder certain assumptions. The author also applied the method to convex feasibility problems, fixed point problems and monotone inclusions.

Dong et al. [14] introduced a modified inertial Mann algorithm and an inertial CQ-algorithm by unifying the accelerated Mann CQ-algorithm with the inertial extrapolation as follows: LetT :HHbe a nonexpansive mapping such that Fix(T)=∅. Chooseμ∈ (0, 1),λ> 0 andx0,x1∈Harbitrarily and setd0:= (T(x0) –x0)/λ. Computedn+1andxn+1

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as follows:

wn=xn+αn(xnxn–1),

dn+1=

1 λ

T(wn) –wn

+βndn,

yn=wn+λdn+1,

xn+1=μγnwn+ (1 –μγn)yn,

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for eachn≥1. Under some conditions they proved that the sequence{xn}generated by

this algorithm converges weakly to a fixed point ofT. They also studied an inertial CQ-algorithm by combining the CQ-CQ-algorithm and the inertial extrapolation defined as fol-lows: Let Hbe a Hilbert space andT :HHbe a nonexpansive mapping such that

Fix(T)=∅. Let{αn}∞n=0⊂[α1,α2],α1∈(–∞, 0],α2∈[0,∞),{βn}∞n=0⊂[β1, 1],β1∈(0, 1).

Setx0,x1∈Harbitrarily. Define the iterative sequence{xn}by the following iteration

pro-cess:

wn=xn+αn(xnxn–1),

yn= (1 –βn)wn+βnTwn,

Cn=

zH: ynzwnz

,

Qn=

zH:xnz,xnx0 ≤0

,

xn+1=PCnQnx0.

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They showed that the sequence{xn}converges in norm toPFix(T)(x0). In this study, they

also performed numerical experiments to illustrate that the modified inertial Mann algo-rithm and inertial CQ-algoalgo-rithm significantly reduced the running time compared with some previous methods without the inertial extrapolation. Some studies of the inertial algorithm can be found in [15–23].

Suparatulatorn et al. [24] introduced a modified S-iteration process defined as follows:

x0∈Cand

yn= (1 –βn)xn+βnS1xn,

xn+1= (1 –αn)S1(xn) +αnS2(yn),

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n≥0, whereCis a nonempty subset of a real Banach space, two sequences{αn}and{βn}

are in the interval (0, 1) andS1,S2:CCare G-nonexpansive mappings. Under some

given conditions, they proved weak and strong convergence theorems of this iteration process for finding common fixed points of two G-nonexpansive mappings in a uniformly convex Banach space. They also provided an example from a numerical experiment which supported the idea that the sequence generated by the modified S-iteration converges faster than the one generated by an Ishikawa iteration. So, to obtain a faster algorithm revised from a modified S-iteration process, it should be combined with the inertial ex-trapolation as well.

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a fixed point of a nonexpansive mapping in a Banach space defined as follows: LetHbe a Banach space andS1,S2:HHbe nonexpansive mappings such thatF=Fix(S1)∩ Fix(S2)=∅. Define

ωn=xn+γn(xnxn–1),

yn= (1 –βn)ωn+βnS1(ωn),

xn+1= (1 –αn)S1(ωn) +αnS2(yn),

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n≥1, where{γn},{αn}and{βn}satisfy:

(D1) ∞n=1γn<∞,{γn} ⊂[0,γ],0≤γ< 1,{αn},{βn} ⊂[δ, 1 –δ]for someδ∈(0, 0.5); (D2) {Si(ωn) –ωn}is bounded fori= 1, 2;

(D3) {Si(ωn) –y}is bounded for anyyFfori= 1, 2.

We prove, under some assumptions, the weak and strong convergence of our new iter-ation process for finding common fixed points ofS1andS2.

2 Preliminaries

In this section we review some definitions and lemmas which will be used in the next section. We start with the following identity that will be used several times in the paper:

αx+ (1 –α)y 2=α x 2+ (1 –α) y 2–α(1 –α) x–y 2, (6)

for allα∈R,x,yH.

Definition 2.1 A Banach spaceXis said to haveOpial’s propertyif whenever a sequence

{xn}inXconverges weakly tox, then

lim inf

n→∞ xnx ≤lim infn→∞ xny ,

for allyX,y=x.

