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On the Positive Pell Equation

y

2

35

x

2

14

K. Meena1, M. A. Gopalan2, T. Priya Lakshmi 3 1

Former VC, Bharathidasan University, Trichy-620 024.Tamilnadu, India

2

Professor, Department of Mathematics, SIGC, Trichy, India.

3

M.Phil Scholar, Department of Mathematics, SIGC, Trichy, India

Abstract: The binary quadratic equation represented by the positive Pellian

y

2

35

x

2

14

is analyzed for its distinct integer solutions. A few interesting relations among the solutions are given. Further, employing the solutions of the above hyperbola, we have obtained solutions of other choices of hyperbola and parabola.

Keywords: Binary quadratic, hyperbola, integral solutions, parabola, pell equation. 2010 mathematics subject classification: 11D09

I. INTRODUCTION

A binary quadratic equation of the form 2 2

1

Dx

y

where D is non-square positive integer has been studied by various mathematicians for its non-trivial integral solutions when D takes different integral values [1-2]. For an extensive review of various problems, one may refer [3-12]. In this communication, yet another interesting hyperbola given by

y

2

35

x

2

14

is considered and infinitely many integer solutions are obtained. A few interesting properties among the solutions are obtained.

A. Method of Analysis

The Positive Pell equation representing hyperbola under consideration is

14

35

2

2

x

y

(1)

whose smallest positive integer solution is

7

,

1

0

0

y

x

To obtain the other solutions of (1), consider the Pell equation

1

35

2

2

x

y

whose general solution is given by

n n

n

n

g

y

f

x

2

1

~

,

35

2

1

~

where

1

1

35

6

35

6

n n

n

f

6

35

1

6

35

1

,

1

,

0

,

1

,

2

...

 

n

g

n n n

Applying Brahmagupta lemma between

x

0

,

y

0

and

~

x

n

,

y

~

n

, the other integer solutions of (1) are given by

n n

n

f

g

x

35

2

7

2

1

1

n n

n

f

g

y

2

35

2

7

1

The recurrence relations satisfied by x and y are given by

0

12

2 1

3

n n

n

x

x

x

0

12

2 1

3

n n

n

y

y

y

(2)

Table: 1 Numerical examples

n

1

n

x

y

n1

-1 1 7

0 13 77

1 155 917

2 1847 10927

3 22009 130207

From the above table, we observe some interesting relations among the solutions which are presented below:

1)

x

n1 and yn+1 are always odd.

2) Relations among the solutions

a)

x

n2

6

x

n1

y

n1

0

b)

y

n2

6

x

n2

x

n1

0

c)

y

n3

71

x

n2

6

x

n1

0

d)

x

n3

12

x

n2

x

n1

0

e)

x

n3

71

x

n2

y

n1

0

f)

x

n3

6

x

n2

y

n2

0

g)

x

n3

71

x

n1

12

y

n1

0

h)

35

x

n3

6

y

n3

y

n2

0

i)

y

n1

x

n2

6

x

n1

0

j)

12

y

n1

x

n3

x

n1

0

k)

12

y

n1

x

n3

71

x

n1

0

l)

2

y

n2

x

n3

x

n1

0

m)

12

y

n3

71

x

n3

x

n1

0

n)

349

x

n1

72

y

n1

x

n3

0

o)

349

x

n2

781

y

n1

6

x

n3

0

p)

349

y

n2

4614

y

n1

35

x

n3

0

q)

349

y

n3

55019

y

n1

420

x

n3

0

r)

6

y

n1

71

y

n2

35

x

n3

0

s)

6

y

n3

35

x

n3

y

n2

0

t)

y

n1

71

y

n3

420

x

n3

0

u)

y

n3

12

y

n2

y

n1

0

v)

280

x

n1

3

y

n3

353

y

n1

0

w)

y

n2

35

x

n1

6

y

n1

0

x)

y

n3

420

x

n1

71

y

n1

0

(3)

z)

y

n1

6

x

n3

71

x

n2

0

aa)

y

n2

x

n3

6

x

n2

0

bb)

y

n3

6

x

n3

x

n2

0

cc)

y

n3

70

x

n2

y

n1

0

dd)

