International Journal of Mathematical Archive-2(12), 2011, Page: 2578-2584
Available online through
www.ijma.info
ON
b
-
FRAMES IN BANACH SPACES
M. I. Ismailov*
Baku State University and scientific worker of Institute of Mathematics and Mechanics of NAS Azerbaijan
E-mail: [email protected]
(Received on: 05-12-11; Accepted on: 21-12-11)
___________________________________________________________________________________________________ ABSTRACT
I
n the paper the generalization of the notionb
-frame in Banach spaces is given by means of bilinear mappings and the notion ofb
-convergence andb
-representation systems are introduced. The relations between these notions are established. The criterion when the system in Banach space formsb
-frame, is given. The projection description ofb
-frame is constructed. Using a linear algorithm of expansion inb
-frame, the extremality estimation for the coefficients of expansion inb
-frame are established.Key words:
b
-frame, expansion inb
-frame,b
-basis,b
-completeness ,CB
-space.2000 Mathematics Subject Classification: 41A17, 41A58, 42C15.
___________________________________________________________________________________________________
1.INTRODUCTION:
Note that, the notion of frame was determined by Duffin and Schaeffer [1] in Hilbert spaces in the following way. Let
H
be a separable Hilbert space the system of non-zero elements{ }
ϕ
n n∈N⊂
H
be called a frame inH
if there exist theconstants
0
<
A
≤
B
<
∞
such that for eachh
∈
H
it is valid
A
h
2H≤
∞
=1
2
)
,
(
n
n
h
ϕ
≤
B
h
2H , (1)where
⋅
H and(
⋅
,
⋅
)
is a norm and scalar product inH
. The constantsA
andB
in (1) are called lower and upper bounds the numberk
=
A
B
is called a condition coefficient of the frame{ }
ϕ
n n∈N. In the case, whenk
=
1
{ }
ϕ
n n∈Nis an tight frame.
Development in theory of a frame in Hilbert spaces reduced to obtaining the analogues of the known results for Banach case. By theory of frame [2]-[5] and others have Banach extensions. The notion of
X
-frame generalizing the notion ofp
-frame studied in [5] was introduced in the paper [6]. In [7] gives the dual notion of a -frame in Banach space, for which in [8] projection description is studied, a criterion on the existence of a linear expansion algorithm in frame is proved, the analogue of the extremality properties for the coefficients of expansion in frame is obtained. A frame is a special case of Bessel sequence introduced and studied [9] in Hilbert spaces. Banach analogies these results were investigated in the paper [10]-[14].Cite the known result [15] from the quant theory of information for projection description of frame.
Theorem: 1.1 Let
{ }
ϕ
n n∈N be a tight frame in Hilbert spaceH
. Then there exists a Hilbert spaceH
′ ⊃
H
and orthonormed basis{ }
ψ
n n∈N⊂
H
′
such that)
(
ψ
nπ
=
ϕ
n,n
∈
N
,where
π
is an operator of orthogonal projection fromH
′
ontoH
.________________________________________________________________________________________________
b
!" # $!% &'( &()© 2011, IJMA. All Rights Reserved 2579 The results [16], [17] and [18] in this direction are known. The frames in Hilbert spaces have close relations with Riesz bases. This matter was considered [19] and is in the following.
Theorem: 1.2 For the system
{ }
ϕ
n n∈N of Hilbert spaceH
to be a frame with boundariesA
andB
,A
≤
B
, it is necessary and sufficient to find a Hilbert spaceH
′
containingH
and the Riesz basis{ }
ψ
n n∈N⊂
H
′
such that2
1
A
2 1
1 2 ∞
=
n n
c
≤
H n
n n
c
′ ∞
=1
ψ
≤
B
122 1
1 2 ∞
=
n n
c
, (2)where
π
(
ψ
n)
=
ϕ
n,n
∈
N
,π
is an operator of orthogonal projection fromH
′
ontoH
.The goal of our paper is extension of the results of [8] to
b
X~-frames forCB
-spaceX
~
. In the paper, necessary andsufficient condition
b
X~-frame of the system in Banach space is proved, projection description ofX
b
~-frame and criterion ofthe existence of linear expansion algorithm in
b
X~-frame is given.2.
