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http://dx.doi.org/10.4236/am.2015.62026

Complete Semigroups of Binary Relations

Defined by Semilattices of the Class

(

X

)

1

Σ

,10

Shota Makharadze

1

, Neşet Aydın

2

, Ali Erdoğan

3

1Shota Rustavelli University, Batum, Georgia

2Çanakkale Onsekiz Mart University, Çanakkale, Turkey 3Hacettepe University, Ankara, Turkey

Email: [email protected], [email protected], [email protected]

Received 10 January 2015; accepted 28 January 2015; published 4 February 2015 Copyright © 2015 by authors and Scientific Research Publishing Inc.

This work is licensed under the Creative Commons Attribution International License (CC BY).

http://creativecommons.org/licenses/by/4.0/

Abstract

In this paper we give a full description of idempotent elements of the semigroup BX (D), which are defined by semilattices of the class Σ1 (X, 10). For the case where X is a finite set we derive

formu-las by means of which we can calculate the numbers of idempotent elements of the respective se-migroup.

Keywords

Semilattice, Semigroup, Binary Relation

1. Introduction

Let X be an arbitrary nonempty set, D be an X-semilattice of unions, i.e. such a nonempty set of subsets of the

set X that is closed with respect to the set-theoretic operations of unification of elements from D, f be an

arbi-trary mapping of the set X in the set D. To each such a mapping f we put into correspondence a binary relation

f

α on the set X that satisfies the condition

{ }

( )

(

)

f x X

x f x

α

=

×

The set of all such αf

(

f X: →D

)

is denoted by BX

( )

D . It is easy to prove that BX

( )

D is a

semi-group with respect to the operation of multiplication of binary relations, which is called a complete semisemi-group of

(2)

Recall that we denote by ∅ an empty binary relation or empty subset of the set X. The condition

( )

x y, ∈α will be written in the form xαy. Further let , x yX , YX , α ∈BX

( )

D , TD, ∅ ≠D′⊆D,

D= ∪D and tD . Then by symbols we denoted the following sets:

{

}

{

}

{ }

(

)

{

}

{

}

{

}

{

}

(

)

(

)

, , 2 , 2 \ ,

, , , ,

, , \ .

X X

y Y

T T

t T

y x X y x Y y Y Y X X

V D Y Y D D T D T T D T D T T

D Z D t Z l D T D D

α α α α

α α

∗ ∈

= ∈ = = ⊆ = ∅

′ ′ ′ ′ ′ ′ ′ ′

= ∈ = ∈ ⊆ = ∈ ⊆

′= ′∈ ′ ∈ ′ ′ = ∪ ′ ′



By symbol Λ

(

D D, ′

)

is denoted an exact lower bound of the set D' in the semilattice D.

Definition 1. We say that the complete X-semilattice of unions D is an XI-semilattice of unions if it satisfies the following two conditions:

a) Λ

(

D D, t

)

D for any tD

;

b)

(

, t

)

t Z

Z=

Λ D D for any nonempty element Z of the semilattice D.

Definition 2. We say that a nonempty element T is a nonlimiting element of the set D' if T l D T\

(

′,

)

≠ ∅

and a nonempty element T is a limiting element of the set D' if T l D T\

(

′,

)

= ∅.

Definition 3. Let α ∈BX

( )

D , TV X

(

∗,

α

)

, YTα =

{

yX y

α

=T

}

. A representation of a binary relation

α

of the form

(

)

(

)

, T

T V X Y T

α α

α=

∗ × is called quasinormal.

Note that, if

(

)

(

)

, T

T V X Y T

α α

α=

∗ × is a quasinormal representation of the binary relation

α

, then the

fol-lowing conditions are true:

1)

(

)

, T T V X X =

α Yα;

2) YTα∩YTα′ = ∅ for T T, ,′∈V X

(

α

)

and TT′.

Let

n

(

X m,

)

denote the class of all complete X-semilattices of unions where every element is isomorphic

to a fixed semilattice D.

The following Theorems are well know (see [1] and [3]).

Theorem 4. Let X be a finite set;δand q be respectively the number of basic sources and the number of all automorphisms of the semilattice D. If X = ≥n δ and Σn

(

X m,

)

=s, then

( )

( ) (

(

)

)

( ) (

)

1 1

1

1 ! !

1

1 ! 1 !

p i p n

p m

m p

p i

C C p i

s

q i p i

δ δ

δ

δ

δ δ

+ + −

+

= =

  

  

= ⋅

 

− ⋅ − +

 

∑ ∑

where

( ) (

! !

)

!

k j

j C

k j k

=

⋅ − (see Theorem 11.5.1 [1]).

Theorem 5. Let D be a complete X-semilattice of unions. The semigroup BX

( )

D possesses right unit iff D is an XI-semilattice of unions (see Theorem 6.1.3 [1]).

Theorem 6. Let X be a finite set and D

( )

α be the set of all those elements T of the semilattice

(

,

) { }

\

Q=V Dα ∅ which are nonlimiting elements of the set QT. A binary relation

α

having a quasinormal

representation ( )

(

)

, T

T V D Y T

α α

α=

× is an idempotent element of this semigroup iff a) V D

(

)

is complete XI-semilattice of unions;

b) ( )

T T

T D Y T

α

α ′

′∈ ⊇

for any TD

( )

α ;

c) YTα∩ ≠ ∅T for any nonlimiting element of the set

( )

T

D α (see Theorem 6.3.9 [1]).

Theorem 7. Let D, Σ

( )

D , E( )Xr

( )

D and I denote respectively the complete X-semilattice of unions, the set of all XI-subsemilatices of the semilattice D, the set of all right units of the semigroup BX

( )

D and the set of all idempotents of the semigroup BX

( )

D . Then for the sets E( )Xr

( )

D and I the following statements are true:

1) if ∅ ∈D and Σ

( )

D =

{

D′∈ Σ

( )

D ∅ ∈D

}

then

a) EX( )r

( )

D′ ∩E( )Xr

( )

D′′ = ∅ for any elements D′ and D′′ of the set Σ∅

( )

D that satisfy the condition D′≠D′′;

b) ( ) ( )Xr

( )

D D

I E D

′∈Σ ′

=

c) the equality ( ) ( )r

( )

X

D D

I E D

′∈Σ ′

(3)

2) if ∅ ∉D, then

a) EX( )r

( )

D′ ∩E( )Xr

( )

D′′ = ∅ for any elements D and D′′ of the set Σ

( )

D that satisfy the condition

D′≠D′′;

b) ( ) ( )Xr

( )

D D

I=

′∈Σ E D

c) the equality ( ) ( )Xr

( )

D D

I =

′∈Σ E D is fulfilled for the finite set X (see Theorem 6.2.3 [1]).

Corollary 1. Let Y=

{

y y1, 2,,yk

}

and Dj =

{

T T1, 2,,Tj

}

be some sets, where k≥1 and j≥1. Then the number s k j

( )

, of all possible mappings of the set Y into any such subset Dj of the set D that j TjDj can be calculated by the formula

( )

, k

(

1

)

k

s k j = j − −j (see Corollary 1.18.1 [1]).

