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Volume 16, Number 4 (2018), 503-517 URL:https://doi.org/10.28924/2291-8639

DOI:10.28924/2291-8639-16-2018-503

A PERTURBED VERSION OF GENERAL WEIGHTED OSTROWSKI TYPE INEQUALITY AND APPLICATIONS

WASEEM GHAZI ALSHANTI∗

Department of General Studies, Jubail University College, Saudi Arabia

Corresponding author: [email protected]

Abstract. The main purpose of this paper is to derive some new generalizations of weighted Ostrowski type inequalities. The new established inequalities are carried out for a twice differentiable mapping in differentLpspaces. Applications throught considering Gr¨uss type inequality and numerical integration are also provided.

1. Introduction

The Ostrowski’s inequality [1] can be considered as a very powerful tool for enhancement of numerical

integration rules. It provides convenient potintial window for establishing bounds for the well known

Newton-Cotes rules. To illustrate this point, consider f : [a, b] → Rto be a bounded function such that b−a is

small, then

I= b Z

a

f (x)dx,

can be, simply, approximated by sampling at one point as I∗(x) = (b−a)f(x) for some x∈[a, b]. Now, if

f 0 exists and is bounded, the inequality of Ostrowski may be stated as follows

|I∗(x)−I| ≤ 

1 4+

x−a+b

2 b−a

!2

kf0k, (1.1)

Received 2018-02-12; accepted 2018-04-27; published 2018-07-02. 2010Mathematics Subject Classification. 26D15.

Key words and phrases. Ostrowski’s inequality; Weight function; Gr¨uss inequality; Numerical integration.

c

2018 Authors retain the copyrights

of their papers, and all open access articles are distributed under the terms of the Creative Commons Attribution License.

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where

kf0k= sup x∈[a,b]

|f0(x)|.

Consequently, over the past few decades, there have been many studies on obtaining sharp bounds of

(1.1) by considering the mappings and their derivatives in various Lebesgue spaces. Further, the new bounds

have been carried out by implementing weighted and weighted Peano kernel. Several weighted and

non-weighted versions of (1.1) have been derived. Applications in both numerical integration and probability

are also presented in this regards. For instance, Roumeliotis et. al [2] proved a weighted integral inequality

of Ostrowski’s type for mappings whose second derivatives are bounded. Cerone [3] obtained bounds for

the deviation of a function from a combination of integral means over the end intervals covering the entire

interval. Qayyum et. al [4] established a new Ostrowski’s type inequality using weight function which

generalizes the inequality in [3]. Barnett [5] reported a companion of (1.1) and the generalized trapezoid

inequalites for various classes of functions, including functions of bounded variation, Lipschitzian, convex

and absolutely continuous functions. Recently, Budak et. al [6] presented a new generalization of weighted

Ostrowski’s type inequality for mappings of bounded variation. Several further generalizations of (1.1) are

provided in [7] - [16].

In [12], Qayyum et. al proved the following non-weighted generalization of Ostrowski’s type integral

inequality.

Theorem 1.1. Let f : [a, b]→Rbe a twice differentiable mapping. Then

1

2 (α+β)[α(x−a)−β(b−x)]f

0

(x)−f(x)

+ 1

α+β

α x−a

x

Z

a

f(t)dt+ β b−x

b

Z

x

f(t)dt

,

≤                       

                     

α(x−a)2+β(b−x)2kf

00k

6(α+β),

f00∈L∞[a, b],

1 (2q+1)1

q

αq(x−a)q+1

+βq(b−x)q+11q kf

00k

p

2(α+β),

f00∈Lp[a, b],

p >1,1

p+

1

q = 1,

[α(x−a) +β(b−x)

+|α(x−a)−β(b−x)|]kf

00k

1 4(α+β), f

00

L1[a, b].

(1.2)

where αandβ are non-negative real numbers such that not both zero.

In this paper, motivated by the non-weighted case in [12], new general weighted Peano kernel has been

defined. To obtain new general weighted inequality of Ostrowski’s type that is more generalized and extended

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and f 00 ∈ L1. Moreover, we utilize Gr¨uss type inequality to present the perturbed verion of our result.

