ISSN: 1821-1291, URL: http://www.bmathaa.org Volume 4 Issue 4 (2012), Pages 99-108
ON GENERALIZED CONFORMAL MAPS
(COMMUNICATED BY KRISHNAN DUGGAL)
A. M. CHERIF, H. ELHENDI AND M. TERBECHE
Abstract. In this paper, we present some new properties of generalized con-formal maps as f-biharmonic between equidimensional Riemannian manifolds.
1. Introduction
Consider a smooth mapϕ :M −→ N between Riemannian manifolds M = (Mm, g) and N = (Nn, h) and f : M ×N −→ (0,+∞) be a smooth positive function, then thef-energy functional ofϕis defined by
Ef(ϕ) = 1 2 Z
M
f(x, ϕ(x))|dxϕ|2vg
(or over any compact subsetK⊂M).
A map is calledf-harmonic if it is a critical point of thef-energy functional. By [1] the mapϕisf-harmonic if and only if
τf(ϕ) = fϕτ(ϕ) +dϕ(gradMfϕ)−e(ϕ)(gradNf)◦ϕ= 0, (1) wherefϕ:Mm−→(0,+∞) be a smooth positive function defined by
fϕ(x) =f(x, ϕ(x)), ∀x∈M,
τ(ϕ) =traceg∇dϕis the tension field ofϕ, ande(ϕ) =12|dϕ|2is the energy density ofϕ.
τf(ϕ) is called the f-tension field of ϕ, and thef-bi-energy functional of ϕ is defined by
E2,f(ϕ) = 1 2
Z
M
|τf(ϕ)|2vg.
02000 Mathematics Subject Classification: 53A45, 53C20, 58E20.
Keywords and phrases. Conformal maps; f-harmonic maps; f-biharmonic maps. c
2012 Universiteti i Prishtin¨es, Prishtin¨e, Kosov¨e. Submitted August 21, 2012. Published November 6, 2012.
A mapϕis calledf-biharmonic if it is a critical point of the f-energy functional. By [1] the mapϕisf-bi-harmonic if and only if
τ2,f(ϕ) = −fϕtracegRN(τf(ϕ), dϕ)dϕ−traceg∇ϕfϕ∇ϕτf(ϕ) (2) +e(ϕ)(∇N
τf(ϕ)grad
Nf)◦ϕ−dϕ(gradMτ
f(ϕ)(f))
−τf(ϕ)(f)τ(ϕ)+<∇ϕτf(ϕ), dϕ >(gradNf)◦ϕ= 0,
whereh, iis the inner product onT∗M⊗ϕ−1T N andRN is the curvature tensor ofN.
τ2,f(ϕ) is called thef-bi-tension field of ϕ.
Thef-biharmonic concept is a natural generalization of biharmonic maps ([3][4][7][8]).
2. Conformalf-bi-harmonic maps.
Theorem A. Let ϕ: (Mn, g)−→(Nn, h) be a conformal map with dilation λ.
The f-bi-tension field of ϕis given by
τ2,f(ϕ) = F1dϕ(gradMlnλ) +F2dϕ(gradM(fN ◦ϕ))
+2(n−2)fϕ2dϕ(RicciM(gradMlnλ))−2fϕdϕ(RicciM(gradMfϕ)) +nfϕdϕ(RicciM(gradM(fN ◦ϕ))) + 2(n−2)fϕ2<∇dϕ,∇dlnλ >
−2fϕ<∇dϕ,∇dfϕ>+nfϕ<∇dϕ,∇d(fN ◦ϕ)> +(n−2)fϕ2dϕ(gradM∆(lnλ))−fϕdϕ(gradM∆(fϕ)) +n
2fϕdϕ(grad
M∆(fN◦ϕ)) + 4(n−2)fϕ∇ϕ gradMf
