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R E S E A R C H

Open Access

Attractivity for a

k

-dimensional system of

fractional functional differential equations

and global attractivity for a

k

-dimensional

system of nonlinear fractional differential

equations

Dumitru Baleanu

1,2,3*

, Sayyedeh Zahra Nazemi

4

and Shahram Rezapour

4

*Correspondence:

[email protected]

1Department of Mathematics,

Cankaya University, Ogretmenler Cad. 14, Balgat, Ankara, 06530, Turkey

2Institute of Space Sciences,

Magurele, Bucharest, Romania Full list of author information is available at the end of the article

Abstract

In this paper, we present some results for the attractivity of solutions for a

k-dimensional system of fractional functional differential equations involving the

Caputo fractional derivative by using the classical Schauder’s fixed-point theorem.

Also, the global attractivity of solutions for ak-dimensional system of fractional

differential equations involving Riemann-Liouville fractional derivative are obtained by using Krasnoselskii’s fixed-point theorem. We give two examples to illustrate our main results.

1 Introduction

In recent years, many researchers have been focused on investigation of fractional dif-ferential equations which has played an important role in different areas of science (see for example, [–] and the references therein). As you know, there are many practical applications of fractional differential equations in different fields of science such as econ-omy, biology, and the study of forced van der Pol oscillators (see for example, [–] and the references therein). On the other hand, there are a few papers on the attractiv-ity of solutions for fractional differential equations and fractional functional differential equations (see for example, [] and []). For the details of basic notions of this paper such the standard Caputo fractional derivative, the standard Riemann-Liouville fractional derivative, and the fractional integral of orderqfor a functionf see []. In , Chen and Zhou reviewed the attractivity of solutions for the fractional functional differential equationcDαx(t) =f(t,x

t) fort∈(t,∞) via the boundary value conditionx(t) =φ(t) for

t–rtt, wheret≥,r> ,  <α< ,cDis the standard Caputo fractional derivative, φC([t–r,t],R) andf : (t,∞)×C([–r, ],R)→Ra function with some properties []. In , Chenet al.reviewed the global attractivity of solutions for the nonlinear fractional differential equationx(t) =g(t,x(t)) fort(t,) via the boundary value

problem [–x(t)]

t=t=x, where t≥,  <α< ,xis a constant,Dis the standard

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problemx(t) =x, wheret≥,  <α< ,xis a constant,cDis the standard Caputo frac-tional derivative, andg: (t,∞)×R→Ra function with some properties [].

In this paper, we investigate the attractivity of solutions for ak-dimensional system of fractional differential equations. Also, we investigate the global attractivity of solutions for anotherk-dimensional system of nonlinear fractional differential equations.

2 Preliminaries

In this paper, we investigate the attractivity of solutions fork-dimensional system of frac-tional funcfrac-tional differential equations

⎧ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎩

cDαx(t) =f(t,x

t,xt, . . . ,xkt),

cDαx(t) =f(t,x

t,xt, . . . ,xkt), ..

.

cDαkx

k(t) =fk(t,xt,xt, . . . ,xkt),

(.)

via the boundary value problems x(t) =φ(t),x(t) =φ(t), . . . ,xk(t) =φk(t) for t–r

tt, where  <αi<  fori= , , . . . ,k,t≥,t∈(t,∞), cDis the standard Caputo fractional derivative,J= (t,∞),r> ,φiC([t–r,t],Rn) fori= , , . . . ,kandfi:J×

C([–r, ],Rn)×C([–r, ],Rn)× · · · ×C([–r, ],Rn)Rn is a function satisfying some

assumptions that will be specified later fori= , , . . . ,k. IfxC([t–r,∞),Rn), thenxt

is defined byxt(θ) =x(t+θ) for –rθ≤ andt∈[t,∞). Also, we investigate the global

attractivity of solutions for thek-dimensional system of nonlinear fractional differential equations

⎧ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎩

x(t) =g(t,x(t),x(t), . . . ,x

k(t)),

x(t) =g(t,x

(t),x(t), . . . ,xk(t)),

.. .