Finally, we investigate the new general weighted inequality in numerical integration.

Before we introduce our main result for a general weighted inequality of Ostrowski’s type, we commence

with the following definition and lemma.

Definition: Let ω: (a, b)→(0,∞)be a non-negative weighted function (density) such that

b Z

a

ω(t)dt <∞.

The domain of ωmay be finite or infinite and may vanish at the boundary points. We denote the moments

m(a, b) = 1

b−a

b Z

a

ω(t)dt, M(a, b) = 1

b−a

b Z

a

tω(t)dt,

N(a, b) = 1

b−a

b Z

a

t2ω(t)dt, µ(a, b) =M(a, b)

m(a, b),

σ2(a, b) = N(a, b)

m(a, b)−µ

2(a, b). (1.3)

Furthermore, for a function f : [a, b]→R,we define the functional

S(f;a, b) = 1

b−a

b Z

a

f(t)ω(t)dt. (1.4)

Lemma 1.1. Let f : [a, b]→Rbe a twice differentiable mapping. Denote by Pω: [a, b]2 →Rthe weighted

Peano kernel function that is given by

Pω(x, t) =    

  

α α+β

1

x−a t R

a

(t−u)ω(u)du, t∈[a, x]

β α+β

1

b−x t R

b

(t−u)ω(u)du, t∈(x, b],

(1.5)

whereα, β≥0and not both zero. Then the following identity

b Z

a

Pω(x, t)f 00(t)dt=z(f;α, β), (1.6)

where

z(f;α, β) = 1

α+β {[αm(a, x)(x−µ(a, x))

+βm(x, b)(x−µ(x, b))]f 0(x)

−[αm(a, x) +βm(x, b)]f(x)

+αS(f;a, x) +βS(f;x, b)}, (1.7)

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Proof: From (1.5), we have

b Z

a

Pω(x, t)f 00(t)dt

= α

α+β

1

x−a

x Z a   t Z a

(t−u)ω(u)du

f 00(t)dt

+ β

α+β

1

b−x

b Z x   t Z b

(t−u)ω(u)du

f 00(t)dt

= α

α+β

1

x−a

f 0(x) x Z

a

(x−u)ω(u)du

−f(x) x Z

a

ω(u)du+ x Z

a

f(t)ω(t)dt

+ β

α+β

1

b−x

f 0(x) b Z

x

(x−u)ω(u)du

−f(x) x Z

b

ω(u)du+ b Z

x

f(t)ω(t)dt

.

After further simplification, the identity (1.6) can be obtained.

2. Main Results

Theorem 2.1. Let f : [a, b]→Rbe a twice differentiable mapping in(a, b). Then∀x∈[a, b], we have

|z(f;α, β)|

≤                                                               

αm(a, x)

(x−µ(a, x))2+σ2(a, x)

+βm(x, b)

(x−µ(x, b))2+σ2(x, b)

×kf 00k

2(α+β),

f 00∈L∞[a, b],

αq

(x−a)q x R

a

(t−a)2qmq(a, t)dt

+(b−xβq)q b R

x

(b−t)2qmq(t, b)dt #1q

kf00k p

2(α+β),

f 00∈Lp[a, b],

p >1,1p+1q = 1,

max{αm(a, x) (x−µ(a, x)),

βm(x, b) (µ(x, b)−x)}kf 00k

1

α+β , f 00L

1[a, b].

(2.1)

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Proof: Taking the modulus of the right hand side of (1.6), yields

b Z

a

Pω(x, t)f 00(t)dt

≤ b Z

a

|Pω(x, t)| |f 00(t)|dt. (2.2)

Hence, forf 00∈L∞[a, b]

|z(f;α, β)| ≤ kf 00k b Z

a

|Pω(x, t)|dt. (2.3)

Now, using (1.5) provids,

b Z

a

|Pω(x, t)|dt

= α

α+β

1

x−a

x2

2 x Z

a

ω(u)du

−x

x Z

a

uω(u)du+1 2

x Z

a

t2ω(t)dt

+ β

α+β

1

b−x

x2

2 b Z

x

ω(u)du

−x

b Z

x

uω(u)du+1 2

b Z

x

t2ω(t)dt

. (2.4)

Thus, by combining (2.3) and (2.4), the first inequality of (2.1) results.

