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(1)

© 2012 Pearson Education, Inc. Lecture by Edward J. Zalisko

PowerPoint Lectures for

Campbell Biology: Concepts & Connections, Seventh Edition Reece, Taylor, Simon, and Dickey

Chapter 10

(2)

Viruses infect organisms by

– binding to receptors on a host’s target cell,

– injecting viral genetic material into the cell, and

– hijacking the cell’s own molecules and organelles to produce new copies of the virus.

The host cell is destroyed, and newly replicated

viruses are released to continue the infection.

Introduction

(3)

Viruses are not generally considered alive

because they

– are not cellular and

– cannot reproduce on their own.

Because viruses have much less complex

structures than cells, they are relatively easy to

study at the molecular level.

For this reason, viruses are used to study the

functions of DNA.

Introduction

(4)

Figure 10.0_1

Chapter 10: Big Ideas

The Structure of the Genetic Material

DNA Replication

The Genetics of Viruses and Bacteria

The Flow of Genetic Information from DNA to

(5)
(6)

THE STRUCTURE OF THE

GENETIC MATERIAL

(7)

10.1 SCIENTIFIC DISCOVERY: Experiments

showed that DNA is the genetic material

Until the 1940s, the case for proteins serving as

the genetic material was stronger than the case

for DNA.

– Proteins are made from 20 different amino acids.

– DNA was known to be made from just four kinds of nucleotides.

Studies of bacteria and viruses

– ushered in the field of molecular biology, the study of heredity at the molecular level, and

– revealed the role of DNA in heredity.

(8)

10.1 SCIENTIFIC DISCOVERY: Experiments

showed that DNA is the genetic material

In 1928, Frederick Griffith discovered that a

“transforming factor” could be transferred into a

bacterial cell. He found that

when he exposed heat-killed pathogenic bacteria to

harmless bacteria, some harmless bacteria were converted to disease-causing bacteria and

– the disease-causing characteristic was inherited by descendants of the transformed cells.

(9)

10.1 SCIENTIFIC DISCOVERY: Experiments

showed that DNA is the genetic material

In 1952, Alfred Hershey and Martha Chase used

bacteriophages to show that DNA is the genetic

material of T2, a virus that infects the bacterium

Escherichia coli

(

E. coli

).

Bacteriophages (or phages for short) are viruses that infect bacterial cells.

Phages were labeled with radioactive sulfur to detect proteins or radioactive phosphorus to detect DNA.

– Bacteria were infected with either type of labeled phage to determine which substance was injected into cells and

which remained outside the infected cell.

(10)

10.1 SCIENTIFIC DISCOVERY: Experiments

showed that DNA is the genetic material

– The sulfur-labeled protein stayed with the phages outside the bacterial cell, while the phosphorus-labeled DNA was detected inside cells.

– Cells with phosphorus-labeled DNA produced new

bacteriophages with radioactivity in DNA but not in protein.

© 2012 Pearson Education, Inc.

(11)

Figure 10.1A

Head

Tail

Tail fiber

(12)

Figure 10.1A_1

Head

Tail

(13)

Figure 10.1B Phage Bacterium Batch 2: Radioactive DNA labeled in green DNA Radioactive protein Centrifuge Phage DNA Empty protein shell Pellet The radioactivity is in the liquid.

Radioactive DNA

Centrifuge

Pellet The radioactivityis in the pellet.

(14)
(15)

Figure 10.1B_2

Phage DNA Empty

protein shell

Pellet

The radioactivity is in the liquid.

Pellet The radioactivityis in the pellet.

3

Centrifuge

Centrifuge

(16)

Figure 10.1C

A phage attaches itself to a bacterial cell.

The phage injects its DNA into the bacterium.

The phage DNA directs the host cell to make more phage DNA and proteins; new phages

assemble. The cell lyses

and releases the new phages.

1 3

(17)

Figure 10.1C_1

A phage attaches itself to a bacterial cell.

The phage injects its DNA into the bacterium.

(18)

Figure 10.1C_2

The phage DNA directs the host cell to make more phage DNA and proteins; new phages

assemble. The cell lyses and releases

the new phages.

3

(19)

10.2 DNA and RNA are polymers of nucleotides

DNA and RNA are nucleic acids.

One of the two strands of DNA is a DNA

polynucleotide

, a nucleotide polymer (chain).

A

nucleotide

is composed of a

– nitrogenous base,

– five-carbon sugar, and

– phosphate group.

The nucleotides are joined to one another by a

(20)

Each type of DNA nucleotide has a different

nitrogen-containing base:

adenine (A),

– cytosine (C),

– thymine (T), and

– guanine (G).