Dαkx

k(t) =gk(t,x(t),x(t), . . . ,xk(t)),

(.)

via the boundary value problems [–x

(t)]t=t =x

, [–x(t)]t=t=x

, . . . , [Dαk–×

xk(t)]t=t =x

k, where  <αi<  fori= , , . . . ,k,t≥,t∈(t,∞),Dis the Riemann-Liouville fractional derivative,J= (t,∞),x, . . . ,xk are constants, andgi:J×Rn×Rn×

· · · ×RnRnis an integrable function satisfying some assumptions that will be specified

later fori= , , . . . ,k. In fact, we say that the solution (x(t),x(t), . . . ,xk(t)) of the problem

(.) is attractive whenever if there exists a constantb

i(t) >  such that|φi(s)| ≤bi for all

i= , , . . . ,kands∈[t–r,t], thenlimt→∞xi(t,t,φi)→. Also, the zero solutionx(t) of

the problem (.) is said to be globally attractive whenever each solution tends to zero as

t→ ∞. LetX=C(J,Rn) be the Banach space of all continuous functions fromJintoRn

with the normx=suptJ|x(t)|, where| · |denotes a suitable complete norm onRn. It is

clear that the product space (Xk=X×X× · · · ×X

k

, · ∗) is also a Banach space, where

(x,x, . . . ,xk)∗=x+x+· · ·+xk. We need the following Schauder fixed-point

theorem and improvement of a fixed-point theorem of Krasnoselskii due to Burton, which one can find in [, ] and [].

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Theorem . Let S be a nonempty,closed,convex,and bounded subset of the Banach space X,A:XX a contraction with constant l< ,B:SX a continuous map which B(S)

resides in a compact subset of X and x=Ax+By and yS implies xS.Then the operator equation Ax+Bx=x has a solution in S.

3 Main results

First, we investigate attractive solutions of the problem (.). In this way, suppose that

xt=sup–rθ≤|x(t+θ)|fortJ. We assume thatfi(t,xt,xt, . . . ,xkt) is Lebesgue mea-surable with respect toton [t,∞) andfi(t,ϕ,ϕ, . . . ,ϕk) is continuous with respect toϕj

onC([–r, ],Rn) fori,j= , , . . . ,k. Note that the problem (.) is equivalent to the system

of equations

xi(t) =

φi(t) +(α

i) t

t(ts) αi–f

i(s,xs,xs, . . . ,xks)ds, t>t,

φi(t), t∈[t–r,t]

or

xi(t) =

(αi) t

t(ts)

αi–[ φi(t)

(–αi)(st)–

αi+f

i(s,xs,xs, . . . ,xks)]ds, t>t,

φi(t), t∈[t–r,t]

fori= , , . . . ,k. Define the operatorT:XkXkby

T(x,x, . . . ,xk)(t) =

⎛ ⎜ ⎜ ⎜ ⎜ ⎝

T(x,x, . . . ,xk)(t)

T(x,x, . . . ,xk)(t)

.. .

Tk(x,x, . . . ,xk)(t)

⎞ ⎟ ⎟ ⎟ ⎟ ⎠,

where

Ti(x,x, . . . ,xk)(t) =

φi(t) +(αi) t

t(ts) αi–f

i(s,xs,xs, . . . ,xks)ds, t>t,

φi(t), t∈[t–r,t]

fori= , , . . . ,k. It is easy to check that (x(t),x(t), . . . ,xk(t)) is a solution of the problem

(.) if and only if (x(t),x(t), . . . ,xk(t)) is a fixed point of the operatorT.

Theorem . Suppose that for each i∈ {, , . . . ,k}there existγi> andαi∈(,αi)such

that

φi(t) +

(αi)

t t

(ts)αi–f

i(s,xs,xs, . . . ,xks)ds

≤(tt)–γi

for all tJ and fiL

αi(J×C([–r, ],Rn)×C([–r, ],Rn)× · · · ×C([–r, ],Rn),Rn).Then

the problem(.)has at least one attractive solution(x,x, . . . ,xk)such that xiC([t–

r,∞),Rn)for all i= , , . . . ,k.

Proof Consider the set

S=

(x,x, . . . ,xk) :xiC

[t–r,∞),Rn

,xi(t)≤(tt)–γi

for alli= , , . . . ,kandt≥ ˜t>t

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where t˜ is a constant. It is easy to check that S is a closed, bounded, and convex subset of Rn×Rn× · · · ×Rn

k

. We show that the operator T has a fixed point in S.