Further, from (2.2) and by using H¨older’s integral inequality for f 00∈Lp[a, b],we have

|z(f;α, β)| ≤ kf 00kp 

 b Z

a

|Pω(x, t)| q

dt

1

q

, (2.5)

where 1p +1q = 1 withp >1.Now, by (1.5) and utilizing the weighted mean value theorem for integrals,

we have

b Z

a

|Pω(x, t)| q

dt

=

α α+β

q

1 (x−a)q

x Z

a 

 t Z

a

(t−u)ω(u)du

 q

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+

β

α+β

q 1

(b−x)q b Z

x 

 t Z

b

(t−u)ω(u)du

 q

dt

=

α

α+β

q 1

(x−a)q x Z

a 

t−a

2 t Z

a

ω(u)du

 q

dt

+

β

α+β

q 1

(b−x)q b Z

x 

b−t

2 b Z

t

ω(u)du

 q

dt, (2.6)

and so, by considering (2.5) and (2.6) the second inequality of (2.1) is obtained.

Finally, forf 00∈L1[a, b],we have from (1.6)

z(f;α, β)≤ sup t∈[a,b]

|Pω(x, t)| kf 00k1, (2.7)

where,

sup t∈[a,b]

|Pω(x, t)| = max  

α α+β

1

x−a

x Z

a

(x−u)ω(u)du ,

β α+β

1

b−x

b Z

x

(u−x)ω(u)du

 

= 1

α+βmax{αm(a, x)(x−µ(a, x),

βm(x, b)(µ(x, b)−x]}. (2.8)

Therefore, combining (2.7) and (2.8) gives the third inequality of (2.1), and so, the theorem is now

completely proven.

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Corollary 2.1. Let the condition of Theorem(2.1) holds. Then

|z(f;α, β)|

αm(a, x)

(x−µ(a, x))2+σ2(a, x)

+βm(x, b)

(x−µ(x, b))2+σ2(x, b)

×kf 00k

∞ 2(α+β)

≤ hα(x−a)2m(a, x) +β(x−b)2m(x, b)i

×kf 00k

2(α+β). (2.9)

Proof: From (1.5), we have

b Z

a

|Pω(x, t)|dt

= 1

2

α α+β

1

x−a

x Z

a

(x−t)2ω(t)dt

+1 2

β α+β

1

b−x

b Z

x

(x−t)2ω(t)dt.

Now, by noting that

x Z

a

(x−t)2ω(t)dt ≤ sup t∈[a,x]

(x−t)2[(x−a)m(a, x)]

= (x−a)3m(a, x),

and

b Z

x

(x−t)2ω(t)dt ≤ sup t∈(x,b]

(x−t)2[(b−x)m(x, b)]

= (b−x)3m(x, b).

The desired second inequality of (2.9) can be obtained.

Corollary 2.2. Settingα=β in Theorem (2.1) gives

1

2{[m(a, x)(x−µ(a, x)) +m(x, b)(x−µ(x, b))]f 0(x)

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≤                                                                 

m(a, x)

(x−µ(a, x))2+σ2(a, x)

+m(x, b)

(x−µ(x, b))2+σ2(x, b)

×kf

00k

4 ,

f00∈L∞[a, b],

1 (x−a)q

x

R

a

(t−a)2qmq(a, t)dt

+ 1

(b−x)q

b

R

x

(b−t)2qmq(t, b)dt

1q kf00k

p

4 ,

f00∈Lp[a, b],

p >1,1

p+

1

q = 1,

max{m(a, x) (x−µ(a, x)),

m(x, b) (µ(x, b)−x)}kf

00k

1

2 , f

00

∈L1[a, b].

(2.10)

Remark 2.2. Setting ω(u) = 1 in Corollary (2.2) gives the corresponding non-weighted result obtained by [12] for the case α=β.

