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ISSN 2229 – 5046closed
I
g
*S−
Sets in Ideal Topological Spaces
Sr. Pauline Mary Helen*
Associate Professor, Nirmala College, Coimbatore, India
Mrs. Ponnuthai Selvarani
Associate Professor, Nirmala College, Coimbatore, India
Mrs. Veronica Vijayan
Associate Professor, Nirmala College, Coimbatore, India
(Received on: 03-06-12; Revised & Accepted on: 30-06-12)
ABSTRACT
I
n this paper,g
*SI
−
closed
sets,*
s
- additive,*
s
- multiplicative,g
*SI
- additive andg
*SI
- multiplicative spaces are introduced and their properties are investigated. We introduce the notion ofg
*SI
−
continuous
function and other related functions. The relationships between them are also studied.Keywords: Semi local function,
g
*SI
−
closed
set,g
*SI
−
open
set,g
*SI
−
continuous
function, weaklycontinuous
I
g
*S−
function, stronglyg
*SI
−
continuous
function,g
*SI
- additive space,g
*SI
- multiplicative space,g
*SI
- connected space,g
*SI
- compact space.1. Introduction
Ideals in topological spaces have been considered since 1930. In 1990, Jankovic and Hamlett [5] once again investigated applications of topological ideals. EI – Monsefetal [1] in 1992 and quite recently Khan and Noiri [7] have studied semi-local functions in ideal topological spaces.
Ig
−
closed
sets were first introduced by Dontchev etal [2] in 1999.gI
−
closed
sets were introduced by M. Khan and T. Noiri [6] in 2010,sgI
−
closed
sets were introduced by M. Khan and T. Noiri [8] in 2011, andI
s*g−
closed
sets were introduced by M. Khan and M.Hamza[4] in 2011. In this paper we define
g
*SI
−
closed
sets,g
*SI
−
continuous
function, and various other related properties of these closed sets and the relationship between these functions are obtained.2. Preliminaries
An ideal I on a non empty set
X
is a collection of subsets ofX
which satisfies the following properties.(i)
A
∈
I
,B
∈
I
⇒
A
∪
B
∈
I
(ii)
A
∈
I
,B
⊂
A
⇒
B
∈
I
A topological space
(
X
,
τ
)
with an idealI
onX
is called an ideal topological space and is denoted by(
X
,
τ
,
I
)
.Let
Y
be a subset ofX
.I
Y=
{
I
∩
Y
/
I
∈
I
}
is an ideal onY
and by(
Y
,
τ
/
Y
,
I
Y)
we denote the ideal topological subspace. LetP
(
X
)
be the power set ofX
, then a set operator ( )*:P
(
X
)
→
P
(
X
)
called the local function [10] of A with respect toτ
andI
is defined as follows:For
A
⊂
X
,A
*(
I
,
τ
)
=
{
x
∈
X
/
U
∩
A
∉
I
for every open setU
containingx
}
.We simply write
A
*instead ofA
*(
I
,
τ
)
in case there is no confusion. A Kuratowski closure operatorcl
*(
)
for a topologyτ
*(
I
,
τ
)
, called the τ*- topology is defined bycl
*(
A
)
=
A
∪
A
*[
4
]
.A subset A of a space
(
X
,
τ
)
is said to be semi-open[1] ifA
⊂
cl
(int(
A
))
.A set operator
(
)
*:
(
)
(
)
X
P
X
P
S
→
called a semi local function and *s
( )
cl
[1] ofA
with respect toτ
andI
are defined as follows:
For
A
⊂
X
,A
*S(
I
,
τ
)
=
{
x
∈
X
/
U
∩
A
∉
I
for every semi open setU
containingx
}
. andS S
A
A
A
Cl
*(
)
=
∪
* .Note:
A
*S defined in [1] andA
* defined in [9] are the same. For a subsetA
ofX
,cl