This implies that the problem (.) has a solution. Note that |Ti(x,x, . . . ,xk)(t)| ≤(t

t)–γifor all i= , , . . . ,k and so T(S)S. Now, we show that T is continuous. Let

(xm

,xm, . . . ,xmk), (x,x, . . . ,xk)∈ S for all m≥ and limm→∞|xim(t) –xi(t)|=  for all

i= , , . . . ,k. Then, we have limm→∞fi(t,xmt,xmt, . . . ,xmkt) =fi(t,xt,xt, . . . ,xkt) for all i= , , . . . ,k and t>t. Let >  be given. Choose T˜ >t such that t≥ ˜T implies that (tt)–γi<

. Letνi=

αi–

–αi and note that  +νi>  fori= , , . . . ,k. Also, we have

Ti

xm,xm, . . . ,xmk(t) –Ti(x,x, . . . ,xk)(t)

≤ 

(αi)

t t

(ts)αi–fi

s,xms,xms, . . . ,xmksfi(s,xs,xs, . . . ,xks)ds

≤ 

(αi)

t

t

(ts)αi––αids

–αi

× t

t

fi

s,xms,xms, . . . ,xmksfi(s,xs,xs, . . . ,xks)

αids αi

≤ 

(αi)

  +νi

(tt)

+νi–αi

×

˜

T t

fi

s,xms,xms, . . . ,xmksfi(s,xs,xs, . . . ,xks)

αids αi

≤ 

(αi)

  +νi

(T˜ –t)

+νi–αi

(T˜ –t)αi

× sup

t≤s≤ ˜T

fi

s,xms,xms, . . . ,xmksfi(s,xs,xs, . . . ,xks)

for t<t≤ ˜T. Thus,limm→∞|Ti(xm,xm, . . . ,xmk)(t) –Ti(x,x, . . . ,xk)(t)|=  for all t<

t≤ ˜T. Also, we have Ti

xm,xm, . . . ,xmk(t) –Ti(x,x, . . . ,xk)(t)

= 

(αi)

t t

(ts)αi–f

i

s,xms,xms, . . . ,xmksds

– 

(αi)

t t

(ts)αi–fi(s,xs,xs, . . . ,xks)ds

≤(tt)–γi≤

fort>T˜. Hence,limm→∞|Ti(xm,xm, . . . ,xkm)(t) –Ti(x,x, . . . ,xk)(t)|=  fort>t. This

im-plies thatTiis continuous fori= , , . . . ,kand soTis continuous. Now, we show that the

setT(S) is equi-continuous. Let> . Sincelimt→∞(tt)–γi=  fori= , , . . . ,k, there is aT˜>tsuch that (tt)–γi< for allt>T˜andi= , , . . . ,k. Lett,t>tandt>t. Ift,t∈(t,T˜], then

Ti(x,x, . . . ,xk)(t) –Ti(x,x, . . . ,xk)(t)

≤ 

(αi)

t

t

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–  (αi)

t

t

(t–s)αi–fi(s,xs,xs, . . . ,xks)ds

≤ 

(αi)

t

t

(t–s)αi–– (t–s)αi–fi(s,xs,xs, . . . ,xks)ds

+ 

(αi)

t

t

(t–s)αi–fi(s,xs,xs, . . . ,xks)ds

≤ 

(αi)

t

t

(t–s)αi–– (t–s)αi–

–αids

–αi

×

t

t

fi(s,xs,xs, . . . ,xks)

αids

αi

+ 

(αi)

t

t

(t–s) αi– –αids

–αit

t

fi(s,xs,xs, . . . ,xks)

αids αi

≤ 

(αi)

  +νi

–αi

(t–t) αi–

–αi++ (t –t)

αi–

–αi+– (t –t)

αi–

–αi+–αi

×

T˜

t

fi(s,xs,xs, . . . ,xks)

αids

αi

+ 

(αi)

  +νi

–αi

(t–t) αi– –αi+–αi

T˜

t

fi(s,xs,xs, . . . ,xks)

αids

αi

≤ 

(αi)

  +νi

–αiT˜ t

fi(s,xs,xs, . . . ,xks)

αids

αi

(t–t)αi–αi

and solimt→t|Ti(x,x, . . . ,xk)(t) –Ti(x,x, . . . ,xk)(t)|= . Ift,t>T˜, then

Ti(x,x, . . . ,xk)(t) –Ti(x,x, . . . ,xk)(t)

= 

(αi)

t

t

(t–s)αi–fi(s,xs,xs, . . . ,xks)ds

– 

(αi)

t

t

(t–s)αi–fi(s,xs,xs, . . . ,xks)ds

≤(t–t)–γi+ (t–t)–γi≤.

