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Stochastic Generalized Complementarity Problems

in Second-Order Cone: Box-Constrained

Minimization Reformulation and Solving Methods

Mei-Ju Luo and Yan Zhang

Abstract—In this paper, we reformulate the stochastic gener-alized second-order cone complementarity problems as box-constrained optimization problems. If satisfy the condition that the reformulation’s objective value is zero, the solutions of box-constrained optimization problems are also solutions of stochastic generalized second-order cone complementarity problems. Since the box-constrained minimization problems contain an expectation function, we then employ sample average approximation method to give approximation problems of the box-constrained minimization reformulation. Meanwhile the convergence results of global solutions and stationary points for the corresponding approximation problems are considered. Index Terms—box-constrained minimization problems, sam-ple average approximation, convergence.

I. INTRODUCTION

G

ENERALIZED second-order cone complementarity problems, denoted by GSOCCP(F,G,K) are to find a vectorx∈Rn satisfying

F(x)∈K∗, G(x)∈K, F(x)TG(x) = 0,

where F(x), G(x) : Rn Rn are continuously

differen-tiable respect tox∈Rn. K is the convex cone

K={x∈Rn|x21 n

j=2

a2jx2j, x10}

and its polar cone K∗ denoted by

K∗={x∈Rn|∀y∈K,⟨x, y⟩ ≥0}.

Here, aj, j = 2, . . . , n is the given parameter. The

general-ized second-order cone complementarity problems play a ba-sic role and occupy an important position in the minimization theory, which have vital applications in many fields. In [2] the authors analyze the case whereK is a polyhedral cone. In [3], [4], based on the well know Fischer-Burmeister NCP-function, smooth merit function is presented for the second-order cone product of Lorentz cones. In [9], the authors study the special case of GSOCCP(F,G,K), where G(x) = x

and K is Cartesian product of Lorentz cones. Moreover, in [1] R. Andreani etc. consider a special cone, which is denoted as K = {x Rn|x21 ≥ ∥(x2, . . . , xp)T∥2}. Since

the origin is not a regular point, the authors make up for

Manuscript received May 10, 2016; revised August 29, December 5, 2016. This work was supported in part by National Natural Science Foundation of China under Grant NO. 11501275 and Scientific Research Fund of Liaoning Provincial Education Department under Grant NO. L2015199.

M.J. Luo is with the School of Mathematics, Liaoning University, Shenyang, Liaoning, 110036, China e-mail: [email protected]. Cor-responding author.

Y. Zhang is with the School of Mathematics, Liaoning University, Shenyang, Liaoning, 110036, China e-mail: [email protected].

this lack by combining two functions which are mentioned in [2]. Then the authors construct two reformulations of GSOCCP(F,G,K) which are nonlinear minimization prob-lems with box constraints. More basic theories, effective algorithms and important applications of GSOCCP(F,G,K) can be found in [7], [13].

However, in practice, stochastic elements are usually in-volved in several problems. Paying no attention to these stochastic elements will make mistake decision. Therefore, it is meaningful and interesting to study the stochastic generalized second-order cone complementarity problems.

Stochastic generalized second-order cone complementarity problems, denoted by SGSOCCP(F,G,K) are to find a vector

x∈Rn such that

E[F(x, ω)]∈K∗,E[G(x, ω)]∈K,

E[F(x, ω)]TE[G(x, ω)] = 0,

where E denotes mathematical expectation, ω Rm

denotes stochastic variable,F(x, ω), G(x, ω) :Rn×Rn

are continuously differentiable respect tox∈Rn, the convex

conesK andK∗ are defined as above.

Without loss of generality, setA=diag(1,−a22,−a23, . . . ,

−a2p,0, . . . ,0), where ai ̸= 0, f or 2 i p, A = diag(1, a21

2

, . . . ,−a21

p, 0, . . . ,0) and M =

diag(m1, m2, . . . , mn), where mi = 0, for 1 i p,

and mi = 1 for i > p, then the convex cone K can be

expressed by matrix form, that is

K={x∈Rn|1 2x

T

Ax≥0, x10}

and its corresponding polar coneK∗ is

K∗={x∈Rn|1 2x

TAx0, x

10, M x= 0}.

