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Volume 2009, Article ID 807943,12pages doi:10.1155/2009/807943

Research Article

Univalence of Certain Linear Operators Defined by

Hypergeometric Function

R. Aghalary and A. Ebadian

Department of Mathematics, Faculty of Science, Urmia University, Urmia, Iran

Correspondence should be addressed to A. Ebadian,[email protected]

Received 11 January 2009; Accepted 22 April 2009

Recommended by Vijay Gupta

The main object of the present paper is to investigate univalence and starlikeness of certain integral operators, which are defined here by means of hypergeometric functions. Relevant connections of the results presented here with those obtained in earlier works are also pointed out.

Copyrightq2009 R. Aghalary and A. Ebadian. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

1. Introduction and Preliminaries

LetHdenote the class of all analytic functionsf in the unit diskD {z ∈C:|z|< 1}. For

n≥0, a positive integer, let

An

f∈ H:fz z

k1

ankznk

, 1.1

withA1:A, whereAis referred to as the normalized analytic functions in the unit disc. A functionf∈ Ais called starlike inDiffDis starlike with respect to the origin. The class of all starlike functions is denoted byS∗:S∗0. Forα <1, we define

S∗α

f ∈ A: Re

zfz fz

> α, zD

, 1.2

and it is called the class of all starlike functions of orderα. Clearly,S∗α⊆ S∗for 0< α <1. For functionsfjz, given by

fjz

k0

ak,jzk, j 1,2

(2)

we define the Hadamard productor convolutionoff1zandf2zby

f1f2z: ∞

k0

ak,1ak,2zk: f2f1

z. 1.4

An interesting subclass of S the class of all analytic univalent functions is denoted by

Uα, μ, λand is defined by

U α, μ, λ

f ∈ A:1−α

z fz

μ

α

z fz

μ1

fz−1< λ, zD

, 1.5

where 0< α≤1, 0≤μ < αn,andλ >0.

The special case of this class has been studied by Ponnusamy and Vasundhra1and Obradovi´c et al.2.

For a,b,c∈C and c/0,-1,-2,. . ., the Gussian hypergeometric series Fa,b;c;zis defined as

Fa, b;c;z

n0

anbn

cn

zn

n!, zD, 1.6

wherean aa1a2· · ·an−1anda0 1. It is well-known thatFa, b;c;zis analytic inD. As a special case of the Euler integral representation for the hypergeometric function, we have

F1, b;c;z Γc

ΓbΓcb

1

0

1 1−tzt

b−11tcb−1dt, zD, Rec >Reb >0. 1.7

Now by letting

φa;c;z:F1, a;c;z, 1.8

it is easily seen that

zφa;c1;zcφa;c;zcφa;c1;z. 1.9

Forf∈ A, Owa and Srivastava3introduced the operatorΩλ:A → Adefined by

Ωλfz Γ2−λ

Γ1−λz

λ d

dz

z

0 ft

(3)

which is extensions involving fractional derivatives and fractional integrals. Using definition ofφa;c;z:F1, a;c;zwe may write

Ωλfz 2; 2λ;zfz. 1.11

This operator has been studied by Srivastava et al.4and Srivastava and Mishra5. Also forλ <1,Reα >0,andfz zk2akzk, let us define the functionFby

Fz:λz1−λ α

1

0

t1−2ftzdt

z 1−λ

k2 ak

k−1α1z

k.

1.12

This operator has been investigated by many authors such as Trimble 6, and Obradovi´c et al.7.

If we take

ψ m, γ, z1 1−m

k2

1

k−1γ1z

k, 1.13

then we can rewrite operatorFdefined by1.11as

Fz z

ψλ, α, zfz z

. 1.14

From the definition ofψm, γ, zit is easy to check that

m, γ, z 1

γψ m, γ, z

1 γ

1 1−m z

1−z

. 1.15

ForfUα, μ, λwithz/fzμ∗φa;c1;z/0 for allzDwe define the transform

Gby

Gz z

1

z/fzμφa

;c1;z 1

, 1.16

wherea, c∈Candc /0,−1,−2, . . . .

Also for fUα, μ, λ with z/fzμψm, γ, z/0 for all zD we define the transformHby

Hz z

1

z/fzμψm, γ, z

1

, 1.17

(4)

In this investigation we aim to find conditions on α, μ, λ such that fUα, μ, λ

implies that the functionfto be starlike. Also we find conditions onα, μ, λ, m, γ, a, cfor each

fUα, μ, λ; the transformsGandHbelong toUα, μ, λandS∗. For proving our results we need the following lemmas.