Now, lett<t<T˜<t. Since

Ti(x,x, . . . ,xk)(t) –Ti(x,x, . . . ,xk)(t)

Ti(x,x, . . . ,xk)(t) –Ti(x,x, . . . ,xk)

˜

T

+Ti(x,x, . . . ,xk)

˜

TTi(x,x, . . . ,xk)(t),

we getlimt→t|Ti(x,x, . . . ,xk)(t) –Ti(x,x, . . . ,xk)(t)|=  in all cases. This implies that

the setT(S) is equi-continuous. SinceT(S)⊂Sis uniformly bounded,T(S) is relatively compact. Now by using Theorem .,T has a fixed point inSwhich is a solution of the problem (.). Sincex(t) = (x(t),x(t), . . . ,xk(t))∈S,limt→∞x(t) = . Thus,x(t) is an

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Theorem . Suppose that for each i∈ {, , . . . ,k} there existγi> ,αi∈(,αi)and

liL

αi(J,R+)such that(αi)

t t(t–s)

αi–l

i(s)(st)–γids≤(tt)–γiand

φi(t)

( –αi)

(tt)–αi+f

i(t,xt,xt, . . . ,xkt)

li(t)xit

for all i= , , . . . ,k,tJ and xiC([t–r,∞),Rn).Then the problem(.)has at least one

attractive solution(x,x, . . . ,xk)such that xiC([t–r,∞),Rn)for all i= , , . . . ,k.

Proof It is sufficient we consider the set

S=

(x,x, . . . ,xk) :xiC

[t–r,∞),Rn

,xit ≤(tt) –γi

for alli= , , . . . ,kandt≥ ˜t>t

,

where˜tis a constant. By using a similar techniques and proof in Theorem ., one can show that T(S)⊂S, T is continuous andT(S) is relatively compact. Now by using Theorem ., T has a fixed point inS which is a solution of the problem (.). Since

x(t) = (x(t),x(t), . . . ,xk(t))∈S,limt→∞x(t) = . Thus,x(t) is an attractive solution for

the problem (.).

Theorem . Suppose that for each i∈ {, , . . . ,k}there existsβi∈(αi, )such that

φi(t)

( –αi)

(tt)–αi+f

i(t,xt,xt, . . . ,xkt)

( +αiβi)

( –βi)

(tt)–βi

for all tJ.Then the problem(.)has at least one attractive solution(x,x, . . . ,xk)such

that xiC([t–r,∞),Rn)for all i= , , . . . ,k.

Proof It is sufficient we consider the set

S=

(x,x, . . . ,xk) :xiC

[t–r,∞),Rn

,xi(t)≤(tt)βi–αi

for alli= , , . . . ,kandt≥ ˜t>t

,

where˜tis a constant. By using a similar techniques and proof in Theorem ., one can show that T(S)⊂S,T is continuous and T(S) is relatively compact. Now, by using Theorem ., T has a fixed point inS which is a solution of the problem (.). Since

x(t) = (x(t),x(t), . . . ,xk(t))∈S,limt→∞x(t) = . Thus,x(t) is an attractive solution for

the problem (.).

Here, we are going to investigate global attractivity of solutions of the problem (.). We assume thatgi(t,x(t),x(t), . . . ,xk(t)) is Lebesgue measurable with respect toton [t,∞) and there exists a constantαi∈(,αi) such thatgiL

αi(J×Rn×Rn× · · · ×Rn,Rn) and

gi(t,x(t),x(t), . . . ,xk(t)) is continuous with respect toxjon [t,∞) for alli,j= , , . . . ,k.

Note that the problem (.) is equivalent to the system of equations

xi(t) =

xi

(αi)

(tt)αi–+  (αi)

t t

(ts)αi–gi

s,x(s),x(s), . . . ,xk(s)

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for allt>tandi= , , . . . ,k. Define the operatorT:XkXkby

T(x,x, . . . ,xk)(t) =

⎛ ⎜ ⎜ ⎜ ⎜ ⎝

T(x,x, . . . ,xk)(t)

T(x,x, . . . ,xk)(t)

.. .

Tk(x,x, . . . ,xk)(t)

⎞ ⎟ ⎟ ⎟ ⎟ ⎠,

where

Ti(x,x, . . . ,xk)(t) =

x

i

(αi)

(tt)αi–+  (αi)

t t

(ts)αi–gi

s,x(s),x(s), . . . ,xk(s)

ds

for alli= , , . . . ,k. Now, define

A(x,x, . . . ,xk)(t) =

⎛ ⎜ ⎜ ⎜ ⎜ ⎝

A(x,x, . . . ,xk)(t)

A(x,x, . . . ,xk)(t)

.. .