Corollary 2.3. Settingx= (a+b)/2 in Theorem(2.1)gives

1 α+β αm

a,a+b

2

a+b

2 −µ

a,a+b

2

+βm

a+b

2 , b

a+b

2 −µ

a+b

2 , b

f 0

a+b

2 − αm

a,a+b

2

+βm

a+b

2 , b

f

a+b

2

+αS

f;a,a+b

2

+βS

f;a+b 2 , b

≤                                                                   

αm(a,a+2b)(a+2b−µ(a,a+2b))2+σ2 a,a+2b

+βm(a+b

2 , b)

(a+b

2 −µ(

a+b

2 , b))

2+σ2 a+b

2 , b

× kf 00k,

f 00∈L∞[a, b],

"

αq

a+b

2

R

a

(t−a)2qmq(a, t)dt

+βq b R

a+b

2

(b−t)2qmq(t, b)dt

1

q

kf00k

p

(b−a)(α+β),

f 00∈Lp[a, b],

p >1,1

p+

1

q = 1,

maxαm(a,a+2b) a+2b−µ(a,a+2b),

β m(a+2b, b) µ(a+2b, b)−a+b

2

kf00k

1

α+β , f 00L

1[a, b].

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Remark 2.3. Setting ω(u) = 1 in Corollary (2.3), gives the corresponding non-weighted result obtained by [12] whenx= (a+b)/2.

Corollary 2.4. If (2.10)evaluated atx= (a+b)/2, then

1 2

m(a,a+b

2 )(

a+b

2 −µ(a,

a+b

2 ))

+m(a+b

2 , b)(x−µ(

a+b

2 , b))

f 0(a+b 2 )

m(a,a+b

2 ) +m(

a+b

2 , b)

f(a+b 2 )

+ S(f;a,a+b

2 ) +S(f;

a+b

2 , b)

≤                                                               

m(a,a+b

2 )

(a+b

2 −µ(a,

a+b

2 ))

2+σ2 a,a+b

2

+m(a+b

2 , b)

(a+b

2 −µ(

a+b

2 , b))

2+σ2 a+b

2 , b

×kf 00k

4 , f

00L

∞[a, b],

"a+b

2

R

a

(t−a)2qmq(a, t)dt

+ b R

a+b

2

(b−t)2qmq(t, b)dt

1

q kf00k

p

2(b−a),

f 00∈Lp[a, b],

p >1,1p+1q = 1,

max

m(a,a+2b) a+2b−µ(a,a+2b)

,

m(a+b

2 , b) µ(

a+b

2 , b)−

a+b

2

kf00k

1

2 , f

00L

1[a, b].

(2.12)

3. Perturbed Results

The Gr¨uss inequality is as follows [13].

Theorem 3.1. Letf, g: [a, b]→Rbe integrable functions on[a, b]such thatϕ≤f(x)≤Φandγ≤g(x)≤Γ ∀x∈[a, b],where ϕ,Φ, γ,Γ are constants. Then

1

b−a

b Z

a

f(t)g(t)dt− 1

b−a

b Z

a

f(t)dt· 1

b−a

b Z

a

f(t)dt

≤ 1

4(Φ−ϕ) (Γ−γ), (3.1)

where the constant 14 is sharp.

Now, the perturbed verions of the results in the pervious section may be obtained by using Gr¨uss type

inequalities involving the ˇCebyˆsev functional [14],

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where

M(f;a, b) = 1

b−a

b Z

a

f(t)dt,

is the integral mean off over [a, b].