In this paper, we supposeai = 1, fori= 2, . . . , p. Then, we can rewrite SGSOCCP(F,G,K) as follows: Findx∈Rn

such that

E[F(x, ω)]∈K∗,E[G(x, ω)]∈K,

E[F(x, ω)]TE[G(x, ω)] = 0, (1)

where

K={x∈Rn|x21≥ ∥(x2, . . . , xp)T∥2, x10}

and its polar cone

K∗={x∈Rn|x21≥ ∥(x2, . . . , xp)T∥2, x10, M x= 0}.

Since pmay be strictly less thann, the cone considered in this paper is more general. This implies, in particular, that

K∗ may be different fromK.

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In fact, problem (1) is also a stochastic complementarity problem. About the classical stochastic complementarity problems(denoted by SCP), there are many good results have been published. For example, the expected value (EV) model suggested by G¨urkan et al. [8]. The Expected residual min-imization (ERM) model presented by Chen and Fukushima [5]. The Condition value-at-risk (CVaR) model presented by Chen and Lin [6]. The CVaR-constrained stochastic programming model presented by Xu and Yu [18]. More recently research of SCP can be seen in [11], [10], [19].

Based on [1], in this paper, we investigate SGSOCCP(F,G,K), where a special cone denoted as

K = {x Rn|x2

1 ≥ ∥(x2, . . . , xp)T∥2} is considered.

The main difference between two papers is that SGSOCCP(F,G,K) contain expectation which is usually difficult to evaluate. Therefore, we employ sample average approximation (SAA) method to solve the corresponding box-constrained minimization reformulation. However, whether the solutions of SAA approximation problems are regarded as the solutions of SGSOCCP(F,G,K) is reasonable? To answer this question, we consider the convergence results of global solutions and stationary points for the corresponding approximation problems in theory.

The remainder of the paper is organized as follows: In Sec-tion 2, we introduce the box-constrained reformulaSec-tion and the corresponding approximation problems of SGSOCCP(F,

G,K). In Section 3, the convergence results of global solu-tions and stationary points for the approximation problems are considered. In Section 4, we give the conclusions.

II. BOX-CONSTRAINED REFORMULATION OF

SGSOCCP(F,G,K)

In this section, we will study the equivalence problems of SGSOCCP(F,G,K) and the approximation problems of box-constrained minimization problems.

Inspired by [1], in order to reformulate SGSOCCP(F,G,K) via nonlinear programming, we employ the KKT conditions of minimization problems which are related to SGSOCCP(F,G,K) to construct two merit functions denoted by

f(x, t) = E[F(x, ω)]−t1AE[G(x, ω)]−t2e1∥2

+(1

2E[G(x, ω)] T

AE[G(x, ω)]−t3)2

+(E[G1(x, ω)]−t4)2+ (t1t3)2+ (t2t4)2,

g(x, s, ζ) = E[G(x, ω)]−s1AE[F(x, ω)]−s2e1−M ζ∥2

+(1

2E[F(x, ω)]

TAE[F(x, ω)]s

3)2+(s1s3)2

+(E[F1(x, ω)]−s4)2+∥ME[F(x, ω)]2+(s2s4)2,

where x, ζ Rn, setting t = (t1, t2, t3, t4)T R4, s =

(s1, s2, s3, s4)T ∈R4, ande1= (1,0, . . . ,0)T ∈Rn.

Then, SGSOCCP(F,G,K) is equivalent to the following box-constrained minimization problem:

min(x,t,s,ζ,r)θ(x, t, s, ζ, r) =rf(x, t)+(1−r)g(x, s, ζ)

s.t. 0≤r≤1, t≥0,

s≥0. (2)

If(x, t, s, ζ, r)is a solution of (2) with objective value zero, thenxis a solution to (1). The detail proof see [1]. Noting

that, (2) is a box-constrained minimization problem which is easily to solve and to deal.

Since the objective function of problem (2) contains an expectation which is generally difficult to evaluate, we use the sample average approximation (SAA) method to solve (2). The detail can be seen in [15]. We suppose that ψ : Ω R is integrable and Ωk :=1,· · ·, ωNk} represents sample space of randomω, we then use N1

k

ωj kψ(ω

j)

to approximateE[ψ(ω)]. If{Nk}is not a decreasing function respect tok, the strong law of large numbers guarantees that the following result holds with probability one (abbreviated by w.p.1). That is

lim k→∞

1 Nk

ωjk

ψ(ωj) =E[ψ(ω)].

