CLASS OF ELEMENTARY FUNCTIONS INVOLVING THE EXPONENTIAL FUNCTION
FENG QI
Abstract. In this paper, the monotonicity and logarithmically convexity of
the function e−1αt−−e−e−tβt are obtained, where t ∈ R and α and β are real
numbers such thatα6=β, (α, β)= (06 ,1) and (α, β)6= (1,0).
1. Introduction
For real numbersαandβ withα6=β, (α, β)6= (0,1) and (α, β)6= (1,0) and for t∈R, let
qα,β(t) =
e−αt−e−βt
1−e−t , t6= 0,
β−α, t= 0.
(1)
In order to obtain the best bounds in Gautschi-Kershaw’s inequalities, it was proved in [9] that the functionqα,β(t) is logarithmically convex in (0,∞) and
loga-rithmically concave in (−∞,0) ifβ−α >1 and is logarithmically concave in (0,∞) and logarithmically convex in (−∞,0) if 0< β−α <1.
When ones study the logarithmically completely monotonic property of some functions involving Euler’s gamma Γ function, the psi functionψand the polygamma functions ψ(i) for i ∈
N, the elementary function qα,β(t) is encountered now and
then. The so-called logarithmically completely monotonic function on an interval I ⊂Ris a positive function f which has derivatives of all orders on I and whose logarithm lnf satisfies 0 ≤(−1)k[lnf(x)](k) <∞for k ∈
Non I. The set of the logarithmically completely monotonic functions onI is denoted byL[I]. For more information on the classL[I], please refer to [1, 2, 3, 5, 6, 7, 8, 9] and the references therein.
The first aim of this paper is to research the monotonicity of the functionqα,β(t).
The first main result of ours is the following Theorem 1 or Corollary 1.
Theorem 1. The following conclusions present the monotonic properties ofqα,β(t).
(1) The functionqα,β(t)is increasing in(0,∞)if either 1≥α+β >2α+ 1or
1≤α+β <2α < α+β+ 1 holds.
(2) The functionqα,β(t)is decreasing in(0,∞)if either1≥α+β >2β+ 1or
1≤α+β <2β < α+β+ 1is valid.
2000Mathematics Subject Classification. Primary 26A48, 26A51; Secondary 26A09, 33B15. Key words and phrases. monotonicity, logarithmically convex function, elementary function, exponential function.
The author was supported in part by the Science Foundation of the Project for Fostering Innovation Talents at Universities of Henan Province, China.
This paper was typeset usingAMS-LATEX.
(3) The functionqα,β(t)is increasing in(−∞,0) if either2α > α+β+ 1≥2
orα+β <2β < α+β+ 1≤2 validates.
(4) The functionqα,β(t)is decreasing in (−∞,0)if either 2β > α+β+ 1≥2
orα+β <2α < α+β+ 1≤2 sounds.
(5) The function qα,β(t) is increasing in (−∞,∞) if and only if one of the
following conditions holds: (a) α=β+ 1>1, (b) α > β+ 1≥1, (c) β=α+ 1<1, (d) 1≥β > α+ 1,
(e) α < β < α+ 1≤1,
(f) β+ 1≤α+β <2α < α+β+ 1.
(6) The function qα,β(t) is decreasing in (−∞,∞) if and only if one of the
following conditions holds: (a) β=α+ 1>1, (b) β > α+ 1≥1,
(c) β < α < β+ 1≤1, (d) 1> α=β+ 1,
(e) 1≥α > β+ 1,
(f) α+ 1≤α+β <2β < α+β+ 1.
Remark 1. The (α, β)-domain where the functionqα,β(t) is monotonic in Theorem 1
can be described respectively by Figure 1 to Figure 6 below.
-α
1 O
6
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1
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β=α
β=α+ 1
β=α−1
β= 1−α
Figure 1. (α, β)-domain where the function qα,β(t) is increasing
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β =α β =α+ 1
β =α−1 β= 1−α
Figure 2. (α, β)-domain where the function qα,β(t) is decreasing
in (0,∞) in Theorem 1
Remark 2. Note that the (α, β)-domain where the functionqα,β(t) is increasing (or
decreasing) in (0,∞) (or in (−∞,0)) is an union where the functionqα,β(t) increases
(or decreases) in either (0,∞) (or (−∞,0)) or (−∞,∞). Therefore, Theorem 1 can be restated as the following Corollary 1.