ϕdϕ(grad
Mlnλ)
−(n−2)2fϕ2∇ϕgradMlnλdϕ(grad
Mlnλ)
− ∇ϕgradMfϕdϕ(grad
Mf ϕ) +n∇ϕgradMfϕdϕ(grad
M(fN ◦ϕ))−n(n−2) 2 fϕ∇
ϕ
gradM(fN◦ϕ)dϕ(grad
Mlnλ)
−n(n−2)
2 ∇
ϕ
gradMlnλdϕ(grad
M(f
N◦ϕ))− n2
4 ∇ ϕ gradM(f
N◦ϕ)dϕ(grad
M(f N ◦ϕ))
+(n−2)dϕ(∇M
gradMlnλgrad
M(fN ◦ϕ)) + (n−2)dϕ(∇M
gradM(fN◦ϕ)grad
Mlnλ)
−dϕ(∇M
gradMfϕgrad
M(f
N ◦ϕ))−dϕ(∇MgradM(fN◦ϕ)grad
Mf ϕ) +n
2dϕ(grad
M(|gradM(fN ◦ϕ)|2),
where
F1 = (n−2)|gradMfϕ|2+ (n−2)fϕ∆(fϕ)−(n−2)2g(gradMlnλ, gradM(fN◦ϕ))
+(n−2)g(gradMfϕ, gradM(fN ◦ϕ))−n(n−2)
2 |grad
M(fN◦ϕ)|2,
and
F2 = −(n−2)∆(lnλ) + ∆(fϕ)− n
Lemma A. Let ϕ: (Mn, g)−→(Nn, h)be a conformal map with dilationλ. The
f-tension field ofϕis given by
τf(ϕ) = (2−n)fϕdϕ(gradMlnλ) +dϕ(gradMfϕ)
−n
2dϕ grad M(f
N◦ϕ)
,
where, at x∈M,fN :N−→(0,∞)defined byfN(y) =f(x, y) for ally∈N. Proof. Since τ(ϕ) = (2−n)dϕ(gradMlnλ), e(ϕ) = n
2λ
2 and let {e
i}ni=1 be an
orthonormal frame inM, then{fi}n
i=1, wherefi◦ϕ= 1
λdϕ(ei) for alli= 1, ..., n, be an orthonormal frame inN. Then
(gradNf)◦ϕ(x) = (gradNfN)ϕ(x)
= fi|ϕ(x)(fN)fi|ϕ(x)
= 1
λ2(x)dϕ(ei)x(fN)dϕ(ei)x
= 1
λ2(x)ei|x(fN ◦ϕ)dϕ(ei)x
= 1
λ2(x)dϕ grad
M(fN ◦ϕ) x,
for allx∈M.
Lemma B. Let γ:M −→Rbe a smooth function, then traceg(∇ϕ)2dϕ(gradMγ) = (2−n)∇ϕ
gradMγdϕ(grad
Mlnλ) + 2dϕ(RicciMgradMγ)
−tracegRN(dϕ(gradMγ), dϕ)dϕ+ 2<∇dϕ,∇dγ > +dϕ(gradM∆(γ)),
where<∇dϕ,∇dγ >=∇dϕ(ei, ej)∇dγ(ei, ej) =∇dϕ(ei, ej)g(∇M eigrad
Mγ, ej).
Proof. Fix a point x0 ∈ M and let {ei}ni=1 be an orthonormal frame, such that
∇M
eiej= 0 atx0 for alli, j= 1, ..., n. Then calculating atx0, we have
traceg(∇ϕ)2dϕ(gradMγ) = ∇ϕ ei∇
ϕ
eidϕ(grad
Mγ)
= ∇ϕei∇dϕ(ei, grad
Mγ) +
∇ϕeidϕ(∇
M eigrad
Mγ) (3)
= ∇ϕ
ei∇dϕ(ei, grad
Mγ) +∇dϕ(ei,∇M eigrad
Mγ)
+dϕ(∇Mei∇
M eigrad
Mγ)
= ∇ϕ
ei∇dϕ(ei, grad
Mγ)+<∇dϕ,∇dγ >
+dϕ(traceg(∇M)2gradMγ) Let∇2dϕbe the third fundamental form defined by
∇2dϕ(X, Y, Z) =∇ϕX∇dϕ(Y, Z)− ∇dϕ(∇ϕXY, Z)− ∇dϕ(Y,∇ϕXZ), (4) for allX, Y, Z∈Γ(T M). And we have
∇2dϕ(X, Y, Z) = ∇2dϕ(Z, Y, X) +dϕ(RM(Z, X)Y) (5)
By (4) and (5), the first term of (3) is
∇ϕ
ei∇dϕ(ei, grad
Mγ) = ∇2dϕ(ei, ei, gradMγ) +∇dϕ(ei,∇M eigrad
Mγ)
= ∇2dϕ(gradMγ, ei, ei) +dϕ(RM(gradMγ, ei)ei)
−RN(dϕ(gradMγ), dϕ(ei))dϕ(ei) +∇dϕ(ei,∇Meigrad
M γ)
= ∇ϕgradMγτ(ϕ) +dϕ(Ricci
MgradMγ)
−tracegRN(dϕ(gradMγ), dϕ)dϕ+<∇dϕ,∇dγ > .