2

. Idempotent Elements of the Semigroups

B D

X

( )

Defined by Semilattices of the

Class

Σ

1

(

X

,10

)

Let X and Σ1

(

X,10

)

be respectively an arbitrary nonempty set and a class X-semilattices of unions, where

each element is isomorphic to some X-semilattice of unions D=

{

Z Z Z Z Z Z Z Z Z D9, 8, 7, 6, 5, 4, 3, 2, 1,

}

that satis-fies the conditions:

9 4 1 9 5 1

9 6 1 9 6 2

9 6 3 9 7 3

9 8 3 1 2 2 1

1 3 3 1 2 3

3 2 4 5 5 4

4 6 6 4 4 7

7 4 4 8

, , , , , ,

, \ , \ ,

\ , \ , \ ,

\ , \ , \ ,

\ , \ , \ ,

\ , \ ,

Z Z Z D Z Z Z D

Z Z Z D Z Z Z D

Z Z Z D Z Z Z D

Z Z Z D Z Z Z Z

Z Z Z Z Z Z

Z Z Z Z Z Z

Z Z Z Z Z Z

Z Z Z Z

⊂ ⊂ ⊂ ⊂ ⊂ ⊂

⊂ ⊂ ⊂ ⊂ ⊂ ⊂

⊂ ⊂ ⊂ ⊂ ⊂ ⊂

⊂ ⊂ ⊂ ≠ ∅ ≠ ∅

≠ ∅ ≠ ∅ ≠ ∅

≠ ∅ ≠ ∅ ≠ ∅

≠ ∅ ≠ ∅ ≠ ∅

≠ ∅ ≠ ∅

 

 

 

8 4

5 6 6 5 5 7

7 5 5 8 8 5

6 7 7 6 6 8

8 6 7 8 8 7

1 2 1 3 2 3 4 2

4 3 4 7 4 8 5 2

5 3 5 7 5 8 7 1

7 2 8

\ ,

\ , \ , \ ,

\ , \ , \ ,

\ , \ , \ ,

\ , \ , \ ,

Z Z

Z Z Z Z Z Z

Z Z Z Z Z Z

Z Z Z Z Z Z

Z Z Z Z Z Z

Z Z Z Z Z Z Z Z

Z Z Z Z Z Z Z Z

Z Z Z Z Z Z Z Z

Z Z Z

≠ ∅

≠ ∅ ≠ ∅ ≠ ∅

≠ ∅ ≠ ∅ ≠ ∅

≠ ∅ ≠ ∅ ≠ ∅

≠ ∅ ≠ ∅ ≠ ∅

∪ = ∪ = ∪ = ∪

= ∪ = ∪ = ∪ = ∪

= ∪ = ∪ = ∪ = ∪

= ∪ = ∪ 1 8 2

4 5 4 6 5 6 1

6 7 6 8 7 8 3

, ,

.

Z Z Z D

Z Z Z Z Z Z Z

Z Z Z Z Z Z Z

= ∪ =

∪ = ∪ = ∪ =

∪ = ∪ = ∪ =

(1)

An X-semilattice that satisfies conditions (1) is shown inFigure 1.

[image:3.595.245.383.596.703.2]

Let C D

( ) {

= P P P P P P P P P P0, ,1 2, 3, 4, 5, 6, 7, 8, 9

}

be a family of sets, where P0, P1, P2, P3, P4, P5, P6, P7, P8, P9

(4)

are pairwise disjoint subsets of the set X and 1 2 3 4 5 6 7 8 9

0 1 2 3 4 5 6 7 8 9

D Z Z Z Z Z Z Z Z Z P P P P P P P P P P

ϕ

=  

 

be a map-

ping of the semilattice D onto the family sets C D

( )

. Then for the formal equalities of the semilattice D we

have a form:

0 1 2 3 4 5 6 7 8 9

1 0 2 3 4 5 6 7 8 9

2 0 1 3 4 5 6 7 8 9

3 0 1 2 4 5 6 7 8 9

4 0 2 3 5 6 7 8 9

5 0 2 3 4 6 7 8 9

6 0 4 5 7 8 9

7

, , , , , , ,

D P P P P P P P P P P Z P P P P P P P P P Z P P P P P P P P P Z P P P P P P P P P Z P P P P P P P P Z P P P P P P P P Z P P P P P P

Z

= ∪ ∪ ∪ ∪ ∪ ∪ ∪ ∪ ∪

= ∪ ∪ ∪ ∪ ∪ ∪ ∪ ∪

= ∪ ∪ ∪ ∪ ∪ ∪ ∪ ∪

= ∪ ∪ ∪ ∪ ∪ ∪ ∪ ∪

= ∪ ∪ ∪ ∪ ∪ ∪ ∪

= ∪ ∪ ∪ ∪ ∪ ∪ ∪

= ∪ ∪ ∪ ∪ ∪

0 1 2 4 5 6 8 9

8 0 1 2 4 5 6 7 9

9 0

, , .

P P P P P P P P Z P P P P P P P P Z P

= ∪ ∪ ∪ ∪ ∪ ∪ ∪

= ∪ ∪ ∪ ∪ ∪ ∪ ∪

=

(2)

Here the elements P1, P2, P3, P4, P5, P6, P7, P8 are basis sources, the elements P0, P6, P9 are sources of

com-pleteness of the semilattice D. Therefore X ≥7 and

δ

=7 (see [2]).

Lemma 1. Let D∈ Σ1

(

X,10

)

, Σ1

(

X,10

)

=s and X ≥ ≥δ 7. If X is a finite set, then

( )

(

)

1

1 4 7 5 21 6 35 7 35 8 21 9 11

8

n n n n n n n

s= − × + × − × + × − × + × + .

Proof. In this case we have: m = 10, δ = 7. Notice that an X-semilattice given inFigure 1 has eight automor-phims. By Theorem 1.1 it follows that

( )

( ) (

(

)

)

(

) (

)

1 7 7

1 10

3

7 1

1 7! 7 !

1

8 1 ! 1 !

p i p n

p

p

p i

C C p i

s

i p i

+ + −

+

= =

  

  

= ⋅

 

− ⋅ − +

 

∑ ∑

,

where

(

!

)

! !

k j

j C

k j k

=

⋅ − and that

( )

(

)

1

1 4 7 5 21 6 35 7 35 8 21 9 11

8

n n n n n n n

s= − × + × − × + × − × + × + .

Example 8. Let n=7, 8, 9, 10 Then:

( )

7 8 9 10

10 , 10 , 10 , 10

X

B D = .

Lemma 2. Let D∈ Σ1

(

X,10

)

. Then the following sets are all proper subsemilattices of the semilattice

{

9, 8, 7, 6, 5, 4, 3, 2, 1,

}

D= Z Z Z Z Z Z Z Z Z D :

1)

{ } { } { } { } { } { } { } { } { }

Z9 , , , , , , , , , Z8 Z7 Z6 Z5 Z4 Z3 Z2 Z1

{ }

D

(see diagram 1 of the Figure 2);

2)

{

Z Z9, 8

} {

, ,Z Z9 7

} {

, ,Z Z9 6

} {

, ,Z Z9 5

} {

, ,Z Z9 4

} {

, ,Z Z9 3

} {

, ,Z Z9 2

} {

, ,Z Z9 1

}

, ,

{

Z D9

}

, ,

{

Z Z8 3

}

,

{

Z D8,

}

, ,

{

Z Z7 3

}

, ,

{

Z D7

}

, ,

{

Z Z6 3

} {

, ,Z Z6 2

} {

, ,Z Z6 1

}

, ,

{

Z D6

}

, ,

{

Z Z5 1

}

, ,

{

Z D5

}

, ,

{

Z Z4 1

}

,

   

{

Z D4,

} {

, ,Z D3

} {

, ,Z D2

} { }

, ,Z D1

   