Ak(x,x, . . . ,xk)(t)

⎞ ⎟ ⎟ ⎟ ⎟ ⎠,

whereAi(x,x, . . . ,xk)(t) = xi

(αi)(tt)

αi–for alli= , , . . . ,k. Finally, define

B(x,x, . . . ,xk)(t) =

⎛ ⎜ ⎜ ⎜ ⎜ ⎝

B(x,x, . . . ,xk)(t)

B(x,x, . . . ,xk)(t)

.. .

Bk(x,x, . . . ,xk)(t)

⎞ ⎟ ⎟ ⎟ ⎟ ⎠,

whereBi(x,x, . . . ,xk)(t) =(αi) t

t(ts) αi–g

i(s,x(s),x(s), . . . ,xk(s))dsfor alli= , , . . . ,k.

It is easy to check that (x(t),x(t), . . . ,xk(t)) is a solution of the problem (.) if and only if

it is a fixed point of the operatorT. Note thatAis a contraction with constant .

Theorem . Suppose that for each i∈ {, , . . . ,k}there existαi<βi< and Mi≥such

that|gi(t,x(t),x(t), . . . ,xk(t))| ≤Mi(tt)–β

ifor all tJ and x, . . . ,xkC((t,),Rn). Then the zero solution of the problem(.)is globally attractive.

Proof Consider the set

S=(x,x, . . . ,xk) :xiC

(t,∞),Rn,xi(t)≤(tt)–γ

i

for alli= , , . . . ,kandtt+T˜

,

whereγi=(βiαi) andT˜is chosen such that

|xi|

(αi)T˜

 (αi–)

 +

Mi(–βi) (+αi–βi)T˜

–(βiαi)

 ≤ for

alli= , , . . . ,k. First, we show thatBmapsSintoS. It is easy to check thatSis a closed, bounded, and convex subset ofRn×Rn× · · · ×Rn. Note that

Bi(y,y, . . . ,yk)(t)

≤ 

(αi)

t t

(ts)αi–gi

(8)

≤ 

(αi)

t t

(ts)αi–Mi(st)–β

ids

Mi( –βi) ( +αiβi)

(tt)–(βi–αi)

and Mi(–βi) (+αiβi)(tt)

–(βiαi) Mi(–βi) (+αiβi) ˜ T

 (βi–αi)

 ≤ for alli= , , . . . ,kandtt+T˜. Thus,

Bi(y,y, . . . ,yk)(t)≤

Mi( –βi) ( +αiβi)

(tt)–(βi–αi)

(tt)–(βi–αi)(tt)γi

for alli= , , . . . ,kandtt+T˜. Hence,B(S)⊂S. Now, we show thatBis continuous on [t+T˜,∞). Let (ym,ym, . . . ,ymk), (y,y, . . . ,yk)∈S for allm≥ andlimm→∞|ymi (t) –

yi(t)|= . Then, one can getlimm→∞gi(t,ym(t),ym(t), . . . ,ymk(t)) =gi(t,y(t),y(t), . . . ,yk(t))

for alltt+T˜. Let>  be given. ChooseT˜ >t+T˜such that Mi

(–βi)

(+αi–βi)(T˜–t)

–(βiαi)<

 for allt>T˜. Letνi=

αi–

–αi fori= , , . . . ,k. Then, we have

Bi

ym,ym, . . . ,ymk(t) –Bi(y,y, . . . ,yk)(t)

≤ 

(αi)

t t

(ts)αi–gi

s,ym(s),ym(s), . . . ,ymk(s)–gi

s,y(s),y(s), . . . ,yk(s)ds

≤ 

(αi)

t

t

(ts)αi–

 –αi

ds

–αi

×

t

t

gi

s,ym(s),ym(s), . . . ,ymk(s)–gi

s,y(s),y(s), . . . ,yk(s)

αids αi

≤ 

(αi)

 +νi(tt) +νi

–αi

×

T˜

t

gi

s,ym(s),ym(s), . . . ,ymk(s)–gi

s,y(s),y(s), . . . ,yk(s)

αids αi

≤ 

(αi)

 +νi(T˜ –t) +νi

–αi

(T˜ –t)αi

× sup

t≤s≤ ˜T

gi

s,ym(s),ym(s), . . . ,ymk(s)–gi

s,y(s),y(s), . . . ,yk(s)

for allt+T˜≤t≤ ˜T. Hence,limm→∞|Bi(ym,ym, . . . ,ymk)(t) –Bi(y,y, . . . ,yk)(t)|=  for all

t+T˜≤t≤ ˜T. Also,

Bi

ym,ym, . . . ,ymk(t) –Bi(y,y, . . . ,yk)(t)

