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ORIGINAL RESEARCH ARTICLE

A COMPLETELY MONOTONIC FOR SOME FUNCTIONS

*Nabil Salman, Mohammad Souecatt, Abdalbaset Younso, Ahmad Beckdash

Department of Mathematics, Faculty of Science, Tishreen University, Lattakia, Syria

ARTICLE INFO ABSTRACT

In this work, the monotonicity properties for some functions involving the gamma function are investigated. Moreover, some inequalities involving gamma function are proved.

Copyright © 2019,Nabil Salman et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

INTRODUCTION

The gamma function defined by

Γ( ) =

, ( ) > 0

is one of the most important special functions and has many applications in physics, probability theory, and engineering, …

A function ( ) defined on an interval is called completely monotonic if has derivatives of all orders and satisfies

(−1) ( )( ) ≥ 0, = 0,1,2, … ; ∈

.

The completely monotonic functions are useful in various branches, including mathematical analysis, probability theory and numerical analysis. Many papers have appeared providing inequalities for the gamma and various related functions. See, for example (Alzer& Batir, 2007; Alzer& Felder, 2009; Alzer & Grinshpan, 2007; Gao, 2011; Mortici, 2011; Salem & Kamel, 2015).

In (Kazarinoff, 1956) proved that the function θ( ) which appeared in Wallis's formula

1.3.5 … (2 − 1) 2.4.6 … (2 ) =

1

+ ( ) ,

satisfies for any = 1,2, … the inequities

1

4< ( ) ≤ 1 2.

*Corresponding author: Nabil Salman,

Department of Mathematics, Faculty of Science, Tishreen University, Lattakia, Syria

ISSN: 2230-9926

International Journal of Development Research

Vol. 09, Issue, 05, pp. 27744-27748, May 2019

Article History:

Received 28th February, 2019 Received in revised form 20th March, 2019 Accepted 06th April, 2019 Published online 30th May, 2019

Available online at http://www.journalijdr.com

Key Words:

Completely monotonic functions; Inequalities; Gamma function.

Citation: Nabil Salman, Mohammad Souecatt, Abdalbaset Younso, Ahmad Beckdash, 2019. “A completely monotonic for some functions”,

International Journal of Development Research, 09, (05), 27744-27748.

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If > − , the function ( ) is defined by

( ) = − + Γ( + 1)

Γ + .

In (Wataon,1959) obtained that the function θ(x) can be written as

θ(x) =

− −

! ( + 1)

, (1)

where, ( ) =Γ( )

Γ( ) is defined by

( ) = 1, ( ) = ( + 1) … ( + − 1), > 0.

It is known that the formula (1) implies the function ( ) is decreasing for > − , (∞) = and − = . This obviously implies the following inequalities

1

4< ( ) ≤ 1

2, ≥ − 1 2.

(Dutka,1958) proved that

1 + 1

2 − 1 < ( )

< 1 − 1

2 − 1, = 1,2, …,

1

4< ( ) < + 1

4 + 3, = 1,2, …

In this paper, we present the monotonicity properties of some functions.

To prove our theorems, we need the following lemma

Lemma 1. The function exp −ℎ( ) is completely monotonic on an interval I if ℎ′( )

is completely monotonic on .

RESULTS

Theorem 1. Let

( ) = ( + ) ( + 1)

+ , > − 1

2, − .

Then

1) ( )is completely monotonic on(− ,)if ≤ ;

2) ( )is completely monotonic on − , if ≥ .

Proof. Let ≤ and the function ℎ( ) defined by

ℎ( ) = − ln ( )

hence

( ) = 1

2 + 2 +

Γ +

Γ + −

Γ′( ) Γ( + 1).

Using lemma 1, it suffices to show that ℎ( ) is completely monotonic.

It is known that ( ) ≔Γ( )

(3)

+ − = 2 ∫ (1 + ) , ( ) > 0, (2)

and this gives

( ) = ( )

− 2 ( )(1 + ) ,

(3)

from which follows

( ) =

( )

1 + 1 − + 2 1 − .

This implies the complete monotonicity of ℎ( ) when since the integrandis timesanonnegative function of .

When ≥ we rewrite (3) in thisform,

−ℎ( ) =

1 + 2 − 2 −

( ) .

The integrand in the above equation is times a nonnegative function of , hence −ℎ( ) is completely monotonic.

From Theorem 1, we get the following corollary.

Corollary 1. The function ( )is increasing on − ,∞ if and decreasing on (− ,)if ≤ .

Theorem 2.Let

+ 1 ≥ > , ≔ max(− , − ) , ≔ max(− , − )

and

( ; , , ) = ( + ) Γ( + )

Γ( + ), > .

Then

1) ( ; , , )is completely monotonic on( ,) if ≤ ( + − 1)

2)

( ; , , )is completely monotonic for > if ≥ .