(
A
)
(
respscl
(
A
))
denotes the closure(
resp semi closure)
ofA
in(
X
,
τ
)
. Similarlycl
*(
A
)
andint
*(
A
)
denote the closure ofA
and interior ofA
in(
X
,
τ
*)
.A subset
A
ofX
is called * closed [5] (resp.∗ 𝑠𝑠 - closed) ifA
*⊆
A
(respA
*S⊆
A
).A
is called * - dense [5] in itself ( resp .∗ 𝑠𝑠 - dense). IfA
⊂
A
* ( respA
⊂
A
*S)A
is called * - perfect [5] ( resp .∗ 𝑠𝑠 - perfect). IfA
=
A
* (respA
=
A
*S) A subsetA
of a topological space (𝑋𝑋, 𝜏𝜏)is said to be generalized closed [5] (briefly g-closed) ifU
A
cl
(
)
⊂
wheneverA
⊂
U
andU
is open inX
. The complement ofg
−
closed
set is said to beg
−
open
.Definition 2.1: A subset
A
of a space(
X
,
τ
,
I
)
is said to be(i)
gI
−
closed
[
6
]
ifA
*S⊆
U
whereverA
⊆
U
andU
−
open
inX
. (ii)I
g−
closed
[
2
]
ifA
⊆
U
*
wherever
A
⊆
U
andU
−
open
inX
.(iii)
sgI
−
closed
[
8
]
ifA
*S⊆
U
whereverA
⊆
U
andU
−
semi
open
inX
. (iv)I
s*g−
closed
[
4
]
ifA
⊂
U
*
wherever
A
⊆
U
andU
−
semi
open
inX
.The complements of
gI
−
closed
(respI
g−
closed
,sgI
−
closed
,I
s*g−
closed
) are calledgI
−
open
(resp
I
g−
open
,sgI
−
open
,I
s*g−
open
).Lemma 2.2 [1]: For
A
,B
in(
X
,
τ
,
I
)
we have (i) IfA
⊂
B
thenA
*S⊂
B
*S(ii)
( )
A
*S *S⊆
A
*S(iii)
A
*S∪
B
*S⊇
(
A
∪
B
)
*S (iv)(
A
∩
B
)
*S⊆
A
*S∩
B
*S(v) If
I
=
{ }
φ
,A
*S=
scl
(
A
)
andcl
*S(
A
)
=
scl
(
A
)
(vi) IfI
=
ρ
(
X
)
thenA
*S=
φ
andcl
*S(
A
)
=
A
(vii)A
*S=
scl
(
A
*S)
⊂
scl
(
A
)
andA
*S is semi closed.3.
g
*SI
- closed setsDefinition 3.1: A subset
A
of an ideal space(
X
,
τ
,
I
)
is said to beg
*SI
closed, ifcl
*S(
A
)
⊆
U
wheneverU
A
⊆
andU
isg
−
open
inX
.Remarks: 3.1
1. If
I
=
p
(
X
)
thencl
*S(
A
)
=
A
∀
A
⊆
X
and hence every subset ofX
isg
*SI
−
closed
. 2. SinceA
*S=
{ }
φ
for everyA
∈
I
, every member ofI
isg
*SI
−
closed
.3. Since every open set is
g
−
open
, everyg
*SI
−
closed
set isgI
−
closed
. But the converse is not true in general as seen from example (3.1).4. Every
τ
*S−
closed
set is
g
*SI
−
closed
. But the converse is not true in general as seen from example (3.3). 5.I
s*g−
closed
andg
*SI
−
closed
are independent concepts as seen from example (3.3, 3.2).6.
I
g−
closed
andg
*SI
−
closed
are independent concepts as seen from example (3.1, 3.4).7.
sgI
−
closed
andg
*SI
−
closed
are independent concepts as seen from example (3.1).Example 3.1: Let
(
X
,
τ
)
be an indiscrete space,x
0∈
X
andI
=
{
φ
,
{ }
x
0}
.Then
A
*S=
A
*=
X
ifA
≠
{ }
x
0=
φ
ifA
=
{ }
x
0 .Any subset
A
≠
{ }
x
0 isgI
−
closed
,I
g−
closed
,sgI
−
closed
,I
s*g−
closed
but notclosed
S−
*
τ
andclosed
I
g
*S−
.Example 3.2: Let
(
X
,
τ
)
be an indiscrete spacep
∈
X
andI
=
{
A
⊆
X
/
p
∉
A
}
.Then
A
*S=
A
*=
X
ifp
∈
A
=
φ
ifp
∉
A
.{ }
p
A
=
isgI
−
closed
,I
g−
closed
,sgI
−
closed
,I
s*g−
closed
but notclosed
S−
*
τ
andg
*SI
−
closed
.Example 3.3: Let
X
=
{
a
,
b
,
c
,
d
}
,τ
=
{
φ
,
{ }
a
,
b
,
X
}
, andI
=
{ }
φ
{ }
a
, thenA
=
{ }
a
,
c
isg
*SI
−
closed
but notτ
*S−
closed
andA
=
{ }
c
isg
*SI
−
closed
but notI
s*g−
closed
.Example 3.4: Let
X
=
{
a
,
b
,
c
,
d
}
,τ
=
{
φ
,
X
,
{ } { } { }
a
,
b
,
a
,
b
}
, andI
=
{ }
φ