(see diagram 2 of the Figure 2);

3)

{

Z Z Z9, 8, 3

}

, ,

{

Z Z D9 8, 

}

, ,

{

Z Z Z9 7, 3

}

, ,

{

Z Z D9 7,

}

, ,

{

Z Z Z9 6, 3

} {

, ,Z Z Z9 6, 2

} {

, ,Z Z Z9 6, 1

}

,

{

Z Z D9, 6,

}

, ,

{

Z Z Z9 5, 1

}

, ,

{

Z Z D9 5,

}

, ,

{

Z Z Z9 4, 1

}

, ,

{

Z Z D9 4,

} {

, ,Z Z D9 3,

} {

, ,Z Z D9 2,

}

,

(5)

{

Z Z D9, 1,

} {

, ,Z Z D8 3,

} {

, ,Z Z D7 3,

} {

, ,Z Z D6 3,

} {

, ,Z Z D6 2,

} {

, ,Z Z D6 1,

} {

, ,Z Z D5 1,

} {

, ,Z Z D4 1,

}

       

(see diagram 3 of the Figure 2);

4)

{

Z Z Z D9, 4, 1,

} {

, ,Z Z Z D9 5, 1,

} {

, ,Z Z Z D9 6, 1,

} {

, ,Z Z Z D9 6, 2,

} {

, ,Z Z Z D9 6, 3,

}

,

    

{

Z Z Z D9, 7, 3,

} {

, Z Z Z D9, 8, 3,

}

 

(see diagram 4 of the Figure 2);

5)

{

Z Z Z Z9, 5, 4, 1

} {

, ,Z Z Z Z9 6, 4, 1

} {

, ,Z Z Z Z9 6, 5, 1

} {

, ,Z Z Z Z9 7, 6, 3

} {

, ,Z Z Z Z9 8, 6, 3

} {

, ,Z Z Z Z9 8, 7, 3

}

,

{

Z Z Z D9, 8, 4,

} {

, Z Z Z D9, 8, 5,

} {

, Z Z Z D9, 7, 2,

} {

, Z Z Z D9, 7, 4,

} {

, Z Z Z D9, 7, 5,

} {

, Z Z Z D9, 8, 1,

}

,

     

{

Z Z Z D9, 8, 2,

} {

, Z Z Z D9, 4, 2,

} {

, Z Z Z D9, 4, 3,

} {

, Z Z Z D9, 5, 2,

} {

, Z Z Z D9, 5, 3,

} {

, Z Z Z D9, 7, 1,

}

,

     

{

Z Z Z D9, 2, 1,

} {

, ,Z Z Z D9 3, 1,

} {

, ,Z Z Z D9 3, 2,

} {

, ,Z Z Z D6 2, 1,

} {

, ,Z Z Z D6 3, 1,

} {

, ,Z Z Z D6 3, 2,

}

;

     

(see diagram 5 of the Figure 2);

6)

{

Z Z Z Z D9, 5, 4, 1, 

} {

, Z Z Z Z D9, 6, 4, 1,

} {

, Z Z Z Z D9, 6, 5, 1, 

} {

, Z Z Z Z D9, 7, 6, 3,

}

,

{

Z Z Z Z D9, 8, 6, 3,

} {

, Z Z Z Z D9, 8, 7, 3,

}

 

(see diagram 6 of the Figure 2);

7)

{

Z Z Z Z D9, 6, 2, 1,

} {

, Z Z Z Z D9, 6, 3, 1,

} {

, Z Z Z Z D9, 6, 3, 2,

}

  

(see diagram 7 of the Figure 2);

8)

{

Z Z Z Z Z D9, 8, 6, 3, 2, 

} {

, Z Z Z Z Z D9, 8, 6, 3, 1,

} {

, Z Z Z Z Z D9, 7, 6, 3, 2,

} {

, Z Z Z Z Z D9, 7, 6, 3, 1, 

}

,

{

Z Z Z Z Z D9, 6, 5, 3, 1,

} {

, Z Z Z Z Z D9, 6, 5, 2, 1,

} {

, Z Z Z Z Z D9, 6, 4, 3, 1,

} {

, Z Z Z Z Z D9, 6, 4, 2, 1,

}

   

(see diagram 8 of the Figure 2);

9)

{

Z Z Z8, 7, 3

} {

, ,Z Z Z8 6, 3

}

, ,

{

Z Z D8 6,

} {

, ,Z Z D8 5,

} {

, ,Z Z D8 4,

} {

, ,Z Z D8 2,

} {

, ,Z Z D8 1,

}

, ,

{

Z Z Z7 6, 3

}

,

    

{

Z Z D7, 5,

} {

, ,Z Z D7 4,

} {

, ,Z Z D7 2,

} {

, ,Z Z D7 1,

}

, ,

{

Z Z Z6 5, 1

} {

, ,Z Z Z6 4, 1

} {

, ,Z Z Z5 4, 1

}

, ,

{

Z Z D5 3,

}

,

    

{

Z Z D5, 2,

} {

, ,Z Z D4 3,

} {

, ,Z Z D4 2,

} {

, ,Z Z D3 2,

} {

, ,Z Z D3 1,

} {

, ,Z Z D2 1,

}

     

(see diagram 9 of the Figure 2);

10)

{

Z Z Z D8, 6, 3,

} {

, ,Z Z Z D8 7, 3,

} {

, ,Z Z Z D7 6, 3,

} {

, ,Z Z Z D5 4, 1,

} {

, ,Z Z Z D6 4, 1,

} {

, ,Z Z Z D6 5, 1,

}

(see diagram 10 of the Figure 3);

11)

{

Z Z Z Z D6, 5, 3, 1,

} {

, Z Z Z Z D6, 5, 2, 1,

} {

, Z Z Z Z D6, 4, 3, 1,

} {

, Z Z Z Z D6, 4, 2, 1,

}

,

{

Z Z Z Z D7, 6, 3, 2,

} {

, Z Z Z Z D7, 6, 3, 1,

} {

, Z Z Z Z D8, 6, 3, 2,

} {

, Z Z Z Z D8, 6, 3, 1,

}

   

(see diagram 11 of the Figure 2);

12)

{

Z Z Z Z6, 5, 4, 1

} {

, ,Z Z Z Z8 7, 6, 3

}

, ,

{

Z Z Z D8 2, 1,

} {

, ,Z Z Z D3 2, 1,

} {

, ,Z Z Z D4 3, 2,

} {

, ,Z Z Z D5 3, 2,

}

,

   

{

Z Z Z D7, 2, 1,

} {

, Z Z Z D7, 4, 2,

} {

, Z Z Z D7, 5, 2,

} {

, Z Z Z D8, 4, 2,

} {

, Z Z Z D8, 5, 2,

}

    

(see diagram 12 of the Figure 2);

13)

{

Z Z Z D7, 5, 3,

} {

, Z Z Z D4, 2, 1,

} {

, Z Z Z D8, 3, 1,

} {

, Z Z Z D8, 3, 2,

} {

, Z Z Z D8, 4, 1,

} {

, Z Z Z D4, 3, 1,

}

,

     

{

Z Z Z D5, 2, 1,

} {

, Z Z Z D5, 3, 1,

} {

, Z Z Z D7, 3, 1,

} {

, Z Z Z D7, 3, 2,

} {

, Z Z Z D7, 4, 1,

} {

, Z Z Z D7, 4, 3,

}

,

     