≤ 

(αi)

t t

(ts)αi–gi

s,ym(s),ym(s), . . . ,ymk(s)–gi

s,y(s),y(s), . . . ,yk(s)ds

≤ 

(αi)

t t

(ts)αi–gi

s,ym(s),ym(s), . . . ,ymk(s)+gi

s,y(s),y(s), . . . ,yk(s)ds

≤ 

(αi)

t t

(ts)αi–Mi(st)–β

(9)

≤ Mi( –βi) ( +αiβi)

(tt)–(βi–αi)

≤ Mi( –βi) ( +αiβi)

(T˜ –t)–(β

i–αi)

for allt>T˜. Thus,limm→∞|Bi(ym,ym, . . . ,ymk)(t) –Bi(y,y, . . . ,yk)(t)|=  for alltt+T˜. This implies thatBiis continuous on [t+T˜,∞) fori= , , . . . ,kand soBis continuous on [t+T˜,∞). Now, we show thatB(S) is equi-continuous. Let >  be given. Since limt→∞(tt)–γi= , there existsT˜>t+T˜ such that (tt)γi<

 fort>T˜. Let

t,t≥t+T˜andt>t. Ift,t∈[t+T˜,T˜], then we have Bi(y,y, . . . ,yk)(t) –Bi(y,y, . . . ,yk)(t)

= 

(αi)

t

t

(t–s)αi–gi

s,y(s),y(s), . . . ,yk(s)

ds

– 

(αi)

t

t

(t–s)αi–gi

s,y(s),y(s), . . . ,yk(s)

ds

≤ 

(αi)

t

t

(t–s)αi–– (t–s)αi–gi

s,y(s),y(s), . . . ,yk(s)ds

+ 

(αi)

t

t

(t–s)αi–gi

s,y(s),y(s), . . . ,yk(s)ds

≤ 

(αi)

t

t

(t–s)αi–– (t–s)αi–

–αi

ds

–αi

× t

t

gi

s,y(s),y(s), . . . ,yk(s)

αi

ds

αi

+ 

(αi)

t

t

(t–s) αi– –αi

ds

–αi t

t

gi

s,y(s),y(s), . . . ,yk(s)

αi

ds

αi

≤ 

(αi)

  +νi

–αi

(t–t)+ν

i– (tt)+νi+ (tt)+νi–α

i

×

T˜

t

gi

s,y(s),y(s), . . . ,yk(s)

αi

ds

αi

+ 

(αi)

  +νi

–αi

(t–t)+ν

i–α

i

T˜

t

gi

s,y(s),y(s), . . . ,yk(s)

αi

ds

αi

≤ 

(αi)

  +νi

–αi T˜ t

gi

s,y(s),y(s), . . . ,yk(s)

αi

ds

αi

(t–t)αi–α

i

and solimtt|Bi(y,y, . . . ,yk)(t) –Bi(y,y, . . . ,yk)(t)|= . Ift,t>T˜, then Bi(y,y, . . . ,yk)(t) –Bi(y,y, . . . ,yk)(t)

≤ 

(αi)

t

t

(t–s)αi–gi

s,y(s),y(s), . . . ,yk(s)ds

+ 

(αi)

t

t

(t–s)αi–gi

s,y(s),y(s), . . . ,yk(s)ds

≤(t–t)–γ

(10)

Ift+T˜≤t<T˜<t, then we have

Bi(y,y, . . . ,yk)(t) –Bi(y,y, . . . ,yk)(t)

Bi(y,y, . . . ,yk)(t) –Bi(y,y, . . . ,yk)

˜

T

+Bi(y,y, . . . ,yk)

˜

TBi(y,y, . . . ,yk)(t)

and solimt→t|Bi(y,y, . . . ,yk)(t) –Bi(y,y, . . . ,yk)(t)|= . Thus,B(S) is equi-contin-uous. Since B(S)⊂S is uniformly bounded, B(S) is relatively compact. Now, sup-pose that x= (x,x, . . . ,xk)∈C((t,∞),RnC((t,∞),Rn)× · · · ×C((t,∞),Rn),y=

(y,y, . . . ,yk)∈Sandx=Ax+By. Then,

xi(t)≤Ai(x,x, . . . ,xk)(t)+Bi(y,y, . . . ,yk)(t)

≤ |xi|

(αi)

(tt)αi–+  (αi)

t t

(ts)αi–gi

s,y(s),y(s), . . . ,yk(s)ds

≤ |xi|

(αi)

(tt)αi–+ Mi( –β

i) ( +αiβi)

(tt)–(βi–αi)

for alli= , , . . . ,k. Since  <αi<βi<  fori= , , . . . ,k, we get

|x

i|

(αi)

(tt)(αi–)+ Mi( –β

i) ( +αiβi)

(tt)–(βi–αi)

≤ |xi|

(αi)

˜ T  (αi–)

 +

Mi( –βi) ( +αiβi)

˜ T

 (βi–αi)

 ≤.