Definition 2.2([25]) LetCbe a nonempty closed convex subset of a real uniformly convex Banach spaceX. The mappingsS1andS2onCare said to satisfyCondition Bif there exists

a nondecreasing functionf: [0,∞)→[0,∞) withf(0) = 0 andf(r) > 0 forr> 0 such that, for allxC,

max xS1(x) , xS2(x) ≥f

d(x,F),

where we denote F=Fix(S1)∩Fix(S2) andFix(Si) is the set of fixed points ofSifor all i= 1, 2.

Definition 2.3([25]) LetCbe a subset of a metric space (X,d). A mappingS:CC

is semicompact if for a sequence{xn} inCwithlimn→∞d(xn,S(xn)) = 0, there exists a

subsequence{xni}of{xn}such thatxnipC.

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lim infn→∞ xnc,lim infn→∞ ync andlim infn→∞ αnxn+ (1 –αn)yn =c for some c≥0.Thenlim infn→∞ xnyn = 0.

In 2002, Berinde [27] compared the rate of convergence between the two iterative meth-ods by using the following definition.

Definition 2.5 Let{an}and{bn}be two sequences of positive numbers that converges to aandb, respectively. Assume there exists

lim

n→∞ |ana| |bnb|

=l.

i. Ifl= 0, then it is said that the sequence{an}converges toafaster than the sequence {bn}tob.

ii. If0 <l<∞, then we say that the sequence{an}and{bn}have the same rate of convergence.

Lemma 2.6([28]) Let X be a Banach space that has Opial’s property,and let{xn}be a sequence in X.Let x,y in X be such thatlimn→∞ xnx andlimn→∞ xny exist.If{xnj}

and{xnk}are subsequences of{xn}that converge to x and y,respectively,then x=y.

Lemma 2.7([29]) Let{ψn},{δn},and{αn}be sequences in[0,∞)such thatψn+1≤ψn+ αn(ψnψn–1) +δnfor all n≥1,

n=1δn<∞and there exists a real numberα with0≤ αnα< 1for all n≥1.Then the following hold:

1. n1[ψnψn–1]+<∞where[t]+=max{t, 0}. 2. there existsψ∗∈[0,∞)such thatlimn→∞ψn=ψ∗.

Lemma 2.8([30]) Let C be a nonempty set of a real Hilbert spaceHand{xn}a sequence inHsuch that the following two conditions hold:

1. for anyxC,limn→∞ xnx exists;

2. every sequential weak cluster point of{xn}is inC. Then{xn}converges weakly to a point in C.

Lemma 2.9([30]) Let C be a nonempty closed convex subset of a real Hilbert spaceH,

T :CHa nonexpansive mapping. Let{xn} be a sequence in C and xHsuch that xn x and Txnxn→0as n→ ∞.Then x∈Fix(T).

3 Results and discussions

In this section we prove the weak and strong convergence of a sequence generated by the proposed algorithm for finding a common fixed point of two nonexpansive mappings.

Theorem 3.1 Let X be a uniformly convex Banach space.Let yF=Fix(S1)∩Fix(S2).Let {xn}be a sequence defined by Eq. (5).If(D1), (D2)and(D3)hold,then

1. limn→∞ xny exists.

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Proof

1. By the triangle inequality and the nonexpansiveness ofS1, we have

yny = (1 –βn)ωn+βnS1(ωn) –y

≤(1 –βn) ωny +βn S1(ωn) –y ≤(1 –βn) ωny +βn ωny

= ωny . (7)

So

xn+1–y = (1 –αn)S1(ωn) +αnS2(yn) –y

= (1 –αn)

S1(ωn) –y

+αn

S2(yn) –y

≤(1 –αn) S1(ωn) –y +αn S2(yn) –y . (8)

Using the nonexpansiveness ofS1,S2and (7), we have

xn+1–y ≤(1 –αn) S1(ωn) –y +αn S2(yn) –y ≤(1 –αn) ωny +αn yny

≤(1 –αn) ωny +αn ωny

= ωny . (9)