10.2 DNA and RNA are polymers of nucleotides

© 2012 Pearson Education, Inc.

(21)

Figure 10.2A A A A A A A A C T T T T T T C C C C G G G G G C C G A T A DNA double helix T DNA nucleotide Covalent bond joining nucleotides A C T Two representations of a DNA polynucleotide

(22)
(23)

Figure 10.2A_2 DNA nucleotide Covalent bond joining nucleotides A Two representations of a DNA polynucleotide

(24)

Figure 10.2A_3

Phosphate group

Sugar

(deoxyribose)

DNA nucleotide

Thymine (T) Nitrogenous base

(25)

Figure 10.2B

Thymine (T) Cytosine (C)

Pyrimidines Purines

(26)

Figure 10.2B_1

Thymine (T) Cytosine (C)

(27)

Figure 10.2B_2

Purines

(28)

10.2 DNA and RNA are Polymers of Nucleotides

RNA (ribonucleic acid) is unlike DNA in that it

– uses the sugar ribose (instead of deoxyribose in DNA) and

– RNA has the nitrogenous base uracil (U) instead of thymine.

(29)

Figure 10.2C

Phosphate group

Sugar (ribose)

Uracil (U)

(30)

Figure 10.2D

Uracil

Adenine

Cytosine

Guanine

Ribose

(31)

10.3 SCIENTIFIC DISCOVERY: DNA is a

double-stranded helix

In 1952, after the Hershey-Chase experiment

demonstrated that the genetic material was most

likely DNA, a race was on to

– describe the structure of DNA and

– explain how the structure and properties of DNA can account for its role in heredity.

(32)
(33)
(34)
(35)

10.3 SCIENTIFIC DISCOVERY: DNA is a

double-stranded helix

In 1953, James D. Watson and Francis Crick

deduced the secondary structure of DNA, using

X-ray crystallography data of DNA from the work of

Rosalind Franklin and Maurice Wilkins and

– Chargaff’s observation that in DNA,

– the amount of adenine was equal to the amount of thymine and

– the amount of guanine was equal to that of cytosine.

(36)

Watson and Crick reported that DNA consisted of

two polynucleotide strands wrapped into a

double

helix

.

– The sugar-phosphate backbone is on the outside.

– The nitrogenous bases are perpendicular to the backbone in the interior.

– Specific pairs of bases give the helix a uniform shape.

– A pairs with T, forming two hydrogen bonds, and

– G pairs with C, forming three hydrogen bonds.

10.3 SCIENTIFIC DISCOVERY: DNA is a

double-stranded helix

© 2012 Pearson Education, Inc.

(37)
(38)

Figure 10.3C

(39)

Figure 10.3D

Base pair

Hydrogen bond

Partial chemical structure

Computer model Ribbon

(40)

Figure 10.3D_1

Base pair

Ribbon model

C G C G G C

G C

T A A T

C G A T

T A C G

C G G C

A T A T

(41)

Figure 10.3D_2

Hydrogen bond

Partial chemical structure

G C

T A

A T

(42)

Figure 10.3D_3

(43)

10.3 SCIENTIFIC DISCOVERY: DNA is a

double-stranded helix

In 1962, the Nobel Prize was awarded to

– James D. Watson, Francis Crick, and Maurice Wilkins.

– Rosalind Franklin probably would have received the prize as well but for her death from cancer in 1958. Nobel Prizes are never awarded posthumously.

The Watson-Crick model gave new meaning to

the words

genes

and

chromosomes

. The genetic

information in a chromosome is encoded in the

nucleotide sequence of DNA.

(44)

DNA REPLICATION

(45)

10.4 DNA replication depends on specific base

pairing

In their description of the structure of DNA,

Watson and Crick noted that the structure of DNA

suggests a possible copying mechanism.

DNA replication follows a

semiconservative

model

.

– The two DNA strands separate.

– Each strand is used as a pattern to produce a

complementary strand, using specific base pairing.

– Each new DNA helix has one old strand with one new strand.

© 2012 Pearson Education, Inc.

(46)

Figure 10.4A_s1

A parental molecule

of DNA

G C

A T

T A A T

(47)

Figure 10.4A_s2 A parental molecule of DNA A C

G C

A T

T A

The parental strands separate and serve

as templates Free

nucleotides

T A T

T A A T A G

G C G

C

A T

C G

(48)

Figure 10.4A_s3 A parental molecule of DNA A C

G C

A T

T A

The parental strands separate and serve

as templates Free

nucleotides

T A T

T A A T A G

G C G

C

A T

C G

C

Two identical daughter molecules

of DNA are formed

A T A T

A T A T

T A T A

C G C G

(49)

Figure 10.4B Parental DNA molecule Daughter strand Parental strand Daughter DNA molecules

A T

G C

A T

A T T A

(50)

DNA replication begins at the origins of replication

where

– DNA unwinds at the origin to produce a “bubble,”

– replication proceeds in both directions from the origin, and

– replication ends when products from the bubbles merge with each other.