{

Z Z Z D7, 5, 1,

} {

, ,Z Z Z D8 4, 3,

} {

, ,Z Z Z D8 5, 1,

} {

, ,Z Z Z D8 5, 3,

}

   

(see diagram 13 of the Figure 2);

(6)

{

Z Z Z Z D9, 5, 3, 2,

} {

, Z Z Z Z D9, 7, 2, 1,

} {

, Z Z Z Z D9, 7, 4, 2,

} {

, Z Z Z Z D9, 7, 4, 3,

} {

, Z Z Z Z D9, 7, 5, 2,

}

,

    

{

Z Z Z Z D9, 8, 2, 1,

} {

, Z Z Z Z D9, 8, 4, 2,

} {

, Z Z Z Z D9, 8, 5, 2,

}

  

(see diagram 14 of the Figure 2);

15)

{

Z Z Z Z D9, 4, 2, 1, 

} {

, Z Z Z Z D9, 4, 3, 1, 

} {

, Z Z Z Z D9, 5, 2, 1,

} {

, Z Z Z Z D9, 5, 3, 1, 

} {

, Z Z Z Z D9, 7, 3, 1, 

}

,

{

Z Z Z Z D9, 7, 3, 2,

} {

, Z Z Z Z D9, 7, 4, 1,

} {

, Z Z Z Z D9, 7, 5, 1,

} {

, Z Z Z Z D9, 7, 5, 3,

} {

, Z Z Z Z D9, 8, 3, 1,

}

,

    

{

Z Z Z Z D9, 8, 3, 2,

} {

, Z Z Z Z D9, 8, 4, 1,

} {

, Z Z Z Z D9, 8, 4, 3,

} {

, Z Z Z Z D9, 8, 5, 1,

} {

, Z Z Z Z D9, 8, 5, 3,

}

    

(see diagram 15 of the Figure 2);

16)

{

Z Z Z Z D5, 4, 3, 1, 

} {

, Z Z Z Z D5, 4, 2, 1,

} {

, Z Z Z Z D7, 5, 4, 1, 

} {

, Z Z Z Z D8, 5, 4, 1,

} {

, Z Z Z Z D8, 7, 3, 2, 

}

,

{

Z Z Z Z D8, 7, 3, 1,

} {

, Z Z Z Z D8, 7, 5, 3,

} {

, Z Z Z Z D8, 7, 4, 3,

}

  

(see diagram 16 of the Figure 2);

17)

{

Z Z Z Z D5, 3, 2, 1,

} {

, Z Z Z Z D4, 3, 2, 1,

} {

, Z Z Z Z D7, 4, 2, 1,

} {

, Z Z Z Z D7, 3, 2, 1,

} {

, Z Z Z Z D7, 5, 3, 2,

}

,

    

{

Z Z Z Z D7, 5, 2, 1,

} {

, Z Z Z Z D7, 4, 3, 2,

} {

, Z Z Z Z D8, 3, 2, 1,

} {

, Z Z Z Z D8, 5, 3, 2,

} {

, Z Z Z Z D8, 5, 2, 1,

}

,

    

{

Z Z Z Z D8, 4, 3, 2,

} {

, Z Z Z Z D8, 4, 2, 1,

}

 

(see diagram 17 of the Figure 2);

18)

{

Z Z Z Z D7, 4, 3, 1, 

} {

, Z Z Z Z D7, 5, 3, 1,

} {

, Z Z Z Z D8, 5, 3, 1, 

} {

, Z Z Z Z D8, 4, 3, 1,

}

(see diagram 18 of the Figure 2); 19)

{

Z Z Z Z D6, 5, 4, 1, 

} {

, Z Z Z Z D8, 7, 6, 3,

}

.

(see diagram 19 of the Figure 2);

20)

{

Z Z Z Z Z D8, 7, 5, 3, 2,

} {

, Z Z Z Z Z D8, 7, 4, 3, 2, 

} {

, Z Z Z Z Z D8, 5, 4, 2, 1, 

} {

, Z Z Z Z Z D7, 5, 4, 2, 1,

}

,

{

Z Z Z Z Z D8, 7, 3, 2, 1,

} {

, Z Z Z Z Z D5, 4, 3, 2, 1,

}

 

(see diagram 20 of the Figure 2);

21)

{

Z Z Z Z Z D6, 5, 4, 2, 1,

} {

, Z Z Z Z Z D8, 7, 6, 3, 2,

} {

, Z Z Z Z Z D8, 7, 6, 3, 1,

} {

, Z Z Z Z Z D6, 5, 4, 3, 1, 

}

(see diagram 21 of the Figure 2);

22)

{

Z Z Z Z Z D9, 5, 4, 2, 1,

} {

, Z Z Z Z Z D9, 8, 7, 4, 3,

} {

, Z Z Z Z Z D9, 8, 7, 3, 1,

} {

, Z Z Z Z Z D9, 8, 5, 4, 1,

}

,

   

{

Z Z Z Z Z D9, 7, 5, 4, 1,

} {

, ,Z Z Z Z Z D9 5, 4, 3, 1,

} {

, ,Z Z Z Z Z D9 8, 7, 3, 2,

} {

, ,Z Z Z Z Z D9 8, 7, 5, 3,

}

   

(see diagram 22 of the Figure 2);

23)

{

Z Z Z Z Z D9, 8, 7, 6, 3,

} {

, Z Z Z Z Z D9, 6, 5, 4, 1,

}

(see diagram 23 of the Figure 2);

24)

{

Z Z Z Z Z D9, 8, 5, 3, 2,

} {

, Z Z Z Z Z D9, 8, 5, 2, 1,

} {

, Z Z Z Z Z D9, 8, 4, 3, 2,

} {

, Z Z Z Z Z D9, 8, 4, 2, 1,

}

,

   

{

Z Z Z Z Z D9, 8, 3, 2, 1,

} {

, Z Z Z Z Z D9, 7, 5, 3, 2,

} {

, Z Z Z Z Z D9, 7, 5, 2, 1,

} {

, Z Z Z Z Z D9, 7, 4, 3, 2,

}

,

   

{

Z Z Z Z Z D9, 7, 4, 2, 1,

} {

, Z Z Z Z Z D9, 7, 3, 2, 1,

} {

, Z Z Z Z Z D9, 5, 3, 2, 1,

} {

, Z Z Z Z Z D9, 4, 3, 2, 1,

}

   

(see diagram 24 of the Figure 2);

25)

{

Z Z Z Z Z D9, 8, 5, 3, 1, 

} {

, Z Z Z Z Z D9, 8, 4, 3, 1,

} {

, Z Z Z Z Z D9, 7, 5, 3, 1, 

} {

, Z Z Z Z Z D9, 7, 4, 3, 1, 

}

(see diagram 25 of the Figure 2); 26)

{

Z Z Z Z Z D9, 6, 3, 2, 1,

}

(7)

27)

{

Z Z Z Z Z D8, 7, 5, 3, 1,

} {

, Z Z Z Z Z D8, 7, 4, 3, 1, 

} {

, Z Z Z Z Z D8, 5, 4, 3, 1,

} {

, Z Z Z Z Z D7, 5, 4, 3, 1,

}

(see diagram 27 of the Figure 2);

28)

{

Z Z Z Z Z D8, 6, 5, 3, 1,

} {

, Z Z Z Z Z D8, 6, 4, 3, 1,

} {

, Z Z Z Z Z D8, 5, 3, 2, 1,

} {

, Z Z Z Z Z D7, 6, 5, 3, 1,

}

,

   