It is not difficult to see that{ωny}is bounded. Indeed, by the conditions (D2) and (D3) and the triangle inequality,

ωny = ωnS1(ωn) +S1(ωn) –y

S1(ωn) –ωn + S1(ωn) –y

K, (10)

for someK∈[0,∞). That is,{ωny}is bounded. Hence by (9),{xny}and {xnxn–1}are bounded. By the identity in (6),

ωny 2= (1 +γn)(xny) –γn(xn–1–y) 2

= (1 +γn) xny 2–γn xn–1–y 2+γn(1 +γn) xnxn–1 2. (11)

This implies that

xn+1–y 2≤ ωny 2

= (1 +γn) xny 2–γn xn–1–y 2+γn(1 +γn) xnxn–1 2. (12)

DenoteΨn:= xny 2. Then (12) becomes

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whereδn=γn(1 +γn) xnxn–1 2. Observe that by (D1),

n=1

δn= ∞

n=1

γn(1 +γn) xnxn–1 2

n=1

γn(1 +γ)(2K)2

<∞. (14)

By Lemma2.7(2), there existsΨ∗∈[0,∞)such thatlimn→∞Ψn=Ψ∗. This means thatlimn→∞ xny 2exists and, therefore,limn→∞ xny exists. This completes the proof of 1.

2. Setc=limn→∞ xny . By the nonexpansiveness ofS1andS2, we get

xnSi(xn) ≤ xny + Si(xn) –y ≤ xny + xny

= 2 xny . (15)

So, ifc= 0, then xnSi(xn) →0. Now assume thatc> 0. Note that

n=1γn<∞implieslimn→∞γn= 0. It follows from (11)

lim

n→∞ ωny 2= lim

n→∞

(1 +γn) xny 2–γn xn–1–y 2

+γn(1 +γn) xnxn–1 2

= lim

n→∞ xny

2

=c2. (16)

That is,limn→∞ ωny =c. So, this forces

lim supn→∞ yny ≤lim supn→∞ ωny =c. Next we will claim that

lim infn→∞ yny ≥c. SinceS1andS2are nonexpansive, by (6) we have

xn+1–y 2= (1 –αn) S1(ωn) –y 2

+αn S2(yn) –y 2

αn(1 –αn) S1(ωn) –S2(yn) 2

≤(1 –αn) ωny 2+αn yny 2. (17)

Rearranging (17) and by (D1), we have

ωny 2≤ yny 2+

1 αn

ωny 2– xn+1–y 2

yny 2+

1 δ

ωny 2– xn+1–y 2

. (18)

By (18) and (9), it yieldslim infn→∞ yny 2≥c2and solim infn→∞ yny ≥c. Since

c≤lim inf

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it follows thatlimn→∞ yny =c. Since

lim sup

n→∞

S1(ωn) –y ≤lim sup

n→∞ ωnyc,

lim sup

n→∞

S2(yn) –y ≤lim sup

n→∞ ynyc,

lim

n→∞ (1 –βn)(ωny) +βn

S1(ωn) –y = lim

n→∞ yny =c,

and

lim

n→∞ (1 –αn)

S1(ωn) –y

+αn

S2(yn) –y = lim

n→∞ xn+1–y =c,

by Lemma2.4,

lim

n→∞ S1(ωn) –ωn = 0 (19)

and

lim

n→∞ S1(ωn) –S2(yn) = 0. (20)

However, we know thatynωn=βn(S1(ωn) –ωn)andωnxn=γn(xnxn–1) which yield

0≤ lim

n→∞ ynωn

= lim

n→∞βn S1(ωn) –ωn

≤ lim

n→∞ S1(ωn) –ωn

= 0 (21)

and

lim

n→∞ ωnxn =nlim→∞γn xnxn–1

= 0. (22)

Note that by (D2) andγn→0we have

lim

n→∞ S1(ωn) –xnnlim→∞ S1(ωn) –ωn +nlim→∞γn xnxn–1

= 0. (23)

It follows that, by (20), (21), (22), (23) and the nonexpansiveness ofS1andS2, we have