10.5 DNA replication proceeds in two directions

at many sites simultaneously

(51)

DNA replication occurs in the 5

to 3

direction.

– Replication is continuous on the 3 to 5 template.

– Replication is discontinuous on the 5 to 3 template, forming short segments.

10.5 DNA replication proceeds in two directions

at many sites simultaneously

(52)

10.5 DNA replication proceeds in two directions

at many sites simultaneously

Two key proteins are involved in DNA replication.

1. DNA ligase joins small fragments into a continuous chain.

2. DNA polymerase

– adds nucleotides to a growing chain and

– proofreads and corrects improper base pairings.

© 2012 Pearson Education, Inc.

(53)

DNA polymerases and DNA ligase also repair

DNA damaged by harmful radiation and toxic

chemicals.

DNA replication ensures that all the somatic cells

in a multicellular organism carry the same genetic

information.

10.5 DNA replication proceeds in two directions

at many sites simultaneously

(54)

Figure 10.5A

Parental DNA

molecule Origin of replication

“Bubble”

Parental strand Daughter strand

Two

daughter DNA

(55)

Figure 10.5B

5 end 3 end

5

43

211

2345P P P P P HO A T C G G C P P P A T OH

(56)

Figure 10.5C

Overall direction of replication DNA ligase

Replication fork Parental DNA

DNA polymerase

molecule This daughter

strand is synthesized continuously This daughter strand is synthesized in pieces 35

(57)

THE FLOW OF GENETIC

INFORMATION FROM DNA TO

RNA TO PROTEIN

(58)

10.6 The DNA genotype is expressed as proteins,

which provide the molecular basis for

phenotypic traits

DNA specifies traits by dictating protein synthesis.

The molecular chain of command is from

– DNA in the nucleus to RNA and

– RNA in the cytoplasm to protein.

Transcription

is the synthesis of RNA under the

direction of DNA.

Translation

is the synthesis of proteins under the

direction of RNA.

(59)

Figure 10.6A_s1

DNA

NUCLEUS

(60)

Figure 10.6A_s2

DNA

NUCLEUS

CYTOPLASM RNA

(61)

Figure 10.6A_s3

DNA

NUCLEUS

CYTOPLASM RNA

Transcription

Translation

(62)

10.6 The DNA genotype is expressed as proteins,

which provide the molecular basis for

phenotypic traits

The connections between genes and proteins

– The initial one gene–one enzyme hypothesis was based on studies of inherited metabolic diseases.

– The one gene–one enzyme hypothesis was expanded to include all proteins.

– Most recently, the one gene–one polypeptide hypothesis recognizes that some proteins are composed of multiple polypeptides.

(63)
(64)

10.7 Genetic information written in codons is

translated into amino acid sequences

The sequence of nucleotides in DNA provides a

code for constructing a protein.

– Protein construction requires a conversion of a nucleotide sequence to an amino acid sequence.

– Transcription rewrites the DNA code into RNA, using the same nucleotide “language.”

(65)

10.7 Genetic information written in codons is

translated into amino acid sequences

– The flow of information from gene to protein is based on a triplet code: the genetic instructions for the

amino acid sequence of a polypeptide chain are written in DNA and RNA as a series of nonoverlapping three-base “words” called codons.

– Translation involves switching from the nucleotide “language” to the amino acid “language.”

– Each amino acid is specified by a codon.

– 64 codons are possible.

– Some amino acids have more than one possible codon.

(66)

Figure 10.7

DNA molecule

Gene 1

Gene 2

Gene 3

A

Transcription

RNA

Translation Codon

Polypeptide

Amino acid

A A C C G G C A A A A

U U G G C C G U U U U

DNA

(67)

Figure 10.7_1

A

Transcription

RNA

Translation Codon

Polypeptide

Amino acid

A A C C G G C A A A A

U U G G C C G U U U U

DNA

(68)

10.8 The genetic code dictates how codons are

translated into amino acids

Characteristics of the

genetic code

– Three nucleotides specify one amino acid.

– 61 codons correspond to amino acids.

– AUG codes for methionine and signals the start of transcription.

– 3 “stop” codons signal the end of translation.