b
-FRAME IN BANACH SPACE:Let
X
be a Banach space with the norm⋅
X . Denote byX
~
B
-space of sequences~
x
=
{ }
x
n n∈N,x
n∈
X
, withcoordinate-wise linear operations. If the convergence in
X
~
is coordinate-wise and the subspacesn
E
~
=
{
x
∈
X
:
~
x
=
{
inx
}
i∈N,
x
∈
X
}
~
~
δ
form a basis, thenX
~
calledCB
-space with a canonical basis.Find the general form of a linear continuous functional in
X
~
. Let~
t
be an arbitrary linear continuous functional inX
~
.Since for each
x
~
∈
X
~
(x
~
=
{ }
x
n n∈N) the equalityx
~
=
{
}
∞=
∈ 1
n
N i n in
x
δ
is valid, then~
t
(
~
x
)
=
{
}
∞
=
∈ 1
)
(
~
n
N i n in
x
t
δ
.Consider the functional
t
n:
X
→
C
such thatt
n(
x
)
=
~
t
(
{
δ
inx
}
i∈N)
for∀
x
∈
X
. Then we get that)
~
(
~
x
t
=
∞
=1
)
(
n n n
x
t
. From the coordinate-wise convergence inX
~
it follows thatt
n∈
X
*. Consequently, identifyingt
~
with
{ }
t
n n∈N⊂
*X
,X
~
* is isometrically isomorphic to someB
-space of sequences of elements fromX
* and
~
t
(
~
x
)
=
∞
=1
)
(
n n n
x
t
is a general form of a linear continuous functional in
X
~
, with the norm*
~
~
X
t
=
1 ~ ~
sup
≤
X x
∞
=1
)
(
n n n
x
t
.Let
Y
andZ
beB
-spaces with appropriate norms Y and Z. Consider a bilinear mappingb
(
x
,
y
)
:
X
×
Y
→
Z
satisfying the condition:
∃
M
0
:Z
xy
≤
M
x
Xy
Y∀
x
∈
X
,y
∈
Y
. (3)where
xy
=
b
(
x
,
y
)
,x
∈
X
,y
∈
Y
. Denote byb
ˆ
(
f
,
y
)
the mappingb
ˆ
(
f
,
y
)
:
Z
*×
Y
→
X
*, determined by the relationb
ˆ
(
f
,
y
)(
x
)
=
f
(
xy
)
∀
f
∈
Z
*,y
∈
Y
,x
∈
X
. Further, for brevity we assume<
f
,
y
>
=
b
ˆ
(
f
,
y
)
. It is easy to get from (3) the validity of the inequality
<
f
,
y
>
X*≤
M
f
Z*y
Y*
Z
f
∈
b
!" # $!% &'( &()© 2011, IJMA. All Rights Reserved 2580 Let
X
~
be aCB
-space with a canonical basis. Introduce the following denotation.Definition: 2.1 The system
{ }
ϕ
n n∈N⊂
Y
is said to beX
b
~-frame inZ
if there exist the constantsA
,B
,∞
<
≤
<
A
B
0
such that for anyg
∈
Z
* the sequence{
<
g
,
ϕ
n>
}
n∈N belongs toX
~
* and satisfies the inequalityA
g
Z*≤
{
<
g
,
ϕ
n>
}
n∈N X~*≤
B
g
Z*. (5)Definition: 2.2 The system
{ }
ϕ
n n∈N⊂
Y
is said to be a system ofb
X~-representation if for anyz
∈
Z
there exists{ }
x
n n∈N∈
Z
such thatz
=
∞=1
n n n
x
ϕ
and a system ofX
b
~-convergence inZ
if for any~
x
∈
X
~
(x
~
=
{ }
x
n n∈N) theseries
∞
=1
n n n
x
ϕ
converges inZ
.Cite the criteria when the system
{ }
ϕ
n n∈N⊂
Y
forms ab
X~-frame inZ
.Theorem: 2.3 The system
{ }
ϕ
n n∈N⊂
Y
forms ab
X~-frame inZ
iff it is simultaneously both a system ofb
X~-representation and a system of
X
b
~-convergence inZ