6

y

n2

35

x

n1

y

n1

0

ee)

y

n3

35

x

n2

6

y

n2

0

3) Each of the following expressions represents a nasty number

a)

6

x

2n3

66

x

2n2

12

b)

131

24

2

1

2 2 4

2n

x

n

x

c)

6

y

2n2

30

x

2n2

12

d)

y

2n3

65

x

2n2

12

e)

6

4650

852

71

1

2 2 4

2n

x

n

y

f)

66

x

2n4

786

x

2n3

12

g)

11

y

2n2

5

x

2n3

12

h)

66

y

2n3

390

x

2n3

12

i)

11

y

2n4

775

x

2n3

12

j)

131

5

142

71

6

4 2 2

2n

x

n

y

k)

131

y

2n3

65

x

2n4

12

l)

786

y

2n4

4650

x

2n4

12

m)

78

6

84

7

1

3 2 2

2n

y

n

y

n)

930

6

1008

84

1

4 2 2

2n

y

n

y

o)

930

78

84

7

1

4 2 3

2n

y

n

y

4) Each of the following expressions represents a cubical integer

a)

x

3n4

11

x

3n3

33

x

n1

3

x

n2

b)

3 5

131

3 3

393

1

3

3

12

1

 

n

n

n

n

x

x

x

x

c)

y

3n3

5

x

3n3

15

x

n1

3

y

n1

d)

3 4

65

3 3

195

1

3

2

6

1

 

n

n

n

n

x

x

y

(4)

e)

3 5

775

3 3

2325

1

3

3

71

1

  

n

n

n

n

x

x

y

y

f)

11

x

3n5

131

x

3n4

393

x

n2

33

x

n3

g)

11

3 3

5

3 4

15

2

33

1

6

1

 

n

n

n

n

x

x

y

y

h)

11

y

3n4

65

x

3n4

195

x

n2

33

y

n2

i)

11

3 5

775

3 4

2325

2

33

3

6

1

 

n

n

n

n

x

x

y

y

j)

917

3 3

35

3 5

2751

1

105

3

497

1

 

n

n

n

n

x

y

x

y

k)

131

3 4

65

3 5

195

3

393

2

6

1

 

n

n

n

n

x

x

y

y

l)

131

y

3n5

775

x

3n5

2325

x

n3

393

y

n3

m)

13

3 3 3 4

39

1

3

2

7

1

 

n

n

n

n

y

y

y

y

n)

155

3 3 3 5

465

1

3

3

84

1

 

n

n

n

n

y

y

y

y

o)

155

3 4

13

3 5

465

2

39

3

7

1

 

n

n

n

n

y

y

y

y

5) Each of the following expressions represents a bi-quadratic integer

a)

x

4n5

11

x

4n4

44

x

2n2

4

x

2n3

6

b)

131

524

4

72

12

1

4 2 2 2 4 4 6

4n

x

n

x

n

x

n

x

c)

y

4n4

5

x

4n4

20

x

2n2

4

y

2n2

6

d)

65

260

4

36

6

1

3 2 2 2 4 4 5

4n

x

n

x

n

y

n

y

e)

775

3100

4

426

71

1

4 2 2 2 4 4 6

4n

x

n

x

n

y

n

y

f)

11

x

4n6

131

x

4n5

524

x

2n3

44

x

2n4

6

g)

11

5

20

44

36

6

1

2 2 3 2 5 4 4

4n

x

n

x

n

y

n

y

h)

11

y

4n5

65

x

4n5

260

x

2n3

44

y

2n3

6

i)

11

775

3100

44

36

6

1

4 2 3 2 5 4 6

4n

x

n

x

n

y

n

y

j)

131

5

524

20

426

71

1

4 2 2 2 6 4 4

4n

x

n

y

n

x

n

y

k)

131

65

260

524

36

6

1

3 2 4 2 6 4 5

4n

x

n

x

n

y

n

(5)

l)

131

y

4n6

775

x

4n6

3100

x

2n4

524

y

2n4

6

m)

13

52

4

42

7

1

3 2 2 2 5 4 4

4n

y

n

y

n

y

n

y

n)