Corollary 1. The following conclusions describe the monotonic properties ofqα,β(t).
(1) The function qα,β(t) is increasing in (−∞,∞) if and only if (α, β) ∈ {(α, β) : α > β ≥ 0, α ≥ 1} ∪ {(α, β) : α < β ≤ 0} ∪ {(α, β) : α ≤
β−1,0≤β≤1} \ {(1,0),(0,1)}.
(2) The function qα,β(t) is decreasing in (−∞,∞) if and only if (α, β) ∈ {(α, β) : β > α ≥ 0, β ≥ 1} ∪ {(α, β) : β < α ≤ 0} ∪ {(α, β) : β ≤
α−1,0≤α≤1} \ {(1,0),(0,1)}.
(3) The functionqα,β(t)is increasing in (0,∞)if and only if(α, β)∈ {(α, β) :
α > β ≥ 1
2} ∪ {(α, β) : α ≥1−β,0 ≤ β < 1
2} ∪ {(α, β) : α+ 1 ≤ β ≤
1−α, α <0} ∪ {(α, β) :β−1≤α < β≤0} \ {(1,0)}.
(4) The functionqα,β(t)is decreasing in(0,∞)if and only if(α, β)∈ {(α, β) :
β≥1−α,12 > α≥0}∪{(α, β) :β > α≥ 1
2}∪{(α, β) :β < α≤0}∪{(α, β) :
β≤α−1,0≤α≤1} ∪ {(α, β) : 1≤α≤1−β} \ {(1,0),(0,1)}.
(5) The functionqα,β(t)is increasing in(−∞,0)if and only if(α, β)∈ {(α, β) :
1−α≤β < α, α≥1} ∪ {(α, β) : α < β ≤1, α≤0} ∪ {(α, β) :α < β ≤
1−α,0≤α < 1
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` ` `` β=α
β = 1−α
β=α−1
β =α+ 1
Figure 3. (α, β)-domain where the function qα,β(t) is increasing
in (−∞,0) in Theorem 1
(6) The functionqα,β(t)is decreasing in(−∞,0)if and only if(α, β)∈ {(α, β) :
1−β≤α < β, β≥1} ∪ {(α, β) :β < α≤ 1
2} ∪ {(α, β) :β≤1−α, 1 2 < α≤
1} \ {(1,0),(0,1)}.
Remark 3. The corresponding (α, β)-domains where the function qα,β(t) is
mono-tonic in Corollary 1 can be described respectively by Figure 5 to Figure 10 below.
The second aim of this paper is to reconsider the logarithmically convexity of the functionqα,β(t) by a very simpler approach than that in [9]. The second main
result of ours is the following Theorem 2.
Theorem 2. The functionqα,β(t)in(−∞,∞)is logarithmically convex ifβ−α >1
and logarithmically concave if 0< β−α <1.
Remark 4. Theorem 2 shows that the logarithmically convexity and logarithmically concavity in the interval (−∞,0) ofqα,β(t) presented in [9] and mentioned at the
beginning of this paper are wrong. However, this does not affect the correctness of the main results established in [9], since the wrong properties aboutqα,β(t) in the
interval (−∞,0) are unuseful there luckily.
Remark 5. Recall that ar-times differentiable functionf(x)>0 is said to be r-log-convex (orr-log-concave) on an intervalIwithr≥2 if and only if [lnf(x)](r)exists
and [lnf(x)](r) ≥0 (or [lnf(x)](r)≤0) on I. In [4], the following conclusions are
obtained: If 1> β−α >0, thenqα,β(t) is 3-log-convex in (0,∞) and 3-log-concave
in (−∞,0); ifβ−α >1, thenqα,β(t) is 3-log-concave in (0,∞) and 3-log-convex in
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β =α
β= 1−α β =α−1
β=α+ 1
Figure 4. (α, β)-domain where the function qα,β(t) is decreasing
in (−∞,0) in Theorem 1
2. Proofs of theorems
Proof of Theorem 1. It is clear that the functionqα,β(t) can be rewritten as
qα,β(t) =
sinh(β−α2 )t sinh2t exp
(1−α−β)t 2 ,pα,β
t
2
. (2)
If α=β + 1, then qα,β(t) = −e−βt is increasing forβ >0 and decreasing for
β <0 in (−∞,∞). If α=β−1, thenqα,β(t) =e−αt is decreasing for α >0 and
increasing forα <0 in (−∞,∞).