(69)

10.8 The genetic code dictates how codons are

translated into amino acids

The

genetic code

is

redundant, with more than one codon for some amino

acids,

unambiguous in that any codon for one amino acid

does not code for any other amino acid,

nearly universal—the genetic code is shared by

organisms from the simplest bacteria to the most complex plants and animals, and

without punctuation in that codons are adjacent to each

other with no gaps in between.

(70)

Figure 10.8A

Second base

T

h

ir

d

b

as

e

F

ir

st

b

as

(71)

Figure 10.8B_s1

T

Strand to be transcribed

A C T T C A A

A T A A

DNA A A T C

T T T T

G A G

(72)

Figure 10.8B_s2

T

Strand to be transcribed

A C T T C A A

A T A A

DNA A A T C

T T T T

G A G

G

RNA

Transcription

(73)

Figure 10.8B_s3

T

Strand to be transcribed

A C T T C A A

A T A A

DNA A A T C

T T T T

G A G

G

RNA

Transcription

A U G A A G U U U U A G

Translation

Polypeptide Met Lys Phe

Stop codon Start

(74)
(75)

10.9 Transcription produces genetic messages in

the form of RNA

Overview of transcription

– An RNA molecule is transcribed from a DNA template by a process that resembles the synthesis of a DNA strand during DNA replication.

– RNA nucleotides are linked by the transcription enzyme RNA polymerase.

– Specific sequences of nucleotides along the DNA mark where transcription begins and ends.

– The “start transcribing” signal is a nucleotide sequence called a promoter.

(76)

10.9 Transcription produces genetic messages in

the form of RNA

– Transcription begins with initiation, as the RNA polymerase attaches to the promoter.

– During the second phase, elongation, the RNA grows longer.

– As the RNA peels away, the DNA strands rejoin.

– Finally, in the third phase, termination, the RNA

polymerase reaches a sequence of bases in the DNA template called a terminator, which signals the end of the gene.

– The polymerase molecule now detaches from the RNA molecule and the gene.

© 2012 Pearson Education, Inc.

(77)

Figure 10.9A RNA polymerase Free RNA nucleotides Template

strand of DNA Newly made RNA

Direction of transcription T G A G G A A

U C C A

C

T T A

(78)

Figure 10.9B

RNA polymerase DNA of gene

Promoter DNA

Initiation

1

2

Terminator DNA

3

Elongation Area shown in Figure 10.9A

Termination GrowingRNA

RNA

polymerase Completed

(79)

Figure 10.9B_1

RNA polymerase

DNA of gene

Promoter DNA

Initiation

1

(80)

Figure 10.9B_2

2 Elongation Area shown

in Figure 10.9A

(81)

Figure 10.9B_3

Termination

RNA

polymerase Completed

RNA

(82)

10.10 Eukaryotic RNA is processed before

leaving the nucleus as mRNA

Messenger RNA

(

mRNA

)

– encodes amino acid sequences and

– conveys genetic messages from DNA to the translation machinery of the cell, which in

– prokaryotes, occurs in the same place that mRNA is made, but in

– eukaryotes, mRNA must exit the nucleus via nuclear pores to enter the cytoplasm.

– Eukaryotic mRNA has

introns, interrupting sequences that separate

exons, the coding regions.

(83)

10.10 Eukaryotic RNA is processed before

leaving the nucleus as mRNA

Eukaryotic mRNA undergoes processing before

leaving the nucleus.

RNA splicing removes introns and joins exons to produce a continuous coding sequence.

– A cap and tail of extra nucleotides are added to the ends of the mRNA to

– facilitate the export of the mRNA from the nucleus,

– protect the mRNA from attack by cellular enzymes, and

– help ribosomes bind to the mRNA.

(84)

Figure 10.10

DNA

Cap

Exon Intron Exon

RNA

transcript with cap and tail

Exon Intron

Transcription

Addition of cap and tail

Introns removed Tail

Exons spliced together

Coding sequence

NUCLEUS

(85)

10.11 Transfer RNA molecules serve as

interpreters during translation

Transfer RNA

(

tRNA

) molecules function as a

language interpreter,

– converting the genetic message of mRNA

– into the language of proteins.

Transfer RNA molecules perform this interpreter

task by

– picking up the appropriate amino acid and

– using a special triplet of bases, called an anticodon, to recognize the appropriate codons in the mRNA.

(86)

Figure 10.11A

Amino acid attachment site

Hydrogen bond

RNA polynucleotide chain

Anticodon

A simplified

schematic of a tRNA A tRNA molecule, showing

(87)

Figure 10.11B

Enzyme tRNA

(88)

10.12 Ribosomes build polypeptides

Translation occurs on the surface of the

ribosome

.