0≤ lim

n→∞ S1(xn) –xn

≤ lim

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≤ lim

n→∞ xnωn +nlim→∞ S1(ωn) –xn

= 0 (24)

and

0 ≤ lim

n→∞ S2(xn) –xn

≤ lim

n→∞ S2(xn) –S2(yn) +nlim→∞ S2(yn) –S1(ωn) +nlim→∞ S1(ωn) –xn ≤ lim

n→∞ xnyn +nlim→∞ S2(yn) –S1(ωn) +nlim→∞ S1(ωn) –xn

≤ lim

n→∞ xnωn +nlim→∞ ωnyn

= 0. (25)

Therefore,limn→∞ S1(xn) –xn = 0 =limn→∞ S2(xn) –xn as desired.

Theorem 3.2 LetHbe a Banach space having Opial’s property.Suppose that S1,S2:HHare two nonexpansive mappings with F=Fix(S1)∩Fix(S2)=∅.Then the sequence{xn} in(5)converges weakly to a common fixed point of S1and S2.

Proof LetyF. By Theorem3.1(1),limn→∞ xny exists. Hence{xn}is bounded. Let {xnk}and{xnj}be subsequences of the sequence of{xn}with the two weak limitsq1andq2,

respectively. By Theorem3.1(2),limn→∞ xnkSi(xnk) = 0 andlimn→∞ xnjSi(xnj) =

0 fori= 1, 2. By Lemma (2.9),Si(q1) =q1 andSi(q2) =q2 fori= 1, 2. That is,q1,q2∈F.

Applying Theorem3.1(1) again, we havelimn→∞ xnq1 andlimn→∞ xnq2 exist and

both{xnk}and{xnj}are sequences converging toq1andq2, respectively. By Lemma (2.6),

q1=q2. Therefore,{xn}converges weakly to a common fixed point inF.

Under certain conditions, we can deduce the strong convergence theorem as follows.

Theorem 3.3 LetHis a uniformly convex Banach space,Suppose that S1,S2:HHare two nonexpansive mappings with F =Fix(S1)∩Fix(S2)=∅and satisfy the Condition B. Then the sequence{xn}in(5)converges strongly to a common fixed point of S1and S2.

Proof LetyF. Now by (12), we get

inf

yF

xn+1–y 2

≤inf

yF

ωny 2

=inf

yF

(1 +γn) xny 2

+inf

yF

γn xn–1–y 2

+inf

yF

γn(1 +γn) xnxn–1 2

≤inf

yF

xny 2

+γninf yF

xny 2

γninf yF

xn–1–y 2

+γn(1 +γn) xnxn–1 2

=inf

yF

xny 2

+γn

inf

yF

xny 2

–inf

yF

xn–1–y 2

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DenoteΨn:=infyF{ xny 2}. Then (26) becomes

Ψn+1≤Ψn+γn(ΨnΨn–1) +δn, (27)

whereδn=γn(1 –γn) xnxn–1 2. Observe that by (D1)

n=1

δn= ∞

n=1

γn(1 +γn) xnxn–1 2

n=1

γn(1 +γ)(2K)2

<∞. (28)

By Lemma2.7(2), there existsΨ∗∈[0,∞) such thatlimn→∞Ψn=Ψ∗.

That is,limn→∞infyF{ xny 2}exists. Therefore,limn→∞infyF{ xny }exists. Since S1andS2satisfy Condition B, by Theorem3.1(2) it implies that

lim

n→∞f

inf

yF

xny

= 0

and, thus,

lim

n→∞infyF

xny

= 0.

So, we can find a subsequence{xnj}of{xn}and a sequence{xj∗} ⊂Fsatisfying xnjxj < 1

2j. Next we will show that{x

j}is a Cauchy sequence. Let> 0. Sincelimn→∞infyF{ xny }= 0, there isN∈Nsuch thatinfyF{ xny }< 6 for allnN. For allm,nN, we

have

xmxn ≤ xmy + xny

for allyF. Thus,

xmxn ≤inf yF

xmy + xny

=inf

yF

xmy

+inf

yF

xny < 6+ 6= 3

for allm,nN. Also, there isj0∈Nsuch that 21j0 <3. ChooseM=max{N,j0}. Then, for

allj>kM, we have

xjxkxjxnj + xnjxnk + xnkx

k <

3+

3+

3 =.