For|α−β| 6= 1, direct differentiation shows
p0α,β(t) = sinh((β−α)t) sinht e
(1−α−β)tϕ α,β(t),
where
ϕα,β(t) = (β−α) coth((β−α)t)−cotht−α−β+ 1 (3)
and
ϕ0α,β(t) =
1
sinht
2 −
β−α
sinh((β−α)t)
2
= 1 t2
t
sinht
2 −
(β−α)t
sinh((β−α)t)
2
-α
1 O
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β=α β=α−1 β=α+ 1
``` ``` ``` ``` ``` ``` ``` ``` ``` ``` ``` ``` ``` ``` ``` ``` ``` ``` ``` ``` ``` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` `
Figure 5. (α, β)-domain where the function qα,β(t) is increasing
in (−∞,∞) in Theorem 1 and Corollary 1
Since ϕ0α,β(t) = ϕ0α,β(−t) and the function sinht t > 0 is decreasing in (0,∞) and increasing in (−∞,0), thenϕ0α,β(t)≥ 0 for |α−β| >1 and ϕ0α,β(t) ≤ 0 for 0 <|α−β| <1 in (−∞,∞). This means that the functionϕα,β(t) is increasing
for|α−β|>1 and decreasing for 0<|α−β|<1 in (−∞,∞). It is not difficult to obtain limt→−∞ϕα,β(t) = 2−α−β− |α−β|, limt→0ϕα,β(t) = 1−α−β and
limt→∞ϕα,β(t) =|α−β| −α−β.
1.If β > α+ 1, thenβ−α > 0,|α−β|>1, limt→−∞ϕα,β(t) = 2(1−β) and
limt→∞ϕα,β(t) = −2α. Further, ifα ≥ 0, then ϕα,β(t) < 0 and p0α,β(t) < 0 in
(−∞,∞), and thenpα,β(t) and qα,β(t) are decreasing in (−∞,∞). Therefore, for
β > α+ 1≥1, the functionqα,β(t) is decreasing in (−∞,∞).
Ifβ > α+ 1 andβ ≤1, then limt→−∞ϕα,β(t)≥0,ϕα,β(t)>0 andp0α,β(t)>0
in (−∞,∞), and then pα,β(t) and qα,β(t) are increasing in (−∞,∞). Hence, for
1≥β > α+ 1, the functionqα,β(t) is increasing in (−∞,∞).
Ifβ > α+ 1 andα+β≤1, then limt→0ϕα,β(t)≥0,ϕα,β(t)>0 andp0α,β(t)>0
in (0,∞), and thenpα,β(t) andqα,β(t) are increasing in (0,∞). Consequently, for
2α+ 1< α+β≤1, the functionqα,β(t) is increasing in (0,∞).
Ifβ > α+ 1 andα+β≥1, then limt→0ϕα,β(t)≤0,ϕα,β(t)<0 andp0α,β(t)<0
in (−∞,0), and thenpα,β(t) andqα,β(t) are decreasing in (−∞,0). Therefore, for
2β > α+β+ 1≥2, the functionqα,β(t) is decreasing in (−∞,0).