Lemma 1.1cf. Hallenbeck and Ruscheweyh8. Lethzbe analytic and convex univalent in the unit diskDwithh0 1. Also let

gz 1b1zb2z2· · · 1.18

be analytic inD. If

gz zgz

chz z∈U;c /0, 1.19

then

gzψz c zc

z

0

tc−1htdthz zD;Rec0;c /0. 1.20

andψzis the best dominant of 1.20.

Lemma 1.2 cf. Ruscheweyh and Stankiewicz 8. If f andg are analytic and F and G are convex functions such thatfF, gG,thenfgFG.

Lemma 1.3cf. Ruscheweyh and Sheil-Small9. LetFandGbe univalent convex functions in D. Then the Hadamard productFGis also univalent convex inD.

2. Main Results

We follow the method of proof adopted in1,10.

Theorem 2.1. Let n be positive integer withn≥2. Also letn1/2n < α≤1andn1−α< μ < αn. Iffz zan1zn1· · · belongs toUα, μ, λ, ThenfS∗γwhenever0< λλα, μ, n, γ,

where

λ α, μ, n, γ: ⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩

αnμ2α 1−γ−1

αnμ2μ22α 1γ1

, 0≤γμn1−α μ1n ,

αnμ 1−γ nμγμ ,

μn1−α

μ1n < γ <1.

2.1

Proof. Let us define

pz

z fz

μ

(5)

SincefUα, μ, λ, we have

1−α

z fz

μ

α

z fz

μ1

fz pzα μzf

z

1 αnμan1zn· · · 1λωz,

2.3

whereωzis an analytic function with|ωz|<1 andω0 ω0 · · ·ωn−10 0.By

Schwarz lemma, we have|ωz| ≤ |z|n. By2.3, it is easy to check that

pz 1−μλ

α

1

0 ωtz tμ/α1dt,

1−α αzf z

fz

1λωz

1−μλ/α10ωtz/ tμ/α1dt.

2.4

Therefore

1 1−γ

zfz fzγ

α−1−αγ

/ 1−γαμλ10 ωtz/tμ/α1dt α/ 1γ1λωz ααμλ10 ωtz/tμ/α1dt .

2.5

We need to show thatfS∗γ. To do this, according to a well-known result9and2.5it suffices to show that

α−1−αγ/ 1−γαμλ01 ωtz/tμ/α1dt α/1−γ1λωz

αα−μλ10 ωtz/tμ/α1dt /iT, T ∈R, 2.6

which is equivalent to

λ

ωz μ

αγ1−α/αi 1−γT10 ωtz/tμ/α1dt α 1−γ1iT

/ 1, T∈R. 2.7

Suppose thatBndenote the class of all Schwarz functionsωsuch thatω0 ω0

· · ·ωn−10 0,and let

M sup

zD,ωBn,T∈R

ωz μ

αγ1−α/αi 1−γT10 ωtz/tμ/α1dt α 1−γ1iT

(6)

then,fS∗γifλM ≤1. This observation shows that it suffices to findM. First we notice that

M≤sup

T∈R

⎧ ⎪ ⎨ ⎪ ⎩

1 μ/ nμ/α αγ1−α22 1γ2T2 α 1−γ1T2

⎫ ⎪ ⎬ ⎪

. 2.9

Defineφ:0,∞ →Rby

φx αnμ

μ αγ1−α2 1−γ2α2x

αnμα 1−γ√1x . 2.10

Differentiatingφwith respect tox, we get

φx μ αnμ

α3 1γ3√1x/2 αγ1α2 1γ2α2x αnμ2α2 1γ21x

αnμα 1−γ αnμμ αγ1−α2 1−γ2α2x

/2√1x αnμ2α2 1γ21x .

2.11

Case 1. Let 0< γ <μ−n1−α/μ1n.Then we see thatφhas its only critical point in the positive real line at

x0

1

1−γ2α2

#

μ2 2α1γ12

αnμ2 − αγ1−γ

2

$

. 2.12

Furthermore, we can see thatφx >0 for 0≤ x < x0 andφx <0 forx > x0. Henceφx attains its maximum value atx0and

φxφx0 αnμ

2μ22α 1γ1

αnμ2α 1−γ−1 αnμ2μ22α1γ12

. 2.13

Case 2. Letγ >μ−n1−α/μ1n, then it is easy to see thatφx<0,and soφxattains its maximum value at 0 and

φxφ0 nμγμ

αnμ 1−γ, ∀x≥0. 2.14

(7)

By puttingγ0 inTheorem 2.1we obtain the following result.

Corollary 2.2. Letnbe the positive integer withn≥2. Also letn1/2n < α≤1andn1−α< μ < αn. Iffz zan1zn1· · · belongs toUα, μ, λ, thenfSwhenever0 < λ ≤αn− μ√2α−1/

αn−μ2μ22α1.