From the equation
traceg(∇M)2gradMγ=RicciM(gradMγ) +gradM(∆γ),
the Lemma B follows.
Lemma C. Letγ:M −→Rbe a smooth function, then
<∇dϕ(gradMγ), dϕ >=nλ2g(gradMγ, gradMlnλ) +λ2∆(γ).
Proof. Let{ei}n
i=1 be an orthonormal frame, then
<∇dϕ(gradMγ), dϕ > = h(∇eidϕ(grad
M
γ), dϕ(ei))
= ei(h(dϕ(gradMγ), dϕ(ei)))
−h(dϕ(gradMγ),∇eidϕ(ei))
= ei(λ2g(gradMγ, ei))
−(2−n)h(dϕ(gradMγ), dϕ(gradMlnλ)) = g(gradMγ, gradMλ2)
+(n−2)λ2g(gradMγ, gradMlnλ) +λ2ei(g(gradMγ, ei))
= 2λ2g(gradMγ, gradMlnλ)
+(n−2)λ2g(gradMγ, gradMlnλ) +λ2∆(γ)
= nλ2g(gradMγ, gradMlnλ) +λ2∆(γ).
Let {ei}n
i=1 be an orthonormal frame, such that ∇
M
eiej = 0 at x0 ∈ M for all
i, j= 1, ..., n. Then calculating atx0, we have
−(2−n)traceg∇ϕfϕ∇ϕfϕdϕ(gradMlnλ) = (n−2)∇ϕ eifϕ∇
ϕ
eifϕdϕ(grad
Mlnλ) = (n−2)∇ϕgradMfϕfϕdϕ(gradMlnλ)
+(n−2)fϕ∇ϕ ei∇
ϕ
eifϕdϕ(grad
Mlnλ) = (n−2)|gradMfϕ|2dϕ(gradMlnλ)
+(n−2)fϕ∇ϕgradMf
ϕdϕ(grad
Mlnλ)
+(n−2)fϕ∆(fϕ)dϕ(gradMlnλ) +2(n−2)fϕ∇ϕgradMfϕdϕ(grad
Mlnλ)
+(n−2)fϕ2traceg(∇ϕ)2dϕ(gradMlnλ),
and by the lemma B, we obtain
−(2−n)traceg∇ϕfϕ∇ϕfϕdϕ(gradMlnλ) = (n−2)|gradMfϕ|2dϕ(gradMlnλ) +3(n−2)fϕ∇ϕgradMf
ϕdϕ(grad
Mlnλ) +(n−2)fϕ∆(fϕ)dϕ(gradMlnλ) +(n−2)fϕ2n(2−n)∇ϕgradMlnλdϕ(grad
Mln(6)λ)
+2dϕ(RicciMgradMlnλ)
−tracegRN(dϕ(gradMlnλ), dϕ)dϕ
+2<∇dϕ,∇dlnλ >+dϕ(gradM∆(lnλ))o.
Of the same method, we obtain
−traceg∇ϕfϕ∇ϕdϕ(gradMfϕ) = −∇ ϕ
gradMfϕdϕ(grad
Mf ϕ)
−fϕn(2−n)∇ϕgradMf
ϕdϕ(grad
Mlnλ)
+2dϕ(RicciMgradMfϕ) (7)
−tracegRN(dϕ(gradMfϕ), dϕ)dϕ +2<∇dϕ,∇dfϕ>+dϕ(gradM∆(fϕ))o,
n
2traceg∇ ϕf
ϕ∇ϕdϕ(gradM(fN◦ϕ)) = n 2∇
ϕ
gradMfϕdϕ(grad
M(f N ◦ϕ))
+n 2fϕ
n
(2−n)∇ϕgradM(f
N◦ϕ)dϕ(grad
Mlnλ)
+2dϕ(RicciMgradM(fN ◦ϕ)) (8)
−tracegRN(dϕ(gradM(fN ◦ϕ)), dϕ)dϕ
by Lemma A we have
e(ϕ)∇N
τf(ϕ)grad
Nf = n 2λ
2n(2−n)∇ϕ gradMlnλ
1
λ2dϕ(grad
M(f N ◦ϕ))
+∇ϕgradMfϕ
1
λ2dϕ(grad
M(f N◦ϕ))
−n
2∇ ϕ
gradM(fN◦ϕ)
1
λ2dϕ(grad
M(f N ◦ϕ))
o
= n
2λ
2n−2(2−n)
λ2 |grad
Mlnλ|2dϕ(gradM(fN ◦ϕ)) (9)
+2−n λ2 ∇
ϕ
gradMlnλdϕ(grad
M(fN◦ϕ))
− 2
λ2(grad
Mfϕ)(lnλ)dϕ(gradM(fN◦ϕ))
+ 1 λ2∇
ϕ gradMf
ϕdϕ(grad
M(fN◦ϕ))
+n λ2(grad
M(f
N ◦ϕ))(lnλ)dϕ(gradM(fN ◦ϕ))
− n
2λ2∇
ϕ gradM(f
N◦ϕ)dϕ(grad
M(fN ◦ϕ))o.