2.If α < β < α+ 1, then β−α > 0 and |α−β|<1. Further, if α≤0, then ϕα,β(t)>0 andp0α,β(t)>0 in (−∞,∞), and thenpα,β(t) andqα,β(t) are increasing
in (−∞,∞). Accordingly, forα < β < α+ 1≤1, the functionqα,β(t) is increasing
-α
1 O
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β
1
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β =α
β =α−1
β=α+ 1
``` ``` ``` ``` ``` ``` ``` ``` ``` ``` ``` ``` ``` ``` ``` ``` ``` ``` ``` `` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` `
Figure 6. (α, β)-domain where the function qα,β(t) is decreasing
in (−∞,∞) in Theorem 1 and Corollary 1
If α < β < α+ 1 and β ≥ 1, then limt→−∞ϕα,β(t) ≤ 0, ϕα,β(t) < 0 and
p0α,β(t)<0 in (−∞,∞), and then pα,β(t) and qα,β(t) are decreasing in (−∞,∞).
Therefore, for α+ 1≤α+β <2β < α+β+ 1, the functionqα,β(t) is decreasing
in (−∞,∞).
If α < β < α+ 1 and α+β ≤ 1, then limt→0ϕα,β(t) ≥ 0, ϕα,β(t) > 0 and
p0α,β(t)>0 in (−∞,0), and thenpα,β(t) andqα,β(t) are increasing in (−∞,0). As
a result, for α+β < 2β < α+β+ 1 ≤ 2, the function qα,β(t) is increasing in
(−∞,0).
If α < β < α+ 1 and α+β ≥ 1, then limt→0ϕα,β(t) ≤ 0, ϕα,β(t) < 0 and
p0α,β(t)<0 in (0,∞), and thenpα,β(t) and qα,β(t) are decreasing in (0,∞).
Con-sequently, for 1 ≤α+β <2β < α+β+ 1, the functionqα,β(t) is decreasing in
(0,∞).
3.If α > β+ 1, thenβ−α <0, |α−β|>1, limt→−∞ϕα,β(t) = 2(1−α) and
limt→∞ϕα,β(t) = −2β. Further, if β ≥ 0, then ϕα,β(t) < 0 and p0α,β(t) > 0 in
(−∞,∞), and then pα,β(t) and qα,β(t) are increasing in (−∞,∞). Therefore, for
-α
1 O
6
β
1
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β=α
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β=α−1
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@ @ ` ` `` ` `
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β=α+ 1
Figure 7. (α, β)-domain where the function qα,β(t) is increasing
in (0,∞) in Theorem 1
Ifα > β+ 1 andα≤1, then limt→−∞ϕα,β(t)≥0,ϕα,β(t)>0 andp0α,β(t)<0
in (−∞,∞), and then pα,β(t) andqα,β(t) are decreasing in (−∞,∞). Hence, for
1≥α > β+ 1, the functionqα,β(t) is decreasing in (−∞,∞).
Ifα > β+ 1 andα+β≤1, then limt→0ϕα,β(t)≥0,ϕα,β(t)>0 andp0α,β(t)<0
in (0,∞), and then pα,β(t) andqα,β(t) are decreasing in (0,∞). Accordingly, for
1≥α+β >2β+ 1, the functionqα,β(t) is decreasing in (0,∞).
Ifα > β+ 1 andα+β≥1, then limt→0ϕα,β(t)≤0,ϕα,β(t)<0 andp0α,β(t)>0
in (−∞,0), and then pα,β(t) and qα,β(t) are increasing in (−∞,0). Hence, for
2α > α+β+ 1≥2, the functionqα,β(t) is increasing in (−∞,0).
4.If β < α < β+ 1, then β−α <0 and |α−β|<1. Further, if β ≤0, then ϕα,β(t)>0 andp0α,β(t)<0 in (−∞,∞), and thenpα,β(t) andqα,β(t) are decreasing
in (−∞,∞). Therefore, for β < α < β+ 1≤1, the function qα,β(t) is decreasing
in (−∞,∞).
If β < α < β + 1 and α ≥ 1, then limt→−∞ϕα,β(t) ≤ 0, ϕα,β(t) < 0 and
p0α,β(t)>0 in (−∞,∞), and then pα,β(t) andqα,β(t) are increasing in (−∞,∞).
Accordingly, forβ+ 1≤α+β <2α < α+β+ 1, the functionqα,β(t) is increasing
in (−∞,∞).