Remark 2.3. Takingα1, μ1 inTheorem 2.1andCorollary 2.2we get results of10. We follow the method ofproof adopted in11.

Theorem 2.4. Letn≥2, a /0, c∈Cwith Re c≥0/cand the functionϕz 1b1zb2z2· · · withbn/0be univalent convex inD. Iffz zan1zn1· · · ∈Uα, μ, λandφa;c;zdefined by1.8satisfy the conditions

z fz

μ

φa;c1;z/0 ∀z∈D, φa;c;zϕz,

2.15

then the transformGdefined by1.16has the following: 1GUα, μ, λ|bn||c|/|cn|,

2GSwhenever

0< λ≤ |cn| αnμ

2α−1

|bn||c| αnμ

2

μ22α1

. 2.16

Proof. From the definition ofGwe obtain

z Gz

μ

z fz

μ

φa;c1;z. 2.17

Differentiatingz/Gzμshows that

z

z Gz

μ

μ

z Gz

μ

μ

z Gz

μ1

Gz. 2.18

It is easy to see that

z

z fz

μ

φa;c1;z z

z fz

μ

φa;c1;z

. 2.19

From1.9and2.19we deduce that

z

z fz

μ

φa;c1;z

c

z fz

μ

φa;c;zc

z fz

μ

(8)

or z z Gz μ c z Gz μ c z fz μ

φa;c;z. 2.21

Let us define

pz 1−α z Gz μ α z Gz μ1

Gz:1dnzn· · · , 2.22

thenpzis analytic inD, withp0 1 andp0 · · ·pn−10 0.Combining2.18with

2.21, one can obtain

pz

1αc

μ z Gz μαc μ z fz μ

φa;c;z. 2.23

Differentiatingpzyields

zpz

1αc

μ z z Gz μαc μz z fz μ

φa;c;z. 2.24

In view of2.21,2.23, and2.24, we obtain

cpz zpz c

1αc

μ

z Gz

μ

αc2 μ

z fz

μ

φa;c;z

1αc

μ z z Gz μαc μ z z fz μ

φa;c;z

c

1αc

μ

z fz

μ

φa;c;z

αc2 μ

z fz

μ

φa;c;zαc

μ

z fz

μ

φa;c;z

c

z fz

μ

φa;c;z

# z fz μz fz μ1 fz

$

φa;c;z

c

#

1−α z fz μ α z fz μ1 fz

$

φa;c;z.

2.25

Hence

pz 1 czp

z

#

1−α z fz μ α z fz μ1 fz

$

(9)

Since 1λznandϕz 1b1zb2z2· · · are convex and

1−α

z fz

μ

α

z fz

μ1

fz≺1λzn, φa;c;zϕz, 2.27

by using Lemmas1.2and1.3, from2.26we deduce that

pz 1 czp

z1b

nλzn. 2.28

It now follows fromLemma 1.1that

pzψz c zc

z

0

tc−11bnλzndt. 2.29

Therefore

pz≺1 λbnc

cnz

n, 2.30

and the result follows from the last subordination andCorollary 2.2.

It is well-known thatsee,12ifc, a >0 andc≥max{2, a}, thenφa;c;zis univalent convex function in D. So if we take ϕz φa;c;z in the Theorem 2.4, we obtain the following.

Corollary 2.5. Forn ≥2, c, a >0,andc≥ max{2, a}, let the functionfz zanzn1· · · ∈

Uα, μ, λandφa;c;zdefined by1.8satisfy the condition

z fz

μ

φa;c1;z/0 ∀z∈D. 2.31

Then the transformGdefined by1.16has the following: 1GUα, μ, λ|an|c/|cn|cn;

2GSwhenever

0< λ≤ cn|cn| αnμ

2α−1

|an|c αnμ

2

μ22α1

. 2.32

(10)

Corollary 2.6. Forn≥2, c∈Cwith Re c≥0/c, let the functionfz zanzn1· · · ∈Uα, μ, λ

andφa;c;zdefined by1.8satisfy the condition

z fz

μ

φa;c1;z/ ∀z∈D. 2.33

Then the transformGdefined by1.16has the following: 1GUα, μ, λ|c|/|cn|;

2GSwhenever

0< λ≤ |cn| αnμ

2α−1

|c| αnμ2μ22α1

. 2.34

Remark 2.7. Takingα1 andμ1 onCorollary 2.6, we get a result of11. By puttingc1−Manda2 onTheorem 2.10we obtain the following.