155

620

4

504

84

1

4 2 2 2 6 4 4

4n

y

n

y

n

y

n

y

o)

155

13

620

52

42

7

1

4 2 3 2 6 4 5

4n

y

n

y

n

y

n

y

6) Each of the following expressions represents a quintic integer

a)

x

5n6

11

x

5n5

55

x

3n3

5

x

3n4

110

x

n1

10

x

n2

b)

5 7

131

5 5

655

3 3

5

3 5

1310

1

10

3

12

1

    

n

n

n

n

n

n

x

x

x

x

x

x

c)

y

5n5

5

x

5n5

25

x

3n3

5

y

3n3

50

x

n1

10

y

n1

d)

5 6

65

5 5

325

3 3

5

3 4

650

1

10

2

6

1

    

n

n

n

n

n

n

x

x

y

x

y

y

e)

5 7

775

5 5

3875

3 3

5

3 5

7750

1

10

3

71

1

    

n

n

n

n

n

n

x

x

y

x

y

y

f)

11

x

5n7

131

x

5n6

655

x

3n4

55

x

3n5

1310

x

n2

110

x

n3

g)

11

5 5

5

5 6

25

3 4

55

3 3

50

2

110

1

6

1

    

n

n

n

n

n

n

x

x

y

x

y

y

h)

11

y

5n6

65

x

5n6

325

x

3n4

55

y

3n4

650

x

n2

110

y

n2

i)

11

5 7

775

5 6

3875

3 4

55

3 5

7750

2

110

3

6

1

    

n

n

n

n

n

n

x

x

y

x

y

y

j)

655

3 3

524

5 5

20

5 7

25

3 5

1965

1

75

3

71

1

    

n

n

n

n

n

n

y

x

x

y

x

y

k)

131

5 6

65

5 7

325

3 5

655

3 4

650

3

1310

2

6

1

    

n

n

n

n

n

n

x

x

y

x

y

y

l)

131

y

5n7

775

x

5n7

3875

x

3n5

655

y

3n5

7750

x

n3

1310

y

n3

m)

13

5 5 5 6

65

3 3

5

3 4

130

1

10

2

7

1

    

n

n

n

n

n

n

y

y

y

y

y

y

n)

155

5 5 5 7

775

3 3

5

3 5

1550

1

10

3

84

1

    

n

n

n

n

n

n

y

y

y

y

y

y

o)

155

5 6

13

5 7

775

3 4

65

3 5

1550

2

130

3

7

1

    

n

n

n

n

n

n

y

y

y

y

y

y

B. Remarkable Observations

(6)

Table: 2 Hyperbolas S. No

Hyperbolas

X

,

Y

1

7

2

5

2

28

Y

X

x

n2

11

x

n1

,

13

x

n1

x

n2

2

7

2

5

2

4032

Y

X

x

n3

131

x

n1

,

155

x

n1

x

n3

3

7

2

5

2

28

Y

X

y

n1

5

x

n1

,

7

x

n1

y

n1

4

7

2

5

2

1008

Y

X

y

n2

65

x

n1

,

77

x

n1

y

n2

5

7

2

5

2

141148

Y

X

y

n3

775

x

n1

,

917

x

n1

y

n3

6

7

2

5

2

28

Y

X

11

x

n3

131

x

n2

,

155

x

n2

13

x

n3

7

7

2

5

2

1008

Y

X

11

y

n1

5

x

n2

,

7

x

n2

13

y

n1

8

7

2

5

2

28

Y

X

11

y

n2

65

x

n2

,

77

x

n2

13

y

n2

9

7

2

5

2

1008

Y

X

11

y

n3

775

x

n2

,

917

x

n2

13

y

n3

10

7

2

5

2

141148

Y

X

131

y

n1

5

x

n3

,

7

x

n3

155

y

n1

11

7

2

5

2

1008

Y

X

131

y

n2

65

x

n3

,

77

x

n3

155

y

n2

12

7

2

5

2

28

Y

X

131

y

n3

775

x

n3

,

917

x

n3

155

y

n3

13

5

2

7

2

980

Y

X

13

y

n1

y

n2

,

y

n2

11

y

n1

14

5

2

7

2

141120

Y

X

155

y

n1

y

n3

,

y

n3

131

y

n1

15

5

2

7

2

980

Y

(7)