.Proof: Necessary: Let
{ }
ϕ
n n∈N be ab
X~-frame inZ
. Determine the operatorS
(of synthesis) in linearity on finitesequences
{ }
x
n by the equalityS
(
{ }
x
n)
=
n n n
x
ϕ
. For an arbitraryg
∈
Z
*we get{ }
))
(
(
S
x
ng
=
n n n
x
g
(
ϕ
)
=
(
)
n
n n
x
g
ϕ
=
,
(
n)
n
n
x
g
>
<
ϕ
=
{
<
g
,
ϕ
n>
}
n∈N(
{ }
x
n)
.Then
{ }
))
(
(
S
x
ng
=
|
{
<
g
,
ϕ
n>
}
n∈N(
{ }
x
n)
|
≤
{
<
g
,
ϕ
n>
}
n∈N X~*{ }
x
n X~≤
B
g
Z*{ }
x
n X~.So,
S
(
{ }
x
n)
Z≤
B
{ }
x
n X~. ContinuingS
in continuity on allX
~
, we get
S
∈
L
(
X
~
,
Z
)
andS
(
~
x
)
=
∞
=1
n n n
x
ϕ
,X
x
~
~
∈
(x
~
=
{ }
N n n
x
∈ ). Consequently,{ }
ϕ
n n∈N is a system ofb
X~-convergence inZ
. Consider an operator (ofanalysis)
R
:Z
*→
~
*X
in the equalityR
(
g
)
=
{
<
g
,
ϕ
n>
}
n∈N, *Z
g
∈
. It is clear that it holds the equalityR
=
S
*. Since for anyg
∈
Z
* it holdsA
g
Z*≤
~**
)
(
X
g
S
, thenS
mapsX
~
on all the spaceZ
(see [20], theorem 4.15).Thus,
{ }
ϕ
n n∈Nis a system ofb
X~-representation inZ
.Sufficiency: Let
{ }
ϕ
n n∈N be a system ofb
X~-representation andb
X~-convergence inZ
. Consider (linear) operatorsn
S
:X
~
→
Z
by the equalitiesS
n(
~
x
)
=
=
n
k k k
x
1
ϕ
,n
∈
N
. From the coordinate-wise convergence inX
~
it follows,that
S
n∈
L
(
X
~
,
Z
)
. Since{ }
ϕ
n n∈N is a system ofb
X~-convergence inZ
, then∃
∞ →n
lim
S
n(
~
x
)
and by the theorem onuniform boundedness
) , ~ (X Z L n
S
≤
B
for anyn
∈
N
. Consequently, the operatorS
determined by the equality)
~
(
x
S
=
∞ →
n
lim
S
n(
~
x
)
belongs toL
(
X
~
,
Z
)
. Further, consider an operatorR
∈
L
(
Z
*,
X
~
*)
such thatR
=
*S
. Then forany
g
∈
Z
* and~
x
∈
X
~
we get)
(
g
R
(
~
x
)
=
S
*(
g
)
(
~
x
)
=
g
(
S
(
~
x
))
=
∞
=1
)
(
n
n n
x
b
!" # $!% &'( &()© 2011, IJMA. All Rights Reserved 2581 Hence we get
R
(
g
)
=
{
<
g
,
ϕ
n>
}
n∈N. Since{ }
ϕ
n n∈N is a system ofb
X~-reresentation thenS
X
)
=
Z
~
(
. Thereforethere exists
A
>
0
:A
g
Z*≤
~**
)
(
X
g
S
(see. [20], theorem 4.15) and{ }
ϕ
n n∈N forms ab
X~-frame inZ
. Thetheorem is proved.
3. PROJECTIVE
b
-FRAMES:Let
X
, Y andZ
beB
-spaces , aX
~
be aCB
-space with a canonical basis. Cite some notion from [14].The system
{ }
ϕ
n n∈N⊂
Y
is said to beb
-complete inZ
if the aggregateL
b(
{ }
ϕ
n n∈N)
of all possible finite sumsn n
x
ϕ
is dense inZ
.The system
{ }
ϕ
n n∈N⊂
Y
is said to beb
X~-basis inZ
if for∀
z
∈
Z
there exists a unique sequence{ }
x
n n∈N⊂
X
:z
=
∞
=1
n n n
x
ϕ
, moreoverX
~
=
{
~
x
=
{ }
x
n n∈N⊂
X
: ∞=1
n n n
y
x
∈
Z
}
.As the analogue of the projective frame (see [8]) introduce the following definition.
