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Vol. 09, Issue 1 (January. 2019), ||V (II) || PP 55-60

On Some Double Integral Transform of Aleph

( )

-Function

Yashwant Singh

Department of Mathematics

Government College, Kaladera, Jaipur (Rajasthan), India Corresponding Author: Yashwant Singh

Abstract:

In the present paper , the author will establish a double integral transform of Aleph

-function which leads to yet another interesting process of augmenting the parameters in the

-function. The result is of general character and on specializing the parameters suitably yields several interesting results as particular cases.

Keywords:

-function, Euler Transformation,

H

-function, Hypergeometric Function, Integral

Transformation.

(2010 Mathematics subject classification: 33C99)

--- --- Date of Submission: 04-01-2019 Date of acceptance: 19-01-2019 ---

---I.

INTRODUCTION

Rainville [6, p.104], Abdul Halim and Al-Salam [1] have shown that the single and double Euler transformations of the hypergeometric function p

F

qare effective tools for augmenting its parameters. Srivastava and Singhal [9] and Srivastava and Joshi [10] have discussed some similar interesting properties of

p

F

qin double

H

-function and double Whittaker transforms respectively.

In what follows for the sake of brevity, we have used the symbols

( ,

a

r

r

), ( , ), ( ,

r a

 

r

a

), (( ,

r a

p

))

to

denote the set of parameters

( ,

a

1 1

),..., ( ,

a

r r

); ,

a a

1

,...,

a

r

1

; ( , ), ( ,

r a

r

a

)

r

r

r

 

 

and

1 2

( ,

r a

), ( ,

r a

),..., ( ,

r a

p

)

respectively.

The

- function introduced by Suland et.al. [11] defined and represented in the following form:

 

,

, : :

[ ]

i i i m n p q r

z

z



, 1, 1,

, ; :

1, 1,

(

,

) ,[ (

,

)]

( ,

)

,[ (

,

)]

i i i

i j j n i ji ji n p m n

p qi r

j j m i ji ji m q

a

a

z

b

b

 

1

( )

2

s

L

s z ds



(1.1)

Where

  

1

;

1 1

1 1 1

(

)

(1

)

( )

(1

)

(

i i

m n

j j j j

j j

q p

r

i ji ji ji ji

i j m j n

b

s

a

s

s

b

s

a

s

 

    

 

 

 

(1.2)

We shall use the following notation:

*

1, 1,

,

,[

,

]

i j j n i ji ji n p

A

a

a

, *

1,

1,

,

,[

,

]

i j j m i ji ji m q

B

b

b

*

1, 1,

,

,[

,

]

i j j f i ji ji f u

C

a

a

, *

1,

1,

,

,[

,

]

i j j g i ji ji g v

(2)

II.

MAIN RESULT

In this section, we have established the following double integral transform of

-function: If

s k

,

and

r

are positive integers, then

1 1 , * , *

, : : * , : : *

0 0

(

)

(

)

(

)

i i i i i i

f g C m n s k r A

u v r D p q r B

x

y

x

y

x

y

tx y x

y

dxdy

 

 



=

1 1

1 1

1

1 1 1 ( ) 2 2

(1 )

2 2 2 2

1 2

(2 )

(

)

v u

j j

d c A u v

D f g u v

s

k

D

s

k

 

    

   

 

    

 

   

 

1 1

( )

(( ,1 )), ( ,1 ), ( ,1 ), *, ( ,1 ),..., ( ,1 ) ,

, : : (( ,1 )), *, ( ,1 ), ( ,1 ),..., ( ,1 )

,

f f u

i i i i i g g v

D v u

D A D s k A D A d D A d

m Dg n Df

p Dv q Du r D D A C B k s D A c D A c

t D

 

    

 

               

                

(2.1)

Where

)

,

,

,

,

(

)

s k

s k

s k

s

k D

s

k

r A

s

k

 

  

  

  

0

Dg

Du

Dv

Du

 

q

p u

,

 

v

2

g

2

f

2 , 0

v

 

n

p p

,

 

q

2

n

2

m

2 ,

q

Re min

i ji

min

i ji

Re(

)