Therefore,{x∗j}is a Cauchy sequence and so there existsqHsuch thatxj converges toq. SinceFis closed,qF. As a result, we see thatxnjconverges toq. Sincelimn→∞ xnq

exists by Theorem3.1(1), the conclusion follows.

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Proof From Theorem3.1,{xn}is bounded andlimn→∞ xnS1(xn) = 0 =limn→∞ xnS2(xn) . By the semicompactness of one ofSi, there existsqHand a subsequence{xnj}

of{xn}such thatxnjqasj→ ∞. Then

qSi(q) ≤ qxnj + xnjSi(xnj) + Si(xnj) –Si(q)

qxnj + xnjSi(xnj) + xnjq

→0 asj→ ∞. (29)

Thus,qF. As in the proof of Theorem3.3,limn→∞infyF{ xny }exists. We observe

that infyF{ xnjy } ≤ xnjq →0 as j→ ∞, hence limn→∞infyF{ xny }= 0. It

follows, as in the proof of Theorem3.3, that{xn}converges strongly to a common fixed

point ofS1andS2. This completes the proof.

4 Numerical illustrations

We next demonstrate the efficiency of the InerSP iteration and compare it with the MSP iteration defined in [24] by giving some numerical examples. We use program MATLAB R2017a running on Core i7 setup processor installed with 8.00 GB of RAM using Win-dows 7. First, we apply our method to solve the following convex feasibility problem (see [31]).

Problem 1([31]) For any nonempty closed convex setCi⊂RN for eachi= 0, 1, . . . ,m,

ifC:=

m

i=1

Ci=∅, findx∗∈C.

Define a mappingT:RN RN by

T:=P0

1

m m

i=1 Pi

,

wherePi=PCi,i= 0, 1, 2, . . . ,mis the metric projection ontoCi. Note thatPiis

nonexpan-sive for alli= 1, 2, . . . ,m, so this implies that the mappingT is also nonexpansive. More-over, it is straightforward to check that

Fix(T) =Fix(P0)∩ m

i=1

Fix(Pi) =C0∩ m

i=1

Fix(Pi) =C.

We use the inertial S-iteration process (InerSP) and the modified S-iteration process

(MSP) to solve Problem1. For InerSP, setS1=S2=T,γ = 0.98,δ= 0.1,γn=

0.95, n≤1010, 1

(n+1)2,n> 1010, andβn=αn= 0.65 +(n+1)10.25, wherendenotes the number of iterations. For MSP, the con-trol parameters are defined the same as InerSP exceptγandγn, which are not parameters

in MSP. In the experiment, we setm= 30 andCi,i= 0, 1, . . . ,mas a closed ball with center ci∈RN and radiusri> 0. Thus, for eachi,Pican be computed as

Pi(x) := ⎧ ⎨ ⎩

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Table 1 Convergence comparison of MSP and InerSP for the given function in Problem1

n MSP iteration Error zn ∞ InerSP iteration Error xn

0 1 1

1 0.146860263 0.146905257

2 0.144519281 0.169202619

3 0.142508272 0.224124309

4 0.140748768 0.240030476

. . .

. . .

. . .

271 0.058053817 0.010021818

272 0.057968808 0.010009268

273 0.057884185 0.009996786

. . .

. . .

12,664 0.010000328

12,665 0.009999947

CPU times (sec) 25.023275 0.660640

Chooseri:= 1 for alli= 0, 1, . . . ,m,c0:= 0,c1= [1, 0, . . . , 0], andc2= [–1, 0, . . . , 0]. For 3≤ im,ci∈(–1/

N, 1/√N) are randomly chosen. From the choice ofc1,c2andr1,r2, we

haveFix(T) ={0}. We select initial pointsx0=rand(N, 10) andx1=x0+rand10,000(N,1) where N= 30. SinceFix(T) ={0}, we can consider the error as

xn ∞=maxxn(1),xn(2), . . . ,xn(N)<= 0.01,

and take it to be the stopping criterion. In Table1,ndenotes the number of iterations,{xn}

and{zn}denote the sequence of approximated fixed points generated by InerSP and MSP,

respectively. The results are shown in Table1.

