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Mathematics Level 6

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(1)

Mathematics

Level 6

(2)

Level 6

Number and Algebra

(3)

Solve the equation x³ + x = 20

Using trial and improvement and give your answer to the nearest tenth

Guess Check Too Big/Too

Small/Correct

(4)

Solve the equation x³ + x = 20

Using trial and improvement and give your answer to the nearest tenth

Guess Check Too Big/Too

Small/Correct

3 3³ + 3 = 30 Too Big

(5)

Solve the equation x³ + x = 20

Using trial and improvement and give your answer to the nearest tenth

Guess Check Too Big/Too

Small/Correct

3 3³ + 3 = 30 Too Big

2 2³ + 2 = 10 Too Small

(6)

Solve the equation x³ + x = 20

Using trial and improvement and give your answer to the nearest tenth

Guess Check Too Big/Too

Small/Correct

3 3³ + 3 = 30 Too Big

2 2³ + 2 = 10 Too Small

2.5 2.5³ + 2.5 =18.125 Too Small

2.6

(7)

Amounts as a %

• Fat in a mars bar 28g out of 35g. What percentage is this?

Write as a fraction

• =

28

/

35

Convert to a percentage (top ÷ bottom x 100)

• 28 ÷ 35 x 100 = 80%

top ÷ bottom converts a fraction to a

decimal

Multiply by 100 to make a decimal into a

percentage

(8)

A percentage is a

fraction out of 100

(9)
(10)
(11)

The ratio of boys to girls in a class is 3:2

Altogether there are 30 students in the class.

How many boys are there?

(12)

The ratio of boys to girls in a class is 3:2

Altogether there are 30 students in the class.

How many boys are there?

The ratio 3:2 represents 5 parts (add 3 + 2) Divide 30 students by the 5 parts (divide)

30 ÷ 5 = 6

Multiply the relevant part of the ratio by the

answer (multiply)

3 × 6 = 18 boys

(13)
(14)

2 3

2

+ 11 = 22

33

6 + 33

= 28 33

A common multiple of 3 and 11 is 33, so change both

fractions to equivalent fractions with a denominator

of 33

(15)

2 3

1

- 4 = 8

12

3 - 12

= 5 12

A common multiple of 3 and 4 is 12, so change both fractions to equivalent fractions with a

denominator of 12

(16)

Find the nth term of this sequence

6 13 20 27 34

7 7 7 7

Which times table is this pattern based on? 7

nth term = 7n - 1

Each number is 1 less How does it compare to the 7 times table?

7 14 21 28 35

(17)

Find the nth term of this sequence

6 15 24 33 42

9 9 9 9

Which times table is this pattern based on? 9

nth term = 9n - 3

Each number is 3 less How does it compare to the 9 times table?

9 18 27 36 45

(18)
(19)

- -

(20)

4p + 5 = 75 - 3p

4p + 5 = 75 - 3p Swap Sides, Swap Signs

4p = 75

3p

+ -

5

7p = 70

p = 10

(21)

2 4 6

-6 -4 -2

2 4 6

-6 -4 -2

y axis

x axis

-5 -3 -1 1 3 5

-1

-3

-5 1 3 5

(3,6) (2,4) (1,2)

(-3,-6)

The y coordinate is always double the x coordinate

y = 2x

(22)

Straight Line Graphs

1 2 3 4

-4 -3 -2 -1

0

2 4 8 6 10

-2 -4

-8 -6

-10

y = ½ x y = x

y = -x y = 2x y = 3x

y = 4x y = 5x

y axis

x axis

(23)

1 2 3 4 -4 -3 -2 -1

0

2 4 8 6 10

-2 -4

-8 -6

-10

y = 2x +1

y = 2x - 5 y = 2x +6

y = 2x - 2

y axis

x axis

(24)

All straight line graphs can be expressed in the form

y = mx + c

m is the gradient of the line

and c is the y intercept

The graph y = 5x + 4 has gradient 5 and cuts the

y axis at 4

(25)

Level 6

Shape, Space and Measures

(26)

Cube Cuboid

Triangular Prism

Hexagonal Prism

Cylinder

Square based Pyramid

Tetrahedron

Cone

Sphere

(27)

Using Isometric Paper

Which Cuboid is the odd one out?