– Ribosomes coordinate the functioning of mRNA and tRNA and, ultimately, the synthesis of polypeptides.

– Ribosomes have two subunits: small and large.

– Each subunit is composed of ribosomal RNAs and proteins.

– Ribosomal subunits come together during translation.

– Ribosomes have binding sites for mRNA and tRNAs.

(89)

Figure 10.12A

tRNA

molecules

Growing polypeptide

Large subunit

Small subunit

(90)

Figure 10.12B

tRNA binding sites

mRNA binding site Large

subunit

Small subunit

P

(91)

Figure 10.12C

mRNA

Codons

tRNA

Growing polypeptide

(92)

10.13 An initiation codon marks the start of an

mRNA message

Translation can be divided into the same three

phases as transcription:

1. initiation,

2. elongation, and

3. termination.

Initiation brings together

– mRNA,

– a tRNA bearing the first amino acid, and

– the two subunits of a ribosome.

(93)

10.13 An initiation codon marks the start of an

mRNA message

Initiation establishes where translation will begin.

Initiation occurs in two steps.

1. An mRNA molecule binds to a small ribosomal subunit and the first tRNA binds to mRNA at the start codon.

– The start codon reads AUG and codes for methionine.

– The first tRNA has the anticodon UAC.

2. A large ribosomal subunit joins the small subunit, allowing the ribosome to function.

– The first tRNA occupies the P site, which will hold the growing peptide chain.

– The A site is available to receive the next tRNA.

(94)

Figure 10.13A

Start of genetic message

Cap

End

(95)

Figure 10.13B Initiator tRNA mRNA Start codon Small ribosomal subunit Large ribosomal subunit P site A site Met

A U G

U A C

2

A U G

U A C

1

(96)

10.14 Elongation adds amino acids to the

polypeptide chain until a stop codon

terminates translation

Once initiation is complete, amino acids are

added one by one to the first amino acid.

Elongation is the addition of amino acids to the

polypeptide chain.

(97)

Each cycle of elongation has three steps.

1. Codon recognition: The anticodon of an incoming tRNA molecule, carrying its amino acid, pairs with the mRNA codon in the A site of the ribosome.

2. Peptide bond formation: The new amino acid is joined to the chain.

3. Translocation: tRNA is released from the P site and the ribosome moves tRNA from the A site into the P site.

10.14 Elongation adds amino acids to the

polypeptide chain until a stop codon

terminates translation

(98)

Elongation continues until the termination stage of

translation, when

– the ribosome reaches a stop codon,

– the completed polypeptide is freed from the last tRNA, and

the ribosome splits back into its separate subunits.

10.14 Elongation adds amino acids to the

polypeptide chain until a stop codon

terminates translation

© 2012 Pearson Education, Inc.

(99)

Figure 10.14_s1

Polypeptide

mRNA

Codon recognition Anticodon Amino

acid

Codons

P

site siteA

(100)

Figure 10.14_s2

Polypeptide

mRNA

Codon recognition Anticodon Amino

acid

Codons

P

site siteA

1

Peptide bond

2

(101)

Figure 10.14_s3

Polypeptide

mRNA

Codon recognition Anticodon Amino

acid

Codons

P

site siteA

1

Peptide bond

2

formation

Translocation

3

(102)

Figure 10.14_s4 Polypeptide mRNA Codon recognition Anticodon Amino acid Codons P

site siteA

(103)

10.15 Review: The flow of genetic information in

the cell is DNA

RNA

protein

Transcription is the synthesis of RNA from a DNA

template. In eukaryotic cells,

– transcription occurs in the nucleus and

– the mRNA must travel from the nucleus to the cytoplasm.

(104)

10.15 Review: The flow of genetic information in

the cell is DNA

RNA

protein

Translation can be divided into four steps, all of

which occur in the cytoplasm:

1. amino acid attachment,

2. initiation of polypeptide synthesis,

3. elongation, and

4. termination.

(105)
(106)

Figure 10.15_1

DNA Transcription

mRNA

RNA

polymerase

Transcription

(107)

Figure 10.15_2 Translation Amino acid Enzyme CYTOPLASM Amino acid attachment 2 tRNA ATP Anticodon Initiation of polypeptide synthesis Large ribosomal subunit Initiator tRNA

Start Codon Small

ribosomal subunit mRNA

(108)

Figure 10.15_3

4 Elongation

Growing polypeptide

New peptide bond forming

Codons mRNA

Polypeptide

Termination

Stop codon

(109)

10.16 Mutations can change the meaning of genes

A

mutation

is any change in the nucleotide

sequence of DNA.