, thenA
=
{ }
a
isg
*SI
−
closed
but notIg
−
closed
.Note: In an ideal space
(
X
,
τ
,
I
)
,(
A
∪
B
)
*S≠
A
*S∪
B
*S in general as seen from example 3.5.Example 3.5: Let
X
=
{
a
,
b
,
c
,
d
}
,τ
=
{
φ
,
X
,
{ } { } { }
a
,
b
,
a
,
b
}
,I
=
{ }
φ
.Then
{ }
a
*S=
{ }
a
,{ }
b
*S=
{ }
b
and{ }
a
,
b
*S=
X
.This shows
(
A
∪
B
)
*S≠
A
*S∪
B
*S.Definition 3.2: An ideal space
(
X
,
τ
,
I
)
is said to be(i)
*
S
−
finitely additive if
n
i
S i S
n
i
i
A
A
1 * *
1
)
(
= =
=
for every positive integer
n
.(ii)
*
S
−
countably additive if
∞= =
=
1 * *
1
)
(
i
S i S
n
i
i
A
(iii)
*
S
−
additive if*
*
(
)
S
S
A
αA
αα∈Ω α∈Ω
=
for all indexing setsΩ
where Ai ‘s are subsets of X.Similarly we define
*
s
- finitely multiplicative, countably multiplicative ideal spaces by taking intersection in the place of union.(iv)
g
*SI
- finitely additive (respg
*SI
- countable additive,g
*SI
- additive) if finite union (resp countable union, arbitrary union) ofg
*SI
−
closed
sets isg
*SI
−
closed
.Similarly we define
g
*SI
- finitely multiplicative (respg
*SI
- countably multiplicative,g
*SI
- multiplicative) if finite intersection (resp countable intersection, arbitrary intersection) ofg
*SI
−
closed
sets isg
*SI
−
closed
.Remark 3.2:
1.
*
s
- finitely additive (respg
*SI
- countable additive, additive spaces )areg
*SI
- finitely additive (resp countably additive, additive) but not conversely.2.
*
s
- additive spaces are*
s
countably additive and*
s
countable additive spaces are*
s
- finitely additive but not conversely.3.
g
*SI
additive spaces areg
*SI
- countably additive andg
*SI
- countably additive spaces areg
*SI
- additive but not conversely.Example 3.3: Let
X
=
R
,I
=
{ }
φ
,τ
- cofinite topology.Then
=
φ
,
X
,
A
/
A
cis
finite
τ
. Closed sets areφ
,X
and all the finite subsets.A
*S=
A
if A is finite and Xif A is infinite.
For every positive integer n,
let
A
n=
{
−
n
,
−
n
+
1
,...
0
,...,..
....
n
−
1
,
n
}
thenA
A
nn
S
n
=
∀
*
.
(
UA
n)
*S=
(
Z
)
*S=
R
andU
(
A
n)
*S=
Z
let A, B be set of all non negative and non positive integers respectively.
Then
A
*S=
R
=
B
*S,A
*S∩
B
*S=
R
and(
A
∩
B
)
*S=
{ }
0
*S=
{ }
0
. Therefore this space is 1. not*
s
- finitely multiplicative, and hence not*
s
- countably multiplicative, and not*
s
- multiplicative. 2.*
s
- finitely additive but not countably*
s
- additive, and not*
s
- additive.3.
g
*SI
- multiplicative,g
*SI
- finitely multiplicative andg
*SI
- countably multiplicative. 4.g
*SI
- finitely additive, but notg
*SI
- countably additive and notg
*SI
- additive.Example 3.4: Let
(
X
,
τ
)
be indiscrete spacex
0∈
X
andI
=
{
φ
,
{ }
x
0}
. thenGO X
( )
=
{
all subsets
}
.X
A
*S=
, ifA
≠
{ }
x
0 andA
*S=
φ
ifA
=
{ }
x
0 ,cl
*S(
A
)
=
X
ifA
≠
{ }
x
0 andcl
*S( )
A
=
A ifA
=
{ }
x
0 .{ }
{
0}
*
,
,
)
(
X
X
x
IC
G
S=
φ
. IfB
=
{
x x
0,
1}
andC
=
{
x x
0,
2}
wherex
1,
x
2≠
x
0 in X,then
B
*S=
X
,C
*S=
X
,B
*S∩
C
*S=
X
;(
B
∩
C
)
*S=
{ }
x
0 *S=
{ }
φ
. Therefore this space is 1. not*
s
- multiplicative, and not*
s
- finitely multiplicative, and not*
s
- countably multiplicative.2.