{

Z Z Z Z Z D7, 6, 4, 3, 1,

}

(see diagram 28 of the Figure 2);

29)

{

Z Z Z Z Z D8, 6, 3, 2, 1, 

} {

, Z Z Z Z Z D7, 6, 3, 2, 1, 

} {

, Z Z Z Z Z D6, 5, 3, 2, 1, 

} {

, Z Z Z Z Z D6, 4, 3, 2, 1,

}

(see diagram 29 of the Figure 2);

30)

{

Z Z Z Z Z D8, 4, 3, 2, 1,

} {

, Z Z Z Z Z D7, 5, 3, 2, 1,

} {

, Z Z Z Z Z D7, 4, 3, 2, 1,

}

  

(see diagram 30 of the Figure 2); 31)

{

Z Z Z Z Z Z D8, 7, 5, 4, 3, 1,

}

(see diagram 31 of the Figure 2);

32)

{

Z Z Z Z Z Z D6, 5, 4, 3, 2, 1,

} {

, Z Z Z Z Z Z D8, 7, 6, 3, 2, 1,

}

(see diagram 32 of the Figure 2);

33)

{

Z Z Z Z Z Z D7, 5, 4, 3, 2, 1, 

} {

, Z Z Z Z Z Z D8, 5, 4, 3, 2, 1,

} {

, Z Z Z Z Z Z D8, 7, 4, 3, 2, 1,

}

,

{

Z Z Z Z Z Z D8, 7, 5, 3, 2, 1,

}

(see diagram 33 of the Figure 2);

34)

{

Z Z Z Z Z Z D7, 6, 5, 4, 3, 1,

} {

, Z Z Z Z Z Z D8, 6, 5, 4, 3, 1,

} {

, Z Z Z Z Z Z D8, 7, 6, 4, 3, 1,

}

,

  

{

Z Z Z Z Z Z D8, 7, 6, 5, 3, 1,

}

(see diagram 34 of the Figure 2);

35)

{

Z Z Z Z Z Z D9, 6, 4, 3, 2, 1,

} {

, Z Z Z Z Z Z D9, 6, 5, 3, 2, 1,

} {

, Z Z Z Z Z Z D9, 7, 6, 3, 2, 1,

}

,

  

{

Z Z Z Z Z Z D9, 8, 6, 3, 2, 1,

} {

, Z Z Z Z Z Z D9, 8, 6, 3, 2, 1,

}

 

(see diagram 35 of the Figure 2);

36)

{

Z Z Z Z Z Z D9, 6, 5, 4, 3, 1,

} {

, Z Z Z Z Z Z D9, 8, 7, 6, 3, 1,

} {

, Z Z Z Z Z Z D9, 8, 7, 6, 3, 1,

}

  

(see diagram 36 of the Figure 2);

37)

{

Z Z Z Z Z Z D9, 7, 4, 3, 2, 1,

} {

, Z Z Z Z Z Z D9, 7, 5, 3, 2, 1,

} {

, Z Z Z Z Z Z D9, 8, 4, 3, 2, 1,

}

,

  

{

Z Z Z Z Z Z D9, 8, 5, 3, 2, 1,

}

(see diagram 37 of the Figure 2);

38)

{

Z Z Z Z Z Z D9, 7, 5, 4, 3, 1,

} {

, Z Z Z Z Z Z D9, 8, 5, 4, 3, 1,

} {

, Z Z Z Z Z Z D9, 8, 7, 4, 3, 1,

}

  

(see diagram 38 of the Figure 2); 39)

{

Z Z Z Z Z Z D9, 7, 6, 5, 3, 1,

}

(see diagram 39 of the Figure 2);

40)

{

Z Z Z Z Z Z D9, 7, 5, 4, 2, 1,

} {

, Z Z Z Z Z Z D9, 8, 5, 4, 2, 1,

} {

, Z Z Z Z Z Z D9, 8, 7, 4, 3, 2,

}

,

  

{

Z Z Z Z Z Z D9, 8, 7, 5, 3, 2,

} {

, Z Z Z Z Z Z D9, 5, 4, 3, 2, 1,

}

 

(see diagram 40 of the Figure 2);

41)

{

Z Z Z Z Z Z D9, 6, 5, 4, 2, 1,

} {

, Z Z Z Z Z Z D9, 8, 7, 6, 3, 2,

}

 

(8)

42)

{

Z Z Z Z Z Z Z D7, 6, 5, 4, 3, 2, 1, 

}

(see diagram 42 of the Figure 2);

43)

{

Z Z Z Z Z Z Z D8, 6, 5, 4, 3, 2, 1,

} {

, Z Z Z Z Z Z Z D8, 7, 6, 4, 3, 2, 1,

} {

, Z Z Z Z Z Z Z D8, 7, 6, 5, 3, 2, 1,

}

  

(see diagram 43 of the Figure 2); 44)

{

Z Z Z Z Z Z Z D8, 7, 5, 4, 3, 2, 1,

}

(see diagram 44 of the Figure 2); 45)

{

Z Z Z Z Z Z Z D9, 8, 7, 5, 4, 3, 1,

}

(see diagram 45 of the Figure 2);

46)

{

Z Z Z Z Z Z Z D9, 6, 5, 4, 3, 2, 1, 

} {

, Z Z Z Z Z Z Z D9, 8, 7, 6, 3, 2, 1, 

}

(see diagram 46 of the Figure 2);

47)

{

Z Z Z Z Z Z Z D9, 7, 5, 4, 3, 2, 1, 

} {

, Z Z Z Z Z Z Z D9, 8, 7, 5, 3, 2, 1, 

} {

, Z Z Z Z Z Z Z D9, 7, 5, 4, 3, 2, 1,

}

,

{

Z Z Z Z Z Z Z D9, 8, 7, 4, 3, 2, 1,

}

(see diagram 47 of the Figure 2);

48)

{

Z Z Z Z Z Z Z D9, 7, 6, 5, 4, 3, 1,

} {

, Z Z Z Z Z Z Z D9, 8, 6, 5, 4, 3, 1, 

} {

, Z Z Z Z Z Z Z D9, 8, 7, 6, 4, 3, 1,

}

,

{

Z Z Z Z Z Z Z D9, 8, 7, 6, 5, 3, 1,

}

[image:8.595.161.470.369.713.2]

(see diagram 48 of the Figure 2);

(9)

49)

{

Z Z Z Z Z Z Z Z D8, 7, 6, 5, 4, 3, 2, 1, 

}

(see diagram 49 of the Figure 2);

50)

{

Z Z Z Z Z Z Z Z D9, 7, 6, 5, 4, 3, 2, 1,

} {

, Z Z Z Z Z Z Z Z D9, 8, 6, 5, 4, 3, 2, 1, 

} {

, Z Z Z Z Z Z Z Z D9, 8, 7, 6, 4, 3, 2, 1, 

}

,

{

Z Z Z Z Z Z Z Z D9, 8, 7, 6, 5, 3, 2, 1,

}

(see diagram 50 of the Figure 2); 51)

{

Z Z Z Z Z Z Z Z D9, 8, 7, 5, 4, 3, 2, 1, 

}

(see diagram 51 of the Figure 2); 52)

{

Z Z Z Z Z Z Z Z D9, 8, 7, 6, 5, 4, 3, 1, 

}

(see diagram 52 of the Figure 2);

Diagrams of subsemilattices of the semilattice D.