The functionτf(ϕ)(f) is given by
τf(ϕ)(f) = τf(ϕ)(fN)
= (2−n)(gradMlnλ)(fN ◦ϕ) + (gradMfϕ)(fN◦ϕ)
−n
2|grad
M(fN ◦ϕ)|2,
then
−dϕ(gradMτf(ϕ)(f)) = (n−2)dϕ(gradM((gradMlnλ)(fN ◦ϕ)))
−dϕ(gradM((gradMfϕ)(fN ◦ϕ))) +n
2dϕ(grad
M(|gradM(f
N ◦ϕ)|2)) = (n−2)dϕ(∇M
gradMlnλgradM(fN ◦ϕ)) (10)
+(n−2)dϕ(∇MgradM(f
N◦ϕ)grad
M lnλ)
−dϕ(∇M gradMf
ϕgrad
M(fN◦ϕ))
−dϕ(∇M
gradM(fN◦ϕ)grad
Mf ϕ) +n
2dϕ(grad
M(|gradM(fN ◦ϕ)|2)),
−τf(ϕ)(f)τ(ϕ) = (n−2) n
(2−n)(gradMlnλ)(fN ◦ϕ) + (gradMfϕ)(fN◦ϕ)
−n
2|grad M(f
N ◦ϕ)|2 o
Then by lemma C, we have
<∇τf(ϕ), dϕ > (gradNf)◦ϕ = n(2−n)nλ2|gradMlnλ|2+ (2−n)λ2∆(lnλ)
+nλ2g(gradMfϕ, gradMlnλ) +λ2∆(fϕ)
−n
2
2 λ
2g(gradM(f
N ◦ϕ), gradMlnλ) (12)
−n
2λ
2∆(f
N◦ϕ) o1
λ2dϕ(grad
M(f
N ◦ϕ)).
The TheoremA, follows from (2), (6), (7), (8), (9), (10), (11) and (12).
Particular Cases
(1) Iff = 1, we obtain
τ2,f(ϕ) = τ2(ϕ)
= 2(n−2)dϕ(RicciM(gradMlnλ)) + 2(n−2)<∇dϕ,∇dlnλ > +(n−2)dϕ(gradM∆(lnλ))−(n−2)∇ϕgradMlnλdϕ(grad
Mlnλ).
Is the natural bi-tension field ofϕ.
(2) If f1 :M −→(0,∞), be a smooth positif function. If f(x, y) =f1(x) for
all (x, y)∈M×N, then thef-bi-tension field ofϕis given by
τ2,f(ϕ) = τ2,f1(ϕ)
= (n−2)|gradMf1|2dϕ(gradMlnλ) + (n−2)f1∆(f1)dϕ(gradMlnλ)
+2(n−2)f12dϕ(RicciM(gradMlnλ))−2f1dϕ(RicciM(gradMf1))
+2(n−2)f12<∇dϕ,∇dlnλ >−2f1<∇dϕ,∇df1>
+(n−2)f12dϕ(gradM∆(lnλ))−f1dϕ(gradM∆(f1))
+4(n−2)f1∇
ϕ gradMf
1dϕ(grad
M
lnλ)−(n−2)2f12∇
ϕ
gradMlnλdϕ(grad
M lnλ)
−∇ϕgradMf1dϕ(grad
Mf
1),
Theorem B. Let ϕ : (Mn, g) −→ (Nn, h) be a conformal map with dilation λ. Thenϕisf-bi-harmonic if and only if
0 = F3gradMlnλ+F4gradM(fN◦ϕ) +F5gradMfϕ
+2(n−2)fϕ2RicciM(gradMlnλ)−2fϕRicciM(gradMfϕ) +nfϕRicciM(gradM(fN ◦ϕ))−4fϕ∇M
gradMlnλgradMfϕ
+(n−2)fϕ2grad M
∆(lnλ)−fϕgradM∆(fϕ) +n 2fϕgrad
M
∆(fN◦ϕ)
+4(n−2)fϕ∇M
gradMfϕgrad
Mlnλ−n(n−2) 2 fϕ∇
M
gradM(fN◦ϕ)grad
Mlnλ
+(n−2)∇M gradM(f
N◦ϕ)grad
Mlnλ− ∇M gradM(f
N◦ϕ)grad
Mfϕ
−(n−2)(n−6)
2 f
2
ϕgrad
M(|gradMlnλ|2)
+2nfϕ−
(n−2)2
2
∇M
gradMlnλgrad
M(f N ◦ϕ)
−1
2grad
M(|gradMf
ϕ|2) + (n−1)∇MgradMfϕgrad
M(f N ◦ϕ)
−n(n−2)
4 grad
M(|gradM(fN ◦ϕ)|2),
where
F3 = F1−2(n−2)fϕ2∆(lnλ) + 2fϕ∆(fϕ)−nfϕ∆(fN ◦ϕ)
−(n−2)2fϕ2|gradMlnλ|2+|gradMfϕ|2
−ng(gradMfϕ, gradM(fN◦ϕ)) +n