Thus, |xi(t)| ≤[

|xi|

(αi)(tt)

(αi–)+ Mi(–β

i) (+αi–βi)(tt)

–(βiαi)](tt )–γ

i ≤(tt)–γi for

alltt+T˜ andi= , , . . . ,k. This implies thatx(t) = (x(t),x(t), . . . ,xk(t))∈S for all

tt+T˜. Therefore, by using Theorem .Thas a fixed point inSwhich is a solution of the problem (.). Since all elements of the setStend to  ast→ ∞, the zero solution

of the problem (.) is globally attractive.

Theorem . Suppose that for each i∈ {, , . . . ,k} there existαi<βi < ( +αi)and

li≥such that|gi(t,x(t),x(t), . . . ,xk(t))| ≤li(tt)–β

i|xi(t)|for all tJ and x, . . . ,xkC((t,∞),Rn).Then the zero solution of the problem(.)is globally attractive.

Proof It is sufficient to consider the set

S=(x,x, . . . ,xk) :xiC

(t,∞),Rn,xi(t)≤(tt)–γ

i

for alli= , , . . . ,kandtt+T˜

,

whereγi=( –αi) andT˜is chosen such that |

xi|

(αi)T˜

 (αi–)

 +

li(–βi–γi) (+αi–βiγi)T˜

(11)

· · · ×C((t,∞),Rn),y= (y,y, . . . ,y

k)∈Sandx=Ax+By. Then, xi(t)≤Ai(x,x, . . . ,xk)(t)+Bi(y,y, . . . ,yk)(t)

≤ |xi|

(αi)

(tt)αi–+  (αi)

t t

(ts)αi–g

i

s,y(s),y(s), . . . ,yk(s)ds

≤ |xi|

(αi)

(tt)αi–+  (αi)

t t

(ts)αi–l

i(st)–β

iy

i(s)ds

≤ |xi|

(αi)

(tt)αi–+  (αi)

t t

(ts)αi–li(st)–β

i–γids

≤ |xi|

(αi)

(tt)αi–+ li( –β

i–γi) ( +αiβi–γi)

(tt)–(βi–γi–αi)

for alli= , , . . . ,k. Since  <αi<βi<( +αi) <  fori= , , . . . ,k, we get

|x

i|

(αi)

(tt)

(αi–)+ li( –β

i–γi) ( +αiβi–γi)

(tt)–(β

i–αi)

≤ |xi|

(αi)

˜ T  (αi–)

 +

li( –βi–γi) ( +αiβi–γi)

˜ T–(βi–αi)

 ≤.

Thus,|xi(t)| ≤[

|xi|

(αi)(tt)

(αi–)+ li(–β

i–γi) (+αi–βiγi)(tt)

–(βiαi)](tt )–γ

i ≤(tt)–γi for

alltt+T˜andi= , , . . . ,k. This implies thatx(t) = (x(t),x(t), . . . ,xk(t))∈S, fort

t+T˜. Since all elements of the setStend to  ast→ ∞, the zero solution of the problem

(.) is globally attractive.

4 Examples

Here, we give an example to illustrate our results.

Example . Consider the -dimensional system of fractional functional differential

equations

⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩

cDx(t) = () ()(t+ )

–  sin

(x (t–))

+(x(t–)) ×

x(t–)

+|x(t–)|, t> ,

cDx

(t) =

()

()

(t+ )

–  cos

(x (t–))

+sin(x(t–))+|x(t–)|, t> ,

cDx(t) =(  )

π (t+ ) –

 (x(t–)) 

+(x(t–))+|x(t–)|, t> , xi(t) =t, i= , , ,t∈[–, ].