(28)
(29)
(30)

50 a

Alternate angles are equal

a = 50

(31)

76 b

Interior angles add up to 180

b = 180 - 76 = 104

(32)

50

c

Corresponding angles are equal

c = 50

(33)

114

d

Corresponding angles are equal

d = 114

(34)

112 e

Alternate angles are equal

e = 112

(35)

50

f

Interior angles add up to 180

f = 130

(36)

Polygon Sides

(n) Sum of Interior Angles

Triangle 3 180

Quadrilateral 4

Pentagon 5

Hexagon 6

Heptagon 7

Octagon 8

The Sum of the Interior Angles

What is the rule that links the Sum of the Interior Angles to n?

(37)

Polygon Sides

(n) Sum of Interior Angles

Triangle 3 180

Quadrilateral 4 360

Pentagon 5

Hexagon 6

Heptagon 7

Octagon 8

The Sum of the Interior Angles

What is the rule that links the Sum of the Interior Angles to n?

(38)

Polygon Sides

(n) Sum of Interior Angles

Triangle 3 180

Quadrilateral 4 360

Pentagon 5 540

Hexagon 6

Heptagon 7

Octagon 8

The Sum of the Interior Angles

What is the rule that links the Sum of the Interior Angles to n?

(39)

Polygon Sides

(n) Sum of Interior Angles

Triangle 3 180

Quadrilateral 4 360

Pentagon 5 540

Hexagon 6 720

Heptagon 7

Octagon 8

The Sum of the Interior Angles

What is the rule that links the Sum of the Interior Angles to n?

(40)

For a polygon with n sides

Sum of the Interior Angles = 180 (n – 2)

(41)

A regular polygon has equal sides and equal angles

(42)

Regular Polygon Interior Angle (i) Exterior Angle (e)

Equilateral Triangle 60 120

Square

Regular Pentagon Regular Hexagon Regular Heptagon

Regular Octagon

If n = number of sides e = 360 ÷ n

e + i = 180

(43)

Regular Polygon Interior Angle (i) Exterior Angle (e)

Equilateral Triangle 60 120

Square 90 90

Regular Pentagon Regular Hexagon Regular Heptagon

Regular Octagon

If n = number of sides e = 360 ÷ n

e + i = 180

(44)

Regular Polygon Interior Angle (i) Exterior Angle (e)

Equilateral Triangle 60 120

Square 90 90

Regular Pentagon 108 72

Regular Hexagon Regular Heptagon

Regular Octagon

If n = number of sides e = 360 ÷ n

e + i = 180

(45)

Regular Polygon Interior Angle (i) Exterior Angle (e)

Equilateral Triangle 60 120

Square 90 90

Regular Pentagon 108 72

Regular Hexagon 120 60

Regular Heptagon Regular Octagon

If n = number of sides e = 360 ÷ n

e + i = 180

(46)
(47)

Translate the object by 4

( ) -3

(48)

Translate the object by 4

( ) -3

Image Move each

corner of the

object 4 squares

across and 3

squares down

(49)

C

Rotate by 90 degrees anti-clockwise about c

(50)

C

Rotate by 90 degrees anti-clockwise about C

Image

Remember to ask for tracing paper

(51)

Triangle

Area = base × height ÷ 2

A = bh / 2

Parallelogram Area = base × height

A = bh

Trapezium

A = ½ h(a + b)

h b a b

h h

b

The formula for the trapezium is given in the front of the SATs paper

We divide by 2 because the area of the

triangle is half that of the rectangle that

surrounds it

(52)

Circumference = π × diameter

Where π = 3.14 (rounded to 2 decimal places)

diameter The circumference

of a circle is the

distance around the

outside

(53)

The radius of a circle is 30m. What is the

circumference?

r=30, d=60

C = π d

C = 3.14 × 60 C = 18.84 m

r = 30

d = 60

(54)

Circle Area = πr

2

(55)

πd πr²

π = 3. 141 592 653 589 793 238 462 643

Need diameter = distance across the middle of a circle

Need radius = distance from the centre of a circle to the edge

Area = π × 100

= 3.142 × 100

= 314.2 cm²

10cm

Circumference = π × 20

= 3.142 × 20

= 62.84 cm

10cm

The distance around

the outside of a circle

(56)

4 cm 9 cm

10 cm

Volume of a cuboid

V= length × width × height

(57)

4 cm 9 cm

10 cm

Volume of a cuboid

V= length × width × height

V= 9 × 4 × 10

= 360 cm³

(58)
(59)
(60)

Level 6

Data Handling

(61)

Colour Frequency

Blue 5

Green 3

Yellow 2

Purple 2

Pink 4

Orange 1

Red 3

Draw a Pie Chart to show the information in the table below

A pie chart to show the favourite colour in our class

(62)