Theorem 3.2. Let f : [a, b]→Rbe a twice differentiable mapping such thatγ≤f 00(x)≤Γ∀x∈[a, b]and α≥0, β≥0, α+β6= 0. Then

z

(f;α, β)− k 2(α+β)

αm(a, x)

(x−µ(a, x))2+σ2(a, x)

+ βm(x, b)(x−µ(x, b))2+σ2(x, b)

≤ (b−a)N(x)

" kf 00k22

b−a −k 2

#12 ,

≤ (b−a)N(x)Γ−γ 2 ,

≤ (b−a) (Γ−γ)

4 (α+β) max{αm(a, x) (x−µ(a, x)),

βm(x, b) (µ(x, b)−x)}, (3.3)

wherez(f;α, β)is given by(1.7), k= (f 0(b)−f 0(a))/(b−a),and

N(x) =

 

 

α

x−a

2Zx

a

(t−a)4m2(a, t)dt

+

β

b−x

2Zb

x

(b−t)4m2(t, b)dt

1

4(α+β)2(ba) (3.4)

αm(a, x)

(x−µ(a, x))2+σ2(a, x)

+ βm(x, b)(x−µ(x, b))2+σ2(x, b) 1 2(α+β) (b−a)

2)

1 2

.

Proof: Replacingf(t) byPω(x, t) andg(t) byf 00(x) in (3.2) yields,

T(Pω(x, t), f00(x)) = M(Pω(x, t)f 00(x);a, b) (3.5)

−M(Pω(x, t);a, b)M(f 00(x);a, b).

Now, by using both (1.6) and (2.4),we have

T(Pω(x, t), f 00(x)) = 1

b−a{z(f;α, β)

− k

2(α+β)

αm(a, x)

(x−µ(a, x))2+σ2(a, x)

+βm(x, b)

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wherekis the secant slope off 0 over [a, b] as given in (3.4).Moreover, by [3], we have

T(Pω(x, t), f 00(x)) ≤ T

1

2(Pω(x, t), Pω(x, t))T 1

2(f 00(x), f00(x)),

(Pω(x, t), f 00(x)∈L2[a, b] )

≤ Γ−γ

2 T

1

2(Pω(x, t), Pω(x, t)),

(γ≤f 00(x)≤Γ, ∀x∈[a, b])

≤ 1

4(Φ−ϕ) (Γ−γ), (3.7)

ϕ≤Pω(x, t)≤Φ, ∀(x, t)∈[a, b]

2

.

But,

0 ≤ T12(f 00(x), f00(x))

= hM((f 00(x))2;a, b)−M2(f 00(x);a, b)i

1 2

=

   

1

b−a

b Z

a

(f 00(x))2dx− 

    b R

a

f 00(x)dx

b−a

   

2

   

1 2

=

1

b−akf

00k2 2−k

2

12

≤ Γ−γ

2 , (3.8)

whereγ≤f 00(x)≤Γ,∀x∈[a, b].

Now, forT12(Pω(x, t), Pω(x, t)),we consider (1.5) as follows

0 ≤ T12(Pω(x, t), Pω(x, t))

= hM((Pω(x, t))2;a, b)−M2(Pω(x, t);a, b) i12

=

   

1

b−a

b Z

a

(Pω(x, t))

2 dx−

    b R

a

Pω(x, t)dx

b−a

   

2

   

1 2

= N(x), (3.9)

whereN(x) is given in (3.4).

Therefore, by combining (3.6), (3.7), (3.8), and (3.9) gives the first and the second inequalities of (3.3).

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from the definition ofPω(x, t) in (1.5) that forα, β≥0, α+β 6= 0, we have

Φ = sup

t∈[a,b]

Pω(x, t)

= 1

α+β max{αm(a, x) (x−µ(a, x)), βm(x, b) (µ(x, b)−x)},

ϕ = inf

t∈[a,b]Pω(x, t) = 0. (3.10)

Hence, from (3.6), (3.8), (3.10) and the last inequality in (3.7), we obtain the third inequality in (3.3)

and the theorem is now completely proved.

4. Application in Numerical Integration

Leta=ζ◦ < ζ1 <· · · < ζn−1< ζn =x=η◦ < η1 <· · · < ηn−1< ηn =b be a partition of the interval

[a, b], with xi ∈ [ζi, ζi+1] for i = 0,1, ..., n−1, x∗j ∈ [ηj, ηj+1] for j = 0,1, ..., n−1, δ =ζi+1−ζi, and

∆ =ηj+1−ηj.Consider the following general quadrature rule.