g
*SI
- additiveg
*SI
- multiplicative,g
*SI
- finitely additive ,g
*SI
- multiplicative andg
*SI
- countably additive andg
*SI
-countably multiplicative.Remark: 3.3: In an ideal topological space
(
X
,
τ
,
I
)
which is*
S
−
finitely additive we have following results:1.
cl
*S(
φ
)
=
φ
2.cl
*S(
X
)
=
X
3.A
⊆
cl
*S(
A
)
4.
cl
*S(
A
∪
B
)
=
cl
*S(
A
)
∪
cl
*S(
B
)
5.cl
*S(
cl
*S(
A
)
)
=
cl
*S(
A
)
for all subsets A, B and X.
Therefore
cl
*S(
)
satisfies Kuratowski Closure axioms [10] and hence it defines a topologyτ
*Swhose closure operation is given ascl
*S(
A
)
=
A
∪
A
*S. Note thatτ
⊆
τ
*⊆
τ
*S.cl
*S(
A
)
and
int
(
)
*A
S
denote the closure
and interior of A in
(
X
,
τ
*S)
.Theorem 3.1: A subset of a
*
S
−
finitely additive ideal space(
X
,
τ
,
I
)
isg
*SI
−
open
if and only if)
(
*A
Int
F
⊂
S whereverF
⊆
A
andF
is ag
−
closed
subset ofX
.Proof: Let
A
beg
*SI
−
open
andF
be ag
−
closed
subset ofX
contained inA
. Then(
X
−
F
)
is aopen
g
−
set containingX
−
A
which impliesX
−
Int
*S(
A
)
=
cl
*S(
X
−
A
)
⊂
X
−
F
Conversely, let)
(
*A
Int
F
⊂
S wheneverF
⊆
A
andF
is ag
−
closed
subset ofX
.Let
U
beg
−
open
andX
−
A
⊂
U
. ThenX
−
U
⊂
Int
*S(
A
)
=
X
−
cl
*S(
X
−
A
)
. ThereforeU
A
X
cl
*S(
−
)
⊂
which provesX
−
A
isg
*SI
−
closed
. SoA
isg
*SI
−
open
.Theorem 3.2: For each
x
∈
(
X
,
τ
,
I
)
either{ }
x
isg
−
closed
or{ }
x
c isg
*SI
−
closed
inX
.Proof: Suppose
{ }
x
is notg
−
closed
, then{ }
x
c is notg
−
open
.Therefore the onlyg
−
open
set containing{ }
cx
isX
and( )
{ }
x
c *S⊆
X
which proves that{ }
x
c isg
*SI
−
closed
.Theorem 3.3: In an ideal space
(
X
,
τ
,
I
)
which is*
S
- finitely additive, ifU
is semi open andA
isg
*SI
−
open
, thenU
∩
A
isg
*SI
−
open
.Proof: Let
X
−
(
U
∩
A
)
⊂
G
andG
beg
−
open
.Then
(
X
−
A
)
∪
(
X
−
U
)
⊂
G
and this impliesX
−
A
⊂
G
andX
−
U
⊂
G
.(
X
−
A
)
isg
*SI
−
closed
andG
isg
−
open
implycl
*S(
X
−
A
)
⊂
G
andcl
*S(
X
−
U
)
⊂
scl
(
X
−
U
)
=
X
−
U
⊂
G
Therefore
cl
*S[
X
−
(
A
∩
U
)
]
=
cl
*S[
(
X
−
A
)
∪
(
X
−
U
)
]
cl
*S(
X
−
A
)
∪
cl
*S(
X
−
U
)
⊂
G
(since the ideal space is*
S
- finitely additive) This impliesA
∩
U
isg
*SI
−
open
.Theorem 3.4: If
B
is a subset of a*
S
- finitely additive space(
X
,
τ
,
I
)
such thatA
⊂
B
⊂
cl
*S(
A
)
andA
isclosed
I
g
*S−
, thenB
is alsog
*SI
−
closed
inX
.Proof: Let
U
beg
−
open
andB
⊂
U
. ThenA
⊂
U
impliescl
*S(
A
)
⊂
U
Note: In general intersection of g-closed sets need not be g-closed.