Lemma 3. Let D∈ Σ1

(

X,10

)

. Then the following sets are all XI-subsemi-lattices of the given semilattice D: 1)

{ } { } { } { } { } { } { } { } { }

Z9 , , , , , , , , , Z8 Z7 Z6 Z5 Z4 Z3 Z2 Z1

{ }

D

(see diagram 1 of the Figure 2);

2)

{

Z D9,

}

, ,

{

Z Z9 8

} {

, ,Z Z9 7

} {

, ,Z Z9 6

} {

, ,Z Z9 5

} {

, ,Z Z9 4

} {

, ,Z Z9 3

} {

, ,Z Z9 2

} {

, ,Z Z9 1

} {

, ,Z Z8 3

}

,

{

Z D8,

}

, ,

{

Z Z7 3

}

, ,

{

Z D7

}

, ,

{

Z Z6 3

} {

, ,Z Z6 2

} {

, ,Z Z6 1

}

, ,

{

Z D6

}

, ,

{

Z Z5 1

}

, ,

{

Z D5

}

, ,

{

Z Z4 1

}

,

   

{

Z D4,

} {

, ,Z D3

} {

, ,Z D2

} { }

, ,Z D1

   

(see diagram 2 of the Figure 2);

3)

{

Z Z D9, 8,

} {

, Z Z D9, 7, 

} {

, Z Z D9, 6,

} {

, Z Z D9, 5, 

} {

, Z Z D9, 4,

} {

, Z Z D9, 3,

} {

, Z Z D9, 2,

} {

, Z Z D9, 1, 

}

,

{

Z Z Z9, 8, 3

} {

, ,Z Z Z9 7, 3

} {

, ,Z Z Z9 6, 3

} {

, ,Z Z Z9 6, 2

} {

, ,Z Z Z9 6, 1

} {

, ,Z Z Z9 5, 1

} {

, ,Z Z Z9 4, 1

}

,

{

Z Z D8, 3,

} {

, ,Z Z D7 3,

} {

, ,Z Z D6 3,

} {

, ,Z Z D6 2,

} {

, ,Z Z D6 1,

} {

, ,Z Z D5 1,

} {

, ,Z Z D4 1,

}

      

(see diagram 3 of the Figure 2);

4)

{

Z Z Z D9, 4, 1,

} {

, Z Z Z D9, 5, 1, 

} {

, Z Z Z D9, 6, 1,

} {

, Z Z Z D9, 6, 2,

} {

, Z Z Z D9, 6, 3, 

}

,

{

Z Z Z D9, 7, 3,

} {

, Z Z Z D9, 8, 3,

}

 

(see diagram 4 of the Figure 2);

5)

{

Z Z Z Z9, 5, 4, 1

} {

, ,Z Z Z Z9 6, 4, 1

} {

, ,Z Z Z Z9 6, 5, 1

} {

, ,Z Z Z Z9 7, 6, 3

} {

, ,Z Z Z Z9 8, 6, 3

}

,

{

Z Z Z Z9, 8, 7, 3

}

, ,

{

Z Z Z D9 8, 4,

} {

, ,Z Z Z D9 8, 5,

} {

, ,Z Z Z D9 7, 2,

} {

, ,Z Z Z D9 7, 4,

}

,

   

{

Z Z Z D9, 7, 5,

} {

, Z Z Z D9, 8, 1,

} {

, Z Z Z D9, 8, 2,

} {

, Z Z Z D9, 4, 2,

} {

, Z Z Z D9, 4, 3,

}

,

    

{

Z Z Z D9, 5, 2,

} {

, Z Z Z D9, 5, 3,

} {

, Z Z Z D9, 7, 1,

} {

, Z Z Z D9, 2, 1,

} {

, Z Z Z D9, 3, 1,

}

,

    

{

Z Z Z D9, 3, 2,

} {

, ,Z Z Z D6 2, 1,

} {

, ,Z Z Z D6 3, 1,

} {

, ,Z Z Z D6 3, 2,

}

   

(see diagram 5 of the Figure 2);

6)

{

Z Z Z Z D9, 5, 4, 1, 

} {

, Z Z Z Z D9, 6, 4, 1,

} {

, Z Z Z Z D9, 6, 5, 1, 

} {

, Z Z Z Z D9, 7, 6, 3,

}

,

{

Z Z Z Z D9, 8, 6, 3,

} {

, Z Z Z Z D9, 8, 7, 3,

}

 

(see diagram 6 of the Figure 2);

7)

{

Z Z Z Z D9, 6, 2, 1,

} {

, Z Z Z Z D9, 6, 3, 1,

} {

, Z Z Z Z D9, 6, 3, 2,

}

  

(10)

8)

{

Z Z Z Z Z D9, 8, 6, 3, 2, 

} {

, Z Z Z Z Z D9, 8, 6, 3, 1,

} {

, Z Z Z Z Z D9, 7, 6, 3, 2,

} {

, Z Z Z Z Z D9, 7, 6, 3, 1, 

}

,

{

Z Z Z Z Z D9, 6, 5, 3, 1,

} {

, Z Z Z Z Z D9, 6, 5, 2, 1,

} {

, Z Z Z Z Z D9, 6, 4, 3, 1,

} {

, Z Z Z Z Z D9, 6, 4, 2, 1,

}

   

(see diagram 8 of the Figure 2);

Proof.It is well know (see [1]), that the semilattices 1 to 8, which are given by lemma 2 are always XI-semi- lattices. The semilattices 9 and 10 which are given by Lemma 2

{

} {

}

{

} {

} {

}

{

} {

}

{

}

{

} {

}

{

} {

}

{

} {

} {

}

{

} {

} {

} {

} {

}

8 7 3 8 6 3 8 6 8 5 8 4

8 2 8 1 7 6 3 7 5 7 4

7 2 7 1 6 5 1 6 4 1 5 4 1

5 3 5 2 4 3 4 2 3 2

3

, , , , , , , , , , , , , , ,

, , , , , , , , , , , , , , ,

, , , , , , , , , , , , , , ,

, , , , , , , , , , , , , , ,

,

Z Z Z Z Z Z Z Z D Z Z D Z Z D

Z Z D Z Z D Z Z Z Z Z D Z Z D

Z Z D Z Z D Z Z Z Z Z Z Z Z Z

Z Z D Z Z D Z Z D Z Z D Z Z D

Z Z

  

   

 

    

{

1,D

} {

, ,Z Z D2 1,

}

.

 

(see diagram 9 of theFigure 2);

{

Z Z Z D8, 6, 3,

} {

, ,Z Z Z D8 7, 3,

} {

, ,Z Z Z D7 6, 3,

} {

, ,Z Z Z D5 4, 1,

} {

, ,Z Z Z D6 4, 1,

} {

, ,Z Z Z D6 5, 1,

}

     

(see diagram 10 of theFigure 2);

are XI-semilattices iff the intersection of minimal elements of the given semilattices is empty set. From the

for-mal equalities (1) of the given semilattice D we have

(

) (

)

8 7 0 1 2 4 5 6 7 9 0 1 2 4 5 6 8 9

ZZ = P ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P PP ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P P ≠ ∅

(

) (

)

8 6 0 1 2 4 5 6 7 9 0 4 5 7 8 9

ZZ = P ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P PP ∪ ∪ ∪ ∪ ∪P P P P P ≠ ∅

(

) (

)

8 5 0 1 2 4 5 6 7 9 0 2 3 4 6 7 8 9

ZZ = P ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P PP ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P P ≠ ∅

(

) (

)