If β < α < β+ 1 and α+β ≤ 1, then limt→0ϕα,β(t) ≥ 0, ϕα,β(t) > 0 and
p0α,β(t) < 0 in (−∞,0), and then pα,β(t) and qα,β(t) are decreasing in (−∞,0).
Consequently, forα+β <2α < α+β+ 1≤2, the functionqα,β(t) is decreasing in
(−∞,0).
If β < α < β+ 1 and α+β ≥ 1, then limt→0ϕα,β(t) ≤ 0, ϕα,β(t) < 0 and
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in (0,∞) in Theorem 1
result, for 1≤α+β <2α < α+β+ 1, the functionqα,β(t) is increasing in (0,∞).
The proof of Theorem 1 is complete.
Proof of Theorem 2. For β > α, the functions qα,β(t) andpα,β(t), related by (2),
are positive. Taking logarithm ofpα,β(t) and differentiating yields
lnpα,β(t) = ln sinh((β−α)t)−ln sinht+ (1−α−β)t,
[lnpα,β(t)]0= (β−α) coth((β−α)t)−cotht−α−β+ 1 =ϕα,β(t),
whereϕα,β(t) is defined by (3).
By the same argument as in the proof of Theorem 1 on page 5, it is easy to see thatϕ0α,β(t) = [lnpα,β(t)]00 ≥0 forβ−α >1 and ϕ0α,β(t) = [pα,β(t)]00 ≤0 for
0 < β−α < 1 in (−∞,∞). This means that the function pα,β(t) = qα,β(2t) is
logarithmically convex forβ−α >1 and logarithmically concave for 0< β−α <1 in the whole axis (−∞,∞). The proof of Theorem 2 is complete.
References
[1] C. Berg,Integral representation of some functions related to the gamma function, Mediterr.
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β=α β=α−1 β =α+ 1
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β = 1−α
Figure 9. (α, β)-domain where the function qα,β(t) is increasing
in (−∞,0) in Theorem 1
[2] A. Z. Grinshpan and M. E. H. Ismail,Completely monotonic functions involving the gamma
andq-gamma functions, Proc. Amer. Math. Soc.134(2006), no. 4, 1153–1160.
[3] F. Qi, Certain logarithmically N-alternating monotonic functions involving gamma and
q-gamma functions, RGMIA Res. Rep. Coll. 8 (2005), no. 3, Art. 5. Available online at
http://rgmia.vu.edu.au/v8n3.html.
[4] F. Qi,Three-log-convexity for a class of elementary functions involving exponential function,
J. Math. Anal. Approx. Theory1(2006), no. 2, in press.
[5] F. Qi and Ch.-P. Chen,A complete monotonicity property of the gamma function, J. Math.
Anal. Appl.296(2004), no. 2, 603–607.
[6] F. Qi and B.-N. Guo,Complete monotonicities of functions involving the gamma and digamma
functions, RGMIA Res. Rep. Coll.7 (2004), no. 1, Art. 8, 63–72. Available online athttp: //rgmia.vu.edu.au/v7n1.html.
[7] F. Qi, B.-N. Guo, and Ch.-P. Chen,Some completely monotonic functions involving the gamma
and polygamma functions, RGMIA Res. Rep. Coll.7(2004), no. 1, Art. 5, 31–36. Available
online athttp://rgmia.vu.edu.au/v7n1.html.
[8] F. Qi, B.-N. Guo, and Ch.-P. Chen,Some completely monotonic functions involving the gamma
and polygamma functions, J. Austral. Math. Soc.80(2006), 81–88.
[9] F. Qi, B.-N. Guo, and Ch.-P. Chen,The best bounds in Gautschi-Kershaw inequalities, Math.
Inequal. Appl. (2006), in press. RGMIA Res. Rep. Coll.8(2005), no. 2, Art. 17. Available
online athttp://rgmia.vu.edu.au/v8n2.html.
(F. Qi)Research Institute of Mathematical Inequality Theory, Henan Polytechnic
University, Jiaozuo City, Henan Province, 454010, China
E-mail address: [email protected], [email protected], [email protected], [email protected], [email protected]
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Figure 10. (α, β)-domain where the functionqα,β(t) is decreasing