Definition 3.3 A topological space
( , )
X
τ
is said to be a g-multiplicative space if arbitrary intersection of g-closed sets in X is g-closed.Remark 3.4
(i) In g-multiplicative spaces, gcl(A) which is the intersection of all g-closed sets in X containing A is also g-closed. (ii) Any indiscrete topological space
( , )
X
τ
is g – multiplicative.(iii) If X = {a,b,c} and τ = {X, φ, {a}} then {a,c} and {a,b} are g-closed but {a} is not g-closed and hence
( , )
X
τ
is not g-multiplicative.Theorem 3.5: Let
(
X
,
τ
,
I
)
be a g-multiplicative ideal space andA
beg
*SI
−
closed
subset ofX
. Then (i)scl
(
A
*S)
⊂
U
for allg
−
open
setU
containingA
.(ii) For all
x
∈
scl
(
A
*S)
,gcl
( )
{ }
x
∩
A
≠
φ
(iii)scl
(
A
*S)
−
A
contains no non empty
g
−
closed
set. (iv)(
A
*S)
−
A
contains no non empty
g
−
closed
set.Proof:
(i) Since
(
A
*S)
=
scl
A
*S, the result follows from definition.(ii) Let
x
∈
scl
(
A
*S)
. Supposegcl
( )
{ }
x
∩
A
=
φ
thenA
⊂
X
−
gcl
( )
{ }
x
which isg
−
open
By (i)scl
(
A
*S)
⊂
X
−
gcl
( )
{ }
x
which is a contradiction to the factx
∈
scl
(
A
*S)
.(iii) Suppose that there exists a non empty
g
−
closed
set F such thatF
⊂
scl
(
A
*S)
−
A
.If
x
∈
F
, thengcl
( )
{ }
x
⊆
gcl
(
F
)
=
F
andA
∩
gcl
( )
{ }
x
=
φ
.Since
x
∈
scl
(
A
*S)
, by (ii)gcl
( )
{ }
x
∩
A
≠
φ
which is a contradiction.(iv) It follows from (iii) since
A
*S=
scl
(
A
*S)
.Theorem 3.6: Let
(
X
,
τ
,
I
)
be a g-multiplicative ideal space and letA
beg
*SI
−
closed
. ThenA
isA
A
closed
SS
−
⇔
*−
*
τ
is closed.Proof:
Necessity:
A
isτ
*S−
closed
⇒
A
*S⊂
A
⇒
A
*S−
A
=
φ
which is closed.
Sufficiency: Let
A
*S−
A
be closed. Then it isg
−
closed
By (iv) of theorem (3.5),A
*S−
A
=
φ
which impliesA
A
*S⊂
.Theorem 3.7: Let
(
X
,
τ
,
I
)
be a g-multiplicative ideal space andA
⊂
X
. IfA
isg
*SI
−
closed
then)
(
X
A
*SA
∪
−
isg
*SI
−
closed
.Proof: Let
U
beg
−
open
andA
∪
(
X
−
A
*S)
⊂
U
.Then
X
−
U
⊂
X
−
[
A
∪
(
X
−
A
*S)]
=
A
*S−
A
.SinceA
isg
*SI
−
closed
,A
*S−
A
contains no non emptyclosed
g
−
set. ThereforeX
−
U
=
φ
which impliesX
=
U
. ThusX
is the onlyg
−
open
set containing)
(
X
A
*STheorem 3.8: Let A be a subset of a g-multiplicative ideal space
(
X
,
τ
,
I
)
. IfA
isg
*SI
−
closed
thenA
*S−
A
isopen
I
g
*S−
.Proof: Since
X
−
(
A
*S−
A
)
=
A
∪
(
X
−
A
*S)
, the proof follows from theorem 3.7.Theorem 3.9: Let
(
X
,
τ
,
I
)
be an ideal space. If everyg
−
open
set isτ
*S−
closed
, then every subset ofX
isclosed
I
g
*S−
.Proof: Let
A
⊂
U
andU
be ag
−
open
set inX
. Thencl
*S(
A
)
⊂
cl
*S(
U
)
=
U
which provesA
isclosed
I
g
*S−
.Theorem 3.10: [(6) Theorem 3.20] Let
(
X
,
τ
,
I
)
be an ideal space andA
⊂
Y
⊂
X
whereY
isα
−
open
inX
.Then
A
*S(
I
Y,
τ
/
Y
)
=
A
*S(
I
,
τ
)
∩
Y
.Theorem 3.11: Let
(
X
,
τ
,
I
)
be an ideal space andA
⊂
Y
⊂
X
. IfA
isg
*SI
−
closed
in(
Y
,
τ
/
Y
,
I
Y)
,Y
isopen
−
α
andτ
*S−
closed
inX
. ThenA
isg
*SI
−
closed
inX
.Proof: Let
A
⊂
U
andU
beg
−
open
inX
. Then(
)
A
I
Y
U
Y
Y
I
A
Y SS
=
∩
⊂
∩
)
,
(
,
**
τ
τ
.