8 4 0 1 2 4 5 6 7 9 0 2 3 5 6 7 8 9

ZZ = P ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P PP ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P P ≠ ∅

(

) (

)

8 2 0 1 2 4 5 6 7 9 0 1 3 4 5 6 7 8 9

ZZ = P ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P PP ∪ ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P P P ≠ ∅

(

) (

)

8 1 0 1 2 4 5 6 7 9 0 2 3 4 5 6 7 8 9

ZZ = P ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P PP ∪ ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P P P ≠ ∅

(

) (

)

7 6 0 1 2 4 5 6 8 9 0 4 5 7 8 9

ZZ = P ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P PP ∪ ∪ ∪ ∪ ∪P P P P P ≠ ∅

(

) (

)

7 5 0 1 2 4 5 6 8 9 0 2 3 4 6 7 8 9

ZZ = P ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P PP ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P P ≠ ∅

(

) (

)

7 4 0 1 2 4 5 6 8 9 0 2 3 5 6 7 8 9

ZZ = P ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P PP ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P P ≠ ∅

(

) (

)

7 2 0 1 2 4 5 6 8 9 0 1 3 4 5 6 7 8 9

ZZ = P ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P PP ∪ ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P P P ≠ ∅

(

) (

)

7 1 0 1 2 4 5 6 8 9 0 2 3 4 5 6 7 8 9

ZZ = P ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P PP ∪ ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P P P ≠ ∅

(

) (

)

6 5 0 4 5 7 8 9 0 2 3 4 6 7 8 9

ZZ = P ∪ ∪ ∪ ∪ ∪P P P P PP ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P P ≠ ∅

(

) (

)

6 4 0 4 5 7 8 9 0 2 3 5 6 7 8 9

ZZ = P ∪ ∪ ∪ ∪ ∪P P P P PP ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P P ≠ ∅

(

) (

)

5 4 0 2 3 4 6 7 8 9 0 2 3 5 6 7 8 9

ZZ = P ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P PP ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P P ≠ ∅

(

) (

)

5 3 0 2 3 4 6 7 8 9 0 1 2 4 5 6 7 8 9

ZZ = P ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P PP ∪ ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P P P ≠ ∅

(

) (

)

5 2 0 2 3 4 6 7 8 9 0 1 3 4 5 6 7 8 9

ZZ = P ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P PP ∪ ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P P P ≠ ∅

(

) (

)

4 3 0 2 3 5 6 7 8 9 0 1 2 4 5 6 7 8 9

(11)

(

) (

)

4 2 0 2 3 5 6 7 8 9 0 1 3 4 5 6 7 8 9

ZZ = P ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P PP ∪ ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P P P ≠ ∅

(

) (

)

3 2 0 1 2 4 5 6 7 8 9 0 1 3 4 5 6 7 8 9

ZZ = P ∪ ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P P PP ∪ ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P P P ≠ ∅

(

) (

)

3 1 0 1 2 4 5 6 7 8 9 0 2 3 4 5 6 7 8 9

ZZ = P ∪ ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P P PP ∪ ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P P P ≠ ∅

(

) (

)

2 1 0 1 3 4 5 6 7 8 9 0 2 3 4 5 6 7 8 9

ZZ = P ∪ ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P P PP ∪ ∪ ∪ ∪ ∪ ∪ ∪ ∪P P P P P P P P ≠ ∅

From the equalities given above it follows that the semilattices 9 and 10 are not XI-semilattices.

The semilattices 11

{

} {

} {

} {

}

{

} {

} {

} {

}

6 5 3 1 6 5 2 1 6 4 3 1 6 4 2 1

7 6 3 2 7 6 3 1 8 6 3 2 8 6 3 1

, , , , , , , , , , , , , , , , , , , ,

, , , , , , , , , , , , , , , , , , , .

Z Z Z Z D Z Z Z Z D Z Z Z Z D Z Z Z Z D

Z Z Z Z D Z Z Z Z D Z Z Z Z D Z Z Z Z D

   

   

(see diagram 1-8 of theFigure 3);

are not XI-semilattice since we have the following inequalities

5 3 5 2 4 3 4 2

7 2 7 1 8 2 8 1

, , , , , , , .

Z Z Z Z Z Z Z Z

Z Z Z Z Z Z Z Z

∩ ≠ ∅ ∩ ≠ ∅ ∩ ≠ ∅ ∩ ≠ ∅

∩ ≠ ∅ ∩ ≠ ∅ ∩ ≠ ∅ ∩ ≠ ∅

The semilattices 12 to 52 are never XI-semilattices. We prove that the semilattice, diagram 52 of theFigure 2,

is not an XI-semilattice (seeFigure 4). Indeed, let Q=

{

T T T T T T T T T0, ,1 2, 3, 4, 5, 6, 7, 8

}

and

( ) {

0, 1, 2, 3, 4, 5, 6, 7, 8

}

C Q = P P P P P P P P P′ ′ ′ ′ ′ ′ ′ ′ ′

be a family of sets, where P P P P P P P P P0′, , , , , , , , 1′ ′2 3′ ′4 5678′ are pairwise disjoint subsets of the set X. Let

0 1 2 3 4 5 6 7 8

0 1 2 3 4 5 6 7 8

T T T T T T T T T

P P P P P P P P P

ϕ=  

 

be a mapping of the semilattice Q onto the family of sets C Q

( )

. Then for the formal equalities of the

[image:11.595.214.412.455.571.2]

semilat-tice Q we have a form:

Figure 3. Diagram of all subsemilattices which are isomorphic to 11 in Figure 2.

[image:11.595.251.377.610.703.2]
(12)

0 0 1 2 3 4 5 6 7 8

1 0 2 3 4 5 6 7 8

2 0 1 3 4 5 6 7 8

3 0 2 4 5 6 7 8

4 0 2 3 5 6 7 8

5 0 3 4 6 7 8

6 , , , , , ,

T P P P P P P P P P T P P P P P P P P T P P P P P P P P T P P P P P P P T P P P P P P P T P P P P P P T ′ ′ ′ ′ ′ ′ ′ ′ ′ = ∪ ∪ ∪ ∪ ∪ ∪ ∪ ∪ ′ ′ ′ ′ ′ ′ ′ ′ = ∪ ∪ ∪ ∪ ∪ ∪ ∪ ′ ′ ′ ′ ′ ′ ′ ′ = ∪ ∪ ∪ ∪ ∪ ∪ ∪ ′ ′ ′ ′ ′ ′ ′ = ∪ ∪ ∪ ∪ ∪ ∪ ′ ′ ′ ′ ′ ′ ′ = ∪ ∪ ∪ ∪ ∪ ∪ ′ ′ ′ ′ ′ ′ = ∪ ∪ ∪ ∪ ∪

0 1 3 4 5 7 8

'

7 0 1 3 4 5 6 8

8 0

, , .