A(f, ζ, η, x)

= n−1

αX

i=0

mi[f (xi)−(xi−µi)f 0(xi)]

+ n−1

βX

j=0 m∗j

f (x∗j)− x∗j−µ∗j

f 0 x∗j

. (4.1)

Theorem 4.1. Let the conditions of Theorem(2.1)hold. The following weighted quadrature rule for weighted integral holds

α δ

x Z

a

f(t)ω(t)dt+ β ∆

b Z

x

f(t)ω(t)dt

= A(f, ζ, η, x) +R(f, ζ, η, x), (4.2)

whereA(f, ζ, η, x)is defined by(4.1), the remainderR(f, ζ, η, x)satisfies the estimate

R(f, ζ, η, x)

(n−1

αX

i=0 mi

h

(xi−µi)

2

i2i

+ n−1

βX

j=0

m∗jh x∗j−µ∗j2

j∗2i

 

kf 00k

2 , (4.3)

and the parametersmi,µi,σ2i,m∗j,µ∗j, andσ∗

2

j are given by

mi = m(ζi, ζi+1), µi=µ(ζi, ζi+1), σi2=σ

2(ζ

i, ζi+1),

m∗j = m(ηj, ηj+1), µ∗j =µ(ηj, ηj+1), and σj∗2=σ

2(η

(13)

Proof: Applying the first inequality of (2.1) over the interval [ζi, ζi+1] withx=xi ∈[ζi, ζi+1] and over

the interval [ηj, ηj+1] withx=x∗j ∈[ηj, ηj+1] gives

αmi(xi−µi)f 0(xi) +βm∗j(x∗j− µj∗)f 0(x∗j)−αmif(xi) +βm∗jf(x∗j)

δ

ζi+1

Z

ζi

f(t)ω(t)dt+ β ∆

ηj+1

Z

ηj

f(t)ω(t)dt

αmi

(xi−µi)2+ σ2i

+βm∗j

(x∗j−µ∗j)2+ σj∗2

kf 00k

2 ,

for alli, j= 0,1, ..., n−1.Summing over i, jfrom 0 ton−1 and using the triangle inequality produces

the desired result (4.2).

Theorem 4.2. Let the conditions of Theorem(2.1)hold. The following weighted quadrature rule for weighted integral holds

α δ

x Z

a

f(t)ω(t)dt+ β ∆

b Z

x

f(t)ω(t)dt

= A(f, ζ, η, x) +R(f, ζ, η, x),

whereA(f, ζ, η, x)is defined by(4.1), the remainderR(f, ζ, η, x)satisfies the estimate

R(f, ζ, η, x)

≤ 

 

αq δq

ζi+1

Z

ζi

(t−ζi)2qmq(ζi, t)dt

+ β q ∆q

ηj+1

Z

ηj

(ηj+1−t) 2q

mq(t, ηj+1)dt

 

1

q kf 00kp

2 . (4.5)

Proof: Applying the second inequality of (2.1) over the interval [ζi, ζi+1] withx=xi∈[ζi, ζi+1] and over

the interval [ηj, ηj+1] withx=x∗j ∈[ηj, ηj+1] gives

αmi(xi−µi)f 0(xi) +βm∗j(x ∗ j− µ

∗ j)f

0(x

j)−αmif(xi) +βm∗jf(x ∗ j)

δ

ζi+1

Z

ζi

f(t)ω(t)dt+ β ∆

ηj+1

Z

ηj

f(t)ω(t)dt

≤ 

 

αq δq

ζi+1

Z

ζi

(t−ζi)

2q

mq(ζi, t)dt

+ β q ∆q

ηj+1

Z

ηj

(ηj+1−t) 2q

mq(t, ηj+1)dt

 

1

q kf 00kp

(14)

for alli, j= 0,1, ..., n−1.Summing over i, jfrom 0 ton−1 and using the triangle inequality produces

the desired result (4.5).