For simplicity, we assume

l1(x, t1, t2) =E[F(x, ω)]−t1AE[G(x, ω)]−t2e1,

l2(x, t3) =

1

2E[G(x, ω)]

TAE[G(x, ω)]t

3,

l3(x, t4) =E[G1(x, ω)]−t4,

l4(x, s1, s2, ζ) =E[G(x, ω)]−s1AE[F(x, ω)]−s2e1−M ζ,

l5(x, s3) =

1

2E[F(x, ω)]

TAE[F(x, ω)]s

3,

l6(x, s4) =E[F1(x, ω)]−s4,

l7(x) =ME[F(x, ω)].

Corresponding, we let

lk1(x, t1, t2) =

1 Nk

ωjk

F(x, ωj)−t1A (1

Nk

ωjk

G(x, ωj))−t2e1,

l2k(x, t3) = ( 1

2Nk

ωjk

G(x, ωj))TA(1 Nk

ωjk

G(x, ωj))−t3,

l3k(x, t4) = ( 1

Nk

ωj k

G1(x, ωj) )

−t4,

l4k(x, s1, s2, ζ) = ( 1

Nk

ωjk

G(x, ωj))−s1A ( 1

Nk

ωjk

F(x, ωj))

−s2e1−M ζ,

lk5(x, s3) = ( 1

2Nk

ωj k

F(x, ωj))TA(1 Nk

ωj k

F(x, ωj))−s3,

lk6(x, s4) = ( 1

Nk

ωjk

F1(x, ωj) )

−s4,

lk7(x) =M ( 1

Nk

ωj∈k

F(x, ωj)).

Thus, we have

fk(x, t) =∥l1k(x, t1, t2)2+(l2k(x, t3))2+(lk3(x, t4))2

+(t1t3)2+(t2t4)2,

gk(x, s, ζ) =∥l4k(x, s1, s2, ζ)∥2+(lk5(x, s3))2+(lk6(x

,s

4))2

+∥lk7(x)2+(s1s3)2+(s2s4)2.

Then, by SAA method one may construct, for each k, an approximation of problem (2) can be constructed as follows:

min(x,t,s,ζ,r)θk(x, t, s, ζ, r) =rfk(x, t)+(1−r)gk(x, s, ζ)

s.t. 0≤r≤1, t≥0,

s≥0. (3)

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In this paper, we assume that, for eachx∈Rn,F(x, ω)

andG(x, ω)are integrable over ω∈Ω, and for anyω∈Ω,

F(x, ω)andG(x, ω)are continuously differentiable respect tox. Furthermore, we suppose thatΩis a nonempty set and for allx∈Rn

max{∥∇xF(x, ω)2,∥∇xG(x, ω)∥2,

∥F(x, ω)2,∥G(x, ω)∥2} ≤σ(ω), (4)

and

E[σ(ω)]<+∞, (5)

from (4),(5) and Cauchy-Schwarz inequality, forx∈Rn, we

have

max{∥∇xF(x, ω)∥,∥∇xG(x, ω)∥,

∥F(x, ω)∥,∥G(x, ω)∥} ≤σ(ω), (6)

and

E[√σ(ω)]<+∞. (7)

In addition, for an n×n matrix A,∥A∥ denotes spectrum norm and ∥A∥F denotes Frobenius norm, that is

∥A∥F := ( n

i=1

n

j=1 |aij|2)

1 2,

where aij be the factor of matrix A. By the definition, we

have∥A∥ ≤ ∥A∥F. For a functionη(x): Rn R, xη(x)

denotes gradient ofη(x)respect to x.

III. CONVERGENCEANALYSIS

Before considering the convergence results of (3), we give the following Definitions and Lemmas, which have been given in [12] firstly.

Definition 1: Let h(x) : Rn Rn, for each N, hN(x) : RnRnis a mapping. If for any ϵ >0, there existsN(ϵ),

when N > N(ϵ), we have

∥hN(x)−h(x)∥< ϵ, ∀x∈Rn.

Then we call {hN(x)} is uniformly convergent to h(x) on Rn.

Definition 2: Let h(x) : Rn Rn, for each N, h N(x) : Rn Rn is a mapping. If for any sequence {xN} → x,

when N → ∞, we have

lim N→∞hN(x

N) =h(x), xRn.