Definition: 3.1
b
-frame{ }
ϕ
n n∈N⊂
Y
inZ
is said to be projective if: (à) there existB
-spaceZ
~
⊃
Z
, including the spaceZ
as a closed subspace; (b) there existb
X~~
-basis
{ }
ψ
n n∈N⊂
L
(
X
,
Z
~
)
inZ
~
, whereb
~
(
x
,
ψ
)
≡
(
x
,
ψ
)
=
ψ
(
x
)
,x
∈
X
,ψ
∈
L
(
X
,
Z
~
)
; (c) there exist a continuous projectorP
∈
L
(
Z
~
,
Z
)
fromZ
~
ontoZ
such thatP
(
x
,
ψ
n)
=
x
ϕ
n for∀
x
∈
X
,N
n
∈
.Definition: 3.2 The space of coefficients of zero-series of the system
{ }
ϕ
n n∈N⊂
Y
is called a closed inX
~
subspace
N
~
=
{
x
~
=
{ }
x
n n∈N∈
X
~
:
∞
=1
n n n
x
ϕ
=
0
}
.Theorem: 3.3 Let
{ }
ϕ
n n∈N⊂
Y
be aX
b
~-frame inZ
. Then{ }
ϕ
n n∈N is a projectiveX
b
~-frame inZ
iffN
~
iscomplemented in
X
~
.Proof: Necessity: Let
{ }
ϕ
n n∈N be a projectiveb
X~-frame inZ
. By theorem 2.3 there exists a synthesisoperator
S
∈
L
(
X
~
,
Z
)
:S
(
~
x
)
=
∞
=1
n n n
x
ϕ
,x
~
∈
X
~
(~
x
=
{ }
x
n n∈N). LetJ
be a natural isomorphism betweenX
~
andZ
~
, i.e.J
(
{ }
x
n n∈N)
=
∞
=1
)
,
(
n
n n
x
ψ
andP
be a projector fromZ
~
ontoZ
. Then the following equality holds:PJ
S
=
. Denote byM
~
=
J
−1(
Z
)
a closed subset inX
~
. Show thatX
~
=
M
~
⊕
N
~
. Take an arbitrary~
x
fromX
~
. Denote byz
=
S
(
~
x
)
and~
x
M~=
J
−1(
z
)
. Considerx
~
N~=
x
~
−
~
x
M~. SinceS
(
~
x
N~)
=
S
(
~
x
)
−
S
(
~
x
M~)
=
0
, thenN
x
N~
~
~
∈
, consequently,~
x
=
M
x
~~
+
N
x
~~
. Now let~
x
∈
M
~
∩
N
~
. From~
x
∈
N
~
it follows thatS
(
~
x
)
=
0
. Sincex
~
∈
M
~
, there existsz
fromZ
, such that 1(
)
z
J
−=
~
x
. Consequently,z
=
P
(
z
)
=
PJ
(
~
x
)
=
S
(
~
x
)
=
0
Thereforex
~
=
1(
)
z
J
−=
0
. Thus,X
~
=
M
~
⊕
N
~
.Sufficiency: Let
N
~
be complemented inX
~
, i.e.X
~
=
M
~
⊕
N
~
. Denote byZ
~
the direct sum ofZ
⊕
N
~
. Obviously,Z
~
is aB
-space by the norm{ }
z
,
x
~
Z~=
max
(
)
X Z
x
b
!" # $!% &'( &()© 2011, IJMA. All Rights Reserved 2582 onto
Z
, i.e.P
(
{ }
z
,
~
x
)
=
z
, andQ
a projection operator fromX
~
ontoM
~
alongN
~
. Define the operatorJ
:X
~
→
Z
~
from the formulaJ
(
~
x
)
=
{
S
(
~
x
),
~
x
−
Q
(
~
x
)
}
. Obviously,J
∈
L
(
X
~
,
Z
~
)
. Show thatJ
is an isomorphism betweenX
~
andZ
~
. IfJ
(
~
x
)
=
0, soS
(
~
x
)
=
0 and~
x
=
Q
(
~
x
)
. Then~
x
∈
M
~
∩
N
~
, thereforex
~
=
0
. Further, wehave
J
(
X
~
)
=
Z
~
. Indeed, if{
z
,
x
~
0}
∈
Z
~
, then there existsξ
~
∈
X
~
such thatz
=
S
(
ξ
~
)
. Denote~
x
=
~
x
0+
Q
(
ξ
~
)
. It is clear thatQ
(
~
x
)
=
Q
(
ξ
~
)
. So,~
x
0=
~
x
−
Q
(
~
x
)
andz
=
S
(
ξ
~
)
=
S
(
Q
(
ξ
~
))
=
S
(
Q
(
x
~
))
=
S
(
~
x
)
,i.e.