Corollary 2.8. Letn≥2andϕz 1∞k1bkzkwithbn/0be univalent convex function inD.

Also letM∈Cwith ReM <1andfz zan1zn1· · · ∈Uα, μ, λ, satisfy

ΩM

z fz

μ

/

0 zD, 2.35

and letGbe the function which is defined by

Gz z

1

ΩM z/fzμ

1

. 2.36

If

φ2; 1−M;zϕz, 2.37

then we have the following:

1GUα, μ, λ|bn||1−M|/|n1−M|;

2GSwhenever

0< λ≤ |1−Mn| αnμ

2α−1

|bn||1−M| αnμ

2

μ22α1

. 2.38

(11)

In13, Pannusamy and Sahoo have also considered the classUα, μ, λfor the case

α1 withμn.

Theorem 2.10. Form <1, γ /0;Reγ >0, n≥2,letfz zan1zn1· · · ∈Uα, μ, λand ψm, γ, zdefined by1.13satisfy the condition

z fz

μ

ψ m, γ, z/0 ∀z∈D. 2.39

Then the transformHdefined by1.17has the following: 1HUα, μ, λ1−m/|1|;

2HSwhenever

0< λ≤ 1 αnμ

2α−1

1−m αnμ2μ22α1

. 2.40

Proof. Let us define

pz 1−α

z Hz

μ

α

z Hz

μ1

Hz, 2.41

thenpzis analytic inD, withp0 1 andp0 · · ·pn−10 0.Using the same method

as onTheorem 2.4we get

pz γzpz

#

1−α

z fz

μ

α

z fz

μ1 fz

$

1 1−m z

1−z

. 2.42

Since 1λznandhz 1 1mz/1zare convex,

1−α

z fz

μ

α

z fz

μ1

fz≺1λzn. 2.43

Using Lemmas1.2and1.3, from2.42it yields

pz γzpz≺1−mλzn. 2.44

It now follows fromLemma 1.1that

pz≺ 1 γz1

z

0

(12)

Therefore

pz1≤ λ 1−m 1|z|

n, 2.46

and the result follows from2.46andCorollary 2.2.

References

1 S. Ponnusamy and P. Vasundhra, “Criteria for univalence, starlikeness and convexity,” Annales Polonici Mathematici, vol. 85, no. 2, pp. 121–133, 2005.

2 M. Obradovi´c, S. Ponnusamy, V. Singh, and P. Vasundhra, “Univalency, starlikeness and convexity applied to certain classes of rational functions,”Analysis, vol. 22, no. 3, pp. 225–242, 2002.

3 S. Owa and H. M. Srivastava, “Univalent and starlike generalized hypergeometric functions,” Canadian Journal of Mathematics, vol. 39, no. 5, pp. 1057–1077, 1987.

4 H. M. Srivastava, A. K. Mishra, and M. K. Das, “A nested class of analytic functions defined by fractional calculus,”Communications in Applied Analysis, vol. 2, no. 3, pp. 321–332, 1998.

5 H. M. Srivastava and A. K. Mishra, “Applications of fractional calculus to parabolic starlike and uniformly convex functions,”Computers & Mathematics with Applications, vol. 39, no. 3-4, pp. 57–69, 2000.

6 S. Y. Trimble, “The convex sum of convex functions,”Mathematische Zeitschrift, vol. 109, pp. 112–114, 1969.

7 M. Obradovi´c, S. Ponnusamy, and P. Vasundhra, “Univalence, strong starlikeness and integral transforms,”Annales Polonici Mathematici, vol. 86, no. 1, pp. 1–13, 2005.

8 St. Ruscheweyh and J. Stankiewicz, “Subordination under convex univalent functions,”Bulletin of the Polish Academy of Sciences, Mathematics, vol. 33, no. 9-10, pp. 499–502, 1985.

9 St. Ruscheweyh and T. Sheil-Small, “Hadamard products of Schlicht functions and the P ¨olya-Schoenberg conjecture,”Commentarii Mathematici Helvetici, vol. 48, pp. 119–135, 1973.

10 S. Ponnusamy and P. Sahoo, “Geometric properties of certain linear integral transforms,”Bulletin of the Belgian Mathematical Society. Simon Stevin, vol. 12, no. 1, pp. 95–108, 2005.

11 M. Obradovi´c and S. Ponnusamy, “Univalence and starlikeness of certain transforms defined by convolution of analytic functions,”Journal of Mathematical Analysis and Applications, vol. 336, no. 2, pp. 758–767, 2007.

12 Y. Ling, F. Liu, and G. Bao, “Some properties of an integral transform,”Applied Mathematics Letters, vol. 19, no. 8, pp. 830–833, 2006.

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