Define the maps

f(t,xt,xt,xt) = ()

( )

(t+ )– sin

(x(t– ))

 + (x(t– )) ×

x(t– )  +|x(t– )|,

f(t,xt,xt,xt) = ()

()

t+ 

–

cos(x(t– ))

 +sin(x(t– )) +|x(t– )| ,

f(t,xt,xt,xt) = ()

π (t+ )

–

 (x(t– ))

(12)

and put m(t) = (

 ) ()(t+ )

–

,m(t) = (  ) ()(t+

 )

–

andm(t) = (  )

π (t+ ) –

. It is easy

to check that|f(t,xt,xt,xt)| ≤m(t),|f(t,xt,xt,xt)| ≤m(t) and|f(t,xt,xt,xt)| ≤

m(t). Since

(α)

t t

(ts)α–m(s)ds=

() t

(ts)– ×(

 ) ()(s+ )

–ds

(  ) ()() t

(ts)–s–ds=t–,

(α)

t t

(ts)α–m

(s)ds=  (

) t

(ts)–×(

 ) (

)

s+  –  ds(  ) ()() t

(ts)–s–ds=t–

and

(α)

t t

(ts)α–m(s)ds=

() t

(ts)– ×(

 )

π (s+ ) –ds

() ()√π

t

(ts)–s–ds=t–,

we get| 

(α)

t

(ts) –f

(s,xs,xs,xs)ds| ≤t

 ,| 

(α)

t

(ts) –f

(s,xs,xs,xs)ds| ≤t

 

and|(α

)

t

(ts)

–f(s,xs,x

s,xs)ds| ≤t

. Now, letα=

,α= 

 andα=  . Then,

t

f(t,xt,xt,xt)

α dt

t

m(t)

αdt

= ∞  () ( )

(t+ )–

dt =   () ()  , ∞ t

f(t,xt,xt,xt)

α dt

t

m(t)

α dt

= ∞  () ( )

t+  –  dt =   () ()  and ∞ t

f(t,xt,xt,xt)

α dt

t

m(t)

α dt

= ∞  () √

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Thus, all conditions of Theorem . hold and so this system of fractional functional dif-ferential equations has an attractive solution.

Example . Let  <αi< ,Mi> ,αi<βi<  andxi be a constant fori= , , . Consider

the -dimensional system of fractional differential equations

⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩

x(t) =Mx(t)sin(x(t))

+|x(t)|+|x(t)|(ta)

β , t>a,

x(t) = Mt(x(t))

(+t)(+(x

(t))+(x(t)))(ta)

β , t>a,

x(t) = Mcos(x(t))(x(t))

+(x(t))+|x(t)| (ta)

β , t>a,

[Dαi–x

i(t)]t=a=xi, i= , , .

Define the maps

g

t,x(t),x(t), . . . ,xk(t)

=Mx(t)sin (x(t))

+|x(t)|+|x(t)|

(ta)–β ,

g

t,x(t),x(t), . . . ,xk(t)

= Mt

(x(t))

( + t)( + (x

(t))+ (x(t)))

(ta)–β

and

g

t,x(t),x(t), . . . ,xk(t)

=Mcos

(x(t))(x(t))

 + (x(t))+|x(t)|(ta) –β .

Thus, one can check that all conditions of Theorem . hold and so this system of frac-tional differential equations has a globally attractive solution.

5 Conclusions

Investigating the attractive solutions of the problems is an interesting topic within the fractional calculus. In this manuscript, we focus on the attractivity of solutions for two

k-dimensional systems of fractional differential equations. Two illustrative examples show the applicability of the proposed methods. The techniques of the reported results can be applied for investigating the attractivity and global attractivity of solutions of different systems of (singular) fractional differential equations. Also, it is an interesting issue to investigate the attractivity and global attractivity of solutions of some systems of fractional differential inclusions.

Competing interests

The authors declare that they have no competing interests regarding the publication of this article.

Authors’ contributions

All authors read and approved the final version of this manuscript.

Author details

1Department of Mathematics, Cankaya University, Ogretmenler Cad. 14, Balgat, Ankara, 06530, Turkey.2Institute of Space

Sciences, Magurele, Bucharest, Romania. 3Department of Chemical and Materials Engineering, Faculty of Engineering,

King Abdulaziz University, P.O. Box 80204, Jeddah, 21589, Saudi Arabia. 4Department of Mathematics, Azarbaijan Shahid

Madani University, Azarshahr, Tabriz, Iran.

Acknowledgements

Research of the second and third authors was supported by Azarbaijan Shahid Madani University. Also, the authors express their gratitude to the referees for their helpful suggestions which improved the final version of this paper.

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