Then we call{hN(xN)} is continuously convergent toh(x)

onRn.

Lemma 1: Leth:RnRn, for eachN,hN :Rn Rn

be a mapping, then hN is continuously convergent to hon compact set Dif and only ifhN is uniformly convergent to

hon compact setD.

Theorem 1: Suppose that for eachk,{(xk, tk, sk, ζk, rk)}

is a global optimal solution of problem (3) and

(x∗, t∗, s∗, ζ∗, r∗) is an accumulation point of

{(xk, tk, sk, ζk, rk)}. Then, we have (x∗, t∗, s∗, ζ∗, r∗)

is a global optimal solution of problem (2).

Proof: Without loss of generality, we may

as-sume limk→∞(xk, tk, sk, ζk, rk) = (x∗, t∗, s∗, ζ∗, r∗). Let

B S be a compact convex set containing the se-quence{(xk, tk, sk, ζk, rk)}, whereS :={(x, t, s, ζ, r)|x Rn, t 0, s0, ζ Rn,0 r 1} denotes the feasible

region of (2). Let

ϕ(x) =E[F(x, ω)], ϕk(x) = 1 Nk

ωj∈k

F(x, ωj),

φ(x) =E[G(x, ω)], φk(x) = 1 Nk

ωjk

G(x, ωj).

From (6), (7) and Propositon 7 in Chapter 6 of [16],

ϕ(x), φ(x) are continuous respect to x and ϕk(x), φk(x)

are uniformly convergent toϕ(x), φ(x)on B, respectively. Moreover, from Lemma 1, we have ϕk(xk), φk(xk) are

continuously convergent to ϕ(x∗), φ(x∗) on B, respec-tively. Taking a limit for lk

1(xk, tk1, tk2), . . ., lk7(xk), we

obtain lk

1(xk, tk1, tk2), . . ., lk7(xk) are continuously

conver-gent to l1(x∗, t∗1, t∗2), . . ., l7(x) on B, respectively. From

the definitions of θ(x, t, s, ζ, r) and θk(x, t, s, ζ, r), we

have that θk(xk, tk, sk, ζk, rk) is continuously convergent

to θ(x∗, t∗, s∗, ζ∗, r∗) on B. On the other hand, for each

k, since (xk, tk, sk, ζk, rk) is a global solution of (3), for

(x, t, s, ζ, r)∈S there holds

θk(xk, tk, sk, ζk, rk)≤θk(x, t, s, ζ, r). (8)

Letting k in (8) and by the fact that

θk(xk, tk, sk, ζk, rk) is continuously convergent to θ(x∗, t∗, s∗, ζ∗, r∗)onB, we have that

θ(x∗, t∗, s∗, ζ∗, r∗)≤θ(x, t, s, ζ, r), (x, t, s, ζ, r)∈S,

which indicates (x∗, t∗, s∗, ζ∗, r∗) is a global optimal solu-tion of (2).

For simplicity, we setθω(x, t, s, ζ, r) =rfω(x, t) + (1 r)gω(x, s, ζ), where

fω(x, t) =∥F(x, ω)−t1AG(x, ω)−t2e1∥2

+(1 2G(x, ω)

TAG(x, ω)t

3)2

+(G1(x, ω)−t4)2+ (t1t3)2+ (t2t4)2,

gω(x, s, ζ) =∥G(x, ω)−s1AF(x, ω)−s2e1−M ζ∥2

+(1 2F(x, ω)

TAF(x, ω)s

3)2+(s1s3)2

+F1(x, ω−s4)2+∥M F(x, ω)2+(s2s4)2.

We then show that with the increase of sample size, the optimal solutions of the approximation problem (3) converge exponentially to a solution of problem (2) with probability approaching one.

Theorem 2:Suppose that for each k, {(xk, tk, sk, ζk, rk)}

is a global optimal solution of problem (3) and

{(xk, tk, sk, ζk, rk)} itself converges to (x∗, t∗, s∗, ζ∗, r∗). Let B be a compact set that contains the whole sequence

{(xk, tk, sk, ζk, rk)}. Then, for anyε >0there exist positive constantsC(ε)andβ(ε), independent ofNk, such that

P rob{sup(x,t,s,ζ,r)∈B|θk(x, t, s, ζ, r)

−θ(x, t, s, ζ, r)| ≥ε}≤C(ε)e−Nkβ(ε).