Then
Y
⊂
U
∪
(
X
−
A
*S(
I
,
τ
))
. SinceY
isτ
*S−
closed
,Y
*S⊂
Y
. ThereforeA
*S⊂
Y
*S⊂
Y
⊂
U
∪
(
X
−
A
*S(
τ
,
I
))
. This impliesA
*S⊂
U
and hencecl
*S(
A
)
⊂
U
. SoA
isg
*SI
−
closed
inX
.Definition 3.4:
{
A
α/
α
∈
Ω
}
is said to be a locally finite (resp. locally countable) family of sets in(
X
,
τ
,
I
)
if for everyx
∈
X
, there exists an open setU
inX
containingx
that intersects only a finite (resp. countable) number of membersn
A
A
α,...,
α1 (resp
A
αi,
i
=
1
,...
∞
) of{
A
α/
α
∈
Ω
}
.Theorem 3.13: Let
(
X
,
τ
,
I
)
be an ideal space which is*
S
- finitely additive, and let{
A
α/
α
∈
Ω
}
be a locallyfinite family of sets in
(
X
,
τ
,
I
)
. Then
( )
Ω ∈ Ω ∈=
α α α α S SA
A
* * .Proof:
A
α⊆
A
α impliesA
α*S⊆
(
A
α)
*S. ThereforeS S
A
A
* *)
(
⊆
Ω ∈ Ω ∈
α αα α (1)
On the otherhand, if
S
A
x
*
∈
Ω ∈
α αthen there exists an open set
U
containingx
, that intersects only finite numberof members
n
A
A
α,...,
α1 .Let
V
be a semi-open set containingx
. ThenU
∩
V
is a semi-open set containingx
.which implies
(
U
V
)
A
∉
I
∩
∩
Ω ∈
α α .i.e.
(
U
V
)
A
(
U
V
)
A
I
n i i i
∉
∩
∩
∩
= ≠
1 α α α αi.e.
{ } (
U
V
)
A
I
n
i
i
∉
∩
=
1 αφ
and this impliesV
A
I
n
i
i
∉
Therefore
n i S S n i i iA
A
x
1 * * 1)
(
= ==
∈
α α *(
A
α)
Sα∈Ω
⊆
Therefore
Ω ∈ Ω ∈
⊆
α α α α S SA
A
* *)
(
(2)From 1 and 2 the result follows:
( )
Ω ∈ Ω ∈=
α α α α S SA
A
* *Theorem 3.14: Let
(
X
,
τ
,
I
)
be a*
S
- countably additive ideal space which is, and let{
A
α/
α
∈
Ω
}
be a locallycountable family of sets in
(
X
,
τ
,
I
)
. Then
( )
Ω ∈ Ω ∈=
α α α α S SA
A
* * .Proof: Similar to proof of Theorem 3.13.
Theorem 3.15: Let the ideal space
(
X
,
τ
,
I
)
be*
S
- finitely additive, and{
A
α/
α
∈
Ω
}
be a locally finite family of sets in(
X
,
τ
,
I
)
. If eachA
αisg
*SI
−
closed
then
Ω ∈
α α
A
isg
*SI
−
closed
inX
.Proof: Let
A
⊆
U
Ω ∈
α α
and U be g - open in
X
. ThenA
α⊆
U
∀
α
∈
Ω
impliescl
*S(
A
α)
⊆
U
∀
α
∈
Ω
.Bytheorem (3.13)
cl
SA
=
cl
SA
⊆
U
Ω ∈ Ω ∈
α αα α
)
(
* * .Therefore
Ω ∈ α αA
isg
*SI
−
closed
.Theorem 3.16: Let the ideal space
(
X
,
τ
,
I
)
be*
S
- countably additive. If{
A
α/
α
∈
Ω
}
is a locally countable family of sets in(
X
,
τ
,
I
)
and eachA
αisg
*SI
−
closed
then
Ω ∈
α α
A
isg
*SI
−
closed
.Proof: Similar to proof of Theorem 3.15.