{
z
,
~
x
0}
=
{
S
(
~
x
),
~
x
−
Q
(
x
~
)
}
. Using the Banach theorem on inverse operator, we get thatJ
is an isomorphism. SinceX
~
is aCB
- space with a canonical basis, the system{ }
ψ
n n∈N:J
(
{
δ
inx
}
i∈N)
=
(
x
,
ψ
n)
formsb
X~~
-basis in
Z
~
.On the other hand for
∀
x
∈
X
,n
∈
N
it is validP
(
x
,
ψ
n)
=
x
ϕ
n.The theorem is proved.
4.LINEAR EXPANSION ALGORITHM IN X
b
~-FRAME:Let
X
,Y
andZ
beB
-spaces,X
~
be aCB
-space with a canonical basis.Definition: 4.1We say that it holds a linear expansion algorithm in
b
X~-frame{ }
ϕ
n n∈N⊂
Y
inZ
, if there exists a system{ }
n n∈N*
ϕ
⊂
L
(
Z
,
X
)
such that for anyz
∈
Z
the sequence{
ϕ
n*(
z
)
}
n∈N belongs toX
~
andz
=
∞
=1 *
)
(
n
n n
z
ϕ
ϕ
.Theorem: 4.2Let
{ }
ϕ
n n∈N⊂
Y
beX
b
~-frame inZ
. For the existence of a linear expansion algorithm inX
b
~-frame{ }
ϕ
n n∈N it is necessary and sufficient that{ }
ϕ
n n∈N be a projectiveb
X~-frame.Proof:Necessity: Let there exists a linear expansion algorithm in
b
X~-frame{ }
ϕ
n n∈N. As in the proof of theorem 2.1 wedenote by
S
∈
L
(
X
~
,
Z
)
:S
(
~
x
)
=
∞
=1
n n n
x
ϕ
,~
x
∈
X
~
(~
x
=
{ }
x
n n∈N) the synthesis operator inX
~
. Determine the
operator
T
:Z
→
X
~
from the formulaT
(
z
)
=
{
n(
z
)
}
n∈N *ϕ
. Show thatT
∈
L
(
Z
,
X
~
)
. Consider the sequence of theoperators
T
m∈
L
(
Z
,
X
~
)
:T
mz
=
{
}
=
∈
m
n
N i n in
z
1 *
)
(
ϕ
δ
. Since the series{
}
∞
=
∈ 1
*
)
(
n
N i n in
ϕ
z
δ
converges, there exists∞ →
m
lim
T
mz
and by the Banach Steinhous theorem the sequence{ }
T
n n∈N is bounded. So,T
∈
)
~
,
(
Z
X
L
, sinceTz
=
∞ →
m
lim
T
mz
. Obviously(
ST
)(
z
)
=
(
)
* 1
z
n n
ϕ
∞
=
n
ϕ
=
z
, i.e.ST
=
I
, whereI
is an identity operator inZ
.Further, let
M
~
=
T
(
Z
)
. We haveX
~
=
M
~
⊕
N
~
, whereN
~
=
KerS
. Indeed, letx
~
be an arbitrary element inX
~
. Denotez
=
S
(
~
x
)
andx
~
M~=
T
(
z
)
. ThenS
(
~
x
−
~
x
M~)
=
S
(
~
x
)
−
S
(
~
x
M~)
=
0
. Therefore~
x
N~=
x
~
−
x
~
M~∈
N
~
.Show that
M
~
∩
N
~
=
{ }
0
. If~
x
∈
M
~
∩
N
~
, thenS
(
~
x
)
=
0
. Suppose thatz
fromZ
is such thatT
(
z
)
=
x
~
. We getz
=
(
ST
)(
z
)
=
S
(
~
x
)
=
0
. Consequently,x
~
=
0
andX
~
=
M
~
⊕
N
~
. It remains to apply theorem 3.3.Sufficiency: Let
{ }
ϕ
n n∈N be a projectiveb
X~-frame inZ
. Then by theorem 3.3N
~
is complemented inX
~
, i.e.b
!" # $!% &'( &()© 2011, IJMA. All Rights Reserved 2583
)
(
)
(
z
J
1z
T
=
− ,z
∈
Z
, and operatore
n(X
~
→
X
):e
n(
~
x
)
=
x
n,~
x
=
{ }
x
n n∈N. Determine the operatorϕ
n* :Z
→
X
from the expressionϕ
*n(
z
)
=
e
n(
T
(
z
))
. So,Tz
=
{
n(
z
)
}
n∈N*
ϕ
. Take an arbitraryz
∈
Z
. Letx
~
=
T
(
z
)
(
x
~
=
{ }
x
n n∈N). Then we havez
=
(
ST
)(
z
)
=
S
(
~
x
)
=
∞
=1
n n n
x
ϕ
=
*(
)
1
z
n n
ϕ
∞
=
n
ϕ
.The theorem is proved.