2
4 |grad
M(fN ◦ϕ)|2,
F4 = F2+ng(gradMfϕ, gradMlnλ)−
n(n−2)
2 (fϕ+ 1)|grad Mlnλ|2
−n
2
2 g(grad
M(fN ◦ϕ), gradMlnλ),
and
F5 = 4(n−2)fϕ|gradMlnλ|2−2g(gradMfϕ, gradMlnλ)
+ng(gradMlnλ, gradM(fN ◦ϕ)).
Proof. The Theorem B follows from Theorem A and the following formulae h(<∇dϕ,∇dlnγ >, dϕ(X)) = g(2λ2∇gradMlnλgradMlnγ (13)
−λ2∆(lnγ)gradMlnλ, X),
h(∇ϕXdϕ(gradMlnγ), dϕ(Y)) = g(λ2X(lnλ)gradMlnγ−λ2X(lnγ)gradMlnλ + λ2dlnλ(gradMlnγ)X+λ2∇M
Xgrad
Mlnγ, Y), (14)
Corollary A. Let ϕ : (Mn, g) −→ (Nn, h) be a conformal map with constant dilation λ. Then ϕ is f-bi-harmonic if and only if the function f satisfies the equation
0 = ∆(fϕ)−n
2∆(fN ◦ϕ)
gradM(fN◦ϕ)−2fϕRicciM(gradMfϕ)
+nfϕRicciM(gradM(fN ◦ϕ))−fϕgradM∆(fϕ) +n 2fϕgrad
M∆(fN ◦ϕ)
−∇M gradM(f
N◦ϕ)grad
Mfϕ−1 2grad
M(|gradMfϕ|2)
+(n−1)∇M
gradMfϕgrad
M(fN ◦ϕ)−n(n−2) 4 grad
M(|gradM(fN ◦ϕ)|2).
Corollary B. Let ϕ : (Mn, g) −→ (Nn, h) be a conformal map with constant
dilation λ. Iffϕ=fN◦ϕ=γ, thenϕ isf-bi-harmonic if and only if the function
γ satisfies the equation
0 = 2−n
2 ∆(γ)grad
Mγ−(2−n)γ RicciM(gradMγ)
−2−n
2 γ grad
M∆(γ)−(2−n)2
4 +
1 2
gradM(|gradMγ|2).
Example A. Letϕ:R2−→(N2, h)be a conformal map with constant dilationλ.
If fϕ=fN ◦ϕ=γ, thenϕisf-bi-harmonic if and only if
( ∂γ ∂x
∂2γ ∂x2 +
∂γ ∂y
∂2γ ∂x∂y = 0, ∂γ
∂y ∂2γ
∂y2 +
∂γ ∂x
∂2γ
∂x∂y = 0.
Example B. Let ϕ: (M2, g)−→(N2, h)be a conformal map with dilation λ. If
fϕ =fN ◦ϕ= lnλ, then ϕisf-bi-harmonic if and only if the function λsatisfies the equation
gradM(|gradMlnλ|2) = 0.
Moreover, if M is related, then ϕ is f-bi-harmonic if and only if the function |gradMlnλ| is constant inM.
Acknowledgements. The authors are highly thankful to the referee for his valuable suggestions towards the improvement of the paper.
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Ahmed Cherif Mohamed
Laboratory of Geometry, Analysis, Contrle and Applications. Saida University,BP 138, 200000, Algeria
E-mail address:[email protected]
Elhendi Hichem
Laboratory of Geometry, Analysis, Controle and Applications. Saida University,BP 138, 200000, Algeria.
E-mail address:[email protected]
Terbeche Mekki