4. -
g
*SI
−
continuous
functionsDefinition 4.1: A function
f
:
(
X
,
τ
,
I
)
→
(
Y
,
Ω
,
J
)
is said to be weaklyI
*S−
continuous
if for eachx
∈
X
and for everyV
inΩ
containingf
(
x
)
, there exists an open setU
containingx
such thatf
(
U
)
⊆
cl
*S(
V
)
.Definition 4.2: A function
f
:
(
X
,
τ
,
I
)
→
(
Y
,
σ
)
is said to beg
*SI
−
continuous
if for every
U
∈
Ω
,)
(
1U
f
− isg
*SI
−
open
in
X
. Equivalently for every closed setV
inY
,f
−1(
V
)
is
g
*SI
−
closed
inX
.Definition 4.3: A function
f
:
(
X
,
τ
,
I
)
→
(
Y
,
Ω
,
J
)
is said to be stronglyg
*SI
−
continuous
if foropen
I
g
*S−
(respg
*SI
−
closed
) setV
inY
,f
−1(
V
)
is open (resp closed) inX
.Definition 4.4: A function
f
:
(
X
,
τ
,
I
)
→
(
Y
,
Ω
,
J
)
is said to be weaklyg
*SI
−
continuous
if for everyX
x
∈
and for everyV
∈
Ω
containingf
(
x
)
, there existsg
*SI
−
open
setU
inX
such thatx
∈
U
and)
(
)
(
U
cl
*V
Definition 4.5: A function
f
:
(
X
,
τ
,
I
)
→
(
Y
,
Ω
,
J
)
is said to beg
*SI
−
irresolute
if for everyg
*SI
−
open
(respg
*SI
−
closed
set) setV
inY
,f
−1(
V
)
isg
*SI
−
open
(respg
*SI
−
closed
) inX
.Remarks: 4.1:
1. Every continuous function is
g
*SI
−
continuous
(since every open set isg
*SI
−
open
) but the converse is not true as seen from example 4.1.2. Every strongly
g
*SI
−
continuous
function is continuous and hence it isg
*SI
−
continuous
but the converse isnot true as seen from example (4.2).
3. Every
g
*SI
−
continuous
function is weaklyg
*SI
−
continuous
but the converse is not true as seen from example (4.2).4. Every weakly
I
*S−
continuous
function is weaklyg
*SI
−
continuous
5. Every strongly
g
*SI
−
continuous
function isg
*SI
−
irresolute
andg
*SI
−
irresolute
function isg
*SI
−
continuous
Example 4.1: Let
X
=
{
a
,
b
,
c
}
,τ
=
{
φ
,
X
,
{ }
a
}
,I
=
{
φ
,
{ }
a
}
,Y
=
X
,Ω
=
τ
.Let
f
:
(
X
,
τ
,
I
)
→
(
Y
,
Ω
,
J
)
be defined byf
(
a
)
=
c
,f
(
b
)
=
f
(
c
)
=
a
.Then f is
g
*SI
−
continuous
but not continuous.Example 4.2: Let
X
=
Y
be indiscrete space andI
=
{
φ
,
x
0}
=
J
wherex
0∈
X
.Let
f
:
(
X
,
τ
,
I
)
→
(
Y
,
Ω
,
J
)
be identity map.Y
,φ
,X
−
{ }
x
0 are the onlyg
*SI
−
open
sets inY
.{ }
(
0)
{ }
01
x
X
x
X
f
−−
=
−
is not open inX
. Thereforef
is not stronglyg
*SI
−
continuous
butf
is bothcontinuous and
g
*SI
−
continuous
.Example 4.3: Let
(
X
,
τ
)
be an indiscrete space,x
0∈
X
andI
=
{
φ
,
x
0}
=
J
.Let
Y
=
X
,Ω
=
τ
,J
=
g
andf
:
(
X
,
τ
,
I
)
→
(
Y
,
Ω
,
J
)
be identity function. Then f is an irresolute function.{ }
x
0A
=
isg
*SI
−
closed
inY
, butf
−1(
A
)
=
{ }
x
0 is not closed inX
.Therefore
f
is not stronglyg
*SI
−
continuous
.Let
x
1≠
x
0 be a point ofX
andf
:
(
X
,
τ
,
I
)
→
(
Y
,
Ω
,
J
)
be defined by f(x0 ) = x1, f(x1 ) = x0 and1 0
,
)
(
x
x
x
x
x
f
=
∀
≠
. Thenf
isg
*SI
−
continuous
.A
=
{ }
x
0 isg
*SI
−
closed
inY
andf
−1(
A