Mutations can involve

– large chromosomal regions or

just a single nucleotide pair.

(110)

10.16 Mutations can change the meaning of genes

Mutations within a gene can be divided into two

general categories.

1. Base substitutions involve the replacement of one nucleotide with another. Base substitutions may

– have no effect at all, producing a silent mutation,

– change the amino acid coding, producing a missense mutation, which produces a different amino acid,

– lead to a base substitution that produces an improved protein that enhances the success of the mutant organism and its descendant, or

– change an amino acid into a stop codon, producing a

nonsense mutation.

(111)

10.16 Mutations can change the meaning of genes

2. Mutations can result in deletions or insertions that may

– alter the reading frame (triplet grouping) of the mRNA, so that nucleotides are grouped into different codons,

– lead to significant changes in amino acid sequence downstream of the mutation, and

– produce a nonfunctional polypeptide.

(112)

10.16 Mutations can change the meaning of genes

Mutagenesis

is the production of mutations.

Mutations can be caused by

– spontaneous errors that occur during DNA replication or recombination or

mutagens, which include

– high-energy radiation such as X-rays and ultraviolet light and

– chemicals.

(113)

Figure 10.16A

Normal hemoglobin DNA Mutant hemoglobin DNA

mRNA mRNA

Sickle-cell hemoglobin Normal hemoglobin

Glu Val

C T T

G A A

C T

G A

A

(114)

Figure 10.16B Normal gene Nucleotide substitution Nucleotide deletion Nucleotide insertion Inserted Deleted mRNA Protein Met Met Lys Phe Lys Phe Ala Ala Gly Ser

A U G A A G U U U G G C G C A

G C G C A

A

G U U U A U G A A

Met Lys Leu Ala His

G U U

A U G A A G G C G C A U

U

Met Lys Leu Ala His

G U U

(115)

THE GENETICS OF VIRUSES

AND BACTERIA

(116)

10.17 Viral DNA may become part of the host

chromosome

A virus is essentially “genes in a box,” an

infectious particle consisting of

– a bit of nucleic acid,

– wrapped in a protein coat called a capsid, and

– in some cases, a membrane envelope.

Viruses have two types of reproductive cycles.

1. In the lytic cycle,

– viral particles are produced using host cell components,

– the host cell lyses, and

– viruses are released.

(117)

10.17 Viral DNA may become part of the host

chromosome

2. In the Lysogenic cycle

– Viral DNA is inserted into the host chromosome by recombination.

– Viral DNA is duplicated along with the host chromosome during each cell division.

– The inserted phage DNA is called a prophage.

– Most prophage genes are inactive.

– Environmental signals can cause a switch to the lytic cycle, causing the viral DNA to be excised from the bacterial

chromosome and leading to the death of the host cell.

© 2012 Pearson Education, Inc.

Animation: Phage T4 Lytic Cycle

(118)

Figure 10.17_s1

Phage Attaches

to cell

Phage DNA Bacterial

chromosome

The phage injects its DNA

Lytic cycle

The phage DNA circularizes

1

2

The cell lyses, releasing phages

4

New phage DNA and proteins are synthesized Phages assemble

(119)

Figure 10.17_s2

Phage Attaches

to cell

Phage DNA Bacterial

chromosome

The phage injects its DNA

Lytic cycle

The phage DNA circularizes

1

2

The cell lyses, releasing phages

4

New phage DNA and proteins are synthesized Phages assemble 3 OR Environmental stress Lysogenic cycle Many cell divisions

The lysogenic bacterium replicates normally

Prophage

Phage DNA inserts into the bacterial chromosome by recombination

5

7

(120)

The cell lyses, releasing phages Figure 10.17_1 Phage Attaches to cell Phage DNA

The phage injects its DNA

Lytic cycle

The phage DNA circularizes

1

New phage DNA and

proteins are synthesized

Phages assemble 2

3 4

Bacterial

(121)

Figure 10.17_2

Phage

Attaches to cell

Phage DNA Bacterial

chromosome

The phage injects its DNA

The phage DNA circularizes

Environmental

stress Many celldivisions

The lysogenic bacterium

replicates normally, copying the prophage at each cell division Prophage

Phage DNA inserts into the bacterial chromosome by recombination

(122)

10.18 CONNECTION: Many viruses cause

disease in animals and plants

Viruses can cause disease in animals and plants.

DNA viruses and RNA viruses cause disease in

animals.