Colour Frequency

Blue 5

Green 3

Yellow 2

Purple 2

Pink 4

Orange 1

Red 3

TOTAL 20

Draw a Pie Chart to show the information in the table below

A pie chart to show the favourite colour in our class Add the frequencies to

find the total

(63)

Colour Frequency

Blue 5

Green 3

Yellow 2

Purple 2

Pink 4

Orange 1

Red 3

TOTAL 20

Draw a Pie Chart to show the information in the table below

A pie chart to show the favourite colour in our class DIVIDE 360° by

the total to find the angle for 1 person

360 ÷ 20 = 18 Add the frequencies to

find the total

(64)

Colour Frequency Angle

Blue 5 5 × 18 = 90

Green 3 3 × 18 = 54

Yellow 2 2 × 18 = 36

Purple 2 2 × 18 = 36

Pink 4 4 × 18 = 72

Orange 1 1 × 18 = 18

Red 3 3 × 18 = 54

TOTAL 20

Draw a Pie Chart to show the information in the table below

A pie chart to show the favourite colour in our class DIVIDE 360° by

the total to find the angle for 1 person

360 ÷ 20 = 18 Add the frequencies to

find the total

Multiply each frequency by the angle

for 1 person

(65)

Colour Frequency Angle

Blue 5 5 × 18 = 90

Green 3 3 × 18 = 54

Yellow 2 2 × 18 = 36

Purple 2 2 × 18 = 36

Pink 4 4 × 18 = 72

Orange 1 1 × 18 = 18

Red 3 3 × 18 = 54

TOTAL 20

Draw a Pie Chart to show the information in the table below

(66)

Length of

string Frequency

0 < x ≤ 20 10

20 < x ≤ 40 20 40 < x ≤ 60 45 60 < x ≤ 80 32 80 < x ≤ 100 0

Draw a frequency polygon to show

the information in the table

(67)

frequency

         











x f

Length of

string (x) Frequency

0 < x ≤ 20 10

20 < x ≤ 40 20 40 < x ≤ 60 45 60 < x ≤ 80 32 80 < x ≤ 100 0

Draw a frequency polygon to show the information in the table

Plot the point using the midpoint of the interval

Use a continuous scale for the x-axis

(68)

Length of

string Frequency

0 < x ≤ 20 10

20 < x ≤ 40 20 40 < x ≤ 60 45 60 < x ≤ 80 32 80 < x ≤ 100 0

Draw a histogram to show

the information in the table

(69)

         











x f

frequency

Length of

string (x) Frequency

0 < x ≤ 20 10

20 < x ≤ 40 20 40 < x ≤ 60 45 60 < x ≤ 80 32 80 < x ≤ 100 0

Draw a histogram to show the information in the table

Use a continuous scale for the x-axis

(70)

Describe the correlation between the marks scored in test A and test B

(71)

Describe the correlation between the marks scored in test A and test B

The correlation is positive because as marks in test A

increase so do the

marks in test B

(72)

y

x

(73)

The sample or probability space shows all 36 outcomes when you add two normal dice together.

2 3 4 5 6 7

3 4 5 6 7 8

7 8 9 10 11 12

4 5 6 7 8 9

5 6 7 8 9 10

6 7 8 9 10 11

1 2 3 4 5 6

1 2

6 3 4 5

Dice 1

Dice 2

Total Probability

1 1/36

2 3 4

5 4/36

6 7 8 9 10 11 12

(74)

Dice 1

Dice 2

Total Probability

0

1

10/36

2

3

4

4/36

5

The sample space shows all 36 outcomes when you find the difference between the scores of two normal dice.

0 1 2 3 4 5

1 0 1 2 3 4

5 4 3 2 1 0

2 1 0 1 2 3

3 2 1 0 1 2

4 3 2 1 0 1

1 2 3 4 5 6

1 2

6

3

4

5

(75)

The total probability of all the mutually exclusive outcomes of an experiment is 1

A bag contains 3 colours of beads, red, white and blue.

The probability of picking a red bead is 0.14

The probability of picking a white bead is 0.2

What is the probability of picking a blue bead?

(76)

The total probability of all the mutually exclusive outcomes of an experiment is 1

A bag contains 3 colours of beads, red, white and blue.

The probability of picking a red bead is 0.14 The probability of picking a white bead is 0.2 What is the probability of picking a blue bead?

0.14 + 0.2 = 0.34

1 - 0.34 = 0.66

References

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