Proof. Since the function 1 − is completely monotonic on (0,) for > 0 , > 0 and the product of completely

monotonic functions is also completely monotonic, it suffices to consider the case ( ) .

Part (1) will follow if we can show that− ln hasacompletelymonotonicderivativeontheintervalunder consideration. Set

( ) = − ln ; , , + − 1 2 .

Clearly,

( ) = 2( − )

2 + + − 1+

Γ′( + )

Γ( + ) −

Γ′( + )

Γ( + )

We now apply the integral representation, (Erdelyi, eta al,1953)

Γ( )

Γ( ) = − + ( − )(1 − ) ,

( ) > 0, (4)

being Euler's constant.

This gives

( ) = ( − ) ( )

+

1 − ( − )

(4)

= ∫ ( ) exp − +

where ( ) = 2( − ) sh − 2 sh ( ) .

Then,

1

2 (2 ) =

( − )( )

(2 + 1)! (1 − ( − ) )

shows that ( ) ≥ 0 for ≥ 0 , hence ( ) is completely monotonic on ( ,). This establishes part (1). We now proceed

with proving part (2). Using the integral representation (4), we get

ln ( ; , , ) = ( )

exp[− ( + )] ,

where ( ) = ( − )(1 − ) + ( ) ( ) .

Since ( ) is an increasing function of , it suffices to prove the positivity of ( ) when = .

If = , we have

( ) = ( − ) − ( − ) ( ) , = , > 0,

which is clearly nonnegative for ≥ 0 Thus is nondecreasing on (0,).

On the other hand, (0) = 0. Therefore ( ) ≥ 0 for ≥ 0 and ≥ which implies the complete monotonicity of

ln ( ; , , ). Finally, part(2) follows from the lemma1.

Theorem 4. The function

1 − 1 2

Γ +

Γ( )Γ( + 1)

is completely monotonic on , .

Proof. Let −ℎ( ) denote the logarithm of the function

1 − 1 2

Γ +

Γ( )Γ( + 1)

Therefore,

( ) =Γ′( )

Γ( )+

Γ′( + 1)

Γ( + 1)−

2Γ′ +

Γ + −

1 2

1

− − 1

,

and using (2) we obtain the integral representation

( ) = 2

1 + ( − 1)

+ ( ) −

=

1 + [2( − 1) + ( − 1)(1 + )]

= − 1

1 + (1 − ) .

This proves the complete monotonicity of ℎ( )

on , , hence ( ) is also completely monotonic on , .

(5)

1 + Γ( )Γ( )

Γ (5)

is completely monotonic on(0,).

Proof. As in the above proof, let the function in (5) be ( )similarly, we derive

( ) = 2

1 + (1 − )

1

2 + 1− 1 2

= 2

1 + (1 − )

+ ( − 1)

= (1 − )

1 +

,

which establishes Theorem 5.

Theorem 6. The function

( ; , ) =Γ( )Γ( + + )

Γ( + )Γ( + ), , ≥ 0

.

is completely monotonic on(0,).

Proof. Let ( ; , ) = − ln ( ; , ). Applying (4) we obtain

( ; , ) =

1 − (1 − )(1 − )

,

which implies the complete monotonicity of ( ; , ) on (0,).

Finally, Lemma1 establishes the complete monotonicity of ( ; , ) on (0,) and the proof is complete.

REFERENCES

Alzer. H, Batir. N, Monotonicity properties of the gamma function, Applied Mathematics Letters 20 (2007) 778–781.

Alzer. H, Felder. G, A Tur´an-type inequality for the gamma function, Journal of Mathematical Analysis and Applications 350 (2009) 276–282.

Alzer. H, Grinshpan. A, Inequalities for the gamma and q-gamma functions, Journal of Approximation Theory, 144 (2007) 67–83. DUTKA. J, On some gamma function inequalities, SIAM J. Math. Anal., Vol.16, (1985) 180-185.

ERDELYI. A, MAGNUS. W, OBERHETTINGER.F & TRICOMI.F, Higher Transcendental Functions, Vol. 1. McGraw-Hill, New York, (1953).

Gao. P, Some monotonicity properties of gamma and q-gamma functions, ISRN Mathematical Analysis (2011) 1–15. KAZARINOFF. D, On Wallis' formula, Edinburgh. Math. Soc. Notes, No. 40, (1956) 19-21.

Mortici. C, Improved asymptotic formulas for the gamma function, Computers and Mathematics with Applications 61 (2011) 3364–3369.

Salem. A, Kamil. E. Some completely monotonic functions associated with the q-gamma and the q-polygamma functions. Acta Mathematica Scientia. Vol. 35 (2015) 1214-1224.

WATSON. G, A note on gamma functions, Proc. Edinburgh Math. Soc. (2), Vol.11 (1959).

*******

References

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