2) Employing linear combinations among the solutions of (1), one may generate integer solutions for other choices of parabola which are presented in the Table: 3 below:

Table: 3 Parabolas S. No

Parabolas

X

,

Y

1

7

5

2

14

Y

X

x

2n3

11

x

2n2

,

13

x

n1

x

n2

2

84

5

2

2016

Y

X

x

2n4

131

x

2n2

,

155

x

n1

x

n3

3

7

5

2

14

Y

X

y

2n2

5

x

2n2

,

7

x

n1

y

n1

4

42

5

2

504

Y

X

y

2n3

65

x

2n2

,

77

x

n1

y

n2

5

497

5

2

70574

Y

X

y

2n4

775

x

2n2

,

917

x

n1

y

n3

6

7

5

2

14

Y

X

11

x

2n4

131

x

2n3

,

155

x

n2

13

x

n3

7

42

5

2

504

Y

X

11

y

2n2

5

x

2n3

,

7

x

n2

13

y

n1

8

7

5

2

14

Y

X

11

y

2n3

65

x

2n3

,

77

x

n2

13

y

n2

9

42

5

2

504

Y

X

11

y

2n4

775

x

2n3

,

917

x

n2

13

y

n3

10

497

5

2

70574

Y

X

131

y

2n2

5

x

2n4

,

7

x

n3

155

y

n1

11

42

5

2

504

Y

X

131

y

2n3

65

x

2n4

,

77

x

n3

155

y

n2

12

7

5

2

14

Y

X

131

y

2n4

775

x

2n4

,

917

x

n3

155

y

n3

13

5

2

70

Y

X

13

y

2n2

y

2n3

,

y

n2

11

y

n1

14

60

2

10080

Y

X

155

y

2n2

y

2n4

,

y

n3

131

y

n1

15

5

2

70

Y

(8)

REFERENCES

[1] Dickson L.E., History of Theory of Numbers, Chelsea Publishing Company,Newyork,Vol.II,1952 [2] Mordell L.J., Diophantine Equations, Academic Press , Newyork,1969.

[3] Gopalan M.A, Vidhyalakshmi S, Sumathi G, Integral points on the Hyperbola,

x

2

6

xy

y

2

40

x

80

y

40

0

Bessel J Math., 2(3), 2012, 159-164.

[4] Gopalan M.A., Sumathi G., Vidhyalakshmi S., Observation on the Hyperbola,

y

2

24

x

2

1

Bessel J Math, 4, 2013, 21-25.

[5] Geetha T., Gopalan M.A., Vidhyalakshmi S., Observation on the hyperbola,

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72

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1

, Scholars Journal of Physics, Mathematics and Statistics, 1(1), 2014, 1-13.

[6] Gopalan M.A, Vidhyalakshmi S., Umarani J., Remarkable Observations on the hyperbola

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24

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1

, Bulletin of Mathematics and Statistics Research, 1, 2014, 9-12.

[7] Gopalan M.A , Vidhyalakshmi S, Premalatha E, Vanitha M, Observation on the hyperbola,

y

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220

x

2

9

, Star Research Journal, Vol.4, Issue3(2), 2016, 12-16.

[8] Ramya S, Kavitha A. On the positive pell equation,

y

2

90

x

2

31

, Journal of Mathematics and informatics, 11(1), 2017, 11-17.

[9] Sumathi G., Observations on the hyperbola,

y

2

150

x

2

16

, International Journal of Recent Trends in Engineering and Research, 3(9), 2017, 198-206.

[10] Meena K, Gopalan M.A., Sivaranjani V, On the positive pell equation

y

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102

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33

. International Journal of Advanced Education and Research 2(1), 2017, 91-96

[11] Gopalan M.A, Devibala S., Swetha T., On the positive pell equation

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5

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4

, IOSR Journal of Mathematics, Vol 13, Issue 5, Ver.1, 2017, 65-69.

[12] Usha Rani T.R, Dhivya K, On the positive pell equation

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14

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18

, International Journal of Academic Research and Development, Volume 3, Issue 3, 2018, 43-50.

References

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