A typical animal virus has a membranous outer

envelope and projecting spikes of glycoprotein.

The envelope helps the virus enter and leave the

host cell.

Many animal viruses have RNA rather than DNA as

their genetic material. These include viruses that

cause the common cold, measles, mumps, polio,

and AIDS.

(123)

10.18 CONNECTION: Many viruses cause

disease in animals and plants

The reproductive cycle of the mumps virus, a typical

enveloped RNA virus, has seven major steps:

1. entry of the protein-coated RNA into the cell,

2. uncoating—the removal of the protein coat,

3. RNA synthesis—mRNA synthesis using a viral enzyme,

4. protein synthesis—mRNA is used to make viral proteins,

5. new viral genome production—mRNA is used as a template to synthesize new viral genomes,

6. assembly—the new coat proteins assemble around the new viral RNA, and

7. exit—the viruses leave the cell by cloaking themselves in the host cell’s plasma membrane.

(124)

10.18 CONNECTION: Many viruses cause

disease in animals and plants

Some animal viruses, such as herpesviruses,

reproduce in the cell nucleus.

Most plant viruses are RNA viruses.

– To infect a plant, they must get past the outer protective layer of the plant.

– Viruses spread from cell to cell through plasmodesmata.

– Infection can spread to other plants by insects, herbivores, humans, or farming tools.

There are no cures for most viral diseases of plants

or animals.

© 2012 Pearson Education, Inc.

(125)

2

Figure 10.18

Viral RNA (genome)

Glycoprotein spike Protein coat Membranous envelope Entry CYTOPLASM Uncoating Plasma membrane of host cell

1 3 5 4 6 Protein synthesis Viral RNA (genome) RNA synthesis by viral enzyme

(126)

Figure 10.18_1

Viral RNA (genome)

Protein coat Membranous envelope

Entry CYTOPLASM

Uncoating Plasma

membrane of host cell

1

Viral RNA (genome)

RNA synthesis by viral enzyme

Glycoprotein spike

2

(127)

Figure 10.18_2

4

mRNA

New

viral proteins

Assembly

New viral genome

Template RNA synthesis (other strand)

Exit Protein

synthesis

6

(128)

10.19 EVOLUTION CONNECTION: Emerging

viruses threaten human health

Viruses that appear suddenly or are new to medical

scientists are called

emerging viruses

. These

include the

– AIDS virus,

– Ebola virus,

– West Nile virus, and

– SARS virus.

(129)

10.19 EVOLUTION CONNECTION: Emerging

viruses threaten human health

Three processes contribute to the emergence of

viral diseases:

1. mutation—RNA viruses mutate rapidly.

2. contact between species—viruses from other animals spread to humans.

3. spread from isolated human populations to larger human populations, often over great distances.

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(133)

10.20 The AIDS virus makes DNA on an RNA

template

AIDS

(acquired immunodeficiency syndrome) is

caused by

HIV

(human immunodeficiency virus).

HIV

– is an RNA virus,

has two copies of its RNA genome,

– carries molecules of reverse transcriptase, which causes reverse transcription, producing DNA from an RNA template.

(134)

Figure 10.20A

Envelope

Glycoprotein Protein coat

RNA

(two identical strands)

Reverse

(135)

After HIV RNA is uncoated in the cytoplasm of the

host cell,

1. reverse transcriptase makes one DNA strand from RNA,

2. reverse transcriptase adds a complementary DNA strand,

3. double-stranded viral DNA enters the nucleus and

integrates into the chromosome, becoming a provirus,

4. the provirus DNA is used to produce mRNA,

5. the viral mRNA is translated to produce viral proteins, and

6. new viral particles are assembled, leave the host cell, and can then infect other cells.

10.20 The AIDS virus makes DNA on an RNA

template

© 2012 Pearson Education, Inc.

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10.21 Viroids and prions are formidable

pathogens in plants and animals

Some infectious agents are made only of RNA or

protein.

Viroids are small, circular RNA molecules that infect plants. Viroids

– replicate within host cells without producing proteins and

– interfere with plant growth.

Prions are infectious proteins that cause degenerative brain diseases in animals. Prions

– appear to be misfolded forms of normal brain proteins,

– which convert normal protein to misfolded form.

(138)

10.22 Bacteria can transfer DNA in three ways

Viral reproduction allows researchers to learn more

about the mechanisms that regulate DNA replication

and gene expression in living cells.

Bacteria are also valuable but for different reasons.

– Bacterial DNA is found in a single, closed loop, chromosome.

– Bacterial cells divide by replication of the bacterial chromosome and then by binary fission.