)
=
{ }
x
1 is notg
*SI
−
closed
inX
. Thereforef
is notg
*SI
−
irresolute
.Definition 4.6: Let N be a subset of
(
X
,
τ
,
I
)
andx
∈
X
. The subset N of X called ag
*SI
−
open
neighbourhood ofx
if there existsg
*SI
−
open
setU
containingx
such thatU
⊂
N
.Theorem 4.1: Let
(
X
,
τ
,
I
)
be an ideal space which isg
*SI
−
multiplica
tive
. Then the following are equivalent. 1.f
isg
*SI
−
continuous
3. For each
x
∈
X
and each open setV
inY
withf
(
x
)
∈
V
,f
−1(
V
)
is ag
*SI
−
open
neighbourhood ofx
.Proof: Since
X
isg
*SI
−
multiplica
tive
, arbitrary union ofg
*SI
−
open
sets isg
*SI
−
open
.1
⇒
2: Letx
∈
X
andV
be open inY
containingf
(
x
)
. ThenU
=
f
−1(
V
)
isg
*SI
−
open
,x
∈
U
andV
U
f
(
)
⊆
.2
⇒
3: Letx
∈
X
,V
open inY
containingf
(
x
)
. By (2), there exists ang
*SI
−
open
setU
containingx
such thatf
(
U
)
⊆
V
. So x∈U ⊆ f −1(V) which provesf
−1(
V
)
is ang
*SI
−
open
neighbourhood ofx
.3
⇒
1: LetV
be open inY
and 1(
)
V
f
x
∈
− . Thenf
−1(
V
)
is ag
*SI
−
open
neighbourhood ofx
.Thus for each
x
∈
f
−1(
V
)
, there exists ang
*SI
−
open
setU
x containingx
such that x∈Ux ⊂ f−1(V).Therefore x
V f x
V
f
) ( 1
1
)
(
−
∈ −
=
is a
g
*SI
−
open
which proves thatf
isg
*SI
−
continuous
.Theorem 4.2: Let
(
X
,
τ
,
I
)
be ag
*SI
−
multiplica
tive
ideal space in which every open set is*
S
−
closed
. Then a functionf
:
(
X
,
τ
,
I
)
→
(
Y
,
Ω
)
is weaklyg
*SI
−
continuous
if and only if it isg
*SI
−
continuous
.Proof: Obviously
g
*SI
−
continuity
⇒
weaklyg
*SI
−
continuity
. Conversely, letf
be weaklycontinuous
I
g
*S−
. Then for eachx
∈
X
and open setV
containingf
(
x
)
, there existsg
*SI
−
open
setU
such thatx
∈
U
andf
(
U
)
⊂
cl
*(
V
)
=
V
. Therefore by theorem 4.1,f
isg
*SI
−
continuous
.Theorem 4.3: Let
f
:
(
X
,
τ
,
I
)
→
(
Y
,
Ω
,
J
)
andg
:
(
Y
,
σ
,
τ
)
→
(
Z
,
Ω
,
K
)
be functions between ideal spaces. 1. Iff
is stronglyg
*SI
−
continuous
andg
isg
*SI
−
continuous
thengof
is continuous.2. If
f
isg
*SI
−
continuous
andg
is continuous thengof
isg
*SI
−
continuous
.3. If
f
is stronglyg
*SI
−
continuous
andg
isg
*SI
−
irresolute
thengof
is stronglyg
*SI
−
continuous
andg
*SI
−
irresolute
.4. If
f
andg
areg
*SI
−
irresolute
thengof
isg
*SI
−
irresolute
.Proof: Obvious from definition.
Theorem 4.4: Let
(
X
,
τ
,
I
)
be*
s
−
finitely
additive. Letf
:
(
X
,
τ
,
I
)
→
(
Y
,
Ω
)
beg
*SI
−
continuous
andU
beg
*SI
−
open
in
X
. Thenf
/
U
:
(
U
,
τ
U,
I
U)
→
(
Y
,
Ω
)
isg
*SI
−
continuous
.Proof: Since
(
X
,
τ
,
I
)
is*
s
−
finitely
additive, finite intersectiong
*SI
−
open
sets isg
*SI
−
open
. LetV
be open in(
Y
,
Ω
)
. Thenf
−1(
V
)
isg
*SI
−
open
inX
.Therefore
(
f
/
U
)
−1(
V
)
=
f
−1(
V
)
∩
U
isg
*SI
−
open
.Therefore(
f
/
U
)
isg
*SI
−
continuous
.Note: The result is true if
g
*SI
−
continuous
is replaced byg
*SI
−
irresolute
.Theorem 4.5: Let