PF Simulation Using Matlab

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One line diagram of a

One line diagram of a five bus system :

five bus system :

INPUT :

%clear

basemva = 100

basemva = 100; ; accuracy = 0.0accuracy = 0.0001; accel = 1.6; maxiter = 100;001; accel = 1.6; maxiter = 100; %

% Ybus Ybus ELEMENTS ELEMENTS CALCULATION, CALCULATION, 5 5 BUSES BUSES 7 7 LINES LINES USINGUSING

%

% GAUSS-SEIDEL GAUSS-SEIDEL METHODMETHOD

%

% Bus Bus Bus Bus Voltage Voltage Angle Angle ---Load--- ---Load--- ---Generator--- ---Generator--- Static Static MvarMvar

%

% No No code code Mag. Mag. Degree Degree MW MW Mvar Mvar MW MW Mvar Mvar Qmin Qmin Qmax Qmax +Qc/-Ql+Qc/-Ql

busdata=[1 busdata=[1 1 1 1.02 1.02 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0 0 0 0 00 2 2 0 0 1.00 1.00 0.0 0.0 60.0 60.0 30.0 30.0 0.0 0.0 0.0 0.0 0 0 0 0 00 3 3 2 2 1.04 1.04 0.0 0.0 0.0 0.0 0.0 100.0 0.0 100.0 0.0 0.0 0 0 0 0 00 4 4 0 0 1.0 1.0 0.0 0.0 40.0 40.0 10.0 10.0 0.0 0.0 0.0 0.0 0 0 0 0 00 5 5 0 0 1.0 1.0 0.0 0.0 60.0 60.0 20.0 20.0 0.0 0.0 0.0 0.0 0 0 0 0 0];0]; %

% Line Line codecode

%

% Bus Bus bus bus R R X X 1/2 1/2 B B = = 1 1 for for lineslines

%

% nl nl nr nr p.u. p.u. p.u. p.u. p.u. p.u. > > 1 1 or or < < 1 1 tr. tr. tap tap at at bus bus nlnl

linedata=[1 linedata=[1 2 2 0.100 0.100 0.400 0.400 0.0 0.0 11 1 1 4 4 0.150 0.150 0.600 0.600 0.0 0.0 11 1 1 5 5 0.050 0.050 0.200 0.200 0.0 0.0 11 2 2 3 3 0.050 0.050 0.200 0.200 0.0 0.0 11 2 2 4 4 0.100 0.100 0.400 0.400 0.0 0.0 11 3 3 5 5 0.050 0.050 0.200 0.200 0.0 0.0 1 1 ];];

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lfybus % form the bus admittance matrix %lfgauss % Load flow solution by Gauss-Seidel method %lfnewton % Load flow solution by Newton-Raphson method %decouple % Load flow solution by Fast Decoupled method %busout % Prints the power flow solution on the screen %lineflow % Computes and displays the line flow and losses

OUTPUT :

Ybus =

Columns 1 through 4

2.1569 - 8.6275i -0.5882 + 2.3529i 0 -0.3922 + 1.5686i -0.5882 + 2.3529i 2.3529 - 9.4118i -1.1765 + 4.7059i -0.5882 + 2.3529i

0 -1.1765 + 4.7059i 2.3529 - 9.4118i 0

-0.3922 + 1.5686i -0.5882 + 2.3529i 0 0.9804 - 3.9216i -1.1765 + 4.7059i 0 -1.1765 + 4.7059i 0 Column 5 -1.1765 + 4.7059i 0 -1.1765 + 4.7059i 0 2.3529 - 9.4118i

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INPUT :

%clear

basemva = 100; accuracy = 0.0001; accel = 1.6; maxiter = 100;

% POWER FLOW CALCULATION, 5 BUSES 7 LINES USING % GAUSS-SEIDEL METHOD

% Bus Bus Voltage Angle ---Load--- ---Generator--- Static Mvar % No code Mag. Degree MW Mvar MW Mvar Qmin Qmax +Qc/-Ql busdata=[1 1 1.02 0.0 0.0 0.0 0.0 0.0 0 0 0 2 0 1.00 0.0 60.0 30.0 0.0 0.0 0 0 0 3 2 1.04 0.0 0.0 0.0 100.0 0.0 0 0 0 4 0 1.0 0.0 40.0 10.0 0.0 0.0 0 0 0 5 0 1.0 0.0 60.0 20.0 0.0 0.0 0 0 0]; % Line code