P P P P P P P T P P P P P P P T P ′ ′ ′ ′ ′ ′ ′ = ∪ ∪ ∪ ∪ ∪ ∪ ′ ′ ′ ′ ′ ′ = ∪ ∪ ∪ ∪ ∪ ∪ ′ = (3)

Here the elements P P P P P P1′, 2′ ′, 3, 4′, 6′, 7′ are basis sources, the elements P0′, P5′, P8′ are sources of

com-pleteness of the semilattice D. Therefore X ≥6 and

δ

=7 (see [2]). Then of the formal equalities we have:

{

}

{

}

{

}

{

}

{

}

{

}

0

7 6 2 0 1

4 3 1 0 2

7 6 5 4 2 1 0 3

7 6 5 3 2 1 0 4

7 6 4 3 2 1 0 5

7 5 4 3 2 1 0 6

6 5 4 3 2 1

, if ,

, , , , if ,

, , , , if ,

, , , , , , , if ,

, , , , , , , if ,

, , , , , , , if ,

, , , , , , , if ,

, , , , ,

t

Q t P

T T T T t P

T T T T t P

T T T T T T T t P

T T T T T T T t P

Q

T T T T T T T t P

T T T T T T T t P

T T T T T T

′ ∈ ′ ∈ ′ ∈ ′ ∈ ′ ∈ = ′ ∈ ′ ∈

{

}

{

8 7 6 5 4 3 02 1 0

}

78

, , if ,

, , , , , , , , , if .

T t P

T T T T T T T T T t P

              ∈ ′ 

(

)

8 0 8 1 8 2 8 3 8 4 8 5 8 6 8 7 8 8

, if ,

, if ,

, if ,

, if ,

, , if ,

, if ,

, if ,

, if ,

, if .

t

T t P

T t P

T t P

T t P

Q Q T t P

T t P

T t P

T t P

T t P

′ ∈     ∈ ′  

Λ =

 ′ ∈     ∈ ′ 

We have, that Q∧ =

{ }

T8 and Λ

(

Q Q, t

)

Q for any tQ. But elements T7, T6, T5, T4, T3, T2, T1, T0 are not

union of some elements of the set Q∧. Therefore from the Definition 1 it follows that Q is not an XI-semilattice

of unions. Statements 12 to 51 can be proved analogously. We denoted the following semitattices by symbols:

a) Q1=

{ }

T , where TD (see diagram 1 of theFigure 5);

b) Q2=

{

T T, ′

}

, where T T, ′∈D and TT′ (see diagram 2 of theFigure 5);

c) Q3=

{

T T T, ′ ′′,

}

, where T T, , ′ T′′∈D and TT′⊂T′′ (see diagram 3 of theFigure 5); d) Q4=

{

Z T T D9, , ′, 

}

, where T T, ′∈D and Z9⊂ ⊂T T′⊂D (see diagram 4 of theFigure 5);

e) Q5=

{

T T T T, ′ ′′ ′, , ∪T′′

}

where T T, , ′ T′′∈D, TT′, TT′′, T′\T′′ ≠ ∅, T′′\T′ ≠ ∅, (see dia-

gram 5 of theFigure 5);

f) Q6 =

{

Z T T T9, , ′, ∪T D′, 

}

, where T T, ′∈D, Z9T, Z9T′, T T\ ′ ≠ ∅, T′\T ≠ ∅ (see diagram

6 of theFigure 5);

g) Q7=

{

Z Z T T D9, 6, , ′, 

}

, where , T T′∈D, Z6T , Z6T′, T T\ ′ ≠ ∅, T′\T ≠ ∅, TT′=D

[image:12.595.83.543.89.524.2] [image:12.595.220.423.255.529.2]
(13)
[image:13.595.169.483.82.188.2]

Figure 5. Diagram of all XI-subsemilattices of D.

h) Q8=

{

Z T T T9, , ′, ∪T Z D′, ,

}

, where Z9T′⊂Z, T T\ ′ ≠ ∅, T′\T ≠ ∅,

(

TT

)

\Z≠ ∅,

(

)

\

Z TT′ ≠ ∅ (see diagram 8 of theFigure 5);

Note that the semilattices inFigure 5 are all XI-semilattices (see [1] and Lemma 1.2.3).

Definition 9. Let us assume that by the symbol Σ′XI

(

X D,

)

denote a set of all XI-subsemilatices of X-semila-

tices of unions D that every element of this set contains an empty set if ∅ ∈D or denotes a set of all XI-sub- semilatices of D.

Further, let D D′, ,′′∈ Σ′XI

(

X D

)

and ϑXI ⊆ Σ′XI

(

X D,

)

× Σ′XI

(

X D,

)

. It is assumed that D′ϑXID′′ iff there

exists some complete isomorphism

ϕ

between the semilatices D′ and D′′. One can easily verify that the

binary relation ϑXI is an equivalence relation on the set Σ′XI

(

X D,

)

.

By the symbol QiϑXI denote the ϑXI-equivalence class of the set Σ′XI

(

X D,

)

, where every element is iso-

morphic to the X-semilattice Qi

(

i=1, 2,,8

)

.

Let D' be an XI-subsemilattice of the semilattice D. By I D

( )

′ we denoted the set of all right units of the

se-migroup BX

( )

D′ , and

( )

( )

i XI

i D Q

I Q I D

ϑ ∗

′∈

=

where i=1, 2,,8.

Lemma 4. If X is a finite set, then the following equalities hold a) I Q

( )

1 =1

b) I Q

( )

2 =

(

2T T′\ − ⋅1 2

)

X T\ ′

c) I Q

( )

3 =

(

2T T′\ − ⋅1

) (

3T′′ ′\T −2T′′ ′\T

)

⋅3X T\ ′′

d)

( )

(

\9

) (

\ \

)

(

\ \

)

\

4 2 1 3 2 4 3 4

D T D T X D

T Z T T T T

I Q = − ⋅ ′ − ′ ⋅ ′ − ′ ⋅

  

e) I Q

( )

5 =

(

2T T′ ′′\ − ⋅1

) (

2T′′ ′\T − ⋅1 4

)

X\(T′∪T′′)

f) I Q

( )

6 =

(

2T T′ ′′\ − ⋅1

) (

2T T′′ ′\ − ⋅1

)

(

5D T\( ∪T′′)−4D T\( ∪T′′)

)

⋅5X D\

  

g)

( )

(

6\ 9

)

( )\ 6

(

\ \

) (

\ \

)

\

7 2 1 2 3 2 3 2 5

T T Z X D

Z Z T T T T T T T T

I Q = − ⋅ ∩ ′ ⋅ ′ − ′ ⋅ ′ − ′ ⋅ 

h) I Q

( )

8 =

(

2T Z\ − ⋅1

) (

2T T′\ − ⋅1

)

(

3Z T\( ∪T′) −2Z T\( ∪T′)

)

⋅6X D\

Proof. This lemma immediately follows from Theorem 13.1.2, 13.3.2, and 13.7.2 of the [1]. 

Theorem 10. Let D∈Σ1

(

X,10

)

and α ∈BX

( )

D . Binary relation

α

is an idempotent relation of the semmigroup BX

( )

D iff binary relation

α

satisfies only one conditions of the following conditions:

a)

α

= ×X T, where TD;

b)

α

=

(

YTα×T

) (

YTα′×T

)

, where T T, ′∈D, TT′, YT , YT

{ }

α α

′ ∉ ∅ , and satisfies the conditions: YT

α

T, YTα′∩T′≠ ∅;

c)

(

YT T

) (

YT T

) (

YT T

)

α α α

α

= × ∪ ′× ′ ∪ ′′× ′′ , where T T, , ′ T′′∈D, TT′⊂T′′, YT , , YT YT

{ }

α α α

′ ′′∉ ∅ , and sa-

tisfies the conditions: YTα ⊇T , YTα∪YTα′ ⊇T′, YT T

α

′ ∩ ′≠ ∅, YT T

α

Figure

Figure 1. Diagram of D.
Figure 2. Diagram of all subsemilattices of D.
Figure 4. Diagram of subsemilattice 52 in Figure 2.
Figure 5Z T T T′,
+4

References

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