Re

,

,

l t

1

ji ji

d

b

s

k

D

A

D

a

C

D

s

k

 

1, 2,..., ;

1, 2,..., ;

1, 2,... ;

1, 2,..., ; , Re(min

i

)

,

i

f j

m l

n t

g u

C

A

v

1

Re max

1

(

), Re max

,

,

,

2

j

l j

d

s

k

A

uD v

D Dv

Du

D Dv

Du

a

s

k

 

 

1

1

1, 2,..., ;

1, 2,..., ;

1, 2,..., ;| arg

|

,

2

2

i

u j

v l

u

f

 

g

u

v

1

1

| arg |

, Re

0, Re

0,

1, 2,...,

2

2

ji ji

i i i

ji ji

b

b

t

m n

p

q

s

k

j

m

 

And the double integral converges.

Proof: To prove (2.1), we start with the following known result [2, p. 177]

1 1 1

0 0 0

(

x

y x

)

y

dxdy

B

( , )

( )

z z

 

dz

  

  

   



(2.2) Which is valid for

Re( )

0

and

Re( )

0

.

It is easy to prove by following the technique of reversing the order of integrations, that

1 1

2 2

1 1 , *

, : : * 1

0 0 2

(

)

(

)

2

(

)

i i i

m n s k r A

p q r B

s

k

x

y x

y

tx y x

y

dxdy

s

k

   

 

   

 

 



1 , ( ,1 ), ( ,1 ), *

, : : *, ( ,1 )

0

( )

i i i

m n D s k A

p q r B k s

z z

   

t z

 

dz

      

 

   

(2.3) Where

s k

,

and

r

are positive integers,

1

1

,

,

,

2(

),| arg |

,

(

)

2

2

s k

i i

s k

s k

s

k D

s

k

r p

q

m n

t

m n

p

q

s

k

 

  

 

 

Re

i ji

0, Re

i ji

0,

1, 2,..., .

ji ji

b

b

s

k

j

m

(3)

, *

, : : *

( )

i i i

f g C

u v r D

z

z

z

 

And evaluating the integral on the right hand side using [8, p.401] the result (2.1) follows.

III.

PARTICULAR CASES

On choosing the parameters suitably in (2.1), several known and unknown results are obtained as particular cases. However, we mention some of the interesting results here.

(a) Taking

1 1 2

1

1

2,

0,

1,

,

,

,

,

1,

1,

1

2

2

i j j j j i

f

 

v

g

u

c

d

v d

 

v

 

 

r

in (2.1) and using [3, p.216, (5)]

1,1 1 1

2,0 2 2 2

1,2 ( ,1),( ,1)

1

,

2

x

b b b

H

x

e

K

x

 

   

  

We obtain

1 1 ( )

1 1 2 2 , *

, *

0 0

1

(

)

(

)

(

)

2

x y m n s k r A

v p q B

x

y

x

y

a

K

x

y

H

tx y x

y

dxdy

 

 



=

1 1

1 1 1 1 2 2

(2 )

1

2 2 2 2

1 2

(2 )

(

)

D f g u v

A

s

k

D

s

k

 

    

 

 

      

 

   

, 2 (( ,1 )), ( ,1 ), ( ,1 ), *

2 , 1

*, (( , )), ( ,1 ) 2

,

D

m n D D A v s k A

p D q D D

B D A k s

t D

H

 

 

       

       

(3.1)

Where

,

D

and

have the same value as (2.1) and

1

;

2(

), Re(

)

0, Re(

)

0,

2

j j

j j

b

b

A

  

p

q

m n

s

v

s

v

   

 

 

 

1

1

1

Re

0,

1, 2,..., ; Re( )

0,| arg |

.