Proof: For all ω Ω and all (x, t, s, ζ, r) B,

noting thatθω andθare all continuously differentiable with respect to(x, t, s, ζ, r), by the norm inequality or the absolute

IAENG International Journal of Applied Mathematics, 47:2, IJAM_47_2_04

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value inequality, following from (4)(5)(6)(7), after a simple calculation, we have that there existκ1(ω),κ2(ω)satisfying

|θω(x, t, s, ζ, r)−θ(x, t, s, ζ, r)| ≤κ1(ω), |θω(x′, t′, s′, ζ′, r′)−θω(x, t, s, ζ, r)|

≤κ2(ω) (

∥x′−x∥+∥t′−t∥+∥s′−s∥+∥ζ′−ζ∥+|r′−r|)

andE[κ1(ω)]<+,E[κ2(ω)]<+. From above results,

it is easy to obtain that the conditions of Theorem 5.1 in reference [17] are all hold, and hence completes the proof.

However, in general, approximation problems are non-convex programming. Then we probably get the stationary points rather than the global optimal solutions. Therefore, considering the stationary points are necessary. We next give some definitions associated with stationary points.

Definition 3: If there exist Lagrange multipliersβk = (βk

1,

βk

2, β3k, β4k)T ∈R4, πk = (πk1, πk2, πk3, πk4)T ∈R4,γ1k ∈R,

γk

2 ∈R satisfying

∇xθk(xk, tk, sk, ζk, rk) = 0, (9)

∇tθk(xk, tk, sk, ζk, rk)

4 ∑

i=1

βkiei= 0, (10)

tki 0, βik≥0, tkiβik = 0, (11)

∇sθk(xk, tk, sk, ζk, rk)

4 ∑

j=1

πkjej= 0, (12)

skj 0, πjk 0, skjπjk= 0, (13)

∇ζθk(xk, tk, sk, ζk, rk) = 0, (14)

∇rθk(xk, tk, sk, ζk, rk)−γ1k+γ2k = 0, (15)

γ1k≥0, γ2k≥0, r1k= 0,(1−rkk2= 0,0≤rk≤1,(16)

whereei denotes a unit vector with theith component is 1, then we call (xk, tk, sk, ζk, rk)is a stationary point of (3).

Definition 4: If there exist lagrange multipliersβ∗= (β1∗, β∗2, β3∗, β4)T R4,π∗ = (π1, π2∗, π3∗, π∗4)T ∈R4, γ1 R,

γ2∗∈R satisfying

∇xθ(x∗, t∗, s∗, ζ∗, r∗) = 0, (17)

∇tθ(x∗, t∗, s∗, ζ∗, r∗)

4 ∑

i=1

βi∗ei= 0, (18) t∗≥0, βi∗≥0, tiβi= 0, (19)

∇sθ(x∗, t∗, s∗, ζ∗, r∗)

4 ∑

j=1

π∗jej = 0, (20)

s∗j 0, π∗j 0, s∗jπ∗= 0, (21)

∇ζθ(x∗, t∗, s∗, ζ∗, r∗) = 0, (22)

∇rθ(x∗, t∗, s∗, ζ∗, r∗)−γ1+γ2= 0, (23)

γ1∗≥0, γ20, r∗γ1= 0,(1−r∗2= 0,0≤r∗≤1,(24) then we call (x∗, t∗, s∗, ζ∗, r∗)is a stationary point of (2).

We now turn our attentions to Slater constraint quali-fication, which can ensure the boundedness of Lagrange multipliers in Definition 3.

Definition 5: If there exists a vector y R4, for each

i I(t∗) :={ i | t∗i = 0, 1 i 4} such that yi > 0.

Then we call Slater constraint qualification holds.

Note that by the condtion (6) and Theory 16.8 of [14], we obtain thatf(x, t)is continuously differentiable with respect

toxand

∇xf(x, t)

= 2l1(x, t1, t2)TE[∇xF(x, ω)−t1A∇xG(x, ω)]

+2l2(x, t3)E[∇xG(x, ω)]TAE[G(x, ω)] +2l3(x, t4)E[∇xG1(x, ω)].

Similarly,g(x, s, ζ)is continuously differentiable overxand

∇xg(x, s, ζ)

= 2l4(x, s1, s2)TE[∇xG(x, ω)−s1A∇xF(x, ω)] +2l5(x, s3)E[∇xF(x, ω)]TAE[F(x, ω)]

+2l6(x, s4)E[∇xF1(x, ω)] + 2lT7(x)ME[∇xF(x, ω)].