% Bus bus R X 1/2 B = 1 for lines

% nl nr p.u. p.u. p.u. > 1 or < 1 tr. tap at bus nl linedata=[1 2 0.100 0.400 0.0 1 1 4 0.150 0.600 0.0 1 1 5 0.050 0.200 0.0 1 2 3 0.050 0.200 0.0 1 2 4 0.100 0.400 0.0 1 3 5 0.050 0.200 0.0 1 ];

lfybus % form the bus admittance matrix

lfgauss % Load flow solution by Gauss-Seidel method %lfnewton % Load flow solution by Newton-Raphson method %decouple % Load flow solution by Fast Decoupled method busout % Prints the power flow solution on the screen lineflow % Computes and displays the line flow and losses

OUTPUT :

Power Flow Solution by Gauss-Seidel Method Maximum Power Mismatch = 9.32572e-005

No. of Iterations = 25

Bus Voltage Angle ---Load--- ---Generation--- Injected No. Mag. Degree MW Mvar MW Mvar Mvar 1 1.020 0.000 0.000 0.000 65.141 32.921 0.000 2 0.955 -3.942 60.000 30.000 0.000 0.000 0.000

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3 1.040 2.001 0.000 0.000 100.000 47.685 0.000 4 0.923 -8.009 40.000 10.000 0.000 0.000 0.000 5 0.993 -2.073 60.000 20.000 0.000 0.000 0.000 Total 160.000 60.000 165.141 80.607 0.000

Line Flow and Losses

--Line-- Power at bus & line flow --Line loss-- Transformer from to MW Mvar MVA MW Mvar tap 1 65.141 32.921 72.987 2 19.802 12.263 23.292 0.521 2.086 4 24.807 11.741 27.446 1.086 4.344 5 20.546 8.908 22.394 0.241 0.964 2 -60.000 -30.000 67.082 1 -19.280 -10.178 21.802 0.521 2.086 3 -57.325 -23.696 62.029 2.110 8.442 4 16.602 3.874 17.048 0.319 1.275 3 100.000 47.685 110.788 2 59.435 32.138 67.568 2.110 8.442 5 40.572 15.543 43.448 0.873 3.491 4 -40.000 -10.000 41.231 1 -23.721 -7.397 24.848 1.086 4.344 2 -16.283 -2.599 16.489 0.319 1.275 5 -60.000 -20.000 63.246

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INPUT :

%clear

% POWER FLOW CALCULATION, 5 BUSES 7 LINES USING

% NEWTON-RAPHSON METHOD

%lfgauss % Load flow solution by Gauss-Seidel method lfnewton % Load flow solution by Newton-Raphson method %decouple % Load flow solution by Fast Decoupled method busout % Prints the power flow solution on the screen lineflow % Computes and displays the line flow and losses

OUTPUT :

Power Flow Solution by Newton-Raphson Method Maximum Power Mismatch = 3.56144e-007

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3 1.040 2.001 0.000 0.000 100.000 47.684 0.000 4 0.923 -8.008 40.000 10.000 0.000 0.000 0.000 5 0.993 -2.073 60.000 20.000 0.000 0.000 0.000 Total 160.000 60.000 165.150 80.599 0.000

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INPUT :

%clear

% POWER FLOW CALCULATION, 5 BUSES 7 LINES USING

% FAST-DECOUPLED METHOD

%lfgauss % Load flow solution by Gauss-Seidel method %lfnewton % Load flow solution by Newton-Raphson method decouple % Load flow solution by Fast Decoupled method busout % Prints the power flow solution on the screen lineflow % Computes and displays the line flow and losses

OUTPUT :

Power Flow Solution by Fast Decoupled Method Maximum Power Mismatch = 9.98889e-005

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3 1.040 2.001 0.000 0.000 100.000 47.680 0.000 4 0.923 -8.008 40.000 10.000 0.000 0.000 0.000 5 0.993 -2.073 60.000 20.000 0.000 0.000 0.000 Total 160.000 60.000 165.156 80.594 0.000