2

2

2

j

j

b

v

D

j

m

t

m n

p

q

  

   

 

(b) Further, replacing

q t

,

and

a

p

,

p

by

q

 

1,

t

and

1

a

p

,

p

respectively and then putting

1 1

1,

,

0,

j

1

j

(

1, 2,... )

m

n

p b

b

 

b j

q

, using the result [3,p. 215, (1)] and [3,p. 4, (11)], we obtain an interesting result obtained by Srivastava and Singhal [9]:

1 1

( ) ,

1 1 2 2

, 0 0

1

(

)

(

)

:

(

)

2

p p q q

x y a

s k r

v p q b

x

y

x

y

a

K

x

y

F

tx y x

y

dxdy

 

 



=

1 2

1

2

( , )

1

v

B

  

  

 

  

  

   

  

 

 

1

( , ,), ( , ), ( , ), ,1 2

3 3 2 2 2 ,1 , ( , ), ( , 1)

p

q s k r

s k r v s k a

p s k r q s k r b s k k s

s k

r

F

t

       

 

        

            

 

, (3.2)

provided

Re(

1

)

0, Re( )

0, Re( )

0.

2

v

  

   

(c) Setting

2,

0,

1,

1

1

,

1

1

,

2

1

,

1,

1

2

2

i

(4)

1 ,1 1

 

2,0 2

1,2 1 1 ,

( ,1),( ,1)

2 2

,

x k

k m

m m

H

x

e

W

x

 

We have

1 ( )

1 1 2 , *

, , *

0 0

(

)

x y v

[ (

)]

p qm n s k

(

)

r BA

x

y

x

y

e

W

x

y H

tx y x

y

dxdy

 

 



=

1 1

1 1 2 2

(2 )

2 2

1 2

(2 )

(

)

D A

s

k

D

s

k

  

    

    

   

1

( , ), ( ,1 ), ( ,1 ), *

, 2 2

2 , *, ( ,1 ), ( , )

,

D

D A v s k A

m n D

p D q D D B k s D A

t D

H

 

        

         

(3.3) Where

, ,

D

 

and

A

are given in (2.1);

1

1

2(

),| arg |

, Re( )

0, Re(

0,

2

2

j

p

 

q

m n

t

m n

 

p

q

sb

1

Re(

)

0, Re

0,

1, 2,..., .

2

j j

k

sb

m n

  

Db

 

v

j

m

(d) Further, replacing

q t

,

and

a

p

,

p

by

q

 

1,

t

and

(1

a

p

,

p

)

respectively and then putting

1 1

1,

,

0,

j

1

j

(

1, 2,..., )

m

n

p b

b

 

b j

q

and using the result [p.215,(1)], (3.3) reduces to a result due to Srivastava and Joshi [10,p.19,(2.3)]

1

( ) ,

1 1 2

, ,

0 0

(

)

(

)

p p

:

(

)

q q

x y a s k r

v p q b

x

y

x

y

e

W

x

y

F

tx y x

y

dxdy

 

 



=

1

2

( , )

1

v

B

  

  

 

 

   

   

   

 

 

1

( , ,), ( , ), ( , ), ,1

' 2

3 3 2 2 2 ,1 , ( , ), ( , 1)

p

q

s k r v s k a

p s k r

F

q s k r

t

b s k k s r

          



        

               

(3.4)

Where

'

,

(

)

s k r s k

s k

s k

s

k

r

s

k

 

 

 

1

Re( )

0, Re( )

0, Re( )

0, Re

0

2

v

  

   

and the resulting hypergeometric series converges.

With

0,

1

2

v

 

and

1

2

 

,(3.4) reduces to the earlier results of Jain [5] and Singh [7].