Therefore, by the definition of θ(x, t, s, ζ, r), it is easy to obtain that θ(x, t, s, ζ, r) is continuously differentiable with respect to t, s, ζ, r, respectively. What means that

θ(x, t, s, ζ, r)is continuously differentiable on S.

Lemma 2: ∇θk(xk, tk, sk, ζk, rk) is continuously

conver-gent to∇θ(x∗, t∗, s∗, ζ∗, r∗)onN(x∗, t∗, s∗, ζ∗, r∗).

Proof: We assume limk→∞(xk, tk, sk, ζk, rk) =

(x∗, t∗, s∗, ζ∗, r∗), andN(x∗, t∗, s∗, ζ∗, r∗)∈S is a neigh-borhood of(x∗, t∗, s∗, ζ∗, r∗)contains{(xk, tk, sk, ζk, rk)}. For each ω Ω, combining (6), (7) and Proposition 7 in Chapter 6 of [16], we have ∇θk(x, t, s, ζ, r) is

uniformly convergent to ∇θ(x∗, t∗, s∗, ζ∗, r∗). Combining with Lemma 1, we obtain the conclusion immediately.

Theorem 3:Suppose that for eachk,(xk, tk, sk, ζk, rk)is a

stationary point of (3),(x∗, t∗, s∗, ζ∗, r∗)is an accumulation point of {(xk, tk, sk, ζk, rk)}. Then (x, t, s, ζ, r) is a

stationary point of (2).

Proof: For simplicity, we assume limk→∞(xk, tk, sk,

ζk, rk) = (x, t, s, ζ, r). Let βk, πk, γk

1, γk2 are the

Lagrange multipliers of (9)(16).

(i) We first show that the sequence of {βk} is bounded

for allk. To this end, we set

τk:=

4 ∑

i=1

βki. (25)

Suppose by contradiction that {βk} is not bounded,

which means that there exists a sequence {τk} such that limk→∞τk = +. We may further assume that the limit

βi:= lim k→∞

βk i

τk,(i= 1, . . . ,4)

exists. By (11), we have for each i /∈ I(t∗) = { i | t∗i = 0,1≤i≤4},βi = 0. Then following from (25), we obtain

i∈I(t∗)

βi=

4 ∑

i=1

βi= 1. (26)

For (10), dividing byτk and taking a limit, following from

Lemma 2 and formulation (26), we have

iI(t∗)

βiei=

4 ∑

i=1

βiei= 0. (27)

Since Slater constraint qualification holds, then there exists a vectory∈R4, for alli∈I(t∗)satisfyingyi>0and there holds:

(y−t∗)Tei=yi−ti∗=yi>0, ∀i∈I(t∗). (28)

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Let (27) multiplying (y −t∗)T, by the fact that β i 0

and (28) holds, we have βi = 0 for each i ∈I(t∗), which contradicts (26). Therefore {βk} is bounded. Similarly, we

can obtain the boundedness of Lagrange multipliers {πk},

{γk

1},2k}.

(ii) Since{βk},{πk}, {γk

1},2k} are bounded, we may

assume that β∗ = limk→∞βk, π = limk

→∞πk, γ1 =

limk→∞γk

1, γ2 = limk→∞γ2k exist, which together with

Lemma 2 and Definition 2, taking a limit in (9)(16), we get (17)(24), which mean(x∗, t∗, s∗, ζ∗, r∗)is a stationary point of problem (2).

IV. CONCLUSION

In this paper, we present an equivalent problem of SGSOCCP(F, G, K), which is constructed by the convex combination of two given merit functions. Since the box-constrained minimization problems contain an expectation function, we then use SAA method to give approximation problems. Furthermore the convergence results of global solutions and stationary points for the corresponding ap-proximation problems are considered, the conclusions ensure that it is feasible to regard the solutions of approximation problems as the solutions of SGSOCCP(F,G,K) in theory.

ACKNOWLEDGMENT

The authors are grateful to the two anonymous referees and editor whose helpful suggestions have led to much improvement of the paper.

REFERENCES

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IAENG International Journal of Applied Mathematics, 47:2, IJAM_47_2_04

References

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