– Because binary fission is an asexual process, bacteria in a colony are genetically identical to the parent cell.

(139)

10.22 Bacteria can transfer DNA in three ways

Bacteria use three mechanisms to move genes from

cell to cell.

1. Transformation is the uptake of DNA from the surrounding environment.

2. Transduction is gene transfer by phages.

3. Conjugation is the transfer of DNA from a donor to a recipient bacterial cell through a cytoplasmic (mating) bridge.

Once new DNA gets into a bacterial cell, part of it may

then integrate into the recipient’s chromosome.

(140)

Figure 10.22A

DNA enters cell

A fragment of DNA from another

bacterial cell

(141)

Figure 10.22B

Phage

A fragment of DNA from another

bacterial cell

(142)

Figure 10.22C

Mating bridge

Sex pili

(143)

Figure 10.22D

Donated DNA Crossovers Degraded DNA

Recombinant chromosome Recipient cell’s

(144)

10.23 Bacterial plasmids can serve as carriers for

gene transfer

The ability of a donor

E. coli

cell to carry out

conjugation is usually due to a specific piece of DNA

called the

F factor

.

During conjugation, the F factor is integrated into the

bacterium’s chromosome.

The donor chromosome starts replicating at the F

factor’s origin of replication.

The growing copy of the DNA peels off and heads

into the recipient cell.

The F factor serves as the leading end of the

transferred DNA.

(145)

Figure 10.23A-B

Donor F factor

(integrated)

Origin of F replication Bacterial chromosome

Recipient cell

F factor starts

replication and transfer of chromosome

Only part of the

chromosome transfers

Recombination can occur

The cell is now a donor The plasmid completes its transfer and circularizes

F factor (plasmid) Donor

Bacterial chromosome

F factor starts

(146)

Figure 10.23A

Donor F factor

(integrated)

Origin of F replication Bacterial chromosome

Recipient cell

F factor starts

replication and transfer of chromosome

Only part of the

chromosome transfers

(147)

10.23 Bacterial plasmids can serve as carriers for

gene transfer

An F factor can also exist as a

plasmid

, a small

circular DNA molecule separate from the bacterial

chromosome.

– Some plasmids, including the F factor, can bring about conjugation and move to another cell in linear form.

– The transferred plasmid re-forms a circle in the recipient cell.

R plasmids

– pose serious problems for human medicine by

– carrying genes for enzymes that destroy antibiotics.

(148)

Figure 10.23B

The cell is now a donor The plasmid completes its transfer and circularizes

F factor (plasmid) Donor

Bacterial chromosome

F factor starts

(149)

Figure 10.23C

(150)

1.

Describe the experiments of Griffith, Hershey,

and Chase, which supported the idea that DNA

was life’s genetic material.

2.

Compare the structures of DNA and RNA.

3.

Explain how the structure of DNA facilitates its

replication.

4.

Describe the process of DNA replication.

5.

Describe the locations, reactants, and products of

transcription and translation.

You should now be able to

(151)

6.

Explain how the “languages” of DNA and RNA

are used to produce polypeptides.

7.

Explain how mRNA is produced using DNA.

8.

Explain how eukaryotic RNA is processed

before leaving the nucleus.

9.

Relate the structure of tRNA to its functions in

the process of translation.

10.

Describe the structure and function of

ribosomes.

You should now be able to

(152)

11.

Describe the step-by-step process by which amino

acids are added to a growing polypeptide chain.

12.

Diagram the overall process of transcription and

translation.

13.

Describe the major types of mutations, causes of

mutations, and potential consequences.

14.

Compare the lytic and lysogenic reproductive

cycles of a phage.

15.

Compare the structures and reproductive cycles of

the mumps virus and a herpesvirus.

You should now be able to

(153)

16.

Describe three processes that contribute to the

emergence of viral disease.

17.

Explain how the AIDS virus enters a host cell and

reproduces.

18.

Describe the structure of viroids and prions and

explain how they cause disease.

19.

Define and compare the processes of

transformation, transduction, and conjugation.

20.

Define a plasmid and explain why R plasmids

pose serious human health problems.

You should now be able to

(154)
(155)

Figure 10.UN02

Growing polypeptide

Amino acid

tRNA

Anticodon

Small

ribosomal subunit Codons

mRNA Large

(156)

Figure 10.UN03

DNA

(b)

is a polymer made from monomers called

is performed by an

enzyme called (c) (a) (d) (e) (f) comes in three kinds called use amino-acid-bearing molecules called is performed by structures called (h) molecules are components of RNA Protein (g) (i) one or more polymers

(157)
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(159)

References

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