Theorem: 4.3Let
{ }
ϕ
n n∈N⊂
Y
be aX
b
~-frame inZ
andN
~
be a space of coefficients of zero-series of the system{ }
ϕ
n n∈N. Then the following properties are equivalent:(i) there exists a continuous projector
P
:X
~
→
N
~
, such thatI
−
P
=
1
;(ii) it holds a linear expansion algorithm in
{ }
ϕ
n n∈N, moreover if forz
∈
Z
, there exists the sequence{ }
x
n n∈N fromX
~
:z
=
∞
=1
n n n
x
ϕ
, then{ }
X N n n
x
∈ ~≥
{
}
X N n n
z
~ *)
(
∈ϕ
.Proof: Let condition (i) be fulfilled. Then
N
~
is complemented inX
~
, i.e.X
~
=
M
~
⊕
N
~
, whereM
~
=
KerP
(see [20], theorem 5.1). Consequently,{ }
ϕ
n n∈N is a projectiveb
X~-frame inZ
and by theorem 4.2 it holds a linearexpansion algorithm. Take an arbitrary
z
∈
Z
. Suppose that there exists{ }
x
n n∈N∈
X
~
, such thatz
=
∞
=1
n n n
x
ϕ
. LetS
be a synthesis operator,J
be a natural isomorphism betweenX
~
andZ
~
,Q
=
I
−
P
,T
be a contraction of1 −
J
onZ
. SinceX
~
=
M
~
⊕
N
~
, thenx
~
=
x
~
M~+
~
x
N~. Letu
∈
Z
:~
x
M~=
T
(
u
)
. We haveu
=
(
ST
)(
u
)
=
(
~
~)
M
x
S
=
S
(
~
x
)
=
z
.Consequently,
{
}
X N n n
z
~ *)
(
∈ϕ
=
T
(
z
)
X~=
X M
x
~ ~~
=
X
x
Q
(
~
)
~≤
{ }
X N n n
x
∈ ~.Let now condition (ii) be fulfilled. Then by theorem 4.2 the
b
X~-frame{ }
ϕ
n n∈N is projective and so by theorem 3.3 thesubspace
N
~
is complemented inX
~
, i.e.X
~
=
M
~
⊕
N
~
. As above, letS
be a synthesis operator,J
be a natural isomorphism betweenX
~
andZ
~
=
Z
⊕
X
~
andT
∈
L
(
Z
,
X
~
)
be an operator determined by the expression)
(
z
T
=
{
n(
z
)
}
n∈N *ϕ
.Denote by
Q
the operator projectingX
~
onM
~
alongN
~
andP
=
I
−
Q
. Take an arbitraryx
~
∈
X
~
. Obviously, there exists~
x
N~=
~
x
−
Q
(
x
~
)
∈
N
~
. SinceQ
(
~
x
)
∈
M
~
, then there exists
z
∈
Z
such thatT
(
z
)
=
Q
(
~
x
)
, sinceM
Z
T
(
)
=
~
. We havez
=
(
ST
)(
z
)
=
S
(
Q
(
~
x
))
=
S
(
~
x
)
=
∞
=1
n n n
x
ϕ
.According to the condition we get
{ }
X N n n
x
∈ ~≥
{
}
X N n n
z
~ *)
(
∈ϕ
. Consequently,{ }
x
n n∈N X~≥
T
(
z
)
X~=
Q
x
)
X~~
(
,b
!" # $!% &'( &()© 2011, IJMA. All Rights Reserved 2584 REFERENCES:
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