Theorem 4.3. Let the conditions of Theorem(2.1)hold. The following weighted quadrature rule for weighted integral holds

α δ

x Z

a

f(t)ω(t)dt+ β ∆

b Z

x

f(t)ω(t)dt

= A(f, ζ, η, x) +R(f, ζ, η, x),

whereA(f, ζ, η, x)is defined by(4.1), the remainderR(f, ζ, η, x)satisfies the estimate

R(f, ζ, η, x)

≤ max

αmi(xi−µi), βm∗j µ∗j −x∗j

kf 00k1. (4.6)

Proof: Applying the third inequality of (2.1) over the interval [ζi, ζi+1] withx=xi ∈[ζi, ζi+1] and over

the interval [ηj, ηj+1] withx=x∗j ∈[ηj, ηj+1] gives

αmi(xi−µi)f 0(xi) +βm∗j(x ∗ j− µ

∗ j)f

0(x

j)−αmif(xi) +βm∗jf(x ∗ j)

δ

ζi+1

Z

ζi

f(t)ω(t)dt+ β ∆

ηj+1

Z

ηj

f(t)ω(t)dt

≤ max

αmi(xi−µi), βm∗j µ∗j−x∗j kf 00k1.

for alli, j= 0,1, ..., n−1.Summing over i, jfrom 0 ton−1 and using the triangle inequality produces

the desired result (4.6).

References

[1] A. Ostrowski, Uber die Absolutabweichung einer differentienbaren Funktionen von ihren Integralimittelwert, Comment.¨ Math. Hel. 10 (1938), 226-227.

[2] J. Roumeliotis, P. Cerone, and S. S. Dragomir,An Ostrowski type inequality for weighted mappings with bounded second derivatives, RGMIA Res. Rep. Collect. 1 (1998), 101-111.

[3] P. Cerone,A new Ostrowski type inequality involving integral means over end intervals, Tamkang J. Math. 33(2) (2002), 109-118.

[4] A. Qayyum, M. Shoaib, and I. Faye, On new weighted Ostrowski type inequalities involving integral means over end intervals and application, Turkish J. Anal. Numb. Theory. 3(2) (2015), 61-67.

[5] N. Barnett, S. S. Dragomir, and I. Gomm,A companion for the Ostrowski and the generalised trapezoid inequalities, Math. Comput. Model. 50(1) (2009), 179-187.

[6] H. Budak, S. Erden, and M. Sarikaya, New Weighted Ostrowski Type Inequalities for Mappings Whose nth Derivatives Are of Bounded Variation, Int. J. Anal. Appl. 12(1) (2016), 71-79.

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[8] M. Alomari,A generalization of companion inequality of Ostrowski’s type for mappings whose first derivatives are bounded and applications in numerical integration, Kragujevac J. Math. 36(1) (2012), 77–82.

[9] W. Liu,New Bounds for the Companion of Ostrowski’s Inequality and Applications, Filomat. 28 (2014), 167-178. [10] R. Agarwal, P. Ravi, M. Luo, and R. Raina,On Ostrowski type inequalities, Fasciculi Math. 56(1) (2016), 5-27.

[11] H. Budak, M. Sarikaya,A New Companion of Ostrowski Type Inequalities for Functions of Two Variables With Bounded Variation, Facta Universitatis, Series: Mathematics and Informatics. 31(2) (2016), 447-463.

[12] A. Qayyum, M. Shoaib, A. Matouk, and M. Latif,On new generalized Ostrowski type integral inequalities, Abstr. Appli. Anal. 2014 (2014), Art. ID 275806.

[13] G. Gr¨uss,Uber das Maximum des absoluten Betrages von 1/(b−a) b

R

a

f(x)g(x)dx−1/(b−a)2Rb

a f(x)dx

b

R

a

g(x)dx,

Mathe-matische Zeitschrift. vol. 39(1) (1935), 215–226.

[14] P. L. ˇCebyˆsev, Sur les expressions approximatives des integrales definies par les autres prises entre les mˆemes limites, Proc. Math. Soc. Kharkov. 2 (1882), 93–98.

[15] W.G. Alshanti and A. Qayyum,A Note On New Ostrowski Type Inequalities Using a Generalized Kernel. Bull. Math. Anal. Appl. 9(1) (2017), 74-91.

References

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