(e) Choosing

1 1 2

1

1

1,

2,

1

,

,

,

1,

1,

1

2

2

j j j j i

(5)

1 ,1 1

 

1,1 2

1,2 1 1 ,

( ,1),( ,1)

2 2

1

2

,

(2

1)

x k

k m

m m

k

m

H

x

e

M

x

m

 

 

 

We obtain

1 ( )

1 1 2 , *

, , *

0 0

(

)

x y k m

[ (

)]

p qm n s k

(

)

r AB

x

y

x

y

e

M

x

y H

tx y x

y

dxdy

 

 



=

1 1

1 1 2 2

(2 )

2 2

1 2

(2

1)

(2 )

1

(

)

2

D k A

m

s

k

D

k

m

s

k

      

    

   

 

1 1

( , ), ( ,1 ), ( ,1 ), ( , )

, 2 2

2 , ( ,1 ), ( , )

,

D

D A m s k D A m

m D n D

p D q D D k s D k A

t D

H

   

            

         

(3.5) Where

, ,

D

 

and

A

are given in (2.1);

1

1

2(

),| arg |

, Re( )

0, Re(

)

0,

2

2

j

p

 

q

m n

t

m n

 

p

q

sb

1

Re(

)

0, Re

0,

1, 2,..., .

2

j j

kb

Db

m

j

m

  

  

 

(f) Substituting

1,

0,

2,

1

1

,

2

1

,

1,

1

2

2

i

f

g

 

u

v

d

v d

 

v

r

and using the result [3,p.216,(3)]

1,0

0,2 1 1

,1 , ,1

2 2

(2

)

v

v v

H

x

 

J

x

       

,

(2.1) reduces to

1 1 , *

, *

0 0

(

)

(2

(

)

m n s k A

v p q B

x

y

x

y J

x

y H

tx y

dxdy

 

 



=

1 1

2 1 2 2

1 2

2

(

)

A

D

s

k

s

k

 

    

  

   

1 1

,1 , ( ,1 ), ( ,1 ), *, ,1

, 2 2

2 , *, ( ,1 )

D

D A v s k A D A v

m n D

p D q p B k s

D

H

t

  

 

   

          

     

      

 

 

 

(3.6)

Where

, ,

D

and

A

have the same values given in (2.1);

1

1

2(

),| arg |

, Re( )

0, Re(

)

0,

2

2

j

p

 

q

m n

t

m n

 

p

q

sb

1

Re(

)

0, Re

0,

1, 2,..., ;

2

j j

kb

v

Db

j

m

  

  

1

Re

, ,

1, 2,..., .

4

i

D

Da

i

n

  

   

(6)

International organization of Scientific Research

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REFERENCES

[1]. Abdul-Halim,N. and Al-Salam, W.A.; Double Euler transformation of certain hypergeometric functions, Duke Math. J., 30(1963), 51-62.

[2]. Edwards, J.; A Treatise on Integral Calculus, Chelsea, New York (1954).

[3]. Erdelyi, A. et. al. ; Higher Transcendental Functions, vol. I, McGraw-Hill, New York (1953).

[4]. Fox, C.; The G and H function as symmetric Fourier kernels Trans. Amer. Math. Soc. 98 , 1961 , 395-429.

[5]. Jain, R.N.; Some double integral transformations of certain hypergeometric functions, Math. Japon, 10(1965), 17-26.

[6]. Rainville, E.D.; Special Functions, Macmillan, New York (1960).

[7]. Singh, R.P.; A note on double transformation of certain hypergeometric functions, Proc. Edinburgh. Math. Soc. (2),1491965), 221-227.

[8]. Saxena, R.K.; Some theorems on generalized Laplace transforms, Proc. Nat. Inst. Sc. India, 26 A(1960), 400-413.

[9]. Srivastava, H.M. and Singhal, J.P.; Double Meijer’s transformation of certain hypergeometric functions, Proc. Camb. Phil. Soc. 64(1968).

[10]. Srivastava, H.M. and Joshi, C.M.; Certain Double Whittaker transforms of generalized hypergeometric functions, The Yokohama Mathematical Journal, vol. XV, (1) (1967), 17-32.

[11]. Sudland, N., Baumann, B. and Nonnenmacher, T.F.; Open problem: who knows about the Aleph(

)-functions? Frac. Calc. Appl. Annl. 1(4),(1998), 401-402.

Yashwant Singh. “On Some Double Integral Transform of Aleph

( )

-Function.” IOSR Journal

of Engineering (IOSRJEN), vol. 09, no. 01, 2019, pp. 55-60.

References

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