The results are listed in Table1, which illustrate that the errors for both the MSP iter-ation and the InerSP iteriter-ation reduce, which means that the approximated solutions for both methods converge to the fixed point 0. In addition, from Table1and Fig.1, we can see that xn ∞≤ zn ∞andlimn→∞ xznn∞∞ = 0 so the InerSP iteration behaves better than the MSP and the sequence{xn}converges faster than{zn}. Moreover, the running CPU

time for finding the fixed point using InerSP is much less than MSP.

In the next example, we perform a numerical experiment to find a common fixed point of two nonexpansive mappings.

Problem 2 DefineS1,S2:R2→R2by

S1(x,y) =

1 +x

2 , 1 +

y

2

and

S2(x,y) =

x, 3 –y 2

.

It is easy to check that bothS1andS2are nonexpansive onR2. In this problem, for InerSP

we setγ = 0.98,δ= 0.1,γn=

0.25, n≤1010 1

(n+1)2,n> 1010, andβn=αn= 0.65 +

1

(n+1)0.25. For MSP we set

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Figure 1Error comparison between MSP and InerSP

Table 2 Convergence comparison of MSP and InerSP for the given function in Problem2

Iteration MSPzn= (z1n,z2n) InerSPxn= (x1n,x2n) Error xnx0 2

n z1n z2n x1n x2n MSP InerSP

1 721 –5 721 –5 720.0340 720.0340

2 393.4 3.3825 423.5113 53.0044 392.4024 425.5787

3 232.8733 1.8392 206.7190 –5.6175 231.8733 205.8600

4 140.6855 2.0138 92.2796 3.9063 139.6856 91.2944

. . .

. . .

. . .

. . .

. . .

. . .

. . .

13 2.6602 2 1.0007 2 1.0177 0.0007

14 2.0177 2 0.6239

. . .

. . .

. . .

. . .

29 1.0007 2 0.0007

CPU times (sec) 0.010388 0.001049

andS2. Setx0= (500, 1000) andx1= (721, –5) as the initial values. Let{zn}and{xn}be

se-quences generated by MSP and InerSP, respectively, wherezn= (z1n,z2n) andxn= (x1n,x2n)

are inR2. Moreover, we take err = x

nx∗ 2to be the error of the iterative algorithm where · 2is the Euclidean norm. The results are shown in Table2.

From Table2, we see that both{zn}and{xn}converge to fixed pointx∗= (1, 2). If we

iterate until the error is less than 0.001 the MSP converges to fixed point in 29 iterations and InerSP converges in 13 iterations. From Table2and Fig.2, it can be observed that

xnx∗ ≤ znx∗ for alln≥2 andlimn→∞ xnx

∗ 2

znx∗ 2 = 0 so the sequence{xn}converges faster than{zn}. In addition, the running time to find the common fixed point using InerSP

is 10 times less than MSP. As illustrated in the two examples, we can perceive that the InerSP iteration has a better behavior than the MSP iteration.

5 Conclusions

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Figure 2Error comparison between MSP and InerSP

InerSP method. Although the number of steps of the iteration process of the InerSP is higher than MSP, the numerical examples show that sequences generated by InerSP itera-tion converge to fixed points more rapidly than MSP iteraitera-tion when using the number of iterations and CPU running times as measures.

Acknowledgements

The authors would like to thank the referee for helpful and detailed comments.

Funding

This article is funded by the authors.

Abbreviations

InerSP, Inertial S-iteration process; MSP, A modified S-iteration; CPU, Central Processing Unit.

Availability of data and materials Not applicable.

Competing interests

The authors declare that they have no competing interests.

Authors’ contributions

All authors read and approved the final manuscript.

Publisher’s Note

Springer Nature remains neutral with regard to jurisdictional claims in published maps and institutional affiliations.

Received: 20 September 2018 Accepted: 16 January 2019

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Figure

Table 1 Convergence comparison of MSP and InerSP for the given function in Problem 1
Table 2 Convergence comparison of MSP and InerSP for the given function in Problem 2
Figure 2 Error comparison between MSP and InerSP

References

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